aiims 6 mock test by allen

(ACADEMIC SESSION 2011-2012)CLASSROOM CONTACT PROGRAMME

1. A seat marked with Reg. No. will be alloted to each student. The student should ensure that he/she

occupies the correct seat only. If any student is found to have occupied the seat of another student,

both the students shall be removed from the examination and shall have to accept any other penalty

imposed upon them.

izR;sd fo|kFkhZ dk jftLV™s'ku ua- ds vuqlkj LFkku fu;r g S rFkk os vius fu;r LFkku ij gh cBS saA ;fn dksbZ fo|kFkhZ fdlh

nwljs fo|kFkhZ ds LFkku ij cBS k ik;k x;k rks nksuksa fo|kfFkZ;ksa dks ijh{kk d{k ls ckgj dj fn;k tk,xk vkjS nksuksa dks dksbZ vU;

tqekZuk Hkh Lohdk;Z gksxkA

2. Student can not use log tables and calculators or any other material in the examination hall.

fo|kFkhZ ijh{kk d{k esa yksx Vscy] dsYdwysVj ;k fdlh vU; lkexzh dk mi;ksx ugha dj ldrk gAS

3. Student must abide by the instructions issued during the examination, by the invigilators or the

centre incharge.

ijh{kk ds le; fo|kFkhZ dks ijhoh{kd }kjk fn;s x;s funsZ'kksa dh ikyuk djuk vko';d gAS

4. Before attempting the question paper ensure that it contains all the pages and that no question is

missing.

iz'u i= gy djus ls igys fo|kFkhZ vk'oLr gks tk, fd blesa lHkh ist layXu gaS vFkok ughaA

5. Each correct answer carries 1 marks, while one third mark will be deducted from the total of

individual subject for each incorrect answer.

izR;sd lgh mŸkj ds 1 vad gaS tcfd ,d frgkbZ vad] xyr mŸkj dk ml fo"k; ds dqy vadksa esa ls de dj fy;k tk;sxkA

MAJOR TESTDATE : 24 – 05 – 2012ALLEN AIIMS # 04

TARGET : PRE-MEDICAL 2012

LEADER, ACHIEVER & ENTHUSIAST COURSE

Corporate Office

ALLEN CAREER INSTITUTE“SANKALP”, CP-6, INDRA VIHAR, KOTA-324005

PHONE : +91 - 744 - 2436001, Fax : +91-744-2435003E-mail: [email protected] Website: www.allen.ac.in

Do not open this Test Booklet until you are asked to do so / bl ijh{kk iqfLrdk dks tc rd uk [kksysa tc rd dgk u tk,sAbl ijh{kk iqfLrdk dks tc rd uk [kksysa tc rd dgk u tk,sA

(Full Syllabus)

E / H 1/33

24–05–2012

Your Target is to secure Good Rank in Pre-Medical 2012

PRE-MEDICAL : LEADER, ACHIEVER & ENTHUSIAST COURSE

MAJOR TEST : AIIMS

1. 5 ehVj dh nwjh ls Lora= :i ls fxjdj] ,d xsanfdlh fy¶V tks fd 1eh-/lS- ds osx ls Åij dh vkSjtk jgh gS] ds Q'kZ ls izR;kLFk VDdj djrh gSA VDdjds i'pkr~ xsan dk izfrf{kIr osx gksxk :-(g = 10 m/sec2)(1) 10 m/sec (2) 11 m/sec(3) 12 m/sec (4) 13 m/sec

2. fdlh jsfM;ks lfØ; rRo dh ek/; vk;q T gSA fdrus le;

esa blds 34

va'k dk fo?kVu gksxk :-

(1) T (2) 2T(3) (loge2) T (4) 2(loge2)T

3. m æO;eku ds ,d CykWd dks u osx ls ,d xfr ;ksX; ostftldk æO;eku nm rFkk Å¡pkbZ h gS] dh rjQ ¥/kdsyktkrk gSS lHkh lrg fpduh gS u dk U;wure eku rkfd CykWd]ost ds 'kh"kZ ij igq¡p tk,] gksxk :-

(1) 2gh(2) 2ngh

(3) 1

2gh 1n

æ ö+ç ÷è ø

nmh v m

(4) 1

2gh 1n

æ ö-ç ÷è ø

4. ,d lrg dk dk;ZQyu 2eV gSA tc ijkcSaxuh QksVkWu dks

bl lrg ij vkifrr fd;k tkrk gS] rc lrg ls 2eV ÅtkZ

ds bysDVªkWu mRlftZr gksrs gSa %&

(1) 9300 Å (2) 6200 Å

(3) 3100 Å (4) 1550 Å

5. Li'k Z j s[kh; yxk; s x;s cy F = (20t – 5t2) U; wVu(tgk¡ t lsds.M esa ukik x;k gS) ds dkj.k 2m f=T;k dh

,d f?kjuh viuh v{k ij ?kw.kZu djrh gSA ;fn ?kw.kZu v{k ds

bZnZ&fxnZ] f?kjuh dk tM+Ro vk?kw.kZ 10 kg m2 gSa] rc f?kjuh

dh xfr dh fn'kk izfryksfer gksus ls igys f?kjuh }kjk fd;s

x;s pDdjksa dh la[;k gSa:-

(1) 6 ls vf/kd ijUrq 9 ls de(2) 9 ls vf/kd

(3) 3 ls de

(4) 3 ls vf/kd ijUrq 6 ls de

1. A ball after falling a distance of 5 metre fromEast hits floor of a lift and rebounds. At the timeof impact the lift was moving up with a velocityof 1m/sec the velocity with which the ballrebounds just after impact is :- (g = 10 m/sec2)

(1) 10 m/sec (2) 11 m/sec(3) 12 m/sec (4) 13 m/sec

2. Mean life of a radioactive element is T. The time

duration in which its 34

fraction disintegrates, is:-

(1) T (2) 2T(3) (loge2) T (4) 2(loge2)T

3. A block of mass m is pushed towards movablewedge of mass nm and height h, with a velocity u.All surfaces are smooth. The minimum value of ufor which the block reach the top of the wedge is:-

(1) 2gh(2) 2ngh

(3) 1

2gh 1n

æ ö+ç ÷è ø

nmh v m

(4) 1

2gh 1n

æ ö-ç ÷è ø

4. Work function of a surface is 2eV. Whenultraviolet photon incident on this surface thenan electron of 2eV energy is emitted from thesurface. Find out the wave length of photon :-(1) 9300 Å (2) 6200 Å(3) 3100 Å (4) 1550 Å

5. A pulley of radius 2 m is rotated about its axis

by a force F = (20t – 5t2) newton (where t is

measured in seconds) applied tangentially. If

the moment of inertia of the pulley about its axis

of rotation is 10 kg m2, the number of rotations

made by the pulley before its direction of

motion it reversed, is :-

(1) more than 6 but less than 9

(2) more than 9

(3) less than 3

(4) more than 3 but less than 6

BEWARE OF NEGATIVE MARKING

HAVE CONTROL ¾® HAVE PATIENCE ¾® HAVE CONFIDENCE Þ 100% SUCCESS

izR;sd iz'u dks vtqZu cudj djksA

24–05–2012

2/33 E / HYour Target is to secure Good Rank in Pre-Medical 2012


MAJOR TEST : AIIMS

6. In the case of forward biasing of P–N Junctionwhich one of the following figures correctlydepicts the direction of flow of carriers :-

(1)

–––

+++

P N

(2)

–––

+++

P N

(3)

–––

+++

P N

(4)

–––

+++

P N

7. The minimum accelerating potential across thecoolidge tube is V to obtain characteristic Ka

line of the target then the minimum requiredaccelerating potential to obtain Kb line willbe :-

(1) More than V (2) Less than V

(3) Equal to V (4) We can't say

8. When a semiconductor is heated its resistance& resitivity respectively :-(1) Increase, Increase(2) Decrease, Decrease(3) Decrease, Constant(4) Increase, Constant

9. Two artificial satellites P and Q are revolvinground the earth in circular orbits. The ratio oftheir orbital radius is 1 : 9. The ratio of theirorbital velocities will be :-(1) 3 : 1 (2) 1 : 3(3) 9 : 1 (4) 1 : 9

10. The field normal to the plane of a coil of n turnsand radius r which carries a current i is measuredon the axis of the coil at a small distance h fromthe centre of the coil. This is smaller than thefield at the centre by the fraction :-

(1) 2

2

3 h2 r

(2) 2

2

2 h3 r

(3) 2

2

3 r2 h

(4) 2

2

2 r3 h

6. P–N laf/k dh vxzck;l fLFkfr ds fy, fuEu esa ls dkSulkfp= lgh gS :-

(1)

–––

+++

P N

(2)

–––

+++

P N

(3)

–––

+++

P N

(4)

–––

+++

P N

7. ;fn y{; dh Ka vfHkyk{kf.kd js[kk izkIr djus ds fy,dqyht uyh ij vkjksfir U;wure Rojd foHkokUrj V gS rks

Kb js[kk izkIr djus ds fy, vko';d U;wure Rojd

foHkokUrj gksxk %&

(1) V ls vf/kd (2) V ls de

(3) V ds cjkcj (4) dqN dg ugha ldr

8. tc v¼Zpkydksa dks xeZ djrs gSa rks bldk izfrjks/k oizfrjksèkdrk Øe'k% ------gS %&(1) c<+rh gS] c<+rh gS(2) ?kVrh gS] ?kVrh gS(3) ?kVrh gS] fu;r gS(4) c<+rh gS] fu;r gS

9. nks d`f=e mixzg P o Q i`Foh ds pkjksa rjQ o`rkdkj d{kkvksa

esa ifjØek dj jgs gSa budh d{kkvksa dh f=T;kvksa dk vuqikr

1 : 9 gS buds d{kh; osxksa dk vuqikr gksxk %&

(1) 3 : 1 (2) 1 : 3

(3) 9 : 1 (4) 1 : 9

10. r f=T;k ,oa n yisVksa okyh o`Ùkkdkj dq.Myh esa ls i /kkjk

izokfgr gks jgh gSA ;fn pqEcdh; {ks= dq.Myh ds ry ds

yEcor~ gS] rks dq.Myh ls h nwjh ij pqEcdh; {ks= ds eku

es fHkUukRed deh gksxh :-

(1) 2

2

3 h2 r

(2) 2

2

2 h3 r

(3) 2

2

3 r2 h

(4) 2

2

2 r3 h

E / H 3/33

24–05–2012



MAJOR TEST : AIIMS

11. The resultant of two vectors Ar

and Br

is

perpendicular to the vector Ar

and itsmagnitude is equal to half of the magnitude of

vector Br

. The angle between Ar

and Br

is :-

A

BR

90°

(1) 120° (2) 150°(3) 135° (4) None of these

12. Correct statement for L-C oscillator is :-(1) It generate radio waves of constant amplitude

(2) Its frequency is f = 1

2 LCp

(3) It have the +ve feed back circuit(4) All of above

13. Correct graph between kinetic energy E andtemperature t(°C) is :–

(1) (2)

(3) (4)

14. A metallic block

DZ

XI

B

C

AFE

BH

YG

carrying current I issubjected to auniform magnetic

induction Br

as shown in the figure. The moving

charges experience a force Fr

given

by...........which results in the lowering of thepotential of the face...........Assume the speedof the carriers to be u :-

(1) eVB $k , ABCD (2) eVB $k , EFGH

(3) – eVB $k , ABCD (4) – eVB $k , EFGH

11. nks lfn'k Ar

rFkk Br

dk ifj.kkeh Ar

ds yEcor~ gS rFkk

bldk ifjek.k Br

ds ifjek.k dk vk/kk gSA rks Ar

rFkk Br

ds e/; dks.k gksxk :-

A

BR

90°

(1) 120° (2) 150°

(3) 135° (4) buesa ls dksbZ ugha

12. L-C nksfy= ds fy, lgh dFku gS %&(1) ;s fu;r vk;ke dh jsfM;ks rjaxs mRiUu djrk gS

(2) bldh vko`fr f = 1

2 LCp gksrh gS

(3) blesa /kukRed iqu%Hkj.k (the feed back) ifjiFk yxkgksrk gS

(4) mijksä lHkh lgh gS13. xfrt ÅtkZ E o rki t(°C) ds e/; lgh xzkQ gksxk :–

(1) (2)

(3) (4)

14. ,d /kkfRod xqVds dks

DZ

XI

B

C

AFE

BH

YG

ftlesa ls fo|qr /kkjk Iizokfgr gks jgh gS] ,dlekaxh pqEcdh; izsj.k

Br

esa j[k fn;k x;k gSAxfreku vkos'kksa ij yxus okyk cy F

r -----gSA ifj.kker%

xqVds ds ry (Face)......ds foHko esa deh vk tkrh gS

(vkos'kksa dk osx u eku ysa) :-

(1) eVB $k , ABCD (2) eVB $k , EFGH

(3) – eVB $k , ABCD (4) – eVB $k , EFGH

24–05–2012



MAJOR TEST : AIIMS

15. The deceleration experienced by a movingmotor boat, after its engine is cut off, is givenby a = – kv, where k is constant. If v0 is themagnitude of velocity at cut off, the magnitudeof velocity at a time t after the cut off is :-

(1) 0

20

v

2v kt 1+ (2) v0e–kt

(3) 0v2

(4) v0

16. The probability of electrons to be found in theconduction band of an intrinsic semiconductor ata finite temperature :-(1) Decreases exponentially with increasing

band gap(2) Increases exponentially with increasing

band gap(3) Decrease linearly with temperature(4) Independent from the temperature

17. The slope of isothermal and adiabatic curvesfor diatomic gas are related as :-

(1) Isothermal curves slope=72

adiabatic curve

slope

(2) Isothermal curve slope = 53

adiabatic curve

slope

(3) Adiabatic curves slope=53

isothermal curve

slope

(4) Adiabatic curves slope=75

isothermal curves

slope

18. Diamagnetic substances are :-

(1) Feebly attracted by magnets

(2) Strongly attracted by magnets

(3) Feebly repelled by magnets

(4) Strongly repelled by magnets

15. fdlh eksVj cksV dk batu can djus ds i'pkr~ bldk eanu

a = – kv }kjk fn;k tkrk gSA ;gk¡ k fu;rkad gSA batu can

djrs le; bldk dV vkWQ osx v0 gSA dV vkWQ ds t le;

i'pkr~ eksVj cksV dk osx gksxk %&

(1) 0

20

v

2v kt 1+ (2) v0e–kt

(3) 0v2

(4) v0

16. fdlh fu;r rki ij pkyu cS.M esa bysDVªkWu ik;s tkus dhlaHkkouk %&

(1) ÅtkZ vUrjky ds lkFk] pj?kkrkadh :i ls ?kVrh gS

(2) ÅtkZ vUrjky ds lkFk] pj?kkrkadh :i ls c<+rh gS

(3) ÅtkZ vUrjky ds lkFk] js[kh; ?kVrh gS

(4) rki ls Lora= gS17. f}ijek.kh; xSl ds fy, lerkih vkSj :¼ks"e oØks ds cy

(slope) esa lEcU/k gks :-

(1) lerkih oØ dk <ky = 72

:¼k s"e oØ dk

<ky

(2) lerkih oØ dk <ky = 53

:¼k s"e oØ dk

<ky

(3) :¼k s"e oØ dk <ky = 53

lerkih oØ dk

<ky

(4) :¼ks"e oØ dk <ky=75

lerkih oØ dk <ky

18. izfr&pqEcdh; inkFkZ :-

(1) pqEcd }kjk nqcZy :i ls vkd£"kr gksrs gSa

(2) pqEcd }kjk izcy :i ls vkd£"kr gksrs gSa

(3) pqEcd }kjk nqcZy :i ls izfrd£"kr gksrs gSa

(4) pqEcd }kjk izcy :i ls izfrd£"kr gksrs gSa

dksbZ Hkh iz'u Key Filling ls xyr ugha gk suk pkfg,A

E / H 5/33

24–05–2012



MAJOR TEST : AIIMS

19. In the part of a circuit shown in the figure, thepotential difference (VG – VH) between pointsG and H will be :-

G2amp

4W2W

1W

H

3amp

5V

1amp

3V

(1) 0 V (2) 15 V(3) 7 V (4) 3 V

20. An ideal gas, have their volume increased fromV to 2V under two conditions. A isothrmalcondition and B adiabatic condition. Then thechange in internal energy :–

