9 june maths iii
TRANSCRIPT
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 1/34
www.afterschoool.tk
MathsMathsDr. T.K. Jain.Dr. T.K. Jain.
AFTERSCHOOOLAFTERSCHOOOLM: 9414430763M: 9414430763
[email protected]@yahoo.co.in
www.afterschool.tkwww.afterschool.tk
www.afterschoool.tkwww.afterschoool.tk
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 2/34
www.afterschoool.tk
The length of minute hand on a wallclock is 7cms. What is the area swept
by the minute hand in 30 minutes?• This is the question of circle
• Area of circle : pi *r*r =
22/7*7*7=154• But the area in 30 minutes will be
half circle – so it will be 77 sq cm.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 3/34
www.afterschoool.tk
A wheel makes 1000 revolution incovering a distance of 88 km. What is
diameter of the wheel?• The circumference of wheel = 88000
/ 1000 = 88.
• Formulae of circumference of circle= 2pi*r = 2*22/7*R = 88
• 2R = 88*7/22 = 28meters Ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 4/34
www.afterschoool.tk
A wire is in the form of an equilateraltriangle with area 5 sq. m. If its shape
is changed to a circle, its radius will be?• Area of Triangle: 3^1/2/4 *side*side• 3^1/2/4 *side*side =5,• side^2 = 20/ 3^1/2 =11.5
Side = 3.4 approx.Length of wire:3*3.4= 10.2Circumference of circle =10.2
2pi *r = 10.2R = 10.2/ 6.28 = 1.63 meters approx.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 5/34
www.afterschoool.tk
at is t e circum erenceof semicircular shape on a
line of length 10 cm?• Circumference = 2pi*r
• =2*22/7*5 =10*3.1428 = 31.42
• Half of circumference = 15.92• Add diameter with this = 25.92 ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 6/34
www.afterschoool.tk
T e ratio o t e engt o aside of an equilateral
triangle and its height is?• Let us assume that side of a triangle is X. its areais .433 X^2. (3^1/2/4 *side * side). Let us assumethat we divide it in two triangles of equal sizewith area = .433 X^2/2. This triangle will have
area ½*base*height. (being right angle triangle)• Here base = side /2, so• .433x^2 /2 =1/2*X/2*h• Height = .433x^2*4 /2x = .433 *2 X
• Ratio of side to height = 1: .866 Ans.• Another method = applying pythogorus rule,• X^2 = (x/2)^2 + height ^2 , solving we get ratio of
side to height as 2:3^1/2
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 7/34
www.afterschoool.tk
There are 4 circles in a bigger circle.The diameter of biggest circle is 56 but
those of smaller circles is 7. what isarea of bigger circle which has not been
occupied by smaller circles.•
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 8/34
www.afterschoool.tk
Answer:
• Area of bigger circle:• 3.1428*28*28 =2464
• Area of smaller circle =22/7*7/2*7/2 = 38.5 ; there arefour circles so area is 38.5*4 = 154
• Area of uncovered bigger circle• 2464-154 = 2310 ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 9/34
www.afterschoool.tk
Inner circumference of a 14 meterwide race track is 440 meters, what
is the radius of outer circle?• Inner radius is
• 2pi*r = 440; r = 440*7/44 = 70
• Radius of outer circle is 70+14 = 84ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 10/34
www.afterschoool.tk
A circular wire of radius 42 cm is bentinto the shape of a rectangle. What isthe diagonal of this rectangle, if the
sides are in the ratio of 6:5?• Step 1: find the circumference :• 2*pi*r = 2*22/7*42 =264
• 6x+5x = 264; 11x=264; x =24• Length of rectangle : 144, width is
120.
• Diagonal will be square root of 144^2+120^2= 187.44 approx.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 11/34
www.afterschoool.tk
at is t e area o circ einscribed in an equilateral
triangle of side 24?• We know that radius of incircle is :
• R = Side /( 2*3^1/2)
• Therefore radius is : 24 / (2*1.73)• =6.928
• Area of circle = pie *r *r = 150.8approx. ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 12/34
www.afterschoool.tk
What is the area of circlecircumscribed in an equilateral triangle
of side 24?• We know that radius of circumcircle
is :
• R = Side /3^1/2
• Therefore radius is : 24 / 1.73• =14aprox
• Area of circle = pie *r *r• = 196 pi. Ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 13/34
www.afterschoool.tk
A man builds a circular pool of radius 5 inside acircular garden of radius 12. In order tocompensate for area lost, he extends the
garden, What is radius of garden, if its area is
same as earlier?• Area of garden: 144 pi. Area of pool=25 pi• Let us assume that he increases radius by x• Pi * (12+x)^2 -144pi = 25 pi.• 144+24x+x^2-144 = 25• X^2+24x-25 =0• X^2 +25x-x-25; x(x+25)-1(x+25)• X=1• New radius of the garden is 13 Ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 14/34
www.afterschoool.tk
What is the area of largest trianglethat can be inscribed in a semi-circle of
radius 7?• Here we will keep the base as
diameter of the circle = 14. Height
will be 7 (as radius).• Thus the area will be ½*7*14
• =49 ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 15/34
www.afterschoool.tk
What is the area of largesttriangle that can be inscribed in a
circle of radius 7?• Radius = side / 3^1/2
• Side= Radius * 1.73 = 7*1.73 =12.12
• Area of triangle:• 3^1/2 /4 * 12.12*12.12
• =63 approx. ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 16/34
www.afterschoool.tk
What is the area of largest squarethat can be inscribed in a circle of
radius 7?• Diagonal of square is 14.
