algebra 7.2 solving systems using substitution. you have already learned that the solution is the...

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There are two algebraic methods that allow you to solve a system easily without graphing. Today you will learn the method called SUBSTITUTION.

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Page 1: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

AlgebraAlgebra7.2 7.2

Solving Systems Solving Systems Using SubstitutionUsing Substitution

Page 2: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

You have already learned that the solution is the point of intersection of the two graphed lines.

Solution to a System of Linear Equations

To solve:1. Graph both equations2. Identify intersection point (x,y)3. Plug in to original equations to check

Page 3: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

There are two algebraic methods that allow you to solve a system easily without graphing.

Today you will learn the method called SUBSTITUTION.

Page 4: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

Steps1. In one equation, isolate one variable.2. Substitute expression from Step 1

into second equation and solve for the other variable.

3. Plug in value from Step 2 into revised equation from Step 1 and solve.

4. Check solution in both original equations.

Page 5: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

Solve the linear system.3x + y = 52x – y = 10

Hint: It is usually easiest to isolate positive 1x or 1y.

y = 5 – 3x

2x – ( ) = 105 – 3x2x – 5 + 3x = 105x – 5 = 105x = 15x = 3

y = 5 – 3(3)y = 5 - 9y = - 4

The solution is (3, - 4)Check: 3(3) + (-4) = 5

2(3) – (-4) = 10

Page 6: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

Solve the linear system.2x + 6y = 15x = 2y

2( ) + 6y = 152y

4y + 6y = 1510y = 15y = 15/10y = 3/2

x = 2( 3/2)x = 3

The solution is (3, 3/2)Check: 2(3) + 6(3/2) = 15

3 = 2(3/2)

x = 2y

Page 7: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

You try!x + 2y = 4-x + y = -7 y = x – 7

x + 2( ) = 4x - 7

x + 2x - 14 = 43x – 14 = 43x = 18x = 6

y = 6 – 7y = -1

The solution is (6, - 1)Check: 6 + 2(-1) = 4

-6 + (-1) = -7

Page 8: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

Mixture Problems

Systems are often used to solved mixture problems. These are problems when you mix two quantities. You know the total quantity and the total value, but not how much of each type. To solve:•Write one equation to describe

QUANTITY.•Write other equation to describe VALUE.

Page 9: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

Set up a system and solve the mixture problem.An audio store sells two styles of I-pod Nanos. The 2 GB

model costs $150 and the 4GB model costs $225. Last Saturday the store sold 22 Nanos for a total of $3900. How many of each model did they sell?

Let x be the # of 2 GB models soldLet y be the # of 4 GB models sold

Quantity: x + y = 22Value: 150x + 225y = 3900

There were 14 2GB Nanos and 8 4 GB Nanos sold.

Now, you solve.

Page 10: Algebra 7.2 Solving Systems Using Substitution. You have already learned that the solution is the point of intersection of the two graphed lines. Solution

Homeworkpg. 408 #17 – 35 odd, 42