(1) Will be zero in A and B

(2) Will be same in Both A and B

(3) Will be zero in A but B is increases

(4) Will be zero in A but B is decreases

21. The network shown in the figure is a part of acomplete circuit. If at a certain instant the currenti is 5 A and is decreasing at the rate of 103 A/sthen VB – VA is :-

A B1W 15V 5mH

i

(1) 5 V (2) 10 V

(3) 15 V (4) 20 V

22. If two conical pendulums of lengths l1 and l2

trace horizontal circles of radii R1 and R2

respectively with the same angular velocity w,if their heights are h1 and h2, then :-(1) h1 = h2 (2) h1 > h2

(3) h1 < h2 (4) h1 >< h2

23. N0 is the number of radioactive nuclei at anyinstant and N the number of radioactive nucleiremaining undecayed after a time t. The graphdrawn with logeN,where e is the base of naturallogarithm along y-axis and t along the x-axiswill be a straight line with slope equal to :-

(1) 1l

(2) 1

-l

(3) l (4) –l

19. ,d ifjiFk dk ,d Hkkx fp= esa izn£'kr gS foHkokUrjVG – VH dk eku gksxk :-

G2amp

4W2W

1W

H

3amp

5V

1amp

3V

(1) 0 V (2) 15 V

(3) 7 V (4) 3 V

20. ,d vkn'kZ xSl ds vk;ru dks V ls 2V rd nks ifjfLFkfr;ksa

ds laxr A lerkih izØe rFkk B :¼ks"e izØe rd c<+k;k

tkrk gS] rks vkUrfjd ÅtkZ esa ifjorZu %&

(1) nksuksa esa 'kwU; gksxk

(2) A vkSj B nksuksa esa leku gksxhA

(3) A esa 'kwU; rFkk B esa c<+ sxhA

(4) A esa 'kwU; rFkk B esa ?kVsxkA

21. fuEu fp= esa fdlh lEiw.kZ ifjiFk ds ,d Hkkx dks fn[kk;kx;k gSA ;fn fdlh {k.k ifjiFk esa cgus okyh /kkjk i dk eku

5 A gS ,oa ;g /kkjk 103 A/s dh nj ls ?kV jgh gS] rks VB

– VA dk eku gksxk :-

A B1W 15V 5mH

i

(1) 5 V (2) 10 V

(3) 15 V (4) 20 V

22. nks 'kaDokdkj yksyd ftuds /kkxs dh yEckbZ l1 rFkk l2 gSleku dks.kh; osx w ls Øe'k% R1 rFkk R2 f=T;k ds oÙkkdkjiFk vuqjsf[kr dj jgsA ;fn budh Å¡pkbZ Øe'k% h1 rFkkh2 gks rks :-(1) h1 = h2 (2) h1 > h2

(3) h1 < h2 (4) h1 >< h2

23. fdlh {k.k ij jsfM;ks lfØ; ukfHkdksa dh la[;k N0 gS rFkkt le; ds ckn cps gq, vfo?kfVr jsfM;ks lfØ; ukfHkdksadh la[;k N gSA logeN dks y v{k ds vuqfn'k tgk¡ ije, izkd`frd y?kqx.kd dk vk/kkj gS rFkk t dks x v{k dsvuqfn'k ysdj xzkQ [khapus ij ,d ljy js[kk izkIr gksrhgS rks ljy js[kk dk <ky fdlds cjkcj gksxk %&

(1) 1l

(2) 1

-l

(3) l (4) –l

24–05–2012



MAJOR TEST : AIIMS

24. What is reading of voltmeter and ameter ingiven diagram, if there is no resistance of source

~A

240V

V

R=30W X =25L W X =25C W

(1) 0 V, 3A (2) 150 V, 3A

(3) 150 V, 6A (4) 0 V, 8 A

25. A mass is suspended separately

m

K1 K2

by two different springs insuccessive order then time periodis T1 and T2 respectively. If it isconnected by both spring asshown in figure then time periodis T0 , the correct relation is

(1) T02 = T1

2 + T22 (2) T0

–2 = T1–2 + T2

–2

(3) T0–1 = T1

–1 + T2–1 (4) T0 = T1 + T2

26. In the given circuit, the

100W

10V

V

50W

( )

voltmeter records 5V. The resistance ofthe voltmeter (inohm) is :-

(1) 200 (2) 100 (3) 10 (4) 50

27. A free neutron decays to a proton but a free protondoes not decay to a neutron. This is because :-(1) Neutron is a composite particle made of a

proton and an electron whereas proton is a fundamental particle

(2) Neutron is an nucharged particle whereas proton is a charged particle

(3) Neutron has larger rest mass than the proton(4) Weak forces can operate in a neutron but not

in a proton28. Potential at a point x-distance from the center

inside the conducting sphere of radius R andcharged with charge Q is :-

(1) QR

(2) Qx

(3) 2

Qx

(4) Qx

24. fp= esa fn[kk;s x;s ifjiFk esa L=ksr ds izfrjks/k dks ux.; ekuusij oksYVehVj ,oa vehVj ds ikB~;kad Øe'k% gksaxs%&

~A

240V

V

R=30W X =25L W X =25C W

(1) 0 V, 3A (2) 150 V, 3A(3) 150 V, 6A (4) 0 V, 8 A

25. fdlh æO;eku m dks ,d fLizax ls

m

K1 K2vyx&vyx yVdku s ij

vkorZdky T1 rFkk T2 izkIr gksrkgSA ;fn æO;eku dks fp= vuqlkj

yVdk;k tk;s rks vkorZdky dsfy;s lgh lEcUèk gksxk %

(1) T02 = T1

2 + T22 (2) T0

–2 = T1–2 + T2

–2

(3) T–1 = T1–1 + T2

–1 (4) T0 = T1 + T2

26. fn;s x;s ifjiFk esa oksYVehVj dk

100W

10V

V

50W

( )

ikB~; k ad 5 V gS rk s

oksYVehVj dk izfrjks/k

gksxk :- (W esa)

(1) 200 (2) 100 (3) 10 (4) 50

27. ,d Lora= U;wVªkWu] ,d izksVkWu esa fo?kfVr gksrk gS ysfdu ,d

Lora= izksVªkWu] U;wVªkWu esa fo?kfVr ugha gksrk gS D;ksafd %&

(1) U;wVªkWu ,d la;ksftr d.k gS tks izksVkWu ,oa bysDVªkWu

ls curk gS tcfd izksVkWu ,d ekSfyd d.k gS

(2) U;wVªkWu ,d vukosf'kr d.k gS tcfd izksVkWu ,d vkosf'kr

d.k gS

(3) U;wVªkWu dk fojke æO;eku izksVkWu ls vf/kd gksrk gS(4) U;wVªkWu esa {kh.k cy dk lapkyu gksrk gS tcfd izksVkWu

esa ugha28. ,d pkyd xksys ds dsUnz ls xksys ds vUnj x-nwjh ij foHko

fdruk gksxk tcfd xksys dh f=T;k R rFkk bls Q vkos'kls vkosf'kr fd;k x;k gS :-

(1) QR

(2) Qx

(3) 2

Qx

(4) Qx

Use stop, look and go method in reading the question

E / H 7/33

24–05–2012



MAJOR TEST : AIIMS

29. Two springs of force constant k and 2k areconnected to a mass as shown below. Thefrequency of oscillation of the mass is :

(1) (1/2p) (k /m) (2) (1/2p) (2k /m)

(3) (1/2p) (3k /m) (4) (1/2p) (m/ k)

30. A potentiometer wire of length 10 m andresistance 20 W is connected in series with a15 V battery and an external resistance 40 W. Asecondary cell of emf E in the secondary circuitis balanced by 240 cm long potentiometer wire.The emf E of the cell is :(1) 2.4 V (2) 1.2 V

(3) 2.0 V (4) 3V31. A hydrogen atom in ground state absorbs

10.2 eV of energy the orbital angular momen-tum of the electron is increased by :-

(1) 1.05 × 10–34 J-s (2) 2.11 × 10–34 J-s

(3) 3.16 × 10–34 J-s (4) 4.22 × 10–34 J-s

32. A particle P lying on smooth horizontal x-y

plane starts from +ˆ ˆ(3i 4 j) m with velocity

ˆ(2i) m/s. Another particle Q is projected

horizontally from origin with velocity +ˆ ˆ(xi yj)

so that is strikes P after 2s. Then :-(1) x = 2.0, y = 2.0 (2) x = 3.5, y = 2.0(3) y = y = 2.5 (4) y = y = 3.5

33. Two beads A and B of equal mass m areconnected by a light inextensible cord. Theyare constrained to move on a frictionless ringin vertical plane. The blocks are released fromrest as shown in figure. The tension in the cordjust after the release is :-

(1) mg4

(2) 2mg

A

B

(3) mg2

(4) mg

2

29. k vkSj 2k cy fu;rkad dh nks fLiazxs ,d æO;eku ls fp=kuqlkj

tqM+h gS rks æO;eku ds nksyu dh vko`fr gSA

(1) (1/2p) (k /m) (2) (1/2p) (2k /m)

(3) (1/2p) (3k /m) (4) (1/2p) (m /k)

30. 10 m yEckbZ rFkk 20 W izfrjks/k dk ,d foHkoekih rkj

15 V cSVjh rFkk 40 W izfrjks/k ls Js.khØe esa tqM+k gqvk

gSA E emf dk ,d f}rh;d lSy ] f}rh;d ifjiFk esa

foHkoekih rkj dh 240 cm yEckbZ ij larqfyr gksrk gS lSy

dk emf E gksxk %&

(1) 2.4 V (2) 1.2 V

(3) 2.0 V (4) 3V

31. gkbMªkstu ijek.kq ewy voLFkk esa 10.2 eV ÅtkZ vo'kksf"krdjrk gS bysDVªkWu ds d{kh; dks.kh; laosx esa o`f¼ gksrh gS%&(1) 1.05 × 10–34 J-s (2) 2.11 × 10–34 J-s(3) 3.16 × 10–34 J-s (4) 4.22 × 10–34 J-s

32. ,d d.k (P) fpdus {kSfrt ry x-y esa fLFkfr +ˆ ˆ(3i 4 j)m

ls osx ˆ(2i) m/s ls xfr izkjEHk djrk gSA nwljk d.k Q dks

ewy fcUnq ls {kSfrt +ˆ ˆ(xi yj) osx ls iz{ksfir djrs gSa rks

;g d.k P ls 2 sec esa Vdjkrk gS rks :-

(1) x = 2.0, y = 2.0 (2) x = 3.5, y = 2.0

(3) y = y = 2.5 (4) y = y = 3.5

33. nks eksrh ftuds æO;eku m leku gSA ,d vforkU; Mksjh ls

tqM+s gq, gSA os ,d ?k"kZ.kghu oy; esa m/okZ/kj ry esa ?kqeus

ds fy;s izfrcfU/kr gSA Cyksdksa dks fp=kuqlkj fojke ls NksM+k

tkrk gS rks NksM+us ds Bhd ckn jLlh esa ruko gksxk :-

(1) mg4

(2) 2mg

A

B

(3) mg2

(4) mg

2

24–05–2012



MAJOR TEST : AIIMS

34. A block of mass m = 0.1 kg is released froma height of 4m on a curved smooth surface. Onthe horizontal surface, path AB is smooth andpath BC offers coefficient of friction µ = 0.1.If the impact of block with the vertical wall atC be perfectly elastic, the total distance coveredby the block on the horizontal surface beforecoming to rest will be : (take g = 10 m/s2)

A B C

1m 2m

4m

(1) 29 m (2) 49 m (3) 59 m (4) 109 m35. A particle of mass m moving with a speed v

hits elastically another stationary particle ofmass 2m on a smooth horizontal circular tubeof radius r. The time in which the next collisionwill take place is equal to :-

(1) p2 rv

(2) p4 rv

m

2m

v

r(3)

p3 r2v

(4) prv

36. In the figure, the block of mass m, attached tothe spring of stiffness k is in contact with thecompletely elastic wall, and the compressionin the spring is e. The spring is compressedfurther by e by displacing the block towards leftand is then released. If the collision betweenthe block and the wall is completely elastic thenthe time period of oscillations of the block willbe :-

Km

wall

(1) p2 m3 k

(2) pm

2k

(3) p m3 k

(4) p m6 k

34. m = 0.1 fdxzk æO;eku ds ,d CykWd dks 4 ehVj dh Å¡pkbZ

ls ,d fpdus oØ lrg ij NksM+k tkrk gSA {kSfrt lrg ij

iFk AB fpduk gS rFkk BC dk ?k"kZ.k xq.kkad µ = 0.1 gSA

;fn m/okZ/kj nhokj C ij CykWd dk la?kkr iw.kZr% izR;kLFk gS

rks CykWd }kjk fojke esa vkus ls igys r; dh xbZ dqy nwjh

gksxh : (take g = 10 m/s2)

A B C

1m 2m

4m

(1) 29 m (2) 49 m (3) 59 m (4) 109 m35. m æO;eku dk ,d d.k v osx ls pyrk gqvk 2m æO;eku

ds ,d vU; fLFkj d.k ls r f=T;k ds fpdus {kSfrt o`Ùk esa

izR;kLFkr% Vdjkrk gSA rks vxyk VDdj fdrus le; ckn

gksxk :-

(1) p2 rv

(2) p4 rv

m

2m

v

r(3)

p3 r2v

(4) prv

36. iznf'kZr fp= esa m æO;eku dk ,d CykWd k cy fu;rkad

okys fLizax ls tqM+k gqvk gS rFkk ,d iw.kZ izR;kLFk nhokj ds

lEidZ esa gSA fLizax esa lEihM+u e gSA fLizax dks CykWd }kjk

iqu% e rd foLFkkfir djds NksM+k tkrk gSA ;fn CykWd ,oa

nhokj ds chp VDdj iw.kZ izR;kLFk gks rks CykWd ds nksyuksa dk

vkorZdky gksxk :-

Km

wall

(1) p2 m3 k

(2) pm

2k

(3) p m3 k

(4) p m6 k

E / H 9/33

24–05–2012



MAJOR TEST : AIIMS

37. A large open tank has two holes in the wall.One is a square hole of side L at a depth y fromthe top and the other is a circular hole of ra-dius R at a depth 4y from the top. When thetank is completely filled with water, thequantitites of water flowing out per second fromboth holes are the same. Then, R is equal to :-

