1 circles and radian measure...the above relation gives us any easy way to convert between degrees...

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Fall 2016-MTH 06- D05-Trigonometry-Handout-5 1 Circles and Radian Measure So far we have been using degrees as our unit of measurement for angles. However, there is another way of measuring angles that is often more convenient. The idea is simple: associate a central angle of a circle with the arc that it intercepts. 1.1 Radian measure Consider a circle of radius r > 0. The circumference C of the circle is C = 2 π r, where π is an irrational number almost equal to 3.14159265.... O A B AB = 1 4 C = π 2 r 90 (a) θ = 90 O A B AB = 1 2 C = π r 180 (b) θ = 180 O A B AB = C = 2 π r 360 (c) θ = 360 Figure 1.1 Angle θ and intercepted arc AB on circle of circumference C = 2πr We see that a central angle of 90 cuts off an arc of length π 2 r, a central angle of 180 cuts off an arc of length π r, and a central angle of 360 cuts off an arc of length 2π r, which is the same as the circumference of the circle. 360 = 2π radians Formally, a radian is defined as the central angle in a circle of radius r which intercepts an arc of length r. This definition does not depend on the choice of r. O r r θ θ = 1 radian = 180 π degrees 57.3 . The above relation gives us any easy way to convert between degrees and radians: Degrees to radians: x degrees = π 180 · x radians Radians to degrees: x radians = 180 π · x degrees The statement θ = 2π radians is usually abbreviated as θ = 2π rad, or just θ = 2π when it is clear that we are using radians. When an angle is given as some multiple of π, you can assume that the units being used are radians.

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Page 1: 1 Circles and Radian Measure...The above relation gives us any easy way to convert between degrees and radians: Degrees to radians: x degrees = ³ π 180 ·x ´ radians Radians to

Fall 2016-MTH 06- D05-Trigonometry-Handout-5

1 Circles and Radian Measure

So far we have been using degrees as our unit of measurement for angles. However, there is

another way of measuring angles that is often more convenient. The idea is simple: associate

a central angle of a circle with the arc that it intercepts.

1.1 Radian measure

Consider a circle of radius r > 0. The circumference C of the circle is C = 2 π r, where π is an

irrational number almost equal to 3.14159265....

OA

B

�AB =14

C =π

2r

90◦

(a) θ = 90◦

OAB

�AB =12

C =π r

180◦

(b) θ = 180◦

O

A

B

�AB = C = 2π r

360◦

(c) θ = 360◦

Figure 1.1 Angle θ and intercepted arc �AB on circle of circumference C = 2πr

We see that a central angle of 90◦ cuts off an arc of length π

2r, a central angle of 180◦ cuts

off an arc of length π r, and a central angle of 360◦ cuts off an arc of length 2π r, which is the

same as the circumference of the circle.

360◦= 2π radians

Formally, a radian is defined as the central angle in a circle of radius r which intercepts an

arc of length r. This definition does not depend on the choice of r.

O r

r

θ

θ = 1 radian =180π

degrees ≈ 57.3◦.

The above relation gives us any easy way to convert between degrees and radians:

Degrees to radians: x degrees =

180· x

)radians

Radians to degrees: x radians =

(180

π· x

)degrees

The statement θ = 2π radians is usually abbreviated as θ = 2π rad, or just θ = 2π when it is

clear that we are using radians. When an angle is given as some multiple of π, you can assume

that the units being used are radians.

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MTH 06 Trig Notes (for Ojakian's class)
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Example

1. Convert 18◦ to radians.

2. Convert π

9radians to degrees.

Conversion between degrees and radians for some common angles:

Table 1 Commonly used angles in radians

Degrees Radians Degrees Radians Degrees Radians Degrees Radians

0◦ 0 90◦π

2180◦ 270◦

π

6120◦

6300◦

45◦3π

4225◦ 315◦

π

3150◦

3

11π

6

The default mode in most scientific calculators is to use degrees for entering angles. On

many calculators there is a button labeled✄

✁DEG for switching between degree mode and ra-

dian mode. On some graphing calculators, such as the the TI-83, there is a✄

✁MODE button for

changing between degrees and radians. Make sure that your calculator is in the correct angle

mode before entering angles. For example,

sin 4◦= 0.0698 ,

sin (4 rad) = −0.7568 ,

so the values are not only off in magnitude, but do not even have the same sign. Using your

calculator’s✄

✁sin−1 ,✄

✁cos−1 , and✄

✁tan−1 buttons in radian mode will of course give you the angle as

a decimal, not an expression in terms of π.

