ac and dc circuits presentation

CIRCUITS AND NETWORKS

CIRCUITSCIRCUITS

Parameters The various elements of an electric circuit, like resistance, inductance,

and capacitance which may be lumped or distibuted.

Parameters The various elements of an electric circuit, like resistance, inductance,

and capacitance which may be lumped or distibuted.

CIRCUITS A closed conducting path through which an electric

current flows or is intended to flow

CIRCUITS A closed conducting path through which an electric

current flows or is intended to flow

CIRCUITSCIRCUITS

Linear Circuit Is one whose parameters are constant (i.e. They do not change with

voltage and current.

Non-Linear Circuit Is that circuit whose parameters change with voltage and current.

Bilateral Circuit Is one whose properties or characteristics are the same in either

direction.

Unilateral Circuit Is that circuit whose properties or characteristics change with the

direction of its operation.

Linear Circuit Is one whose parameters are constant (i.e. They do not change with

voltage and current.

Non-Linear Circuit Is that circuit whose parameters change with voltage and current.

Bilateral Circuit Is one whose properties or characteristics are the same in either

direction.

Unilateral Circuit Is that circuit whose properties or characteristics change with the

direction of its operation.

TYPES


ELECTRICAL NETWORKSELECTRICAL NETWORKS

Passive NetworkWith no source of emf.

Active NetworkContains one or more than one sources of emf.

Passive NetworkWith no source of emf.

Active NetworkContains one or more than one sources of emf.

ELECTRICAL NETWORK Connection of various electric elements in any manner

ELECTRICAL NETWORK Connection of various electric elements in any manner

TYPES


ELECTRICAL NETWORKSELECTRICAL NETWORKS

Node A junction in a circuit where two or more circuit elements and/or

branches are connected together.

Branch Part of a network which lies netween two junctions.

Loop A closed path in a circuit in which no element or node is encountered

more than once.

Mesh A loop that contains no other loop within it.

Node A junction in a circuit where two or more circuit elements and/or

branches are connected together.

Branch Part of a network which lies netween two junctions.

Loop A closed path in a circuit in which no element or node is encountered

more than once.

Mesh A loop that contains no other loop within it.

PARTS


OHM’S LAWOHM’S LAW

OHM’S LAW One of the most fundamental law in electrical circuits relating

voltage, current and resistance Developed in 1827 by German physicist Georg Simon Ohm

OHM’S LAW One of the most fundamental law in electrical circuits relating

voltage, current and resistance Developed in 1827 by German physicist Georg Simon Ohm


OHM’S LAWOHM’S LAW

According to Ohm’s Law, the current (I) flowing in an electrical circuit is directly is directly proportional to the applied voltage (E) and inversely proportional to the equivalent resistance (R) of the circuit and mathematically expressed as:

According to Ohm’s Law, the current (I) flowing in an electrical circuit is directly is directly proportional to the applied voltage (E) and inversely proportional to the equivalent resistance (R) of the circuit and mathematically expressed as:


SERIES CIRCUITSSERIES CIRCUITS

SERIES circuits A circuit connection in which the components are

connected to form one conducting path

SERIES circuits A circuit connection in which the components are

connected to form one conducting path

SERIES/PARALLEL CIRCUITS

SERIES CIRCUITSSERIES CIRCUITS

Where: EX – voltage across the resistor concerned ET – total voltage across the circuit RX – the resistor concerned RT – the sum of all resistances in the circuit

Where: EX – voltage across the resistor concerned ET – total voltage across the circuit RX – the resistor concerned RT – the sum of all resistances in the circuit

Voltage Division for Series Circuit:

EX = ET • RX

RT


PARALLEL CIRCUITSPARALLEL CIRCUITS

PARALLEL circuits A circuit connection in which the components are

connected to form more than 1 conducting path

PARALLEL circuits A circuit connection in which the components are

connected to form more than 1 conducting path


PARALLEL CIRCUITSPARALLEL CIRCUITS

Where: IX – current concerned flowing through resistor Rx

IT – total current of the circuit

Req – equivalent resistance of the parallel circuit except Rx

RT – the sum of all resistances in the circuit

Where: IX – current concerned flowing through resistor Rx

IT – total current of the circuit

Req – equivalent resistance of the parallel circuit except Rx

RT – the sum of all resistances in the circuit

Voltage Division for Parallel Circuit:

IX = IT • Req

RT


KIRCHHOFF’S LAWKIRCHHOFF’S LAW

“In any electrical network, the algebraic sum of the current meeting at a point (or junction) is zero.”

“In any electrical network, the algebraic sum of the current meeting at a point (or junction) is zero.”

KIRCHHOFF’S LAW More comprehensive than Ohm’s Law and is used in solving electrical Termed as “Laws of Electric Networks” Formulated by German physicist Gustav Robert Kirchhoff

KIRCHHOFF’S LAW More comprehensive than Ohm’s Law and is used in solving electrical Termed as “Laws of Electric Networks” Formulated by German physicist Gustav Robert Kirchhoff

Kirchhoff’s Current Law (KCL)

NETWORK ANALYSIS

KIRCHHOFF’S CURRENT LAWKIRCHHOFF’S CURRENT LAW

In short the sum of currents entering a node equals the sum of currents leaving the node⁻ Current towards the node, positive current⁻ Current away from the node, negative current

IB + IC + ID = IA

(IB + IC + ID) - IA = 0

In short the sum of currents entering a node equals the sum of currents leaving the node⁻ Current towards the node, positive current⁻ Current away from the node, negative current

IB + IC + ID = IA

(IB + IC + ID) - IA = 0

NETWORK ANALYSIS

KIRCHHOFF’S VOLTAGE LAWKIRCHHOFF’S VOLTAGE LAW

“The algebraic sum of the products of currents and resistances in each of thr conductors in any closed path (or mesh) in a network PLUS the algebraic sum of the emfs in the path is zero.”

“The algebraic sum of the products of currents and resistances in each of thr conductors in any closed path (or mesh) in a network PLUS the algebraic sum of the emfs in the path is zero.”

Kirchhoff’s Voltage Law (KVL)

NETWORK ANALYSIS

KIRCHHOFF’S VOLTAGE LAWKIRCHHOFF’S VOLTAGE LAW

In short, the sum of the voltages around the loop is equal to zero⁻ For voltage sources, if loops enters on minus and goes out on plus,

positive voltage and if loops enters on plus and goes out on minus, negative voltage.

⁻ For voltage drops, if the loop direction is the same as current direction, negative voltage drop and if the loop direction is opposite to the current direction, positive voltage drop.

In short, the sum of the voltages around the loop is equal to zero⁻ For voltage sources, if loops enters on minus and goes out on plus,

positive voltage and if loops enters on plus and goes out on minus, negative voltage.

⁻ For voltage drops, if the loop direction is the same as current direction, negative voltage drop and if the loop direction is opposite to the current direction, positive voltage drop.

NETWORK ANALYSIS

MESH ANALYSISMESH ANALYSIS

Loop Analysis Procedure:1. Label each of the loop/mesh currents. 2. Apply KVL to loops/meshes to form

equations with current variables.a. For N independent loops, we may write

N total equations using KVL around each loop. Loop currents are those currents flowing in a loop; they are used to define branch currents.

b. Current sources provide constraint equations.

3. Solve the equations to determine the user defined loop currents.

Loop Analysis Procedure:1. Label each of the loop/mesh currents. 2. Apply KVL to loops/meshes to form

equations with current variables.a. For N independent loops, we may write

N total equations using KVL around each loop. Loop currents are those currents flowing in a loop; they are used to define branch currents.

b. Current sources provide constraint equations.

3. Solve the equations to determine the user defined loop currents.

NETWORK ANALYSIS

MESH analysis A sophisticated application of KVL with mesh currents.

MESH analysis A sophisticated application of KVL with mesh currents.

NODAL ANALYSISNODAL ANALYSIS

Consist of finding the node voltages at all principal nodes with respect to the reference node.

PRINCIPAL node – a node with three or more circuit elements joined together.

Reference node – the node from which the unknown voltages are measured.

Consist of finding the node voltages at all principal nodes with respect to the reference node.

PRINCIPAL node – a node with three or more circuit elements joined together.

Reference node – the node from which the unknown voltages are measured.

NETWORK ANALYSIS

NODAL analysis A systematic application of KCL at a node and after simplifying

the resulting KCL equation, the node voltage can be calculated.

NODAL analysis A systematic application of KCL at a node and after simplifying

the resulting KCL equation, the node voltage can be calculated.

SUPERPOSITION THEOREMSUPERPOSITION THEOREM

In general: Number of network to analyze is equal to number of independent

sources. To consider effects of each source independently, sources must be

removed and replaced without affecting the final result:

All voltage sources >> short circuited All current sources >> open circuited

In general: Number of network to analyze is equal to number of independent

sources. To consider effects of each source independently, sources must be

removed and replaced without affecting the final result:

All voltage sources >> short circuited All current sources >> open circuited

NETWORK ANALYSIS

SUPERPOSITION theorem “ The current through or voltage across, an element in a linear bilateral network is equal to the algebraic sum of the current or voltages produced independently in each source. ”

SUPERPOSITION theorem “ The current through or voltage across, an element in a linear bilateral network is equal to the algebraic sum of the current or voltages produced independently in each source. ”

COMPENSATION THEOREMCOMPENSATION THEOREM

NETWORK ANALYSIS

COMPENSATION theorem If the impedance Z of a branch in a network in which a current I

flows is changed by a finite amount dZ, then the change in the currents in all other branches of the network may be calculated by inserting a voltage source of -IdZ into that branch with all other voltage sources replaced by their internal impedances.

COMPENSATION theorem If the impedance Z of a branch in a network in which a current I

flows is changed by a finite amount dZ, then the change in the currents in all other branches of the network may be calculated by inserting a voltage source of -IdZ into that branch with all other voltage sources replaced by their internal impedances.

RECIPROCITY THEOREMRECIPROCITY THEOREM

Simply mean, E and I are mutually transferable, or The receiving point and the sending point in a network are

interchangeable, or Interchange of an IDEAL voltage source and an IDEAL ammeter in any

network will not change the ammeter reading, Interchange of an IDEAL current source and an IDEAL voltmeter in any

network will not change the voltmeter reading

Simply mean, E and I are mutually transferable, or The receiving point and the sending point in a network are

interchangeable, or Interchange of an IDEAL voltage source and an IDEAL ammeter in any

network will not change the ammeter reading, Interchange of an IDEAL current source and an IDEAL voltmeter in any

network will not change the voltmeter reading

NETWORK ANALYSIS

RECIPROCITY theorem “If a voltage source E acting in one branch of a network causes a current I to flow in another branch of the network, then the same voltage source E acting in the second branch would cause an identical current I to flow in the first branch. ”

RECIPROCITY theorem “If a voltage source E acting in one branch of a network causes a current I to flow in another branch of the network, then the same voltage source E acting in the second branch would cause an identical current I to flow in the first branch. ”

MILLMAN’S THEOREMMILLMAN’S THEOREM

In Millman’s Theorem, the circuit is re-drawn as a parallel network of branches, each branch containing a resistor or series battery/resistor combination.

Millman’s theorem is applicable only to those cicuits which can be re-drawn accordingly.

In Millman’s Theorem, the circuit is re-drawn as a parallel network of branches, each branch containing a resistor or series battery/resistor combination.

Millman’s theorem is applicable only to those cicuits which can be re-drawn accordingly.

NETWORK ANALYSIS

MILLMAN’S theorem “ A special case of the application of Thevenin’s Theorem/or Norton’s Theorem used for finding the COMMON voltage (VAB) across any network which contains a number of parallel voltage sources. ”

MILLMAN’S theorem “ A special case of the application of Thevenin’s Theorem/or Norton’s Theorem used for finding the COMMON voltage (VAB) across any network which contains a number of parallel voltage sources. ”

MAXIMUM POWER TRANSFER THOREM

MAXIMUM POWER TRANSFER THOREM

NETWORK ANALYSIS

MAXIMUM POWER TRANSFER theorem For loads connected directly to a DC voltage supply, maximum

power will be delivered to the load when the resistance is equal to the internal resistance of the source.

