CIRCUITSParametersThe various elements of an electric circuit, like resistance, inductance, and capacitance which may be lumped or distibuted.

CIRCUITSA closed conducting path through which an electric current flows or is intended to flow

CIRCUITS

Linear CircuitIs one whose parameters are constant (i.e. They do not change with voltage and current.Non-Linear CircuitIs that circuit whose parameters change with voltage and current.Bilateral CircuitIs one whose properties or characteristics are the same in either direction.Unilateral CircuitIs that circuit whose properties or characteristics change with the direction of its operation.

ELECTRICAL NETWORKS

Passive NetworkWith no source of emf.Active NetworkContains one or more than one sources of emf.ELECTRICAL NETWORKConnection of various electric elements in any manner

ELECTRICAL NETWORKS

NodeA junction in a circuit where two or more circuit elements and/or branches are connected together.BranchPart of a network which lies netween two junctions.LoopA closed path in a circuit in which no element or node is encountered more than once.MeshA loop that contains no other loop within it.

OHMS LAWOHMS LAWOne of the most fundamental law in electrical circuits relating voltage, current and resistanceDeveloped in 1827 by German physicist Georg Simon Ohm

OHMS LAWAccording to Ohms Law, the current (I) flowing in an electrical circuit is directly is directly proportional to the applied voltage (E) and inversely proportional to the equivalent resistance (R) of the circuit and mathematically expressed as:

SERIES CIRCUITS SERIES circuitsA circuit connection in which the components are connected to form one conducting path

SERIES CIRCUITS

Where: EX voltage across the resistor concerned ET total voltage across the circuit RX the resistor concerned RT the sum of all resistances in the circuit

PARALLEL CIRCUITS PARALLEL circuitsA circuit connection in which the components are connected to form more than 1 conducting path

PARALLEL CIRCUITS

Where: IX current concerned flowing through resistor Rx IT total current of the circuit Req equivalent resistance of the parallel circuit except Rx RT the sum of all resistances in the circuit

KIRCHHOFFS LAW

In any electrical network, the algebraic sum of the current meeting at a point (or junction) is zero.

KIRCHHOFFS LAWMore comprehensive than Ohms Law and is used in solving electricalTermed as Laws of Electric NetworksFormulated by German physicist Gustav Robert Kirchhoff

KIRCHHOFFS CURRENT LAWIn short the sum of currents entering a node equals the sum of currents leaving the nodeCurrent towards the node, positive currentCurrent away from the node, negative current

IB + IC + ID = IA

(IB + IC + ID) - IA = 0

KIRCHHOFFS VOLTAGE LAW

The algebraic sum of the products of currents and resistances in each of thr conductors in any closed path (or mesh) in a network PLUS the algebraic sum of the emfs in the path is zero.

KIRCHHOFFS VOLTAGE LAWIn short, the sum of the voltages around the loop is equal to zeroFor voltage sources, if loops enters on minus and goes out on plus, positive voltage and if loops enters on plus and goes out on minus, negative voltage.For voltage drops, if the loop direction is the same as current direction, negative voltage drop and if the loop direction is opposite to the current direction, positive voltage drop.

MESH ANALYSISLoop Analysis Procedure:

Label each of the loop/mesh currents. Apply KVL to loops/meshes to form equations with current variables.For N independent loops, we may write N total equations using KVL around each loop. Loop currents are those currents flowing in a loop; they are used to define branch currents. Current sources provide constraint equations. Solve the equations to determine the user defined loop currents.

MESH analysisA sophisticated application of KVL with mesh currents.

NODAL ANALYSISConsist of finding the node voltages at all principal nodes with respect to the reference node.

PRINCIPAL node a node with three or more circuit elements joined together.

Reference node the node from which the unknown voltages are measured.NODAL analysisA systematic application of KCL at a node and after simplifying the resulting KCL equation, the node voltage can be calculated.

SUPERPOSITION THEOREMIn general:Number of network to analyze is equal to number of independent sources.To consider effects of each source independently, sources must be removed and replaced without affecting the final result:

All voltage sources >> short circuitedAll current sources >> open circuitedSUPERPOSITION theorem The current through or voltage across, an element in a linear bilateral network is equal to the algebraic sum of the current or voltages produced independently in each source.

COMPENSATION THEOREMCOMPENSATION theoremIf the impedance Z of a branch in a network in which a current I flows is changed by a finite amount dZ, then the change in the currents in all other branches of the network may be calculated by inserting a voltage source of -IdZ into that branch with all other voltage sources replaced by their internal impedances.

RECIPROCITY THEOREMSimply mean,E and I are mutually transferable, orThe receiving point and the sending point in a network are interchangeable, orInterchange of an IDEAL voltage source and an IDEAL ammeter in any network will not change the ammeter reading,Interchange of an IDEAL current source and an IDEAL voltmeter in any network will not change the voltmeter readingRECIPROCITY theorem If a voltage source E acting in one branch of a network causes a current I to flow in another branch of the network, then the same voltage source E acting in the second branch would cause an identical current I to flow in the first branch.

MILLMANS THEOREMIn Millmans Theorem, the circuit is re-drawn as a parallel network of branches, each branch containing a resistor or series battery/resistor combination.Millmans theorem is applicable only to those cicuits which can be re-drawn accordingly. MILLMANS theorem A special case of the application of Thevenins Theorem/or Nortons Theorem used for finding the COMMON voltage (VAB) across any network which contains a number of parallel voltage sources.

MAXIMUM POWER TRANSFER THOREMMAXIMUM POWER TRANSFER theoremFor loads connected directly to a DC voltage supply, maximum power will be delivered to the load when the resistance is equal to the internal resistance of the source.For maximum power transfer: RS = RL

THEVENINS THEOREMwhere: VTH the open circuit voltage which appears across the two terminals from where the load resistance has been removed.RTH the resistance looking back into the network across the two terminals with all the voltage sources shorted and replaced by their internal resistances (if any) and all current sources by infinite resistance.THEVENINS theorem Any two-terminal of a linear, active bilateral network of a fixed resistances and voltage source/s may be replaced by a single voltage source (VTH) and a series of internal resistance (RTH).

