6 xml parsing
DESCRIPTION
XML ParsingTRANSCRIPT
XML Parsing | Atul Kahate 2
Agenda XML Parsing/Processing Basics
Simple API for XML (SAX) Document Object Model (DOM)
XML and Java using JAXP XML and ASP.NET
XML Parsing/Processing
XML Parsing | Atul Kahate 4
XML Processing XML processing means
Reading an XML document Parsing it in the desired manner
Allows handling the contents of an XML document the way we want
XML Parsing | Atul Kahate 5
XML Parser Software that sits between an
application and the XML files Shield programmers from having to
manually parse through XML documents
Programmers are free to concentrate on the contents of the XML file, not syntax
Programmers use the parser APIs to access/manipulate an XML file
XML Parsing | Atul Kahate 6
XML Processing Approaches Process as a sequence of events
Simple API for XML Processing (SAX)
Process as a hierarchy of nodes Document Object Model (DOM)
Pull approach Streaming API (StAX)
XML Parsing | Atul Kahate 7
SAX Versus DOM
XML Parsing | Atul Kahate 8
StAX Pulls events from the XML
document via the parser Also an event-based API, but
differs from SAX The application, and not the parser;
controls the flow
Simple API for XML (SAX)
XML Parsing | Atul Kahate 10
XML Processing as Sequence of Events – 1 Process as a sequence of events
Event is the occurrence of something noticeable
e.g. in Windows, mouse movement, keyboard input are events
The OS captures all events and sends messages to a program
The programmer has to take an appropriate action to deal with the event
XML Parsing | Atul Kahate 11
XML Processing as Sequence of Events – 2 Process as a sequence of events
Event-based model can be applied to XML documents also
Various events that occur while reading an XML document sequentially
Start of document Start tag of an element End tag of an element Comments
XML Parsing | Atul Kahate 12
XML Processing as Sequence of Events – 3 Process as a sequence of events
The programmer has to write code to handle these events
Called as event handlers
XML Parsing | Atul Kahate 13
Sequential Processing Example – 1 Consider the following XML document<?xml version=“1.0”?><books>
<book><name> Learning XML </name><author> Simon North </author><publication> TMH </publication>
</book><book>
<name> XML by Example </name><author> Don Box </author><publication> Pearson </publication>
</book></books>
XML Parsing | Atul Kahate 14
Sequential Processing Example – 2 Events generated when we read the
above XML fileStart documentStart element: booksStart element: bookStart element: nameCharacters: Learning XML End element: nameStart element: authorCharacters: Simon North End element: authorStart element: publication Characters: TMH End element: publication…End element: bookEnd document
XML Parsing | Atul Kahate 15
Sample XML Tree
XML Parsing | Atul Kahate 16
Tree Processing Sequence1
2 8
3 4 9 10 14 15
5 6 7 11 12 13 16 17
XML Parsing | Atul Kahate 17
Sequential Traversal: Summary Order
Top to bottom Left to right
Advantages Simple Fast Requires less amount of memory
Drawback Not possible to look ahead
XML Parsing | Atul Kahate 18
SAX Concept
JAXP
Java API for XML Processing
XML Parsing | Atul Kahate 20
JAXP Concept
Application program written in Java for working with XML
Java API for XML Processing (JAXP)
JAXP APIs
Simple API for XML Processing (SAX)
Document Object Model (DOM)
Sequential processing Tree-based processing
XML Parsing | Atul Kahate 21
JAXP Java API for XML Processing Standardized by Sun Very thin layer on top of SAX or DOM Makes application code parser-
independent Our programs should use JAXP,
which in turn, calls parser APIs Include package javax.xml.parsers.*
XML Parsing | Atul Kahate 22
JAXP: API or Abstraction? JAXP is an API, but is called as an
abstraction layer Does not provide new means of parsing
XML Does not add to SAX or DOM Does not give new functionality to Java
or XML handling Makes working with SAX and DOM easier It is vendor-neutral
XML Parsing | Atul Kahate 23
JAXP and Parsing JAXP is not a replacement for SAX, DOM, JDOM
etc Some vendor must supply the implementation of
SAX, DOM, etc JAXP provides APIs to use these implementations
In the early versions of JDK, Sun had supplied a parser called Crimson
Now, Sun provides Apache Xerces Both are not a part of JAXP API – they are part of JAXP
distribution In JDK, we can locate Xerces implementations in
the org.xml.sax and org.w3c.dom packages
XML Parsing | Atul Kahate 24
JAXP API The main JAXP APIs are defined in the
package javax.xml.parsers Contains two vendor-neutral factory
classes SAXParserFactory – Gives a SAXParser
object DocumentBuilderFactory – Gives a
DocumentBuilder object DocumentBuilder, in turn, gives Document object
XML Parsing | Atul Kahate 25
Package Details javax.xml.parsers
The JAXP APIs, which provide a common interface for different vendors' SAX and DOM parsers.
org.w3c.dom Defines the Document class (a DOM), as well as
classes for all of the components of a DOM. org.xml.sax
Defines the basic SAX APIs. javax.xml.transform
Defines the XSLT APIs that let you transform XML into other forms.
XML Parsing | Atul Kahate 26
Which Packages to use in JAXP? We need to include two sets of packages – one
for JAXP and the other for SAX/DOM, as appropriate
// JAXP import javax.xml.parsers.SAXParserFactory;
// SAX import org.xml.sax.Attributes; import org.xml.sax.SAXException; import org.xml.sax.SAXNotRecognizedException; import org.xml.sax.SAXNotSupportedException; import org.xml.sax.SAXParseException; import org.xml.sax.XMLReader; import org.xml.sax.helpers.DefaultHandler; import org.xml.sax.helpers.XMLReaderFactory;
SAX Programming in JAXP
XML Parsing | Atul Kahate 28
SAX Approach
XML Parsing | Atul Kahate 29
Key SAX APIs – 1 SAXParserFactory
Creates an instance of the parser determined by the system property, javax.xml.parsers.SAXParserFactory.
SAXParser
An interface that defines several kinds of parse() methods. In general, you pass an XML data source and a DefaultHandler object to the parser, which processes the XML and invokes the appropriate methods in the handler object.
