2. biology (from engineering perspective)cmbe.engr.uga.edu/bche4510/assign/notes/a4 - biology...

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2. Biology (from Engineering Perspective) Read: Chapter 2 (pp. 10 - 55) cause infections in other higher cells obligate parasites 30 - 200 x 10 -9 m diameter (0.03 - 0.2 Pm) Bacteriophages are viruses which specifically infect bacteria. contain DNA or RNA enclosed in a protein coat called a capsid A. Cell types 1. Viruses

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Page 1: 2. Biology (from Engineering Perspective)cmbe.engr.uga.edu/bche4510/assign/Notes/A4 - Biology for...2. Biology (from Engineering Perspective) Read: Chapter 2 (pp. 10 - 55) ... sporozoa

2. Biology (from Engineering Perspective)

Read: Chapter 2(pp. 10 - 55)

• cause infections in other higher cells

• obligate parasites• 30 - 200 x 10-9 m diameter (0.03 - 0.2 m)

• Bacteriophages are viruses which specifically infectbacteria.

• contain DNA or RNA enclosed in a protein coatcalled a capsid

A. Cell types1. Viruses

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• After infection:1) Lytic Cycle - host cells lyse (break

apart) and release new viruses, which goon to infect new host cells.

2) Lysogenic Cycle - viral DNA is incorporatedinto host DNA, and continues to multiply withhost.

• Viruses are important because they can:1) infect bacteria used in a commercial process.

2) cause disease in animals and plants.

3) be used to incorporate foreign DNA into ahost cell.

• do not contain a membrane-enclosed nucleus• 5 - 30 x 10-7 m diameter (0.5 - 3 m)

• usually do not associate with other cells• often multiply quickly when nutrients are plentiful

Some populations can double every 20 minutes.

2. Procaryotes

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Gram-negative• categorized by their cell envelope

Secretion of proteins is often more difficult for Gram-negative cells because of outer membrane.Gram stain developed to distinguish these cell types, involves a dye which is retained by peptidoglycan.

a. Eubacteria

8 nm cytoplasmic membrane7 nm periplasmic space2 nm peptidoglycan8 nm outer membrane

Gram-positive8 nm cytoplasmic membrane80 nm peptidoglycan

• formation of spores in response to adverseconditions

• formation of inclusion bodies (can be large)examples: sulfur, proteins

• excretion of polysaccharides to adhere to surfaces(teeth, bioremediation)

• have no peptidoglycan

b. Archaebacteria

• have different lipid composition in cytoplasmicmembrane

• live in extreme environmentsexamples: 110ºC, dead sea water

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• 1 - 20 x 10-6 m diameter (1 - 20 m)• contain a membrane-enclosed nucleus• Cell membrane has sterols which provide rigidity.• Plant cells contain cellulose fibers which make

them strong. Animal cells do not have cellulose.

3. Eucaryotes

• have numerous complex cell organelles1) Mitochondria are site for respiration and

oxidative phosphorylation. Cristae are theircomplex inner membrane folds.

2) Chloroplasts are site for photosynthesis.Replicate independentlyHave their own DNA

Both eucaryotes and procaryotes contain:Endoplasmic reticulum• rough - Contain ribosomes and are site of

protein synthesis• smooth - site of lipid synthesis

Flagella and cilia are filamentous structures which permit cell to propel through fluid. Chemotaxis is the tendency of cells to move towards/away from chemicals.

Both eucaryotes and procaryotes may contain:

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• spherical cells• widespread in nature (soil)• do not use sunlight for energy• free-living

a. Fungi

• reproduce by budding

1) Yeasts

mother

daughter

• distinctly non-spherical cells• A Mycelium is a highly branched system of hyphae.• Hyphae are thin filaments of cells.• Conidia are asexual spores which form on hyphae.• in submerged culture can form thick mats which

result in complex rheological behavior

2) Molds

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Penicillium

Conidia

Conidiophore

Septate Hypha

Hyphae

Septate Hypha

Rhizoctania

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Aspergillus

Conidiophore

Conidia

Conidia

Chrysosporium

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• distinctly non-spherical cells• Mycelium are a highly branched system of tubes.• Hyphae are thin filaments of cells.• Conidia are asexual spores which form on hyphae.• in submerged culture can form thick mats which

result in complex rheological behavior

2) Molds

• do not use sunlight for energy• free-living

• have high oxygen requirement

• spores

• photosynthetic• often, but not always, unicellular• some contain silica or calcium carbonate in structure• principal products:

b. Algae

diatomaceous earthagarfoodstuffs

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• large unicellular cells that lack cell walls• ingest other smaller organisms• move to seek prey

amebae - cytoplasm forms pseudopodium

c. Protozoa

flagellates - have one flagellumciliates - have many ciliasporozoa - usually have aid of host

• used for many vaccines (animal cells)

• colors, flavors, insecticides (plant cells)

d. Animal and Plant Cells

• therapeutic proteins (animal cells)

Comparison of cell growth rates

Freq

uenc

y of

dou

blin

g tim

e

0 60 120 180 240 300 360Doubling time (min)

bacteriayeast

mold

protozoa

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Class Example Function

• composed of 20 amino acids covalently linked• have diverse functions:

B. Cell construction1. Proteins

regulatory insulin regulates glucose metabolismenzymes alcohol dehydrogenase oxidizes alcohols to aldehydes

transport hemoglobin transport of oxygen and carbondioxide in blood

protection IgG antibody forms complex with foreignprotein and initiates immuneresponse

structure collagen cartilage and tendonsstorage albumin egg-white

• Isoelectric point is pH at which amino acidhas no net charge.