NORTONS THEOREMwhere: IN the current which would flow in a short circuit placed across the output terminals.RN the resistance of the network when viewed from the open circuited terminals after all voltage sources being replaced by open circuits.

THEVENINS theorem Any two-terminal active network containing voltage sources and resistances when viewed from its output terminals, is equivalent to a constant-current source (IN) and a parallel internal resistance (RN).

THEVENIN-NORTON TRANSFORMATION

NORTON-THEVENIN TRANSFORMATION

EQUIVALENT THREE-TERMINAL NETWORKSDELTA to WYEThe equivalent resistance of each arm to the wye is given by the PRODUCT of the two delta sides that meet at its end divided by the SUM of the three delta resistances.

EQUIVALENT THREE-TERMINAL NETWORKSWYE to DELTAThe equivalent delta resistance between any two twrminals is given by the SUM of a star resistance between those terminals PLUS the PRODUCT of these two star resistances DIVIDED by the third resistance.

REVIEW QUESTIONSA battery with a rating of 9 volts has an internal resistance of 20 ohms. What is the expected resistance of the bulb that is connected across the battery to attain a maximum power transfer?a. 20 ohmsb. 10 ohmsc. 5 ohmsd. 2 ohms

2. In a sireis ciscuit a resistors 2200 and 4500 with an impressed voltage of 10, what is the circuit current in mA?a. 1.49b. 6.67c. 4.34d. 1.34

REVIEW QUESTIONS3. The current needed to operate a soldering iron which has a rating of 600 watts at 110 volts is.a. 5.455 Ab. 66,000 Ac. 18,200 Ad. 0.182 A

4. The ammeter reads 230 ampere while the voltmeter is 115 volts. What is the power inKW at the time of readinga. 264.5b. 2645c. 264500d.26.45

REVIEW QUESTIONS5. What is the type of circuit whose parameters are constant which do not change with voltage or current?a. Lumpedb. Tunedc. Reactived. Linear

6. What is the resistance of two equal valued resistor series?a. Twice as oneb. The sum of their reciprocal c. The difference of bothb. The product of both

REVIEW QUESTIONS7. What do you expect when you use two 20 kohms, 1 watts resistors in parallel instead of one 10 kohms, 1 watt?a. Provide more powerb. Provide lighter currentc. Provide less powerd. Provide wider tolerance

8. The voltage applied in DC circuit having a power of 36 watts and a total resistance of 4 ohms.a. 6 Vb. 9Vc. 12 Vd. 24 V

REVIEW QUESTIONS9. When resistor are connected in series, what happens?a. The effective resistanceb. Nothingc. The toleranced. The effective resistance is increased

10. Find the thevenins impedance equivalent across R2 of a linear close circuit having 10-V supply in series with the resistors (R1=100 ohms and R2=200 ohms)a. 666 ohmsb. 6.66 ohmsc. 66.6 ohmsd. 6666 ohms

REVIEW QUESTIONS11. How much power does electronic equipment consume, assuming a 5.5A current flowing and a 120-V power source.a. 60 Wb. 66 Wc. 660 Wd. 125.5 W

12. How many nodes are needed to completely analyze a circuit according to Kirchoffs Current Law.a. Oneb. Two c. All nodes in the circuitd. One less than the total number of nodes in the circuit

REVIEW QUESTIONS13. A common connection between circuit elements or conductors from different branches.a. Nodeb. Junctionc. Groundd. Mesh

14. It is used to denote a common electrical point of zero potential.a. Short circuitb. Reference pointc. Open circuitd.ground

REVIEW QUESTIONS15. Loop currents should be assumed to flow in which direction?a. Straightb. Clockwisec. Counterclockwised. Either b or c

16. In mesh analysis, we apply:a. KCLb. KVLc. Sourced. Millmans theorem

REVIEW QUESTIONS17. Which of the following is not a valid expression of Ohms Lawa. R = PIb. E = IRc. I = E/Rd. R = E/I

18. Using ohms Law, what happens to the circuit current if the applied voltage increases?a. Current doublesb. Current increasesc. Current remians constantd. Current decreases

REVIEW QUESTIONS19. According to ohms law, what happen to the circuit current if the circuit resistance increases?a. Current doublesb. Current decreasesc. Current increasesd. Current remains constant

20. If the resistance of a circuit is doubled and the applied voltage is kept constant, the current will be _______ .a. Be quaddrupledb. Remainsc. Be cut in halfd. Be doubled

REVIEW QUESTIONS21. It is an electrical current that flows in one direction only?a. Normal currentb. Alternating currentc. Direct currentd. Eddy current

22. In Ohms Law, what is E/R?a. Amperageb. Voltagec. Resistanced. Power

REVIEW QUESTIONS23. A 33-Kohm resistor is connected in series with a parallel combination made up of 56-Kohm resistor and a 7.8-kohm resistor. What is the total combined reistance of the three resistors?a. 390667 ohmsb. 49069 ohmsc. 63769 ohmsd. 95000 ohms

24. Which of the following cannot be included in a loop of Kirchoffs Volatage Lawa. Current sourceb. Voltage sourcec. Resistanced. Reactance

REVIEW QUESTIONS25. A series connected circuit consists of 3 loads and consume a total power of 50 Watts. It was reconfigured such that 2 are in parallel and the other load is in series with a combination. What is the applied expected powers to be consumed them?a. 50 wattsb. 25 wattsc. 75 wattsd. 45 watts

26. If the number of valence electrons of an atom is less than 4, the substance is usuallya. Semiconductorb. An insulatorc. A conductord. None of the above

