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KLKSK

Pertemuan IIIAnalog & Digital Data

Shannon TheoremxDSL

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Analog and Digital Signaling of Analog and Digital Data

• Analog signals: represents data with continuously varying electromagnetic wave

• Digital signals: represents data with sequence of voltage pulses

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Data and Signals

• Usually use digital signals for digital data and analog signals for analog data

• Can use analog signal to carry digital data– Modem

• Can use digital signal to carry analog data – Compact Disc audio

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Analog & Digital Transmission

Analog Signal Digital Signal

Analog

Data

Two alternatives: (1) signal occupies the same spectrum as the analog data; (2) analog data are encoded to occupy a different portion of spectrum

Analog data are encoded using a codec to produce a digital bit stream

Digital

DataDigital data are encoded using a modem to produce analog signal

Two alternatives: (1) signal consists of two voltage levels to represent the two binary values; (2) digital data are encoded to produce a digital signal with desired properties

Data and Signal

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Analog Signals Carrying Analog and Digital Data

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Digital Signals Carrying Analog and Digital Data

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Analog & Digital Transmission

Analog Transmission

Digital Transmission

Analog

Signal

Is propagated through amplifiers; same treatment whether signal is used to represent analog data or digital data

Assumes that the analog signal represents digital data. Signal is propagated through repeaters; at each repeater, digital data are recovered from inbound signal and used to generate a new analog outbound signal

Digital

SignalNot used

Digital signal represents a stream of 1s and 0s, which may represent digital data or may be an encoding of analog data. Signal is propagated through repeaters; at each repeater, stream of 1s and 0s is recovered from inbound signal and used to generate a new digital outbound signal

Treatment of Signals

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Channel Capacity

• Data rate– In bits per second– Rate at which data can be communicated

• Bandwidth– In cycles per second of Hertz– Constrained by transmitter and medium

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Nyquist Bandwidth

• If rate of signal transmission is 2B then signal with frequencies no greater than B is sufficient to carry signal rate

• Given bandwidth B, highest signal rate is 2B• Given binary signal, data rate supported by B Hz

is 2B bps• Can be increased by using M signal levels

• C= 2B log2M

• M is the of discrete signal or voltage levels

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Shannon Capacity Formula

• Consider data rate, noise and error rate

• Faster data rate shortens each bit so burst of noise affects more bits– At given noise level, high data rate means

higher error rate

• Signal to noise ratio (in decibels)

• SNRdb=10 log10 (signal/noise)

• Capacity C=B log2(1+SNR)

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• Consider a voice channel being used, via modem, to transmit digital data. Assume a bandwidth of 3100 Hz. A typical value of S/N for a voice-grade line is 30 dB; or a ratio of 1000:1

• Thus

• C = 3100 log2(1 + 1000) = 30,894 bps

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• Shannon proved that if the actual information rate on a channel is less than the error-free capacity, then it is theoretically possible to use a suitable signal code to achieve error – free transmission through the channel

• Unfortunately Shannon formula does not suggest a means for finding such codes

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• Eb/No : ratio of signal energy per bit to noise power density per hertz

• Consider a signal, digital or analog, that contains binary digital data transmitted at a certain bit rate R

• 1 W = 1 J/s

• The energy per bit in a signal Eb = STb

• S : the signal power

• Tb : the time required to send one bit

• The data rate R = 1/Tb

• (Eb/No) = (S/R)/No = S/(kTR)

• Eb/No = S – 10log R + 228.6 dBW – 10 logT

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• Ex. For binary phase-shift keying, Eb/No = 8.4 dB is required for a bit error rate of 10-4 (probability of error = 10-4). If the effective noise temperature is 290oK (room temperature) and the data rate is 2400 bps, what received signal level is required?

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• Ans.

• 8.4 = S (dBW) – 10 log 2400 + 228.6 dBW – 10 log 290

• = S (dBW) – (10) (3.38) + 228.6 – (10)(2.46)

• S = -161.8 dBW