12x1 t06 01 integration using substitution (2010)

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Integration Using Substitution

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Page 1: 12X1 T06 01 integration using substitution (2010)

Integration Using Substitution

Page 2: 12X1 T06 01 integration using substitution (2010)

Integration Using Substitution

Try to convert the integral into a “standard integral”

Page 3: 12X1 T06 01 integration using substitution (2010)

Integration Using Substitution

Try to convert the integral into a “standard integral”STANDARD INTEGRALS

dxxn 0 if ,0;1 ,1

1 1

nxnxn

n

Page 4: 12X1 T06 01 integration using substitution (2010)

Integration Using Substitution

Try to convert the integral into a “standard integral”STANDARD INTEGRALS

dxxn 0 if ,0;1 ,1

1 1

nxnxn

n

dxx1

0 ,ln xx

Page 5: 12X1 T06 01 integration using substitution (2010)

Integration Using Substitution

Try to convert the integral into a “standard integral”STANDARD INTEGRALS

dxxn 0 if ,0;1 ,1

1 1

nxnxn

n

dxx1

0 ,ln xx

Page 6: 12X1 T06 01 integration using substitution (2010)

Integration Using Substitution

Try to convert the integral into a “standard integral”STANDARD INTEGRALS

dxxn 0 if ,0;1 ,1

1 1

nxnxn

n

dxx1

0 ,ln xx

dxeax 0 ,1 ae

aax

Page 7: 12X1 T06 01 integration using substitution (2010)

Integration Using Substitution

Try to convert the integral into a “standard integral”STANDARD INTEGRALS

dxxn 0 if ,0;1 ,1

1 1

nxnxn

n

dxx1

0 ,ln xx

dxeax 0 ,1 ae

aax

dxax cos 0 ,sin1 aax

a

Page 8: 12X1 T06 01 integration using substitution (2010)

Integration Using Substitution

Try to convert the integral into a “standard integral”STANDARD INTEGRALS

dxxn 0 if ,0;1 ,1

1 1

nxnxn

n

dxx1

0 ,ln xx

dxeax 0 ,1 ae

aax

dxax cos 0 ,sin1 aax

a

dxax sin 0 ,cos1 aax

a

Page 9: 12X1 T06 01 integration using substitution (2010)

dxax sec2 0 ,tan1 aax

a

Page 10: 12X1 T06 01 integration using substitution (2010)

dxax sec2 0 ,tan1 aax

a

dxaxax tansec 0 ,sec1 aax

a

Page 11: 12X1 T06 01 integration using substitution (2010)

dxax sec2 0 ,tan1 aax

a

dxaxax tansec 0 ,sec1 aax

a

dxxa

122 0 ,tan1 1 a

ax

a

Page 12: 12X1 T06 01 integration using substitution (2010)

dxax sec2 0 ,tan1 aax

a

dxaxax tansec 0 ,sec1 aax

a

dxxa

122 0 ,tan1 1 a

ax

a

dxxa

122 axaa

ax

0, ,sin 1

Page 13: 12X1 T06 01 integration using substitution (2010)

dxax sec2 0 ,tan1 aax

a

dxaxax tansec 0 ,sec1 aax

a

dxxa

122 0 ,tan1 1 a

ax

a

dxxa

122 axaa

ax

0, ,sin 1

dxax

122 0 ,ln 22 axaxx

Page 14: 12X1 T06 01 integration using substitution (2010)

dxax sec2 0 ,tan1 aax

a

dxaxax tansec 0 ,sec1 aax

a

dxxa

122 0 ,tan1 1 a

ax

a

dxxa

122 axaa

ax

0, ,sin 1

dxax

122 0 ,ln 22 axaxx

dxax

122 22ln axx

Page 15: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 42

Page 16: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 4242 xu

Page 17: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 4242 xu

u

Page 18: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 4242 xu

xdxdu 2u

Page 19: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 4242 xu

xdxdu 2udu

21

Page 20: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 4242 xu

duu

dxxx

21

2

21

4221

xdxdu 2udu

21

Page 21: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 4242 xu

duu

dxxx

21

2

21

4221

xdxdu 2udu

21

cu 23

32

21

Page 22: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 4242 xu

duu

dxxx

21

2

21

4221

xdxdu 2udu

21

cu 23

32

21

cu 23

31

Page 23: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 4242 xu

duu

dxxx

21

2

21

4221

xdxdu 2udu

21

cu 23

32

21

cu 23

31

cx 23

2 431

Page 24: 12X1 T06 01 integration using substitution (2010)

e.g. (i) dxxx 4242 xu

duu

dxxx

21

2

21

4221

xdxdu 2udu

21

cu 23

32

21

cu 23

31

cx 23

2 431

cxx 4431 22

Page 25: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

Page 26: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

dxxduxxu

88784 2

Page 27: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

dxxduxxu

88784 2

udu

81

Page 28: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

dxxduxxu

88784 2

cu log81

udu

81

Page 29: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

dxxduxxu

88784 2

cu log81

cxx 784log81 2

udu

81

Page 30: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

dxxduxxu

88784 2

cu log81

cxx 784log81 2

udu

81

3log xx

dxiii

Page 31: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

dxxduxxu

88784 2

cu log81

cxx 784log81 2

udu

81

3log xx

dxiii

xdxdu

xu

log

Page 32: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

dxxduxxu

88784 2

cu log81

cxx 784log81 2

udu

81

3log xx

dxiii

xdxdu

xu

log

duuudu

3

3

Page 33: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

dxxduxxu

88784 2

cu log81

cxx 784log81 2

udu

81

3log xx

dxiii

xdxdu

xu

log

duuudu

3

3

cu

cu

2

2

21

21

Page 34: 12X1 T06 01 integration using substitution (2010)