REVIEW QUESTIONS27. Electric current in a wire is the flow ofa. Free electronsb. Valence electronsc. Bound electronsd. Atoms

28. EMF in a circuit is a forma. Powerb. Energyc. Charged. none

REVIEW QUESTIONS29. The SI unit of specific-resistance isa. Mhob. Ohm-nc. Ohm-sq.-md. Ohm-cm

30. The resistance of a material is ___ its area of cross-sectiona. Directly proportionalb. Inversely proportionalc. Independentd. None of these

REVIEW QUESTIONS31. The value of , i.e., the temperarure coefficient of resistance depends upon the ____ of the material.a. Lengthb. Volumec. X-sectional aread. Nature and temperature

32. The value of of a conductor is 1/236 C. The value of a is a. 1/218 Cb. 1/272 Cc. 1/254 Cd. 1/265 C

REVIEW QUESTIONS33. Electrical appliances are not connected in series becausea. Series circuit is complicatedb. Power loss is greaterc. Appliances have different current ratingd. None of these

34. Electrical appliances are connected in parallel because ita. Is a simple circuitb. Results in reduced power lossc. Draw less currentd. Makes the operation of the appliances independent from each other

REVIEW QUESTIONS35. The hot resistance of a 100W, 250V incandecent lamp isa. 2.5 ohmsb. 625 ohmsc. 25 ohmsd. None of these

36. When a number of resistances are connecte in parallel, the total resistance isa. Less than the smallest resistanceb. Greater than the smallest resistancec. Between the smallest and greater resistanced. None of these

REVIEW QUESTIONS37. If the resistances, each of value 36 ohms are connected in parallel, the total resistance isa. 2 ohmsb. 54 ohmsc. 36 ohmsd. None of these

38. Two incandecent lamps of 100 W, 200V are in parallel across the 200 V. The total resistance will bea. 800 ohmsb. 200 ohmsc. 400 ohmsd. 600 ohms

REVIEW QUESTIONS39. Three resistors are connected in parallel and draws 1A, 2.5A, and 3.5A, rspectively. If the applied voltage is 210V, what is the total resistance of the circuit?a. 5 ohmsb. 147 ohmsc. 3 ohmsd. 73.5 ohms

40. An ordinary dry cell can deliver about ____ continuously.a. 3 Ab. 2 Ac. 1/8 Ad. None of these

REVIEW QUESTIONS41. Four cells of internal resistance 1 ohms, are connected in parallel. The battery resistance will bea. 4 ohmsb. 0.25 ohmsc. 2 ohmsd. 1 ohms

42. Of the following combination of units, the one that is not equal to the watt isa. Joule/secb. Ampere-voltc. Ampere-ohmd. Ohm/volt

REVIEW QUESTIONS43. The power dissipated in a circuit is not equal toa. VIb. IRc. V/Rd. IR/V

44. An electric iron draws a current of 15A when connected to 120V power source. Its resistance isa. 0.125 ohmsb. 8 ohmsc. 16 ohmsd. 1,800 ohms

REVIEW QUESTIONS45. The power rating of an electric motor which draws a current of 3 A when operated at 120 V isa. 40 Wb. 360 Wc. 540 Wd. 1,080 W

46. When a 100W, 240V, light bulb is operated at 200V, the current that flows in it isa. 0.35 Ab. 0.42 Ac. 0.5 Ad. 0.58 A

REVIEW QUESTIONS47. The equivalent resistance of a network of three 2 ohm resistors cannot bea. 0.67 ohmsb. 1.5 ohmsc. 3 ohmsd. 6 ohms

48. A 12V potential difference is applied across a series combination of four six-ohms resistors. The current in each six-ohm resistor will bea. 0.5 Ab. 2 Ac. 8 Ad. 6 A

REVIEW QUESTIONS49. A 12V potential difference is applied across a parallel combination of four six-ohms resistors. The current in each six-ohm resistor will be a. 0.5 Ab. 2 Ac. 8 Ad. 6 A

50. The dissipation of energy can cause burns because it proceducesa. Heatb. Firec. Frictiond. Overload

REVIEW QUESTIONS51. The rate of expenditure of energy isa. Voltageb. Powerc. Currentd. Energy

52. In a simple DC power line, the wire that carries the current from the generator to the load is calleda. Return wireb. Feederc. Outgoing wired. Conductor

REVIEW QUESTIONS53. A circuit in which the resistance are connected in a continuous run, i.e., end-to-end is a _____ circuit.a. Saries b. Parallelc. Series-paralleld. None of these

54. A battery is connected to an external circuit. The potential drop with the battery is proportional to a. The EMF of the batteryb. The current of the circuitc. The equivqlent circuit resistanced. Power dissipated in the circuit

REVIEW QUESTIONS55. Two wires A and B have the same cross-sectional area and are made of the same material. Ra = 600 ohms and Rb = 100 ohms. The number of times A is longer tahn B isa. 6b. 2c. 4d. 5

56. A coil has a resistance of 100 ohms at 90 C. At 100 C, its resistance is 101 ohms. The temperature coefficient of the wire isa. 0.01b. 0.1c. 0.0001d. 0.001

REVIEW QUESTIONS57. The resistance of a conductor does not depend on itsa. Resistivityb. Lengthc. Cross-sectiond. Mass

58. A material which has a negative temperature coefficient of resistance is usually a/ana. Insulatorb. Conductorc. Semi-conductord. All of these

REVIEW QUESTIONS59. Which of the following statements is true both for a series and a parallel dc circuit?a. Power additiveb. Current are additivec. Voltage are additived. All of these

60. Two resistors are said to be in series when a. Both carry the same value of currentb. Total current equals the sum of the branch currentc. Sum of IR drops equal to EMFd. Same current phases through both

