alkanes lecture 2014 fullnotes updated
DESCRIPTION
NYJC chemTRANSCRIPT
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H2 Chemistry 9647 Alkanes NYJC 2014
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Alkanes Lecturers: Ms Joanne Low and Mrs Zhuo (Mdm Tan Shuyun) Contents Alkanes (exemplified by ethane)
(i) Free-radical reactions Hydrocarbons as fuels Learning Outcomes Candidates should be able to: (a) Recognise the general unreactivity of alkanes, including towards polar reagents
(b) Describe the chemistry of alkanes as exemplified by the following reactions of ethane:
(i) Combustion (ii) Substitution by chlorine and by bromine
(c) Describe the mechanism of free-radical substitution at methyl groups with particular reference to the initiation, propagation and termination reactions
(d) Recognise the environmental consequences of: (i) Carbon monoxide, oxides of nitrogen and unburnt hydrocarbons arising from the
internal combustion engine and of their catalytic removal (ii) Gases that contribute to the enhanced greenhouse effect
1. Introduction 1.1 Alkanes
belong to a homologous series of hydrocarbons (contain C and H atoms only) are saturated (only single bonds between atoms, hence they contain maximum
number of hydrogens per carbon atoms) are combustible but unreactive There are two homologous series of alkanes:
Aliphatic alkanes (open-chained alkanes) Alicyclic alkanes (closed-chained alkanes) General formula: CnH2n+2 General formula: CnH2n E.g. CH3CH2CH2CH2CH3 Pentane C5H12
E.g. Cyclobutane C4H8 Cyclopentane C5H10
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NH2 Chemistr
1.2 Nomen No. of C atoms
1
2
3
4
4
5
5
6
1.3 Alkyl g formed named
Gen
C
ry 9647
nclature
IUPAC NMolecular
MethaCH
EthaC2H
PropaC3H
ButaC4H
2-methylpC4H
2,2-dimethyC5H
cyclopenC5H
cyclohexan
groups
d when ond by replac
Aliphatic Aneral formu
CH3 Metha
CH3CHEthan
CH3CH2CPropan
CH3CH2CHButan
Name/ formula
ane 4
ne H6
ane H8
ne 10
propane 10
ylpropane 12
ntane 10
ne C6H12
e of the hycing ane b
Alkane la: CnH2n+2
H ne 2 H
ne CH2 H ne 2CH2 H
ne
A
Condeform
CH
CH3C
CH3CH
CH3 (CH
CH(C
C(CH
H2C
H2C
HC
H2C
H2CCH
HC
ydrogen of by yl
Ge
Alkanes
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ensed mula
H4
CH3
H2CH3
H2)2CH3
CH3)3
H3)4
H2C
CH2
CH2
CH2
CH2
CH2
H2C
the alkane
Alkyl grneral formu
CH3 Meth
CH3CHEthy
CH3CH2CProp
CH3CH2CHButy
Displayed
CH
C
H
H
H
C
H
H
H
es is remov
roup ula: CnH2n+1 yl
H2 yl CH2 yl
H2CH2 yl
C C
H
H
H
H
H
C
CC
H
HH
H
H
C
CC
CH
H
H
H
HH
d formula
C H
H
H
C H
H
H
C C
H
H H
H
H
ved
AGen
C
H
C
H
H
H
H
C
C
C
HH
H
HH
CC
CC
HH
H
H
H
H
Melting point /oC
182
183
190
138
160
17
94
7
Abbreviationeral symb
Me
Et
Pr
Bu
NYJC 201
C Boiling
point /oC
164
88
42
0.5
12
10
49
81
on ol: R
4
C
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gH2 Chemistr
2. Bondi Bonding a
C has 4 C atom
configu Shape
2.1. Hybri
W
All the Hence Each c
atomic
C* (hyb
How?