• Area of square is ½ *Diagonal *
diagonal.• ½*14*14 = 98 ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 17/34
W d ’t t t th
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 18/34
www.afterschoool.tk
We don’t want a cow to graze more than9856 sq m area in circular form. Whatshould be the length of rope by which
we should tether the cow?• We have to calculate the radius in
this question.
• Pi*r *r = 9856• R^2 =9856 / pi = 3136
• R = 56 ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 19/34
www.afterschoool.tk
The ratio of radii of two circles is inthe ratio of 1:2, what is the ratio of
their area?• 1:4 ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 20/34
www.afterschoool.tk
The ratio of radii of two circles isin the ratio of 1:2, what is the
ratio of their circumference?• 1:2 ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 21/34
www.afterschoool.tk
The ratio of radii of two spheresin the ratio of 1:2, what is the
ratio of their volume?• 1:8 ans.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 22/34
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 23/34
www.afterschoool.tk
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 24/34
www.afterschoool.tk
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 25/34
www.afterschoool.tk
ThanksAfterschoool conducts three year integrated PGPSE(after class 12th along with IAS / CA / CS) and 18month PGPSE (Post Graduate Programme in Social
Entrepreneurship) along with preparation for CS /CFP / CFA /CMA / FRM. This course is alsoavailable online also. It also conducts workshops onsocial entrepreneurship in schools and colleges allover India – start social entrepreneurship club in
your institution today with the help fromafterschoool and help us in developing society.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 26/34
www.afterschoool.tk
About AFTERSCHOOOL PGPSE –the best programme for developing
great entrepreneurs• Most flexible, adaptive but rigorous programme• Available in distance learning mode• Case study focused- latest cases
• Industry oriented practical curriculum• Designed to make you entrepreneurs – not just an
employee• Option to take up part time job – so earn while
you learn• The only absolutely free course on internet
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 27/34
www.afterschoool.tk
Workshops from
AFTERSCHOOOL• IIF, Delhi• CIPS, Jaipur• ICSI Hyderabad Branch
• Gyan Vihar, Jaipur• Apex Institute of Management, Jaipur• Aravali Institute of Management, Jodhpur• Xavier Institute of Management, Bhubaneshwar
• Pacific Institute, Udaipur• Engineering College, Hyderabad
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 28/34
www.afterschoool.tk
Flexible Specialisations:• Spiritualising business and society• Rural development and transformation• HRD and Education, Social Development
• NGO and voluntary work• Investment analysis,microfinance and inclusion• Retail sector• Hospital management and Health care• Hospitality sector and culture and heritage
• Other sectors of high growth, high technologyand social relevance
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 29/34
www.afterschoool.tk
Salient features:• The only programme of its kind (in the whole world)• No publicity and low profile course• For those who want to achieve success in life – not just a
degree
• Indepth knowledge and expertise• Professional approac: World class approach• Strong intellectual and business capabilities• Flexible – you may stay for a month and continue the rest of
the education by distance mode.• Scholarships for those from poor economic background
• Latest and constantly changing curriculum – keeping pacewith the time
• Placement for those who are interested
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 30/34
www.afterschoool.tk
Components• Meditation, spiritualisation, and self development• Business plan• Essential softwares for business• Research projects
• Participation in conferences / seminars• Workshops on leadership, team building etc.• Written submissions of research projects/articles / papers• Interview of entrepreneurs, writing biographies of
entrepreneurs• Editing of journals / newsletters• Consultancy / research projects• Assignments, communication skill workshops
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 31/34
www.afterschoool.tk
Pedagogy• Case analysis• Quiz, seminars, workshops, games,• Visits to entrepreneurs and industrial
visits• Presentations• Group discussions and group projects• Periodic self assessment
• Mentoring and counselling
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 32/34
www.afterschoool.tk
Branches• AFTERSCHOOOL will shortly openits branches in important cities inIndia including Delhi, Kota, Mumbai,Gurgaon and other important cities.Afterschooolians will be responsiblefor managing and developing these
branches – and for promoting socialentrepreneurs.
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 33/34
www.afterschoool.tk
Case Studies• We want to write case studies onsocial entrepreneurs, first
generation entrepreneurs, ethicalentrepreneurs. Please help us in thisprocess. Help us to be in touch withentrepreneurs, so that we maydevelop entrepreneurs.
www a ersc ooo
8/14/2019 9 June Maths III
http://slidepdf.com/reader/full/9-june-maths-iii 34/34
www afterschoool tk
www.a ersc ooo . social entrepreneurship for
better society