2015.02.11 - load transfer to and through shear walls
DESCRIPTION
wall concretTRANSCRIPT
By R. Terry Malone, P.E., S.E.
SE University, February, 2015 www.LearnWithSEU.com
Load Transfer To And Through Shear Walls
Senior Technical Director Architectural & Engineering Solutions [email protected]
Copyright Woodworks
By: R. Terry Malone, PE, SE Senior Technical Director Architectural & Engineering Solutions
Based on 2012 IBC, ASCE 7-10 and 2008 SDPWS
Copyright McGraw-Hill, ICC
Presentation Based On:
T
Shear Wall
Hdr.
Collector
Chord
h1
Transfer area
Foundation
T
h2 Ve
rt. S
tep
in d
iaph
.
Chord
Load Transfer To And Through Shear Walls
1
Course Description-SEU
The method of distributing lateral forces through simple structures, has been generally understood for decades. However, with the increase in the complexity of plan layouts, understanding how to distribute loads into and out of shear walls is becoming increasingly more difficult. Topics will include how to maintain continuous load paths to shear walls, force transfer through shear walls with openings using the FTAO method and how to design In-plane and out-of-plane offset shear walls.
2
Learning Objectives-SEU
• Load Paths To Shear Walls Understand the detailing required to maintain continuous load paths to
shear walls.
• Shear Walls With Openings Determine how to design shear walls with openings using the FTAO
method of analysis. Special design issues will be discussed.
• Offset Shear Wall Design Understand how to design in-plane and out-of-plane offset shear walls.
• Offset Shear Walls Irregularities Understand the irregularities that are commonly caused by offset shear
walls.
3
Poll Question
Are you familiar with the design of wood shear walls? Segmented?
Yes No
Perforated? Yes No
Force transfer around an opening? Yes No
4
Standard Shear Walls
Segmented Walls FTAO Walls
Perforated Walls
5
Photo courtesy of Willdan Engineering
Segmented SW FTAO SW
6
No opportunity for perforated shear walls at exterior line
In-plane Offset Segmented Shear Walls
Hold Down (option 1) No irreg.
Wd
Hdr
Sill
Nail shtg to each 2x stud (option 2) Wd
Hold down (Typical)
Tie strap
Boundary nailing should be installed at each 2x stud at hold down and each plate
A
Compr. blocks required at all H.D. locations
Blk’g. or rim joist Analyze this Section as a transfer diaph. or transfer wall
Header/collector
Section C
Section B Section A
B C
Col
lect
or
C D
Alt. Config.
Sect. B
Anchor bolts or nails
Shear transfer Conn.
Tie strap
Nail shtg to each 2x stud
Load Paths
Type 4 vert. irreg. SDC B-F
Type 4 vert. irreg. SDC B-F
7
• Type 4 Vertical Irregularity, in-plane offset • ASCE 7-10 12.3.3.3 Elements supporting discontinuous walls SDC B-F • ASCE 7-10 12.3.3.4 25% increase in Fpx SDC D-F (connections)
Hold down (Option 2 -only)
Wd. Wd.
Wd.
Opening
Floor or roof sheathing
Blocking or continuous rim joist
Continuous rim joist, beam or special truss can be used as strut / collector or chord.
Double top plate can be used as strut / collector or chord.
Splice at all joints in boundary element
Opening
Column
Possible perforated or FTAO shear wall
Segmented shear wall
Header
Examples of Drag Struts, Collectors and chords at Exterior Boundaries
Sect.
Optional load path If balcony
Blocking (typ.)
Header
Direction of Load
8
T
Shear Wall (transfer wall)
Hdr.
Collector Chord
Chord
h1
Diaphragm sht’g. elevation
Diaphragm sht’g. elevation
Parapet (typ.)
Vert
. Ste
p in
dia
ph.
Transfer area
Complete Load Path to Foundation- Roof at Different Elevations-Chord Forces
Soil pressure
Chord force
Fo/t Fo/t
Foundation
Parapet (typ.)
