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3 Measurement __ /__ pts First Last Name___Per__ Anticipatory Response Final Cornell Question & Ans Answers Directions: Make 5 questions 1. Lincoln knew Bob Marley. & answers that are different 2. Gigameter is bigger than Km. than the Anticipatory Response 3. Base units are 1m, 1L, & 1g. 1. 4. Mega means 1 million. 5. Mega means 10 6 6. Kilo means 10 3 . 7. Deci is like diez meaning 1/10. Give Giga 10 9 Me Mega 10 8 Knowledge K 10 2. brother d 3. c 4. m m n Anticipatory Response Final Answers 1. 3.04 km x 1000m = 3,004 m 1 km 5. 2. 3,210 Gg x 10 6 g =3.210x10 6 g 1 Gg 3. 1.234 m = 1,234 Km Summary Section 1 1 corrected by: x____________________

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3 Measurement                                __ /__ pts First Last Name___Per__ 

Anticipatory Response Final    Cornell Question & Ans   Answers    Directions:Make 5 questions1. Lincoln knew Bob Marley.        & answers that are different2. Gigameter is bigger than Km.        than the Anticipatory Response3. Base units are 1m, 1L, & 1g.        1. 4. Mega means 1 million.         5. Mega means 10 ‐6         6. Kilo means 103.         7. Deci is like diez meaning 1/10.         Give                   Giga       109       Me                       Mega     108      Knowledge         K             10     2. brother       

 

                              

d      3. c       

 

                                  4. 

m       m      n       Anticipatory Response  Final       Answers     1.  3.04 km x 1000m = 3,004 m                                 1 km        5.                                               2. 3,210 Gg x 106 g  =3.210x106 g                                    1 Gg                         3. 1.234 m                    = 1,234 Km       Summary Section   

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1corrected by: x____________________

T G M K b d c m μ n Tera Giga Mega Kilo Base deci Centi Milli Micro nano Trill. Billion Million Thousand 1 1/10 1/100 1/1000 1/million 1/billion 1012 109 106 103 10 0 10 -1 10 -2 10 -3 10 -6 10 -9 Tg Tm TL Ts TW Tb

Gg Gm GL Gb

Mg Mm ML Mb

Kg Km KL Ks Kwatts Kb

1gram 1meter 1 liters

Second Watts byte

dg dm dL

cg cm cL

mg mm mL m s

μ g μ m μ L

ng nm nL

Directions: Fill in each box with the an appropriate answer or question?

1 1.234 Gb = Kb An acquaintance sells you a laptop with 1.234 Gbytes of memory. How many Kbytes is that? =

2 600.01 Gb = Tb A Best Buy sales rep. is trying to sell you 600.01 Gb of memory. How many TeraBytes is that? =

3 0.0594 Tb = Gb Radio Shack says that they have a computer with 0.0594 Tb of RAM. How many Gb is that? =

4 2.204x10-4 Tb = Kb On Craiglist someone is selling a 1.204x10-4 Tb “Thumb Drive”. How many Kbytes does it hold. =

5 4.5 Gb = In Walmart you see a 4.5 Gb hard drive computer. How many Mbytes is that? =

6 53.5 Gb = Kb In Walmart__________________________________ = 7 = Gb In a computer store you see at 1.356 x 103 Kb drive.

How many________________________________? = 8 = How many GL are in a 2.0 Liter bottle of Soda? = 9 32.04x10-4 Gg = How many grams are in 32.04x10-4 Gg of salt? = 10 1.5 x 10-4 Tg = A 1.5 x 10-4 Tg of Carbon is equal to how many

grams of Carbon? = 11 1.5 x 104 g C = Kg C How many Kg of Carbon _______________________ = 12 = How many Tb are 3,129,000 Kb? = 13 13.42 Kb = Gb How many Gb_______________________________ = 14 .00204x104Kb = How many Gb are in __________________________ =

Directions: Show work and make the appropriate lines and conversions. 15. How many Kg are in 1.5 x 106 g Carbon? 16. How many btyes are in 1.5 x 103 Mbytes of memory? 17. How many Liters are in 1.5 x 10-3 KL of memory?

