3.1 osmosis

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1 MARKING SCHEME 1 Question1 1 (a)(i) (ii) KB0603 – Measuring Using Numbers Score Explanation 3 Able to record 1 reading for the initial mass and all 4 readings for the final mass of potato strips correctly . Sample Answer: Initial mass : 50 gm Type of solution Final mass of potato strip after 30 minutes ( gm) 0.2M 58 0.4M 52 0.6M 46 0.8M 42 2 Able to record 1 reading for the initial mass and all 3 readings for the final mass of potato strips correctly . 1 Able to record any 1 reading for the initial mass and all 2 readings for the final mass of potato strips correctly . 0 No response or 1 reading for the initial mass and 1 reading for the final mass . 1 (b) (i) [KB0601 - Observation] Score Explanation 3 Able to state two correct observations based on the following criteria : [Observation must have values for MV and RV from Table 1 or comparison between two readings.]

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Page 1: 3.1 Osmosis

1

MARKING SCHEME 1

Question1

1 (a)(i) (ii) KB0603 – Measuring Using Numbers

Score Explanation

3

Able to record 1 reading for the initial mass and all 4 readings for thefinal mass of potato strips correctly .

Sample Answer:Initial mass : 50 gm

Type ofsolution

Final mass of potato strip after 30minutes

( gm)

0.2M 580.4M 520.6M 460.8M 42

2Able to record 1 reading for the initial mass and all 3 readings for thefinal mass of potato strips correctly .

1Able to record any 1 reading for the initial mass and all 2 readings forthe final mass of potato strips correctly .

0

No response or 1 reading for the initial mass and 1 reading for the finalmass .

1 (b) (i) [KB0601 - Observation]

Score Explanation

3

Able to state two correct observations based on the following criteria :[Observation must have values for MV and RV from Table 1 orcomparison between two readings.]

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2

MV : Concentration of sucrose solutionRV : The final mass of potato strip

Sample answer:1. In 0.2M sucrose solution, the final mass of potato strip is 58 gm.2. The final mass of potato strip immersed in 0.8M sucrose solution is

42 gm.3. The final mass of potato strip immersed in 0.8M sucrose solution is

less than the final mass of potato strip immersed in 0.2M sucrosesolution // inversely

2

Able to state two different observations inaccurately OR without values.

Sample Answer:1. At concentration 0.8 M, the final mass is the lowest // inversely.2. The highest concentration of sucrose solution, the final mass is 58

gm // inversely.3. The concentration of sucrose solution influences the final mass of

potato strip .

1

Able to state two different observations at idea level.

Sample Answer:1. The concentration changes / increases / decreases.2. The final mass of potato strip changes /increases /decreases.

0No response or wrong response.

ScoringScore Correct Inaccurate Idea Wrong

3 2 - - -2 1 1 - -

- 2 - -

11 - 1 -- - 2 -- 1 1 -

0 - 1 - 1- - 1 1

Page 3: 3.1 Osmosis

3

1 (b) (ii) [KB0604 – Making inference]

Score Explanation

3

Able to state two inferences for each observation made correctly andaccurately for each observation and equivalent in 1(b)(i).

Sample answers:1. (At concentration of 0.2M), water molecule diffuse into the cell.2. (At concentration of 0.8M), water molecule diffuse out of the cell.3. More water molecule diffuse out of the cell at 0.8M but more water

diffuse into the cell at 0.2M.

2

Able to state any two inferences inaccurately .

Sample answers:1. More water molecule diffuse .2. The diffusion of water is influenced by concentration

1

Able to state two inferences at idea level.

Sample Answer:1. Osmosis occurs.

0 No response OR wrong response.

Scoring:Score Correct Inaccurate Idea Wrong

3 2 - - -2 1 1 - -

- 2 - -

11 - 1 -- - 2 -- 1 1 -

0 - 1 - 1- - 1 1

Page 4: 3.1 Osmosis

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1 (c) [KB0610 – Controlling Variables]

Score Explanation

3

Able to state all 3 variables and the methods to handle the variablecorrectly.Sample Answer :

Variables Method to handle the variable correctlyManipulated variable:Concentration of sucrosesolution

Use 0.2M,0.4M,0.6M and 0.8M / differentconcentration of sucrose solution

Responding variable :Final mass of potato strip //percentage change in massof potato strip

Using a triple beam balance measureand record the final mass of potato strip// Calculate the percentage change inmass of potato using formula:Final mass-Initial mass X 100%

Initial mass

Constant variable:1. Duration of immersion /

2. Length / mass of thepotato strip / Volume ofsucrose solution

1. Fix the time of 30 minutes toimmersedthe potato strip.

2. Used the length of 5mm / Fix themass at50 gm.

3. Fix / used the volume at 20ml

Reject way how to handle the variable if variable is wrong

2Able to state 4-5 correctly.