Tie strap
T T
If strut action
Shear Wall
9
T
h2
No shear wall perpendicular to this wall at step
Blocking not full height. No diaph. Shr. Transfer (boundary nailing?). Truss top chords in cross-grain bending.
Cross grain bending at gang-nail plate
Assumed bearing of block against truss chord
Incomplete Load Path-Blocking Issues 10
Diaphragm 1 Diaphragm 2
Diaphragm 2 Boundary (typical)
Chord
Chord
Col
lect
or
Stru
t St
rut
Chord
Stru
t
Fundamental Principles: A shear wall is a location where diaphragm forces are resisted (supported), and therefore defines a diaphragm boundary location.
Note: Interior shear walls without a collector or a complete alternate load path are NOT ALLOWED!
Interior Shear Walls and Diaphragm Boundary Elements
SW1
SW2
SW3
Note: All edges of a diaphragm shall be supported by a boundary element.
Diaphragm 1 Boundary (typical)
• Diaphragm Boundary Elements:
• Chords, drag struts, collectors, Shear walls, frames
• Boundary member locations: • Diaphragm and shear wall perimeters • Interior openings • Areas of discontinuities • Re-entrant corners.
• Diaphragm and shear wall sheathing shall not be used to splice boundary elements. • Collector elements shall be provided that are capable of
transferring forces originating in other portions of the structure to the element providing resistance to those forces.
Required for Seismic and wind
1 2
B
3
C
A
11
Let’s take a look at load paths to the shear wall at grid line 2.
Special sheathing nailing required
Strut/truss (Call out force)
End nailed w/2-16d. This connection often has less capacity than the shears applied (e. g. nail capacity failure problem)
Cont. 2x plate w/ 16d at calculated Spacing (cross-grain or end nail failure problem)
16d at calculated spacing (truss to flat blk’g.)
Shear clips
Strut/truss (multiple if required)
Special sheathing nailing required, usually 8d or 10d at 6” o.c. or 4” o.c.
Configuration A
Configuration C Configuration B
Prying Cross-grain
If truss deflects
Optional Shth’g.
Strut/ truss
Typical Collector Framing and Connection Parallel to Shear Wall
Lateral distribution
a b
V
V
L/2 L/2
2x flat cross blk’g. at 24” o.c. w/2 or 4-16d to plate
12
Horizontal and vertical distribution
Typical interior Shear wall or braced wall
Roof trusses @ 24” o.c.
Roof diaphragm force to wall
No shear panels installed or detailed.
GWB ceiling buckling Trusses rotate because there
is nothing present to resist the lateral forces, and the lateral load is not transferred into the wall.
Collector / strut is missing
Typical Collector Framing and Connection Perpendicular to Shear Wall
13
Interior Shear Wall with Shear Panels and Collector Added
Shear panels vary in detailing from designer to designer (mini-shear walls). Add member at end of wall as required.
Trusses also brace wall
Continuous drag strut or collector is required
Tie straps at end of wall as required.
Ceiling
Shea
r wal
l hei
ght
Typical interior Shear wall or braced wall
Note: When designing the shear wall, the forces from the shear panels above must be transposed to the shear wall below.
Wall Perpendicular to Framing 14
Wood shear panels between trusses
Does not appear to have vertical blocking at truss (no shear transfer for vertical shear force).
Shear panel ratios 3:1
The shear panels shown are 24” wide by 6’-0” high. The framing could easily be 16” wide by 12’-0” high or greater.
Wall studs at 8” o.c.
