4/2 do now [explain your answer] the wavelength of a wave doubles as it travels from medium a into...

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4/2 do now • [explain your answer] The wavelength of a wave doubles as it travels from medium A into medium B. Compared to the wave in medium A, the wave in medium B has a.half the speed b.twice the speed c.half the frequency d.twice the frequency

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4/2 do now• [explain your answer] The wavelength of a

wave doubles as it travels from medium A into medium B. Compared to the wave in medium A, the wave in medium B has

a. half the speedb. twice the speedc. half the frequencyd. twice the frequency

13-1 sound waves1. Explain how sound waves are produced.2. Relate frequency to pitch.3. Compare the speed of sound in various media.4. Recognize the Doppler effect, and determine the

direction of a frequency shift when there is relative motion between a source and an observer.

HomeworkCastle learningReading 13.2

Quarter ends Friday, No post Friday

The production of sound waves• Sound waves, like all waves, are produced by VIBRATING

objects, such as tuning fork, vocal cord, string on guitar, etc.• Sound is a MECHANICAL wave that propagates through a

MEDIUM from one location to another. • Sound is a LONGITUDINAL wave. The vibrations of medium is

PARALLEL to the direction of wave motion.

• The frequency of a sound wave, like all waves, is the same as its originator.

• Sound cannot travel through vacuum

• High pressure regions are known as compressions and low pressure regions rarefactions.

• The wavelength is commonly measured as the distance from one compression to the next adjacent compression.

• Since a sound wave consists of a repeating pattern of high pressure and low pressure regions moving through a medium, it is sometimes referred to as a pressure wave.

Exmaple #1

1. A sound wave is different than a light wave in that a sound wave is

a. produced by an oscillating object and a light wave is not.

b. not capable of traveling through a vacuum.c. not capable of diffracting and a light wave is.d. capable of existing with a variety of frequencies and

a light wave has a single frequency.

Example #2• A sound wave is a pressure wave; regions of high

(compressions) and low pressure (rarefactions) are established as the result of the vibrations of the sound source. These compressions and rarefactions result because sound

1. is more dense than air and thus has more inertia, causing the bunching up of sound.

2. waves have a speed which is dependent only upon the properties of the medium.

3. is like all waves; it is able to bend into the regions of space behind obstacles.

4. is able to reflect off fixed ends and interfere with incident waves

5. vibrates longitudinally; the longitudinal movement of air produces pressure fluctuations.

Example #3

• As a sound wave travels through air, there is a net transfer of

1. energy, only2. mass, only3. both mass and energy4. neither mass nor energy

Characteristics of sound waves• Frequency determines the pitch.

– The ears of a human (and other animals) are sensitive detectors of the fluctuations in air pressure which impinge upon the eardrum.

The sensation of a frequency of sound is commonly referred to as the pitch. A high pitch sound corresponds to a high frequency sound wave and a low pitch sound corresponds to a low frequency sound wave.

• Infrasound and ultrasound– The human ear is capable of detecting sound waves

with a wide range of frequencies, ranging between approximately 20 Hz to 20 000 Hz. Any sound with a frequency below the audible range of hearing (i.e., less than 20 Hz) is known as an infrasound and any sound with a frequency above the audible range of hearing (i.e., more than 20 000 Hz) is known as an ultrasound.

– Ultrasound waves can produce images.

• Speed of sound depends on the medium– Sound is a mechanical wave, it depends on the

medium interaction to travel. The speed of sound waves depends on how fast the particles can interact with each other. In general, sound wave travels faster in denser materials.

vsolids > vliquids > vgases

• Sound in air– The speed of a sound wave in air depends upon the properties

of the air, namely the temperature and the pressure. – The speed of sound wave at STP is 331 m/s– At normal atmospheric pressure, the temperature dependence of

the speed of a sound wave through air is approximated by the following equation:

v = 331 m/s + (0.6 m/s/oC)•T• where T is the temperature of the air in degrees Celsius.