For maximum power transfer: RS = RL

MAXIMUM POWER TRANSFER theorem For loads connected directly to a DC voltage supply, maximum

power will be delivered to the load when the resistance is equal to the internal resistance of the source.

For maximum power transfer: RS = RL

THEVENIN’S THEOREMTHEVENIN’S THEOREM

where: VTH – the open circuit voltage which appears across the two terminals from where

the load resistance has been removed.RTH – the resistance looking back into the network across the two terminals with all

the voltage sources shorted and replaced by their internal resistances (if any) and all current sources by infinite resistance.

where: VTH – the open circuit voltage which appears across the two terminals from where

the load resistance has been removed.RTH – the resistance looking back into the network across the two terminals with all

the voltage sources shorted and replaced by their internal resistances (if any) and all current sources by infinite resistance.

NETWORK ANALYSIS

THEVENIN’S theorem “ Any two-terminal of a linear, active bilateral network of a fixed resistances and voltage source/s may be replaced by a single voltage source (VTH) and a series of internal resistance (RTH). ”

THEVENIN’S theorem “ Any two-terminal of a linear, active bilateral network of a fixed resistances and voltage source/s may be replaced by a single voltage source (VTH) and a series of internal resistance (RTH). ”

NORTON’S THEOREMNORTON’S THEOREM

where: IN– the current which would flow in a short circuit placed across the output terminals.RN – the resistance of the network when viewed from the open circuited terminals after all voltage sources being replaced by open circuits.

where: IN– the current which would flow in a short circuit placed across the output terminals.RN – the resistance of the network when viewed from the open circuited terminals after all voltage sources being replaced by open circuits.NETWORK ANALYSIS

THEVENIN’S theorem “ Any two-terminal active network containing voltage sources and resistances when viewed from its output terminals, is equivalent to a constant-current source (IN) and a parallel internal resistance (RN). ”

THEVENIN’S theorem “ Any two-terminal active network containing voltage sources and resistances when viewed from its output terminals, is equivalent to a constant-current source (IN) and a parallel internal resistance (RN). ”

THEVENIN-NORTON TRANSFORMATIONTHEVENIN-NORTON TRANSFORMATION

NETWORK ANALYSIS

NORTON-THEVENIN TRANSFORMATIONNORTON-THEVENIN TRANSFORMATION

NETWORK ANALYSIS

EQUIVALENT THREE-TERMINAL NETWORKS


NETWORK ANALYSIS

DELTA to WYE The equivalent resistance of each arm to the wye is given by the

PRODUCT of the two delta sides that meet at its end divided by the SUM of the three delta resistances.

DELTA to WYE The equivalent resistance of each arm to the wye is given by the

PRODUCT of the two delta sides that meet at its end divided by the SUM of the three delta resistances.



NETWORK ANALYSIS

WYE to DELTA The equivalent delta resistance between any two twrminals is given by the

SUM of a star resistance between those terminals PLUS the PRODUCT of these two star resistances DIVIDED by the third resistance.

WYE to DELTA The equivalent delta resistance between any two twrminals is given by the

SUM of a star resistance between those terminals PLUS the PRODUCT of these two star resistances DIVIDED by the third resistance.

REVIEW QUESTIONSREVIEW QUESTIONS1. A battery with a rating of 9 volts has an internal resistance of 20 ohms.

What is the expected resistance of the bulb that is connected across the battery to attain a maximum power transfer?a. 20 ohmsb. 10 ohmsc. 5 ohmsd. 2 ohms

2. In a sireis ciscuit a resistors 2200 and 4500 with an impressed voltage of 10, what is the circuit current in mA?a. 1.49b. 6.67c. 4.34d. 1.34

1. A battery with a rating of 9 volts has an internal resistance of 20 ohms. What is the expected resistance of the bulb that is connected across the battery to attain a maximum power transfer?a. 20 ohmsb. 10 ohmsc. 5 ohmsd. 2 ohms

2. In a sireis ciscuit a resistors 2200 and 4500 with an impressed voltage of 10, what is the circuit current in mA?a. 1.49b. 6.67c. 4.34d. 1.34

REVIEW QUESTIONSREVIEW QUESTIONS3. The current needed to operate a soldering iron which has a rating of

600 watts at 110 volts is.a. 5.455 Ab. 66,000 Ac. 18,200 Ad. 0.182 A

4. The ammeter reads 230 ampere while the voltmeter is 115 volts. What is the power inKW at the time of readinga. 264.5b. 2645c. 264500d.26.45

3. The current needed to operate a soldering iron which has a rating of 600 watts at 110 volts is.a. 5.455 Ab. 66,000 Ac. 18,200 Ad. 0.182 A

4. The ammeter reads 230 ampere while the voltmeter is 115 volts. What is the power inKW at the time of readinga. 264.5b. 2645c. 264500d.26.45

REVIEW QUESTIONSREVIEW QUESTIONS5. What is the type of circuit whose parameters are constant

which do not change with voltage or current?a. Lumpedb. Tunedc. Reactived. Linear

6. What is the resistance of two equal valued resistor series?a. Twice as oneb. The sum of their reciprocal c. The difference of bothb. The product of both

5. What is the type of circuit whose parameters are constant which do not change with voltage or current?a. Lumpedb. Tunedc. Reactived. Linear

6. What is the resistance of two equal valued resistor series?a. Twice as oneb. The sum of their reciprocal c. The difference of bothb. The product of both

REVIEW QUESTIONSREVIEW QUESTIONS7. What do you expect when you use two 20 kohms, 1 watts resistors

in parallel instead of one 10 kohms, 1 watt?a. Provide more powerb. Provide lighter currentc. Provide less powerd. Provide wider tolerance

8. The voltage applied in DC circuit having a power of 36 watts and a total resistance of 4 ohms.a. 6 Vb. 9Vc. 12 Vd. 24 V

7. What do you expect when you use two 20 kohms, 1 watts resistors in parallel instead of one 10 kohms, 1 watt?a. Provide more powerb. Provide lighter currentc. Provide less powerd. Provide wider tolerance

8. The voltage applied in DC circuit having a power of 36 watts and a total resistance of 4 ohms.a. 6 Vb. 9Vc. 12 Vd. 24 V

REVIEW QUESTIONSREVIEW QUESTIONS9. When resistor are connected in series, what happens?

a. The effective resistanceb. Nothingc. The toleranced. The effective resistance is increased

10. Find the thevenin’s impedance equivalent across R2 of a linear close circuit having 10-V supply in series with the resistors (R1=100 ohms and R2=200 ohms)a. 666 ohmsb. 6.66 ohmsc. 66.6 ohmsd. 6666 ohms

9. When resistor are connected in series, what happens?a. The effective resistanceb. Nothingc. The toleranced. The effective resistance is increased

10. Find the thevenin’s impedance equivalent across R2 of a linear close circuit having 10-V supply in series with the resistors (R1=100 ohms and R2=200 ohms)a. 666 ohmsb. 6.66 ohmsc. 66.6 ohmsd. 6666 ohms

REVIEW QUESTIONSREVIEW QUESTIONS11. How much power does electronic equipment consume, assuming a

5.5A current flowing and a 120-V power source.a. 60 Wb. 66 Wc. 660 Wd. 125.5 W

12. How many nodes are needed to completely analyze a circuit according to Kirchoffs Current Law.a. Oneb. Two c. All nodes in the circuitd. One less than the total number of nodes in the circuit

11. How much power does electronic equipment consume, assuming a 5.5A current flowing and a 120-V power source.a. 60 Wb. 66 Wc. 660 Wd. 125.5 W

12. How many nodes are needed to completely analyze a circuit according to Kirchoffs Current Law.a. Oneb. Two c. All nodes in the circuitd. One less than the total number of nodes in the circuit

REVIEW QUESTIONSREVIEW QUESTIONS13. A common connection between circuit elements or conductors

from different branches.a. Nodeb. Junctionc. Groundd. Mesh

14. It is used to denote a common electrical point of zero potential.a. Short circuitb. Reference pointc. Open circuitd.ground

13. A common connection between circuit elements or conductors from different branches.a. Nodeb. Junctionc. Groundd. Mesh

14. It is used to denote a common electrical point of zero potential.a. Short circuitb. Reference pointc. Open circuitd.ground

REVIEW QUESTIONSREVIEW QUESTIONS15. Loop currents should be assumed to flow in which

direction?a. Straightb. Clockwisec. Counterclockwised. Either b or c

16. In mesh analysis, we apply:a. KCLb. KVLc. Sourced. Millman’s theorem

15. Loop currents should be assumed to flow in which direction?a. Straightb. Clockwisec. Counterclockwised. Either b or c

16. In mesh analysis, we apply:a. KCLb. KVLc. Sourced. Millman’s theorem

REVIEW QUESTIONSREVIEW QUESTIONS17. Which of the following is not a valid expression of Ohms Law

a. R = PIb. E = IRc. I = E/Rd. R = E/I

18. Using ohms Law, what happens to the circuit current if the applied voltage increases?a. Current doublesb. Current increasesc. Current remians constantd. Current decreases

17. Which of the following is not a valid expression of Ohms Lawa. R = PIb. E = IRc. I = E/Rd. R = E/I

18. Using ohms Law, what happens to the circuit current if the applied voltage increases?a. Current doublesb. Current increasesc. Current remians constantd. Current decreases

REVIEW QUESTIONSREVIEW QUESTIONS19. According to ohms law, what happen to the circuit current if the

circuit resistance increases?a. Current doublesb. Current decreasesc. Current increasesd. Current remains constant

20. If the resistance of a circuit is doubled and the applied voltage is kept constant, the current will be _______ .a. Be quaddrupledb. Remainsc. Be cut in halfd. Be doubled

19. According to ohms law, what happen to the circuit current if the circuit resistance increases?a. Current doublesb. Current decreasesc. Current increasesd. Current remains constant

20. If the resistance of a circuit is doubled and the applied voltage is kept constant, the current will be _______ .a. Be quaddrupledb. Remainsc. Be cut in halfd. Be doubled

REVIEW QUESTIONSREVIEW QUESTIONS21. It is an electrical current that flows in one direction only?

a. Normal currentb. Alternating currentc. Direct currentd. Eddy current

22. In Ohms Law, what is E/R?a. Amperageb. Voltagec. Resistanced. Power

21. It is an electrical current that flows in one direction only?a. Normal currentb. Alternating currentc. Direct currentd. Eddy current

22. In Ohms Law, what is E/R?a. Amperageb. Voltagec. Resistanced. Power

REVIEW QUESTIONSREVIEW QUESTIONS23. A 33-Kohm resistor is connected in series with a parallel

combination made up of 56-Kohm resistor and a 7.8-kohm resistor. What is the total combined reistance of the three resistors?a. 390667 ohmsb. 49069 ohmsc. 63769 ohmsd. 95000 ohms

24. Which of the following cannot be included in a loop of Kirchoff’s Volatage Lawa. Current sourceb. Voltage sourcec. Resistanced. Reactance

23. A 33-Kohm resistor is connected in series with a parallel combination made up of 56-Kohm resistor and a 7.8-kohm resistor. What is the total combined reistance of the three resistors?a. 390667 ohmsb. 49069 ohmsc. 63769 ohmsd. 95000 ohms

24. Which of the following cannot be included in a loop of Kirchoff’s Volatage Lawa. Current sourceb. Voltage sourcec. Resistanced. Reactance

REVIEW QUESTIONSREVIEW QUESTIONS25. A series connected circuit consists of 3 loads and consume a total power

of 50 Watts. It was reconfigured such that 2 are in parallel and the other load is in series with a combination. What is the applied expected powers to be consumed them?a. 50 wattsb. 25 wattsc. 75 wattsd. 45 watts