dx

xxxii

7841

2

dxxduxxu

88784 2

cu log81

cxx 784log81 2

udu

81

3log xx

dxiii

xdxdu

xu

log

duuudu

3

3

cu

cu

2

2

21

21

c

x 2log2

1

Page 35: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1

Page 36: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

Page 37: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

udu

uu 21 2

Page 38: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

uduuu 21 2

Page 39: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

Page 40: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

cxx 12132 3

Page 41: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

cxx 12132 3

cxxx 121132

Page 42: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

2

3

5 cossin

xdxxv

cxx 12132 3

cxxx 121132

Page 43: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

2

3

5 cossin

xdxxvxdxduxu

cossin

cxx 12132 3

cxxx 121132

Page 44: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

2

3

5 cossin

xdxxvxdxduxu

cossin

cxx 12132 3

cxxx 121132

23

3sin,

3

u

ux

Page 45: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

2

3

5 cossin

xdxxvxdxduxu

cossin

cxx 12132 3

cxxx 121132

23

3sin,

3

u

ux

1 2

sin,2

u

ux

Page 46: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

2

3

5 cossin

xdxxvxdxduxu

cossin

1

23

5duu

cxx 12132 3

cxxx 121132

23

3sin,

3

u

ux

1 2

sin,2

u

ux

Page 47: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

2

3

5 cossin

xdxxvxdxduxu

cossin

1

23

5duu

123

6

61 u

cxx 12132 3

cxxx 121132

23

3sin,

3

u

ux

1 2

sin,2

u

ux

Page 48: 12X1 T06 01 integration using substitution (2010)

dx

xxiv

1ududx

xuux2

11 2

duu 12 2

cuu

3

312

uduuu 21 2

2

3

5 cossin

xdxxvxdxduxu

cossin

1

23

5duu

123

6

61 u

38437

231

61

66

cxx 12132 3

cxxx 121132

23

3sin,

3

u

ux

1 2

sin,2

u

ux

Page 49: 12X1 T06 01 integration using substitution (2010)

4

3225 x

xdxvi

Page 50: 12X1 T06 01 integration using substitution (2010)

4

3225 x

xdxvixdxdu

xu2

25 2

Page 51: 12X1 T06 01 integration using substitution (2010)

4

3225 x

xdxvixdxdu

xu2

25 2

9,416,3

uxux

Page 52: 12X1 T06 01 integration using substitution (2010)

4

3225 x

xdxvixdxdu

xu2

25 2

16

9

21

9

16

21

21

duu

udu

9,416,3

uxux

Page 53: 12X1 T06 01 integration using substitution (2010)

4

3225 x

xdxvixdxdu

xu2

25 2

16

9

21

9

16

21

21

duu

udu

16

9

21

u

9,416,3

uxux

Page 54: 12X1 T06 01 integration using substitution (2010)

4

3225 x

xdxvixdxdu

xu2

25 2

16

9

21

9

16

21

21

duu

udu

16

9

21

u

1916

9,416,3

uxux

Page 55: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxvii

Page 56: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxvii

ududx

xuux

cos55

sinsin5 1

Page 57: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxvii

ududx

xuux

cos55

sinsin5 1

2

1sin,50

0sin,0

1

1

u

uxuux

Page 58: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxvii

ududx

xuux

cos55

sinsin5 1

2

0

2 cos5sin2525

uduu

2

1sin,50

0sin,0

1

1

u

uxuux

Page 59: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxvii

ududx

xuux

cos55

sinsin5 1

2

0

2 cos5sin2525

uduu

2

0

2

2

0

2

cos25

cos5cos25

udu

uduu

2

1sin,50

0sin,0

1

1

u

uxuux

Page 60: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxvii

ududx

xuux

cos55

sinsin5 1

2

0

2 cos5sin2525

uduu

2

0

2

2

0

2

cos25

cos5cos25

udu

uduu

2

0

2

0

2sin21

225

2cos1225

uu

duu2

1sin,50

0sin,0

1

1

u

uxuux

Page 61: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxvii

ududx

xuux

cos55

sinsin5 1

2

0

2 cos5sin2525

uduu

2

0

2

2

0

2

cos25

cos5cos25

udu

uduu

2

0

2

0

2sin21

225

2cos1225

uu

duu2

1sin,50

0sin,0

1

1

u

uxuux

425

0sin21

2225

Page 62: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxvii

Page 63: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxviiy

x5

5

-5

225 xy

Page 64: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxviiy

x5

5

-5

225 xy

Page 65: 12X1 T06 01 integration using substitution (2010)

5

0

225 dxxviiy

x5

5

-5

225 xy

425

541 2

Page 66: 12X1 T06 01 integration using substitution (2010)

Exercise 6C; 1, 2ace, 3, 4ace, 5ace etc, 6, 7 & 8ac, 11, 12Exercise 6D; 1, 2a, 3, 4b, 5ac, 6ace etc, 7ab(i,ii)

8ab (i,iii,vi), 9ab (ii,iv,vi), 11, 13

Patel Exercise 2A ace in all NOTE: substitution is not given in Extension 2

5

0

225 dxxviiy

x5

5

-5

225 xy

425

541 2