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2 Corrected by:X_______________

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2corrected by: x____________________

T G M K b d c m μ n Giga Mega Kilo Base deci Centi Milli Micro nano Billion Million Thousand 1 1/10 1/100 1/1000 1/million 1/billion 109 106 103 10 0 10 -1 10 -2 10 -3 10 -6 10 -9

Gg Gm GL

Mg Mm ML

Kg Km KL

Ks Kwatts

1gram

1meter

1 liters

Second watts

dg dm dL

cg cm cL

mg mm mL

m s

μ g μ m μ L

ng nm nL

1 1.234 GL = KL 16 12,001 KL = ML = = 2 600.01 GL = mL 17 0.0594 mL = cL = = 3 0.0594 GL = dL 18 1.234 dL = L = = 4 1.234 ML = KL 19 345 KL = L = = 5 0.0103ML = L 20 600.01 L = KL = = 6 4.3x 104ML = nL 21 12,001 nL = ML = = 7 6.7x 10-9Kg = dg 22 0.0594 dg = g = = 8 12,001 Kg = cg 23 0.0103 cg = Kg = = 9 600.01Km = µm 24 140x10-3µm = Gm = = 10 0.0594 Kg = g 25 1.234 g = mg = = 11 4.3x 104 L = nL 26 600.01 cm = L = = 12 1.234 mm = m 27 6.4x 10-3mL = L = = 13 0.064x10-3g = Kg 28 144x10-3ms = Ks = = 14 0.0103 m = mm 29 12,001 sec = m-s = = 15 94x 103 Gb = Kbyte 30 600 T bytes = bytes = =

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3 Corrected by:X_______________

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3corrected by: x____________________

Metric Conversions 1. Convert the following to km:

1600.0 m _______= _______ 2050 cm_______ = _______ 1.033 Mm_______ = ____

245 565 mm_____= _______ 20 099 m_______= _______ 499 m __________= ___

2. Convert the following:

10.034 mJ = ________ cJ 36.45 cL = ______________ μL

0.05 cm = ________mm 1024 B = ______________ kB

0.0325 kJ = ________cJ 1202.5 mL = ______________ L

0.42101 Gg = ________Mg 25.5 km = ______________ m

0.12907 cm = ________ mm 756 900 μs = ______________ ms

5600.4 Ms = ________Gs 268 000 cm = ______________ km

3. Convert the following:

0.0075 Gm = ________ km 0.00091 TL = ___________ML

0.00046 ks = ________cs 244475.3 μs = ___________ ms

4096 MB = ________GB 210 hm = ___________cm

0.0002 μg = ________mg 448.5 cg = ___________g

0.00034 μL = ________cL 2103.55 s = ___________ks

11120.33 ng = ________cg 0.0000012 GL = _______cL

Word Problems 1. The distance from your home to the airport is 0.0000075 Gm. How far is this in km? 2. There are 10 computers in the computer lab that each have 20 GB hard drives. How many bytes (B) of disk space do we have in the computer lab in total. 3. A challenge: convert 100125368477004 ng to Gigagrams. 

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4 Corrected by:X_______________

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4corrected by: x____________________

DENSITY EXERCISE 1

1. List the 2 methods we learned to determine volume. Give an example of the type of object you might use for each method. Volume of a Liquid – Pour liquid into a ___________ _______ and read the meniscus. Ex: Volume of a weird shaped object- Fill graduated cylinder about half full, then plunge the w_____ shaped object in the cylinder. Subtract the 2 v______. The answer is the objects’ volume.

2. The following liquids are mixed together. Determine the density of each. Show calculations with colors in order that form in the graduated cylinder to the right. Use calculator below a. 22 ml of a blue liquid that has a mass of 51.1 g = 2.3 g/ml

b. 46 ml of a red liquid that has a mass of 43.3 g =___g/ml 46 ml c. 25 ml of a clear liquid with a mass of 25.8 g = ___ / 25.8 ml d. 17 ml of a green liquid with a mass of 14.5 g = ___ / e. 30 ml of a yellow liquid with a mass of 20.7 g = / f. 6.5 ml of an orange liquid with a mass of 6.7 g g. 7.8 ml of a silver liquid with a mass of 84 g

3. Which liquid (letter a-g) above is the densest? ___ 4. Which liquid (letter a-g) above is the least dense? ___ 5. Which liquid is probably water because of a density of 1.0 g/ml? ___ 6. What is the difference between MASS and WEIGHT. Mass is how many part______ are in the

object but weight is the force of gr_______ on those particles which is ze___ in outer-space.

7. What is the density of the rock in the cylinder?

a. Formula D ______ = ma__ = m w Vo ?

b. Plug in numbers =____ g ml

c. Solve by dividing = ___

8. If you found another pyroclastic volcanic rock with lots of holes that has a mass of 21.2g & a volume of 35.2 ml, what’s its density. a. Formula =____ b. Plug in numbers =____

Volume of water after = ___ ml c. Solve by dividing = Volume of before = - ___ ml

------------- Volume of the Rock = ___ ml

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5 Corrected by:X_______________

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5corrected by: x____________________

The Percent Sugar & Flavors in Gum Lab

Directions: Make sure to use appropriate sig figs and units. 1. Weigh a stick of gum with the foil (paper). 2. Record the weight and put the stick in mouth. 3. Weigh the foil. 4. Chew the gum for 10 minutes and let dry on the foil. 5. Weigh again.

