div class=ts-pagebutton class=gotoPage data-page=1Page 1button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=1 data-page=1 class=ts-thumb lazyload alt=Page 1: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails1jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=2Page 2button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=2 data-page=2 class=ts-thumb lazyload alt=Page 2: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails2jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=3Page 3button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=3 data-page=3 class=ts-thumb lazyload alt=Page 3: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails3jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=4Page 4button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=4 data-page=4 class=ts-thumb lazyload alt=Page 4: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails4jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=5Page 5button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=5 data-page=5 class=ts-thumb lazyload alt=Page 5: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails5jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=6Page 6button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=6 data-page=6 class=ts-thumb lazyload alt=Page 6: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails6jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=7Page 7button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=7 data-page=7 class=ts-thumb lazyload alt=Page 7: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails7jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=8Page 8button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=8 data-page=8 class=ts-thumb lazyload alt=Page 8: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails8jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=9Page 9button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=9 data-page=9 class=ts-thumb lazyload alt=Page 9: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails9jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=10Page 10button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=10 data-page=10 class=ts-thumb lazyload alt=Page 10: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails10jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=11Page 11button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=11 data-page=11 class=ts-thumb lazyload alt=Page 11: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails11jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=12Page 12button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=12 data-page=12 class=ts-thumb lazyload alt=Page 12: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails12jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=13Page 13button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=13 data-page=13 class=ts-thumb lazyload alt=Page 13: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails13jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=14Page 14button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=14 data-page=14 class=ts-thumb lazyload alt=Page 14: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails14jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=15Page 15button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=15 data-page=15 class=ts-thumb lazyload alt=Page 15: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails15jpg width=140 height=200 divdivdiv class=ts-pagebutton class=gotoPage data-page=16Page 16button div class=ts-imageimg data-url=-if-a-point-is-on-the-perpendicular-bisector-of-a-segment-then-write-anhtmlpage=16 data-page=16 class=ts-thumb lazyload alt=Page 16: · If a point is on the perpendicular bisector of a segment Then write an equation to how the relationships of Therefore point B is Form K equidistant from loading=lazy src=data:imagegifbase64iVBORw0KGgoAAAANSUhEUgAAAAIAAAACCAQAAADYv8WvAAAAD0lEQVR42mP8X8AwAgiABKBAv+vAXklAAAAAElFTkSuQmCC data-src=https:reader031vdocumentsnetreader031viewer20220220185b8a23a17f8b9a655f8da801html5thumbnails16jpg width=140 height=200 divdiv