REVIEW QUESTIONS61. According to KCL as applied to a juction in a network of conductors.a. Total sum of currents meeting at the juction is Zerob. No current can leave the juction without same current passing throuhg itc. Net current flow at he juction is positived. Algebraic sum of the currents meeting at the juction is zero

62. Kirchoffs Current Law is applicable only toa. Closed-loop circuitb. Electronic circuitsc. Juctions in a networkd. Electric circuit

REVIEW QUESTIONS63. Kirchoffs Voltage Las\w is concerned witha. IR dropsb. Battery EMFsc. Juction voltagesd. A and b

64. According to KVL, the algebraic sum of all IR drops and EMFs in any closed loop of a network is alwaysa. Zerob. Negativec. Positived. Determined by battery EMF

REVIEW QUESTIONS65. The algebraic sign of an IR drops primarily dependent upona. The amount of current flowing through itb. Direction of currentc. The value of the resistanced. The battery connection

66. Choose the wrong statement. In the node voltage technique of solvingnetwork parameters, the choice of the reference node does not a. Affect the operation of the circuitb. Change the voltage across the element c. Alter the potential difference between any pair of nodesd. Affect the volatge of various nodes

REVIEW QUESTIONS67. The nodal analysis is primarily based on the application ofa. KVLb. KCL.c. Ohms Lawd. b and c

68. Superposition theorem can be applied only to circuits having ____ elementsa. Non-linearb. Passivec. Linear bilaterald. Resistive

REVIEW QUESTIONS69. The superposition theorem is essentially based on the concept ofa. Reciprocityb. Linearityc. non-linearityd. Duality

70. What are the electrons in motion called?a. Current variationb. Electric currentc. Electron velocityd. Dynamic electricity

REVIEW QUESTIONS71. An active element in a circuit is one which _____ .a. Receives energyb. Supplies energyc. a or bd. None of these

72. The siperposition theorem is used when the circuit containsa. A single voltage sourceb. A number of voltage sourcec. Passive element onlyd. None of these

REVIEW QUESTIONS73. Thevenins theorem is ____ form of equivalent circuit.a. Voltageb. Currentc. Both a and bd. None of these

74. Nortons theorem is ____ form of an equivalent circuit.a. Voltageb. Currentc. Both a and bd. None of these

REVIEW QUESTIONS75. In the analysis of vacuum tube circuit, we can generally use ____ theorem.a. Nortonsb. Theveninsc. Superpositiond. Reciprocity

76. In the analysis of transistor circuits, we generally use _____ theorem.a. Voltageb. Currentc. Both a and bd. None of these

REVIEW QUESTIONS77. Under the condition of Maximum Power Transfer, the efficiency isa. 75 %b. 100 %c. 50 %d. 25 %

78. The maximum power transfer theorem is used ina. Electronic circuitsb. Home lightningc. Power sytemd. None of the above

REVIEW QUESTIONS79. delta/star or star/delta transformation technique is applied toa. One terminalb. Two terminal c. Three terminald. None of these

80. _____ will be used under elctrostatics.a. Incandecent lampb. Electric motorc. Electric irond. Lightning rod

REVIEW QUESTIONS81. The value of the absulute permitivity of air is ______ F/m.a. 9 x 10 b. 8,854 x 10 ^ -12c. 5 x 10d. 9 X 10

82. When two similar charges eaach of 1 coulumb each are placed 1m apart in air, then the force of repusion isa. 8 x10 Nb. 10 Nc. 9 x 10^9 Nd. 5 x 10 N

REVIEW QUESTIONS83. Another name for dielectric strength isa. Potetial gradientb. Breakdown voltagec. Dielectric constantd. Electric intensity

84. A heater connected to a 100 V supply, generates 10,000 J of heat energy is 10 sec. How much time is needed to generate the same amount of heat when it is used on 220V line?a. 5 secb. 2.5 secc. 7.5 secd. 4 sec.

REVIEW QUESTIONS85. Kirchoffs current law is applied in what type of circuit analysis?a. Meshb. Theveninsc. Superpositiond. Nodal

86. Inductance and capacitance are not relevant in a dc circuit becausea. Frequency of DC is zerob. It is a simple circuitc. They do not exist in dc circuitd. None of the above

REVIEW QUESTIONS87. Three resistors of 3 ohms resistance each are connected in delta, the equivalent wye-connected resistors will bea. 1 ohmb. 3 ohmsc. 9 ohmsd. 0.111 ohm

88. Cells are conneted in series when _____ is requireda. High currentb. High voltagec. High powerd. All of these

ALTERNATING CURRENTALTERNATING CURRENTA current that is constantly changing in amplitude and direction. Advantages of AC:Magnitude can easily be changed (stepped-up or stepped down) with the use of a transformerCan be produced either single phase for light loads, two phase for control motors, three phase for power distribution and large motor loads or six phase for large scale AC to DC conversion.

AC WAVEFORMS

AC WAVEFORMSPeriod (T) the time of one complete cycle in secondsFrequency (f) the number of cycles per second (Hertz)1 cycle/second (cps) = 1 Hertz (Hz)Proper operation of electrical equipmnent requires specific frequencyFrequencies lower than 60 Hz would cause flicker when used in lightningWavelength () the length of one complete cyclePropagation Velocity (v) the speed of the signalPhase () an angilar measurement that specifies the position of a sine wave relative to reference

AC WAVEFORMSTHE SINUSOIDAL WAVEIs the most common AC waveform that is practically generated by generators used in household and industriesGeneral equation for sine wave:Where:a(t) instantaneous amplitude of voltage or current at a given time (t)Am maximum voltage or current amplitude of the signal angular velocity in rad/sec; = 2ft time (sec) phase shift ( + or in degrees)

AC WAVEFORMSPEAK AMPLITUDE the height of an AC waveform as measured from the zero mark to the highest positive or lowest negative point on a graph. Also known as the crest amplitude of a wave.