26. If the number of valence electrons of an atom is less than 4, the substance is usuallya. Semiconductorb. An insulatorc. A conductord. None of the above

25. A series connected circuit consists of 3 loads and consume a total power of 50 Watts. It was reconfigured such that 2 are in parallel and the other load is in series with a combination. What is the applied expected powers to be consumed them?a. 50 wattsb. 25 wattsc. 75 wattsd. 45 watts

26. If the number of valence electrons of an atom is less than 4, the substance is usuallya. Semiconductorb. An insulatorc. A conductord. None of the above

REVIEW QUESTIONSREVIEW QUESTIONS27. Electric current in a wire is the flow of

a. Free electronsb. Valence electronsc. Bound electronsd. Atoms

28. EMF in a circuit is a forma. Powerb. Energyc. Charged. none

27. Electric current in a wire is the flow ofa. Free electronsb. Valence electronsc. Bound electronsd. Atoms

28. EMF in a circuit is a forma. Powerb. Energyc. Charged. none

REVIEW QUESTIONSREVIEW QUESTIONS29. The SI unit of specific-resistance is

a. Mhob. Ohm-nc. Ohm-sq.-md. Ohm-cm

30. The resistance of a material is ___ its area of cross-sectiona. Directly proportionalb. Inversely proportionalc. Independentd. None of these

29. The SI unit of specific-resistance isa. Mhob. Ohm-nc. Ohm-sq.-md. Ohm-cm

30. The resistance of a material is ___ its area of cross-sectiona. Directly proportionalb. Inversely proportionalc. Independentd. None of these

REVIEW QUESTIONSREVIEW QUESTIONS31. The value of α, i.e., the temperarure coefficient of resistance

depends upon the ____ of the material.a. Lengthb. Volumec. X-sectional aread. Nature and temperature

32. The value of α of a conductor is 1/236 C. The value of a α is a. 1/218 Cb. 1/272 Cc. 1/254 Cd. 1/265 C

31. The value of α, i.e., the temperarure coefficient of resistance depends upon the ____ of the material.a. Lengthb. Volumec. X-sectional aread. Nature and temperature

32. The value of α of a conductor is 1/236 C. The value of a α is a. 1/218 Cb. 1/272 Cc. 1/254 Cd. 1/265 C

REVIEW QUESTIONSREVIEW QUESTIONS33. Electrical appliances are not connected in series because

a. Series circuit is complicatedb. Power loss is greaterc. Appliances have different current ratingd. None of these

34. Electrical appliances are connected in parallel because ita. Is a simple circuitb. Results in reduced power lossc. Draw less currentd. Makes the operation of the appliances independent from each other

33. Electrical appliances are not connected in series becausea. Series circuit is complicatedb. Power loss is greaterc. Appliances have different current ratingd. None of these

34. Electrical appliances are connected in parallel because ita. Is a simple circuitb. Results in reduced power lossc. Draw less currentd. Makes the operation of the appliances independent from each other

REVIEW QUESTIONSREVIEW QUESTIONS35. The hot resistance of a 100W, 250V incandecent lamp is

a. 2.5 ohmsb. 625 ohmsc. 25 ohmsd. None of these

36. When a number of resistances are connecte in parallel, the total resistance isa. Less than the smallest resistanceb. Greater than the smallest resistancec. Between the smallest and greater resistanced. None of these

35. The hot resistance of a 100W, 250V incandecent lamp isa. 2.5 ohmsb. 625 ohmsc. 25 ohmsd. None of these

36. When a number of resistances are connecte in parallel, the total resistance isa. Less than the smallest resistanceb. Greater than the smallest resistancec. Between the smallest and greater resistanced. None of these

REVIEW QUESTIONSREVIEW QUESTIONS37. If the resistances, each of value 36 ohms are connected in parallel,

the total resistance isa. 2 ohmsb. 54 ohmsc. 36 ohmsd. None of these

38. Two incandecent lamps of 100 W, 200V are in parallel across the 200 V. The total resistance will bea. 800 ohmsb. 200 ohmsc. 400 ohmsd. 600 ohms

37. If the resistances, each of value 36 ohms are connected in parallel, the total resistance isa. 2 ohmsb. 54 ohmsc. 36 ohmsd. None of these

38. Two incandecent lamps of 100 W, 200V are in parallel across the 200 V. The total resistance will bea. 800 ohmsb. 200 ohmsc. 400 ohmsd. 600 ohms

REVIEW QUESTIONSREVIEW QUESTIONS39. Three resistors are connected in parallel and draws 1A, 2.5A, and

3.5A, rspectively. If the applied voltage is 210V, what is the total resistance of the circuit?a. 5 ohmsb. 147 ohmsc. 3 ohmsd. 73.5 ohms

40. An ordinary dry cell can deliver about ____ continuously.a. 3 Ab. 2 Ac. 1/8 Ad. None of these

39. Three resistors are connected in parallel and draws 1A, 2.5A, and 3.5A, rspectively. If the applied voltage is 210V, what is the total resistance of the circuit?a. 5 ohmsb. 147 ohmsc. 3 ohmsd. 73.5 ohms

40. An ordinary dry cell can deliver about ____ continuously.a. 3 Ab. 2 Ac. 1/8 Ad. None of these

REVIEW QUESTIONSREVIEW QUESTIONS41. Four cells of internal resistance 1 ohms, are connected in parallel.

The battery resistance will bea. 4 ohmsb. 0.25 ohmsc. 2 ohmsd. 1 ohms

42. Of the following combination of units, the one that is not equal to the watt isa. Joule/secb. Ampere-voltc. Ampere-ohmd. Ohm/volt

41. Four cells of internal resistance 1 ohms, are connected in parallel. The battery resistance will bea. 4 ohmsb. 0.25 ohmsc. 2 ohmsd. 1 ohms

42. Of the following combination of units, the one that is not equal to the watt isa. Joule/secb. Ampere-voltc. Ampere-ohmd. Ohm/volt

REVIEW QUESTIONSREVIEW QUESTIONS43. The power dissipated in a circuit is not equal to

a. VIb. IRc. V/Rd. IR/V

44. An electric iron draws a current of 15A when connected to 120V power source. Its resistance isa. 0.125 ohmsb. 8 ohmsc. 16 ohmsd. 1,800 ohms

43. The power dissipated in a circuit is not equal toa. VIb. IRc. V/Rd. IR/V

44. An electric iron draws a current of 15A when connected to 120V power source. Its resistance isa. 0.125 ohmsb. 8 ohmsc. 16 ohmsd. 1,800 ohms

REVIEW QUESTIONSREVIEW QUESTIONS45. The power rating of an electric motor which draws a current of 3 A

when operated at 120 V isa. 40 Wb. 360 Wc. 540 Wd. 1,080 W

46. When a 100W, 240V, light bulb is operated at 200V, the current that flows in it isa. 0.35 Ab. 0.42 Ac. 0.5 Ad. 0.58 A

45. The power rating of an electric motor which draws a current of 3 A when operated at 120 V isa. 40 Wb. 360 Wc. 540 Wd. 1,080 W

46. When a 100W, 240V, light bulb is operated at 200V, the current that flows in it isa. 0.35 Ab. 0.42 Ac. 0.5 Ad. 0.58 A

REVIEW QUESTIONSREVIEW QUESTIONS47. The equivalent resistance of a network of three 2 ohm resistors

cannot bea. 0.67 ohmsb. 1.5 ohmsc. 3 ohmsd. 6 ohms

48. A 12V potential difference is applied across a series combination of four six-ohms resistors. The current in each six-ohm resistor will bea. 0.5 Ab. 2 Ac. 8 Ad. 6 A

47. The equivalent resistance of a network of three 2 ohm resistors cannot bea. 0.67 ohmsb. 1.5 ohmsc. 3 ohmsd. 6 ohms

48. A 12V potential difference is applied across a series combination of four six-ohms resistors. The current in each six-ohm resistor will bea. 0.5 Ab. 2 Ac. 8 Ad. 6 A

REVIEW QUESTIONSREVIEW QUESTIONS49. A 12V potential difference is applied across a parallel combination

of four six-ohms resistors. The current in each six-ohm resistor will be a. 0.5 Ab. 2 Ac. 8 Ad. 6 A

50. The dissipation of energy can cause burns because it proceducesa. Heatb. Firec. Frictiond. Overload

49. A 12V potential difference is applied across a parallel combination of four six-ohms resistors. The current in each six-ohm resistor will be a. 0.5 Ab. 2 Ac. 8 Ad. 6 A

50. The dissipation of energy can cause burns because it proceducesa. Heatb. Firec. Frictiond. Overload

REVIEW QUESTIONSREVIEW QUESTIONS51. The rate of expenditure of energy is

a. Voltageb. Powerc. Currentd. Energy

52. In a simple DC power line, the wire that carries the current from the generator to the load is calleda. Return wireb. Feederc. Outgoing wired. Conductor

51. The rate of expenditure of energy isa. Voltageb. Powerc. Currentd. Energy

52. In a simple DC power line, the wire that carries the current from the generator to the load is calleda. Return wireb. Feederc. Outgoing wired. Conductor

REVIEW QUESTIONSREVIEW QUESTIONS53. A circuit in which the resistance are connected in a continuous run,

i.e., end-to-end is a _____ circuit.a. Saries b. Parallelc. Series-paralleld. None of these

54. A battery is connected to an external circuit. The potential drop with the battery is proportional to a. The EMF of the batteryb. The current of the circuitc. The equivqlent circuit resistanced. Power dissipated in the circuit

53. A circuit in which the resistance are connected in a continuous run, i.e., end-to-end is a _____ circuit.a. Saries b. Parallelc. Series-paralleld. None of these

54. A battery is connected to an external circuit. The potential drop with the battery is proportional to a. The EMF of the batteryb. The current of the circuitc. The equivqlent circuit resistanced. Power dissipated in the circuit

REVIEW QUESTIONSREVIEW QUESTIONS55. Two wires A and B have the same cross-sectional area and are

made of the same material. Ra = 600 ohms and Rb = 100 ohms. The number of times A is longer tahn B isa. 6b. 2c. 4d. 5

56. A coil has a resistance of 100 ohms at 90 C. At 100 C, its resistance is 101 ohms. The temperature coefficient of the wire isa. 0.01b. 0.1c. 0.0001d. 0.001

55. Two wires A and B have the same cross-sectional area and are made of the same material. Ra = 600 ohms and Rb = 100 ohms. The number of times A is longer tahn B isa. 6b. 2c. 4d. 5

56. A coil has a resistance of 100 ohms at 90 C. At 100 C, its resistance is 101 ohms. The temperature coefficient of the wire isa. 0.01b. 0.1c. 0.0001d. 0.001

REVIEW QUESTIONSREVIEW QUESTIONS57. The resistance of a conductor does not depend on its

a. Resistivityb. Lengthc. Cross-sectiond. Mass

58. A material which has a negative temperature coefficient of resistance is usually a/ana. Insulatorb. Conductorc. Semi-conductord. All of these

57. The resistance of a conductor does not depend on itsa. Resistivityb. Lengthc. Cross-sectiond. Mass

58. A material which has a negative temperature coefficient of resistance is usually a/ana. Insulatorb. Conductorc. Semi-conductord. All of these

REVIEW QUESTIONSREVIEW QUESTIONS59. Which of the following statements is true both for a series

and a parallel dc circuit?a. Power additiveb. Current are additivec. Voltage are additived. All of these

60. Two resistors are said to be in series when a. Both carry the same value of currentb. Total current equals the sum of the branch currentc. Sum of IR drops equal to EMFd. Same current phases through both

59. Which of the following statements is true both for a series and a parallel dc circuit?a. Power additiveb. Current are additivec. Voltage are additived. All of these