1. The2. Dur
form3. The4. Bon
atom
groundstate
ry 9647
ing in Al
and molec
4 valence ms share eluration. of the mol
dization o
What is hybThe comolecuHybridiview. Iorbital
carbons inalkanes h
carbon is aorbitals)
bridised s
e electron iring hybridm four sp3
e four sp3 hnding will tms.
eC heat
kanes
cular struc
electrons alectrons by
lecule with
of carbon
bridizationncept of h
ular orbitalsisation dest involves s.
n alkanes aave carbonable to fo
state):
in the 2s oisation, on
3 hybrid orhybrid orbithen occur
excitedst
A
cture of al
and it has y forming 4
respect to
in alkanes
n? ybridisatios for molecscribes the mixing of
are sp3 hybn with tetrarm four sp
rbital first gne 2s and trbitals. tals form awhen the
1s fo
tateC he
Alkanes
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lkanes
electron co4 covalent
o carbon: T
s
on is usefucules. bonding a
f atomic o
bridised. ahedral arrp3 hybrid o
gets excitethree 2p a
a tetrahedrsp3 hybrid
our sp3 hyb
hybreat
onfiguratiobonds to a
Tetrahedra
ul in explai
atoms fromrbitals to f
rangementorbitals (by
ed and it isatomic orbit
ral arrangeorbitals ov
brid orbitals
ridisedstate
n: 1s22s22achieve no
al (4bp, 0lp
ining the s
m an atomsform new
t of CC ay mixing o
s promotedtals are hy
ement. (Boverlap with
s
C
2p2. ble gas ele
p)
hape of
s point of hybrid
and CH one 2s an
d to the 2p ybridised (m
ond angle =h orbitals o
NYJC 201
ectronic
bonds. d three 2p
orbital. mixed) to
= 109o) of other
4
p
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H2 Chemistr Recall: Ov Sigma Pi () All sin Example: During
four sp Each s four C
Example: The C The tet
orbital The rem
1s orbi
s orbital
ry 9647
verlap of oa () bondsbonds aregle bonds
Methane
hybridisatp3 hybrid osp3 hybrid oH bond
Ethane (C
atom formtrahedral cfrom each maining spital of hydr
l of H
orbitals tos are forme formed bys are sigm
(CH4)
tion, one 2orbitals. orbital will ds are form
C2H6)
s four sp3carbon atom C atom. p3 orbitals rogen atom
A
o form boned by heady side-on
ma bonds.
2s and thre
overlap hemed.
3 hybrid orms form a
of carbon m.
non
Alkanes
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nds (Chemd-on overloverlap of
ee 2p atom
ead-on wit
rbitals. CC bo
form CH
ne sp3 orbitne sp3 orbi
mical bondlap of orbitf orbitals.
mic orbitals
th one of th
ond by hea
bonds b
tal of C tal of C
ding chaptals
are hybrid
he 1s orbit
ad-on over
by head-o
ter)
dised (mixe
tals of four
rlapping of
on overlapp
NYJC 201
ed) to form
H atoms.
one sp3
ping with a
4
m
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H2 Chemistry 9647 Alkanes NYJC 2014
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3. Physical Properties 3.1 Boiling point and melting point Alkanes have relatively low boiling and melting points.
Alkanes are non-polar: C H bond is considered non-polar as C and H only differ slightly in electronegativity. [electronegativity of C(2.5) and H(2.1) are similar]
Have a simple molecular structure consisting of alkane molecules held together by weak van der Waals forces.
Boiling or melting involves overcoming the weak van der Waals forces between the alkane molecules.
Boiling point generally increase with an increasing number of C atoms.
C1 C4: gas C5 C17: liquid >C18: solid
- When Mr increases, number of electrons increases. - Larger electron cloud becomes more polarisable. - Strength of intermolecular van der Waals forces increases. - More energy is required to overcome the van der Waals forces.
The greater the degree of branching (with the same number of C atoms), the
lower the boiling point.