If v=200 plf 400
400
1200
1200
2’
6’
Photo-Typical Shear Panels Courtesy of Willdan Engineering
15
If 3:1 A/R
Side members nailed to truss chords by side grain nailing, full height
Typical Shear Panel Detailing
Side members nailed to truss chords by side grain nailing-2 16d
Top and bottom members nailed to truss chords by end grain nailing-2 16d
Option 1 Option 2 Option 3
16
Blk’g. top and bottom only
Side frm’g. members added
Panel edge buckling
Add vertical nailing member in truss
These connections are part of the complete load path
Section A
Roof sheathing
Roof trusses
Splice strap 1 or 2 sides Blocking at tie strap
Shear panels per detail 3
Hold down straps as required Shear wall
2x blocking w/ shear clips (if req’d)
Single or multiple continuous drag members
Collector Framing Option 2 (Assuming the collector does not fall at a truss joint)
Special strut nailing full length
Connections for shear transfer
Blocking
A
Edge nailing each 2x block
Blocking
17
Section A
Roof sheathing Roof trusses
Shear panels per detail 3
Hold down straps as required
Shear wall
2x blocking w/ shear clips (as req’d.)
Shear clips as required
Special strut nailing full length
Connections for shear transfer
Blocking with nails and/or shear clips (as req’d.)
Edge nailing each 2x Horizontal strap is required across joint if 2x members can not be cont.
A
Single or multiple continuous drag members
Drag Strut Framing Option 3 (Assuming the collector does not fall at a truss joint) 18
Roof sheathing
Roof trusses
Shear panels per detail 3
Shear wall
2x blk’g.
Cont. drag members
Shear clips as required
Edge nailing each 2x Horizontal strap is required across joint if 2x members can not be continuous
A
Shear wall
Drag strut or collector Tr
usse
s (ty
p.)
A B
Section B
Special nailing
Shear panels
Special transfer area nailing (drag shear plus basic diaphragm shear)
Plan View
B
V
V F F
Special nailing required
Drag Strut Framing Option 4 (If the collector falls at a truss joint) 19
Truss joint
3’ 6’ 5.5’
14.5’
4’
3’
2’
1 2
A
B
3
C
D
4
9’
3.6
4500 lb 1.2 w=200 plf
(See recent Testing-APA Form M410)
Tie straps full length of wall per SDPWS section 4.3.5.2
Anchor bolts or nails
(Typical boundary Member)
Typical boundary member
2’ min. per SDPWS Section 4.3.5.2 (2008 requirement)
Many examples ignore gravity loads
FTAO Shear Walls
Cont. Rim joist
Strut/collector
Shear panels or blocking
20
Let’s talk about loads:
(b) Force Transfer Around Opening
Wall pier
Wall pier
Wall pier
Wall pier
Wall pier
Wal
l Pie
r he
ight
W
all p
ier
heig
ht
Wall pier width
Cle
ar h
eigh
t
Wal
l pie
r he
ight
Overall width AF & PA SDPWS Figure 4E
Dr.
Wall pier width
Boundary members
Collector (typ.)
Foundation wall
Allowable Shear Wall Aspect Ratios For FTAO Shear Walls
Notice: Not shown as having to comply w/ A/R
Wd.
Wd.
• Sections exceeding 3.5:1 aspect ratio shall not be considered a part of the wall.
• The aspect ratio limitations of Table 4.3.4 shall apply to the overall wall and the pier sections on each side of the openings
• Minimum pier width=2’-0”.
• A full height pier section shall be located at each end of the wall.
• Where a horizontal offset occurs, portions on each side of the offset shall be considered as separate FTAO walls.
• Collectors for shear transfer shall be provided through the full length of the wall.
Limitations:
21
4500
C
Tie strap/blocking full width
Blocking
Point of inflection is assumed to occur at mid-length (Typ.)
M M
V
V
V
V
M
M
1 2
A
B
3
C
D
4
C
A B
D
F
E
H G
I
L
J
K
T
V
V
M
M
M M
V
V
F=0 lb
F=0 lb F=0 lb
M
F=0
M F=0 Force Transfer Methodology (Diekmann)-Vierendeel Truss/Frame
F=0 lb
F F
Gravity loads to wall
1343.1 4243.1 22
w=200 plf
N.A.