60. Two resistors are said to be in series when a. Both carry the same value of currentb. Total current equals the sum of the branch currentc. Sum of IR drops equal to EMFd. Same current phases through both

REVIEW QUESTIONSREVIEW QUESTIONS61. According to KCL as applied to a juction in a network of

conductors.a. Total sum of currents meeting at the juction is Zerob. No current can leave the juction without same current passing throuhg itc. Net current flow at he juction is positived. Algebraic sum of the currents meeting at the juction is zero

62. Kirchoff’s Current Law is applicable only toa. Closed-loop circuitb. Electronic circuitsc. Juctions in a networkd. Electric circuit

61. According to KCL as applied to a juction in a network of conductors.a. Total sum of currents meeting at the juction is Zerob. No current can leave the juction without same current passing throuhg itc. Net current flow at he juction is positived. Algebraic sum of the currents meeting at the juction is zero

62. Kirchoff’s Current Law is applicable only toa. Closed-loop circuitb. Electronic circuitsc. Juctions in a networkd. Electric circuit

REVIEW QUESTIONSREVIEW QUESTIONS63. Kirchoff’s Voltage Las\w is concerned with

a. IR dropsb. Battery EMF’sc. Juction voltagesd. A and b

64. According to KVL, the algebraic sum of all IR drops and EMF’s in any closed loop of a network is alwaysa. Zerob. Negativec. Positived. Determined by battery EMF

63. Kirchoff’s Voltage Las\w is concerned witha. IR dropsb. Battery EMF’sc. Juction voltagesd. A and b

64. According to KVL, the algebraic sum of all IR drops and EMF’s in any closed loop of a network is alwaysa. Zerob. Negativec. Positived. Determined by battery EMF

REVIEW QUESTIONSREVIEW QUESTIONS65. The algebraic sign of an IR drops primarily dependent upon

a. The amount of current flowing through itb. Direction of currentc. The value of the resistanced. The battery connection

66. Choose the wrong statement. In the node voltage technique of solvingnetwork parameters, the choice of the reference node does not a. Affect the operation of the circuitb. Change the voltage across the element c. Alter the potential difference between any pair of nodesd. Affect the volatge of various nodes

65. The algebraic sign of an IR drops primarily dependent upona. The amount of current flowing through itb. Direction of currentc. The value of the resistanced. The battery connection

66. Choose the wrong statement. In the node voltage technique of solvingnetwork parameters, the choice of the reference node does not a. Affect the operation of the circuitb. Change the voltage across the element c. Alter the potential difference between any pair of nodesd. Affect the volatge of various nodes

REVIEW QUESTIONSREVIEW QUESTIONS67. The nodal analysis is primarily based on the application of

a. KVLb. KCL.c. Ohms Lawd. b and c

68. Superposition theorem can be applied only to circuits having ____ elementsa. Non-linearb. Passivec. Linear bilaterald. Resistive

67. The nodal analysis is primarily based on the application ofa. KVLb. KCL.c. Ohms Lawd. b and c

68. Superposition theorem can be applied only to circuits having ____ elementsa. Non-linearb. Passivec. Linear bilaterald. Resistive

REVIEW QUESTIONSREVIEW QUESTIONS69. The superposition theorem is essentially based on the

concept ofa. Reciprocityb. Linearityc. non-linearityd. Duality

70. What are the electrons in motion called?a. Current variationb. Electric currentc. Electron velocityd. Dynamic electricity

69. The superposition theorem is essentially based on the concept ofa. Reciprocityb. Linearityc. non-linearityd. Duality

70. What are the electrons in motion called?a. Current variationb. Electric currentc. Electron velocityd. Dynamic electricity

REVIEW QUESTIONSREVIEW QUESTIONS71. An active element in a circuit is one which _____ .

a. Receives energyb. Supplies energyc. a or bd. None of these

72. The siperposition theorem is used when the circuit containsa. A single voltage sourceb. A number of voltage sourcec. Passive element onlyd. None of these

71. An active element in a circuit is one which _____ .a. Receives energyb. Supplies energyc. a or bd. None of these

72. The siperposition theorem is used when the circuit containsa. A single voltage sourceb. A number of voltage sourcec. Passive element onlyd. None of these

REVIEW QUESTIONSREVIEW QUESTIONS73. Thevenin’s theorem is ____ form of equivalent circuit.

a. Voltageb. Currentc. Both a and bd. None of these

74. Norton’s theorem is ____ form of an equivalent circuit.a. Voltageb. Currentc. Both a and bd. None of these

73. Thevenin’s theorem is ____ form of equivalent circuit.a. Voltageb. Currentc. Both a and bd. None of these

74. Norton’s theorem is ____ form of an equivalent circuit.a. Voltageb. Currentc. Both a and bd. None of these

REVIEW QUESTIONSREVIEW QUESTIONS75. In the analysis of vacuum tube circuit, we can generally use ____

theorem.a. Norton’sb. Thevenin’sc. Superpositiond. Reciprocity

76. In the analysis of transistor circuits, we generally use _____ theorem.a. Voltageb. Currentc. Both a and bd. None of these

75. In the analysis of vacuum tube circuit, we can generally use ____ theorem.a. Norton’sb. Thevenin’sc. Superpositiond. Reciprocity

76. In the analysis of transistor circuits, we generally use _____ theorem.a. Voltageb. Currentc. Both a and bd. None of these

REVIEW QUESTIONSREVIEW QUESTIONS77. Under the condition of Maximum Power Transfer, the

efficiency isa. 75 %b. 100 %c. 50 %d. 25 %

78. The maximum power transfer theorem is used ina. Electronic circuitsb. Home lightningc. Power sytemd. None of the above

77. Under the condition of Maximum Power Transfer, the efficiency isa. 75 %b. 100 %c. 50 %d. 25 %

78. The maximum power transfer theorem is used ina. Electronic circuitsb. Home lightningc. Power sytemd. None of the above

REVIEW QUESTIONSREVIEW QUESTIONS79. delta/star or star/delta transformation technique is

applied toa. One terminalb. Two terminal c. Three terminald. None of these

80. _____ will be used under elctrostatics.a. Incandecent lampb. Electric motorc. Electric irond. Lightning rod

79. delta/star or star/delta transformation technique is applied toa. One terminalb. Two terminal c. Three terminald. None of these

80. _____ will be used under elctrostatics.a. Incandecent lampb. Electric motorc. Electric irond. Lightning rod

REVIEW QUESTIONSREVIEW QUESTIONS81. The value of the absulute permitivity of air is ______ F/m.

a. 9 x 10 b. 8,854 x 10 ^ -12c. 5 x 10d. 9 X 10

82. When two similar charges eaach of 1 coulumb each are placed 1m apart in air, then the force of repusion isa. 8 x10 Nb. 10 Nc. 9 x 10^9 Nd. 5 x 10 N

81. The value of the absulute permitivity of air is ______ F/m.a. 9 x 10 b. 8,854 x 10 ^ -12c. 5 x 10d. 9 X 10

82. When two similar charges eaach of 1 coulumb each are placed 1m apart in air, then the force of repusion isa. 8 x10 Nb. 10 Nc. 9 x 10^9 Nd. 5 x 10 N

REVIEW QUESTIONSREVIEW QUESTIONS83. Another name for dielectric strength is

a. Potetial gradientb. Breakdown voltagec. Dielectric constantd. Electric intensity

84. A heater connected to a 100 V supply, generates 10,000 J of heat energy is 10 sec. How much time is needed to generate the same amount of heat when it is used on 220V line?a. 5 secb. 2.5 secc. 7.5 secd. 4 sec.

83. Another name for dielectric strength isa. Potetial gradientb. Breakdown voltagec. Dielectric constantd. Electric intensity

84. A heater connected to a 100 V supply, generates 10,000 J of heat energy is 10 sec. How much time is needed to generate the same amount of heat when it is used on 220V line?a. 5 secb. 2.5 secc. 7.5 secd. 4 sec.

REVIEW QUESTIONSREVIEW QUESTIONS85. Kirchoff’s current law is applied in what type of circuit analysis?

a. Meshb. Thevenin’sc. Superpositiond. Nodal

86. Inductance and capacitance are not relevant in a dc circuit becausea. Frequency of DC is zerob. It is a simple circuitc. They do not exist in dc circuitd. None of the above

85. Kirchoff’s current law is applied in what type of circuit analysis?a. Meshb. Thevenin’sc. Superpositiond. Nodal

86. Inductance and capacitance are not relevant in a dc circuit becausea. Frequency of DC is zerob. It is a simple circuitc. They do not exist in dc circuitd. None of the above

REVIEW QUESTIONSREVIEW QUESTIONS87. Three resistors of 3 ohms resistance each are connected in

delta, the equivalent wye-connected resistors will bea. 1 ohmb. 3 ohmsc. 9 ohmsd. 0.111 ohm

88. Cells are conneted in series when _____ is requireda. High currentb. High voltagec. High powerd. All of these

87. Three resistors of 3 ohms resistance each are connected in delta, the equivalent wye-connected resistors will bea. 1 ohmb. 3 ohmsc. 9 ohmsd. 0.111 ohm

88. Cells are conneted in series when _____ is requireda. High currentb. High voltagec. High powerd. All of these

ALTERNATING CURRENTALTERNATING CURRENT

ALTERNATING CURRENT A current that is constantly changing in amplitude and

direction.

ALTERNATING CURRENT A current that is constantly changing in amplitude and

direction.

Advantages of AC: Magnitude can easily be changed (stepped-up or stepped down) with the use of a

transformer Can be produced either single phase for light loads, two phase for control motors,

three phase for power distribution and large motor loads or six phase for large scale AC to DC conversion.

Advantages of AC: Magnitude can easily be changed (stepped-up or stepped down) with the use of a

transformer Can be produced either single phase for light loads, two phase for control motors,

three phase for power distribution and large motor loads or six phase for large scale AC to DC conversion. BASIC AC THEORY

AC WAVEFORMSAC WAVEFORMS

BASIC AC THEORY


Period (T) – the time of one complete cycle in seconds Frequency (f) – the number of cycles per second (Hertz)

a. 1 cycle/second (cps) = 1 Hertz (Hz)b. Proper operation of electrical equipmnent requires specific frequencyc. Frequencies lower than 60 Hz would cause flicker when used in lightning

Wavelength (λ) – the length of one complete cycle Propagation Velocity (v) – the speed of the signal Phase (Φ) – an angilar measurement that specifies the position of a sine wave

relative to reference

Period (T) – the time of one complete cycle in seconds Frequency (f) – the number of cycles per second (Hertz)

a. 1 cycle/second (cps) = 1 Hertz (Hz)b. Proper operation of electrical equipmnent requires specific frequencyc. Frequencies lower than 60 Hz would cause flicker when used in lightning

Wavelength (λ) – the length of one complete cycle Propagation Velocity (v) – the speed of the signal Phase (Φ) – an angilar measurement that specifies the position of a sine wave

relative to reference

f = 1 T

λ = v f

Parameters of Alternating Signal

BASIC AC THEORY


THE SINUSOIDAL WAVE Is the most common AC waveform that is practically

generated by generators used in household and industries General equation for sine wave:

THE SINUSOIDAL WAVE Is the most common AC waveform that is practically

generated by generators used in household and industries General equation for sine wave:

Where:a(t) – instantaneous amplitude of voltage or current at a given time (t)Am – maximum voltage or current amplitude of the signal

ω – angular velocity in rad/sec; ω = 2πft – time (sec)Φ – phase shift ( + or – in degrees)

Where:a(t) – instantaneous amplitude of voltage or current at a given time (t)Am – maximum voltage or current amplitude of the signal

ω – angular velocity in rad/sec; ω = 2πft – time (sec)Φ – phase shift ( + or – in degrees)

A(t) = Am sin (ωt + Φ)

BASIC AC THEORY


PEAK AMPLITUDE – the height of an AC waveform as measured from the zero mark to the highest positive or lowest negative point on a graph. Also known as the crest amplitude of a wave.