AMPLITUDE It is the height of an AC waveform as depicted on a graph over time (peak, peak-to-peak, average, or RMS quantity)

AC WAVEFORMSPEAK-TO-PEAK AMPLITUDE the total height of an AC waveform as measured from maximum positive to maximum negative peaks on a graph. Often abbreviated as P-P

AC WAVEFORMSAVERAGE AMPLITUDE the mathematical mean of all a waveforms points over the period of one cycle. Technically, the average amplitude of any waveform with equal-area portions above and below the zero line on a graph is zero.

For a sine wave, the average value so calculated is approximately 0.637 of its peak value.

AC WAVEFORMSRMS AMPLITUDE - RMS stands for Root Mean Square, and is a way of expressing an AC quantity of voltage or current in terms functionally equivalent to DC. Also known as the equivalent or DC equivalent value of an AC voltage or current.

For a sine wave, the RMS value is approximately 0.707 of its peak value.

AC WAVEFORMSThe crest factor of an AC waveform is the ratio of its peak (crest) to its RMS value.

The form factor of an AC waveform is the ratio of its RMS value to its average value.

AC QUANTITIES

AC QUANTITIESInductive Reactance (XL)The property of the inductor to oppose the alternating current

Inductive Susceptance (BL)Reciprocal of inductive reactance

Capacitive Reactance (XC)The property of a capacitor to oppose alternating current

Capacitive Susceptance (BC)Reciprocal of capacitive reactance

d

XL = 2fLBL = 1 BL = 1 XL 2fLXC = 1 2fCBL = 1 BL = 2fC XC

AC QUANTITIESIMPEDANCE (Z)Total opposition to the flow of Alternating currentCombination of the resistance in a circuit and the reactances involvedWhere: |Z| = R2 + X2 = Arctan Xeq R

AC QUANTITIESIf I = Im is the resulting current drawn by a passive, linear RLC circuit from a source voltage V = Vm , then

Where: Z = Vm = R2 + X2 = magnitude of the impedance Im = = tan-1 X = phase angle of the impedance RR = Zcos = active or real component of the impedance

X = Zsin = reactive or quadrature component of impedanceZ = V = Vm = Z I Im Z cos + jZsin = R + jX = R2 + X2 tan-1 X R

AC QUANTITIESADMITTANCE (Y)The reciprocal of impedanceExpressed in siemens or mho (S)

Where: Y = Im = G2 + B2 = 1 = magnitude of the admittance Zy = = = tan-1 B = phase angle of the admittance GG = Ycos y = conductive/conductance component

B = Ysin y = susceptive/susceptance component

Y = Im = Y = Ycos y + jYsin y = G + jB Vm Y = G2 + B2 tan-1 B G

AC RESISTOR CIRCUITWith an AC circuit like this which is purely resistive, the relationship of the voltage and current is as shown:

Voltage (e) is in phase with the current (i)Power is never a negative value. When the current is positive (above the line), the voltage is also positive, resulting in a power (p=ie) of a positve valueThis consistent polarity of a power tell us that the resistor is always dissipating power, taking it from the source and releasing it in the form of heat energy. Whether the current is negative or positive, a resistor still dissipated energy.Impedance (Z) = R

AC INDUCTOR CIRCUITThe most distinguishing electrical characteristics of an L circuit is that current lags voltage by 90 electrical degrees

Because the current and voltage waves arae 90o out of phase, there sre times when one is positive while the other is negative, resulting in equally frequent occurences of negative instantaneous power.Negative power means that the inductor is releasing power back to the circuit, while a positive power means that it is absorbing power from the circuit.The inductor releases just as much power back to the circuit as it absorbs over the span of a complete cycle.Impedance (Z) = jXL

AC INDUCTOR CIRCUITInductive reactance is the opposition that an inductor offers to alternating current due to its phase-shifted storage and release of energy in its magnetic field. Reactance is symbolized by the capital letter X and is measured in ohms just like resistance (R).

Inductive reactance can be calculated using this formula: XL = 2fL

The angular velocity of an AC circuit is another way of expressing its frequency, in units of electrical radians per second instead of cycles per second. It is symbolized by the lowercase Greek letter omega, or .

Inductive reactance increases with increasing frequency. In other words, the higher the frequency, the more it opposes the AC flow of electrons.

AC CAPACITOR CIRCUITThe most distinguishing electrical characteristics of an C circuit is that leads the voltage by 90 electrical degrees

The current through a capacitor is a reaction against the change in voltage across itA capacitors opposition to change in voltage translates to an opposition to alternating voltage in general, which is by definition always changing in instantaneous magnitude and direction. For any given magnitude of AC voltage at a given frequency, a capacitor of given size will conduct a certain magnitude of AC current.The phase angle of a capacitors opposition to current is -90o,meaning that a capacitors opposition to current is a negative imaginary quantityImpedance (Z) = -jXC

AC CAPACITOR CIRCUITCapacitive reactance is the opposition that a capacitor offers to alternating current due to its phase-shifted storage and release of energy in its electric field. Reactance is symbolized by the capital letter X and is measured in ohms just like resistance (R).

Capacitive reactance can be calculated using this formula: XC = 1/(2fC)

Capacitive reactance decreases with increasing frequency. In other words, the higher the frequency, the less it opposes (the more it conducts) the AC flow of electrons.

