8-1 geometric mean

14
8-1 Geometric Mean p. 537 You used proportional relationships of corresponding angle bisectors, altitudes, and medians of similar triangles. Find the geometric mean between two numbers. Solve problems involving relationships between parts of a right triangle and the altitude to its hypotenuse.

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8-1 Geometric Mean. p. 537. You used proportional relationships of corresponding angle bisectors, altitudes, and medians of similar triangles. . Find the geometric mean between two numbers. - PowerPoint PPT Presentation

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Page 1: 8-1 Geometric Mean

8-1 Geometric Meanp. 537

You used proportional relationships of corresponding angle bisectors, altitudes, and medians of similar triangles.

• Find the geometric mean between two numbers.

• Solve problems involving relationships between parts of a right triangle and the altitude to its hypotenuse.

Page 2: 8-1 Geometric Mean

Geometric mean – when the means of a proportion are the same number.

𝒂𝒙=

𝒙𝒅

extremeextrememeanmean

The geometric mean between two numbers is the positive square room of their product.

Page 3: 8-1 Geometric Mean

p. 537

Page 4: 8-1 Geometric Mean

Find the geometric mean between 2 and 50.

Answer: The geometric mean is 10.

Definition of geometric mean

Let x represent the geometric mean.

Cross products

Take the positive square root of each side.

Simplify.

Page 5: 8-1 Geometric Mean

A. 3.9

B. 6

C. 7.5

D. 4.5

A. Find the geometric mean between 3 and 12.

Page 6: 8-1 Geometric Mean

Geometric Means in Right Triangles

In a right triangle, an altitude drawn from the vertex of the right angle to the hypotenuse forms two additional right triangles.The two triangles formed are similar to the original triangle and to each other.

Page 7: 8-1 Geometric Mean

p. 538

Page 8: 8-1 Geometric Mean

Write a similarity statement identifying the three similar triangles in the figure.

Separate the triangles into two triangles along the altitude.Then sketch the three triangles, reorienting the smaller ones so that their corresponding angles and sides are in the same position as the original triangle.

Answer: So, by Theorem 8.1, ΔEGF ~ ΔFGH ~ ΔEFH.

Page 9: 8-1 Geometric Mean

A. ΔLNM ~ ΔMLO ~ ΔNMO

B. ΔNML ~ ΔLOM ~ ΔMNO

C. ΔLMN ~ ΔLOM ~ ΔMON

D. ΔLMN ~ ΔLMO ~ ΔMNO

Write a similarity statement identifying the three similar triangles in the figure.

Page 10: 8-1 Geometric Mean

A B

C

D

ab

x y

h

c

A B

CA

B

C

D

C

Da

a

bb

x

c

h

h y

h𝑠 𝑜𝑟𝑡𝑒𝑟 𝑙𝑒𝑔𝑙𝑜𝑛𝑔𝑒𝑟 𝑙𝑒𝑔 =

𝑏𝑎=

𝑥h=

h𝑦

h𝑦𝑝𝑜𝑡𝑒𝑛𝑢𝑠𝑒h𝑠 𝑜𝑟𝑡𝑒𝑟 𝑙𝑒𝑔 =

𝑐𝑏=

𝑏𝑥=

𝑎h

p. 538

Page 11: 8-1 Geometric Mean

p.539

h=√𝑥𝑦

𝑏=√𝑥𝑐𝑎=√𝑦𝑐

Page 12: 8-1 Geometric Mean

Find c, d, and e.Since e is the measure of the altitude drawn to the hypotenuse of right ΔJKL, e is the geometric mean of the lengths of the two segments that make up the hypotenuse, JM and ML.

Geometric Mean(Altitude) TheoremSubstitutionSimplify.

Geometric Mean (Leg) TheoremSubstitutionUse a calculator to simplify.

Since d is the measure of leg JK, d is the geometric mean of JM, the measure of the segment adjacent to this leg, and the measure of the hypotenuse JL.

Page 13: 8-1 Geometric Mean

Geometric Mean(Leg) Theorem

Substitution

Use a calculator tosimplify.

Answer: e = 12, d ≈ 13.4, c ≈ 26.8

Since c is the measure of leg KL, c is the geometric mean of ML, the measure of the segment adjacent to KL, and the measure of the hypotenuse JL.

Page 14: 8-1 Geometric Mean

8-1 Assignment

Page 541, 8-19