8-5 exponential and logarithmic equations
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85 Exponential and Logarithmic Equations
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Objectives:• Solve exponential equations.• Solve logarithmic equations.
8-5 Exponential & Logarithmic Equations
85 Exponential and Logarithmic Equations
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Evaluate each logarithm.
1. log981 log93 2. log 10 log39
3. log216 ÷ log28 4. Simplify 12523
Check Skills You'll Need
85 Exponential and Logarithmic Equations
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An equation of the form bcx=a, where the exponent includes a variable, is an exponential equation.
If m and n are positive and m = n, then log m = log n.
Therefore, you can solve an exponential equation by taking the logarithm of each side of the equation.
Solving Exponential Equations
85 Exponential and Logarithmic Equations
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Example #1: Solving an Exponential Equation
Solve 73x = 20.
73x = 20log 73x = log 20 Take the common logarithm of each side.
3x log 7 = log 20 Use the power property of logarithms.
x =
x ≈ 0.5132
log 203log 7
Divide each side by 3 log 7.
Use a calculator.
Check: 73x = 20 73(0.5132) = 20 20.00382 ≈ 20
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Example #2: Solve each equation. Round to the nearest ten-thousandth. Check your answers.
a. 3x = 4 b. 62x = 21 c. 3x+4 = 101
85 Exponential and Logarithmic Equations
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Solving Logarithmic Equations
To evaluate a logarithm with any base, you can use the Change of Base Formula.
85 Exponential and Logarithmic Equations
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Example #3: Using the Change of Base Formula
Use the Change of Base Formula to evaluate log315.
log315 =
≈ 2.4650
log 15log 3
85 Exponential and Logarithmic Equations
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Example #4: Evaluate log5400.
85 Exponential and Logarithmic Equations
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An equation that includes a logarithmic expression, such as log315 = log2x is called a
logarithmic equation.
85 Exponential and Logarithmic Equations
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Example #5: Solving a Logarithmic Equation
Solve log (3x + 1) = 5.
log (3x + 1) = 5
3x + 1 = 105
3x + 1 = 100,000
3x = 99,999
x = 33,333Check: log (3x + 1) = 5
log (3(33,333) + 1) = 5 log (100,000) = 5
log 105 = 5 5 = 5
85 Exponential and Logarithmic Equations
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Example #6: Solve log (7 2x) = 1. Check your answer.
85 Exponential and Logarithmic Equations
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Example #7: Using Logarithmic Properties to Solve an Eqauation
Solve 2 log x log 3 = 2.
2 log x log 3 = 2
log = 2 Write as a single logarithm.
= 102Write in exponential form.
x2 = 3(100)
x = ±10√3 ≈ ±17.32
Log x is defined only for x>0, so the solution is 10√3 or about 17.32.
x2
3x2
3
( )
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Example #8: Solve log 6 log 3x = 2.
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Homework: page 464(1 - 12, 23, 25 - 32 evaluate, 33 - 45)