XML Parsing | Atul Kahate 30
Key SAX APIs – 2 SAXReader
The SAXParser wraps a SAXReader. Typically, you don't care about that, but every once in a while you need to get hold of it using SAXParser's getXMLReader(), so you can configure it. It is the SAXReader which carries on the conversation with the SAX event handlers you define.
DefaultHandler Not shown in the diagram, a DefaultHandler
implements the ContentHandler, ErrorHandler, DTDHandler, and EntityResolver interfaces (with null methods), so you can override only the ones you're interested in.
Design Patterns
Factory Pattern
XML Parsing | Atul Kahate 32
“new” means “Concrete”Vehicle vehicle = new Car ();
We want to use an interface (say Vehicle) to keep code flexible
However, we must create an instance of a concrete class (e.g. Car)
Makes the code more fragile and less flexible – Why? See next slide.
XML Parsing | Atul Kahate 33
Using “new” – 1
Vehicle vehicle;
if (picnic) vehicle = new Car ();else if (work) vehicle = new Bus ();else vehicle = new Scooter ();
XML Parsing | Atul Kahate 34
Using “new” – 2 We do not know until run time which
class to instantiate Whenever code needs to be changed,
we need to reopen this code and examine what needs to be added or removed
Mandates application changes at multiple places, making it difficult to maintain
XML Parsing | Atul Kahate 35
What is wrong with “new”? Nothing as such Problem is changes to code and their
impact on “new” By coding to an interface, we know that
we are insulated from changes made to a system
This is because different classes would implement the interface using polymorphism appropriately
XML Parsing | Atul Kahate 36
Key OO Principle Identify the aspects of code
that vary and separate them from what stays the same
Code should be open for extension, but closed for modifications
XML Parsing | Atul Kahate 37
Pizza Class – Ideal SituationPizza orderPizza () { Pizza pizza = new Pizza ();
Pizza.prepare (); Pizza.bake (); Pizza.cut (); Pizza.pack();
return pizza;}
Ideally, we would like this to be an abstract class or an interface, but we cannot directly instantiate an abstract class or an interface!
XML Parsing | Atul Kahate 38
Pizza Class – Ideal SituationPizza orderPizza () { Pizza pizza = new CheesePizza ();
Pizza.prepare (); Pizza.bake (); Pizza.cut (); Pizza.pack();
return pizza;}
We are left with no choice but to instantiate a concrete class
XML Parsing | Atul Kahate 39
SolutionPizza orderPizza (String type) { Pizza pizza;
if (type.equals (“cheese”)) { pizza = new CheesePizza (); } else if (type.equals (“corn”)) { pizza = new CornPizza (); } else { pizza = new GeneralPizza (); } Pizza.prepare (); Pizza.bake (); Pizza.cut (); Pizza.pack(); return pizza; }
1. We are passing the type of pizza to orderPizza () method.
2. Based on the type of pizza, we instantiate the correct concrete class. Each pizza has to implement the Pizza interface.
3. Each pizza sub-type (e.g. cheese) knows how to prepare itself.
XML Parsing | Atul Kahate 40
Is this correct? Let us review the principles:
Identify the aspects of code that vary and separate them from what stays the same
Code should be open for extension, but closed for modifications
XML Parsing | Atul Kahate 41
Problems What if we remove one pizza type,
and add another?
We need to touch the code
See next slide
XML Parsing | Atul Kahate 42
Problem – CodePizza orderPizza (String type) { Pizza pizza;
if (type.equals (“veg”)) { pizza = new VeggiePizza (); } else if (type.equals (“corn”)) { pizza = new CornPizza (); } else { pizza = new GeneralPizza (); } Pizza.prepare (); Pizza.bake (); Pizza.cut (); Pizza.pack(); return pizza; return pizza;}
1. Problem is that we end up touching code for modifications.
2. This is not what we want.
3. What is the solution?
XML Parsing | Atul Kahate 43
Code Modified FurtherPizza orderPizza (String type) { Pizza pizza;
if (type.equals (“cheese”)) {if (type.equals (“cheese”)) { pizza = new CheesePizza ();pizza = new CheesePizza (); }} else if (type.equals (“corn”)) {else if (type.equals (“corn”)) { pizza = new CornPizza ();pizza = new CornPizza (); }} else {else { pizza = new GeneralPizza ();pizza = new GeneralPizza (); }} Pizza.prepare (); Pizza.bake (); Pizza.cut (); Pizza.pack(); return pizza; return pizza;}
if (type.equals (“cheese”)) { pizza = new CheesePizza (); } else if (type.equals (“corn”)) { pizza = new CornPizza (); } else { pizza = new GeneralPizza (); }
Abstract out the code that varies, and put it into a separate class, that would only worry about how to create objects. If any other object needs a pizza object, this is the class to come to.
XML Parsing | Atul Kahate 44
This new Class is our “Factory”public class PizzaFactory { public Pizza createPizza (String type) { Pizza pizza = null; if (type.equals (“cheese”)) { pizza = new CheesePizza (); } else if (type.equals (“corn”)) { pizza = new CornPizza (); } else { pizza = new GeneralPizza (); } return pizza; }}
1. This new class creates new pizzas for its clients.
2. It has a createPizza () method, which all clients will use to instantiate new objects.
3. It contains code plucked out of the orderPizza () method.
XML Parsing | Atul Kahate 45
Modified Client Codepublic class PizzaStore { PizzaFactory factory = new PizzaFactory ();
public Pizza orderPizza (String type) { Pizza pizza = factory.createPizza (“Cheese”);
pizza.prepare (); pizza.bake (); pizza.cut (); pizza.pack ();
return pizza; }}
A variation of this is:
PizzaFactory factory = PizzaFactory.newInstance ();
In this case, newInstance () would be a static method in PizzaFactory, since we are not creating any object of PizzaFactory here
Another Factory Pattern Example
XML Parsing | Atul Kahate 47
Factory Pattern – The Need – 1 Consider this:Connection connection = new OracleConnection ();Connection connection = new SqlServerConnection
();Connection connection = new DB2Connection ();...
What are the problems? How to resolve them?
XML Parsing | Atul Kahate 48
Problems Summarized Sometimes, an Application (or framework) at runtime,
cannot anticipate the class of object that it must create. The Application (or framework) may know that it has to instantiate classes, but it may only know about abstract classes (or interfaces), which it cannot instantiate. Thus the Application class may only know when it has to instantiate a new Object of a class, not what kind of subclass to create.
