20.9 the diffusion equationcontents.kocw.net/kocw/document/2015/pusan/limmanho1/4.pdf(2015) chemical...
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(2015) Chemical Kinetics by M Lim 1
20.9 The diffusion equation
( ) ( )
( ) ( )
2
2
1
J x Adt J x l Adtct Al dt
J x J x l Jl x
c cD Dx x x
− +∂=
∂− + ∂
= = −∂
∂ ∂ ∂ = − − = ∂ ∂ ∂
2
2 (Fick's 2nd law)c cDt x
∂ ∂=
∂ ∂
Time-dependent diffusion process:
can be used to predict c(x,t)
(2015) Chemical Kinetics by M Lim 2
20.9 (b) solutions of the diffusion equation2
2
c cDt x
∂ ∂=
∂ ∂2
0 41Solution for 1-d, ( , )xDtnc x t e
A Dtπ−
=
n0 x
Dt=
2
22
2
1Gaussian, ( )2
2 4 2
x
G x e
Dt Dt
σ
σ
πσ
σ
−=
→ ==
( )
2
2
40 3 2
for 3-d
1If spherically symmetric, ( , )8
rDt
c D ct
c r t n eDtπ
−
∂= ∇
∂
=
A
(2015) Chemical Kinetics by M Lim 3
Review 20-5
[ ],
1 (force arising from gradient)
(Stokes-Einstein relation)
, (Einstein relation)
p T
cRTc x
kTDf
zFD uRTu DRT zF
∂ = − ∂
=
= =
F
2
2
c cDt x
∂ ∂=
∂ ∂
zuFλ =
2
0 41Solution for 1-d, ( , )xDtnc x t e
A Dtπ−
=
2 for 3-dc D ct
∂= ∇
∂
( )
2
40 3 2
1If spherically symmetric, ( , )8
rDtc r t n e
Dtπ
− =
(2015) Chemical Kinetics by M Lim 4
20.9 (a) Diffusion with convection
Convective flux, ( : flowing velocity)
cAv tJ cv vA t
c J cvt x x
∆= =
∆∂ ∂ ∂
= − = −∂ ∂ ∂
Transport by the motion of a streaming fluid
2
2 (contribution from reaction)c c cD vt x x
∂ ∂ ∂= − +
∂ ∂ ∂Used in reactor design,
the utilization of resources in living cells
• Measurement of D: capillary techniquediaphragm technique
Generalized diffusion eqn (diffusion with convection)
(2015) Chemical Kinetics by M Lim 5
20.10 Diffusion probabilitiesThe solution of the diffusion equation can be used to predict c(x,t), and to calculate the net distance through which the particles diffuse in a given time
The average distance travelled by a diffus
2
ing par
(see ne
ticl
xt s
e
lide)Dtxπ
=
When particles diffuse in both directions,<x>=0 at all times
10 2 1
2
10 10 2
2 5 1
7 5
6 3
4 1
3 3
When 5 10
For 0.1 ,
2 5 10 0.1 10
10 10
10 10 10 10 10 10 10 10
D m s
s x
m
x m for s
m for sm for sm for sm for s
− −
− −
− −
− −
− −
−
−
= ×
= ⋅ × ⋅ =
=
( )2
0
2
2 2
2x
x x
x D
P x Dt
tσ
∞
=
=
=
=∫
( )2
0
2
2 24 6
6 r
r r P r r
r
r
D
d Dt
t
π
σ
∞=
= =
=∫For 3D
(2015) Chemical Kinetics by M Lim 6
20.10 Diffusion probabilities (Ex 20.5)
x0
2
2
2
0
0
2 3 2
0
12
12
41
4
ax
ax
ax
e dxa
xe dxa
x e dx a
aDt
π
π
∞ −
∞ −
∞ − −
=
=
=
=
∫
∫
∫( )
( )
2
2
0 0
0
0 00
4
0 40
0
The number of particles in a slab: Probability that any of the particles in the slab:
=
1
1
A
A
A
A
xA Dt
xDt
cN AdxN n N
cN AdxP x dx dxN
cN Ax xP x x dxN
N A nx e dxN A Dt
eDt
π
π∞ ∞
∞ −
−
=
=
= =
=
=
∫ ∫
∫
( )
2
2
40
2 2 2 40 0
1
2
2
xDt
xDt
xe dxDt
x x P x
Dt
x Dte dxDt
π π
π
∞ −
∞ ∞ −
=
= = =
∫
∫ ∫
2
0 4
Solution for 1-d,
1( , )xDtnc x t e
A Dtπ−
=
(2015) Chemical Kinetics by M Lim 7
20.10 Diffusion probabilities for 3D2
2
2
2
2
0
0
2 3 2
0
320
4 5 2
0
12
12
41
23
4 21
4
ax
ax
ax
ax
ax
e dxa
xe dxa
x e dx a
x e dxa
x e dx a
aDt
π
π
π
∞ −
∞ −
∞ − −
∞ −
∞ − −
=
=
=
=
=
=
∫
∫
∫
∫
∫( )
( )
( )( )
( )( )
2
2
2
43 2
2 243 20 0
2 2 2 2 243 20 0
,
18
14 4 48
14 48
6
π
π πππ
π ππ
−
∞ ∞ −
∞ ∞ −
=
= = =
= = =
∫ ∫
∫ ∫
rDt
rDt
rDt
For spherically symmetric case
P r eDt
Dtr rP r r dr re r drDt
r r P r r dr r e r drDt
Dt
(2015) Chemical Kinetics by M Lim 8
20.10 Diffusion probabilities for 2D2
2
2
2
2
0
0
2 3 2
0
320
4 5 2
0
12
12
41
23
4 21
4
ax
ax
ax
ax
ax
e dxa
xe dxa
x e dx a
x e dxa
x e dx a
aDt
π
π
π
∞ −
∞ −
∞ − −
∞ −
∞ − −
=
=
=
=
=
=
∫
∫
∫
∫
∫( )
( )
( )
2
2
2
4
40 0
2 2 2 40 0
,
14
12 24
4412 2
π
π π ππ
π ππ
−
∞ ∞ −
∞ ∞ −
=
= = =
= = =
∫ ∫
∫ ∫
rDt
rDt
rDt
For radially symmetric case
P r eDt
r rP r rdr re rdr DtDt
r r P r rdr r e rdrDt
Dt
(2015) Chemical Kinetics by M Lim 9
20.11 The statistical view
( )2
222 xtP x e
t
τλτ
π−
=
2 2
For a perfect gas, ,
and : mean free path 1 1
2 2 2 3
c
cD c c
λτ
λ
λ λ λ λτ λ
=
= = = →
Random walk: particles jump through a distance λ (step length) in a time τ (duration)
The probability of a particle being at a distance x from the origin after a time tin 1-d random walk.