PEAK AMPLITUDE – the height of an AC waveform as measured from the zero mark to the highest positive or lowest negative point on a graph. Also known as the crest amplitude of a wave.

AMPLITUDE It is the height of an AC waveform as depicted on a graph over time

(peak, peak-to-peak, average, or RMS quantity)

AMPLITUDE It is the height of an AC waveform as depicted on a graph over time

(peak, peak-to-peak, average, or RMS quantity)

Measurements of AC Magnitude

BASIC AC THEORY


PEAK-TO-PEAK AMPLITUDE – the total height of an AC waveform as measured from maximum positive to maximum negative peaks on a graph. Often abbreviated as “P-P”

PEAK-TO-PEAK AMPLITUDE – the total height of an AC waveform as measured from maximum positive to maximum negative peaks on a graph. Often abbreviated as “P-P”

BASIC AC THEORY


AVERAGE AMPLITUDE – the mathematical “mean” of all a waveform’s points over the period of one cycle. Technically, the average amplitude of any waveform with equal-area portions above and below the “zero” line on a graph is zero.

For a sine wave, the average value so calculated is approximately 0.637 of its peak value.

AVERAGE AMPLITUDE – the mathematical “mean” of all a waveform’s points over the period of one cycle. Technically, the average amplitude of any waveform with equal-area portions above and below the “zero” line on a graph is zero.

For a sine wave, the average value so calculated is approximately 0.637 of its peak value.

BASIC AC THEORY


RMS AMPLITUDE - “RMS” stands for Root Mean Square, and is a way of expressing an AC quantity of voltage or current in terms functionally equivalent to DC. Also known as the “equivalent” or “DC equivalent” value of an AC voltage or current.

For a sine wave, the RMS value is approximately 0.707 of its peak value.

RMS AMPLITUDE - “RMS” stands for Root Mean Square, and is a way of expressing an AC quantity of voltage or current in terms functionally equivalent to DC. Also known as the “equivalent” or “DC equivalent” value of an AC voltage or current.

For a sine wave, the RMS value is approximately 0.707 of its peak value.

BASIC AC THEORY


The crest factor of an AC waveform is the ratio of its peak (crest) to its RMS value.

The form factor of an AC waveform is the ratio of its RMS value to its average value.

The crest factor of an AC waveform is the ratio of its peak (crest) to its RMS value.

The form factor of an AC waveform is the ratio of its RMS value to its average value.

BASIC AC THEORY

AC QUANTITIESAC QUANTITIES

BASIC AC THEORY

AC QUANTITIESAC QUANTITIESInductive Reactance (XL)

• The property of the inductor to oppose the alternating current

Inductive Susceptance (BL)• Reciprocal of inductive reactance

Capacitive Reactance (XC)• The property of a capacitor to oppose alternating current

Capacitive Susceptance (BC)• Reciprocal of capacitive reactance

d

Inductive Reactance (XL)• The property of the inductor to oppose the alternating current

Inductive Susceptance (BL)• Reciprocal of inductive reactance

Capacitive Reactance (XC)• The property of a capacitor to oppose alternating current

Capacitive Susceptance (BC)• Reciprocal of capacitive reactance

d

XL = 2πfLXL = 2πfL

BL = 1 BL = 1 XL 2πfLBL = 1 BL = 1 XL 2πfL

XC = 1 2πfC

XC = 1 2πfC

BL = 1 BL = 2πfC XC BL = 1 BL = 2πfC XC

BASIC AC THEORY

AC QUANTITIESAC QUANTITIESIMPEDANCE (Z)

Total opposition to the flow of Alternating current Combination of the resistance in a circuit and the reactances

involved

IMPEDANCE (Z) Total opposition to the flow of Alternating current Combination of the resistance in a circuit and the reactances

involved

Z = R + jXeq Z = |Z| ∠φ

Where: |Z| = √ R2 + X2 φ = Arctan Xeq

R

Where: |Z| = √ R2 + X2 φ = Arctan Xeq

R

BASIC AC THEORY


If I = Im ∠β is the resulting current drawn by a passive, linear RLC circuit from a source voltage V = Vm ∠θ, then

Where: Z = Vm = √ R2 + X2 = magnitude of the impedance Imφ = θ – β = tan-1 X = phase angle of the impedance

RR = Zcos φ = active or real component of the impedance

X = Zsin φ = reactive or quadrature component of impedance

If I = Im ∠β is the resulting current drawn by a passive, linear RLC circuit from a source voltage V = Vm ∠θ, then

Where: Z = Vm = √ R2 + X2 = magnitude of the impedance Imφ = θ – β = tan-1 X = phase angle of the impedance

RR = Zcos φ = active or real component of the impedance

X = Zsin φ = reactive or quadrature component of impedance

Z = V = Vm ∠θ = Z ∠φ I Im ∠β

Z = V = Vm ∠θ = Z ∠φ I Im ∠β

Z cosφ + jZsin φ = R + jX = √ R2 + X2 ∠ tan-1 X RZ cosφ + jZsin φ = R + jX = √ R2 + X2 ∠ tan-1 X R

BASIC AC THEORY


ADMITTANCE (Y) The reciprocal of impedance Expressed in siemens or mho (S)

ADMITTANCE (Y) The reciprocal of impedance Expressed in siemens or mho (S)

Where: Y = Im = √ G2 + B2 = 1 = magnitude of the admittance Z

φy = β – θ = φ = tan-1 B = phase angle of the admittance G

G = Ycos φy = conductive/conductance component

B = Ysin φy = susceptive/susceptance component

Where: Y = Im = √ G2 + B2 = 1 = magnitude of the admittance Z

φy = β – θ = φ = tan-1 B = phase angle of the admittance G

G = Ycos φy = conductive/conductance component

B = Ysin φy = susceptive/susceptance component

Y = Im ∠ β – θ = Y = Ycos φy + jYsin φy = G + jB Vm

Y = Im ∠ β – θ = Y = Ycos φy + jYsin φy = G + jB Vm

Y = √ G2 + B2 ∠ tan-1 B G

Y = √ G2 + B2 ∠ tan-1 B G

BASIC AC THEORY

AC RESISTOR CIRCUITAC RESISTOR CIRCUIT

With an AC circuit like this which is purely resistive, the relationship of the voltage and current is as shown:

Voltage (e) is in phase with the current (i) Power is never a negative value. When the current is positive (above the line),

the voltage is also positive, resulting in a power (p=ie) of a positve value This consistent “polarity” of a power tell us that the resistor is always

dissipating power, taking it from the source and releasing it in the form of heat energy. Whether the current is negative or positive, a resistor still dissipated energy.

With an AC circuit like this which is purely resistive, the relationship of the voltage and current is as shown:

Voltage (e) is in phase with the current (i) Power is never a negative value. When the current is positive (above the line),

the voltage is also positive, resulting in a power (p=ie) of a positve value This consistent “polarity” of a power tell us that the resistor is always

dissipating power, taking it from the source and releasing it in the form of heat energy. Whether the current is negative or positive, a resistor still dissipated energy. AC CIRCUITS

Impedance (Z) = RImpedance (Z) = R

AC INDUCTOR CIRCUITAC INDUCTOR CIRCUIT

The most distinguishing electrical characteristics of an L circuit is that current lags voltage by 90 electrical degrees

Because the current and voltage waves arae 90o out of phase, there sre times when one is positive while the other is negative, resulting in equally frequent occurences of negative instantaneous power.

Negative power means that the inductor is releasing power back to the circuit, while a positive power means that it is absorbing power from the circuit.

The inductor releases just as much power back to the circuit as it absorbs over the span of a complete cycle.

The most distinguishing electrical characteristics of an L circuit is that current lags voltage by 90 electrical degrees

Because the current and voltage waves arae 90o out of phase, there sre times when one is positive while the other is negative, resulting in equally frequent occurences of negative instantaneous power.

Negative power means that the inductor is releasing power back to the circuit, while a positive power means that it is absorbing power from the circuit.

The inductor releases just as much power back to the circuit as it absorbs over the span of a complete cycle.

Impedance (Z) = jXLImpedance (Z) = jXL

AC CIRCUITS

AC INDUCTOR CIRCUITAC INDUCTOR CIRCUIT

o Inductive reactance is the opposition that an inductor offers to alternating current due to its phase-shifted storage and release of energy in its magnetic field. Reactance is symbolized by the capital letter “X” and is measured in ohms just like resistance (R).

o Inductive reactance can be calculated using this formula: XL = 2πfL

o The angular velocity of an AC circuit is another way of expressing its frequency, in units of electrical radians per second instead of cycles per second. It is symbolized by the lowercase Greek letter “omega,” or ω.

o Inductive reactance increases with increasing frequency. In other words, the higher the frequency, the more it opposes the AC flow of electrons.

o Inductive reactance is the opposition that an inductor offers to alternating current due to its phase-shifted storage and release of energy in its magnetic field. Reactance is symbolized by the capital letter “X” and is measured in ohms just like resistance (R).

o Inductive reactance can be calculated using this formula: XL = 2πfL

o The angular velocity of an AC circuit is another way of expressing its frequency, in units of electrical radians per second instead of cycles per second. It is symbolized by the lowercase Greek letter “omega,” or ω.

o Inductive reactance increases with increasing frequency. In other words, the higher the frequency, the more it opposes the AC flow of electrons.

AC CIRCUITS

AC CAPACITOR CIRCUITAC CAPACITOR CIRCUIT

The most distinguishing electrical characteristics of an C circuit is that leads the voltage by 90 electrical degrees

The current through a capacitor is a reaction against the change in voltage across it A capacitor’s opposition to change in voltage translates to an opposition to alternating

voltage in general, which is by definition always changing in instantaneous magnitude and direction. For any given magnitude of AC voltage at a given frequency, a capacitor of given size will “conduct” a certain magnitude of AC current.

The phase angle of a capacitor’s opposition to current is -90o,meaning that a capacitor’s opposition to current is a negative imaginary quantity

The most distinguishing electrical characteristics of an C circuit is that leads the voltage by 90 electrical degrees

The current through a capacitor is a reaction against the change in voltage across it A capacitor’s opposition to change in voltage translates to an opposition to alternating

voltage in general, which is by definition always changing in instantaneous magnitude and direction. For any given magnitude of AC voltage at a given frequency, a capacitor of given size will “conduct” a certain magnitude of AC current.

The phase angle of a capacitor’s opposition to current is -90o,meaning that a capacitor’s opposition to current is a negative imaginary quantity

Impedance (Z) = -jXCImpedance (Z) = -jXC

AC CIRCUITS

AC CAPACITOR CIRCUITAC CAPACITOR CIRCUIT

o Capacitive reactance is the opposition that a capacitor offers to alternating current due to its phase-shifted storage and release of energy in its electric field. Reactance is symbolized by the capital letter “X” and is measured in ohms just like resistance (R).

o Capacitive reactance can be calculated using this formula: XC = 1/(2πfC)

o Capacitive reactance decreases with increasing frequency. In other words, the higher the frequency, the less it opposes (the more it “conducts”) the AC flow of electrons.

o Capacitive reactance is the opposition that a capacitor offers to alternating current due to its phase-shifted storage and release of energy in its electric field. Reactance is symbolized by the capital letter “X” and is measured in ohms just like resistance (R).

o Capacitive reactance can be calculated using this formula: XC = 1/(2πfC)

o Capacitive reactance decreases with increasing frequency. In other words, the higher the frequency, the less it opposes (the more it “conducts”) the AC flow of electrons.