4500 lb
4’
14.5’
208.62 lb
208.62 lb
991.38 lb
587.08 lb
F1B.5
VB.5
1 2
A
B
3
A
B
4
2’
2’
4500 lb
200 plf
200 plf 0=∑M
0=∑MB.5
B.5
2691.38 lb F4B.5
3912.92 lb VB.5
B A
C
A
I
G
B
H
C
V2.5 3’
3’
Free-body of Upper Half and Upper Left Section
Point of inflection
I
H
23
A
C
D
B
F
587.08 VB=587.08
VB.5=587.08 (587.08)
Vc=587.08
587.08
V2.5
1551
.7
V2
(1343.1)
3’
3’
F2b(V) 391.39
F2C(v) 391.39
991.
38
V2
391.
39
(208.62)
F2A
F2B(H)
1381
1037.1
1160.3
F2C(H)
F1B 600
F1C 182.77
E
(0)
(0)
573.23
2’
2’
2’
1 2
0=∑M
0=∑M0=∑M
0=∑M
0=∑M
0=∑M
Units are in lb
Corner tie strap force
Corner tie strap force
H G
J
I
K L
1591
.38
(991
.38)
V3
268.8
1937.1
1551
.7
1551
.7
236.17
3676.6
V3
(4243.1)
(2691.38) VB.5=3912.92
VB=3912.92 3912.92
(3912.92)
VC=3912.92
3912.92
(0)
5.5’
3’
2’
2’
2’
F3(V) 1422.88
F3B(V) 1422.9
F4B 1268.5
F4C 4114.3 F3C(H)
F3B(H)
F3A A
B
3
C
D
4
0=∑M
0=∑M
0=∑M
3’ 3’
3’ 3’
2.5
B.5 B.5
2124.9
1551.7
(4500)
(4500)
F2.5A 1274.9
(xxx) Shears and forces determined in previous step.
0=∑M
0=∑M 0=∑M
200 plf 200 plf 200 plf 200 plf
F2.5C
Resultant Forces on Wall Segments
0=∑V
0=∑H
0=∑V
0=∑V
0=∑V0=∑V
0=∑H
0=∑V
0=∑H
1551.7
1706.9 931 931 931
24
25
Complete Example with narrative and calculations
http://www.woodworks.org/publications-media/solution-papers/
Download Process: • WoodWorks.org website • Publications-Media tab • Wood Solutions Papers
http://www.woodworks.org/wp-content/uploads/Irregular-Diaphragms_Paper1.pdf
3’ 6’ 5.5’
14.5’
4’
3’
2’
1 2
A
B
3
C
D
4
T.D.2 T.D.1
2.67’ 2.67’
9’
3.6
4500 lb
Support
Support
Support
Support
1.2
Example -Blocking and Strapping Partial Width (with uniform load)
w=200 plf
Use results from previous example
Check aspect ratio of transfer Diaphragms/walls
2x blk’g. full depth of TD
Tie straps full depth of TD Transfer
diaphragm sections
26
3676.6
1551
.7
4243.1
1937.1
Transfer Diaphragm Shears and Net Shears using loads and forces from previous example
2.67’ - +
1937.1
3676.6
281.1
2020.6
v= 281.1 2.67
= - 105.3 plf
v= 1656 2.67 = +620.2 plf
v= 2020.6 2.67 = -756.8 plf
-105.3
-756.8
+620.2
+471.5 +408.6
A
B
3
C
D
T.D.2
Sign convention
Transfer diaphragm shears
1591
.4
vnet=349.23-105.38 =+243.93 plf
vnet=349.23+620.2 =+969.45 plf
vnet=349.23-756.8 =-407.55 plf
1975.8
3.6
+303.3 +243.9
+1028.8 +969.5
+1028.8 +969.5
-348.2 -407.6
-348.2 -407.6 +471.5 +408.6
3677.1 lb (+408.57 plf)
4243.1 lb (+471.46 plf)
3143.1 lb (+349.23 plf)
Basic Shear Diagram Summing V=0
vnet=408.57-105.38 =+303.27 plf
vnet=408.6+620.2 =+1028.8 plf
vnet=408.57-756.8 =-348.21 plf
408.6
408.6
408.6
471.5
471.5
471.5
w=200 plf
0=∑V
27
Fo/t
Pier Section Collector Force Diagrams
2.67’
- +
A
B
3
C
D
4
T.D.2
Sign convention
2.83’
Support
Support
Fbot
Ftop
Vtop
v3.6 v4 v3
Basic Shear Diagram
Summing
w
Transfer diaphragm shears
3.6
Fbot
Ftop
Vbot
28
Poll Question
Are you familiar with the common types of irregularities associated with offset shear walls?