(1) p

L

2(2) 2pL

(3) L (4) p

L2

38. A string of linear mass density 0.2 kg/m andlength l = 0.6 m is fixed at both ends andstretched such that it has a tension of 80 N. Thestring vibrates in 3 segments with maximumamplitude of 0.5 cm. The maximum particlevelocity is :-

(1) 1.57 m/s (2) 6.28 m/s

(3) 3.14 m/s (4) 9.42 m/s

39. An open organ pipe of length L vibrates in its

first overtone mode. The pressure variation is

maximum :-

(1) At two open ends

(2) At L4

& 3L4

inside the pipe from one end

(3) At middle of pipe

(4) At L8

& 3L8

inside the pipe from one end

40. No current flow between two charged bodiesconnected together when they have the same

(1) Capacitance or QV

ratio

(2) Charge

(3) Resistance

(4) Potential of QC

ratio

37. ,d yEch [kqyh Vadh dh nhokj esa nks fNæ gSA ,d fNæ Vadhds Åijh fljs ls y nwjh ij L Hkqtk okys oxZ ds :i esa rFkk

nwljk fNæ Vadh ds Åijh fljs ls 4y nwjh ij R f=T;k ds o`Ùk

ds vkdkj esa gSA tc Vadh dks iw.kZr% ikuh ls Hkj fn;k tkrk

gS rks nksuksa fNæksa ls fudyh gqbZ ikuh dh ek=k leku gksrh gS

rks R dk eku gksxk :-

(1) p

L

2(2) 2pL

(3) L (4) p

L2

38. ,d Mksjh dh yEckbZ l = 0.6 m gS rFkk js[kh; æO;eku

?kuRo 0.2 kg/m gS] nksuksa fljs ls dlh gqbZ gSA blesa ruko

80 N gS] ; s Mksjh rhu ywi esa rFkk vf/kdre vk;ke

0.5 cm. ls dfEir djrh gSA Mksjh esa vf/kdre d.k osx

gksxk :-

(1) 1.57 m/s (2) 6.28 m/s

(3) 3.14 m/s (4) 9.42 m/s

39. ,d [kqyh vkxZu ufydk ftldh yEckbZ L gS vius izFke

vfèkLoj ls dEiUu mRiUu dj jgh gSA rks nkc ifjorZu

vfèkdre gksxk :-

(1) nksuksa [kqys fljksa ij

(2) [kqys fljs ls L4

o 3L4

fcUnqvksa ij uyh ds vUnj

(3) e/; fcUnq ij

(4) uyh ds vUnj ,d fljs ls L8

o 3L8

ij

40. nks vkosf'kr oLrqvksa dks la;ksftr djus ij muds chp vkos'kdk izokg ugh gksxk ;fn muds fy, leku gks %&

(1) /kkfjrk ;k QV

vuqikr

(2) vkos'k

(3) izfrjks/k

(4) foHko ;k QC

vuqikrs

24–05–2012



MAJOR TEST : AIIMS

41. S1 foy;u [M+3] = 4 × 10–5M rFkk S2 foy;u

[S–2] = 2 × 10–3 M. j[kus okys foy;uksa dks leku

vk;ru esa feykus ij M2S3 dk vo{ksi izkIr gksrk gS

rks bldk foys;rk xq.kuQy Kkr djks :-

(1) 4 × 10–17 (2) 32 × 10–17

(3)16 × 10–17 (4) None

42. N2 xSl ds 10 Mslh ehVj3 esa rFkk fdlh xSl X ds10 Mslh ehVj3 esa leku rki ij v.kqvksa dh la[;k leku gSAxSl X gS :-

(1) CO (2) CO2 (3) H2 (4) NO

43.SO3H

NaHCO3

NO2NaHCO3

[I]

[II]

NO2

OH

:-

(I) ,oa (II) vfHkfØ;k esa eqDr gksus okyh xSls gSa :-(1) CO2, CO2 (2) SO2, NO2

(3) SO2, CO2 (4) SO2, NO

44. fuEufyf[kr esa vlR; dFku gS :-

(1) Be {kkjh; e`nk /kkrq ugha gS

(2) vfØ; xSl rRoksa dh okUMjoky f=T;k vkorZ esa y?kqÙkegksrh gSA

(3) IIA oxZ ds ¶yksjkbM~l esa BeF2 ty esa lokZf/kd foys;gksrk gSA

(4) NH4Cl lgla;ksth ;kSfxd gS

45. ukbVªhd vkDlkbM ds fuekZ.k esa vxz vfHkfØ;k ds vuqdwygS :-

(1) mPp nkc (2) fuEu nkc

(3) mPp rki (4) fuEu rki46. 298 K rki ij H2(g) rFkk H(g) dh ,UV ªkih ds eku Øe'k%

130.6 rFkk 114.6 J mol–1 K–1 gSA fuEu vkadM+ksa dksiz;qä djrs gq, Hydrogen dh ijekf.odj.k m"ek dkeku gksxk

H2(g) ¾® 2H(g) ; DG° = 406.6 kJ

(1) 436 kJ (2) 218 kJ

(3) 377.2 kJ (4) 430.5 kJ

41. The precipitate of M2S3 is obtained on mixing

equal volumes of solutions S1 having

[M3+] = 4 × 10–5M and S2 having

[S–2] = 2 × 10–3 M.. Calculate its solubility

product:-

(1) 4 × 10–17 (2) 32 × 10–17

(3)16 × 10–17 (4) None

42. 10 dm3 of N2 gas and 10 dm3 of gas X at the

same temperature contain the same number of

molecules. The gas X is :-

(1) CO (2) CO2 (3) H2 (4) NO

43.SO3H

NaHCO3

NO2NaHCO3

[I]

[II]

NO2

OH

:-

Gases released in reaction (I) and (II) are :-(1) CO2, CO2 (2) SO2, NO2

(3) SO2, CO2 (4) SO2, NO44. The incorrect statement among the following,

is :-(1) Be is not an alkaline earth metal(2) Vanderwaal radius of inert gases is the

smallest in the period(3) BeF2 is the most soluble in water in

IIA group fluorides(4) NH4Cl is covalent compound

45. In the manufacture of nitric oxide, the forward

reaction is favoured by :-

(1) High pressure (2) Low pressure

(3) High temperature (4) Low temperature46. The entropies of H2(g) and H(g) are 130.6 and

114.6 J mol–1 K–1 respectively at 298 K. Usingthe data given below calculate the heat ofatomisation of hydrogen in kJ/mol

H2(g) ¾® 2H(g) ; DG° = 406.6 kJ

(1) 436 kJ (2) 218 kJ

(3) 377.2 kJ (4) 430.5 kJ

E / H 11/33

24–05–2012



MAJOR TEST : AIIMS

47. Conversion of cyclohexanol into cyclohexeneis most effective in :-(1) Conc. H3PO4

(2) Conc. HCI(3) Conc. HCI/ZnCl2

(4) Conc. HBr48. Which among the following statement

regarding application of complex isincorrect :-(1) D-penicillamine is used to remove excess

of Cu and Fe from body(2) Wilkinson catalyst is used in hydrogenation

of alkenes(3) Na2EDTA is used to detect Ni2+ ion(4) Cyanocobalamine is used as antipernicious

anaemia factor49. How many effective Na+ and Cl–1 ions are

present respectively in a unit cell of NaCl solid

(Rocksalt structures). If ions along line

connecting opposite face centres are absent ?

(1) 72

, 4 (2) 7 7

,2 2

(3) 4,4 (4) 3,3

50. If enthalpy of hydrogenation of C6H6(l) intoC6H12(l) is – 205 kJ and resonance energy ofC6H6(l) is – 152 kJ/mol then enthalpy of

hydrogenation of is :-

(1) – 535.5 kJ/mol (2) – 238 kJ/mol(3) – 357 kJ/mol (4) – 119 kJ/mol

51. CH3CHO + H2NOH ¾® CH3 – CH = N – OH.The above Rxn occurs at :-(1) PH = 1(2) Ph ; 4.5(3) Any value of Ph(4) Ph = 12

52. Which is not a mineral :-(1) Mica (2) Peat

(3) Quartz (4) Felspar

53. 100 ml. of 0.1M HCl is mixed with 100 ml. of

0.01M HCl. The pH of the resulting solution

is:–

(1) 2.0 (2) 1.0

(3) 1.26 (4) None of these

47. lkbDyksgsDlsukWy dks lkbDyksgsDlhu esa ifjorZu djus ds fy,lokZf/kd izHkkoh gS :-(1) lkUæ H3PO4

(2) lkUæ HCI(3) lkUæ HCI/ZnCl2

(4) lkUæ HBr

48. ladqy dh mi;ksfxrk ds lanHkZ esa fuEu esa dkSulk dFku xyr

gS:-

(1) D-isfufly,ehu] 'kjhj esa Cu o Fe dh vf/kdrk dks

nwj djus esa iz;qDr gksrk gSA

(2) fofYdUlu mRizsjd ,Ydhu ds gkbMªksthfudj.k ds fy,

iz;qDr gksrk gSA

(3) Na2EDTA }kjk Ni2+ vk;u dh tk¡p dh tkrh gSA

(4) lk;uksdkscky,ehu izfr iz.kkyh vojDrrk dkjd gSA

49. ;fn NaCl dh bZdkbZ lsy (jkWd lkYV lajpuk) esa ls foifjr

Qyd esa dsUnz dks tksM+us okyh js[kk ds vuqfn'k mifLFkr vk;u

mifLFkr gks rks] NaCl dh bZdkbZ lsy esa izHkkoh Na+ rFkkCl– vk;uksa dh la[;k gS %&

(1) 72

, 4 (2) 7 7

,2 2

(3) 4,4 (4) 3,3

50. C6H6(l) dh C6H12(l) esa gkbMªkstuhdj.k dh m"ek dkeku – 205 kJ gSA ;fn C6H6(l) dh vuquknh ÅtkZ dk

eku – 152 kJ/mol gks rks , dh gkbMªkstuhdj.k

Å"ek dk eku gksxk :-(1) – 535.5 kJ/mol (2) – 238 kJ/mol

(3) – 357 kJ/mol (4) – 119 kJ/mol

51. CH3CHO + H2NOH ¾® CH3 – CH = N – OHmijksDr vfHkfØ;k gksrh gS(1) PH = 1 ij(2) Ph ; 4.5 ij(3) Ph ds fdlh Hkh eku ij(4) Ph = 12 ij

52. fuEu esa ls [kfut ugh gS :-

(1) vHkzd (2) ihV(3) DokVZt (4) QsyLikj

53. tc 100 ml., 0.1M HCl dks 100 ml., 0.01M HCl

ds lkFk feyk;k tkrk gS] rks ifj.kkeh foy;u dh pH gksxh%&(1) 2.0 (2) 1.0

(3) 1.26 (4) None of these

Take it Easy and Make it Easy

24–05–2012



MAJOR TEST : AIIMS

54. If enthalpies of formation for C2H4(g), CO2(g)and H2O(l) at 25°C and 1atm pressure be 52,–394 and –286 kJ mol–1 respectively. Enthalpyof combustion of C2H4 (g) will be :(1) +141.2 kJ mol–1 (2) +1412 kJ mol–1

(3) –141.2 kJ mol–1 (4) –1412 kJ mol–1

55. MeO CHO + X (i) CH3COONa/D(ii) H2O

MeO CH=CH COOH

What is X ?

(1)

CHO

CH2 COOH (2) BrCH2—COOH

(3) CHO—CHO (4) (CH3CO)2O56. The number of P–O–P and P–O–H bonds

present respectively in pyrophosphoric acidmolecule are :-(1) 2, 2 (2) 1, 4(3) 1, 6 (4) 1, 2

57. A metal oxide AB has a formula A0.90

O in

which A is present in A(+2) and A(+3) form.

Find the % of A(+2) present :-

(1) 33.33% (2) 66.66%

(3) 77.77% (4) 90%58. Which is not the correct statement for a catalyst:

(1)It does not alter Ea(2)It provides an alternate mechanism with a

lower energy of activation(3)Catalyst may form intermediates with the

reactants(4) Action of enzyme catalyst is always specific

59. Which is most basic :-

(1) NH –C–NH2 2

NH

(2) NH –C–CH2 3

NH

(3) NH –C–CH2 3

O(4) NH2

60. By which process blackened oldhead paintings

(by action of H2S) restores the color by H2O2:-

(1) By converting PbO2 to Pb

(2) By oxidising PbS to PbSO4

(3) By converting PbCO3 to Pb

(4) By oxidising PbSO3 to PbSO4

54. C2H4(g), CO2(g) rFkk H2O(l) dh 25°C rFkk 1atmnkc ij laHkou ,UFkSYih ds eku Øe'k% 52, –394 rFkk–286 kJ mol–1 gSA C2H4 (g) dh ngu ,UFkSYih dk ekugksxk :(1) +141.2 kJ mol–1 (2) +1412 kJ mol–1

(3) –141.2 kJ mol–1 (4) –1412 kJ mol–1

55. MeO CHO + X (i) CH3COONa/D(ii) H2O

MeO CH=CH COOH

X D;k gS ?

(1)

CHO

CH2 COOH (2) BrCH2—COOH

(3) CHO—CHO (4) (CH3CO)2O

56. ik;ksjkQkWLQksfjd vEy ds v.kq esa P–O–P o P–O–H

cU/kksa dh la[;k Øe'k% gS :-

(1) 2, 2 (2) 1, 4

(3) 1, 6 (4) 1, 2

57. ,d /kkfRod vkWDlkbM AB dk lw= A0.90

O gS ftlesaA, A(+2) rFkk A(+3) ds :i esa mifLFkr gSA blesa mifLFkrA(+2) dk izfr'kr D;k gksxk :-(1) 33.33% (2) 66.66%

(3) 77.77% (4) 90%58. fuEu esa ls dkSulk mRizsjd ds fy, lgh dFku ugha gS &

(1) ;g Ea dks ifjofrZr ugha djrk gS(2) ;g de lfØ;.k ÅtkZ dh fØ;kfof/k dks fodflr

djrh gS(3) vfHkdkjd ds lkFk e/;orhZ dk fuekZ.k djrk gS(4) ,Utkbe mRizsjd dh fØ;k ges'kk fof'k"B gksrk

gSA59. dkSu lokZf/kd {kkjh; gS :-

(1) NH –C–NH2 2

NH

(2) NH –C–CH2 3

NH

(3) NH –C–CH2 3

O(4) NH2

60. fuEufyf[kr fdl izØe ls H2O2 }kjk dkyh ysM dh isafVx(H2S dh fØ;k) dk jax iqu% izkIr fd;k tkrk gS%&(1) PbO2 dks Pb esa ifjo£rr djds(2) PbS dks PbSO4 esa vkWDlhÏr djds(3) PbCO3 dks Pb esa ifjo£rr djds(4) PbSO3 dks PbSO4 esa vkWDlhÏr djds

E / H 13/33

24–05–2012



MAJOR TEST : AIIMS

61. The volumes of 4 N HCl and 10 N HCl required

to make 1 litre of 6 N HCl are :-

(1) 0.75 litre of 10 N HCl and 0.25 litre of 4 N HCl




62. Which of the following has been arranged in

order of increasing oxidation number of

nitrogen ?