AC CIRCUITS

SERIES RESITOR-INDCUTOR CIRCUITSERIES RESITOR-INDCUTOR CIRCUIT

For a series resistor-inductor circuit, the voltage and current relation is determined in its phase shift. Thus, current lags voltage by a phase shift (θ)

For a series resistor-inductor circuit, the voltage and current relation is determined in its phase shift. Thus, current lags voltage by a phase shift (θ)

Impedance (Z) = R + jXLImpedance (Z) = R + jXL

Admittance (Y) = 1 = R – jXL

R + jXL R2 + jXL2

Admittance (Y) = 1 = R – jXL

R + jXL R2 + jXL2

AC CIRCUITS

SERIES RESITOR-INDCUTOR CIRCUITSERIES RESITOR-INDCUTOR CIRCUIT

o When resistors and inductors are mixed together in circuits, the total impedance will have a phase angle somewhere between 0o and +90o. The circuit current will have a phase angle somewhere between 0o and -90o. Series AC circuits exhibit the same fundamental properties as series DC circuits: current is uniform throughout.

o When resistors and inductors are mixed together in circuits, the total impedance will have a phase angle somewhere between 0o and +90o. The circuit current will have a phase angle somewhere between 0o and -90o. Series AC circuits exhibit the same fundamental properties as series DC circuits: current is uniform throughout.

Phase shift (θ) = Arctan ( XL ) |Z| = √ R2 + jXL2 = e

R i

Phase shift (θ) = Arctan ( XL ) |Z| = √ R2 + jXL2 = e

R i

AC CIRCUITS

SERIES RESISTOR-CAPACITOR CIRCUITSERIES RESISTOR-CAPACITOR CIRCUIT For a series resistor – capacitor circuit, the voltage and current relation is

determined by the phase shift. Thus the current leads the voltage by an angle less than 90 degrees but greater than 0 degrees.

For a series resistor – capacitor circuit, the voltage and current relation is determined by the phase shift. Thus the current leads the voltage by an angle less than 90 degrees but greater than 0 degrees.

Impedance (Z) = R – jXCImpedance (Z) = R – jXC

Admittance (Y) = 1 = R + jXC

R – jXC R2 + jXC2

Admittance (Y) = 1 = R + jXC

R – jXC R2 + jXC2

AC CIRCUITS

SERIES RESISTOR-CAPACITOR CIRCUITSERIES RESISTOR-CAPACITOR CIRCUIT

Phase shift (θ) = Arctan ( XC ) |Z| = √ R2 + jXC2 = e

R i

Phase shift (θ) = Arctan ( XC ) |Z| = √ R2 + jXC2 = e

R i

AC CIRCUITS

PARALLEL RESISTOR-INDUCTORPARALLEL RESISTOR-INDUCTOR

Y = G – jβL where: G – conductance = 1/R

βL – susceptance = 1/XL

Z = E , by Ohm’s Law I

The basic approachwith regarda to parallel circuits is using admittance because it is additive

Y = G – jβL where: G – conductance = 1/R

βL – susceptance = 1/XL

Z = E , by Ohm’s Law I

The basic approachwith regarda to parallel circuits is using admittance because it is additive AC CIRCUITS

PARALLEL RESISTOR-INDUCTORPARALLEL RESISTOR-INDUCTOR

o When resistors and inductors are mixed together in parallel circuits (just like in series cicuits), the total impedance will have a phase angle somewhere between 0o and +90o. The circuit current will have a phase angle somewhere between 0o and -90o.

o Parallel AC circuits exhibit the same fundamental properties as parallel DC circuits: voltage is uniform throughour the circuit, brach currents add to form the total current, and impedances diminish (through the reciprocal formula) to form the total impedance.

o When resistors and inductors are mixed together in parallel circuits (just like in series cicuits), the total impedance will have a phase angle somewhere between 0o and +90o. The circuit current will have a phase angle somewhere between 0o and -90o.

o Parallel AC circuits exhibit the same fundamental properties as parallel DC circuits: voltage is uniform throughour the circuit, brach currents add to form the total current, and impedances diminish (through the reciprocal formula) to form the total impedance.

AC CIRCUITS

PARALLEL RESISTOR-CAPACITORPARALLEL RESISTOR-CAPACITOR

Y = G + jβC where: G – conductance = 1/R

βC – susceptance = 1/XC

o When resistors and capacitors are mixxed together in circuits, the total impedance will have a phase angle somewhere between 0o and -90o.

Y = G + jβC where: G – conductance = 1/R

βC – susceptance = 1/XC

o When resistors and capacitors are mixxed together in circuits, the total impedance will have a phase angle somewhere between 0o and -90o.

AC CIRCUITS

APPARENT POWER (S)APPARENT POWER (S)

APPARENT POWER Represents the rate at which the total energy is supplied to the

system Measured in volt-amperes (VA) It has two components, the Real Power and the Capacitive or

Inductive Reactive Power

APPARENT POWER Represents the rate at which the total energy is supplied to the

system Measured in volt-amperes (VA) It has two components, the Real Power and the Capacitive or

Inductive Reactive Power

POWER IN AC CIRCUITS

S = Vrms Irms = Irms2 |Z|

APPARENT POWER (S)APPARENT POWER (S)

Power Triangle

Complex Power

S = P ± jQPOWER IN AC CIRCUITS

REAL POWER (R)REAL POWER (R)REAL POWER

The power consumed by the resistive component Also called True Power, Useful Power and Productive Power Measured in Watts (W) It is equal to the product of the apparent power and the power factor

REAL POWER The power consumed by the resistive component Also called True Power, Useful Power and Productive Power Measured in Watts (W) It is equal to the product of the apparent power and the power factor

Cosine of the power factor angle (θ) Measure of the power that is dissipated by the cicuit in relation to the

apparent power and is usually given as a decimal or percentage

Cosine of the power factor angle (θ) Measure of the power that is dissipated by the cicuit in relation to the

apparent power and is usually given as a decimal or percentage


Pf = cos θ

P = Scos θPower Factor

REAL POWER (R)REAL POWER (R) Ratio of the Real Power to the Apparent Power ( P )

Swhen:Pf = 1.0 I is in phase with V; resistive systemPf = lagging I lags V by θ; inductive systemPf = leading I leads V by θ; capacitive systemPf = 0.0 lag I lags V by 90o; purely inductivePf = 0.0 lead I leads V by 90o; purely capacitive

The angle between the apparent power and the real poweer in the power triangle

Let v(t) = Vm cos(ωt + θv) voltsV = Vrms ∠θv

i(t) = Im cos(ωt + θi) AI = Irms ∠θi

Ratio of the Real Power to the Apparent Power ( P ) S

when:Pf = 1.0 I is in phase with V; resistive systemPf = lagging I lags V by θ; inductive systemPf = leading I leads V by θ; capacitive systemPf = 0.0 lag I lags V by 90o; purely inductivePf = 0.0 lead I leads V by 90o; purely capacitive

The angle between the apparent power and the real poweer in the power triangle

Let v(t) = Vm cos(ωt + θv) voltsV = Vrms ∠θv

i(t) = Im cos(ωt + θi) AI = Irms ∠θi


Power factor Angle (θ)

REAL POWER (R)REAL POWER (R)

Where: θ = phase shfit between v(t) and i(t) or the phase angle of the equivalent impedanceWhere: θ = phase shfit between v(t) and i(t) or the phase angle of the equivalent impedance


Instantaneous Power (watts)

Average Power (watts)

P(t) = v(t) i(t)P(t) = v(t) i(t)

P(t) = ½ VmIm cos (θv – θi) + ½ VmIm cos (2ωt + θv + θi)P(t) = ½ VmIm cos (θv – θi) + ½ VmIm cos (2ωt + θv + θi)

P(t) = ½ VmIm cos (θv – θi) = VmIm cos θP(t) = ½ VmIm cos (θv – θi) = VmIm cos θ

REACTIVE POWER (QL or QC)REACTIVE POWER (QL or QC)

REACTIVE POWER Represents the rate at which energy is stored or released in any of the

energy storing elements (the inductor or the capacitor) Also called the imaginary power, non-productive or wattless power Measured in volt-ampere reactive (Var) When the capacitor and inductor are both present, the reactive power

associated with them take opposite signs since they do not store or release energy at the same time

It is positive for inductive power (QL) and negative for capacitive power (QC)

REACTIVE POWER Represents the rate at which energy is stored or released in any of the

energy storing elements (the inductor or the capacitor) Also called the imaginary power, non-productive or wattless power Measured in volt-ampere reactive (Var) When the capacitor and inductor are both present, the reactive power

associated with them take opposite signs since they do not store or release energy at the same time

It is positive for inductive power (QL) and negative for capacitive power (QC)

Ratio of the Reactive Power to the Apparent Power Sine of the power factor angle (θ)

Ratio of the Reactive Power to the Apparent Power Sine of the power factor angle (θ)


Q = VmIm sin θQ = VmIm sin θ

Reactive factor

Rf = sin θRf = sin θ

BALANCED THREE PHASE SYSTEMSBALANCED THREE PHASE SYSTEMSBALANCED 3-PHASE SYSTEM

Comprises of three identical single-phase systems operating at a 120o phase displacement from one another. This means that a balance three-phase system provides three voltages(and currents) that are equal in magnitude and separated by 120o from each other

BALANCED 3-PHASE SYSTEM Comprises of three identical single-phase systems operating at a 120o

phase displacement from one another. This means that a balance three-phase system provides three voltages(and currents) that are equal in magnitude and separated by 120o from each other

Three-Phase, 3-wire systems Provide only one type of voltage(line to line) both single phase and

three phase loads

Three-Phase, 4-wire systems Provide two types of voltages(line to line and line to neutral) to both

single phase and three phase loads

Three-Phase, 3-wire systems Provide only one type of voltage(line to line) both single phase and

three phase loads

Three-Phase, 4-wire systems Provide two types of voltages(line to line and line to neutral) to both

single phase and three phase loads

BALANCED THREE PHASE SYSTEM

CLASSIFICATION

BALANCED THREE PHASE SYSTEMSBALANCED THREE PHASE SYSTEMS

and

VLL and VLN are out of phase by 30o

and

VLL and VLN are out of phase by 30o

BALANCED Y-system

VLL = √3 VLNVLL = √3 VLN IL = IPIL = IP

and

IL and IP are out of phase by 30o

Where: VLL or VL - line to line or line voltage VLN or VP - line to neutral or phase voltage IL - line current IP - phase current

and

IL and IP are out of phase by 30o

Where: VLL or VL - line to line or line voltage VLN or VP - line to neutral or phase voltage IL - line current IP - phase current

BALANCED ∆-system

IL = √3 IPIL = √3 IP VLL = VLNVLL = VLN


ALTERNATING CURRENTALTERNATING CURRENT

VJH

watts vars va

VJH

watts vars va


Note: for balanced 3-phase systems:Note: for balanced 3-phase systems:

IA + IB + IC = 0IA + IB + IC = 0

VAN + VBN + VCN = 0VAN + VBN + VCN = 0

VAB + VBC + VCA = 0VAB + VBC + VCA = 0

P = 3VPIPcos θ = √3 VLIL cos θP = 3VPIPcos θ = √3 VLIL cos θ

Q = 3VPIPsin θ = √3 VLIL sin θQ = 3VPIPsin θ = √3 VLIL sin θ

S = 3VPIP = √3 VLILS = 3VPIP = √3 VLIL

THREE-PHASE POWER

REVIEW QUESTIONSREVIEW QUESTIONS1. The description of two sine waves that are in step with each other

going through their maximum and minimum points ate the same time and in the same direction.

a. Sine waves in phaseb. Stepped sine wavesc. Phased sine wavesd. Sine waves in coordination

2. Term used for the out of phase, non-productive power associated with inductors and capacitors.a. Effective powerb. True powerc. Reactive powerd. Peak envelope power

1. The description of two sine waves that are in step with each other going through their maximum and minimum points ate the same time and in the same direction.

a. Sine waves in phaseb. Stepped sine wavesc. Phased sine wavesd. Sine waves in coordination

2. Term used for the out of phase, non-productive power associated with inductors and capacitors.a. Effective powerb. True powerc. Reactive powerd. Peak envelope power