1.2 Arc length

We have seen that one revolution has a radian measure of 2π rad. Note that 2π is the ratio of

the circumference (i.e. total arc length) C of a circle to its radius r:

Radian measure of 1 revolution = 2π =

2π r

r=

C

r=

total arc length

radius

Clearly, that ratio is independent of r. In general, the radian measure of an angle is the ratio

of the arc length cut off by the corresponding central angle in a circle to the radius of the circle,

independent of the radius.

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To see this, recall our formal definition of a radian: the central angle in a circle of radius r

which intercepts an arc of length r. So suppose that we have a circle of radius r and we place

a central angle with radian measure 1 on top of another central angle with radian measure 1,

as in Figure 1.2(a). Clearly, the combined central angle of the two angles has radian measure

1+1= 2, and the combined arc length is r+ r =2r.

r

r

11

2

r

(a) 2 radians

r/2

r/2

1/2

1

r

(b)12

radian

Figure 1.2 Radian measure and arc length

Now suppose that we cut the angle with radian measure 1 in half, as in Figure 1.2(b).

Clearly, this cuts the arc length r in half as well. Thus, we see that

Angle = 1 radian ⇒ arc length = r ,

Angle = 2 radians ⇒ arc length =

Angle =12

radian ⇒ arc length =

and in general, for any θ ≥ 0,

Angle = θ radians ⇒ arc length = θ r ,

so that

θ =

arc length

radius.

O r

s= rθ

θ

(a) Angle θ, radius r

O r′

s= r′θ

θ

(b) Angle θ, radius r′

Figure 1.3 Circles with the same central angle, different radii

We thus get a simple formula for the length of an arc:

In a circle of radius r, let s be the length of an arc intercepted by a central angle with

radian measure θ ≥ 0. Then the arc length s is:

s = rθ

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Example

1. In a circle of radius r = 2 cm, what is the length s of the arc intercepted by a central angle

of measure θ= 1.2 rad ?

2. In a circle of radius r =10 ft, what is the length s of the arc intercepted by a central angle of

measure θ= 41◦ ?

3. A central angle in a circle of radius 5 m cuts off an arc of length 2 m. What is the measure

of the angle in radians? What is the measure in degrees?

4. A rope is fastened to a wall in two places 8 ft apart at the same height. A cylindrical

container with a radius of 2 ft is pushed away from the wall as far as it can go while being

held in by the rope, as in the following figure which shows the top view. If the center of the

container is 3 feet away from the point on the wall midway between the ends of the rope, what

is the length L of the rope?

2

A

B

D CE3

4

4

θ

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Workbook problems: p. 101-104: 5,6,7,8,9,12
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Fall 2016-MTH 06- D05-Trigonometry-Handout-1

1 Trigonometric Ratios

Trigonometry is the study of the relations between the sides and angles of triangles. The

word “trigonometry” is derived from the Greek words trigono, meaning “triangle”, and metro,

meaning “measure”.

1.1 Angles

From elementary geometry:

An angle is formed by two rays (called the sides or arms of the angle), sharing a common

endpoint (called the vertex of the angle).

A degree, usually denoted by ◦ (the degree symbol), is a measurement of plane angle, repre-

senting 1360

of a full rotation.

Cvertex Aside

B

side

(a) angle ∠A,∠CAB

0◦

15◦

30◦

45◦

60◦75◦90◦

105◦

120◦

135◦

150◦

165◦

180◦

195◦

210◦

225◦

240◦

255◦

270◦285◦300◦

315◦

330◦

345◦

O

(b)angles in degree measurement

Instead of using the angle notation ∠A to denote an angle, we will sometimes use just a cap-

ital letter by itself (e.g. A, B, C) or a lowercase variable name (e.g. a, b, c). It is also common

to use letters (either uppercase or lowercase) from the Greek alphabet to represent angles. For

example:

Letters Name Letters Name Letters Name

A α alpha B β beta Γ γ gamma

Θ θ theta Φ φ phi Σ σ sigma

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Types of angles:

(a) An angle is acute if it is between 0◦ and 90◦.

(b) An angle is a right angle if it equals 90◦.

(c) An angle is obtuse if it is between 90◦ and 180◦.

