PowerPoint “”
*
*DDA
3-2
3-3
3-3
3

XeYXYe0 (3-1)
OE PXY
3-5
Y
F>0
FPi(XiYi)Fi
3
Fi≥0Pi(XiYi)OEXXi+1Yi+1Xi+1=Xi+1Yi+1=Yi ,
Fi<0PiXiYiOE Y(Xi+1Yi+1)Xi+1=Xi ,Yi+1Yi1
(3-3)
3
 
E′(-Xe,-Ye)
3-8L1L2L3L4XYXY
3-8YXF≥0XXXXF<0YYYY
L3
y
x
AXaYaBXbYbRPXY
X2Y2R2=0
3-10
3-10aABSR1F≥0YF<0X
A
D
Y
SR1
NR1

Fi≥0Pi(XiYi)Y(Xi1,Yi1)Xi1XiYi1Yi1
(3-6)
Fi<0XXi1Yi
(3-7)

XY
∑=Xb-Xa+Yb-Ya
3-2 AB3-12A04B40
3-12
(3-8)
XXXY
3-13abSR1SR2SR3SR4NR1NR2NR3NR43-13
XYF ≥0,
3-3
3-3
(3-10)
—mm/
3
3-16 Y=f(t)
3




OEOE(74)1Xe7Ye487/84/8XY
7/84/8
X7/8+7/81+6/811X6/8Y4/8+4/81Y
X6/8+7/81XY0+4/81Y
3-18
3
OE3-18OEXeYeVXYVxVy

Vy
Y
X
V
Vx
E(Xe,Ye)
O
3


Xe=1001016k=1/26kXe=0.1001016XekXe
3
XJVX

XJRX
YJVY

YJRY
3
3-3 OE3-20O(00)E4337J≥8O000000E100011J≥1000DDA
3-3
2.
3-22OAXaYaBXbYbPXY VVxVy
XY
XJVX

XJRX
YJVY

YJRY
Δt
Δx
Δy
3
3-4 AB3-24A05B50n=3A000101B101000DDA
3-4
A(0,5)
4
2
3
5
4
Y
O
1
2
3
X
B(5,0)
5
1
3-24
3
4.
fgHzEXeYeXYfxfy
(3-22)
Vg—
3
3-27
3
5.
(1)   
“”
XY1
i2i

3
FRNfgfgV/LV/RLR




DDAJRXJRY2n/2“1”100…000“”
3
3-5 AB3-27A05B05n=3 “”DDA
3-5
3
5
5
CNC8ms
3

(3-28)
(3-29)
(3-30)
3-30
δ—
HM
CD
(3-33)sinαcos α sin450cos450
tgα′ tgαtgα α=0 3-31α α ′ΔXΔX ′.
ΔY ′
(3-35) ΔY’
Δ X→ Δ X ‘, ΔY → ΔY’, AB →ASl → l’ 1
3
3-32
Δ
X
Δ
X
(3-36)
3



3
3-34 DDA
BXBFYFAiEGAi+1Ai+1NXAiEN3-33OFBAiNAi+1
(3-41)


(3-42)




3-43
Ai(XiYi)3-423-43ΔXΔY,xi+1,yi+1:
3
3.3.1

A
B
r


3
3.3.2
1.  
PPxpzpQxqzq
(3-45)






A
D
D
A
B
B
C
C
x
x
3
1.  B
(3-46)
(3-47)
3-41
K
Δ
X
y
α
A
(3-48)
A′B′ BB′
x
B
3-43 B
B1B2B1B2B1B2
3. C
3-44 C
3
3-453-46G41α00<< 3600
α
r
B
C
r
A
r
r
b)
α
A
a)
r
r
α
C
A
r
r
B
c)
B
C
B1
M
D
E
F
G
H
F
H
G
D
E
F
D
E
G
H
αC
3
3.4  
3.4.1


3
3.4.2
1.
1
3
n=tj/ty19
3-47
0







F

F’
X,Y
ΔX
ΔY
ΔX’
ΔY’







N
Y
Y
N

N
Y
Y
N
Si
S
Si
3
2
(a)
3
APAX
PBAY
y
A
C
D
O
α
B
KL, Vi=Vi-1+KL
Vc ---- ;
Vi-1 -----;
Vi=Vc, ,
Vi=Vi-1, Vi=Vc
Vi=Vc, ,
KL,
Vi=Vi-1-KL

E
1/T
Δt
y
x
2
E(4,3)
O
1
3
4
1
2
3
¸ø
å
ò
×ø±ê¼ÆËã
FK
FK
1
B
C
x