(1) NH3 < N2O5 < NO < N2

(2) NH4+ < N2H4 < NH2OH < N2O

(3) NO2+ < NO3

– < NO2– < N3

–

(4) NO2 < NaN3 < NH4+ < N2O

63.CH3

+X2Fe

Dark A + B

A & B can be easily separated because theyhave :-

(1) Large difference in Melting point

(2) Large difference in solubility

(3) Large difference in boiling point

(4) Large difference in dipole moment

64. Oxone is :-

(1) Ozone with oxygen

(2) Sodamide

(3) Sodium peroxide

(4) Hydrogen peroxide + ozone

65. Depression in freezing point of 0.01 metal

equous HCOOH solution is 0.02046 1 molal

aqueous Urea solution freezes at – 1.86°C,

assuming molality equal to molarity, pH of

HCOOH solution is :-

(1) 2 (2) 3

(3) 4 (4) 5

61. ,d yhVj 6 N HCl cukus ds fy, 4 N HCl vkSj10 N HCl ds fdrusa vk;ruksa dh vko';drk gksxh :-

(1) 10 N HCl, 0.75 yhVj rFkk 0.25 yhVj 4 N HCl

(2) 4 N HCl, 0.25 yhVj rFkk 0.75 yhVj 10 N HCl

(3) 4 N HCl , 0.67 yhVj rFkk 0.33 yhVj 10 N HCl

(4) 4 N HCl , 0.80 yhVj rFkk 0.20 yhVj 10 N HCl

62. fuEu esa ls dkSulk ukbV ªkstu ds vkWDlhdj.k vad ds c<+rs gq,Øe gS ?

(1) NH3 < N2O5 < NO < N2

(2) NH4+ < N2H4 < NH2OH < N2O

(3) NO2+ < NO3

– < NO2– < N3

–

(4) NO2 < NaN3 < NH4+ < N2O

63.CH3

+X2Fe

Dark A + B

A ,oa B dks vklkuh ls iFkd fd;k tk ldrk gS D;ksafd buds :-

(1) xyukad esa vf/kd vUrj gksrk gSA

(2) foys;rk esa vf/kd vUrj gksrk gSA

(3) DoFkukad esa vR;f/kd vUrj gksrk gSA

(4) f}/kqzo vk?kw.kZ eas vf/kd vUrj gksrk gSA

64. vksDlksu gS :-

(1) vkWDlhtu ds lkFk vkstksu

(2) lksMkekbM

(3) lksfM;e ijkWDlkbM

(4) gkbMªkstu ijkDlkbM + vkstksu

65. 0.01 eksyy tyh; HCOOH foy;u dk fgekad esa

voueu 0.02046 gS 1 eksyy ;wfj;k dk tyh; foy;u

– 1.86°C rki ij terk gS ;fn eksyyrk rFkk eksyjrk dk

eku leku gks rks] HCOOH foy;u dk pH gksxk :-

(1) 2 (2) 3

(3) 4 (4) 5

24–05–2012



MAJOR TEST : AIIMS

66. Among the following, the least stableresonance structure is :-

(1) N

O

O

(2) NO

O

(3) NO

O

(4) NO

O

67. "Denaturation of alcohol" is :-(1) Fermentation of alcohol

(2) C6H12O6 Zymase 2C2H5OH + 2CO2

(3) Mixing some copper sulphate & pyridine(4) All of the above

68. AlCl3 exist in form of dimer when :-(1) Dissolved in water(2) Dipped in ice(3) Heated above 747°C(4) Dissolved in benzene

69. It has been observed that gaseous hydrogen

chloride is a very poor conductor of electricity

but a solution of hydrogen chloride gas in water

is a good conductor of electricity. This is due

to the fact that :-

(1) Water is good conductor of electricity

(2) Hydrogen chloride gas in water solution

ionizes

(3) A gas is non-conductor but a liquid

conducts electricity

(4) Gas does not obey Ohm's law whereas

solution does70. Hyperconjugation involves overlap of the

following orbitals :-(1) s - s (2) s - r(3) r - r (4) All

66. fuEu eas dkSu U;wure LFkkbZ vuquknh lajpuk gS :-

(1) N

O

O

(2) NO

O

(3) NO

O

(4) NO

O

67. ",Ydksgy dk fod`frdj.k" gS :-(1) ,Ydksgy dk fd.Mou

(2) C6H12O6 Zymase 2C2H5OH + 2CO2

(3) blesa dqN dkijlYQsV ,oa fijhMhu feykuk(4) mijksDr lHkh

68. AlCl3 f}yd ds :i esa jgrk gS tc :-

(1) ty esa ?kksyk tkrk gS(2) cQZ esa j[kk tkrk gS(3) 747°C ls mij xeZ fd;k tkrk gS(4) csathu esa ?kksyk tkrk gS

69. ;g ns[kk x;k gS fd xSlh; gkbMªkstu DyksjkbM fo|qrdk cgqr nqcZy lqpkyd gS ysfdu gkbMªkstu DyksjkbMdk tyh; foy;u fo|qr dk vPNk lqpkyd gSA bldk

lgh dkj.k gS :-

(1) ty fo|qr dk vPNk lqpkyd gS

(2) gkbMªkstu DyksjkbM xSl tyh; foy;u esa vk;fur gks

tkrh gSA

(3) ,d xSl fo|qr dh dqpkyd gS ysfdu ,d nzo fo|qr

dk lqpkyd gSA(4) ,d xSl vkse ds fu;e dk ikyu ugha djrh tcfd

foy;u djrk gSA70. vfrla;qXeu esa fuEu d{kdksa dk vfrO;k;u gksrk gS :-

(1) s - s (2) s - r

(3) r - r (4) All

LoLFk jgks] eLr jgks rFkk i<+kbZ esa O;Lr jgks A

E / H 15/33

24–05–2012



MAJOR TEST : AIIMS

71. Vitamin B6 is :-(1) Thiamine (2) Riboflavin(3) Pyridoxine (4) Ascorbic acid

72. In seperation of zero gases from air in whichmethod CaC2 + N2 is used :-(1) Ramsay method(2) Rayleigh method(3) Adsorption method(4) Fisher ring method

73. By how much is the oxidising power of

Cr2O7–2/Cr+3 couple decreased if the H+

concentration is decreased from 1 m to 10–3m

at 25°C :-

(1) 0.001 V (2) 0.207 V

(3) 0.441 V (4) 0.414 V

74.OH H/D

X[Mixture]

Br2

Mixture gives 5 compounds of molecularformula C4H8Br2. No. of compounds X will be:-(1) 2 (2) 3 (3) 4 (4) 5

75.Polymerisation

HNC O

CH2

CH2CH2

H2C

H2CPolymer;

Polymer is :-(1) Nylon-6,6 nylon-6,6 (2) Nylon-6 nylon-6(3) Nylon-2-nylon-6 (4) Nylon-2-nylon-2

76. N–O–N linkage is present in :-(1) N2O5 (2) N2O3 (3) N2O (4) All

77. Rate of the given reaction,

(i) A + B 1r 0.05=¾¾¾® X

(ii) X + B 2r 0.89=¾¾¾® Y

(iii) Y + A 3r 0.001=¾¾¾¾® (AY)

(iv) AY + B 4r 0.10=¾¾¾® AYB

will be determined by

(1) Step (i) Because the reaction starts with the

formation of X

(2) Step (ii) because it is fastest step

(3) Step (iii) because it is the slowest step

(4) Step (iv) because it ends the reaction

71. foVkehu B6 gS :-(1) fFk;kehu (2) jkbcks¶yksfou(3) ikbjhMksDlhu (4) ,LdWkfcZd vEy

72. 'kwU; xSlka s ds ok;q ls izFkDdj.k es a fdl fof/k esaCaC2 + N2 iz;qä gksrk gS :-(1) jkels fof/k(2) jsysfof/k(3) vf/k'kks"k.k fof/k(4) fQ'kj fjax fof/k

73. 25°C rki ij ;fn H+ vk;u dh lkUnzrk 1 M ls

10–3 M rd ?kVk nh tk;s rks] Cr2O7–2/Cr+3 ;qXe dh

vkWDlhdkjd lkeF;Z fdruh ?kV tk;sxh :-(1) 0.001 V (2) 0.207 V

(3) 0.441 V (4) 0.414 V

74.OH H/D

X[Mixture]

Br2

feJ.k C4H8Br2 v.kqlw= okys 5 ;kSfxd nsrk gS] X ;kSfxdksa

dh la[;k gksxh :-(1) 2 (2) 3 (3) 4 (4) 5

75.Polymerisation

HNC O

CH2

CH2CH2

H2C

H2CPolymer;

Polymer gS :-(1) ukbyksu-6,6 ukbyksu-6,6 (2) ukbyksu-6 ukbyksu-6(3) ukbyksu-2-ukbyksu-6 (4) ukbyksu-2-ukbyksu-2

76. N–O–N lfU/k fdl v.kq esa mifLFkr gS :-(1) N2O5 (2) N2O3 (3) N2O (4) All

77. nh xbZ vfHkfØ;k dh nj

(i) A + B 1r 0.05=¾¾¾® X

(ii) X + B 2r 0.89=¾¾¾® Y

(iii) Y + A 3r 0.001=¾¾¾¾® (AY)

(iv) AY + B 4r 0.10=¾¾¾® AYB

dk fu/kkZj.k gksxk(1) in (i) ls D;ksafd vfHkfØ;k X ds fuekZ.k ds lkFk 'kq:

gksrh gS(2) in (ii) ls D;ksafd ;g lcls rst in gS(3) in (iii) ls D;ksafd ;g lcls /khek in gS(4) in (iv) ls D;ksafd ;g vfHkfØ;k lekIr djrk gS

24–05–2012



MAJOR TEST : AIIMS

78.Me Me

HNO

Br2Fe

?

Major product in this reaction is :-

(1)

Me MeHN

O

Br

(2)

Me MeHN

O

Br

(3)

Me MeHN

O

Br

(4) Me Me

HNO

Br

79. H3BO3 when dissolve in D2O, it gives :-(1) H3O

+ (2) D3O+

(3) HOD (4) None of these80. In the graph element M form which types of

oxalates :-

At. volume

At. wt.

M×

(1) M2C2O4 (2) M2(C2O4)3

(3) M3(C2O4)2 (4) MC2O4

78.Me Me

HNO

Br2Fe

?

bl vfHkfØ;k esa eq[; mRikn gksxk :-

(1)

Me MeHN

O

Br

(2)

Me MeHN

O

Br

(3)

Me MeHN

O

Br

(4) Me Me

HNO

Br

79. H3BO3 tc D2O esa ?kqyrk gS] rks nsrk gS :-(1) H3O

+ (2) D3O+

(3) HOD (4) buesa ls dksbZ ugha80. xzkQ ds vuqlkj rRo M fdl izdkj ds vkWDlsysV

cuk,xk :-

M×ij- vk;ru

ij- Hkkj(1) M2C2O4 (2) M2(C2O4)3

(3) M3(C2O4)2 (4) MC2O4

fdlh iz'u ij nsj rd :dks ugha A

E / H 17/33

24–05–2012



MAJOR TEST : AIIMS

81. O;k/k irax fdlls NqVdkjk fnykus esa vR;Ur ykHkizn gS ?(1) ,fQM (2) ePNj(3) frryh dk ykokZ (4) 1 rFkk 2

82. fuEu esa ls dkSulk izksVhu ds oyu o ifjogu ls lEcfUèkrgS :-(1) jkbckstkbe (2) iksjhUl(3) vkf.od pSisjkWUl (4) Transcription factor

83. laogu iwy ftlesa ,d tkbye dk lewg ,oa ,d ¶yks,edk lewg ,d gh f=T;k ij rFkk tkbye eTtk ds ikl o

¶yks,e oYdqV ds ikl rFkk nksuksa] ,/kk }kjk i`Fkd jgrs gSa]

dgykrk gS :-

(1) vjh;(2) la;qDr] laikf'Zod o o/khZ

(3) la;qDr laikf'Zod o vo/khZ

(4) ladsUæh84. dod dks fdl vk/kkj ij 'kSoky ls iFkd fd;k tkrk gS:-

(1) ekbVksdksf.Mª;k dh vuqifLFkfr

(2) dksf'kdk f>Yyh dk lsY;qyk sl dk cuk gk suk o

DYkksjksfQy dh vuqifLFkfr

(3) dsUnzd mifLFkr gksrk gSA

(4) dksf'kdk fHkfÙk dkbfVu dk cuk gksuk o DyksjksfQyvuqifLFkr

85. jkD;wQksVZ pht esa ik;s tkus okys cM+s cM+s fNæ fdlds dkj.kgksrs gS ?(1) izksfivksfucsDVhfj;e(2) isuhlhyh;e dsesecVhZ(3) L;wMkseksukl(4) mijksDr esa ls dksbZ ugha

86. lkbZ LFky gksrs gS :-(1) iqu%;ksZtu ds gksV LFky(2) DNA jsIyds'ku ds fy, LFky(3) DNA iksyhesjst II ds fy, cU/ku LFky(4) VªkUlfØI'ku ds fy, izkjEHku LFky

87. ;fn rus ds 'kh"k Z esa V~;wfudk dh ,d ls vf/kd ijrsagks a] rc fuEufyf[kr esa ls D;k gksus dh vf/kd lEHkkoukgk sxh ?(1) lHkh ijrsa] oYdqV dh dksf'kdkvksa esa fodflr gksaxh(2) lHkh ijrs a] ckãRopk dh dksf'kdkvks a esa fodflr gk saxhA(3) ckgj dh ijr] ckãRopk ,oa dkWVsZDl dh dksf'kdkvksa

esa fodflr gksxhA(4) lcls ckgjh ijr] ckãRopk dk fuekZ.k djrh gS ,oa

'ks"k irsZa ] dkWilZ ds lkFk feydj vU; çdkj ds Årdcukrh gSaA

81. Dragonflies are useful to get rid of ?(1) Aphids (2) Mosquitoes(3) Butterfly larva (4) 1 & 2

82. Which of the following is responsible forfolding & transportation of a protein :-(1) Ribozyme (2) Porins(3) Molecular chaperones (4) Transcription factor

83. A vascular bundle in which a group of xylemand a group of phloem are on the same radiuswith xylem near the pith and phloem near thecortex and the two separated by the cambium,called as :-(1) Radial(2) Conjoint collateral and open(3) Conjoint collateral and closed(4) Concentric

84. Fungi can be distinguished from algae by thefact that :-(1) Mitochondria are absent(2) Cell wall is cellulosic and chlorophyll i s

absent(3) Nucleus is present(4) Cell wall is chitinous and chlorophyll

isabsent85. Large holes in Roquefort cheese are due to the

activity of ?(1) Propionibacterium sharamanii(2) Penecillium camemberti(3) Pseudomonas(4) None of these

86. Chi sites are the :-(1) hot spots for recombination(2) sites for DNA replication(3) sites for binding of DNA polymorase II(4) Sites for initiaion of transcription

87. If there is more than one tunica layers, in the

stem apex, then which among the following ismost likely to happen ?(1) All the layers will develop into cortical cells(2) All the layers will develop into the epidermal

cells(3) The outer layer will develop into epidermal

and cortical cells(4) The outer most layer forms the epidermis

and remaining layers, form another type oftissues with the association of corpus

24–05–2012



MAJOR TEST : AIIMS

88. Serology-the antigen and antibody reaction, isused to find out the phylogenetic relationshipsof organisms. The antibody interacts against :-

(1) The protein which are structurally simillarto antigen which induced the formation ofthat particular antibody