Yes No
29
Offset Shear Walls
SW 1
SW 2
Col
lect
or
Collector
Collector
Out-of-plane Offsets In-plane Offsets 30
Potential buckling problem w/ supporting columns and beams
A
B 3
2
1
A.75
A.33
The deflection equation must be adjusted to account for the uniformly distributed load plus the transfer force.
Elements requiring over-strength load combinations
Transfer diaphragm grid line 1 to 3 See Section 12.10.1.1
ASCE 7 Table 12.3-2 Type 4 vertical irregularity-in-plane offset discontinuity 12.3.3.3 Discont. Walls SDC B-F 12.3.3.4 25% incr. SDC D-F
ASCE 7 Table 12.3-1 Type 4 horizontal irregularity-out-of-plane offset discontinuity in the LFRS 12.3.3.3 Discont. Walls SDC B-F 12.3.3.4 25% incr. SDC D-F
ASCE 7 Table 12.3-2 Type 4 vertical irregularity- in-plane offset discontinuity in the LFRS (if no H.D. at A.25) 12.3.3.3 Discont. Walls SDC B-F 12.3.3.4 25% incr. SDC D-F
Relevant Irregularities Per ASCE 7-10
Tables 12.3-1 and 12.3-2
A.25
31
Out-of-Plane Offset Shear Walls Assumed to act in the Same Line of Resistance
Loads
Col
lect
or
Collector
Collector
SW
SW
Transfer area
Offset
Discont. drag strut
Dra
g st
rut
Dra
g
stru
t
SW
Col
lect
or
Collector
Collector
• Offset walls are often assumed to act in the same line of lateral-force-resistance.
• Calculations are seldom provided showing how the walls are interconnected to act as a unit, or to verify that a complete lateral load path has been provided.
• Collectors are required to be installed to
transfer the disrupted forces across the offsets.
Discont. drag strut
Typical mid-rise multi-family structure at exterior wall line
ASCE 7-10 Section 14.5.2 Where offset walls occur in the wall line, the shear walls on each side of the offset should be considered as separate shear walls unless provisions for force transfer around the offset are provided. Check for Type 2 horizontal irregularity Re-entrant corner irregularity
32
Poll Question
Do you know how to analyze offset shear walls?
Yes No
33
Cant.
Mid-rise Multi-family
SW SW SW SW
SW SW SW SW SW
SW
No exterior Shear walls
Flexible, semi-rigid, or rigid??? 34
TD3
TD1
TD2
SW4
SW3
SW5
SW2
SW1
Diaphragm stiffness changes
Multi Story, Multi-family
1
2
3
Loads
I1 I2 I3
Higher shears and nailing requirements
ASCE7-10 1.3.5 - Cont. load Paths 12.1.3 - Cont. load paths-inter-connection ties 12.10.1-Openings, re-entrant. –transfer of dis-cont. forces combined with other forces 12.10.2-Collector elements
I1 I2
SW
SW4
SW3
SW5
SW1
1
2
3 Transfer Area Higher shears and nailing Reqmts.
Collector (typ.)
Higher shears and nailing Reqmts.