• R = side chainThe R-group distinguishes amino acids.

2. Amino acids

• zwitterion - doubly charged• chiral - L-form found in proteins

C

H

C O

O

H3N

R+ _

• Proteins are formed from amino acids by peptidebonds

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Glycine

LysinePhenylalanineAspartate

IsoleucineAlanine

• Primary structure is merely the sequence of aminoacids

• Secondary structure is the structural conformationof amino acids that are close neighbors. Thepeptide bond restricts flexibility.

3. Protein structure

• Tertiary structure is the three dimensional structurearising from hydrogen bonds, disulfide bridges,hydrophobic and ionic interactions between aminoacids which are widely separated in linear sequencebut are spatially proximate.

• Quarternary structure is the interactions betweenprotein subunits.

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• General formula is (CH2O)N.

• Involved in structure, storage and signaling

4. Carbohydrates

• Analogous to amino acids, monomeric units cancombined to form polymeric molecules calledpolysaccharides

• 3-9 carbon atoms

• 5 or 6 carbon atoms most common, which oftenform stable furanose (5-membered) or pyranose(6-membered) ring

a. Monosaccharides

• examples:

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H O

OH

H

OHH

OH

CH2OH

H

OH

H

23

4

5

6

1

H O

OH

H

OHH

OH

CH2OH

HOH

H23

4

5

6

1

-D-fructose

O

OH

H

OHH

O H

CH2OH H

2

34

5

6

1CH2OH

Haworthprojection

-D-glucose -D-glucose

H O

OH

H

OHH

OH

CH2OH

H

-D-glucose

OH

H

23

4

5

6

1

-D-glucose

H O

OH

H

OHH

OH

CH2OH

HOH

H23

4

5

6

1

H

CH O

C OH

C HHO

C OHH

C OHH

CH2OH

1

5

2

3

4

6

H O

OH

H

OHH

OH

CH2OH

HO

H

H

23

4

5

6

1 C= below ring

= above ring

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O

H

HO

H

HO

H

OHOHH

H

OH

1

6

5

4

32

O

H

HO

H

HO

H

HOHH

OH

OH

1

6

5

4

32

-D-glucopyranose -D-glucopyranose

35%64%

1% furanose<0.03% linear

• formed by the condensation of twomonosaccharides(while amino acids only form one type of covalent bond - peptide bond - saccharides can form several different linkages)

b. Disaccharides

• examples:

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H O

OH

H

OHH

OH

CH2OH

H-1,4 linkageO

H H O

H

OHH

OH

CH2OH

H

maltose OH

H

H O

OH

H

OHH

OH

CH2OH

H-1,4 linkageO

Hcellobiose

H O

H

OHH

OH

CH2OH

HOH

H

Cellobiose

Maltose

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HO O

H

H

OHH

OH

CH2OH

H H O

H

OHH

OH

CH2OH

HOH

H

OH

with -1,4 linkage yields lactose

-D-glucose+

-D-galactose

(1 4) galacto-glucopyranose

H O

OH

H

OHH

OH

CH2OH

H

with , -1,2 linkage yields sucrose

O

H

-D-fructose+

-D-glucose

O

H

OHH

O H

CH2OH H

CH2OH

(1 2) gluco-fructofuranose

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Sucrose

Lactose

• formed by the condensation of more than twomonosaccharides

c. Polysaccharides

• examples:

Amylose

Cellulose

Straight chain of 15 - 3,000 glucose units linked by -1,4 glycosidic bonds.

Straight chain of 300 - 6,000 glucose units linked by -1,4 glycosidic bonds.

Insoluble in water

Insoluble in water

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c. Polysaccharides (cont’d)

Amylopectin Branched chain of 5,000 - 10,000 glucose units linked by -1,4 and -1,6 glycosidic bonds. Branching occurs via -1,6 bonds after an average of 25 units.

Glycogen Like amylopectin but smaller and more frequent branching.

Soluble in water (forms gels)

More exposed monomers available for enzymatic cleavage.

c. Polysaccharides (cont’d)

Starch 20% amylose80% amylopectin

Cellulose is more difficult to decompose in nature than amylose and amylopectin because of interchainhydrogen bond between C3 hydroxyl and pyranose oxygen leading to crystalline structure.