A class may want it's subclasses to specify the objects to be created.
A class may delegate responsibility to one of several helper subclasses so that knowledge can be localized to specific helper subclasses.
XML Parsing | Atul Kahate 49
Factory Pattern – The Need – 2public Connection createConnection (String type) {
if (type.equals ("Oracle") { return new OracleConnection (); } else if (type.equals ("SQL Server") { return new SqlServerConnection (); } else if (type.equals ("DB2") { return new DB2Connection (); }}
Does it resolve all problems?
XML Parsing | Atul Kahate 50
More on Factory Pattern – 1 Factory Method is a creational pattern. This
pattern helps to model an interface for creating an object which at creation time can let its subclasses decide which class to instantiate. We call this a Factory Pattern since it is responsible for "Manufacturing" an Object. It helps instantiate the appropriate Subclass by creating the right Object from a group of related classes. The Factory Pattern promotes loose coupling by eliminating the need to bind application-specific classes into the code.
Factories have a simple function: Churn out objects.
XML Parsing | Atul Kahate 51
More on Factory Pattern – 2 Obviously, a factory is not needed to make an
object. A simple call to new will do it for you. However, the use of factories gives the programmer the opportunity to abstract the specific attributes of an Object into specific subclasses which create them.
The Factory Pattern is all about "Define an interface for creating an object, but let the subclasses decide which class to instantiate. The Factory method lets a class defer instantiation to subclasses"
XML Parsing | Atul Kahate 52
Factory Pattern – The Need – 3
We still need to add new code for a new connection type
The existing class needs to undergo changes every time
When object creation changes a lot, use a factory
XML Parsing | Atul Kahate 53
Factory Pattern – The Need – 4
Client code to use the factoryFirstFactory factory = FirstFactory.getInstance ();
Connection connection = factory.createConnection (“Oracle”);
XML Parsing | Atul Kahate 54
The Factory Class – 1public class FirstFactory { protected static String type;
public static FirstFactory getInstance () { type = null;
return new FirstFactory (); }
...}
XML Parsing | Atul Kahate 55
The Factory Class – 2public class FirstFactory {
protected static String type;
public static FirstFactory getInstance () { type = ""; return new FirstFactory (); }
public Connection createConnection (String t) {
type = t;
if (type.equals ("Oracle")) { return new OracleConnection (); } else if (type.equals ("SQL Server")) { return new SQLServerConnection (); } else { //if (type.equals ("DB2")) { return new DB2Connection (); } }
}
XML Parsing | Atul Kahate 56
Connection Classespublic interface Connection { public String description ();}
public class OracleConnection implements Connection { public OracleConnection () {
// Logic specific to Oracle }
public String description () { return "Oracle"; }}
public class SQLServerConnection implements Connection { public SQLServerConnection () {
// Logic specific to SQL Server }
public String description () { return "SQL Server"; }}
public class DB2Connection implements Connection { public DB2Connection () {
// Logic specific to DB2 }
public String description () { return "DB2"; }}
XML Parsing | Atul Kahate 57
Client Codepublic class TestConnection {
public static void main (String args []) {
FirstFactory factory = FirstFactory.getInstance ();
Connection connection = factory.createConnection ("DB2");
System.out.println ("You are connected with " + connection.description ());
}}
Factory Pattern - Exercise
XML Parsing | Atul Kahate 59
Exercise We want to be able to create any
of the following objects that have some similarities and some differences. Design using factory method design pattern. Employee Student Player
SAX
XML Parsing | Atul Kahate 61
Sequential Traversal: SAX SAX (Simple API for XML)1. Specify the parser to be used2. Create a parser instance3. Create an event handler to
respond to parsing events4. Invoke the parser with the
designated content handler and document
XML Parsing | Atul Kahate 62
1 – Specify the Parser Various approaches are possible
Set a system property for javax.xml.parsers.SAXParserfactory
Specify the parser in jre_dir/lib/jaxp.properties
Use system-dependent default parser (check documentation)
Usually done at the time of JDK installation itself automatically
XML Parsing | Atul Kahate 63
1 – Specify the Parser Example
Public static void main (String [] args){
String jaxpPropertyName = “javax.xml.parsers.SAXParserFactory”;…
}
XML Parsing | Atul Kahate 64
2 – Create a Parser Instance Steps
i. Create an instance of a parser factoryii. Use that to create a SAXParser object
Example
SAXParserFactory factory = SAXParserFactory.newInstance ();
SaxParser p = factory.newSAXParser ();
XML Parsing | Atul Kahate 65
3 – Create an Event Handler Event handler responds to
parsing events It is a subclass of DefaultHandler
public class MyHandler extends DefaultHandler { … }
Main event methods (callbacks) startDocument, endDocument startElement, endElement characters, ignoreableWhitespace
XML Parsing | Atul Kahate 66
3 – Create an Event Handler Example method: startElementDeclaration
public void startElement (String nameSpaceURI, String localName, String qualifiedName, Attributes attributes)
throws SASExceptionArgumentsnameSpaceURI URI identifying the namespace uniquelylocalName Element name without namespace prefixqualifiedName Complete element name, including
namespace prefixattributes Attributes object, representing attributes of the
element
XML Parsing | Atul Kahate 67
3 – Create an Event Handler
nameSpaceURI
<cwp:book xmlns:cwp=“http://www.test.com/xml/”>
qualifiedName attribute[1]
<cwp:chapter number=“23” part=“Server programming”>
<cwp:title> XML made easy </cwp:title></cwp:chapter>
localName
</cwp:book>
XML Parsing | Atul Kahate 68
4 – Invoke the Parser Call the parse method, supplying:
The content handler The XML document
File or Input stream
p.parse (file name, handler);
XML Parsing | Atul Kahate 69
Sample XML File (emp.xml) <?xml version="1.0" encoding="UTF-8"?>