(d) An angle is straight if it equals 180◦.

(a) angle (b) angle (c) angle (d) angle

Example:

• The angle 30◦ is

• The angle 45◦ is

• The angle 120◦ is

Types of pair of angles:

(a) Two acute angles are complementary if their sum equals 90◦.

(b) Two angles between 0◦ and 180◦ are supplementary if their sum equals 180◦.

(c) Two angles between 0◦ and 360◦ are conjugate (or explementary) if their sum equals

360◦.

∠A

∠B

(a) complementary

∠A

∠B

(b) supplementary

∠A∠B

(c) conjugate

Figure 1.1 Types of pairs of angles

Example:

• The angle 30◦ and the angle are complementary

• The angle is complementary to itself

• The angle 45◦ and the angle are supplementary

• The angle 300◦ is the conjugate angle of

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1.2 Triangles

A triangle has three sides and three interior angles. We have learned that the sum of the

interior angles in a triangle equals 180◦.

• Acute trianlges – triangles in which the measures of all three angles are less than 90◦.

• Right triangles – triangles in which the measure of one angle equals 90◦. Note that the

other two angles are acute angles whose sum is 90◦ (i.e. the other two angles are comple-

mentary angles).

• Obtuse triangles – triangles in which the measure of one angle is greater than 90◦.

Example:

For each triangle below, determine the unknown angle(s):

α

65◦ 70◦

53◦

α α α

Triangles are similar if their corresponding angles are equal, and that similarity implies

that corresponding sides are proportional. We can also classify triangles according to the sides:

• Equilateral trianlges – triangles in which all three sides have the same length.

• Isosceles triangles – triangles in which two of the sides have the same length.

• Scalene triangles – triangles without two equal sides.

Example:

1. Draw an Equilateral Triangle. What are the three interior angles?

2. Draw a Right Isosceles Triangle (has a right angle 90◦ and also two equal angles). What

are the equal angles?

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1.3 Trigonometric Ratios for Acute Angles

In a right triangle, the side opposite the right angle is called the hypotenuse, and the other

two sides are called its legs.

A C

B

badjacent

a

op

posite

Pythagorean Theorem says:

a2+ b2

=

chypot

enuse

Consider a right triangle △ABC, with the right angle at C and with lengths a, b, and c, as

in the figure on the right. For the acute angle A, call the leg BC its opposite side, and call

the leg AC its adjacent side.

The ratios of sides of a right triangle occur often enough in practical applications to warrant

their own names, so we define three basic trigonometric ratios of A as follows:

Name of ratio Abbreviation Definition

sine A sin A =opposite side

hypotenuse=

a

c

cosine A cos A =adjacent side

hypotenuse=

tangent A tan A =opposite side

adjacent side=

Notice that we have

tan A =sin A

cos A

The three basic trig ratios can be easily remembered using the acronynm SOHCAHTOA.

The other three trigonometric ratios, cosecant, secant and cotangent, are defined in terms of

the first three:

Name of ratio Abbreviation Definition

cosecant A csc A =hypotenuse

opposite side=

1

sin A

secant A sec A =hypotenuse

adjacent side=

1

cotangent A cot A =adjacent side

opposite side=

1

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Example

For the right triangle △ABC, find the values of all six trigonometric ratios of the acute angles

A and B.

A C

B

4

3?

Example Find the value of each trigonometric ratio.

1.

A C

B

8

6

sin A =

cos A =

tan A =

sinB =

cosB =

tanB =

2.

β

12α

13

sinα=

cosα=

tanα=

sinβ=

cosβ=

tanβ=

3.

β

4

α

2

sinα=

cosα=

tanα=

sinβ=

cosβ=

tanβ=

Question: Can the sine of an angle ever equal 2? How about cosine? tangent?

Note that when calculating the trigonometric functions of an acute angle A, you may use

any right triangle which has A as one of the angles.

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Example

1. Find the values of all six trigonometric ratios of 45◦.

A

B

C

1

1

1

1

45◦

2. Find the values of all six trigonometric ratios of 60◦.

A

B

C1 1

60◦ 60◦

30◦

2

3. Find the values of all six trigonometric ratios of 30◦.

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You may have noticed the connections between the sine and cosine, secant and cosecant,

and tangent and cotangent of the complementary angles in the examples. Actually we have

the following theorem.