(2) All the proteinaceous structures

(3) Other antibodies obtained from a differentsource

(4) Only the animal proteins

89. Australian marsupiale resemble the placentalmammals of same or different continent. Thisindicate that when more than one adaptiveradiations found in an isolated geographicalarea, than we called it :-

(1) Divergent evolution

(2) Convergent evolution

(3) Mega evolution

(4) Micro evolutiona

90. First strand cDNA synthesis requires :-

(1) T4 DNA ligase

(2) Reverse transcriptase

(3) Klenow enzyme

(4) E.coli DNA polymerase

91. Which of the following statement is correct withrespect to Rana tigrina ?

(a) Urinary bladder is dorsal to the rectum andopens in the cloaca

(b) 1 pair vasa efferentia enters in kidney andopen into Bidder's canal

(c) Ovaries have no functional connection withkidneys

(d) Eyes are simple possessing only oneunit

(1) a & b (2) b & c

(3) c & d (4) a, c & d

92. Catalytic converter is used in automobiles :

(1) For removing the poisonous lead

(2) For converting CO and harmful

hydrocarbons into CO2 and water vapours

(3) For removing water from air

(4) For removing organic matter from lake

88. lhjksyksth (,UVhtu&,UVhcksMh fØ;k) }kjk lthoksa ds

tkfro`rh; lEcU/k Kkr fd;s tkrs gSA ,UVhcksMh fdlds

f[kykQ fØ;k djrh gS :-

(1) mu izksVhu ds f[kykQ tks lajpuk esa ml ,UVhtu ds leku

gksrs gS ftlus ,UVhcksMh fuekZ.k dks izsfjr fd;k gS

(2) lHkh izksVhu ;qä lajpukvksa ds f[kykQ

(3) nwljh ,UVhcksMh ds f[kykQ ftudks fdlh vU; òksr lsizkIr fd;k x;k gS

(4) dsoy tUrq izksVhu ds f[kykQ89. vkLVªsfy;k ds eklqZfi,y mlh ;k nwljs egk}hi ds vijk

Lru/kkfj;ksa ls lekurk iznf'kZr djrs gSaA ;g iznf'kZr djrk gSfd tc ,d vyx Fkyx HkkSxksfyd {ks= esa ,d ls vf/kdvuqdwyh fofdj.k ik;s tkrs gSa rc ge bls dg ldrs gSa :-

(1) vilkfjr fodkl

(2) vfHklkfjr fodkl

(3) esxk mf}dkl

(4) lw{e mf}dkl

90. cDNA dh izFke LVªs.M ds la'ys"k.k ds fy, vko';d gS :-(1) T4 DNA ykbxst(2) fjolZ VªkWUlfØIVst(3) DyhukWo ,Utkbe(4) E.coli DNA iksyhesjst

91. fuEu esa ls dkSulk dFku Rana tigrina ds lanHkZ esa lR;gS ?

(a) ew=k'k;] eyk'k; ds v/kj Hkkx ij fLFkr gksrk gS rFkkvoLdj esa [kqyrk gS

(b) ,d tksM+h 'kqØ okfgdk,a] o`Dd esa izos'k djrh gS rFkkfcMj uky esa [kqyrh gS

(c) v.Mk'k; dk oDd ls dksbZ fØ;kRed laca/k ugha gksrkgSA

(d) us= lk/kkj.k gksrs gS tks dsoy ,d bZdkbZ dh rjg dk;Zdjrs gSA

(1) a rFkk b (2) b rFkk c

(3) c rFkk d (4) a, c rFkk d

92. dsVkfyfVd duojVj (dsVkfyfVd ifjorZd) dkvksVkseksckbYl (Lopkfyr okguksa) esa mi;ksx fd;k tkrk gS%&(1) tgjhys lhls dks gVkus ds fy,(2) gkfudkjd gkbMªksdkcZUl rFkk CO dks CO2 rFkk ty

ok"i esa ifjofrZr djus ds fy,(3) ok;q ls ty dks gVkus ds fy,(4) dkcZfud inkFkZ dks >hy ls gVkus ds fy,

J ges'kk eqLdjkrs jgsa A

E / H 19/33

24–05–2012



MAJOR TEST : AIIMS

93. Miller used a mixture of H2, NH3, CH4 andwater vapour in his experiment. Heat isproduced by electric discharge. He heated thismixture at :-(1) 100°C (2) 500°C(3) 800°C (4) 1800°C

94. Intron splicing of nuclear m-RNA occurs :-(1) In the nucleus(2) On polysomes at the start of translation(3) After transport into cytoplasm(4) In cytoplasm

95. DCMU, PARAQuat treated a plant producesATP in sunlight by process of :-(1) Photosynthesis(2) Respiration(3) Both(4) Non cyclic photophosphorylation

96. Biological equilibrium is an equilibriumamongst :(1) Producers and decomposers(2) Producers and consumers(3) Producers, consumers and decomposers(4) Consumers and decomposers

97. Which of the following statement/s is/are true:-(1) In veins chloride ions are more in RBC than

plasma(2) The enzyme carbonic anhydrase is found

in both plasma and RBC(3) A person can not expire whole the air from

lungs(4) All statements are true

98. A nucleotide has three distinct component, oneis a heterocyclic compound, second is aphosphoric acid and the third is a ............ :-(1) Monosaccharide (2) Disaccharide(3) Trisaccharide (4) All the above

99. What is the final Hydrogen acceptor inRespiratory chain :-(1) Thylakoid (2) Oxygen(3) Cytochrome (4) H2O

100. Dunaliella species found in hyper saline lakecan tolerate saline conditions by accumulating:-(1) Glycerol in the cells(2) Proline in the cells(3) Chaperonins in the cells(4) All the above

93. feyj us vius iz;ksx esa H2, NH3, CH4 vkSj tyok"i dk

feJ.k fy;kA m"ek fo|qr LQqfyax }kjk mRiUu dh xbZA bUgksus

bl feJ.k dks fdl rki ij xeZ fd;k :-

(1) 100°C (2) 500°C

(3) 800°C (4) 1800°C

94. U;wfDy;j m-RNA dh bUVªkWu Liykbflax gksrh gS :-(1) dsUæd esa(2) iksyhlkse ij tgk¡ ls vuqoknu izkjEHk gksrk gS(3) dksf'kdk æO; esa LFkkukUrfjr gksus ds ckn(4) dksf'kdk æo esa

95. DCMU, isjkDosV mipkfjr ikS/kk izdk'k esa ATP mRiknufdl izfØ;k }kjk djsxk :-(1) izdk'k la'ys"k.k(2) 'olu(3) nksuksa(4) vpfØ; izdk'k QksLQksfjfydj.k

96. tSfod lkE;rk fdlds chp dh lkE;rk gS %&

(1) mRiknd vkSj vi?kVudkjh

(2) mRiknd vkSj miHkksDrk

(3) mRiknd] miHkksDrk] vkSj vi?kVudkjh

(4) miHkksDrk vkSj vi?kVudkjh97. fuEu esa ls dkSulk@dkSuls dFku lR; gS :-

(1) f'kjkvksa esa DyksjkbM vk;u IykTek ls RBC esa vf/kd

gksrs gSa

(2) IykTek vkSj RBC nksuksa esa dkcksZfud , sugkbMªst ,Utkbe

ik;k tkrk gSA

(3) ,d O;fDr lEiw.kZ ok;q dks cfg'olfur ugha dj ldrkA

(4) lHkh dFku lR; gS98. ,d U;wfDy;ksVkbM esa rhu Li"V ?kVd gksrs gS ,d ?kVd

fo"ke pØh; ;kSfxd] nwljk ?kVd QkWLQksfjd vEy rFkkrhljk ?kVd gksrk gS ............ :-(1) eksukslsdsjkbM (2) MkblSdsjkbM(3) VªkblSdsjkbM (4) mijksDr lHkh

99. 'olu Ük ` a[kyk e s a v a fre gkbM ª k stu x z kgh gk srkgS :-(1) Thylakoid (2) Oxygen(3) Cytochrome (4) H2O

100. MwusySyk tkfr mPp yo.kh;rk okyh >hy esa ik;h tkrh gS]tks mPp yof.k;rk dks lgu dj ldrh gS %&(1) dksf'kdkvksa esa fXyljksy ,df=r djds(2) dksf'kdkvksa esa izksyhu ,df=r djds(3) dksf'kdkvksa esa dsijksfuUl ,df=r djds(4) mijksDr lHkh

24–05–2012



MAJOR TEST : AIIMS

101. Which of the following is correctly matchedpair :-(1) Microvilli : Stomach and intestine(2) Ligament and tendons :

Dense regular connective tissue(3) Cilia : Fallopian tube and buccal cavity(4) Hyaline cartilage : Ear pinna, Pliable matrix

102. Adenine and guanine are :-(1) Subtituted purines(2) Subtituted pyrimidine(3) Subtituted methane(4) Polysaccharide

103. Which pair is wrong :-(1) Gibberellin - Increase the length of grape

statics(2) Ethylene - Flowering in pineapple(3) Auxin - First isolated from oat(4) ABA - Stress Hormone

104. The functioning of an ecosystem is governedby:-(1) The interactions of plants and animals(2) Small population size(3) The climatic and edaphic factor(4) The interaction of decomposers and biota

105. According to circulatory system of vertebratewhich of the following is correct match pair :-(1) Hepatic portal vein : Transport urea from

liver to IVC(2) Dorsal aorta : transport O2 and nutrients

towards systemic organs(3) Renal portal vein : Transport O2 and

nutrients towards kidney(4) Carotid artery : Supply oxygenated blood

to heart musculature106. Which of the following is respiratory organ of

silkworm?(1) External gills(2) Pulmonary sac(3) Body wall(4) Trachea and spiracles

107. During photophosphorylation, protonsaccumulated towards the inside of membrane of:-(1) Mesosome(2) Thylakoid(3) Intermembrane space(4) Chromoplast

101. fuEu esa ls dkSulk lgh feyku ; qXe gS :-

(1) lw{ekadqj : vkek'k; vkSj vka=

(2) Luk;q vkSj daMjk : l?ku fu;fer ;ksth mÙkd

(3) i{e : Qsyksfi;u ufydk vkSj eq[k xqgk

(4) dkpkHk mikfLFk : d.kZ iYyo] vkuE; vk|k=h

102. ,Msfuu o xqvkfuu gS :-(1) izfrLFkkih I;wjhu(2) izfrLFkkih ikbjhehMhu(3) izfrLFkkih esFksu(4) iksyhlSdsjkbM

103. dkSulh tksM+h xyr gS :-(1) Gibberellin - vaxwj ds o`Urksa dh yEckbZ esa

o`fð(2) Ethylene - vukukl esa iq"ihdj.k(3) Auxin - loZizFke tbZ ls i`FkDÏr(4) ABA - ruko gkWeksZu

104. ikfjfLFkfrdh ra= dh fØ;k izHkkfor gksrh gS %&

(1) ikS/kksa vkSj tkuojksa ds chp ikjLifjd fØ;k }kjk

(2) NksVk lef"V vkeki

(3) tyok;q o e`nk lEcfU/k dkjd }kjk

(4) vi?kVd vkSj tSo leqnk; ds chp kjLifjd fØ;k }kjk105. d'ks:fd;ksa ds ifjlapj.k ra= ds vuqlkj fuEu esa ls dkSulk

lgh feyku ;qXe gS :-(1) ;Ïr fuokfgdk f'kjk : ;Ïr ls IVC rd ;wfj;k dk

ifjogu(2) i`"B egk/keuh : O2 rFkk iks"kdksa dk nSfgd vaxksa dh rjQ

ifjogu(3) o`Dd fuokfgdk f'kjk : o`Dd dh rjQ O2 vkSj iks"kdksa

dk ifjogu(4) dsjksfVM /keuh : án; isf'k;ksa dks vkWDlhtfur jDr dks

vkiwfrZ106. fuEufyf[kr dkSulk js'kedhV dk 'olu vax gS?

(1) cká Dykse

(2) iYeksujh dks"k(3) nsgfHkfr

(4) Vªsfd;k o Likbjsdy107. izdk'k QksLQksfjfydj.k ds nkSjku izksVksu dk laxzg.k fdldh

f>Yyh ds Hkhrjh rjQ gksrk gS :-(1) Mesosome(2) Thylakoid(3) Intermembrane space(4) Chromoplast

viuh {kerk dks iwjk olwyus dk iz;kl djsa A

E / H 21/33

24–05–2012



MAJOR TEST : AIIMS

108. The property of 'memory' of immune systemis used in(1) Agglutination (2) Vaccination(3) Grafting (4) Infection

109. Which of the following is an example of firstclass lever ?(1) Forward walking(2) Atlanto-occipital joint(3) Elbow joint(4) Human body resting on toe

110. Indicate the wrong pair in the following:-(1) Paramoecium - Trichocyst(2) Aurelia - Cnidoblast(3) Pila - Muscular foot(4) Balanoglossus - Tunicate

111. Prokaryotic cell wall is made up of :-(1) Cellulose (2) Hemi cellulose(3) Peptidoglycan (4) Glycogen

112. Which is/are the example/s of Psychologicaldisorders ?(a) Anxienty(b) Obsersive-compulsive disorder(c) Schizophrenia(d) Borderline personality disorder(e) Attention deficit disorder(f) mood disorders(1) c,d (2) b,c,d(3) a,b,c,e (4) a,b,c,d,e,f

113. Which of the following set is correct :-(1) Medicinal plant - Muliathi, indiofera(2) Fodder plant - Sesbania; Trifolium(3) Dye - Sunhemp(4) Spice - Tobacco, Petunia

114. The endosperm of Angiosperm differ from thatof Gymnosperm in that it:-(1) Is triploid(2) Only lasts a few days(3) Does not form until fertilization take place(4) Both 1and 3

115. In Non cyclic photophosphorylation PS-I isreduced by :-(1) Electrons from ferredoxin(2) Electrons from PS-II(3) Hydrogen from water(4) Hydrogen from PS-II

108. izfrj{kkra= dk ^Lefr* xq.k dk mi;ksx fdlesa gksrk gS\

(1) ,XyqfVus'ku esa (2) Vhdkdj.k esa

(3) xzkf¶aVx esa (4) laØe.k esa

109. fuEu ls dkSulk izFke Js.kh mÙkksyd dk mnkgj.k gS ?