1Able to state 2-3 correctly

0No response or only one criteria correct.

Page 5: 3.1 Osmosis

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1 (d) [KB0611 – Making Hypothesis]

Score Explanation

3

Able to state a hypothesis by relating the manipulated variable andresponding variable correctly with following aspects:

P1 : Stating manipulated variable.P2: Stating responding variableH : Showing a specific relationship/ showing direction of relationship

Sample Answer :1. As the concentration of sucrose solution increases, the final mass

of potato strip decreases // the percentage change in massdecreases.

2. As the concentration of sucrose solution increases / decreases,the final mass of potato strip increases /decreases // thepercentage change in mass increases // decreases

2

Able to state a hypothesis relating the manipulated variable inaccurately.

Sample Answer:1. The increase of the concentration of sucrose solution influences /

affects the final mass of potato strip.2. The percentage change in mass of potato strip is affected by

concentration of sucrose solution.

1

Able to state a hypothesis relating the manipulated variable at idea level.

Sample Answer :1. Final mass of potato strip / concentration of sucrose solution

changes.2. As the final mass of potato strip increases the percentage change

increases.

0No response or wrong response if no P1 or P2 no mark for each.

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1 (e) (i) [KB0606 – Communication]

Score Explanation

3

Able to construct a table correctly with the following aspects:

1 : Able to state the 4 titles with units correctly.2 : Able to record all the data correctly.3 : Able to calculate and record percentage change correctly

Sample answer :Concentration ofsucrose solution

(M)

Initialmass(gm)

Finalmass(gm)

Percentage change inmassFinal mass-Initial mass X100

Initial mass(%)

0.2 50 58 16.00.4 50 52 4.00.6 50 46 -8.00.8 50 42 -16.0

2Any two aspects correct

1Any one aspect correct

0No response or wrong response.

1 (e)(ii) [KB0612 – Relationship between space and time]

Score Explanation

3

Able to draw the graph correctly with the following aspects:

P(paksi) : Corrected title with unit on both horizontal, vertical axis anduniform scale on the axis.

T(titik) : All points plotted / transferred correctly.B(bentuk) : Able to join the points to form a smooth graph / line

2Able to state any two correct.

1Able to state any one correct

0 No response or wrong response.

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1 (f) [KB0608 – Interpreting Data]

Score Explanation

3

Able to interpret data correctly and explain with the following aspects :

Relationship :

P1 = Able to state the concentration of sucrose solution which is isotonicto the cell sap

ExplanationP2 = K Linmacam tak lengkap aje………………………………..P3 = Able to stateSample answer :

Produced (P3).

2Able to interpret data with two aspects correctly.

1Able to interpret data only one aspect correctly.

0No response or wrong response.

1 (g) [KB0609 –Defining by Operation ]

Score Explanation

3

Able to define operationally based on the result of the experiment with thefollowing aspects:

P1 : Movement of water in / outP2 : Plasma membrane of the potato cellsP3 : Difference in concentration gradient between the sucrose solution

and the cell sap.

Sample answer:

1. Osmosis is a process in which water molecules entering / leaving thepotato strips (P1) across the plasma membrane of the potato strip (P2)when there is a difference in concentration gradient between thesucrose solution and the cell sap (P3).

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2Able to define operationally based on the result of the experiment with twoaspects correctly.

1Able to define operationally based on the result of the experiment withonly one aspects correctly.

0 No response or wrong response

1 (h) [KB0605 – Predicting]

Score Explanation

3

Able to predict and explain the outcome of the experiment correctly withthe following aspects:

Prediction :P1 : Able to predict the mass of the potato strip correctly.

Explanation :P2 : Able to state distilled water is hypotonicP3 : Able to state more water molecules diffuse into the potato strip

Sample answer:1. The mass of the potato strip increases more than 46 gm // any

values more than 46 gm .Water molecules diffused into the potatostrip because distilled water is hypotonic.

** P1 must be correct to get P2 & P3, if P1 wrong automaticallyreject P2 & P3 - for score 3, 2, 1

2Able to predict and explain the outcome of the experiment correctly withthe two aspects.

1Able to predict and explain the outcome of the experiment correctly withone aspect correctly.

0No response or wrong response.

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1(i) [KB0602 – Classifying]

3

Able to classify all 3 solutions concentration and types of solutioncorrectly:

Solutionconcentrations

Kepekatan larutan(%)

Types of solution compared tothe osmotic concentration of cellsapJenis larutan dibandingkandengan kepekatan osmotik sapsel

0.25% natrium chloridesolution Hypotonic

0.8% natrium chloride

solutionIsotonic

1.10% natrium chloride

solution.Hypertonic

2Able to classify 2 solutions concentration and types of solution correctly

1Able to classify 1 solution concentration and types of solution correctly

0No response or wrong response