3. Refers to a reactive power.a. Wattles, non productive powerb. Power consumed in circuit Qc. Power loss because of capacitor leakaged. Power consumed in wire resistance in an inductor

4. Term used for an out-of-phase, non-productive power associated with inductors and capacitors.a. Effective powerb. Reactive powerc. Peak envelope powerd. True power

3. Refers to a reactive power.a. Wattles, non productive powerb. Power consumed in circuit Qc. Power loss because of capacitor leakaged. Power consumed in wire resistance in an inductor

4. Term used for an out-of-phase, non-productive power associated with inductors and capacitors.a. Effective powerb. Reactive powerc. Peak envelope powerd. True power

REVIEW QUESTIONSREVIEW QUESTIONS

5. The product of current and voltage in an AC circuit refers to thea. Real powerb. Useful powerc. Apparent powerd. DC power

6. The distance covered or traveled by a waveform during the time interval of one complete cycle.a. Frequencyb. Wavelengthc. Time slotd. Wave time

5. The product of current and voltage in an AC circuit refers to thea. Real powerb. Useful powerc. Apparent powerd. DC power

6. The distance covered or traveled by a waveform during the time interval of one complete cycle.a. Frequencyb. Wavelengthc. Time slotd. Wave time


7. The power dissipated accross the resistance in an AC circuit.a. Real powerb. Reactive powerc. Apparent powerd. True power

8. It is the number of complete cycles of alternating voltage or current complete each seconda. Periodb. Frequencyc. Amplituded. Phase

7. The power dissipated accross the resistance in an AC circuit.a. Real powerb. Reactive powerc. Apparent powerd. True power

8. It is the number of complete cycles of alternating voltage or current complete each seconda. Periodb. Frequencyc. Amplituded. Phase


9. How many degrees are there in one complete cycle?a. 720 degb. 360 degc. 180 degd. 90 deg

10. The impedance in the study of electronics is represented by resistance and ___ .a. Reactanceb. Inductance and capacitancec. Inductanced. capacitance

9. How many degrees are there in one complete cycle?a. 720 degb. 360 degc. 180 degd. 90 deg

10. The impedance in the study of electronics is represented by resistance and ___ .a. Reactanceb. Inductance and capacitancec. Inductanced. capacitance


11. It is the current that is eliminated by a synchro capacitor?a. Magnetizing statorb. Lossc. Statord. Rotor

12. It is a rotaing sector that represent either current or voltage in an AC circuit.a. Resistanceb. Phasorc. Solar diagramd. velocity

11. It is the current that is eliminated by a synchro capacitor?a. Magnetizing statorb. Lossc. Statord. Rotor

12. It is a rotaing sector that represent either current or voltage in an AC circuit.a. Resistanceb. Phasorc. Solar diagramd. velocity


13. The relationship of the voltage accros an inductor to its current is described asa. Leading the current by 90 degb. Lagging the current by 90 degc. Leading the current by 180 degd. In phase with the current

14. Find the phase angle between the voltage across through the cicuit when Xc is 25ohms, R is 100 ohms and XL is 50 ohms.a. 76 deg with the voltage leading the currentb. 24 deg with the voltage lagging the currentc. 14 deg with the voltage lagging the currentd. 76 deg with the voltage lagging the current

13. The relationship of the voltage accros an inductor to its current is described asa. Leading the current by 90 degb. Lagging the current by 90 degc. Leading the current by 180 degd. In phase with the current

14. Find the phase angle between the voltage across through the cicuit when Xc is 25ohms, R is 100 ohms and XL is 50 ohms.a. 76 deg with the voltage leading the currentb. 24 deg with the voltage lagging the currentc. 14 deg with the voltage lagging the currentd. 76 deg with the voltage lagging the current


15. Calculate the period of an alternating current having a equation of I=20sin 120πta. 4.167 msb. 8.33 msc. 16.67 msd. 33.33 ms

16. What do you mean by root-mean-square (rms) value?a. It is the average valueb. It is the effective valuec. It is the value that causes the same heating effect as the DC voltaged. b or c

15. Calculate the period of an alternating current having a equation of I=20sin 120πta. 4.167 msb. 8.33 msc. 16.67 msd. 33.33 ms

16. What do you mean by root-mean-square (rms) value?a. It is the average valueb. It is the effective valuec. It is the value that causes the same heating effect as the DC voltaged. b or c


17. The maximum instances value of a vrying current, voltage or power equal to 1.414 times the effective value of a sine wave.a. RMS valueb. Peak valuec. Effective valued. Peak to Peak value

18. If an AC signal has a peak voltage of 55V, what is the average value?a. 34.98 Vb. 61.05Vc. 86.34 Vd. 38.89 V

17. The maximum instances value of a vrying current, voltage or power equal to 1.414 times the effective value of a sine wave.a. RMS valueb. Peak valuec. Effective valued. Peak to Peak value

18. If an AC signal has a peak voltage of 55V, what is the average value?a. 34.98 Vb. 61.05Vc. 86.34 Vd. 38.89 V


19. If an AC signal has an average voltage of 18V, what is the rms voltage?a. 12.726 Vb. 19.980 Vc. 25.380 Vd. 16.213 V

20. A 220-V, 60Hz is driving a series RL circuit. Determine the current if R=100 ohms and 20 mH inductancea. 2.2 A (lagging)b. 2.0 A (lagging)c. 2.2 A (leading)d. 2.0 A (leading)

19. If an AC signal has an average voltage of 18V, what is the rms voltage?a. 12.726 Vb. 19.980 Vc. 25.380 Vd. 16.213 V

20. A 220-V, 60Hz is driving a series RL circuit. Determine the current if R=100 ohms and 20 mH inductancea. 2.2 A (lagging)b. 2.0 A (lagging)c. 2.2 A (leading)d. 2.0 A (leading)


21. Ignoring any inductive effects, what is the impedance of RC series capacitor made up of a 56K ohm resistor and a 0.33uF capacitor at a signal frequency of 4650 Hz.a. 66730 ohmsb. 57019 ohmsc. 45270 ohmsd. 10730 ohms

22.What is the time constant of a 500mH coil and a 3300 ohm resistor in series?a. 0.00015 secb. 6.6 secc. 0.0015 secd. 0.0000015 sec

21. Ignoring any inductive effects, what is the impedance of RC series capacitor made up of a 56K ohm resistor and a 0.33uF capacitor at a signal frequency of 4650 Hz.a. 66730 ohmsb. 57019 ohmsc. 45270 ohmsd. 10730 ohms

22.What is the time constant of a 500mH coil and a 3300 ohm resistor in series?a. 0.00015 secb. 6.6 secc. 0.0015 secd. 0.0000015 sec


23. What is the realtionship between frequency and the value of XC ?

a. Frequency has no effectb. XC varies inversely with frequencyc. XC varies indirectly with frequencyd. XC varies directly with frequency

24. The reactance of a 25mH coil at 5000Hz which of the following?a. 785 ohmsb. 785000 ohmsc. 13 ohmsd. 0.0012 ohms

23. What is the realtionship between frequency and the value of XC ?

a. Frequency has no effectb. XC varies inversely with frequencyc. XC varies indirectly with frequencyd. XC varies directly with frequency

24. The reactance of a 25mH coil at 5000Hz which of the following?a. 785 ohmsb. 785000 ohmsc. 13 ohmsd. 0.0012 ohms


25. There are no transients in pure resistive circuites becaus theya. Offer high resistanceb. Obey ohm’s Lawc. Are linear circuitsd. Have no stored energy

26. The reciprocal of capacitance is called a. Elastanceb. Conductancec. Permitivityd. permeability

25. There are no transients in pure resistive circuites becaus theya. Offer high resistanceb. Obey ohm’s Lawc. Are linear circuitsd. Have no stored energy

26. The reciprocal of capacitance is called a. Elastanceb. Conductancec. Permitivityd. permeability


REVIEW QUESTIONSREVIEW QUESTIONS27. The AC system is prefered over DC system because

a. Ac voltages can easily changed in amgnitudeb. Dc motors do not have fine speed controlc. High voltage AC transmission is less efficientd. DC voltage cannot be used for domestic aplliences

28. An altenating voltage is given by v = 20 sin 157 t. The frequency of the alternating voltage isa. 50 Hzb. 25 HZc. 100 Hzd. 75 Hz

27. The AC system is prefered over DC system becausea. Ac voltages can easily changed in amgnitudeb. Dc motors do not have fine speed controlc. High voltage AC transmission is less efficientd. DC voltage cannot be used for domestic aplliences

28. An altenating voltage is given by v = 20 sin 157 t. The frequency of the alternating voltage isa. 50 Hzb. 25 HZc. 100 Hzd. 75 Hz

REVIEW QUESTIONSREVIEW QUESTIONS29. An alternating current given by i = 10 sin 314 t. The time taken to

generate two cycles of current isa. 20 msb. 10 msc. 40 msd. 50 ms

30. In a pure resistive circuit, the instantaneous voltage and are current are given by:v=250 sin 314t i=10sin314t

The peak power in the circuit isa.1250 Wb. 25 Wc. 2500 Wd. 250 w

29. An alternating current given by i = 10 sin 314 t. The time taken to generate two cycles of current isa. 20 msb. 10 msc. 40 msd. 50 ms

30. In a pure resistive circuit, the instantaneous voltage and are current are given by:v=250 sin 314t i=10sin314t

The peak power in the circuit isa.1250 Wb. 25 Wc. 2500 Wd. 250 w

REVIEW QUESTIONSREVIEW QUESTIONS31. An average value of 6.63 A is _____ the effective value of 7.07 A.

a. The same areab. Less thanc. Greater than d. Any of these

32. In an R-L series circuit, the resistance is 10 ohms and the inductive reactance is 10 ohms. The phase angle between the applied voltage and circuit current will bea. 45 degb. 30 degc. 60 degd. 36.8 deg

31. An average value of 6.63 A is _____ the effective value of 7.07 A.a. The same areab. Less thanc. Greater than d. Any of these

32. In an R-L series circuit, the resistance is 10 ohms and the inductive reactance is 10 ohms. The phase angle between the applied voltage and circuit current will bea. 45 degb. 30 degc. 60 degd. 36.8 deg

REVIEW QUESTIONSREVIEW QUESTIONS33.An R-L series ac circuit has 15V across the resistor and 20V across

the inductor. The supply volatge isa. 35 Vb. 5 Vc. 25 Vd. 175 V

34. The active and reactive powers of an inductive circuit are equal. The power factor of the circuit isa. 0.8 lagging b. 0.707 laggingc. 0.6 laggingd. 0.5 lagging

33.An R-L series ac circuit has 15V across the resistor and 20V across the inductor. The supply volatge isa. 35 Vb. 5 Vc. 25 Vd. 175 V

34. The active and reactive powers of an inductive circuit are equal. The power factor of the circuit isa. 0.8 lagging b. 0.707 laggingc. 0.6 laggingd. 0.5 lagging

REVIEW QUESTIONSREVIEW QUESTIONS35. A circuit when connected to 200V mains takes a current of 20 A, leading

the voltage by one-twelfth of time period. The circuit resistance isa. 10 ohmsb. 8.66 ohmsc. 20 ohmsd. 17.32 ohms

36. An AC circuit has a resistance of 6 ohms, inductive reactance of 20 ohms, and capacitive reactance of 12 ohms. The circuit power will bea. 0.8 laggingb. 0.8 leadingc. 0.6 laggingd. 0.6 leading

35. A circuit when connected to 200V mains takes a current of 20 A, leading the voltage by one-twelfth of time period. The circuit resistance isa. 10 ohmsb. 8.66 ohmsc. 20 ohmsd. 17.32 ohms

36. An AC circuit has a resistance of 6 ohms, inductive reactance of 20 ohms, and capacitive reactance of 12 ohms. The circuit power will bea. 0.8 laggingb. 0.8 leadingc. 0.6 laggingd. 0.6 leading