(1) lEeq[k ?kweuk

(2) ,sVysUVks&vkWDlhihVy laf/k

(3) dksguh laf/k

(4) ekuo 'kjhj dk iatksa ij [kM+s gksuk110. fuEufyf[kr esa xyr ; qXe dks fpfUgr dhft;s:-

(1) isjkehfl;e - VªkbdksflLV(2) vkWjsfy;k - fuMksCykLV(3) ikbyk - is'kh; ikn(4) csysuksXyksll - V;wuhdsV

111. izksdSfj;ksfVd dksf'kdk fHkfÙk fdlls cuh gksrh gS:-(1) Cellulose (2) Hemi cellulose(3) Peptidoglycan (4) Glycogen

112. fuEu esa ls dkSuls mnkgj.k] euksdkf;Zdh; fodkjksa ds gS ?(a) cSpsuh

(b) vkWClsflo dEiyflo fodkj

(c) lkbtksÝsfu;k

(d) ckWMZjykbu ilZfufyVh fodkj

(e) lpsrrk U;wurk fodkj

(f) ewM fodkj(1) c,d (2) b,c,d(3) a,b,c,e (4) a,b,c,d,e,f

113. fuEufyf[kr esa ls dkSulk leqPp; lgh gS%&(1) Medicinal plant - Muliathi, indiofera(2) Fodder plant - Sesbania; Trifolium(3) Dye - Sunhemp(4) Spice - Tobacco, Petunia

114. ,fUt;ksLieZ dk Hkz w.kdks"k] ftEuksLieZ ls fHkUu gksrk gSD;ksfd ;g:-(1) f=xqf.kr gksrk gSA(2) dqN fnuksa rd gh lhfer jgrk gSaA(3) tc rd fu"kspu ugha gksrk gS bldk fuEkkZ.k ugha gksrk gSaA(4) 1 o 3 nksuksa

115. vpØh;&QksVksQksLQksjhyslu esa PS-I dks fdlds }kjkvipf;r fd;k tkrk gS :-(1) QsjsMkWfDlu ds bysDVªkWu ls(2) PS-II ds bysDVªkWu ls(3) ty ds gkbMªkstu ls(4) PS-II ds gkbMªkstu ls

Time Management is Life Management

24–05–2012



MAJOR TEST : AIIMS

116. A.D.H. is also called vasopressin because :-(A) It maintains B.P. through vasoconstriction

(B) It regulares electrolytes

(C) It works during high B.P.

(D) It comes under demand during hypervolumea

(1) A & D (2) A & B(3) C & D (4) A & C

117. Which of the following change is not foundduring insect's spermateleosis(1) Nacleus ¾® Head(2) Mitochondria ¾® Mid piece(3) Distal centriole ¾® Annulus(4) Golgi apparatus ¾® Acrosomic cap

118. In which of the following flower of plant, fliesare trapped like in ''prison''?(1) Salvia (2) Yucca(3) Aristolochia (4) Kigelia

119. What change occured during evolution ofsporophyte in plant kingdom :-(1) Gradual sterilisation of gametophytic tissues(2) Gradual sterilisation of sporophytic tissues(3) Gradual reduction of sporophyte(4) Gradual increase of fertile part of

sporophytic tissues120. Which one does't include cerebrum :-

(1) Hippocampal lobe (2) Lymbic lobe(3) Ameygdala lobe (4) Cerebral aquaduct

DIRECTIONS FOR Q. NO. 121 TO 180

These questions consist of two statements each,printed as Assertion and Reason.Whileanswering these Questions you are required tochoose any one of the following four responses.

A. If both Assertion & Reason are True & theReason is a correct explanation of the Assertion.

B. If both Assertion & Reason are True but Reasonis not a correct explanation of the Assertion.

C. If Assertion is True but the Reason is False

D. If both Assertion & Reason are false.

121. Assertion :- Focal length of lens for red colouris more then violet colour.

Reason :- Because 1f

= (µ – 1)1 2

1 1R R

æ ö-ç ÷è ø.

(1) A (2) B (3) C (4) D

116. A.D.H. dks oslksizslhu Hkh dgrs gS] D;ksafd :-(A) ;g B.P. dks oslksdksUlVªhD'ku }kjk fu;af=r djrk gS(B) ;g bysDVªksykbV~l dks fu;fer djrk gS(C) ;g mPp B.P. esa dk;Z djrk gS(D) ;g ml le; vko';d gksrk gS tc gkbijoksY;qfe;k

gksrk gS(1) A & D (2) A & B(3) C & D (4) A & C

117. dhV ds LieSZVhfy;ksfll ds nkSjku dkSulk ifjorZu ugha gksrkgS -(1) dsUæd ¾® flj(2) ekbVksdkWfUMª;k ¾® e/; Hkkx(3) nwjLFk lsfUVª;kWy ¾® ,uqyl(4) xksYth midj.k ¾® ,Økslkse dsi

118. fuEufyf[kr fdl ikni ds iq"i esa efD[k;ka ^tsy** dh rjgcUn gks tkrh gS?(1) lkYoh;k (2) ;qDdk(3) ,fjLVksyksfd;k (4) dkbxsfy;k

119. ikni txr esa chtk.kqmn~fHkn ds fodkl ds nkSjku D;k ifjorZu

gqvk :-

(1) ;qXeksnfHkn~ ÅÙkdksa dk Øfed cU/;kdj.k

(2) chtk.kqmn~fHkn ÅÙkdksa dk Øfed cU/;kdj.k

(3) chtk.kqmn~fHkn dk Øfed âkl

(4) chtk.kqmn~fHkn ÅÙkdksa esa tuu'khy Hkkx dh Øfed of¼120. fuEu esa ls izefLr"d dk Hkkx ugha gS :-

(1) fgIiksdsEiy fi.M (2) fyfEcd yksc(3) ,fexMsyk yksc (4) ljsfczy ,DokMDV

iz'u la[;k 121 ls 180 ds fy, funs Z'k

izR;sd iz'u es a dFku rFkk dkj.k fn, x;s gSaA iz'uks a

dks gy djrs le; uhps fn, x, pkjks a fodYiks a es als lgh fodYi dks pqfu,A

A. ;fn dFku ,oa dkj.k nksuks a lR; ga S rFkk dkj.k dFkudk lgh Li"Vhdj.k gSA

B. ;fn dFku ,oa dkj.k nksuks a lR; gaS] ysfdu dkj.k] dFkudk lgh Li"Vhdj.k ugha gSA

C. ;fn dFku lR; gS] ysfdu dkj.k vlR; gSA

D. dFku o dkj.k nksuks a vlR; gSaA

121. dFku :- yky j[kus ds fy;s ysUl dh Qksdl nwjh csaxuhls vf/kd gksrh gSA

dkj.k :- D;ksafd 1f

= (µ – 1)1 2

1 1R R

æ ö-ç ÷è ø

(1) A (2) B (3) C (4) D

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MAJOR TEST : AIIMS

122. Assertion :- In bomb explosion kinetic energyof the system increases.Reason :- Because chemical energy convertedinto kinetic energy.(1) A (2) B (3) C (4) D

123. Assertion :- Angular momentum about originfor a particle moving along x-axis is zero.

Reason :- Because line of action of momentumis passing through the origin.

(1) A (2) B (3) C (4) D

124. Assertion :- If a gas follow any of the gas lawsthen it is nessary that it will also follow idealgas equation.Reason :- All gas laws can also be derived fromideal gas equation.(1) A (2) B (3) C (4) D

125. Assertion :- The average velocity of a particleis zero in a time interval. It is possible that theinstantaneous velocity is never zero in theinterval.Reason :- The magnitude of average velocityin an interval is equal to its average speed inthat interval.(1) A (2) B (3) C (4) D

126. Assertion :- Mass of partical decrease up to 1/6

when move from earth surface to moon surface.

Reason :- gmoon = gEarth6

.

(1) A (2) B (3) C (4) D127. Assertion :- When the direction of motion of a

particle moving in a circular path is reversedthe direction of radial acceleration still remainsthe same (at the given point).Reason :- Fora particle revolving on circular pathin any direction such as clockwise oranticlockwise, the direction of radial accelerationis always towards the centre of the circular path.(1) A (2) B (3) C (4) D

128. Assertion :- The ionising power of b-particle

is less compared to a-particles but their

penetrating power is more.

Reason :- The mass of b-particle is more than

the mass of a-particle.

(1) A (2) B (3) C (4) D

122. dFku :- ce foLQksV esa fudk; dh xfrt ÅtkZ c<+rhgSAdkj.k :- D;ksafd jklk;fud ÅtkZ] xfrt ÅtkZ esa ifjorhZrgksrh gSA(1) A (2) B (3) C (4) D

123. dFku :- ,d d.k dk dks.kh; laosx ewy fcUnq ds lkis{k'kwU; gksrk gS

dkj.k :- D;ksafd laosx dh fØ;k js[kk ewy fcUnq ls tkrhgS(1) A (2) B (3) C (4) D

124. dFku :- ;fn ,d xSl fdlh Hkh fu;e dk ikyu djrhgS rks ;g vko';d gS fd ;g xSl lehdj.k dk Hkh ikyudjsxhAdkj.k :- lHkh xSl fu;eksa dk vkn'kZ xSl lehdj.k ls HkhO;qRiUu fd;k tk ldrk gSA(1) A (2) B (3) C (4) D

125. dFku :- fdlh le;kUrjky esa d.k dk vkSlr osx 'kwU; gSA

;g lEHko gS fd bl le; vUrjky esa d.k dk rkR{kf.kd

osx dHkh 'kwU; u gksA

dkj.k :- fdlh lek;kUrjky esa vkSlr osx dk ifjek.k ml

le; vUrjky esa vkSlr pky ds ifjek.k ds cjkcj gksrk gSA

(1) A (2) B (3) C (4) D

126. dFku :- i`Foh ls pUnzek dh lrg ij tkus ij nzO;eku1/6 xquk gks tkrk gSA

dkj.k :- gpUnzek = giFoh

6.

(1) A (2) B (3) C (4) D

127. dFku :- tc o`Ùkh; iFk ij xfr dj jgs d.k ds ?kw.kZu dh

fn'kk foijhr dj nh tk;s rks Hkh f=T; Roj.k vifjofrZr jgrk

gSA (fn;s x;s fcUnq ij)

dkj.k :- d.k o`Ùkh; iFk ij fdlh Hkh fn'kk esa ?kwes okekorZ

;k nf{k.kkorZ f=T; Roj.k dh fn'kk ges'kk o`Ùk ds dsUæ dh

vksj gksrh gSA

(1) A (2) B (3) C (4) D

128. dFku :- b-d.k dh vk;uhdj.k {kerk a-d.k dh rqyuk

esa de gksrh gSA ijUrq budh Hksnu {kerk a-d.k dh Hksnu

{kerk ls vf/kd gksrh gSA

dkj.k :- b-d.k dk æO;eku a-d.k dh rqyuk esa vfèkd

gksrk gSA

(1) A (2) B (3) C (4) D

24–05–2012



MAJOR TEST : AIIMS

129. Assertion :- In standing wave pattern particleof medium between two consecutive nodesvibrates in same phase but with differentamplitude.

Reason :- In stationary wave, the amplitude ofvibration does not depends on the position ofthe particle.

(1) A (2) B (3) C (4) D

130. Assertion :- Radioactivity is a nuclearphenomenon.

Reason :- Radioactivity is the phenomenon ofspontaneous emission of certain kinds ofradiations from the nuclei of the atoms of sameelements.

(1) A (2) B (3) C (4) D

131. Assertion :- In transverse wave particle velocityis perpendicular to the direction of wave velocity.

Reason :- In wave motion energy alwaystransfered in the direction of wave propagation.

(1) A (2) B (3) C (4) D

132. Assertion :- The mass of a nucleus can be eitherless than or more than the sum of the massesof nucleons present in it.

Reason :- The whole mass of the atom isconsidered in the nucleus.

(1) A (2) B (3) C (4) D

133. Assertion :- A violin note and sitar note mayhave same frequency, yet we can distinguishbetween the two notes.

Reason :- Different musical instruments anddifferent quality (Timbre)

(1) A (2) B (3) C (4) D134. Assertion :- A loosely round helix made of stiff

wire is suspended vertically with the lower endjust touching a dish of mercury. When a curentis passed through the wire, the helical wireexecutes oscillatory motion with the lower endjumping out of and inside of mercury.

Reason :- When electric current is passedthrough helix, a magnetic field is produced bothinside and outside the helix.

(1) A (2) B (3) C (4) D

129. dFku :- vizxkeh rjax izk:i esa nks Øekxr fuLianksa ds chp

ekè;e ds d.k leku dyk esa ,oa fHkUu&fHkUu vk;ke ls

dEiu djrs gSaA

dkj.k :- vizxkeh rjax esa] dEiuksa dk vk;ke d.kksa dh

fLFkfr ij fuHkZj ugh djrk gSA

(1) A (2) B (3) C (4) D

130. dFku :- jsfM;ks ,fDVork ukfHkdh; ifj?kVuk gSA

dkj.k :- ,d gh izdkj ds ijek.kq ds ukfHkd ls fuf'pr

izdkj ds fofdj.k ds Lor% mRltZu dh ?kVuk dks jsfM;ks

,fDVork dgrs gSaA

(1) A (2) B (3) C (4) D

131. dFku :- vuqizLFk rjax esa d.k osx] rjax osx dh fn'kk ds

yEcor~ gksrk gSA

dkj.k :- rjax xfr esa ÅtkZ ges'kk rjax ds xeu dh fn'kk esa

LFkkUrfjr gksrh gSA

(1) A (2) B (3) C (4) D

132. dFku :- ukfHkd dk æO;eku U;qfDyvkuksa ds æO;eku ds

;ksx dh rqyuk esa ;k rks de ;k vf/kd gks ldrh gSA

dkj.k :- ijek.kq dk lEiw.kZ æO;eku ukfHkd esa fopkj.kh;

gSA

(1) A (2) B (3) C (4) D

133. dFku :- ,d ok;fyu Loj o flrkj Loj dh leku vko`fÙk

gksrs gq, Hkh mUgsa vyx&vyx igpkuk tk ldrk gSA

dkj.k :- vyx&vyx ok|;U= vyx&vyx xq.krk j[krs

gSaA

(1) A (2) B (3) C (4) D

134. dFku :- dBksj rkjksa dh cuh ,d <hyh gsyhdy dq.Myh

dks Å/okZ/kj yVdk;k x;k gSA bldk fupyk fljk ,d ik=

esa Hkjh ejdjh dh lrg dks Bhd Li'kZ djrk gSA tc rkj ls

/kkjk izokfgr gksrh gS] rks gsyhdy rkj nksyu djus yxrk gS

vkSj bldk fupyk fljk ejdjh ds vUnj vkSj ckgj gksus

yxrk gSA

dkj.k :- tc gsyhdy dq.Myh ls /kkjk izokfgr dh tkrh gS

rc blds vUnj o ckgj pqEcdh; {ks= mRiUu gks tkrk gSA(1) A (2) B (3) C (4) D

E / H 25/33

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MAJOR TEST : AIIMS

135. Assertion :- Transistor works as an amplifieronly in active region.Reason :- Switching circuit is desined in sucha way that transistor remain in either saturationor cut off region.(1) A (2) B (3) C (4) D

136. Assertion :- Self-inductance is called the inertiaof electricity.Reason :- Self-inductance is the phenomenon,according to which an induced e.m.f. isproduced in a coil as a result of change in currentor magnetic flux linked in the coil.(1) A (2) B (3) C (4) D

137. Assertion :- In a simple battery circuit the pointat the lowest potential is positive terminal ofthe battery.Reason :- The current flows from negative tothe positive terminal.(1) A (2) B (3) C (4) D

138. Assertion :- There may be resonance in seriesLCR circuit.Reason :- When inductive reactance andcapacitive reactance are equal and oppositethen resonance occures.(1) A (2) B (3) C (4) D

139. Assertion :- An electric bulb becomes dim,when an electric heater in parallel circuit isswitched on.Reason :- Dimness decreases after sometime.(1) A (2) B (3) C (4) D

140. Assertion :- The capacity of a given conductor

remains same even if charge is varied on it.

Reason :- Capacitance depends upon nearly

medium as well as size and shape of conductor.

(1) A (2) B (3) C (4) D

141. Assertion :- In CsCl crystal the co–ordinationnumber of Cs+ ions is 6.Reason :- Cl– ion in CsCl adopt body centredcubic arrangement.