Cofunction Theorem: If A and B are the complementary acute angles in a right triangle

△ABC, then the following relations hold:

sin A = cos B sec A = csc B tan A = cot B

sin B = cos A sec B = csc A tan B = cot A

Example

1. sin45◦ =

2. sin60◦ =

3. tan30◦ =

3. cos15◦ =

Given one trig ratio of an acute angle we can work out the others. In general it helps to draw

a right triangle to solve problems of this type.

Example

1. Suppose α is an acute angle such that sinα=23. Find the values of the other trigonometric

ratios of α.

α

2

b

3

2. Suppose β is an acute angle such that cosβ=15. Find the values of the other trigonometric

ratios of β.

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3. Suppose γ is an acute angle such that cotγ= 2. Find the values of the other trigonometric

ratios of γ.

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See workbook problems: p. 89, 90
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p. 4,5: Problem 14 (Distance Formula)
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Fall 2016-MTH 06- D05-Trigonometry-Handout-2

1 Applying Right Triangles

We will use trigonometry to find the missing elements of a right triangle and solve application

problems involving right triangles.

1.1 Find missing elements of a right triangle

Basic strategy:

• Decide on the acute angle/ two sides with which we will work

• Identify the two sides as opposite, adjacent, or hypotenuse with respect to the angle we

chose

• Determine the trig ratio which relates the chosen angle and sides

• Write an equation using the ratio and solve the equation

Example

1. Find a and c in the given triangle.

2

c

a

60◦

30◦

2. Find a and b in the given triangle.

a

b

10

37◦

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Workbook problems: p.
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92,93: #1, #2
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1.2 Solve application problems involving right triangles

Angle of elevation or depression:

object

object

angle of elevation

angle of depression

Example

1. A 30-ft ladder leans against a building so the the angle between the ground and the lad-

der is 62◦. How high does the ladder reach on the building?

h30

62◦

2. A blimp 4280 ft above the ground measures an angle of depression of 24◦ from its hori-

zontal line of sight to the base of a house on the ground. Assuming the ground is flat, how far

away along the ground is the house from the blimp?

24◦

4280

θ

x

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Workbook problems: p.93,94- problems #3,#4,#5
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3. A person standing 400 ft from the base of a mountain measures the angle of elevation

from the ground to the top of the mountain to be 25◦. The person then walks 500 ft straight

back and measures the angle of elevation to now be 20◦. How tall is the mountain?

h

500 400 x

20◦ 25◦

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Fall 2016-MTH 06- D05-Trigonometry-Handout-3

1 Trigonometric Functions and Cartesian Coordinates

1.1 Definition of a general angle

To define the trigonometric functions of any angle - including angles less than 0◦ or greater

than 360◦ - we need a more general definition of an angle.

We say that an angle is formed by rotating a ray−−→OA about the endpoint O (called the

vertex), so that the ray is in a new position, denoted by the ray−−→OB. The ray

−−→OA is called the

initial side of the angle, and−−→OB is the terminal side of the angle.

AOinitial side

B

term

inal

side

(a) angle ∠AOB

counter-clockwise

direction (+)

clockwise

direction (−)A

O

B

(b) positive and negative angles

If the rotation is counter-clockwise then we say that the angle is positive, and the angle is

negative if the rotation is clockwise.

One full counter-clockwise rotation of−−→OA back onto itself (called a revolution), so that the

terminal side coincides with the initial side, is an angle of 360◦; in the clockwise direction

this would be −360◦. Not rotating−−→OA constitutes an angle of 0◦. More than one full rotation

creates an angle greater than 360◦. For example, notice that 30◦ and 390◦ have the same

terminal side, since 30+360= 390.

30◦

390◦

1.2 Trigonometric functions and Cartesian coordinates

Recall that the xy-coordinate plane consists of points denoted by pairs (x, y) of real numbers.

The first number, x, is the point’s x coordinate, and the second number, y, is its y coordi-

nate. The x and y coordinates are measured by their positions along the x-axis and y-axis,

respectively, which determine the point’s position in the plane. This divides the xy-coordinate

plane into four quadrants (denoted by QI, QII, QIII, QIV), based on the signs of x and y.

