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Coding and Decoding

OLD

Direction (1-5):-

lend ka me ro money ve for di him se various la matters ba to yo

S1. Ans.(c) Sol. S2. Ans.(a) Sol. S3. Ans.(e) Sol. S4. Ans.(b) Sol. S5. Ans.(c) Sol.

NEW Direction (6-10):– S6. Ans.(d) Sol. @T5 #H5 *E4 %D6 S7. Ans.(b)

Sol. @Y7 S8. Ans.(e) Sol. *A3 %E4 @R5 #E4 S9. Ans.(c) Sol. @N5 #S6 *S5 %M4 S10. Ans.(b) Sol. %M7 @D4 Directions (11-13):


S11. Ans.(d) Sol. train is scheduled at = 5 hour 10 minute = #& Time should he leave to reach the station 5 minute earlier = 5 hour 10 minute-(25+5) minute= 4 hour 40 minute S12. Ans.(a) Sol. 4 hour 15 minute S13. Ans.(b) Sol. Scheduled time of departure of train= @%= 8:00 PM Time for travel+ early arrival= 4 hour 15 minutes + 25 minutes = 4 hour 40 minutes 8:00 PM- 4 hour 40 minutes= 3:20 PM= £$

Input and Output

Directions (14-18):

The machine rearranges one word and one number is each step. As for word, the words are arranged

in alphabetical order while for numbers, perfect square and non-perfect square come in each alternate

step in ascending order when starts from perfect square.

Input : ink 17 silent 100 burn 15 49 June 25 queen 64 3 firefox 20 time

Step I: burn 25 ink 17 silent 100 15 49 June queen 64 3 firefox 20 time

Step II: burn 25 firefox 3 ink 17 silent 100 15 49 June queen 64 20 time

Step III: burn 25 firefox 3 ink 49 17 silent 100 15 June queen 64 20 time

Step IV: burn 25 firefox 3 ink 49 June 15 17 silent 100 queen 64 20 time

Step V: burn 25 fireox 3 ink 49 June 15 queen 64 17 silent 100 20 time

Step VI: burn 25 firefox 3 ink 49 June 15 queen 64 silent 17 100 20 time

Step VII: burn 25 firefox 3 ink 49 June 15 queen 64 silent 17 time 100 20

S14. Ans.(b)

Sol.

S15. Ans.(b)

Sol.

S16. Ans.(b)

Sol.

S17. Ans.(a)

Sol.

S18. Ans.(b)

Sol.

Directions (19-20):


The alphabets are arranged according to the direction of arrows.

In step 3, the elements arranged in the first and third column in the same column in such way that the

element in third row placed in first row and first row element is placed in second row and second

row element is placed in third row. The alphabet of first row second column is replaced with the

alphabet which is placed three places after the alphabet in alphabetical series. The alphabet of third

row second column is replaced with the alphabet which is placed five places after the alphabet in

alphabetical series.

S19. Ans.(b)

Sol.


S20. Ans.(d)

Sol.

Directions (21-23):

S21. Ans. (d)

Sol.

For step-I, both the numbers of 1st block is written as, Ist number of

block-1 of the Input is multiplied with 2nd no. of block-4 of the Input

same as 2nd number of block-1 is multiplied with 1st number of

block-4. This process is same for Block-2 and Block-3 in step-1.

For step-II, All 1st digit of each block is added and that sum is written in 1st block and all 2nd digit of each block is added and that sum is written as 2nd block. For step-III, Half of the addition of 1st and 2nd digit of each block. For Step- IV, Subtraction of both numbers of Step-3. So, INPUT: 42 51 29 32 71 14

Step-1: 86 57 89 Step-2: ….21….22…. Step-3: ….1.5….2…. Step-4:…...0.5……

S22. Ans. (b) Sol.

For step-I, both the numbers of 1st block is written as, Ist number of block-1 of the Input is multiplied

with 2nd no. of block-4 of the Input same as 2nd number of block-1 is multiplied with 1st number of



For step-II, All 1st digit of each block is added and written in 1st block and all 2nd digit of each block is

added and written as 2nd block.

For step-III, Half of the addition of 1st and 2nd digit of each block.

For Step- IV, Subtraction of both numbers of Step-3.

So,

INPUT: 42 51 29 32 71 14

Step-1: 86 57 89

Step-2: ….21….22….

Step-3: ….1.5….2….

Step-4:…...0.5……

S23. Ans. (b)

Sol.

For step-I, both the numbers of 1st block is written as, Ist number of block-1 of the Input is multiplied

with 2nd no. of block-4 of the Input same as 2nd number of block-1 is multiplied with 1st number of


For step-II, All 1st digit of each block is added and written in 1st block and all 2nd digit of each block is

added and written as 2nd block.

For step-III, Half of the addition of 1st and 2nd digit of each block.

For Step- IV, Subtraction of both numbers of Step-3.

So,

INPUT: 42 51 29 32 71 14

Step-1: 86 57 89

Step-2: ….21….22….

Step-3: ….1.5….2….

Step-4:…...0.5……


Syllogism

Direction (24-28):

S24. Ans.(e)

Sol.

S25. Ans.(b)

Sol.

S26. Ans.(e)

Sol.

Directions (27-28):


S27. Ans.(d)

Sol.

S28. Ans.(b)

Sol.

Direction (29-30):

S29. Ans.(c) Sol.

S30. Ans.(a) Sol.