<root> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> </root>
XML Parsing | Atul Kahate 70
Java Program to Count Total Number of Elements import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.*; import org.xml.sax.helpers.DefaultHandler;
public class SAXEmployeeCount extends DefaultHandler { int tagCount = 0;
public void startElement (String uri, String localName, String rawName, Attributes attributes) { tagCount++;
}
public void endDocument() { System.out.println("There are " + tagCount + " elements."); }
public static void main(String[] args) { SAXEmployeeCount handler = new SAXEmployeeCount ();
try { SAXParserFactory spf = SAXParserFactory.newInstance (); SAXParser parser = spf.newSAXParser ();
parser.parse("employee.xml", handler); } catch (Exception ex) { System.out.println(ex); } } }
XML Parsing | Atul Kahate 71
Count Only Book Elements<?xml version="1.0"?><books> <book category="reference"> <author>Nigel Rees</author> <title>Sayings of the Century</title> <price>8.95</price> </book> <book category="fiction"> <author>Evelyn Waugh</author> <title>Sword of Honour</title> <price>12.99</price> </book> <book category="fiction"> <author>Herman Melville</author> <title>Moby Rick</title> <price>8.99</price> </book></books>
XML Parsing | Atul Kahate 72
Parsing Code in JAXP import java.io.IOException; import java.lang.*; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.Attributes; import org.xml.sax.Locator; import org.xml.sax.SAXException; import org.xml.sax.SAXNotRecognizedException; import org.xml.sax.SAXNotSupportedException; import org.xml.sax.SAXParseException; import org.xml.sax.XMLReader; import org.xml.sax.ext.LexicalHandler; import org.xml.sax.helpers.DefaultHandler; import org.xml.sax.helpers.ParserAdapter; import org.xml.sax.helpers.XMLReaderFactory;
public class BookCount extends DefaultHandler{
private int count = 0;
public void startDocument() throws SAXException { System.out.println("Start document ..."); }
public void startElement(String uri, String local, String raw, Attributes attrs) throws SAXException {
int year = 0; String attrValue;
System.out.println ("Current element = " + raw);
if (raw.equals ("book")) { count++; } }
public void endDocument() throws SAXException { System.out.println("The total number of books = " + count); }
public static void main (String[] args) throws Exception { BookCount handler = new BookCount ();
try { SAXParserFactory spf = SAXParserFactory.newInstance (); SAXParser parser = spf.newSAXParser (); parser.parse ("book.xml", handler); } catch (SAXException e) { System.err.println(e.getMessage()); } } }
XML Parsing | Atul Kahate 73
Specifying Parser Name import java.io.IOException; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.Attributes; import org.xml.sax.Locator; import org.xml.sax.SAXException; import org.xml.sax.SAXNotRecognizedException; import org.xml.sax.SAXNotSupportedException; import org.xml.sax.SAXParseException; import org.xml.sax.XMLReader; import org.xml.sax.ext.LexicalHandler; import org.xml.sax.helpers.DefaultHandler; import org.xml.sax.helpers.ParserAdapter; import org.xml.sax.helpers.XMLReaderFactory;
public class SAXApp extends DefaultHandler{
// default parser to use protected static final String DEFAULT_PARSER_NAME = "org.apache.xerces.parsers.SAXParser";
private int count = 0;
public void countTopics () throws IOException, SAXException { // create parser try { System.out.println ("Inside countTopics"); } catch (Exception e) { e.printStackTrace(System.err); } }
public void startElement(String uri, String local, String raw, Attributes attrs) throws SAXException { if (raw.equals("topic")) count++; System.out.println (raw); }
public void endDocument() throws SAXException { System.out.println("There are " + count + " topics"); }
public static void main (String[] args) throws Exception{ System.out.println ("Inside main ...");
SAXApp handler = new SAXApp();
try { SAXParserFactory spf = SAXParserFactory.newInstance (); SAXParser parser = spf.newSAXParser (); parser.parse ("contents.xml", handler); } catch (SAXException e) { System.err.println(e.getMessage()); } } }
XML Parsing | Atul Kahate 74
Exercise Consider the following XML file and write a program to
count the number of elements that have at least one attribute.
<?xml version="1.0"?><BOOKS>
<BOOK pubyear="1929"><BOOK_TITLE>Look Homeward, Angel</BOOK_TITLE><AUTHOR>Wolfe, Thomas</AUTHOR>
</BOOK><BOOK pubyear="1973">
<BOOK_TITLE>Gravity's Rainbow</BOOK_TITLE><AUTHOR>Pynchon, Thomas</AUTHOR>
</BOOK><BOOK pubyear="1977">
<BOOK_TITLE>Cards as Weapons</BOOK_TITLE><AUTHOR>Jay, Ricky</AUTHOR>
</BOOK><BOOK pubyear="2001">
<BOOK_TITLE>Computer Networks</BOOK_TITLE><AUTHOR>Tanenbaum, Andrew</AUTHOR>
</BOOK></BOOKS>
XML Parsing | Atul Kahate 75
Solution import java.io.IOException; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.Attributes; import org.xml.sax.Locator; import org.xml.sax.SAXException; import org.xml.sax.SAXNotRecognizedException; import org.xml.sax.SAXNotSupportedException; import org.xml.sax.SAXParseException; import org.xml.sax.XMLReader; import org.xml.sax.ext.LexicalHandler; import org.xml.sax.helpers.DefaultHandler; import org.xml.sax.helpers.ParserAdapter; import org.xml.sax.helpers.XMLReaderFactory;
public class countAttr extends DefaultHandler{ private int count = 0; public void startDocument() throws SAXException { System.out.println("Start document ..."); } public void startElement(String uri, String local, String raw, Attributes attrs) throws SAXException { System.out.println ("Current element = " + raw); if (attrs.getLength () != 0) { count++; } } public void endDocument() throws SAXException { System.out.println("The total number of attributes = " + count); }
public static void main (String[] args) throws Exception { countAttr handler = new countAttr (); try { SAXParserFactory spf = SAXParserFactory.newInstance (); SAXParser parser = spf.newSAXParser (); parser.parse ("countAttr.xml", handler); } catch (SAXException e) { System.err.println(e.getMessage()); } } }
XML Parsing | Atul Kahate 76
Exercise For the same XML file, display
element names only if the book is published in the 1970s.