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x

y

0

QI

x > 0

y> 0

QII

x < 0

y> 0

QIII

x < 0

y< 0

QIV

x > 0

y< 0

(a) Quadrants I-IV

x

y

0

(2,3)

(−3,2)

(−2,−2)(3,−3)

(b) Points in the plane

x

y

0

θ

r

(x, y)

(c) Angle θ in the plane

Let θ be any angle. We say that θ is in standard position if its initial side is the positive

x-axis and its vertex is the origin (0,0).

Pick any point (x, y) on the terminal side of θ a distance r > 0 from the origin.

r =

We will define the trigonometric functions of θ as follows:

sin θ =y

rcos θ = tan θ =

csc θ = sec θ = cot θ =

As in the acute case, by the use of similar triangles these definitions are well-defined (i.e. they

do not depend on which point (x, y) we choose on the terminal side of θ). Also, notice that

|sin θ| ≤ 1 and |cos θ| ≤ 1, since |y| ≤ r and |x| ≤ r in the above definitions.

Notice that in the case of an acute angle these definitions are equivalent to our earlier defini-

tions in terms of right triangles: draw a right triangle with angle θ such that x = adjacent side,

y = opposite side, and r = hypotenuse. For example, this would give us sin θ = yr= opposite

hypotenuse

and cos θ = xr= adjacent

hypotenuse, just as before.

The following figure summarizes the signs (positive or negative) for the trigonometric func-

tions based on the angle’s quadrant:

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x

y

0

θr

hyp

oten

use

(x, y)

x

adjacent side

y

opposite side

(a) Acute angle θ

x

y

0

QI

0◦ < θ < 90◦QII

90◦ < θ < 180◦

QIII

180◦ < θ < 270◦QIV

270◦ < θ < 360◦

0◦

90◦

180◦

270◦

(b) Angles by quadrant

Figure 1.1

x

y

0

QI

sin +cos +tan +csc +sec +cot +

QII

sin +cos −tan −csc +sec −cot −

QIII

sin −cos −tan +csc −sec −cot +

QIV

sin −cos +tan −csc −sec +cot −

Figure 1.2 Signs of the trigonometric functions by quadrant

In general, if two angles differ by an integer multiple of 360◦ then they have the same initial

and terminal sides. Hence each trigonometric function will have equal values at both angles.

Angles such as these, which have the same initial and terminal sides, are called coterminal.

Example

1. Find five angles coterminal with 30◦.

2. Identify the angle that is not coterminal with the others

−120◦,600◦,−480◦,180◦,240◦

3. sin(390◦)= , cos(−315◦)= , tan(405◦)=

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Workbook problems: p.99,100: #5, #7
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The values of trigonometric functions of an angle θ larger than 90◦ can be found by using a

certain acute angle as part of a right triangle. That acute angle has a special name: if θ is a

nonacute angle then we say that the reference angle for θ is the acute angle formed by the

terminal side of θ and either the positive or negative x-axis.

Example

1. Let θ= 928◦.

(a) Which angle between 0◦ and 360◦ has the same terminal side

(and hence the same trigonometric function values) as θ ?

(b) What is the reference angle for θ ?

28◦

x

y

0

208◦

928◦

2. Draw the given angle in standard position and find the reference angle.

(a) 120◦ (b) 135◦ (c) −45◦

(a) −120◦ (b) 210◦ (c) 330◦

3. Find the exact values of all six trigonometric functions of 120◦.

x

y

0

120◦p

3

1

2

(−1,p

3)

60◦

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4. Find the exact values of all six trigonometric functions of 225◦.

x

y

0

225◦

1

1

p2

(−1,−1)

45◦

5. Find the exact values of all six trigonometric functions of 330◦.

x

y

0

330◦ 1

p3

2

(p

3,−1)

30◦

6. Find the exact values of all six trigonometric functions of 0◦, 90◦, 180◦, and 270◦.

x

y

0

0◦

(1,0)

90◦(0,1)

180◦

(−1,0)

270◦(0,−1)

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The following table summarizes the values of the trigonometric functions of angles between

0◦ and 360◦ which are integer multiples of 30◦ or 45◦:

Table 1 Table of trigonometric function values

Angle sin cos tan csc sec cot

0◦ 0 1 0 undefined 1 undefined

30◦ 12

p3

2

p3

32 2

p3

3

p3

45◦

60◦

90◦

120◦

135◦

150◦

180◦

210◦

225◦

240◦

270◦

300◦

315◦

330◦

Example

1. Suppose that cos θ=−45. Find the exact values of sin θ and tan θ.

x

y

0

θ3

4

5

(−4,3)

(a) θ in QII

x

y

0

θ

3

4

5

(−4,−3)

(b) θ in QIII

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2. Suppose that θ in the second quadrant and sin θ = 13

. Find the exact values of cos θ and

tan θ.

