2.5 apply the remainder and factor theorems p. 120

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2.5 Apply the Remainder and Factor Theorems p. 120 How do you divide polynomials? What is the remainder theorem? What is the difference between synthetic substitution and synthetic division? What is the factor theorem?

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2.5 Apply the Remainder and Factor Theorems p. 120. How do you divide polynomials? What is the remainder theorem? What is the difference between synthetic substitution and synthetic division? What is the factor theorem?. - PowerPoint PPT Presentation

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Page 1: 2.5 Apply the Remainder and Factor Theorems p. 120

2.5 Apply the Remainder and Factor Theorems p. 120

How do you divide polynomials?What is the remainder theorem?

What is the difference between synthetic substitution and synthetic division?

What is the factor theorem?

Page 2: 2.5 Apply the Remainder and Factor Theorems p. 120

When you divide a Polynomial f(x) by a divisor d(x), you get a quotient polynomial q(x) with a remainder r(x) written:

f(x) = q(x) + r(x)d(x) d(x)

Page 3: 2.5 Apply the Remainder and Factor Theorems p. 120

The degree of the remainder must be less than the degree of the divisor!

Page 4: 2.5 Apply the Remainder and Factor Theorems p. 120

Polynomial Long Division:

You write the division problem in the same format you would use for numbers. If a term is missing in standard form …fill it in with a 0 coefficient.

Example: 2x4 + 3x3 + 5x – 1 = x2 – 2x + 2

Page 5: 2.5 Apply the Remainder and Factor Theorems p. 120

1503222 2342 xxxxxx

2x4 = 2x2

x2

2x2

Page 6: 2.5 Apply the Remainder and Factor Theorems p. 120

1503222 2342 xxxxxx

2x2

+4x2-4x32x4-( )

- 4x27x3 +5x

7x3 = 7x x2

+7x

7x3 - 14x2 +14x-( )

10x2 - 9x -1

+10

10x2 - 20x +20-( )

11x - 21

remainder

Page 7: 2.5 Apply the Remainder and Factor Theorems p. 120

The answer is written:

2x2 + 7x + 10 + 11x – 21 x2 – 2x + 2

Quotient + Remainder over divisor

Page 8: 2.5 Apply the Remainder and Factor Theorems p. 120

Now you try one!

y4 + 2y2 – y + 5 =y2 – y + 1

Answer: y2 + y + 2 + 3 y2 – y + 1

Page 9: 2.5 Apply the Remainder and Factor Theorems p. 120

2. (x3 – x2 + 4x – 10) (x + 2)

SOLUTION

Write polynomial division in the same format you use when dividing numbers. Include a “0” as the coefficient of x2 in the dividend. At each stage, divide the term with the highest power in what is left of the dividend by the first term of the divisor. This gives the next term of the quotient.

Page 10: 2.5 Apply the Remainder and Factor Theorems p. 120

Multiply divisor by x3/x = x2.

x3 + 2x2

–3x2 + 4x Subtract. Bring down next term.Multiply divisor by –3x2/x = –3x.

– 3x2 – 6x

10x – 1 Subtract. Bring down next term.

Multiply divisor by 10x/x = 10.

10x + 20

– 30 remainder

x2 – 3x + 10 x + 2 x3 – x2 + 4x – 10)

quotient

Page 11: 2.5 Apply the Remainder and Factor Theorems p. 120

x3 – x2 +4x – 10x + 2

= (x2 – 3x +10)+ – 30 x + 2

ANSWER

OR…

Page 12: 2.5 Apply the Remainder and Factor Theorems p. 120

Use Synthetic Division (x3 – x2 + 4x – 10) (x + 2) Set x + 2 = 0. Solve for x x = −2 Use − 2 as the divisor for synthetic

division which is the same as synthetic substitution.

Synthetic division can be used to divide any polynomial by a divisor of the form “x −k”

Page 13: 2.5 Apply the Remainder and Factor Theorems p. 120

Remainder Theorem:

If a polynomial f(x) is divisible by (x – k), then the remainder is r = f(k).