(1) A (2) B (3) C (4) D

142. Assertion :- Acetylene reacts with sodamide toevolove H2 gas.Reason :- Acetylene is weaker acid than

ammonia.

(1) A (2) B (3) C (4) D

135. dFku :- VªkaftLVj lfØ; voLFkk esa gh izo/kZd dh Hkk¡fr

dk;Z djrk gSA

dkj.k :- VªkaftLVj ls fLop ifjiFk cukrs le;] VªkaftLVj

lUr`Ir voLFkk ;k dkV voLFkk esa cuk jgrk gSA(1) A (2) B (3) C (4) D

136. dFku :- LoiszjdRo fo|qr dk tM+Ro dgykrk gSA

dkj.k :- LoizsjdRo og xq.k gSa] ftlds vuqlkj fdlh

dq.Myh ls lEc¼ /kkjk ;k pqEcdh; ¶yDl esa ifjorZu gksus

ij dq.Myh esa ,d fo-ok- cy mRiUu gks tkrk gSA

(1) A (2) B (3) C (4) D

137. dFku :- ,d ljy ifjiFk esa U;qure foHko okyk fcUnq]

cSVjh dk /kukRed fljk gksrk gSA

dkj.k :- /kkjk mPp foHko ls fuEu foHko dh vksj izokfgr

gksrh gSA

(1) A (2) B (3) C (4) D

138. dFku :- ,d LCR Js.kh ifjiFk esa vuqukn gks ldrk gSA

dkj.k :- ;fn izsj.kh; izfr?kkr ,oa /kkfjrh; izfr?kkr cjkcj

,oa foijhr gS rc vuqukn gksrk gSA

(1) A (2) B (3) C (4) D

139. dFku :- ,d fo|qr cYc ef¼e gks tkrk gS tc lekUrj

esa tqM+s gq;s ghVj dks pkyw fd;k tkrk gSA

dkj.k :- dqN le; ckn ef¼erk ?kV tkrh gSA

(1) A (2) B (3) C (4) D

140. dFku :- ,d fn, x, pkyd dh /kkfjrk leku jgrh gS

Hkys gh bldk vkos'k ifjo£rr gks tk,A

dkj.k :- /kkfjrk] lehi fLFkr ek/;e rFkk pkyd dh vkÏfr

,oa vkdkj ij fuHkZj djrh gSA(1) A (2) B (3) C (4) D

141. dFku :- CsCl fØLVy esa Cs+ vk;u dh leUo; la[;k6 gksrh gSAdkj.k :- CsCl fØLVy esa Cl– vk;u dk; dsfUnz; ?kulajpuk esa O;ofLFkr jgrk gSA(1) A (2) B (3) C (4) D

142. dFku :- ,flVhyhu lksMkekbM ls fØ;k djds H2 xSl nsrhgSAdkj.k :- ,flVhyhu] veksfu;k ls nqcZy vEy gksrkgSA(1) A (2) B (3) C (4) D

24–05–2012



MAJOR TEST : AIIMS

143. Assertion :- pH of a buffer solution does not

change on dilution.Reason :- On dilution the ratio of concentrationof salt and acid (or base) remains unchanged.

(1) A (2) B (3) C (4) D

144. Assertion :- Benzyl bromide when kept inacetone water it produces benzyl alcohol.Reason :- The reaction follows SN2

mechanism.

(1) A (2) B (3) C (4) D

145. Assertion :- 1 amu equals to 1.66 × 10–24 g.

Reason :- 1.66 × 10–24 g equals to 1

12th of

mass of a C12 atom and it is defined as 1 amu

(1) A (2) B (3) C (4) D

146. Assertion :- Anilinium chloride is more acidicthan ammonium chloride.Reason :- ammonium ion is resonance

stabilized.

(1) A (2) B (3) C (4) D

147. Assertion :- Camphor is used as solvent in the

determination of molecular masses of

naphthalene, anthracene etc.Reason :- Camphor has high molal depressionconstant.

(1) A (2) B (3) C (4) D

148. Assertion :- Octane number can be increasedby isomerisation.Reason :- Branched alkane has more octane

number than unbranched alkane.

(1) A (2) B (3) C (4) D

149. Assertion :- For the Daniel cell 2 2Zn Zn Cu+ + Cu

with Ecell = 1.1 V, the application of oppositepotential greater than 1.1 V results into flow ofelectron from cathode to anode.Reason :- Zn is deposited at anode and Cu isdissolved at cathode.

(1) A (2) B (3) C (4) D150. Assertion :- Hg vapours not shows metallic

lusture.Reason :- Lusture appears only in condensedstate.(1) A (2) B (3) C (4) D

143. dFku :- cQj foy;u dh pH, foy;u dks ruq djus ijifjofrZr ugha gksrh gSAdkj.k :- ruq djus ij yo.k rFkk vEy (;k {kkj) dhlkUnzrkvksa dk vuqikr vifjofrZr jgrk gSA(1) A (2) B (3) C (4) D

144. dFku :- csfUty czksekbM dks ,flVksu ty esa j[kus ij csfUty,sYdksgy izkIr gksrk gSA

dkj.k :- vfHkfØ;k dh fØ;kfof/k SN2 gSA

(1) A (2) B (3) C (4) D

145. dFku :- 1 amu, 1.66 × 10–24 xzke ds cjkcj gksrk gSA

dkj.k :- 1.66 × 10–24 xzke C12 ijek.kq ds Hkkj ds 1

12th

ds cjkcj gksrk gS rFkk bls 1 amu ifjHkkf"kr fd;k tkrk gS(1) A (2) B (3) C (4) D

146. dFku :- ,fufyfu;e DyksjkbM] veksfu;e DyksjkbM lsvfèkd vEyh; gksrk gSA

dkj.k :- veksfu;e vk;u vuqukn LFkk;hd`r gSA

(1) A (2) B (3) C (4) D

147. dFku :- us¶FkSyhu] ,UFkzklhu vkfn ds v.kqHkkjksa ds fu/kkZj.kesa diwj dk mi;ksx foyk;d ds :i esa gksrk gSA

dkj.k :- diwj dk mPp eksyy voueu fLFkjkad gksrkgSA

(1) A (2) B (3) C (4) D

148. dFku :- vkDVsu la[;k dks leko;ohdj.k }kjk c<+k;k tkldrk gSAdkj.k :- 'kkf[kr ,Ydsu dh vkDVsu la[;k] v'kkf[kr ,Ydsuls vf/kd gksrh gSA(1) A (2) B (3) C (4) D

149. dFku :- 2 2Zn Zn Cu+ + Cu Msfu;y lsy ds fy,

Ecell = 1.1 V gS] 1.1 V ls vf/kd foijhr foHko dsvuqiz;ksx ls dSFkksM+ ls ,uksM dh vksj bysDVªkWuksa dk izokg 'kq:gks tkrk gSAdkj.k :- Zn ,uksM ij fo{ksfir gksrk gS vkSj Cu dSFkksM+ij foys; gksrk gSA(1) A (2) B (3) C (4) D

150. dFku :- Hg ok"i /kkfRod ped O;ä ugh djrh gSA

dkj.k :- dsoy l?kfur voLFkk esa gh ped mRiUu gksrh

gSA

(1) A (2) B (3) C (4) D

E / H 27/33

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MAJOR TEST : AIIMS

151. Assertion :- The Joule – Thomson coefficient

for an ideal gas is zero.

Reason :- There are no intermolecular attractive

forces in an ideal gas.

(1) A (2) B (3) C (4) D

152. Assertion :- Spots of iron rusting can be

removed by addition of oxalic acid

Reason :- Rust reacts with oxalic acid to

produce water soluble complex

(1) A (2) B (3) C (4) D

153. Assertion :- Decrease in free energy causes

spontaneous reaction.

Reason :- Spontaneous reactions are invariably

exothermic.

(1) A (2) B (3) C (4) D

154. Assertion :- Cu(OH)2 is soluble in NH4OH but

not in NaOH solution.

Reason :- Cu(OH)2 forms complex compound

in NaOH not in NH4OH.

(1) A (2) B (3) C (4) D

155. Assertion :- H2SO4 cannot be used along with

KI in the conversion of an alcohol to an alkyl

iodide.

Reason :- It converts KI to HI & then oxidises

it to I2.

(1) A (2) B (3) C (4) D

156. Assertion :- [Fe(H2O)5NO]SO4 is paramagnetic.

Reason :- Fe has three unpaired electron.

(1) A (2) B (3) C (4) D

157. Assertion :- Oxidation with nitric acid, glucose

yield a dicarboxylic acid, saccharic acid.

Reason :- Glucose has carbonyl group.

(1) A (2) B (3) C (4) D

158. Assertion :- BeCO3 has to be kept in the

atmosphere of CO2 gas

Reason :- CO2 is used to give inert atmosphere.

(1) A (2) B (3) C (4) D

151. dFku :- ,d vkn'kZ xSl ds fy, twy Fkkelu xq.kkad dk

eku 'kwU; gksrk gSA

dkj.k :- vkn'kZ xSl esa dksbZ vUrjkvkf.od cy ugha ik;stkrs gSA

(1) A (2) B (3) C (4) D

152. dFku :- yksgs ds tax ds nkx vkDtsfyd vEy }kjk feVk;s

tk ldrs gSA

dkj.k :- tax] vkDtsfyd vEy ds lkFk fØ;k djds tyesa ?kqyu'khy ladqy dk fuekZ.k djrk gSA

(1) A (2) B (3) C (4) D

153. dFku :- eqDr ÅtkZ esa deh ds dkj.k Lor% vfHkfØ;k gksrh

gSA

dkj.k :- Lor% vfHkfØ;k] Å"ek{ksih vfHkfØ;k gksrhgSA

(1) A (2) B (3) C (4) D

154. dFku :- Cu(OH)2 , NH4OH esa foys; gS ysfdu NaOH

esa ugha

dkj.k :- Cu(OH)2 NaOH esa ladqy fuekZ.k djrk gS

u fd NH4OH esaA(1) A (2) B (3) C (4) D

155. dFku :- ,Ydksgy ls ,fYdy vk;ksMkbM cukus ds fy,]

KI ds lkFk H2SO4 mi;ksx esa ugha yk;k tkrk gSA

dkj.k :- H2SO4, KI dks HI esa ifjofrZr dj nsrk

gS vkSj blds ckn bls I2 esa vkDlhd`r dj nsrk gSA

(1) A (2) B (3) C (4) D

156. dFku :- [Fe(H2O)5NO]SO4 vuqpqEcdh; gSA

dkj.k :- Fe ds ikl rhu v;qfXer bysDVªkWu gSA

(1) A (2) B (3) C (4) D

157. dFku :- Xyqdkst ds ukbVªhd vEy }kjk vkDlhdj.k ls

f}dkcksZDlfyd lewg okyk lSdjhd vEy izkIr gksrk gSA

dkj.k :- Xyqdksl esa dkcksZfuy lewg gksrk gSA

(1) A (2) B (3) C (4) D

158. dFku :- BeCO3 dks CO2 ds okrkoj.k esa j[kk tkrk gSA

dkj.k :- CO2 dks vfØ; okrkoj.k ds fy, dke esa fy;k

tkrk gSA

(1) A (2) B (3) C (4) D

24–05–2012



MAJOR TEST : AIIMS

159. Assertion :- CH3Cl is less reactive than

Cl towards SN1 reaction.

Reason :- Tertiary alkyl halides react

predominantly by SN2 mechanism.

(1) A (2) B (3) C (4) D

160. Assertion :- When a blue litmus paper dip inhypochlorous acid, It turns into red and latergets decolourise.Reason :- HOCl gives nascent oxygen ondecomposition.(1) A (2) B (3) C (4) D

161. Assertion :- If ADH increases in blood thenvolume of urine is reduced.

Reason :- ADH increases the reabsorption ofwater from DCT and CD.

(1) A (2) B (3) C (4) D

162. Assertion :– In dicot stems, the endodermis isalso referred to as the starch sheath.Reason :– The cells of the endodermis are richin starch grains.(1) A (2) B (3) C (4) D

163. Assertion :- Number of RBCs are more inarterial blood than venous blood.Reason :- In arterial blood RBCs are onlycomponent of blood which transport O2 to tissue.(1) A (2) B (3) C (4) D

164. Assertion :- Cytoskeleton of cell is made upof microtubules and microfilaments.Reason :- These are polysaccharide structures.

(1) A (2) B (3) C (4) D165. Assertion :- All ribs are bicephalic.

Reason :- One end of rib is attached withvertebral column and another end may bearticulate with sternum.

(1) A (2) B (3) C (4) D

166. Assertion :- Cell plate is the precursor for newcell wall.Reason :- Plasmodesmata occurs in livinganimal cells.

(1) A (2) B (3) C (4) D

159. dFku :- CH3Cl dh SN1 vfHkfØ;kvks a ds

izfrfØ;k'khyrk Cl

ls de gSA

dkj.k :- r`rh;d ,fYdy gSykbM eq[; :i ls SN2

fØ;kfof/k }kjk fØ;k djrs gSA(1) A (2) B (3) C (4) D

160. dFku :- tc gkbiksDyksjl vEy esa uhyk fyVel Mqcks;ktkrk gS rks ;g yky jax esa ifjofrZr gksrk gSA rFkk dqN nsjckn jaxghu gks tkrk gSAdkj.k :- HOCl fo?kfVr gksdj uotkr vkWDlhtu nsrkgSA(1) A (2) B (3) C (4) D

161. dFku :- ;fn jDr esa ADH dh vf/kdrk gks rks ew= dkvk;ru ?kV tkrk gSA

dkj.k :- ADH, DCT vkSj CD ls ty ds iquZ% vo'kks"k.kdks c<+krk gSA(1) A (2) B (3) C (4) D

162. dFku :– f}chti=h ruksa esa ,.MksMfeZl dks e.M vkPNnHkh dgrs gSaAdkj.k :– ,.MksMfeZl dh dksf'kdkvksa esa e.M d.kksa dhizpqjrk gksrh gSA(1) A (2) B (3) C (4) D

163. dFku :- /keuh; jDr esa RBC dh la[;k f'kjh; jDr ls vfèkdgksrh gSAdkj.k :- /keuh; jDr esa RBC dsoy jDr dk ,slk ?kVdgS tks mÙkdksa rd O2 ifjogu djrk gSA(1) A (2) B (3) C (4) D

164. dFku :- dksf'kdkiatj lw{e ufydkvksa ,oa lw{erarqvksa lscuk gksrk gSAdkj.k :- ;s iksyhlsdsjkbM + lajpuk;sa gksrh gSA(1) A (2) B (3) C (4) D

165. dkj.k :- lHkh ilfy;k¡ f}'kh"kZ ;qDr gksrh gSA

dkj.k :- ilyh dk ,d fljk d'ks:d naM ds lkFk tqM+k gksrk

gS vkSj nwljk fljk mjksfLFk ds lkFk laf/k cuk ldrk gSA

(1) A (2) B (3) C (4) D

166. dFku :- dksf'kdk iV~V u;h dksf'kdk fHkfÙk dk iwoZ inkFkZ gSA

dkj.k :- IykTeksMsLesVk izkf.k;ksa dh thfor dksf'kdkvksas esa

ik;s tkrs gSA

(1) A (2) B (3) C (4) D

E / H 29/33

24–05–2012



MAJOR TEST : AIIMS

167. Assertion :- Life cannot originated now on earth.Reason :- Present atmosphere of earth isreducing.(1) A (2) B (3) C (4) D

168. Assertion :- Deficiency of zinc causes Rosette,nature in plants.Reason :- Zinc is a macronutrient for plant.(1) A (2) B (3) C (4) D

169. Assertion :- High levels of estrogens providea negative feed back control of hormoneslevels.Reason :- It induces more secretion of GnRH.(1) A (2) B (3) C (4) D

170. Assertion :- Drought resistant plants are truexerophytes.Reason :- Drought resistant plants always havephysiological dryness.(1) A (2) B (3) C (4) D

171. Assertion :- Inheritance of karyo gene isbiparental.Reason :- Cytogene is located in nucleus.

(1) A (2) B (3) C (4) D172. Assertion :- B.O.D. of eutrophic lake is high.