3. Suppose that θ in the fourth quadrant and tan θ = −2 . Find the exact values of sin θ and

cos θ.

4. Suppose that θ in the third quadrant and csc θ =−1312

. Find the exact values of sin θ, cos θ

and tan θ.

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Fall 2016-MTH 06- D05-Trigonometry-Handout-6

1 Unit Circle and Trignometric Functions

1.1 Unit circle

The unit circle is the circle of radius 1 in the xy-plane consisting of all points (x, y) which satisfy

the equation x2 + y2 = 1.

x

y

s= rθ = θ1

θ

10

(x, y)= (cos θ,sin θ)x2 + y2 = 1

Each real number θ also corresponds to a central angle (in standard position) whose radian

measure is θ.

1.2 Unit circle and Trignometric Functions

Definitions of Trignometric Functions

Let θ be a real number and let (x, y) be the point on the unit circle corresponding to θ.

sin θ = y cos θ = x tan θ =y

x, x 6= 0

csc θ =1

y, y 6= 0 sec θ =

1

x, x 6= 0 cot θ =

x

y, y 6= 0

The unit circle has been divided into 8 equal arcs, corresponding to θ-values of 0, π4

, π2

, 3π4

,π, 5π4

, 3π2

, 7π4

and 2π.

x

y

(1,0)0

(p

22

,p

22

)(0,1)

(−p

22

,p

22

)

(−1,0)

(−p

22

,−p

22

)(0,−1)

(p

22

,−p

22

)

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The unit circle has been divided into 12 equal arcs, corresponding to θ-values of

0, π6

, π3

, π2

, 2π3

, 5π6

,π, 7π6

, 4π3

, 3π2

, 5π3

, 11π6

and 2π.

x

y

0◦

30◦

60◦90◦

120◦

150◦

180◦

210◦

240◦

270◦300◦

330◦

360◦

π

6

π

4

π

3

π

22π3

3π4

5π6

π

7π6

5π4

4π3

3π2

5π3

7π4

11π6

(p3

2, 1

2

)

(p2

2,p

22

)

(

12,p

32

)

(

−p

32

, 12

)

(

−p

22

,p

22

)

(

−12,p

32

)

(

−p

32

,−12

)

(

−p

22

,−p

22

)

(

−12,−

p3

2

)

(p3

2,−1

2

)

(p2

2,−

p2

2

)

(

12,−

p3

2

)

(−1,0) (1,0)

(0,−1)

(0,1)

Example

1. Evaluate sinθ, cosθ, tanθ when θ = 0,π, π3

, π2

, 5π4

, 11π6

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2. Evaluate the following:

sin π

6+cos 2π

3=

tan π

4+cot 7π

4=

sin2 π

3+cos2 π

3=

sin2 π

4+cos2 π

4=

1+ tan2 5π6=

sec2 5π6=

tan 9π4+cos π

3=

sin 21π6

+cos(−2π3

)=

2sin π

6cos π

6=

1−cos π

3

2=

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Evaluate trig functions at angles: 8pi/3, 8pi, 3pi, -17pi/4
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Fall 2016-MTH 06- D05-Trigonometry-Handout-7

1 Graphing the Trignometric Functions

The trigonometric functions can be graphed just like any other function, as we will now show.

In the graphs we will always use radians for the angle measure.

1.1 Unit circle

The unit circle is the circle of radius 1 in the xy-plane consisting of all points (x, y) which satisfy

the equation x2 + y2 = 1.

x

y

s= rθ = θ1

θ

10

(x, y)= (cos θ,sin θ)x2 + y2 = 1

We see from the unit circle that any point on the unit circle has coordinates (x, y)= (cos θ, sin θ),

where θ is the angle that the line segment from the origin to (x, y) makes with the positive

x-axis (by definition of sine and cosine). So as the point (x, y) goes around the circle, its y-

coordinate is sin θ.