SW2
Col
lect
or
Stru
t/cho
rd
Bea
m
TD2
TD1
Stru
t
Main diaphragm
becomes TD3
Optional Framing Layouts
Collector (typ.)
35
SW 1
SW 2
25’ 20’
15’
200
plf
Drag strut
Cho
rd
colle
ctor
s
Cho
rd
80’
35’ 50’
Drag strut is discontinuous
1 2
A
B
3
C
4
10’ 25’ 5’
15’
200
plf
TD1 C
hord
co
llect
ors
Pos. direction + -
SW 3 SW 4
8’
8’
Drag strut
Collector
5’
12’ 45’
80’
Drag strut
Drag strut C
hord
Drag strut
Example 3-Diaphragm with Horizontal End Offset Longitudinal Loading-Out-of-plane offset Shear Walls
Assumptions: 1. Assume shear walls at grid lines B and C act along the same line of lateral-force- resistance. 2. Assume the total load distributed to grid lines A and B/C= wL/2 .
Offset SW
Offset SW
Support
Support
36
Diaphragm 2
Diaphragm 1
SW 2
35’
50’
1 2
A
B
3
C
10’
8’
Pos. direction + -
8’
2
SW 3
Pos.
40 plf 160 plf
200
plf
200
plf
SW 1
Vnet=Vsw-Vdiaph
Fend F2B
F2B
VA
VB
Basic Diaphragm Shears and Transfer Diaphragm Shear
Neg
.
200 plf
Vsw2=wL/2, vsw2=Vsw2/Lsw2 plf ∑ Vsw1, sw3, sw4=wL/2, vsw=∑V1,3,4/(Lsw1+Lsw3+Lsw4) plf
Determine Force transferred Into Transfer Diaphragm
Total Shear to Shear Walls (Assumed)
17’
SW 4
15’
F2B
VA
VC
VA
VC
VB
37
TD1 Diaphragm 2 Diaphragm 1
25’ 20’
15’
80’
1 2
A
B
3
C
No net change Net change in TD
No net change
35’
Net Diaphragm Shears
8’ SW 1
15’ SW 3 SW 4
SW 2
Pos. direction + -
50’
Vnet sw
Pos.
N
eg.
8’
4
V=Basic shear +/- TD shear plf
(Net shear)
Vnet sw
Vnet sw Vnet sw V=Basic shear +/- TD shear plf
(Net shear)
VA
VC
VA
VC
VB
38
15’
-
F2B
F2B
1
2
A
B
3
C
Transverse Collector Force Diagrams
8’ SW 1 8’ SW3 15’ SW 4
Pos. direction + -
SW 2
Net shear
Special nailing
So far, so good
Net shear (TD tension chord and Diaph.2 compression chord)
Net shear -vB
+vC
x1’
x2’
+F
-F
F3B
F3B
Diaphragm 2
39
25’ 20’
15’
80’
F= F2B
Fstart
F3C
1 2
A
B
3
C
Longitudinal Strut Force Diagrams
SW 4
Pos. direction + -
SW 2
15’
Fend
F2B
F4C = -xxx lb (Error)
F2A Fend
F3A
F4A=+xxx lb (Error)
Note: Neither force diagram closes to zero, therefore error. Notice that they do not close by the same amount.
8’
12’
8’
45’
5’ 5’ 10’
80’
SW 1
SW 3
Vnet sw
Vnet sw Vnet sw
Vnet sw
Fstart Fend
Fstart
40
4600 lb
25’ 20’
15’
80’
1 2
A
B
3
C
Adjusted Longitudinal Strut Force Diagrams (8% to 20% increase to B/C) [Amount shifted to B/C depends on the offset to span ratio of the transfer diaphragm]
SW 1
SW 3 SW 4
Pos. direction + -
SW 2
5400 lb
Line needs to move in this direction
The shear wall shears need to be higher in order to move the force diagram in this direction
Line needs to move in this direction
The shear wall shears needs to be lower in order to move the force diagram in this direction
Load distribution needs to increase towards line B/C. Increase the load to B/C by the amount off +/-.