SERIES RESITOR-INDCUTOR CIRCUITFor a series resistor-inductor circuit, the voltage and current relation is determined in its phase shift. Thus, current lags voltage by a phase shift ()Impedance (Z) = R + jXLAdmittance (Y) = 1 = R jXL R + jXL R2 + jXL2

SERIES RESITOR-INDCUTOR CIRCUITWhen resistors and inductors are mixed together in circuits, the total impedance will have a phase angle somewhere between 0o and +90o. The circuit current will have a phase angle somewhere between 0o and -90o. Series AC circuits exhibit the same fundamental properties as series DC circuits: current is uniform throughout.Phase shift () = Arctan ( XL ) |Z| = R2 + jXL2 = e R i

SERIES RESISTOR-CAPACITOR CIRCUITFor a series resistor capacitor circuit, the voltage and current relation is determined by the phase shift. Thus the current leads the voltage by an angle less than 90 degrees but greater than 0 degrees.Impedance (Z) = R jXCAdmittance (Y) = 1 = R + jXC R jXC R2 + jXC2

SERIES RESISTOR-CAPACITOR CIRCUITPhase shift () = Arctan ( XC ) |Z| = R2 + jXC2 = e R i

PARALLEL RESISTOR-INDUCTORY = G jL where: G conductance = 1/R L susceptance = 1/XL Z = E , by Ohms Law I

The basic approachwith regarda to parallel circuits is using admittance because it is additive

PARALLEL RESISTOR-INDUCTORWhen resistors and inductors are mixed together in parallel circuits (just like in series cicuits), the total impedance will have a phase angle somewhere between 0o and +90o. The circuit current will have a phase angle somewhere between 0o and -90o.

Parallel AC circuits exhibit the same fundamental properties as parallel DC circuits: voltage is uniform throughour the circuit, brach currents add to form the total current, and impedances diminish (through the reciprocal formula) to form the total impedance.

PARALLEL RESISTOR-CAPACITORY = G + jC where: G conductance = 1/R C susceptance = 1/XC

When resistors and capacitors are mixxed together in circuits, the total impedance will have a phase angle somewhere between 0o and -90o.

APPARENT POWER (S)APPARENT POWERRepresents the rate at which the total energy is supplied to the systemMeasured in volt-amperes (VA)It has two components, the Real Power and the Capacitive or Inductive Reactive Power

APPARENT POWER (S)

REAL POWER (R)REAL POWERThe power consumed by the resistive componentAlso called True Power, Useful Power and Productive PowerMeasured in Watts (W)It is equal to the product of the apparent power and the power factor

Cosine of the power factor angle ()Measure of the power that is dissipated by the cicuit in relation to the apparent power and is usually given as a decimal or percentage

REAL POWER (R)Ratio of the Real Power to the Apparent Power ( P ) Swhen:Pf = 1.0I is in phase with V; resistive systemPf = laggingI lags V by ; inductive systemPf = leadingI leads V by ; capacitive systemPf = 0.0 lagI lags V by 90o; purely inductivePf = 0.0 leadI leads V by 90o; purely capacitive

The angle between the apparent power and the real poweer in the power triangle Let v(t) = Vm cos(t + v) voltsV = Vrms vi(t) = Im cos(t + i) AI = Irms i

REAL POWER (R)Where: = phase shfit between v(t) and i(t) or the phase angle of the equivalent impedanceP(t) = v(t) i(t)P(t) = VmIm cos (v i) + VmIm cos (2t + v + i)P(t) = VmIm cos (v i) = VmIm cos

REACTIVE POWER (QL or QC)REACTIVE POWERRepresents the rate at which energy is stored or released in any of the energy storing elements (the inductor or the capacitor)Also called the imaginary power, non-productive or wattless powerMeasured in volt-ampere reactive (Var)When the capacitor and inductor are both present, the reactive power associated with them take opposite signs since they do not store or release energy at the same timeIt is positive for inductive power (QL) and negative for capacitive power (QC)

Ratio of the Reactive Power to the Apparent PowerSine of the power factor angle ()Q = VmIm sin Rf = sin

BALANCED THREE PHASE SYSTEMSBALANCED 3-PHASE SYSTEMComprises of three identical single-phase systems operating at a 120o phase displacement from one another. This means that a balance three-phase system provides three voltages(and currents) that are equal in magnitude and separated by 120o from each other

Three-Phase, 3-wire systemsProvide only one type of voltage(line to line) both single phase and three phase loads

Three-Phase, 4-wire systemsProvide two types of voltages(line to line and line to neutral) to both single phase and three phase loads

BALANCED THREE PHASE SYSTEMS

andVLL and VLN are out of phase by 30o

VLL = 3 VLNIL = IP

andIL and IP are out of phase by 30o

Where: VLL or VL - line to line or line voltage VLN or VP - line to neutral or phase voltage IL - line current IP - phase currentIL = 3 IPVLL = VLN

ALTERNATING CURRENT VJH watts vars vaNote: for balanced 3-phase systems:IA + IB + IC = 0VAN + VBN + VCN = 0VAB + VBC + VCA = 0P = 3VPIPcos = 3 VLIL cos Q = 3VPIPsin = 3 VLIL sin S = 3VPIP = 3 VLIL

REVIEW QUESTIONS1. The description of two sine waves that are in step with each other going through their maximum and minimum points ate the same time and in the same direction.a. Sine waves in phaseb. Stepped sine wavesc. Phased sine wavesd. Sine waves in coordination

2. Term used for the out of phase, non-productive power associated with inductors and capacitors.a. Effective powerb. True powerc. Reactive powerd. Peak envelope power

3. Refers to a reactive power.a. Wattles, non productive powerb. Power consumed in circuit Qc. Power loss because of capacitor leakaged. Power consumed in wire resistance in an inductor

4. Term used for an out-of-phase, non-productive power associated with inductors and capacitors.a. Effective powerb. Reactive powerc. Peak envelope powerd. True powerREVIEW QUESTIONS

5. The product of current and voltage in an AC circuit refers to thea. Real powerb. Useful powerc. Apparent powerd. DC power

6. The distance covered or traveled by a waveform during the time interval of one complete cycle.a. Frequencyb. Wavelengthc. Time slotd. Wave timeREVIEW QUESTIONS

7. The power dissipated accross the resistance in an AC circuit.a. Real powerb. Reactive powerc. Apparent powerd. True power