Now you will use synthetic division (like synthetic substitution)

f(x)= 3x3 – 2x2 + 2x – 5 Divide by x - 2

Page 14: 2.5 Apply the Remainder and Factor Theorems p. 120

F(x) = x3 – x2 + 4x – 10 (x + 2)

– 2 1 −1 4 −10

– 2 6 – 20

1 – 3 10 – 30ANSWER

SOLUTION

Page 15: 2.5 Apply the Remainder and Factor Theorems p. 120

f(x)= 3x3 – 2x2 + 2x – 5 Divide by x - 2 Long division results in ?...... 3x2 + 4x + 10 + 15

x – 2 Synthetic Division: f(2) = 3 -2 2 -5

23

6

4

8

10

20

15

Which gives you: 3x2 + 4x + 10 + 15 x-2

Page 16: 2.5 Apply the Remainder and Factor Theorems p. 120

Synthetic Division

Divide x3 + 2x2 – 6x -9 by (a) x-2 (b) x+3 (a) x-2 1 2 -6 -9

2 1

2

4

8

2

4

-5

Which is x2 + 4x + 2 + -5 x-2

Page 17: 2.5 Apply the Remainder and Factor Theorems p. 120

Synthetic Division Practice cont.

(b) x+3 12 -6 -9 -

31

-3

-1

3

-3

9

0

x2 – x - 3

Page 18: 2.5 Apply the Remainder and Factor Theorems p. 120

Factor Theorem:

A polynomial f(x) has factor x-k if f(k)=0

note that k is a ZERO of the function because f(k)=0

Page 19: 2.5 Apply the Remainder and Factor Theorems p. 120

Factoring a polynomial

Factor f(x) = 2x3 + 11x2 + 18x + 9 Given f(-3)=0

Since f(-3)=0 x-(-3) or x+3 is a factor So use synthetic division to find the

others!!

Page 20: 2.5 Apply the Remainder and Factor Theorems p. 120

Factoring a polynomial cont.

211 18 9

-3 2

-6

5

-15

3

-9

0

(x + 3)(2x2 + 5x + 3)

So…. 2x3 + 11x2 + 18x + 9 factors to:

Now keep factoring-- gives you:

(x+3)(2x+3)(x+1)

Page 21: 2.5 Apply the Remainder and Factor Theorems p. 120

Your Turn…Factor the polynomial completely given that x – 4 is a factor. f (x) = x3 – 6x2 + 5x + 12

SOLUTION

Because x – 4 is a factor of f (x), you know that f (4) = 0. Use synthetic division to find the other factors.

4 1 – 6 5 12

4 – 8 –12

1 – 2 – 3 0

Page 22: 2.5 Apply the Remainder and Factor Theorems p. 120

Use the result to write f (x) as a product of two factors and then factor completely.

f (x) = x3 – 6x2 + 5x + 12 Write original polynomial.

= (x – 4)(x2 – 2x – 3) Write as a product of two factors.

= (x – 4)(x –3)(x + 1) Factor trinomial.

Page 23: 2.5 Apply the Remainder and Factor Theorems p. 120

Your turn!

Factor f(x)= 3x3 + 13x2 + 2x -8 given f(-4)=0

(x + 1)(3x – 2)(x + 4)

Page 24: 2.5 Apply the Remainder and Factor Theorems p. 120

Finding the zeros of a polynomial function

f(x) = x3 – 2x2 – 9x +18. One zero of f(x) is x=2 Find the others! Use synthetic div. to reduce the degree

of the polynomial function and factor completely.

(x-2)(x2-9) = (x-2)(x+3)(x-3) Therefore, the zeros are x=2,3,-3!!!

Page 25: 2.5 Apply the Remainder and Factor Theorems p. 120

Your turn!

f(x) = x3 + 6x2 + 3x -10 X=-5 is one zero, find the others!

The zeros are x=2,-1,-5 Because the factors are (x-2)(x+1)(x+5)

Page 26: 2.5 Apply the Remainder and Factor Theorems p. 120

How do you divide polynomials?

By long division What is the remainder theorem?

If a polynomial f(x) is divisible by (x – k), then the remainder is r = f(k).

What is the difference between synthetic substitution and synthetic division?

It is the same thing What is the factor theorem?

If there is no remainder, it is a factor.

Page 27: 2.5 Apply the Remainder and Factor Theorems p. 120

AssignmentPage 124, 7, 9, 11-15 odd, 21-23 odd, 29-33 odd, 35- 37 all