XML Parsing | Atul Kahate 77
Solution import java.io.IOException; import java.lang.*; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.Attributes; import org.xml.sax.Locator; import org.xml.sax.SAXException; import org.xml.sax.SAXNotRecognizedException; import org.xml.sax.SAXNotSupportedException; import org.xml.sax.SAXParseException; import org.xml.sax.XMLReader; import org.xml.sax.ext.LexicalHandler; import org.xml.sax.helpers.DefaultHandler; import org.xml.sax.helpers.ParserAdapter; import org.xml.sax.helpers.XMLReaderFactory;
public class seventiesBooks extends DefaultHandler{ private int count = 0; public void startDocument() throws SAXException { System.out.println("Start document ..."); } public void startElement(String uri, String local, String raw, Attributes attrs) throws SAXException { int year = 0; String attrValue; System.out.println ("Current element = " + raw); if (attrs.getLength () > 0) { attrValue = attrs.getValue (0); year = Integer.parseInt (attrValue); if (year < 1970) { count++; } } } public void endDocument() throws SAXException { System.out.println("The total number of matching elements = " + count); }
public static void main (String[] args) throws Exception { seventiesBooks handler = new seventiesBooks(); try { SAXParserFactory spf = SAXParserFactory.newInstance (); SAXParser parser = spf.newSAXParser (); parser.parse ("countAttr.xml", handler); } catch (SAXException e) { System.err.println(e.getMessage()); } } }
XML Parsing | Atul Kahate 78
Exercise Consider the following XML document (stock.xml) <?xml version="1.0"?>
<stock> <stockinfo symbol="IFL"> <company>i-flex solutions limited</company> <price>2500</price> </stockinfo> <stockinfo symbol="HLL"> <company>Hindustan Lever</company> <price>1840</price> </stockinfo> <stockinfo symbol="LT"> <company>Laresn and Toubro</company> <price>2678</price> </stockinfo> <stockinfo symbol="Rel"> <company>Reliance Communications</company> <price>1743</price> </stockinfo> </stock> Produce output as shown on the next slide
XML Parsing | Atul Kahate 79
Expected Output
XML Parsing | Atul Kahate 80
Solution import java.io.*; import org.xml.sax.*; import org.xml.sax.helpers.*; import javax.xml.parsers.*;
public class DisplayStockDetails extends DefaultHandler {
public void startDocument () throws SAXException { System.out.println ("\nDisplaying Stock Details"); System.out.println ("=========================\n"); }
public void endDocument () throws SAXException { System.out.println ("\nEnd of Details"); System.out.println ("==============\n"); }
public void startElement (String uri, String local, String raw, Attributes attrs) throws SAXException {
// Skip processing root element if (local.equals ("stock")) return;
// Skip processing if there are no attributes if (attrs == null) return;
for (int i=0; i<attrs.getLength (); i++) { System.out.println ("[Symbol: " + attrs.getValue (i) + "]"); } }
public void endElement (String uri, String local, String raw) throws SAXException { // System.out.println (); }
public void characters (char[] ch, int start, int length) throws SAXException { System.out.println (new String (ch, start, length)); }
public static void main (String[] args) throws Exception {
DisplayStockDetails handler = new DisplayStockDetails ();
try { SAXParserFactory spf = SAXParserFactory.newInstance (); SAXParser parser = spf.newSAXParser (); parser.parse ("stock.xml", handler); } catch (SAXException e) { System.err.println(e.getMessage()); } } }
XML Parsing | Atul Kahate 81
Exercise Consider the following XML file and write a program to find out and display the total cost for
all CDs.
<?xml version="1.0" encoding="ISO-8859-1"?> <catalog> <cd> <title>Empire Burlesque</title> <artist>Bob Dylan</artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> </cd> <cd> <title>Candle in the wind</title> <artist>Elton John</artist> <country>UK</country> <company>HMV</company> <price>8.20</price> <year>1998</year> </cd> </catalog>
XML Parsing | Atul Kahate 82
Solution import java.io.IOException; import java.lang.*; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.Attributes; import org.xml.sax.Locator; import org.xml.sax.SAXException; import org.xml.sax.SAXNotRecognizedException; import org.xml.sax.SAXNotSupportedException; import org.xml.sax.SAXParseException; import org.xml.sax.XMLReader; import org.xml.sax.ext.LexicalHandler; import org.xml.sax.helpers.DefaultHandler; import org.xml.sax.helpers.ParserAdapter; import org.xml.sax.helpers.XMLReaderFactory;
public class CDPrice extends DefaultHandler{
private int count = 0, total = 0; private boolean flagIsAvailable = false, flagIsCurrentElementPrice = false;
public void startDocument() throws SAXException { System.out.println("Start document ..."); }
public void startElement(String uri, String local, String raw, Attributes attrs) throws SAXException {
int year = 0; String attrValue;
System.out.println ("Current element = " + raw);
if (raw.equals ("price")) { flagIsCurrentElementPrice = true; System.out.println ("INSIDE if of startElement ==="); }
}
public void characters (char [] ch, int start, int len) throws SAXException {
if (flagIsCurrentElementPrice) {
System.out.println ("ch = " + ch); System.out.println ("start = " + start); System.out.println ("len = " + len);
StringBuffer buffer = new StringBuffer ();
for (int i=0; i<len; i++) { buffer.append (ch[start+i]); }
System.out.println ("*** buffer = " + buffer + " ***");
String str = buffer.substring (0); int uprice = Integer.parseInt(str);
total += uprice; flagIsCurrentElementPrice = false; System.out.println ("Current total = " + total);
}
}
public void endDocument() throws SAXException { System.out.println("The total price of available CDs = " + total); }
public static void main (String[] args) throws Exception { CDPrice handler = new CDPrice();
try { SAXParserFactory spf = SAXParserFactory.newInstance (); SAXParser parser = spf.newSAXParser (); parser.parse ("cdcatalog2.xml", handler); } catch (SAXException e) { System.err.println(e.getMessage()); } } }
Document Object Model (DOM)
XML Parsing | Atul Kahate 84
DOM – Basic Flow
XML Parsing | Atul Kahate 85
Basic Concepts
XML Parsing | Atul Kahate 86
JAXP and DOM – Overview Class DocumentBuilderFactory
public abstract class javax.xml.parsers.DocumentBuilderFactory extends java.lang.object
Defines a factory API that enables applications to obtain a parser that produces DOM object trees from XML documents
parse method: Parses the contents of an XML document and returns the contents as a new Document object
