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Chapter 5 Gases - 2 Combined Gas Law, Ideal Gas Law and Applications of Gas Laws Dr. Sapna Gupta

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Page 1: 2 Combined Gas Law, Ideal Gas Law and Applications of Gas Laws - Manu's …drsapnag.manusadventures.com/chemistry/general-chemistry/... · 2017-06-21 · Combined Gas Law The volume

Chapter 5Gases - 2

Combined Gas Law, Ideal Gas Law and

Applications of Gas LawsDr. Sapna Gupta

Page 2: 2 Combined Gas Law, Ideal Gas Law and Applications of Gas Laws - Manu's …drsapnag.manusadventures.com/chemistry/general-chemistry/... · 2017-06-21 · Combined Gas Law The volume

Combined Gas Law

The volume of a sample of gas at constant pressure is inversely proportional to the pressure and directly proportional to the absolute temperature.

The mathematical relationship:

In equation form:

Include the Avogadro’s law and it becomes (1=initial and 2= final)

PiVi

niTi

=PfVf

nfTf

P1V1

n1T1

=P2V2

n2T2

P

TV

f

ff

i

ii

constant

T

VP

T

VP

T

PV

Dr. Sapna Gupta/Gases-IdealGasLawApps 2

OR

Page 3: 2 Combined Gas Law, Ideal Gas Law and Applications of Gas Laws - Manu's …drsapnag.manusadventures.com/chemistry/general-chemistry/... · 2017-06-21 · Combined Gas Law The volume

Solved Problem:Divers working from a North Sea drilling platform experience pressure of 5.0 × 101 atm at a depth of 5.0 × 102 m. If a balloon is inflated to a volume of 5.0 L (the volume of the lung) at that depth at a water temperature of 4°C, what would the volume of the balloon be on the surface (1.0 atm pressure) at a temperature of 11°C?

Vi = 5.0 L

Pi = 5.0 × 101 atm

Ti = 4°C = 277 K

Vf = ?

Pf = 1.0 atm

Tf = 11°C = 284 K fi

iiff

PT

VPTV

1

f

(284 K)(5.0 10 atm)(5.0 L)

(277 K)(1.0 atm)V

= 2.6 102 L

(2 significant figures)

Dr. Sapna Gupta/Gases-IdealGasLawApps 3

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Ideal Gas Law

Ideal Gas Law• Combining the historic gas laws yields:

• Adding the proportionality constant, R

Dr. Sapna Gupta/Gases-IdealGasLawApps 4

R =PV

nT

Page 5: 2 Combined Gas Law, Ideal Gas Law and Applications of Gas Laws - Manu's …drsapnag.manusadventures.com/chemistry/general-chemistry/... · 2017-06-21 · Combined Gas Law The volume

Standard Temperature and Pressure (STP)

• The reference condition for gases, chosen by convention to be exactly 0°C and 1 atm pressure.

• The ideal gas equation is not exact, but for most gases it is quite accurate near STP (760 torr (1 atm) and 273 K)

• An “ideal gas” is one that “obeys” the ideal gas equation.

• At STP, 1 mol of an ideal gas occupies 22.41 L.

at STP

T = 0°C = 273 K

n = 1 mol

P = 1 atm

V = 22.41 L

Dr. Sapna Gupta/Gases-IdealGasLawApps 5

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Solved Problem:A steel cylinder with a volume of 68.0 L contains O2 at a pressure of 15,900 kPa at 23ºC. What is the volume of this gas at STP?

P2 = 1 atm

T1 = 23 + 273 = 296 KT2 = 273 K

V1 = 68.0 L

L 9850 atm 1K 296

K 273L 68.0atm 157.0

1 1 22

1 2

PVTV

T P

atm 0.157 kPa 101.3

atm 1 kPa 15,900 P1

V2 = ?

Dr. Sapna Gupta/Gases-IdealGasLawApps 6

P1V1

n1T1=

P2V2

n2T2

Page 7: 2 Combined Gas Law, Ideal Gas Law and Applications of Gas Laws - Manu's …drsapnag.manusadventures.com/chemistry/general-chemistry/... · 2017-06-21 · Combined Gas Law The volume

Solved Problem:A 50.0-L cylinder of nitrogen, N2, has a pressure of 17.1 atm at 23°C. What is the mass of nitrogen in the cylinder?

V = 50.0 LP = 17.1 atmT = 23oC = 296 K

RT

PVn

K)(296Kmol

atmL0.08206

L)atm)(50.0(17.1

•n

mass = 986 g(3 significant figures)

mol

g28.02mol35.20mass

= 35.20 mols

Dr. Sapna Gupta/Gases-IdealGasLawApps 7

Page 8: 2 Combined Gas Law, Ideal Gas Law and Applications of Gas Laws - Manu's …drsapnag.manusadventures.com/chemistry/general-chemistry/... · 2017-06-21 · Combined Gas Law The volume

Solved Problem: For an ideal gas, calculate the pressure of the gas if 0.215 mol occupies 338 mL at 32.0ºC.

n = 0.215 mol

V = 338 mL = 0.338 L

T = 32.0 + 273.15 = 305.15 K

P = ?

L×atm

0.215 mol 0.08206 305.15 Kmol×K

0.338 L

P

PV = nRT nRT

PV

= 15.928

= 15.9 atm

Dr. Sapna Gupta/Gases-IdealGasLawApps 8

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Gas Density and Molar Mass

• Using the ideal gas law, it is possible to calculate the moles in 1 L at a given temperature and pressure. The number of moles can then be converted to grams (per liter).

Relation to density

• Get n/V on one side (mol/vol)

• Multiply by molar mass M (g/mol)

• Units of density are g/L here.

To find molar mass, rearrange the above equation.

Dr. Sapna Gupta/Gases-IdealGasLawApps 9

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Solved Problem:What is the density of methane gas (natural gas), CH4, at 125°C and 3.50 atm?

Mm = 16.04 g/molP = 3.50 atmT = 125°C = 398 K

RT

PMd m

K)(398Kmol

atmL0.08206

atm))(3.50mol

g(16.04

•d

figures)tsignifican(3

L

g1.72d

Dr. Sapna Gupta/Gases-IdealGasLawApps 10

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All Gas Laws

• Gases are compressible because the gas molecules are separated by large distances.

• The magnitude of P depends on how often and with what force the molecules strike the container walls.

• At constant T, as V increases, each particle strikes the walls less frequently and P decreases.

• To maintain constant P, as V increases T must increase; fewer collisions require harder collisions.

• To maintain constant P and T, as V increases n must increase.

• Gas molecules do not attract or repel one another, so one gas is unaffected by the other and the total pressure is a simple sum.

(Boyle’s Law)

(Charles’ Law)

(Avogadros’ Law)

(Dalton’s Law)

Dr. Sapna Gupta/Gases-IdealGasLawApps 11

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Key Points

• Combined gas law

• The ideal gas law

• Standard Temperature and Pressure

• Applications of gas laws

• Density

• Molar mass

Dr. Sapna Gupta/Gases-IdealGasLawApps 12