We thus get a correspondence between the y-coordinates of points on the unit circle and

the values f (θ) = sin θ, as shown by the horizontal lines from the unit circle to the graph of

f (θ)= sin θ for the angles θ = 0, π

6, π

3, π

2:

θ

f (θ)

0

1

π

22π3

5π6

π

f (θ)= sin θ

π

6

π

3

π

2

01

1

x2+ y2 = 1

θ

Figure 1.1 Graph of sine function based on y-coordinate of points on unit circle

We can extend the above picture to include angles from 0 to 2π radians. This illustrates the

unit circle definition of the sine function.

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θ

f (θ)

0

−1

1

π

22π3

5π6

π 5π4

3π2

7π4

f (θ)= sin θ

x

y

1

x2+ y2 = 1

θ

Figure 1.2 Unit circle definition of the sine function

Since the trigonometric functions repeat every 2π radians (360◦), we get, for example, the

following graph of the function y= sin x for x in the interval [−2π,2π]:

x

y

0

−1

1

π

23π4

π 5π4

3π2

7π4

2π−π

4−

π

2−3π4

−π−

5π4

−3π2

−7π4

−2π

y= sin x

Figure 1.3 Graph of y= sin x

To graph the cosine function, we could again use the unit circle idea (using the x-coordinate

of a point that moves around the circle), but there is an easier way. Recall from Section 1.5

that cos x = sin (x+90◦) for all x. So cos 0◦ has the same value as sin 90◦, cos 90◦ has the same

value as sin 180◦, cos 180◦ has the same value as sin 270◦, and so on. In other words, the

graph of the cosine function is just the graph of the sine function shifted to the left by 90◦ =π/2

radians, as in Figure 1.4:

x

y

0

−1

1

π

23π4

π 5π4

3π2

7π4

2π−π

4−

π

2−3π4

−π−

5π4

−3π2

−7π4

−2π

y= cos x

Figure 1.4 Graph of y= cos x

1.2 Amplitude and Period of Sine/Cosine Functions

Recall that the domain of a function f (x) is the set of all numbers x for which the function

is defined. For example, the domain of f (x) = sin x is the set of all real numbers, whereas the

domain of f (x) = tan x is the set of all real numbers except x =±π

2, ± 3π

2, ± 5π

2, .... The range

of a function f (x) is the set of all values that f (x) can take over its domain. For example, the

range of f (x) = sin x is the set of all real numbers between −1 and 1 (i.e. the interval [−1,1]),

the range of f (x) = cos x is the set of all real numbers between −1 and 1 (i.e. the interval

[−1,1]), whereas the range of f (x)= tan x is the set of all real numbers.

We know that −1≤ sin x ≤ 1 and −1≤ cos x≤ 1 for all x. Thus, for a constant A 6= 0,

−|A | ≤ A sin x ≤ |A | and −|A | ≤ A cos x ≤ |A |

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for all x. In this case, we call |A | the amplitude of the functions y= A sin x and y= A cos x. In

general, the amplitude of a periodic curve f (x) is half the difference of the largest and smallest

values that f (x) can take:

Amplitude of f (x) =(maximum of f (x)) − (minimum of f (x))

2

In other words, the amplitude is the distance from either the top or bottom of the curve to the

horizontal line that divides the curve in half.

x

y

0

|A |

−|A |

π

23π4

π 5π4

3π2

7π4

2 |A |

|A |

|A |

Figure 1.5 Amplitude =max−min

2=

|A |−(−|A |)2

= |A |

A function f (x) is periodic if there exists a number p > 0 such that x+ p is in the domain of

f (x) whenever x is, and if the following relation holds:

f (x+ p) = f (x) for all x (1)

There could be many numbers p that satisfy the above requirements. If there is a smallest

such number p, then we call that number the period of the function f (x).

Example

Find the amplitude/period of each function and sketch the graph for x in [−2π,2π]

1. f (x)= 2sin x, x ∈ [−2π,2π]

Amplitude: 2; Period: 2π.

x

y

0

−2

2

π

23π4

π 5π4

3π2

7π4

2π−π

4−π

2− 3π4

−π− 5π

4− 3π

2− 7π

4−2π

y= 2sin x

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2. f (x)=−sin x

x

y

0

−1

1

π

23π4

π 5π4

3π2

7π4

2π−π

4−

π

2−3π4

−π−

5π4

−3π2

−7π4

−2π

3. f (x)= 2cos x

x

y

0

−2

2

π

23π4

π 5π4

3π2

7π4

2π−π

4−

π

2−3π4

−π−

5π4

−3π2

−7π4

−2π

4. f (x)=−3cos x

x

y

0

−3

3

π

23π4

π 5π4

3π2

7π4

2π−π

4−

π

2−3π4

−π−

5π4

−3π2

−7π4

−2π

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Workbook- p. 111: Problems 1,2,3,4
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Fall 2016-MTH 06- D05-Trigonometry-Handout-8

