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    Chapter 7Acceleration Analysis

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    Definition

    Rate of change of velocity with respect totime Angular

    Linear

    Position Vector

    Velocity

    dt

    d

    dt

    dVA

    j

    PA peR

    jjPApa ep

    dt

    dpje

    dt

    RV

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    Definition

    dt

    jepd

    dt

    d jPAPA

    A

    A

    sincoscossin 2 jpjpPA A

    "Absolute"PPA AA

    dt

    dje

    dt

    dejp

    jj

    PA

    A

    jj

    PA epjep2A

    PAn

    PAt

    PA AAA

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    Definition

    Acceleration (difference)

    Relative Acceleration

    "bodysameon the"

    PAAP AAA

    APPA AAA

    nPAtPAnAtAnPtP AAAAAA

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    Graphical Analysis

    Graphical Acceleration Analysis

    Solve for

    PAAP AAA

    rAtt

    A

    CBA ,,on;acceleratilinear

    ,;onacceleratiangular 43

    2rA

    nn A

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    Graphical Analysis

    Example 7-1 Given 2, 3, 4, 2 ,3, 4,2

    find 3 , 4 , AA, AB and AC

    Velocity analysis alreadyperformed

    1. Start at the end of thelinkage about which you havethe most information.Calculate the magnitude ofthe acceleration of point A,

    222 AOAn

    A 22 AOAt

    A

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    Graphical Analysis

    Example 7-1 2. Draw the acceleration AA 3. Move next to a point which

    you have some information,point B. Draw theconstruction line pp throughB perpendicular to BO4

    4. Write the acceleration

    difference equation for pointB vs. A

    BAAB AAA

    n

    BA

    t

    BA

    n

    A

    t

    A

    n

    B

    t

    B AAAAAA 2

    44 BOAn

    B

    n

    BA

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    Graphical Analysis

    5. Draw construction line qqthrough point B andperpendicular to BA torepresent the direction ofABA

    6. The vector equation can besolve graphically by drawing

    the following vector diagram

    23BAAn

    BA

    nBAtBAnAtAnBtB AAAAAA BAAB AAA

    n

    B

    n

    BA

    n

    A

    t

    A AAAA ?& t

    B

    t

    BA

    AA

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    Graphical Analysis

    7. The angular velocities of link3 and 4 can be calculated,

    8. Solve for VC

    4

    4BO

    At

    B

    BA

    At

    BA3

    CAAC AAA

    3cAtCA

    2

    3cAn

    CA

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    Graphical Analysis

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    Analytical Analysis

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    Fourbar Pin-Joint Linkage Vector Loop

    Position

    Velocity

    Acceleration

    Analytical Solution

    01432 RRRR

    01432

    jjjj

    decebeae

    0432 432

    jjj

    ejcejbeja

    0443322 244233222 jjjjjj ecjecebjebeajea

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    Fourbar Pin-Joint Linkage

    Analytical Solution

    04433

    22

    2

    44

    2

    33

    2

    22

    jjn

    B

    t

    BB

    jjn

    BA

    t

    BABA

    jjn

    A

    t

    AA

    ecjec

    ebjeb

    eajea

    AAA

    AAA

    AAA

    0 BBAA AAA

    identityEuler

    partreal

    partimaginary

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    Fourbar Pin-Joint Linkage

    Analytical Solution

    4

    2

    43

    2

    32

    2

    222

    3

    4

    coscoscossin

    sin

    sin

    cbaaC

    bB

    cA

    BDAE

    AFCD

    3

    BDAE

    BFCE

    4

    4

    2

    43

    2

    32

    2

    222

    3

    4

    sinsinsincos

    cos

    cos

    cbaaF

    bE

    cD

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    Fourbar Pin-Joint Linkage

    Analytical Solution

    442

    4444

    33

    2

    3333

    22

    2

    2222

    sincoscossin

    sincoscossin

    sincoscossin

    jcjc

    jbjb

    jaja

    B

    BA

    A

    A

    A

    A

    0 BBAA AAA

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    Analytical Solution

    Slider-Crank

    d

    ebjeb

    eajea

    t

    BB

    jjn

    BA

    t

    BABA

    jjn

    A

    t

    AA

    AA

    AAA

    AAA

    33

    22

    2

    33

    2

    22

    0 BBAA AAA

    BABA

    AA

    BAAB AAA

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    Analytical Solution

    Slider-Crank

    3

    2

    3332

    2

    222

    3

    3

    2

    32

    2

    2223

    cossincossincos

    sinsincos

    bbaadb

    baa

    identityEuler

    partreal

    partimaginary

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    Coriolis Acceleration Is an additional component

    of acceleration present whena sliding joint is on a rotating

    link Thy position vector is both

    rotating and changing lengthas the system moves

    Analytical Solution

    2j

    P peR

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    Coriolis Acceleration The velocity expression is

    The acceleration,

    Analytical Solution

    22

    2

    jj

    P epep V

    sliptrans PPP VVV

    2222

    2

    22

    22

    2

    jjjj

    P

    epjepejpjep A

    slipcoriolisnormaltangetial PPPPPAAAAA

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    Coriolis Acceleration

    The acceleration,

    Analytical Solution

    2222

    222

    22 2 jjjj

    P epjepejpjep A

    slipcoriolisnormaltangetial PPPPPAAAAA

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    Acceleration of Any Point

    Once the angular acceleration of all the links arefound it is easy to define and calculate theacceleration of any point on any link for any input

    position of the linkage

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    Acceleration of Any Point

    To find the acceleration of points S

    22220

    sincos222

    jssej

    SSRR

    222222 cossin22

    jsjsej

    SV

    22222

    2

    22222

    sincos

    cossin

    js

    jsS

    A

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    Acceleration of Any Point

    To find the acceleration of points U

    44440

    sincos444

    juuej

    UR

    444444

    cossin44

    jujsej

    UV

    444424

    44444

    sincos

    cossin

    ju

    juUA

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    Acceleration of Any Point

    To find the acceleration of point P

    PAAP

    j

    PA jppe

    RRR

    R

    3333sincos33

    PAAP

    jPA jpjpe

    VVV

    V

    333333cossin33

    3333

    2

    3

    33333

    sincos

    cossin

    jp

    jpPA

    PAAP

    A

    AAA

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    Jerk page 367-369 Human Tolerance to Acceleration page 364-366 Fourbar Inverted Slider-Crank page 354-360

    Acceleration Analysis of the Geared Fivebar- page361 -362

    Important topics to review