2012 mathematical methods (cas) exam 1
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STUDENT NUMBER Letter
MATHEMATICAL METHODS (CAS)
Written examination 1
Wednesday 7 November 2012
Reading time: 9.00 am to 9.15 am (15 minutes)
Writing time: 9.15 am to 10.15 am (1 hour)
QUESTION AND ANSWER BOOK
Structure of book
Number of
questions
Number of questions
to be answered
Number of
marks
10 10 40
Studentsarepermittedtobringintotheexaminationroom:pens,pencils,highlighters,erasers,
sharpeners,rulers.
StudentsareNOTpermittedtobringintotheexaminationroom:notesofanykind,blanksheetsof
paper,whiteoutliquid/tapeoracalculatorofanytype.
Materials supplied
Questionandanswerbookof10pages,withadetachablesheetofmiscellaneousformulasinthe
centrefold.
Workingspaceisprovidedthroughoutthebook.
Instructions
Detachtheformulasheetfromthecentreofthisbookduringreadingtime.
Writeyourstudent numberinthespaceprovidedaboveonthispage.
AllwrittenresponsesmustbeinEnglish.
Students are NOT permitted to bring mobile phones and/or any other unauthorised electronic
devices into the examination room.
VICTORIANCURRICULUMANDASSESSMENTAUTHORITY2012
SUPERVISOR TO ATTACH PROCESSING LABEL HEREVictorian Certicate of Education
2012
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2012MATHMETH(CAS)EXAM1 2
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3 2012 MATHMETH(CAS) EXAM 1
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Question 1
a. Ify = (x2 5x)4, fnddy
dx.
1 mark
b. Iff(x) =x
xsin( ), fndf '
2.
2 marks
Instructions
Answerall questions in the spaces provided.
In all questions where a numerical answer is required an exact value must be given unless otherwise
specifed.
In questions where more than one mark is available, appropriate working must be shown.
Unless otherwise indicated, the diagrams in this book are not drawn to scale.
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2012MATHMETH(CAS)EXAM1 4
Question 2
Findananti-derivativeof1
2 13
x ( )withrespecttox.
2marks
Question 3
Theruleforfunctionhish(x)=2x3+1.Findtherulefortheinversefunctionh1.
2marks
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5 2012MATHMETH(CAS)EXAM1
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Question 4
Onanygivenday,thenumberXoftelephonecallsthatDanielreceivesisarandomvariablewithprobability
distributiongivenby
x 0 1 2 3
Pr(X=x) 0.2 0.2 0.5 0.1
a. FindthemeanofX.
2marks
b. WhatistheprobabilitythatDanielreceivesonlyonetelephonecalloneachofthreeconsecutivedays?
1mark
c. DanielreceivestelephonecallsonbothMondayandTuesday.
WhatistheprobabilitythatDanielreceivesatotaloffourcallsoverthesetwodays?
3marks
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2012MATHMETH(CAS)EXAM1 6
Question 5
a. Sketchthegraphoff:[0,5]R,f(x)=|x3|+2.Labeltheaxesinterceptsandendpointswiththeir
coordinates.
y
x
1
1 2 3 4 5 6 7
1
1234567
2
3
4
5
6
7
2
3
4
5
6
7
O
3marks
b. i. Findthecoordinatesoftheimageofthepoint(3,2)underareectioninthex-axis,followedbya
translationof5unitsinthepositivedirectionofthex-axis.
ii. Findtheequationoftheimageofthegraphoffunderareectioninthex-axis,followedbya
translationof5unitsinthepositivedirectionofthex-axis.
1+2=3marks
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Question 6
Thegraphsofy=cos(x)andy = asin(x),whereaisarealconstant,haveapointofintersectionatx =
3.
a. Findthevalueofa.
2marks
b. Ifx[0,2],ndthex-coordinateoftheotherpointofintersectionofthetwographs.
1mark
Question 7
Solvetheequation2loge(x+2)loge(x)=loge(2x+1),wherex>0,forx.
3marks
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2012 MATHMETH(CAS) EXAM 1 8
Question 8
a. The random variableXis normally distributed with mean 100 and standard deviation 4.
If Pr(X< 106) = q, fnd Pr(94
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Question 9
a. Let f:R R, f(x) =x sin (x).
Findf '(x).
1 mark
b. Use the result ofparta. to nd the value of x xcos( )
6
2 dx in the form a+ b.
3 marks
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2012MATHMETH(CAS)EXAM1 10
Question 10
Letf:RR,f(x)=emx + 3x,wheremisapositiverationalnumber.
a. i. Find,intermsofm,thex-coordinateofthestationarypointofthegraphofy =f(x).
ii. Statethevaluesofmsuchthatthex-coordinateofthisstationarypointisapositivenumber.
2+1=3marks
b. Foraparticularvalueofm,thetangenttothegraphofy =f(x)atx=6passesthroughtheorigin.
Findthisvalueofm.
3marks
END OF QUESTION AND ANSWER BOOK
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MATHEMATICAL METHODS (CAS)
Written examinations 1 and 2
FORMULA SHEET
Directions to students
Detach this formula sheet during reading time.
This formula sheet is provided for your reference.
VICTORIAN CURRICULUM AND ASSESSMENT AUTHORITY 2012
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MATHMETH (CAS) 2
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3 MATHMETH (CAS)
END OF FORMULA SHEET
Mathematical Methods (CAS)
Formulas
Mensuration
area of a trapezium:1
2 a b h+( ) volume of a pyramid:
1
3 Ah
curved surface area of a cylinder: 2rh volume of a sphere:4
3
3r
volume of a cylinder: r2h area of a triangle:1
2bc Asin
volume of a cone:1
3
2r h
Calculus
d
dx
x nxn n
( )=
1
x dx
n
x c nn n=
+
+ +
1
1
11
,
d
dxe ae
ax ax( ) = e dx a e cax ax= +
1
d
dxx
xelog ( )( ) =
1
1
xdx x ce= + log
d
dxax a axsin( ) cos( )( ) = sin( ) cos( )ax dx a ax c= +
1
d
dxax a axcos( )( ) = sin( )
cos( ) sin( )ax dx
aax c= +
1
d
dxax
a
axa axtan( )
( )
( ) ==
cos
sec ( )2
2
product rule:d
dxuv u
dv
dxv
du
dx( ) = + quotient rule:
d
dx
u
v
vdu
dxudv
dx
v
=
2
chain rule:dy
dx
dy
du
du
dx= approximation: f x h f x h f x+( ) ( ) + ( )
Probability
Pr(A) = 1 Pr(A) Pr(AB) = Pr(A) + Pr(B) Pr(AB)
Pr(A|B) =Pr
Pr
A B
B
( )
( )transition matrices: S
n= Tn S0
mean: = E(X) variance: var(X) = 2 = E((X)2) = E(X2) 2
Probability distribution Mean Variance
discrete Pr(X=x) =p(x) = xp(x) 2 = (x )2p(x)
continuous Pr(a< X < b) = f x dxa
b( ) =
x f x d x( ) 2 2=
( ) ( )x f x dx