Experiment 3

Experiment 3ESTIMATION OF ACETIC ACID FROM VINEGAR 1Introduction2ObjectiveTo estimate the concentration of acetic acid from vinegar by using acid-base titration3Materials

Chemicals:

0.1N NaOHOxalic acidPhenolphthalein Distilled waterVinegar

ClampBurette4Methods

5Vinegar

6ResultsStandardization of NaOH

Titration123Final (mL)19.919.919.6Initial (mL)000Volume used (mL)19.919.919.6Average (mL)19.8C2H2O4 (aq) + NaOH(aq) C2HO4-Na+ (aq) + H2O(aq)7Results: CalculationConcentration NaOH used:M1V1 = M2V2M2 =

M2 = 0.0505N

Therefore, the concentration of NaOH solution used is 0.0505N.

M1 = Concentration of oxalic acidV1 = Volume needed for 0.1N oxalic acidM2 = Concentration of NaOHV2 = Volume of NaOH used for titration

8ResultsGraphs: Standardization NaOH

9ResultsAcetic acid from vinegarTitration123Final (mL)7.16.86.6Initial (mL)000Volume used (mL)7.16.86.6Average (mL)6.83C2H4O2 (aq) + NaOH(aq) C2H3O2-Na+ (aq) + H2O(aq)10Results: CalculationMolarity of NaOH = 0.0505 NNumber of moles NaOH reacted,

= 0.0505 N x = 3.45 x 10-4 N NaOHFrom the equation,1 mol NaOH = 1 mol C2H4O2= 3.45 x 10-4 mol C2H4O2

Molality of diluted C2H4O2 solution,= = 3.45 x 10-3 N

Number of mole of C2H4O2 in 10mL (undiluted),= 3.45 x 10-3 N

11Results: CalculationMolality of acetic acid,

= = 0.345 N

The concentration of acetic acid content in vinegar is 0.345N.

Therefore, weight-volume percentage of C2H4O2 in vinegar,

=

= 2.07%

Percentage of acetic acid in vinegar is 2.07%.

12ResultsGraphs: Acetic acid from vinegar

13ResultsPhysical observation

InitialFinal(End Point)14DiscussionEnd point : color change from colorless to pale pink indicator is colorless when acidic, neutral : colorless

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16ConclusionThe concentration of acetic acid is 0.345N with percentage of 2.07% in the vinegar.

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Thank You18