– Using this equation, we can determine the speed of a sound wave in air at a temperature of 20 degrees Celsius:

v = 331 m/s + (0.6 m/s/oC)•(20oC)v = 331 m/s + 12 m/sv = 343 m/s

• Using Wave Speed to Determine Distances– At normal atmospheric pressure and a temperature of 20oC, a

sound wave will travel at approximately 343 m/s; – The speed of a sound wave is slow in comparison to the

speed of a light wave. Light travels through air at a speed of approximately 3 x 108 m/s;

– The time delay between the arrival of the light wave (lightning) and the arrival of the sound wave (thunder) allows a person to approximate his/her distance from the storm location.

– For instance if the thunder is heard 5 seconds after the lightning is seen, then sound has traveled a distance of d = v • t = 345 m/s • 5 s = 1715 m, which means the storm is about one mile away.

Every 5 seconds is about a mile.

• Another phenomenon related to the perception of time delays between two events is an echo.

• For instance if an echo is heard 1.40 seconds after making the holler, then the distance to the canyon wall can be found as follows:

distance = v • t = 345 m/s • 0.70 s = 242 m

• Echolocation is a physiological process for locating distant or invisible objects (as prey) by sound waves reflected back to the emitter (as a bat) from the objects

• Sound wave propagate in three dimensions

The Wave Equation Revisited• Like any wave, a sound wave has a speed which is

mathematically related to the frequency and the wavelength of the wave.

• Speed = Wavelength • Frequency v = f • λ• Even though wave speed is calculated using the frequency and

the wavelength, the wave speed is not dependent upon these quantities. – An alteration in wavelength does not affect (i.e., change)

wave speed. Rather, an alteration in wavelength affects the frequency in an inverse manner.

– A doubling of the wavelength results in a halving of the frequency; yet the wave speed is not changed.

– The speed of a sound wave depends on the properties of the medium through which it moves and the only way to change the speed is to change the properties of the medium.

Class work – today’s date1. What occurs when sound passes from air into

water? a. Its speed decreases, its wavelength becomes

smaller, and its frequency remains the same.b. Its speed decreases, its wavelength becomes

smaller, and its frequency increases.c. Its speed increases, its wavelength becomes larger,

and its frequency remains the same.d. Its speed increases, its wavelength becomes larger,

and its frequency decreases.

2. A sound wave is produced by a musical instrument for 0.50 second. If the frequency of the wave is 360 hertz, how many complete waves are produced in that time period?

3. An automatic focus camera is able to focus on objects by use of an ultrasonic sound wave. The camera sends out sound waves that reflect off distant objects and return to the camera. A sensor detects the time it takes for the waves to return and then determines the distance an object is from the camera. If a sound wave (speed = 340 m/s) returns to the camera 0.150 seconds after leaving the camera, how far away is the object?

4. On a hot summer day, a pesky little mosquito produced its warning sound near your ear. The sound is produced by the beating of its wings at a rate of about 600 wing beats per second.a. What is the frequency in Hertz of the sound wave? b. Assuming the sound wave moves with a velocity of 350 m/s, what is

the wavelength of the wave?

5. True or False: Doubling the frequency of a wave source doubles the speed of the waves.

6. Playing middle C on the piano keyboard produces a sound with a frequency of 256 Hz. Assuming the speed of sound in air is 345 m/s, determine the wavelength of the sound corresponding to the note of middle C.

7. Most people can detect frequencies as high as 20 000 Hz. Assuming the speed of sound in air is 345 m/s, determine the wavelength of the sound corresponding to this upper range of audible hearing.

8. An elephant produces a 10 Hz sound wave. Assuming the speed of sound in air is 345 m/s, determine the wavelength of this infrasonic sound wave.

9. The diagram shows a tuning fork vibrating in air. The dots represent air molecules as the sound wave moves towards the right. Which diagram below best represents the direction of motion of the air molecules?

A B C D

10. An electric bell connected to a battery is sealed inside a large jar. What happens as the air is removed from the jar?

a. The electric circuit stops working because electromagnetic radiation cannot travel through a vacuum.

b. The bell's pitch decreases because the frequency of the sound waves is lower in a vacuum than in air.

c. The bell's loudness increases because of decreased air resistance.

d. The bell's loudness decreases because sound waves cannot travel through a vacuum.

