2.4_dividing polynomials.pdf

Upload: amanda-martinez

Post on 02-Jun-2018

215 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    1/25

    Section 2.4

    Dividing Polynomials;Remainder and Factor Theorems

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    2/25

    Long Division of Polynomials

    and

    The Division Algorithm

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    3/25

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    4/25

    Long Division of Polynomials

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    5/25

    Long Division of Polynomials

    2 3 2 9 6 5x x x

    12 5x

    4

    13

    3x

    29 6x x

    12 8x

    13

    3 2x

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    6/25

    Long Division of Polynomials with Missing Terms

    2 3

    3 2

    2

    2

    x +5x -3 x 3x 2

    x +5x 3x

    -5x 6x 2

    -5x 25x 15

    31x- 17

    5x 231 17

    5 3

    x

    x x

    You need to leave a hole when you have

    missing terms. This technique will help

    you line up like terms. See the dividend

    above.

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    7/25

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    8/25

    Example

    Divide using Long Division.3 22 5 6 4 +7x x x

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    9/25

    Example

    Divide using Long Division.2 4 32 1 8 3 +5 1x x x x x

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    10/25

    Dividing Polynomials Using

    Synthetic Division

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    11/25

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    12/25

    Comparison of Long Division and Synthetic

    Division of X3+4x2-5x+5 divided by x-3

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    13/25

    Steps of Synthetic Division dividing 5x3+6x+8 by x+2

    Put in a 0 for the missing term.

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    14/25

    2 5 + 7 - 1

    Using synthetic division instead of long division.

    Notice that the divisor has to be a binomial of

    degree 1 with no coefficients.

    5

    10

    3

    6

    5

    2

    55 3

    22 5 7 1

    x

    xx x x

    Thus:

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    15/25

    Example

    Divide using synthetic division.3 23 5 7 8

    4

    x x x

    x

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    16/25

    The Remainder Theorem

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    17/25

    If you are given the function f(x)=x3- 4x2+5x+3 and

    you want to find f(2), then the remainder of this

    function when divided by x-2 will give you f(2)

    f(2)=5

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    18/25

    2(1) for f(x)=6x 2 5 is

    1 6 -2 5

    6 4

    6 4 9

    f(1)=9

    f x

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    19/25

    Example

    Use synthetic division and the remaindertheorem to find the indicated function value.3 2( ) 3 5 1; f(2)f x x x

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    20/25

    The Factor Theorem

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    21/25

    Solve the equation 2x3-3x2-11x+6=0 given that 3 is

    a zero of f(x)=2x3-3x2-11x+6. The factor theorem

    tells us that x-3 is a factor of f(x). So we will use

    both synthetic division and long division to show

    this and to find another factor.

    Another factor

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    22/25

    Example

    Solve the equation 5x2

    + 9x

    2=0 giventhat -2 is a zero of f(x)= 5x2 + 9x - 2

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    23/25

    Example

    Solve the equation x3

    - 5x2

    + 9x - 45 = 0 giventhat 5 is a zero of f(x)= x3- 5x2+ 9x 45.

    Consider all complex number solutions.

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    24/25

    (a)

    (b)

    (c)

    (d)

    3 2Divide 2 8 3x x x x 2

    2

    2

    2

    8

    4 24 14

    344 14

    3

    x x

    x xx x

    x xx

  • 8/11/2019 2.4_Dividing Polynomials.pdf

    25/25

    (a)

    (b)

    (c)

    (d)

    3 2

    Use Synthetic Division and the Remainder

    Theorem to find the value of f(2) for the function

    f(x)=x +x - 11x+10

    2

    0

    5

    12