( )2 2
22 4
2
2
12 4
x xt DtP x e e
t
t Dt
τλτ
πτλ
− −= ∝
=
Einstein-Smoluchowski equationLink between the microscopic details of particle motion and the macroscopic parameters relating to diffusion.
Illus. For SO42-, D=1.1×10-9 m2 s-1, a=210 pm
Suppose it jumps through its own diameter, λ=2a, then τ=80 ps,meaning that 1×1010 jumps per second.
2
2D λ
τ=
(2015) Chemical Kinetics by M Lim 10
Review 20-6[ ]
,
1 (force arising from gradient)
(Stokes-Einstein relation)
, (Einstein relation)
p T
cRTc x
kTDf
zFD uRTu DRT zF
∂ = − ∂
=
= =
F
2
2 (contribution from reaction)c c cD vt x x
∂ ∂ ∂= − +
∂ ∂ ∂2 2 for 1D
4 for 2D
6 for 3D
x Dt
Dt
Dt
=
=
=( )
2
22
22 2
xtP x e D
t
τλτ λ
π τ−
= =
(2015) Chemical Kinetics by M Lim 11
20.11 The statistical view-1
( ) ( )
( ) ( )
(1-d) and
The net distance after steps: ( ) ,, net distance of travel:
1 1Since , and 2 2
! !The number of way to arrive at : ( )1 1! ! ! !2 2
R L
R L
R L R L
R L
tN
N N Nn N N x n
N N N N N n N N n
N Nx W xN N N n N n
τλλ
=
−≡ − =
− = = + = −
= = + −
( ) ( )
Toral number of step: 2! !The probability of the net distance walked being : ( )
1 1! ! 2 ! !2 2
1For large , ln ! ln - ln 2 (Stirling's approximation)2
ln ( )
N
NR L
N Nx P xN N N n N n
N x x x x
P x
π
= = + −
≈ + +
( ) ( )1 1ln ! ln ! ln ! ln 22 2
N N n N n N = − + − − −
(2015) Chemical Kinetics by M Lim 12
20.11 The statistical view-2( ) ( ) ( )
( ) ( ) ( )
1 1 1 1 1ln ( ) ln ln 2 ln ln 22 2 2 2 2
1 1 1 1 ln ln 2 ln 22 2 2 2
1 2
P x N N N N n N n N n
N n N n N n N
N
π π
π
= + − + − + + + − + +
− − + − − − + −
= +
( ) ( ) ( )
( ) ( ) ( )
( ) ( )
( )
1ln 1 ln 1 ln 221 1 ln 1 ln 2 ln 2 ln 22
1 1 1 ln 1 ln 1 1 ln2 2 2
1 1 ln 12
N N n N n N n
N n N n N n N
nN N N n N n NNnN nN
π
− + + + + + +
− − + − + − + − −
= + − + + + − + +
− − + − ( )
( ) ( )
( ) ( )
( ) ( )2
2
1 1 ln ln 2 ln 22
1 1 1 ln 2 ln ln 2 1 ln 1 1 ln 12 2 2
2 1 1 ln 1 ln 1 1 ln 12 2
2 1 1 1 1 ln 1 12 2 2 2
N n N
n nN N n N nN N
n nN n N nN N N
n n n nN n N nN N N N
π
π
π
π
− − + − −
= − − − + + + − − + −
= − + + + − − + −
− + + − − + − − −
2
2N
(2015) Chemical Kinetics by M Lim 13
20.11 The statistical view-3( )( ) ( )( )
( ) ( )
( ) ( )
( )
2 2
2 2
2 2 3
2 2
2 2 3
2 2
2 2
2
2 1 1 1 1ln ( ) ln 1 12 2 2 2
1 11 12 22 1 ln
2 1 11 12 2
2 1 1 ln 12 2
n n n nP x N n N nN N N N N
n n n nN NN N N N
N n n n nN NN N N N
n nNN N N
π
π
π
= − + + − − + − − −
+ − + + − = −
+ − + − + + +
= − − + + +
( )
( )
2
2
2
2 2
2
2 2 2 2 2
2 2
2
2
2
1 12
2 1 2 2 1 2 ln 1 ln2 2
2ln ( ) ln2
2( ) and
2( )
nN
xt
n nNN N
n n n n nNN N N N N N N
nP xN N
x tP x e n NN
P x et
τλ
π π
π
π λ τ
τπ
−
−
− + +
= − − + + = − − − +
≈ −
= = =
∴ =