1 Basic Trigonometric Identities

So far we know a few relations between the trigonometric functions. For example, we know

the reciprocal relations:

1. csc θ =1

sin θwhen sin θ 6= 0

2. sec θ =1

cos θwhen cos θ 6= 0

3. cot θ =1

tan θwhen tan θ is defined and not 0

4. sin θ =1

csc θwhen csc θ is defined and not 0

5. cos θ =1

sec θwhen sec θ is defined and not 0

6. tan θ =1

cot θwhen cot θ is defined and not 0

Notice that each of these equations is true for all angles θ for which both sides of the equation

are defined. Such equations are called identities, and in this section we will discuss several

trigonometric identities, i.e. identities involving the trigonometric functions. These identities

are often used to simplify complicated expressions or equations. For example, one of the most

useful trigonometric identities is the following identity we have seen earlier:

tan θ =sin θ

cos θwhen cos θ 6= 0

To prove this identity, pick a point (x, y) on the terminal side of θ a distance r > 0 from the

origin, and suppose that cos θ 6= 0. Then x 6= 0 (since cos θ=xr), so by definition

sin θ

cos θ=

y

rx

r

=y

x= tan θ .

Note how we proved the identity by expanding one of its sides ( sin θ

cos θ) until we got an expression

that was equal to the other side (tan θ). This is probably the most common technique for

proving identities. Taking reciprocals in the above identity gives:

cot θ =cos θ

sin θwhen sin θ 6= 0

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One of the most important trigonometric identities is the Pythagorean identity. Let θ be

any angle with a point (x, y) on its terminal side a distance r > 0 from the origin. By the

Pythagorean Theorem, r2 = x2 + y2 (and hence r =√

x2 + y2). For example, if θ is in QIII, then

the legs of the right triangle formed by the reference angle have lengths |x| and |y| (we use

absolute values because x and y are negative in QIII). The same argument holds if θ is in the

other quadrants or on either axis. Thus,

r2= |x|2 + |y|2 = x2

+ y2 ,

so dividing both sides of the equation by r2 (which we can do since r > 0) gives

r2

r2=

x2 + y2

r2=

x2

r2+

y2

r2=

( x

r

)2+

( y

r

)2.

Since r2

r2 = 1, xr= cos θ, and

yr= sin θ, we can rewrite this as:

cos2θ + sin2

θ = 1

Note that we use the notation sin2θ to mean (sin θ)2, likewise for cosine and the other

trigonometric functions.

From the above identity we can derive more identities. For example:

sin2θ = 1 − cos2

θ

cos2θ = 1 − sin2

θ

from which we get (after taking square roots):

sin θ = ±

1 − cos2 θ

cos θ = ±

1 − sin2θ

In formula cos2θ + sin2

θ = 1, dividing both sides of the identity by cos2θ gives

cos2θ

cos2 θ+

sin2θ

cos2 θ=

1

cos2 θ,

so since tan θ=sin θ

cos θand sec θ =

1cos θ

, we get:

1 + tan2θ = sec2

θ

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Likewise, dividing both sides of the Pythagorean identity by sin2θ gives

cos2θ

sin2θ

+sin2

θ

sin2θ

=1

sin2θ

,

so since cot θ =cos θ

sin θand csc θ =

1sin θ

, we get:

cot2θ + 1 = csc2

θ

Example

1. Prove that cos2θ tan2

θ = sin2θ.

2. Prove that 5sin2θ + 4cos2

θ = sin2θ + 4.

3. Prove that tan θ + cot θ = sec θ csc θ .

4. Prove that1 + cot2

θ

sec θ= csc θ cot θ .

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5. Prove thattan2

θ + 2

1 + tan2θ

= 1 + cos2θ .

6. Prove that1 + sin θ

cos θ=

cos θ

1 − sin θ.

7. Prove that1 − tan θ

1 + tan θ=

cot θ − 1

cot θ + 1

8. Prove that cos4θ−sin4

θ = 1−2sin2θ

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Workbook- p.
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112: 1,2,3,4
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