REVIEW QUESTIONSREVIEW QUESTIONS37. An alternating voltage of 80 + j60 V is applied to a circuit and the

current flowing is -40 + j10 A. Find the phase angle.a. 25 degb. 50 degc. 75 degd. 100 deg

38. A current wave is represented by the equation i = 10 sin 251t. The average and RMS value of current area. 7.07 A; 6.63Ab. 6.36A; 7.07Ac. 10A; 7.07Ad. 6.36A; 10A

37. An alternating voltage of 80 + j60 V is applied to a circuit and the current flowing is -40 + j10 A. Find the phase angle.a. 25 degb. 50 degc. 75 degd. 100 deg

38. A current wave is represented by the equation i = 10 sin 251t. The average and RMS value of current area. 7.07 A; 6.63Ab. 6.36A; 7.07Ac. 10A; 7.07Ad. 6.36A; 10A

REVIEW QUESTIONSREVIEW QUESTIONS39. Calculate the susceptance in mho of a circuit consisting of resistor of 10

ohms in series with a conductor of 0.1H, when the frequency is 50Hz.a. 0.0303b. 0.0092c. -0.029d. 32.95

40. An inductive circuit of resistance 16.5 ohms and inductive of 0.14H takes a current of 25 A. If the frequency is 50Hz, the supply voltage isa. 117.4 Vb. 1174 Vc. 1714 Vd. 1471 V

39. Calculate the susceptance in mho of a circuit consisting of resistor of 10 ohms in series with a conductor of 0.1H, when the frequency is 50Hz.a. 0.0303b. 0.0092c. -0.029d. 32.95

40. An inductive circuit of resistance 16.5 ohms and inductive of 0.14H takes a current of 25 A. If the frequency is 50Hz, the supply voltage isa. 117.4 Vb. 1174 Vc. 1714 Vd. 1471 V

REVIEW QUESTIONSREVIEW QUESTIONS41. The current taken by a circuit is 1.2 A when the applied potential

difference is 250 V and the power taken is 135W. The power factor isa. 0.35b. 0.45c. 0.55d. 0.65

42. A capacitor has a capacitance of 20uF. The current supplied if it is placed across a 1100 V, 25 Hz supply.a. 3.554 Ab. 6.91 Ac. 3.45 Ad. 9.61 A

41. The current taken by a circuit is 1.2 A when the applied potential difference is 250 V and the power taken is 135W. The power factor isa. 0.35b. 0.45c. 0.55d. 0.65

42. A capacitor has a capacitance of 20uF. The current supplied if it is placed across a 1100 V, 25 Hz supply.a. 3.554 Ab. 6.91 Ac. 3.45 Ad. 9.61 A

REVIEW QUESTIONSREVIEW QUESTIONS43. A non-inductive load takes a 100A at 100V. Calculate the inductance of

the inductor to be connected in series in order that the same current is supplied from 220 V, 50 Hz mains.a. 1.96 ohmsb. 6.91 ohmsc. 19.6 ohmsd. 9.61 ohms

44. An inductor having negligible resistance and an inductance of 0.07H is connected in series with a resiostor of 20 ohms resitance across a 200, 50 Hz supply. The maximum energy stored in the coil isa. 3.175 Jb. 1.585 Jc. 0.236 Jd. 0.33 J

43. A non-inductive load takes a 100A at 100V. Calculate the inductance of the inductor to be connected in series in order that the same current is supplied from 220 V, 50 Hz mains.a. 1.96 ohmsb. 6.91 ohmsc. 19.6 ohmsd. 9.61 ohms

44. An inductor having negligible resistance and an inductance of 0.07H is connected in series with a resiostor of 20 ohms resitance across a 200, 50 Hz supply. The maximum energy stored in the coil isa. 3.175 Jb. 1.585 Jc. 0.236 Jd. 0.33 J

REVIEW QUESTIONSREVIEW QUESTIONS45. A coil has 1200 turns and procedures 100 uWb mwhen the current

flowing is 1A. The inductance of the coil isa. 0.21 Hb. 0.12 Hc. 0.31 Hd. 0.41 H

46. A capacitor connected to a 115 V, 25 Hz supply takes 5 A. What current will it take when the capacitance and frequency are doubled?a. 2 Ab. 5 Sc. 10 Ad. 20 A

45. A coil has 1200 turns and procedures 100 uWb mwhen the current flowing is 1A. The inductance of the coil isa. 0.21 Hb. 0.12 Hc. 0.31 Hd. 0.41 H

46. A capacitor connected to a 115 V, 25 Hz supply takes 5 A. What current will it take when the capacitance and frequency are doubled?a. 2 Ab. 5 Sc. 10 Ad. 20 A

REVIEW QUESTIONSREVIEW QUESTIONS47. A resistor of 20 ohms is connected in parallel with a capacitor across a

110 V, 40 Hz supply. If the current taken is 6A, what is the capacitance?a. 88.6 uFb. 68.8 uFc. 86.8 uFd. 76.8 uF

48. What capacitance must be placed in series with an inductance of 0.05H, so that when the frequency is 100 Hz, the impedance becomes equal to the ohmic resitance?a. 70.5 uFb. 50.7 uFc. 5.7 uFd. 7.05 uF

47. A resistor of 20 ohms is connected in parallel with a capacitor across a 110 V, 40 Hz supply. If the current taken is 6A, what is the capacitance?a. 88.6 uFb. 68.8 uFc. 86.8 uFd. 76.8 uF

48. What capacitance must be placed in series with an inductance of 0.05H, so that when the frequency is 100 Hz, the impedance becomes equal to the ohmic resitance?a. 70.5 uFb. 50.7 uFc. 5.7 uFd. 7.05 uF

REVIEW QUESTIONSREVIEW QUESTIONS49. A reactance of 20 ohms and inductance of 0.1 H is connected in

parallel with a capacitor. The capacitance of the capacitor required to produce a resonance when connected to a 100V, 50 Hz isa. 71.2 uFb. 1.277 uFc. 17.2 uFd. 72.1 uF

50. What is the resonant frequency of a circuit when an inductance of 1uH and capacitance of 10 picofarad are in series?a. 15.9 MHzb. 50.3 MHzc. 15.9 kHzd. 50.3 KHz

49. A reactance of 20 ohms and inductance of 0.1 H is connected in parallel with a capacitor. The capacitance of the capacitor required to produce a resonance when connected to a 100V, 50 Hz isa. 71.2 uFb. 1.277 uFc. 17.2 uFd. 72.1 uF

50. What is the resonant frequency of a circuit when an inductance of 1uH and capacitance of 10 picofarad are in series?a. 15.9 MHzb. 50.3 MHzc. 15.9 kHzd. 50.3 KHz

REVIEW QUESTIONSREVIEW QUESTIONS51. The _____ the Q of a circuit, the narrower the bandwidth.

a. Lowerb. Higherc. Broaderd. Selective

52. Find the half power bandwidth of a parallel resonant circuit which has a resonant frequency of 3.6MHz and Q of 218.a. 606 kHzb. 58.7 kHzc. 16.5 kHzd. 47.3 kHz

51. The _____ the Q of a circuit, the narrower the bandwidth.a. Lowerb. Higherc. Broaderd. Selective

52. Find the half power bandwidth of a parallel resonant circuit which has a resonant frequency of 3.6MHz and Q of 218.a. 606 kHzb. 58.7 kHzc. 16.5 kHzd. 47.3 kHz

REVIEW QUESTIONSREVIEW QUESTIONS53. At series resonance _____ .

a. Circuit impedance is very largeb. Cicuit power factor is minimumc. Voltage across L or C is zerod. Circuit power factor is unity

54. At series resonance, the voltage across the inductor isa. Equal to the applied voltageb. Much more than the apllied voltagec. Equal to voltage across Rd. Less than the applied voltage

53. At series resonance _____ .a. Circuit impedance is very largeb. Cicuit power factor is minimumc. Voltage across L or C is zerod. Circuit power factor is unity

54. At series resonance, the voltage across the inductor isa. Equal to the applied voltageb. Much more than the apllied voltagec. Equal to voltage across Rd. Less than the applied voltage

REVIEW QUESTIONSREVIEW QUESTIONS55. The Q factor of the coil is _____ the resistance of the coil.

a. Inversely proportional tob. Directly proportional toc. Independent ofd. None of these

56. An RLC circuit is connected is connected to 200V AC source. If Q factor of the coil is 10, then the voltage across the capacitor at resonance isa. 200 Vb. 2000 Vc. 20 Vd. 210 V

55. The Q factor of the coil is _____ the resistance of the coil.a. Inversely proportional tob. Directly proportional toc. Independent ofd. None of these

56. An RLC circuit is connected is connected to 200V AC source. If Q factor of the coil is 10, then the voltage across the capacitor at resonance isa. 200 Vb. 2000 Vc. 20 Vd. 210 V

REVIEW QUESTIONSREVIEW QUESTIONS57. At parallel resonance

a. Circuit impedance is minimumb. Power factor is zeroc. Line current is maximumd. Power factor is unity

58. The dynamic impedance of parallel resonant circuit is 1 Mohms. If the capacitance is 1uF, and the resistance is 1ohm, then the value of the inductancea. 1 Hb. 10 Hc. 10 pHd. 10 uH

57. At parallel resonancea. Circuit impedance is minimumb. Power factor is zeroc. Line current is maximumd. Power factor is unity

58. The dynamic impedance of parallel resonant circuit is 1 Mohms. If the capacitance is 1uF, and the resistance is 1ohm, then the value of the inductancea. 1 Hb. 10 Hc. 10 pHd. 10 uH

REVIEW QUESTIONSREVIEW QUESTIONS59. When supply frequency is less than the resonant frequency in a

parallel ac circuit, then the circuit isa. Resistiveb. Capacitivec. Inductived. None of these

60. At parallel resonance, the circuit drwas a current of 2mA. If the Q of the circuit is 100, then the current through the capacitor isa. 2 mAb. 1 mAc. 200 mAd. None of these

59. When supply frequency is less than the resonant frequency in a parallel ac circuit, then the circuit isa. Resistiveb. Capacitivec. Inductived. None of these

60. At parallel resonance, the circuit drwas a current of 2mA. If the Q of the circuit is 100, then the current through the capacitor isa. 2 mAb. 1 mAc. 200 mAd. None of these

REVIEW QUESTIONSREVIEW QUESTIONS61. A circuit has an impedance of (1-j2) ohms. The susceptance of the

circuit in mho isa. 0.1 b. 0.2c. 0.4d. None of these

62. If the admittance of a parallel ac circuit increased, the circuit currenta. Remains constantb. Is increasedc. Is decreasedd. None of these

61. A circuit has an impedance of (1-j2) ohms. The susceptance of the circuit in mho isa. 0.1 b. 0.2c. 0.4d. None of these

62. If the admittance of a parallel ac circuit increased, the circuit currenta. Remains constantb. Is increasedc. Is decreasedd. None of these

REVIEW QUESTIONSREVIEW QUESTIONS63. The resistance between any pair two terminals of a balanced wye-

connected load is 12 ohms.a. 6 ohmsb. 18 ohmsc. 24 ohmsd. None of these

64. If an AC circuit contains three nodes, the number of each mesh equations that can be formulated isa. 1b. 2c. 3d. 4

63. The resistance between any pair two terminals of a balanced wye-connected load is 12 ohms.a. 6 ohmsb. 18 ohmsc. 24 ohmsd. None of these

64. If an AC circuit contains three nodes, the number of each mesh equations that can be formulated isa. 1b. 2c. 3d. 4


65. The relation of the voltage across an inductor to its current is describe asa. Leading the current by 90 degb. Lagging the current by 90 degc. Leading the current by 180 degd. In phase with the current

65. The relation of the voltage across an inductor to its current is describe asa. Leading the current by 90 degb. Lagging the current by 90 degc. Leading the current by 180 degd. In phase with the current

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