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amylose

cellulose

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amylopectin

c. Polysaccharides (cont’d)

Corn Starch Corn Syruppartial hydrolysis glucose, maltose, etc.

Production of Sweeteners

Relative Sweetness

glucose 0.7sucrose 1.0fructose 2.0

How to obtain more fructose?

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c. Polysaccharides (cont’d)

Corn Starch glucoseEnzymatic and

chemical hydrolysis

“high fructose corn syrup”

glucose/fructose

glucose isomerase

annual U.S. consumption 50 - 70 kg/person

• long threadlike molecule which carries geneticinformation in its sequence of purine andpyrimidine bases

5. DNA

• transcription: DNA template tomessenger RNA

• codon on mRNA interacts withanticodon on transfer RNA

• translation: RNA code convertedto amino acid sequence

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• plasmids are nonchromosomal self-replicatingsegments of DNA floating around in cytoplasm

5. DNA (cont’d)

• plasmids are a means for cells totransfer DNA quickly between cells andbetween species (e.g., give resistance tocells against antibiotics).

• plasmids can be inserted into cells toget them to overproduce a desiredprotein.

• copy number is the number of desiredplasmids in a cell.

• phototrophs utilize light energy• chemotrophs utilize chemical energy

C. Cell Nutritional Requirements

1. Energy

• lithotrophs utilize inorganic chemicals• organotrophs utilize organic chemicals

• autotrophs utilize inorganic carbon (CO2)• heterotrophs utilize organic carbon

2. Carbon

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“complex” media

Industrial fermentations use cheap carbon sourcessuch as molasses, malt extract, corn steep liquor,sulfite waste liquor

Nature of carbon source has great impacton growth of cells:

complex media 35 minglucose + salts 50 minacetate + salts 80 minsuccinate + salts 300 min

Doubling time

Example (with E. coli)J. Bacteriol. (1971) 105:20+

“defined”media

1) Cheap

Advantages of using complex media instead of defined media:

4) Have all nutritional requirements3) Best cell growth2) Readily available

Disadvantages of using complex media instead of defined media:

1) Considerable variation in media composition

3) Complicates separation and purification2) Processes less reliable and reproducible

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12% of bacterial dry mass7.5% of yeast dry mass

• complex media

3. Nitrogen

• peptone (protein hydrolysate)meat, cottonseeds, soy

• yeast extract(Baker’s yeast lysed at 55ºC)

• defined media• ammonia• ammonium salts• urea

Prices for Defined Nitrogen Sources (Dec 2002)

Substance $ per lb $ per lb N%N

NH3

NH4Cl

(NH4)2SO4

NH4H2PO4

(NH4)2HPO4

NH4NO3

urea

0.073 0.0880.823

0.21 0.8020.262

0.053 0.2500.212

0.082 0.6720.122

0.062 0.2920.212

0.069 0.1970.350

0.054 0.1170.46

1) 27% P - $0.30/lb P

1)

2) 24% P - $0.26/lb P

2)

Are materials pure enough for biological processes?

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3% of bacterial dry mass1.5% of yeast dry mass

• phosphate salts added if more P is necessary

4. Phosphorus

• 180% as much P is supplied as N• 25% as much P is needed as N

• in some fermentations, P can inhibitproduction of desired product

1% of bacterial and yeast dry mass

• sulfate salts added if more S is necessary

5. Sulfur

• 60% as much S is supplied as N• 10% as much S is needed as N

• supplied as necessary (in excess?)by addition of salts

a) trace elements:K+, Mg++, Ca++, Fe++, Mn++, Co++, etc.

• very important in regulating enzymes(both presence and absence)

6. Micronutrients

• carefully controlled(example: citric acid fermentation)

b) vitamins

• expensive

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Elemental Composition of E. coli

Element

C

N

P

S

Mg

K

Na

393---

140---

41 55---

10 13---

6.4 8.72.8

41 2212

23 53---

(mg / g dry cell weight)

early lategrowth osmol,

low high

18 40

3.9 3.2

---

---

---

---

---

---

---

---

--- ---

---

---

ref (2)(1) (3)

Element

Ca

Cl

Zn

ref

2.12.3

23---

41 550.15

(2)(1)

early lategrowth

0.5

25

(1) Kung et al. J. Bacteriol. 1976, 126(3):1089

(2) Heldal et al. Appl. Environ. Microbiol. 1985 50(5):1251

(3) Epstein & Schultz J. Gen. Physiol. 1965 49:221

Elemental Composition of E. coli(mg / g dry cell weight)

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Comments

• composition of cells is very flexible…cells have ability to adapt to environment.

• ~20-30% of carbon consumed by an organoheterotroph ends up as cell material. Thus, 3-5 times as much carbon needs to be added as calculated merely from cell composition.

• composition of medium can strongly impact composition of cells, which in turn can profoundly impact cellular metabolism (and product formation).