Puzzle (floor) Directions (31-25):

Person Colour Floor

P Sky Blue

II

Q Yellow IV

R Blue III

S Purple I

T Red V

U Green VII

V Pink VI

S31. Ans.(c) Sol.


S32. Ans.(a) Sol. S33. Ans.(b) Sol. S34. Ans.(b) Sol. S35. Ans.(c) Sol.

Directions (36-38):

FLOOR FLAT-1 FLAT-2 FLAT-3

THIRD L R P

SECOND O K M

FIRST Q A N

or

FLOOR FLAT-1 FLAT-2 FLAT-3

THIRD L R P

SECOND O A M

FIRST Q K N

S36. Ans.(d)

Sol.

S37. Ans.(a)

Sol.

S38. Ans.(c)

Sol.

Direction based puzzle(Latest):

S39. Ans.(b)

Sol. These questions are new pattern of direction which was asked in IBPS PO MAINS 2017. Before

starting with explanation of these question we want to make you understand this question. In this

question information is given like:

P*Q- Q or P is in the south direction of P or Q at distance of 6m. It means “Q is in the south of P at distance of 6m” Or “P is in the south of Q at distance of 6m” Step I: If A@$B$C*D is related to each other, point C is in south of point A, point A is vertically in line with point C, So, there can be two possible cases— Case:1-


Case-2:

Step II: C is the midpoint of AD, So, case-1 will get eliminated. Now with case-2

So, for distance between point B and D use pythagoras theorem BD2= BC2 + CD2


BD=√42 + 62

=√52 = 2√13 m

S40. Ans.(d) Sol. By using K@L$M*#N is related to each other, N is 6m to the west of K and M is in south-west of K so we get-

So, by using Pythagoras theorem the shortest distance between N and M is = √32 + 22

=√13 m

Figure based puzzle(Latest) Directions (41-45): Step I: First let us start with seating arrangement of the circle. Eight persons Abhay, Isha, Riya, Rahul, Piya, Diya, Sahil, Sanyam are sitting around the circle having eight vacant chairs. Four of them are facing towards the center while four are facing outside the center. Only two persons are sitting between Isha and Abhay. Sahil sits second right of Abhay. Rahul and

Sahil are immediate neighbours. Riya sits third left of Rahul. Both Abhay and Isha are facing outside the center. Rahul is facing opposite direction of Isha. Piya sits immediate right of Sahil who is facing same direction as Abhay. Sanyam sits second left of Riya. Both Sanyam and Piya are facing same direction.

Step II: Now, according to the given conditions - 1. Isha draws queen of Club, 2. Abhay draws Jack of Club and If card drawn is club, person remains on the same position facing opposite direction of current direction. So, Isha and Abhay remains on the same position facing opposite direction of current direction.


Step III: 3. Piya draws 3 of Spade, If the card drawn is spade, the person who draws first moves to position 5 facing opposite direction of current direction, then the second person who also draw spade moves to position 6, similarly 7 and 8. So, it is clear that Piya will move to position-5 and will now face outside the center. Further 4. Rahul draws a King of Diamond, If the card drawn is diamond, the person who draws first moves to corner 1 facing same direction, then the second person who also draw diamond moves to corner 2, similarly 3 and 4. So, it is clear that Rahul will move to corner-1 facing same direction.

Step IV: 5. Diya draws Ace of Heart, 6. Sahil draws 9 of Heart and If card drawn is heart, person remains on the same position facing same direction. So, both Diya and Sahil remains on the same position facing same direction. Further, Sanyam draws 7 of Diamond and If the card drawn is diamond, the person who draws first moves to corner 1 facing same direction, then the second person who also draw diamond moves to corner 2, similarly 3 and 4. Now, Sanyam will move to corner-2 facing same direction.


Step V: 8. Riya draws 4 of Spade, If the card drawn is spade, the person who draws first moves to position 5 facing opposite direction of current direction, then the second person who also draw spade moves to position 6, similarly 7 and 8. So, Riya will move to position-6 now facing outside the center. So, the final arrangement is----------

S41. Ans.(d) Sol. S42. Ans.(b) Sol. S43. Ans.(c) Sol. S44. Ans.(e) Sol. S45. Ans.(b) Sol.

Seating Arrangement

Directions (46-50)


S46. Ans.(e)

Sol.

S47. Ans.(c)

Sol.

S48. Ans.(c)

Sol.

S49. Ans.(d)

Sol.

S50. Ans.(a)

Sol.

Alpha Numeric

Directions (51 – 53):

S51. Ans.(c)

Sol.

Required number of letters = number of symbols + number of numerals

= 7+6

= 13

S52. Ans.(d)

Sol.

S53. Ans.(b)

Sol.


Directions (54-56):

S54. Ans.(b)

Sol.

S55. Ans.(b)

Sol.

S56. Ans.(e)

Sol.

Ranking and Direction

Directions (57–58):

S57. Ans.(e)

Sol. Atul is to the immediate left of Kunal and Prashant is to the north-east of Atul.

S58. Ans.(c)

Sol. Required Distance = NA+AK+KD+DP

= (25+40+60+90) m

= 215 m.

Inequalities

Direction (59-63)

S58. Ans.(a)

Sol. I. H>L(True) II.K>T(False)

S59. Ans.(e)

Sol. I.G


Sol. I.YS(False)

S62. Ans.(a)

Sol. I.V

| no. 1 app for banking & ssc preparation website: email · 2019. 7. 19. · 6 adda247 | no. 1 app...

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