11. A student plucks a guitar string and the vibrations produce a sound wave with a frequency of 650 hertz. The sound wave produced can best be described as a

a. transverse wave of constant amplitudeb. longitudinal wave of constant frequencyc. mechanical wave of varying frequencyd. electromagnetic wave of varying

wavelengths

Doppler Effect

Stationary source

Wave fronts: A wave front is the curve of all adjacent points on a wave that are in phase.

To observer A and observer B, the frequency is the same everywhere.

Moving source

Higher frequency, short λLower frequency, longer λ

The Doppler effect can be described as the effect produced by a moving source of waves, the observer, or both –

an apparent upward shift in frequency if the observers and the source is approaching each otheran apparent downward shift in frequency if the observers and the source is moving away from each other.

Relative motion creates an apparent change in frequency.

Explaining the Doppler Effect• The Doppler effect is observed because the distance between the

source of sound and the observer is changing. • If the source and the observer are approaching each other, then

the distance is decreasing and the waves is compressed into the smaller distance. The observer perceives sound waves reaching him or her at a more frequent rate (_______ pitch).

• If the source and the observer are moving apart, then the distance is increasing. the waves can be spread apart; the observer perceives sound waves reaching him or her at a less frequent rate (____pitch).

high

low

• It is important to note that both the speed and the frequency of the source does not change.

• The Doppler effect can be observed for any type of wave - water wave, sound wave, light wave, etc.

• car horn - coming and going• As the car approached with its siren blasting, the pitch of the siren

sound (a measure of the siren's frequency) was high; and then suddenly after the car passed by, the pitch of the siren sound was low. That was the Doppler effect - an apparent shift in frequency for a sound wave produced by a moving source.

Shock Waves and Sonic Booms• If a moving source of sound moves at the same speed as

sound or faster than sound, then shock waves will be produced.

• http://edweb.sdsu.edu/doppler/elab/elab1.htm

..\..\RealPlayer Downloads\Plane break sound barrier - sonic boom.flv

Blue shift and red shiftThe human eye perceives light waves of different frequencies as differences in color. The lowest frequency we can see is red and the highest frequency we can see is blue-violet.Due to Doppler effect, the apparent color of an approaching light source is shifted toward the blue end of the spectrum, while that of a receding source is shifted toward the red end.

Applications of the Doppler Effect• Police work – the speed of a car is determined by a radar system.

– when a car is at rest, the sent out frequency is the same as received frequency.

– If the car is moving toward the source of radar, the reflected waves have higher frequency, the greater the car’s speed, the greater the Doppler shift in frequency.

– If the car is moving away from the source of radar, the reflected waves have lower frequency.

• Weather stations – Doppler radars are used to determine the location and intensity of precipitation as well as directions and speed of the winds blowing around rain drops.

Class work – today’s date

1. A police officer's stationary radar device indicates that the frequency of the radar wave reflected from an automobile is less than the frequency emitted by the radar device. This indicates that the automobile is

a. moving toward the police officer b. moving away from the police officer c. not moving

example

2. The diagram shows radar waves being emitted from a stationary police car and reflected by a moving car back to the police car. The difference in apparent frequency between the incident and reflected rays is an example of

a. constructive interference b. refraction c. the Doppler effect d. total internal reflection

3. As observed from the Earth, the light from a star is shifted toward lower frequencies. This is an indication that the distance between the Earth and the star is

a. decreasing b. increasing c. Constant

4. Suppose you are standing on the passenger-loading platform of the commuter railway line. As the commuter train approaches the station, what pitch or changes in pitch will you perceive as the train approaches you on the loading platform?

5. A stationary research ship uses sonar to send a 1.18 × 103-hertz sound wave down through the ocean water. The reflected sound wave from the flat ocean bottom 324 meters below the ship is detected 0.425 second after it was sent from the ship. Calculate the wavelength of the sound wave in the ocean water.

6. What is the frequency of a sound wave with a wavelength of 0.04 meter in air? What type of wave is this, transverse or longitudinal?

7. A bat is using sound waves to locate an insect. The bat produces sounds with a frequency of 120 kilo-hertz and notes that the sound it transmits echo’s back in 0.02 second.

a. What is the bat’s distance to its prey? b. What is the wavelength of the bat’s radar?

