# 2.3 visualizing data graphic relationships. equationtype of relationship shape of graph

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2.3 Visualizing DataGraphic Relationships

EquationType of RelationshipShape of Graph

EquationType of RelationshipShape of Graphy=mx + b

EquationType of RelationshipShape of Graphy=mx + bLinear (direct)

EquationType of RelationshipShape of Graphy=mx + bLinear (direct)line

EquationType of RelationshipShape of Graphy=mx + bLinear (direct)line

y=ax2 + bx + c

EquationType of RelationshipShape of Graphy=mx + bLinear (direct)line

y=ax2 + bx + cquadratic

EquationType of RelationshipShape of Graphy=mx + bLinear (direct)line

y=ax2 + bx + cquadraticparabola

EquationType of RelationshipShape of Graphy=mx + bLinear (direct)line

y=ax2 + bx + cquadraticparabolay=a/x or xy=a

EquationType of RelationshipShape of Graphy=mx + bLinear (direct)line

y=ax2 + bx + cquadraticparabolay=a/x or xy=aInverse

EquationType of RelationshipShape of Graphy=mx + bLinear (direct)line

y=ax2 + bx + cquadraticparabolay=a/x or xy=aInversehyperbola

What type of relationship and graph would be represented between the variables in each of the following examples?

EquationRelationshipGraph ShapeK=8c + 5L = 4/m +7 y = 5x2 + 6x 1P = 1/ T

What type of relationship and graph would be represented between the variables in each of the following examples?

EquationRelationshipGraph ShapeK=8c + 5Linear (direct)L = 4/m +7 y = 5x2 + 6x 1P = 1/ T

What type of relationship and graph would be represented between the variables in each of the following examples?

EquationRelationshipGraph ShapeK=8c + 5Linear (direct)lineL = 4/m +7 y = 5x2 + 6x 1P = 1/ T

EquationRelationshipGraph ShapeK=8c + 5Linear (direct)lineL = 4/m +7 inversey = 5x2 + 6x 1P = 1/ T

EquationRelationshipGraph ShapeK=8c + 5Linear (direct)lineL = 4/m +7 inversehyperbolay = 5x2 + 6x 1P = 1/ T

EquationRelationshipGraph ShapeK=8c + 5Linear (direct)lineL = 4/m +7 inversehyperbolay = 5x2 + 6x 1quadraticP = 1/ T

EquationRelationshipGraph ShapeK=8c + 5Linear (direct)lineL = 4/m +7 inversehyperbolay = 5x2 + 6x 1quadraticparabolaP = 1/ T

EquationRelationshipGraph ShapeK=8c + 5Linear (direct)lineL = 4/m +7 inversehyperbolay = 5x2 + 6x 1quadraticparabolaP = 1/ T inverse

EquationRelationshipGraph ShapeK=8c + 5Linear (direct)lineL = 4/m +7 inversehyperbolay = 5x2 + 6x 1quadraticparabolaP = 1/ T inversehyperbola

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