Calculated forces
Revised forces
41
In-plane Offset Shear Walls
42
Wd
Hdr
Sill
Nail shtg. To each 2x stud
No hold down (option 1) Hold-down (option 2)
Blk’g. or rim joist
Sections do not comply with the required aspect ratio for a perforated or FTO shear wall.
4’
8’
8’
8’
12’
1’
2000 lb
3000 lb
Hdr/collector
Wd
Sill
DL=150 plf
DL=250 plf
SW2
SW1
6’
Example 4-In-plane Offset Segmented Shear Wall -with Gravity Loads
1’
Col
lect
or
VHdr=960 lb
VHdr=450 lb
A B C
ASCE 7 Table 12.3-2-Type 4 vertical irreg.- in-plane discontinuity in the LFRS if no hold down at B.
12.3.3.3 & 12.3.3.4 SDC B-F SDC D-F 43
Ends of wall panels do not line up. Requires special nailing of sheathing into stud below.
Nailing found in field was 12” o.c.
Requires same number of studs above and below with boundary nailing each stud Solid blocking
required
Photo-In-plane Offset Segmented Shear Walls
No hold-down below
Hold down
Hold down
44
Wall and Transfer Diaphragm Shears
5000 lb
8’
8’ 4’
2920 lb 1080 lb
+ +
2000 lb
8’
8’
+ Pos. direction -
5000 lb 1’
12’ 416.67 lb 416.67 lb
416.67 416.67 3370
1080
Upper Shear Wall
Rim joist
135 365
Col
lect
or
1080 lb 330 plf (incl. wall DL)
Lower Shear Wall
TD shears-lbs. (plf)
w=230 plf (incl. wall DL)
+ - 8’ 4’
SW2
SW1
+250
plf
+416
.67
plf
1260 (-157.5)
1020 (-127.5)
60 (+7.5)
1620 (+202)
2490 lb 9700 lb
+ + +
+
1 2
+424.1
+259.2
+618.7 +289.2
VHdr=450 lb
VHdr=960 lb
1260 lb (-157.5)
1620 lb (+202)
Sign Convention
+ shears
- shears
Aver.=250 plf +
+450 lb 3370 lb
Bas
ic S
hear
45
+ T
T
+ +
+
2000 lb
3000 lb 1’
8’
8’
8’ 4’
C
+ Pos. direction -
Vertical Collector Forces
2nd floor Rim joist
+ + SW1
SW2 D
epth
TD
1 2
+424.2
+259.2
+618.7
135 365
+289.2
Roof
+
T
C
+ +
+
2000 lb
3000 lb
8’
1’
8’
8’
8’ 4’ C
2nd floor Rim joist
+ + SW1
SW2
Dep
th T
D
1 2
+424.2
+259.2
+618.7
135 365
+289.2
Roof C
Horizontal Collector Forces
T
C
2490 lb 2490 lb
8’
416.67 365(8)+450=3370
9700 lb
VHdr=990 lb
416.67
Sign Convention Collector Force Diagrams
9700 lb
46
Conclusion:
Maintaining continuous load paths to the vertical lateral force resisting elements is essential. A load path is only as good as its weakest link.
Offset shear walls can create challenging design problems. It is important to recognize these issues and the irregularities they cause.
47
By R. Terry Malone, P.E., S.E.
SE University, February, 2015 www.LearnWithSEU.com
This Concludes Our Presentation on: Load Transfer To And Through Shear Walls
Senior Technical Director Architectural & Engineering Solutions [email protected]
Copyright
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CHALLENGE QUESTION:
Which type of Shear Wall is the answer to this session’s Challenge Question?
A. Perforated B. Segmented C. Force Transfer Around Openings (FTAO) D. None of the above
Please circle the answer that is announced so that you can use the information to complete your quiz (NY) or form (FL) for PDH.