XML Parsing | Atul Kahate 87
JAXP and DOM – Overview Class DocumentBuilder
public abstract class javax.xml.parsers. DocumentBuilder extends java.lang.Object
Defines the API to obtain DOM Document instances from an XML document
XML Parsing | Atul Kahate 88
JAXP and DOM – Overview Interface Document
public interface Document extends Node
The Document interface represents the entire HTML or XML document
Conceptually, it is the root of the document tree, and provides the primary access to the document's data
XML Parsing | Atul Kahate 89
JAXP and DOM – Overview Interface Element
public interface Element extends Node The Element interface represents an
element in an HTML or XML document Elements may have attributes associated
with them Inherits from Node, the generic Node
interface attributes may be used to retrieve the set of
all attributes for an element
XML Parsing | Atul Kahate 90
JAXP and DOMDocumentBuilderFactory factory =
DocumentBuilderFactory.newInstance ();DocumentBuilder builder =
factory.newDocumentBuilder ();Document document = builder.parse (fileName);Element root = document.getDocumentElement
();
XML Parsing | Atul Kahate 91
Example – XML File Count the number of Employee elements from this XML
using DOM <?xml version="1.0" encoding="UTF-8"?> <root> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> <employee>test 1</employee> </root>
XML Parsing | Atul Kahate 92
Example – Java Code package javaapplication1;
import org.w3c.dom.*;
public class Main { public static void main(String[] args) {
try { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance (); DocumentBuilder builder = factory.newDocumentBuilder (); Document document = builder.parse ("cdcatalog.xml"); Element root = document.getDocumentElement (); NodeList nodes = document.getElementsByTagName("employee"); System.out.println("There are " + nodes.getLength() + " elements.");
} catch (Exception ex) { System.out.println(ex); } } }
XML Parsing | Atul Kahate 93
Check if a File is Well-Formed package sicsr; import javax.xml.parsers.*;
public class IsWellFormed {
/** * @param args */ public static void main(String[] args) {
try { DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder domBuilder = domFactory.newDocumentBuilder(); domBuilder.parse("NWF.xml"); }
catch (org.xml.sax.SAXException ex) { System.out.println("File is not well-formed"); }
catch (FactoryConfigurationError ex) { System.out.println(ex.toString ()); }
catch (ParserConfigurationException ex) { System.out.println(ex.toString ()); }
catch (Exception ex) { System.out.println(ex.toString ());
} } }
XML Parsing | Atul Kahate 94
JAXP Code to Open an XML Fileimport org.w3c.dom.*;import javax.xml.parsers.*;import org.xml.sax.*;
public class DOMExample1 { public static void main (String[] args) { try { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance (); DocumentBuilder builder = factory.newDocumentBuilder (); Document document = builder.parse ("cdcatalog.xml"); Element root = document.getDocumentElement (); System.out.println ("In main ... XML file openend successfully ..."); } catch (ParserConfigurationException e1) { System.out.println ("Exception: " + e1); } catch (SAXException e2) { System.out.println ("Exception: " + e2); } catch (java.io.IOException e3) { System.out.println ("Exception: " + e3); } }}
XML Parsing | Atul Kahate 95
Case Study – XML File<?xml version="1.0"?><catalog> <cd> <title>Empire Burlesque</title> <artist>Bob Dylan</artist> <country>USA</country> <company>Columbia</company> <price>10</price> <year>1985</year> </cd> <cd> <title>Candle in the wind</title> <artist>Elton John</artist> <country>UK</country> <company>HMV</company> <price>8</price> <year>1998</year> </cd></catalog>
XML Parsing | Atul Kahate 96
Problem Write a program to find out if an
element by the name price exists in the XML file and display its contents
XML Parsing | Atul Kahate 97
Solution import org.w3c.dom.*; import javax.xml.parsers.*; import org.xml.sax.*;
public class DOMExample2 { public static void main (String[] args) { NodeList elements; String elementName = "price"; try { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance (); DocumentBuilder builder = factory.newDocumentBuilder (); Document document = builder.parse ("cdcatalog.xml"); Element root = document.getDocumentElement (); System.out.println ("In main ... XML file openend successfully ..."); elements = document.getElementsByTagName(elementName);
// is there anything to do? if (elements == null) { return; }
// print all elements int elementCount = elements.getLength(); System.out.println ("Count = " + elementCount); for (int i = 0; i < elementCount; i++) { Element element = (Element) elements.item(i); System.out.println ("Element Name = " + element.getNodeName()); System.out.println ("Element Type = " + element.getNodeType()); System.out.println ("Element Value = " + element.getNodeValue()); System.out.println ("Has attributes = " + element.hasAttributes()); } } catch (ParserConfigurationException e1) { System.out.println ("Exception: " + e1); } catch (SAXException e2) { System.out.println ("Exception: " + e2); } catch (DOMException e2) { System.out.println ("Exception: " + e2); } catch (java.io.IOException e3) { System.out.println ("Exception: " + e3); } } }
XML Parsing | Atul Kahate 98
Problem Write a program to display
element names and their attribute names and values
XML Parsing | Atul Kahate 99
Solution import org.w3c.dom.*; import javax.xml.parsers.*; import org.xml.sax.*;
public class DOMExample3 { public static void main (String[] args) { NodeList elements; String elementName = "cd"; try { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance (); DocumentBuilder builder = factory.newDocumentBuilder (); Document document = builder.parse ("cdcatalog.xml"); Element root = document.getDocumentElement (); System.out.println ("In main ... XML file openend successfully ..."); elements = document.getElementsByTagName(elementName);
// is there anything to do? if (elements == null) { return; }