8. A radar station is tracking a dense section of cloud cover. If the radar station transmits energy at a frequency of 300 megahertz and receives reflected energy from the clouds at a frequency of 150 megahertz, what can the forecasters say about the motion of the clouds?

9. If a ship sends a sonar signal through the water to the sea floor and it bounces back to arrive back at the ship in 2.0 seconds, how deep is the water under the ship if sound travels through water at 1500 meters per second?

10. If it takes a sound wave 2.5 seconds to travel from the spot where a lightning strike occurs to an observer, how far away from the observer did the strike occur?

11. Why would an astronaut not be able to communicate with another astronaut by talking in the vacuum of space?

12. Circle the terms that properly complete the sentences below.

a. Sound is transmitted as a TRANSVERSE / LONGITUDINAL wave. b. Sound is produced as a(n) MECHANICAL / ELECTROMAGNETIC wave. c. Sound travels more QUICKLY / SLOWLY in water than it does in air. Explain

why this is true!

13. The diagram below shows a source of sound waves moving with a constant speed near an observer. The source produces sound waves with a frequency of 100 hertz.

1) Is the source getting closer to the observer or farther away?

2) Which frequencies could the observer be hearing as the source approaches? (a) 80 Hz (b) 100 Hz (c) 110 Hz (d) 120 Hz

3) As the source approaches, will the frequency heard by the observer be constant, increasing, or decreasing?

14. A train is moving at a constant 35 meters per second away from an observer. As the train is moving it blasts its horn which produces a sound with a frequency of 1000 hertz. The observer will perceive that the horn’s frequency is

(1) less than 1000 hertz and constant (2) less than 1000 hertz and decreasing (3) greater than 1000 hertz and constant (4) greater than 1000 hertz and increasing

15. A police car is accelerating toward an observer. The police car’s siren produces a sound with a frequency of 1200 hertz. The observer will perceive that the siren’s frequency is

(1) less than 1200 hertz and constant (2) less than 1200 hertz and decreasing (3) greater than 1200 hertz and constant (4) greater than 1200 hertz and increasing

Lab – determine the speed of sound

Purpose (5 pt): To determine the speed of soundMaterial (5 pt): computer, Vernier computer interface, Logger Pro, microphone,

tube, thermometer, meter stickProcedure (10 pt):

– Briefly describe how the lab is going to be done. Someone who was not present during the lab should be able to understand how the experiment was perforem and be able to reporduce the results by reading your procedure.

Data section (20 pt): – The Data Section should include two tables of data with labeled column

headings (and units) to demonstrate a systematic study of the effect of amplitude and length upon the period of the pendulum.

Data analysis / conclusion (20 pt):– Calculate the speed of sound. Remember that your time interval

represents the time for sound to travel down the tube and back.– The accepted speed of sound at atmospheric pressure and 0oC is 331.5

m/s. The speed of sound increaseds 0.607 m/s for every oC. Calculate the speed of sound at the temperature of your room and compare your measured value to the accepted value.

PROCEDURE1. Connect the Vernier Microphone to Channel 1 of the interface.2. Use a thermometer or temperature probe to measure the air temperature of the classroom

and record the value in the data table.3. Open the file “Speed of Sound” in the Physics with Vernier folder. A graph of sound level vs.

time will be displayed.4. Close the end of the tube. Measure and record the length of the tube in your data table.5. Place the Microphone as close to the end of the long tube as possible, so that it can detect

the initial sound and the echo coming back down the tube.6. Click to begin data collection. Snap your fingers near the opening of the tube. 7. If you are successful, the graph will resemble the one below. Repeat your run if necessary.

The second set of vibrations with appreciable amplitude marks the echo. Click the Examine button, . Move the mouse and determine the time interval between the start of the first vibration and the start of the echo vibration. Record this time interval in the data table.

8. Repeat the measurement for a total of five trials and determine the average time interval.

DATA TABLES

Length of tube m

Temperature of room °C

Trial Total travel time (s)1

2

3

4

5

Average

Average speed =