8. It is the number of complete cycles of alternating voltage or current complete each seconda. Periodb. Frequencyc. Amplituded. Phase

REVIEW QUESTIONS

9. How many degrees are there in one complete cycle?a. 720 degb. 360 degc. 180 degd. 90 deg

10. The impedance in the study of electronics is represented by resistance and ___ .a. Reactanceb. Inductance and capacitancec. Inductanced. capacitanceREVIEW QUESTIONS

11. It is the current that is eliminated by a synchro capacitor?a. Magnetizing statorb. Lossc. Statord. Rotor

12. It is a rotaing sector that represent either current or voltage in an AC circuit.a. Resistanceb. Phasorc. Solar diagramd. velocityREVIEW QUESTIONS

13. The relationship of the voltage accros an inductor to its current is described asa. Leading the current by 90 degb. Lagging the current by 90 degc. Leading the current by 180 degd. In phase with the current

14. Find the phase angle between the voltage across through the cicuit when Xc is 25ohms, R is 100 ohms and XL is 50 ohms.a. 76 deg with the voltage leading the currentb. 24 deg with the voltage lagging the currentc. 14 deg with the voltage lagging the currentd. 76 deg with the voltage lagging the currentREVIEW QUESTIONS

15. Calculate the period of an alternating current having a equation of I=20sin 120ta. 4.167 msb. 8.33 msc. 16.67 msd. 33.33 ms

16. What do you mean by root-mean-square (rms) value?a. It is the average valueb. It is the effective valuec. It is the value that causes the same heating effect as the DC voltaged. b or cREVIEW QUESTIONS

17. The maximum instances value of a vrying current, voltage or power equal to 1.414 times the effective value of a sine wave.a. RMS valueb. Peak valuec. Effective valued. Peak to Peak value

18. If an AC signal has a peak voltage of 55V, what is the average value?a. 34.98 Vb. 61.05Vc. 86.34 Vd. 38.89 VREVIEW QUESTIONS

19. If an AC signal has an average voltage of 18V, what is the rms voltage?a. 12.726 Vb. 19.980 Vc. 25.380 Vd. 16.213 V

20. A 220-V, 60Hz is driving a series RL circuit. Determine the current if R=100 ohms and 20 mH inductancea. 2.2 A (lagging)b. 2.0 A (lagging)c. 2.2 A (leading)d. 2.0 A (leading)REVIEW QUESTIONS

21. Ignoring any inductive effects, what is the impedance of RC series capacitor made up of a 56K ohm resistor and a 0.33uF capacitor at a signal frequency of 4650 Hz.a. 66730 ohmsb. 57019 ohmsc. 45270 ohmsd. 10730 ohms

22.What is the time constant of a 500mH coil and a 3300 ohm resistor in series?a. 0.00015 secb. 6.6 secc. 0.0015 secd. 0.0000015 secREVIEW QUESTIONS

23. What is the realtionship between frequency and the value of XC ?a. Frequency has no effectb. XC varies inversely with frequencyc. XC varies indirectly with frequencyd. XC varies directly with frequency

24. The reactance of a 25mH coil at 5000Hz which of the following?a. 785 ohmsb. 785000 ohmsc. 13 ohmsd. 0.0012 ohmsREVIEW QUESTIONS

25. There are no transients in pure resistive circuites becaus theya. Offer high resistanceb. Obey ohms Lawc. Are linear circuitsd. Have no stored energy

26. The reciprocal of capacitance is called a. Elastanceb. Conductancec. Permitivityd. permeabilityREVIEW QUESTIONS

REVIEW QUESTIONS27. The AC system is prefered over DC system becausea. Ac voltages can easily changed in amgnitudeb. Dc motors do not have fine speed controlc. High voltage AC transmission is less efficientd. DC voltage cannot be used for domestic aplliences

28. An altenating voltage is given by v = 20 sin 157 t. The frequency of the alternating voltage isa. 50 Hzb. 25 HZc. 100 Hzd. 75 Hz

REVIEW QUESTIONS29. An alternating current given by i = 10 sin 314 t. The time taken to generate two cycles of current isa. 20 msb. 10 msc. 40 msd. 50 ms

30. In a pure resistive circuit, the instantaneous voltage and are current are given by:v=250 sin 314ti=10sin314tThe peak power in the circuit isa.1250 Wb. 25 Wc. 2500 Wd. 250 w

REVIEW QUESTIONS31. An average value of 6.63 A is _____ the effective value of 7.07 A.a. The same areab. Less thanc. Greater than d. Any of these

32. In an R-L series circuit, the resistance is 10 ohms and the inductive reactance is 10 ohms. The phase angle between the applied voltage and circuit current will bea. 45 degb. 30 degc. 60 degd. 36.8 deg

REVIEW QUESTIONS33.An R-L series ac circuit has 15V across the resistor and 20V across the inductor. The supply volatge isa. 35 Vb. 5 Vc. 25 Vd. 175 V

34. The active and reactive powers of an inductive circuit are equal. The power factor of the circuit isa. 0.8 lagging b. 0.707 laggingc. 0.6 laggingd. 0.5 lagging

REVIEW QUESTIONS35. A circuit when connected to 200V mains takes a current of 20 A, leading the voltage by one-twelfth of time period. The circuit resistance isa. 10 ohmsb. 8.66 ohmsc. 20 ohmsd. 17.32 ohms

36. An AC circuit has a resistance of 6 ohms, inductive reactance of 20 ohms, and capacitive reactance of 12 ohms. The circuit power will bea. 0.8 laggingb. 0.8 leadingc. 0.6 laggingd. 0.6 leading

REVIEW QUESTIONS37. An alternating voltage of 80 + j60 V is applied to a circuit and the current flowing is -40 + j10 A. Find the phase angle.a. 25 degb. 50 degc. 75 degd. 100 deg