// print all elements int elementCount = elements.getLength(); System.out.println ("Count = " + elementCount); for (int i = 0; i < elementCount; i++) { Element element = (Element) elements.item(i); System.out.println ("Element Name = " + element.getNodeName()); System.out.println ("Element Type = " + element.getNodeType()); System.out.println ("Element Value = " + element.getNodeValue()); System.out.println ("Has attributes = " + element.hasAttributes()); // If attributes exist, print them if(element.hasAttributes()) { // if it does, store it in a NamedNodeMap object NamedNodeMap AttributesList = element.getAttributes(); // iterate through the NamedNodeMap and get the attribute names and values for(int j = 0; j < AttributesList.getLength(); j++) { System.out.println("Attribute: " + AttributesList.item(j).getNodeName() + " = " + AttributesList.item(j).getNodeValue()); } } } } catch (ParserConfigurationException e1) { System.out.println ("Exception: " + e1); } catch (SAXException e2) { System.out.println ("Exception: " + e2); } catch (DOMException e2) { System.out.println ("Exception: " + e2); } catch (java.io.IOException e3) { System.out.println ("Exception: " + e3); } } }
XML Parsing | Atul Kahate 100
Problem For a given element, find out all
the child elements and display their types
XML Parsing | Atul Kahate 101
Solution import org.w3c.dom.*; import javax.xml.parsers.*; import org.xml.sax.*;
public class DOMExample4 { public static void main (String[] args) { NodeList elements, Children; String elementName = "cd"; String local = ""; Element element = null; try { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance (); DocumentBuilder builder = factory.newDocumentBuilder (); Document document = builder.parse ("cdcatalog.xml"); Element root = document.getDocumentElement (); System.out.println ("In main ... XML file openend successfully ..."); elements = document.getElementsByTagName(elementName);
// is there anything to do? if (elements == null) { return; }
// print all elements int elementCount = elements.getLength(); System.out.println ("Count = " + elementCount); for (int i = 0; i < elementCount; i++) { element = (Element) elements.item(i); System.out.println ("Element Name = " + element.getNodeName()); System.out.println ("Element Type = " + element.getNodeType()); System.out.println ("Element Value = " + element.getNodeValue()); System.out.println ("Has attributes = " + element.hasAttributes()); // Find out if child nodes exist for this element Children = element.getChildNodes();
if (Children != null) { for (int j=0; j< Children.getLength(); j++) { local = Children.item(j).getNodeName(); System.out.println ("Child element name = " + local); } } } } catch (ParserConfigurationException e1) { System.out.println ("Exception: " + e1); } catch (SAXException e2) { System.out.println ("Exception: " + e2); } catch (DOMException e2) { System.out.println ("Exception: " + e2); } catch (java.io.IOException e3) { System.out.println ("Exception: " + e3); } } }
XML Parsing | Atul Kahate 102
Node Types 1 ELEMENT_NODE Element The element name
2 ATTRIBUTE_NODE Attribute The attribute name 3 TEXT_NODE Text #text 4 CDATA_SECTION_NODE CDATA #cdata-section 5 ENTITY_REFERENCE_NODE Entity reference The entity reference name 6 ENTITY_NODE Entity The entity name 7 PROCESSING_INSTRUCTION_NODE PI The PI target 8 COMMENT_NODE Comment #comment 9 DOCUMENT_NODE Document #document 10 DOCUMENT_TYPE_NODE DocType Root element 11 DOCUMENT_FRAGMENT_NODE DocumentFragment #document-fragment 12 NOTATION_NODE Notation The notation name
XML Parsing | Atul Kahate 103
Making Use of Node Types import org.w3c.dom.*; import javax.xml.parsers.*; import org.xml.sax.*;
public class DOMExample4 { public static void main (String[] args) { NodeList elements, Children; String elementName = "cd"; String local = ""; Element element = null; try { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance (); DocumentBuilder builder = factory.newDocumentBuilder (); Document document = builder.parse ("cdcatalog.xml"); Element root = document.getDocumentElement (); System.out.println ("In main ... XML file openend successfully ..."); elements = document.getElementsByTagName(elementName);
// is there anything to do? if (elements == null) { return; }
// print all elements int elementCount = elements.getLength(); System.out.println ("Count = " + elementCount); for (int i = 0; i < elementCount; i++) { element = (Element) elements.item(i); System.out.println ("Element Name = " + element.getNodeName()); System.out.println ("Element Type = " + element.getNodeType()); System.out.println ("Element Value = " + element.getNodeValue()); System.out.println ("Has attributes = " + element.hasAttributes()); // Find out if child nodes exist for this element Children = element.getChildNodes();
if (Children != null) { for (int j=0; j< Children.getLength(); j++) { local = Children.item(j).getNodeName(); System.out.println ("Child element name = " + local); } } } } catch (ParserConfigurationException e1) { System.out.println ("Exception: " + e1); } catch (SAXException e2) { System.out.println ("Exception: " + e2); } catch (DOMException e2) { System.out.println ("Exception: " + e2); } catch (java.io.IOException e3) { System.out.println ("Exception: " + e3); } } }
XML Parsing | Atul Kahate 104
Problem Write a program to create XML
contents dynamically and write them to a file on the disk
XML Parsing | Atul Kahate 105
Solution import java.io.File; import java.io.IOException; import java.io.OutputStreamWriter; import java.io.Writer;
import org.w3c.dom.*; import javax.xml.parsers.*; import org.xml.sax.*; import javax.xml.transform.TransformerConfigurationException; import javax.xml.transform.TransformerException; import javax.xml.transform.Source; import javax.xml.transform.dom.DOMSource; import javax.xml.transform.Result; import javax.xml.transform.stream.StreamResult; import javax.xml.transform.Transformer; import javax.xml.transform.TransformerFactory;
public class DOMExample5 { public static void main (String[] args) { Source source; File file; Result result; try { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance (); DocumentBuilder builder = factory.newDocumentBuilder (); // Create a new XML document Document document = builder.newDocument (); Element root = (Element) document.createElement("Order"); // Insert child Manifest document.appendChild(root); Node manifestChild = document.createElement("Manifest"); root.appendChild(manifestChild); // Insert Items CreateOrderDOM co = new CreateOrderDOM (); co.insertItem(document, manifestChild, "101", "Name one", "$29.99"); co.insertItem(document, manifestChild, "108", "Name two", "$19.99"); co.insertItem(document, manifestChild, "125", "Name three", "$39.99"); co.insertItem(document, manifestChild, "143", "Name four", "$59.99"); co.insertItem(document, manifestChild, "118", "Name five", "$99.99");
// Normalizing the DOM document.getDocumentElement().normalize(); // Prepare the DOM document for writing source = new DOMSource(document);