Reason :- Quantity of organic matter is verymuch in eutrophic lake.(1) A (2) B (3) C (4) D

173. Assertion :- Pomato is an example of allopolyploid.Reason :- In pomato sets of chromosomes aresimilar in origin.

(1) A (2) B (3) C (4) D174. Assertion :- London smog or sulphur smog

requires low temperature.Reason :- London smog or sulphur smog is theexample of secondary pollution.(1) A (2) B (3) C (4) D

175. Assertion :- Products of human gene can beobtained from transgenic bacteria.Reason :- Genetic code is universal.(1) A (2) B (3) C (4) D

176. Assertion :– In heterothallic fungi, sexualreproduction occurs either between two (–)strains or two (+) strains.Reason :– Sexually reproducing fungi do notshow alternation of generation.(1) A (2) B (3) C (4) D

167. dFku :- vc iFoh ij thou mRiUu ugha gks ldrkA

dkj.k :- i`Foh dk orZeku okrkoj.k vipk;h gSA

(1) A (2) B (3) C (4) D

168. dFku :- ftad dh vYirk ikS/kksa esa xqykcor izÏfr dkfjrdjrh gSAdkj.k :- ftad ikS/ks ds fy;s xq:iks"kd gSA(1) A (2) B (3) C (4) D

169. dFku :- ,LVªkstu dk mPp Lrj gkeksZuksa ds Lrj dks udkjkRedQhM cSd nsrk gSAdkj.k :- ;g GnRH ds vR;f/kd lzo.k dks izsfjr djrkgSA(1) A (2) B (3) C (4) D

170. dFku :- lw[kk izfrjks/kh ikni lR; e:n~fHkn gksrs gSaA

dkj.k :- lw[kk izfrjks/kh ikni ges'kk dkf;Zdh; 'kq"drk j[krs

gSaA

(1) A (2) B (3) C (4) D

171. dFku :- dsfj;ksthu dh oa'kkxfr f}iSr`dh; gksrhgSAdkj.k :- lkbVksthu dsUæd esa fLFkr gksrh gSA(1) A (2) B (3) C (4) D

172. dFku :- lqiksf"kr >khy dk B.O.D. mPp gksrk gSdkj.k :- ;wVªksfQd >hy esa dkcZfud inkFkZ dh ek=k cgqrT;knk gksrh gSA(1) A (2) B (3) C (4) D

173. dFku :- iheSVks ,yksiksyhIyksbM dk mnkgj.k gSA

dkj.k :- ikSesVks esa xq.klw=ksa dk leqPp; leku mRifÙk easgksrs gSA

(1) A (2) B (3) C (4) D174. dFku :- yUnu Leksx vFkok lYQj Leksx esa fuEu rki dh

vko';drk gksrh gSAdkj.k :- yUnu Leksx vFkok lYQj Leksx f}fr;d iznq"k.kdk mnkgj.k gSA(1) A (2) B (3) C (4) D

175. dFku :- áweu thu ds mRiknksa dks VªkUltSfud thok.kqvksals izkIr fd;k tk ldrk gSAdkj.k :- vkuqoaf'kd dwV lkoZf=d gksrk gSA(1) A (2) B (3) C (4) D

176. dF ku :– fo"ke tkfyd dod es a y Sa fxd tuu

nks & strains ;k nks + strains ds chp gksrk gSA

dkj.k :– ySafxd tuu djus okyh dod ih<+h ,dkUrj.kizn£'kr ugh djrh gSA

(1) A (2) B (3) C (4) D

24–05–2012



MAJOR TEST : AIIMS

177. Assertion :- Parthenogenesis is a kind ofmethod of reproduction.Reason :- In parthenogenesis, a embryodevelops from zygote without fertilization.(1) A (2) B (3) C (4) D

178. Assertion :- Lymphoma is tumor ofhaemopoietic cells.Reason :- Carcinoma forms about 85% of alltumors.

(1) A (2) B (3) C (4) D179. Assertion :- Annelids, molluscans and

arthropods are protostomous coelomateanimals.Reason :- All these animals have tube withinbody plan.

(1) A (2) B (3) C (4) D180. Assertion :- Twilight vision, requires Rhods

(scotopic vision).Reason :- In dim light Rhods is maintained asRhodopsin photopigment.(1) A (2) B (3) C (4) D

181. India had appealed to the International OlympicCommittee to withdraw the sponsorship ofwhich company from the London Olympics :-(1) General motors (2) Dow Chemicals(3) Vodaphone (4) Google

182. The White House on Feb 10, 2012 namedIndia's renowned economist as the recipient ofthe 2011 US National Humanities Medal.Identify him :-(1) C. Rangarajan(2) Usha Thorat(3) Montek Singh Ahluwalia(4) Amartya Sen

183. Which of the following is the currency ofMyanmar ?(1) Kyat (2) Dinar(3) Peso (4) Euro

184. Where is the Doldrums belt located ?(1) Near the Tropic of Cancer(2) Near the Tropic of Capricorn(3) Near the Equator(4) Near the Poles

185. In what language were the Buddhist literaryworks generally written ?(1) Prakrit (2) Pali(3) Sanskrit (4) Apabhramsa

177. dFku :- vfu"ksdtuu] tuu dh ,d çdkj dh fof/k gSA

dkj.k :- vfu"ksdtuu esa Hkzw.k dk fuekZ.k ; qXeut ls fcuk

fu"kspu ds gksrk gSaA

(1) A (2) B (3) C (4) D

178. dFku :- fyEQksek] gheksiksbfVd dksf'kdkvksa dk V~;wej gS\

dkj.k :- dkflZuksek] lHkh V~;welZ dk yxHkx 85% Hkkx

cukrk gSA

(1) A (2) B (3) C (4) D179. dFku :- ,fufyM] eksyLdu o vkFkzks ZiksM çksVksLVksel

lhykseksV tUrq gSaA

dkj.k :- bu lHkh tUrqvksa esa ufydk ds Hkhrj ufydk ckWMh

Iyku gksrk gSaA

(1) A (2) B (3) C (4) D

180. dFku :- frfejksuqdwfyr izdk'k ds fy,s 'kykdkvksa dhvko';drk gksrh gS (LdksVksfid izdk'k)dkj.k :- ean izdk'k esa 'kykdkvksa dk jksMksIlhu izdk'k o.kZdfu;fer jgrk gSA(1) A (2) B (3) C (4) D

181. Hkkjr us varjjk"Vªh; vksyfEid lfefr ls yanu vksyfEiddh izk;kstd fdl dEiuh ls djkj jn~n djus ds fy;s vihydh gS :-(1) tujy eksVlZ (2) Mkm dsfedy(3) oksMkQksu (4) xwxy

182. 10 Qjojh 2012 dks OgkbV gkml us Hkkjr ds fdl izfl¼vFkZ'kkL=h dks o"kZ 2011 dk ; w-,l- us'kuy áwesfuVh esMy

iznku djus dh ?kks"k.kk dh gS :-(1) lh- jaxjktu(2) m"kk FkksjkV

(3) eksUVsd flag vkgywokfy;k

(4) veR;Z lsu

183. E;kaekj dh eqnzk fuEu esa ls dkSulh gS ?(1) D;kr (2) nhukj

(3) islks (4) ;wjks

184. MksYMªe {ks= dgk¡ fLFkr gS ?(1) ddZ js[kk ds ikl(2) edj js[kk ds ikl(3) fo"kqor js[kk ds ikl(4) /kqzoksa ds ikl

185. ckS¼ lkfgfR;d dk;ks± dh jpuk lkekU;r;k fdl Hkk"kk esa dhxbZ gS ?(1) izkÏr (2) ikyh(3) laLÏr (4) viHkza'k

E / H 31/33

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MAJOR TEST : AIIMS

186. Which of the following was composed byBanabhatta ?(1) Kadambari (2) Rajatarangini(3) Meghaduta (4) Arthashastra

187. On which particular date does the Sun remainat its farthest distance from the Earth ?(1) January 3 (2) March 21(3) July 4 (4) December 22

188. Which of the following is the working principleof a washing machine ?(1) Diffusion (2) Dialysis(3) Centrifugation (4) Reverse Osmosis

189. Who was the first Indian to get selected inIndian Civil Services :-(1) Satyendra Nath Tagore(2) Surendra Nath Banerjee(3) Subhash Chandra Bose(4) Pherozshah Mehta

190. Which one of the following pairs is notcorrectly matched ?(1) Raja Rammohan Roy – Brahmo Samaj(2) Swami Dayanand Saraswati – Arya Samaj(3) Swami Vivekanand – Ramkrishna Mission(4) Mahadev Govind Ranade – Theosophical Society

191. In which one of the following states, the densityof population, as per the provisional figures of2011 Census, is the lowest ?(1) Arunachal Pradesh (2) Meghalaya(3) Sikkim (4) Uttarakhand

192. World Diabetes Day is observed on :-(1) November 19 (2) October 2(3) November 14 (4) June 5

193. The winner of Man Booker Prize for the year2011 is :-(1) Julian Barnes (2) Peter Carey(3) Howard Jacobson (4) Tom Macarthy

194. Who is called the 'Nightingale of India' ?(1) Mother Teresa (2) Indira Gandhi(3) Vijay Laxmi Pandit (4) Sarojini Naidu

195. Who called part III of the Constitution of Indiaas 'conscience of the Constitution' ?(1) Dr. B.R. Ambedkar(2) Jawaharlal Nehru(3) Sacchidanand Sinha(4) Dr. Rajendra Prasad

186. fuEufyf[kr esa dkSulh ck.kHkê }kjk jfpr Ïfr gS ?

(1) dknEcjh (2) jktrjafxuh

(3) es?knwr (4) vFkZ'kkL=

187. fuEu esa ls og dkSulk fnu gS tc lw;Z i`Foh ls vf/kdre nwjhij gksrk gS ?(1) 3 tuojh (2) 21 ekpZ(3) 4 tqykbZ (4) 22 fnlEcj

188. okf'kax e'khu fdl fl¼kUr ij dk;Z djrh gS ?

(1) folj.k (2) viksgu

(3) vidsanz.k (4) O;qRØe ijklj.k

189. Hkkjrh; iz'kklfud lsok esa p;fur izFke Hkkjrh; dk ukecrkb;s :-(1) lR;sUnz ukFk VSxksj(2) lqjsUnz ukFk cSuthZ(3) lqHkk"k pUnz cksl(4) fQjkst'kkg esgrk

190. fuEufyf[kr esa ls dkSulk ;qXe lqesfyr ugha gS ?

(1) jktk jkeeksgu jk; & czã lekt

(2) Lokeh n;kuUn ljLorh & vk;Z lekt

(3) Lokeh foosdkuUn & jkeÏ".k fe'ku

(4) egknso xksfoUn jkukMs & fFk;kslkWfQdy lkslk;Vh191. o"kZ 2011 dh tux.kuk ds vuqlkj fuEu esa ls dkSuls jkT;

dk tula[;k ?kuRo U;wure gS ?

(1) v:.kkpy izns'k (2) es?kky;

(3) flfDde (4) mÙkjk[k.M

192. fo'o e/kqesg fnol dc euk;k tkrk gS :-(1) 19 uoEcj (2) 2 vDVwcj(3) 14 uoEcj (4) 5 twu

193. o"kZ 2011 ds esu cqdj iqjLdkj ds fotsrk dkSu gS :-

(1) twfy;u ckuZ (2) ihVj dSjh

(3) gkWoMZ tSdClu (4) VkWe esdkFkhZ

194. ^Hkkjr dh dksfdyk* fdls dgk tkrk gS ?(1) enj Vsjslk (2) bafnjk xka/kh(3) fot; y{eh iafMr (4) ljksftuh uk;Mw

195. Hkkjrh; lafo/kku ds Hkkx III dks fdlus ^lafo/kku dhvarjvkRek* dgk gS ?(1) Mk- ch- vkj vEcsMdj(2) tokgjyky usg:(3) lfPpnkuUn flUgk(4) MkW- jktsUnz izlkn

24–05–2012



MAJOR TEST : AIIMS

196. Who looked upon the Khilafat agitation as "anopportunity of uniting Hindus andMohammedans as would not arise in a hundredyears" ?(1) Maulana Azad(2) Gandhiji(3) Bal Gangadhar Tilak(4) Zinnah

197. Which one of the following painters was giventhe title of 'Shiri Kalam' by Akbar ?(1) Basawan (2) Abdus samad(3) Saiyid Ali (4) Daswant

198. Subhash Chandra Bose was the president ofIndian National Congress for how many times?(1) Once (2) Twice(3) Thrice (4) Four times

199. Sachin Tendulkar scored its 100th hundredrecently. Against which country did he achieveit?(1) Pakistan (2) Bangladesh(3) Sri Lanka (4) Australia

200. Which is called as "Reptile-like mammal" ?(1) Scaly ant eater (2) Giant ant eater(3) Spiny ant eater (4) All the above

196. ^^fgUnw vkSj eqlyekuksa dh ,drk LFkkfir djus ds lEcU/k esa,slk volj vxys 100 o"kks± rd ugha feysxk** & f[kykQr

vkUnksyu ds lEcU/k esa ,slk fdlus lkspk Fkk ?

(1) ekSykuk vktkn

(2) xk¡/khth

(3) cky xaxk/kj fryd

(4) ftUuk197. fuEu fp=dkjks esa ls fdls ^'khjh dye* dh mikf/k vdcj

}kjk nh xbZ Fkh ?(1) clkou (2) vCnql len(3) lS;n vyh (4) nloUr

198. lqHkk"k pUnz cksl Hkkjrh; jk"Vªh; dk¡xzsl ds v/;{k fdruhckj jgs ?(1) ,d ckj (2) nks ckj(3) rhu ckj (4) pkj ckj

199. lfpu rasnqydj us gky gh esa varjkZ"Vªh; fØdsV esa viuk100 oka 'kr yxk;k gSA fuEu esa ls fdl ns'k ds fo:¼ [ksyrsgq, mlus ;g miyfC/k izkIr dh gS\(1) ikfdLrku (2) ckaXykns'k(3) Jh yadk (4) vkWLVªsfy;k

200. fdldks ^^ljhl`i uqek Lrfu** dgrs gS ?(1) 'kYdh phaVh[kksj (2) egkdk; phaVh[kksj(3) dafVdh; phaVh[kksj (4) mijksä lHkh

Your moral dutyis that to prove ALLEN is ALLEN

E / H 33/33

24–05–2012



MAJOR TEST : AIIMS

SPACE FOR ROUGH WORK / jQ dk;Z ds fy;s txg

aiims 6 mock test by allen

Documents

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