Gum Type sugar free/ regular _____________

Before Chewing Mass – Before chewing with paper ______g 1 Mass – of Paper - ______g 2 Mass – of Dry Gum (without paper) _____ g 3 After Chewing Mass – Chewed Gum & Paper ______g 4 Mass – Paper - ______g 2 Mass – Chewed Gum _____ g 5 Weight of Sugars & Flavors Mass – of Dry Gum ______ g 3 Mass – of Chewed Gum - ______ g 5 Mass – Sugars and Flavors ______ g 6

% Sugars & Flavors = Mass Sugars & Flavors = ______6 x 100% = ______ % Mass – Dry Gum 3

Gum

Conclusions: 1. Which types of gum were higher in % sweeteners? Why? 2. Which types of gum were lower in % sweeteners? Why? 3. Explain how to calculate % composition? _______________________________________ ___________________________________________________________________________

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6 Corrected by:X_______________

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6corrected by: x____________________

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1. To find the density of the old pennies (80’s and earlier), 1st measure mass on the balance to the nearest 100th – example 31.57 g. 2. Measure the volume of the copper pennies sliding them slowly into a graduated cylinder that has 73.5 ml of water. 3. Record final volume of the pennies in the H2O. Subtract the Vtotal -Vwater = Vpennies . Divide m by v; D=m/v 4. Repeat steps 1- 3 for the new pennies (82’ & later). 5. Repeat steps 1- 3 for the cork stopper. Use a pencil tip to keep the stopper under water. 6. Repeat steps 1 – 3 for the rubber stopper. 7. Mass the diet soda in its’ can, then subtract the mass of can to obtain the mass of the liquid inside. 8. Read the volume on the bottom of the diet soda and record. Divide m by v; D = m/v 9. Repeat step 7-8 for the regular soda. 10. To find density of the water, first mass the graduated cylinder and record the container’s mass. 11. Then fill the cylinder to 73.5 ml and mass again. mtotal -mcylinder = mwater 12. Divide the mass of the water by the volume of the water (73.5 ml);; Divide m by v; D = m/v

Data Table Fill in each box using a minimum of 3-4 significant digits and with units. D = ____ Old

Pennies New Pennies

Cork Stopper

Rubber Stopper

Diet Soda

Regular Soda

Tap Water

g

g

g

Liquid’s Mass + Container

- 13.35 g

-13.55 g

- g

Mass Container

Actual M ass

g

g

g

g

g

g

Liquid’s Mass

Total Volume

ml

ml

ml

ml

ml

ml

Water Volume

- _____ml

- _____ml

- _____ml

- _____ml

- _____ml

- _____ml

73.5 ml

Pennies Volume

ml

ml

ml

ml

ml

ml

D = M V

g_ ml

g_ ml

g_ ml

g_ ml

√ √ √ √ √ √ Check 3 of the 6 choices Questions 1. Why did water not have an exact density of 1.0 g/ml?____________________________________________________________ 2. Which stopper material would use to make your boat?_______Why?________________________________________________ 3. Why are the sodas a different density?________________________________________________________________________ 4. Why are the pennies a different density? ______________________________________________________________________ 5. What is the rule for rounding? _________________________________________________________________________________ 6. What is the rule for how many digits should be used in your measurements? ____________________________________________

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7 Corrected by:X_______________

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7corrected by: x____________________

MEASURING AND CALCULATING REVIEW

1. Red, Blue, 5g, 20.3m, warm. Which are qualitative/quantitative? Why? Connect the dots to the appropriate answers 2. Centi • •0.001• •1/100 • •cm

Kilo • •0.01 • •1/1000 • •mm Milli • •0.1 • •1000 • •km Deci • •1000 • •1/10 • •dm

3. 1 significant digit • •0.080 2 sig. Figs. • •800.0 x 10-1

3 sig. Figs. • •0.00800 4 sig. Figs. • •8000 ml 8.O Liters = • •800

4. Mass • •Amount of particles Weight • •Compactness; mass/volume Density • •Space occupied Volume • •Measure of the fore of gravity on an object 5. Accuracy • •In solving chem problems one needs it Precision • •Solving a problem (1st step) Technique • •Arriving at the truth Known Info • •Proving to be consistent

Found/Documented Density • •Uses a derived unit

Connect dots & show work for credit. 6. Mass =10g, Volume =2ml • • 6 Density = ? Your value =95g, True value = 100g• • 5 % Error = ? Mass =25g, Density =10g/ml • • 5 Volume = ? 87070 has how many sig. Figures • • 2.5 0.0870700 has how many sig. Figs. • • 4

6.02 x 10 23 molecules is 1 mole • •Scientific Notation

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8 Corrected by:X_______________

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8corrected by: x____________________

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