// Prepare the output file file = new File("test.xml"); result = new StreamResult(file);
// Write the DOM document to the file // Get Transformer Transformer xformer = TransformerFactory.newInstance().newTransformer(); // Write to a file xformer.transform(source, result);
} catch ( Exception ex ) { ex.printStackTrace(); } }
}
Stream API (StAX) – Brief Overview
To be covered in more depth in “Web Services”
XML Parsing | Atul Kahate 107
What is StAX? Addition in Java EE 5.0 Pull approach Event-based API Different from SAX, since
application pulls event from the XML document/parser, and not the other way round
Can do read and write
XML Parsing | Atul Kahate 108
StAX Classification Two APIs
Cursor-based API Allows walk-through of an XML document
in document order and Provides access to all the structural and
content information in the form of event objects
Iterator-based API Similar to cursor API, but does not
provide low level access
Using XSLT in JAXP
XML Parsing | Atul Kahate 110
Applying an XSLT to an XML File Programatically package sicsr;
import javax.xml.transform.*; import javax.xml.transform.stream.StreamResult; import javax.xml.transform.stream.StreamSource; import java.io.*;
public class ApplyXSLT {
public static void main(String[] args) {
try {
StreamSource xmlFile = new StreamSource (new File ("history.xml")); StreamSource xslFile = new StreamSource (new File ("history.xsl"));
TransformerFactory xslFactory = TransformerFactory.newInstance(); Transformer transformer = xslFactory.newTransformer (xslFile);
StreamResult resultStream = new StreamResult (System.out);
transformer.transform(xmlFile, resultStream); }
catch (Exception ex) { ex.printStackTrace(); }
}
}
XML Parsing | Atul Kahate 111
Details about the Transformer TransformerFactory is an abstract
class in javax.xml.transform package Can be used to create a Transformer
object Transformer is also an abstract class
in javax.xml.transform.Transformer package An instance of this class can transform a
source tree into a result tree
XML and ASP.NET – An Overview
XML Parsing | Atul Kahate 113
XmlReader and XmlWriter XMLReader
Pull-style API for XML Forward-only, read-only access to XML
documents XMLReader is an abstract class that other
classes derive from, to provide specific concrete instances such as XmlTextReader and XmlNodeReader
In ASP.NET 2.0, XMLReader is a factory We need not specify which implementation of
XMLReader needs to be used We use a static Create method, and supply necessary
parameters and let .NET decide how to instantiate it
XML Parsing | Atul Kahate 114
Example – XML Document <?xml version="1.0" encoding="utf-8" ?> <bookstore> <book genre ="autobiography" publicationdate="1981" ISBN="1-861003-11-0"> <title>The Autobiography of Benjamin Franklin</title> <author> <first-name>Benjamin</first-name> <last-name>Franklin</last-name> </author> <price>8.99</price> </book> <book genre ="novel" publicationdate="1967" ISBN="0-201-65512-2"> <title>The Confidence Man</title> <author> <first-name>Herman</first-name> <last-name>Melville</last-name> </author> <price>11.99</price> </book> <book genre ="philosophy" publicationdate="1991" ISBN="1-861001-57-6"> <title>The Gorgias</title> <author> <first-name>Sidas</first-name> <last-name>Plato</last-name> </author> <price>9.99</price> </book> </bookstore>
XML Parsing | Atul Kahate 115
Example – ASP.NET Page using System; using System.Data; using System.Configuration; using System.Collections; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; using System.Xml; using System.IO;
public partial class XMLReader2 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { int bookCount = 0; XmlReaderSettings settings = new XmlReaderSettings();
settings.IgnoreWhitespace = true; settings.IgnoreComments = true;
string booksFile = Path.Combine(Request.PhysicalApplicationPath, "Books.xml");
using (XmlReader reader = XmlReader.Create(booksFile, settings)) { while (reader.Read()) { if (reader.NodeType == XmlNodeType.Element && "book" == reader.LocalName) { bookCount++; } } } Response.Write(String.Format("Found {0} books!", bookCount));
} }
XML Parsing | Atul Kahate 116
Validating an XML Against a Schema using System.Xml.Schema; using System; using System.Xml; using System.IO;
public partial class XMLReader3 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { int bookCount = 0; XmlReaderSettings settings = new XmlReaderSettings();
string booksSchemaFile = Path.Combine(Request.PhysicalApplicationPath, "books.xsd"); settings.Schemas.Add (null, XmlReader.Create (booksSchemaFile)); settings.ValidationType = ValidationType.Schema; settings.ValidationFlags = XmlSchemaValidationFlags.ReportValidationWarnings; settings.ValidationEventHandler += new ValidationEventHandler (settings_ValidationEventHandler); settings.IgnoreWhitespace = true; settings.IgnoreComments = true;
string booksFile = Path.Combine(Request.PhysicalApplicationPath, "Books.xml");
using (XmlReader reader = XmlReader.Create(booksFile, settings)) { while (reader.Read()) { if (reader.NodeType == XmlNodeType.Element && "book" == reader.LocalName) { bookCount++; } } } Response.Write(String.Format("Found {0} books!", bookCount)); }
void settings_ValidationEventHandler(object sender, System.Xml.Schema.ValidationEventArgs e) { Response.Write(e.Message); } }
XML Parsing | Atul Kahate 117
Creating an XML Document using System.Xml.Schema; using System; using System.Xml; using System.IO;
public partial class XMLReader3 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { int bookCount = 0; XmlReaderSettings settings = new XmlReaderSettings();
string booksSchemaFile = Path.Combine(Request.PhysicalApplicationPath, "books.xsd"); settings.Schemas.Add (null, XmlReader.Create (booksSchemaFile)); settings.ValidationType = ValidationType.Schema; settings.ValidationFlags = XmlSchemaValidationFlags.ReportValidationWarnings; settings.ValidationEventHandler += new ValidationEventHandler (settings_ValidationEventHandler); settings.IgnoreWhitespace = true; settings.IgnoreComments = true;
string booksFile = Path.Combine(Request.PhysicalApplicationPath, "Books.xml");
using (XmlReader reader = XmlReader.Create(booksFile, settings)) { while (reader.Read()) { if (reader.NodeType == XmlNodeType.Element && "book" == reader.LocalName) { bookCount++; } } } Response.Write(String.Format("Found {0} books!", bookCount)); }
void settings_ValidationEventHandler(object sender, System.Xml.Schema.ValidationEventArgs e) { Response.Write(e.Message); } }
Thank you!
Any Questions?