38. A current wave is represented by the equation i = 10 sin 251t. The average and RMS value of current area. 7.07 A; 6.63Ab. 6.36A; 7.07Ac. 10A; 7.07Ad. 6.36A; 10A

REVIEW QUESTIONS39. Calculate the susceptance in mho of a circuit consisting of resistor of 10 ohms in series with a conductor of 0.1H, when the frequency is 50Hz.a. 0.0303b. 0.0092c. -0.029d. 32.95

40. An inductive circuit of resistance 16.5 ohms and inductive of 0.14H takes a current of 25 A. If the frequency is 50Hz, the supply voltage isa. 117.4 Vb. 1174 Vc. 1714 Vd. 1471 V

REVIEW QUESTIONS41. The current taken by a circuit is 1.2 A when the applied potential difference is 250 V and the power taken is 135W. The power factor isa. 0.35b. 0.45c. 0.55d. 0.65

42. A capacitor has a capacitance of 20uF. The current supplied if it is placed across a 1100 V, 25 Hz supply.a. 3.554 Ab. 6.91 Ac. 3.45 Ad. 9.61 A

REVIEW QUESTIONS43. A non-inductive load takes a 100A at 100V. Calculate the inductance of the inductor to be connected in series in order that the same current is supplied from 220 V, 50 Hz mains.a. 1.96 ohmsb. 6.91 ohmsc. 19.6 ohmsd. 9.61 ohms

44. An inductor having negligible resistance and an inductance of 0.07H is connected in series with a resiostor of 20 ohms resitance across a 200, 50 Hz supply. The maximum energy stored in the coil isa. 3.175 Jb. 1.585 Jc. 0.236 Jd. 0.33 J

REVIEW QUESTIONS45. A coil has 1200 turns and procedures 100 uWb mwhen the current flowing is 1A. The inductance of the coil isa. 0.21 Hb. 0.12 Hc. 0.31 Hd. 0.41 H

46. A capacitor connected to a 115 V, 25 Hz supply takes 5 A. What current will it take when the capacitance and frequency are doubled?a. 2 Ab. 5 Sc. 10 Ad. 20 A

REVIEW QUESTIONS47. A resistor of 20 ohms is connected in parallel with a capacitor across a 110 V, 40 Hz supply. If the current taken is 6A, what is the capacitance?a. 88.6 uFb. 68.8 uFc. 86.8 uFd. 76.8 uF

48. What capacitance must be placed in series with an inductance of 0.05H, so that when the frequency is 100 Hz, the impedance becomes equal to the ohmic resitance?a. 70.5 uFb. 50.7 uFc. 5.7 uFd. 7.05 uF

REVIEW QUESTIONS49. A reactance of 20 ohms and inductance of 0.1 H is connected in parallel with a capacitor. The capacitance of the capacitor required to produce a resonance when connected to a 100V, 50 Hz isa. 71.2 uFb. 1.277 uFc. 17.2 uFd. 72.1 uF

50. What is the resonant frequency of a circuit when an inductance of 1uH and capacitance of 10 picofarad are in series?a. 15.9 MHzb. 50.3 MHzc. 15.9 kHzd. 50.3 KHz

REVIEW QUESTIONS51. The _____ the Q of a circuit, the narrower the bandwidth.a. Lowerb. Higherc. Broaderd. Selective

52. Find the half power bandwidth of a parallel resonant circuit which has a resonant frequency of 3.6MHz and Q of 218.a. 606 kHzb. 58.7 kHzc. 16.5 kHzd. 47.3 kHz

REVIEW QUESTIONS53. At series resonance _____ .a. Circuit impedance is very largeb. Cicuit power factor is minimumc. Voltage across L or C is zerod. Circuit power factor is unity

54. At series resonance, the voltage across the inductor isa. Equal to the applied voltageb. Much more than the apllied voltagec. Equal to voltage across Rd. Less than the applied voltage

REVIEW QUESTIONS55. The Q factor of the coil is _____ the resistance of the coil.a. Inversely proportional tob. Directly proportional toc. Independent ofd. None of these

56. An RLC circuit is connected is connected to 200V AC source. If Q factor of the coil is 10, then the voltage across the capacitor at resonance isa. 200 Vb. 2000 Vc. 20 Vd. 210 V

REVIEW QUESTIONS57. At parallel resonancea. Circuit impedance is minimumb. Power factor is zeroc. Line current is maximumd. Power factor is unity

58. The dynamic impedance of parallel resonant circuit is 1 Mohms. If the capacitance is 1uF, and the resistance is 1ohm, then the value of the inductancea. 1 Hb. 10 Hc. 10 pHd. 10 uH

REVIEW QUESTIONS59. When supply frequency is less than the resonant frequency in a parallel ac circuit, then the circuit isa. Resistiveb. Capacitivec. Inductived. None of these

60. At parallel resonance, the circuit drwas a current of 2mA. If the Q of the circuit is 100, then the current through the capacitor isa. 2 mAb. 1 mAc. 200 mAd. None of these

REVIEW QUESTIONS61. A circuit has an impedance of (1-j2) ohms. The susceptance of the circuit in mho isa. 0.1 b. 0.2c. 0.4d. None of these

62. If the admittance of a parallel ac circuit increased, the circuit currenta. Remains constantb. Is increasedc. Is decreasedd. None of these

REVIEW QUESTIONS63. The resistance between any pair two terminals of a balanced wye-connected load is 12 ohms.a. 6 ohmsb. 18 ohmsc. 24 ohmsd. None of these

64. If an AC circuit contains three nodes, the number of each mesh equations that can be formulated isa. 1b. 2c. 3d. 4

REVIEW QUESTIONS65. The relation of the voltage across an inductor to its current is describe asa. Leading the current by 90 degb. Lagging the current by 90 degc. Leading the current by 180 degd. In phase with the current

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