activity on nodes

Activity on Nodes

ACTIVITY ON NODES-Prof. Pradeep PaiGroup 6

DRAWING THE PROJECT NETWORKActivity On Arc/Arrow

Activity on Arrow networks show each activity as an arrow, and the nodes represent the starting and ending pointsActivity On Node

Activity on Node networks show each activity as a node and arcs show the immediate predecessor activities

2

ESEFLSLFActDurTotal FloatFree Float


Free FloatTotal FloatDurationActivityLate FinishLate StartEarly FinishEarly Start

Early StartEarly FinishLate StartLate FinishActivityDurationTotal FloatFree FloatEvery activity is shown in rectangleNode Design

RULES OF ACTIVITY ON NODENo need for a dummyMultiple start and multiple end is possibleSufficient space to write between the arrowsArrows cannot come backCannot start from top or bottomRelationship is from left to right









PROBLEM 1ActDurPredESEFLSLFTotal FloatFree FloatA3-030300B5A3871240C7A31031000D4B812121644E6C1016101600F4C1014172177G5D,E1621162100H8G,F2129212900I2G2123272966J4H,I2933293300

29332933J40(0)

21232729I26(6)

21292129H80(0)

10141721F47(7)

10161016E60(0)

310310C70(0)

16211621G50(0)

8121216D44(4)

38712B54(0)

0303A30(0)SOLUTION

FORWARD PASS

05A5

37B4FF+2

05A5

26B4SS+2

05A5

48B4FS-1

05A5

610B4FS+1To determine early start (ES) and early finish (EF) times for each task:Work from left to rightAdding times in each path (EF= ES+ Activity Duration)

Rule: when several tasks converge, the ES for the next task is the largest of preceding EF times

BACKWARD PASS

05A5

48B4-(FF+2)

16A5

37B4-(SS+2)

13A2

48B4-(FS-1)

05A5

610B4-(FS+1)

To determine the last finish (LF) and last start (LS) times:Start the end node Compute the bottom pairs of numbers Subtract duration from connecting nodes earliest start timeRule : Take the lowest value when several tasks converge

PROBLEM 2ACTIVITYDescriptionCOMPLETION TIME ARedesign product5BRedesign packaging3COrder and receive components for redesigned product 4DOrder and receive material for redesigned packaging 7EAssemble products5FMake up packaging 3GPackage redesigned product 2HTest market redesigned product6IRevise redesigned product3JRevise redesigned packaging 4KPresent results to the Board2

10

ActivityDurationPredecessorRelationESEFLSLFTotal FloatFree FloatA5--050500B3AFS-236111488C4AFS+38128120-4D7CSS8158150-1E5CFF+41116121710F3B,DFS,FS-11417141700G2EFS1618171910H6F,GFS,FS-2172317230-2I3GFS1821212433J4HSS+4212521250-1K2I,JFS,FF+12426242600

0505A50(0)

17231723H60(6)

361114B38(8)

21252125J40(0)

14171417F30(0)

812812C40(0)

815815D70(0)

18212124I33(3)

24262426K20(0)

11161217E51(0)

16181719G21(0)FSFSFS - 1FS - 2FF + 1FS-2FS + 3SSFF + 4FSFSSS+4FSSOLUTION

Whenever free float is negative, make it zeroNegative comes because of parallel workingRelationship Calculation requires AON methodCannot be solved by AOA method

13

Thank YouHarsh Kumar Jhunjhunwala B017Karan Malviya B021Amit Jain B023Deeksha Darak B027Piyush Jajodia B036Ekta Agarwal B043

activity on nodes

Documents