Name pentane 2-methylbutane 2,2-dimethylpropane
Structure CH3CH2CH2CH2CH3
CH3CHCH2CH3
CH3 CH3CCH3
CH3
CH3 Boiling point /oC 36 28 10 Melting point /oC 130 160 17
- Highly branched alkanes are more spherical in shape. - Smaller surface area of contact between molecules. - Strength of intermolecular van der Waals forces decreases. - Less energy is required to overcome the weak intermolecular forces.
The trend for melting point less regular than that of boiling point
- Branched alkanes can have lower or higher melting points than the straight chain alkanes depending on the packing of the molecules in the solid
- Highly symmetrical branched alkanes allow the molecules to be packed more efficiently in the solid and hence have unusually high melting point.
*at room temperature
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H2 Chemistry 9647 Alkanes NYJC 2014
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3.2 Solubility Alkanes are: soluble in non-polar (organic) solvents like CCl4, benzene and ether (R-O-R).
- They can form van der Waals interactions with the non-polar solvent. - The energy released during the formation of van der Waals forces with the non-
polar solvent is enough to overcome the van der Waals forces between the alkane molecules and the van der Waals forces between the solvent molecules.
insoluble in polar solvents like water. - They can only interact with water molecules via weak van der Waals bonds - the energy released during the formation of weak van der Waals forces with
water is not enough to overcome the strong hydrogen bonds between water molecules.
and water molecules
strong hydrogen bonding between water molecules
water layeralkane layer
weak van der Waals interactions between alkane
weak van der Waals between alkane molecules
+
+
+
+ +
+
+
+
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H2 Chemistry 9647 Alkanes NYJC 2014
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4. Chemical Properties Alkanes are saturated and are generally unreactive because:
(i) The C-H bond is non-polar They have no centres of electrical charge to act as electrophiles or
nucleophiles to attract polar reagents like H+, OH- or MnO4-. (ii) The C-C and C-H bonds are relatively strong
C C: 350 kJ mol-1 C H: 410 kJ mol-1
Alkanes do, however, react with oxygen and halogens under appropriate conditions,
like in the presence of ultraviolet light or heat.
Alkanes undergo two main types of reactions: (i) Combustion (ii) Free Radical Substitution
(i) Combustion Complete combustion
Alkanes burn in excess oxygen to form carbon dioxide and water. This reaction is very exothermic, which accounts for their use as fuels.
Alkanes burn with a non-luminous blue flame with little or no soot if combustion is complete.
General equation: CxHy + (x + 4
y ) O2 x CO2 + 2y
H2O
e.g. Complete combustion of hexane:
C6H14 (l) + 192
O2 (g) 6CO2 (g) + 7H2O (l)
Incomplete combustion
In a limited supply of oxygen, alkanes burn to form carbon monoxide, water and soot (C).
e.g. Incomplete combustion of methane:
2CH4 + 3O2 2CO + 4H2O CH4 + O2 C + 2H2O (soot) 4CH4 + 5O2 2CO + 2C + 4H2O (soot)
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H2 Chemistry 9647 Alkanes NYJC 2014
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(ii) Substitution
Alkanes react with halogen (e.g. Cl2 and Br2) to form halogenoalkanes (alkyl halides) when irradiated with ultraviolet light or heated.
No reaction takes place in the dark. The mechanism for the halogenation reactions of alkanes is known as free radical
substitution.
Type of reaction free radical substitution
Equation CxHy (g) + Cl2 (g) CxHy-1Cl (g) + HCl (g) Reagents Cl2 Conditions
Ultra-violet light sunlight Heat may be supplied to initiate the reaction. Reaction proceeds very slowly at room temperature.
Product chloroalkanes Observations Yellowish-green colour of Cl2 decolourises.
White fumes of HCl produced. Example: Write a balanced equation for the reaction of propane with bromine. Indicate clearly the conditions and observations in this reaction.
C3H8 (g) + Br2 (l) C3H9Br (l) + HBr (g) Conditions: UV light or heat Observations: Reddish-brown Br2 turns colourless. White fumes of HBr formed. Note: - Solvent is CCl4 (used when alkane and halogen is present in different phases)
Example: C3H8 (g) + Br2 (l) - Bromination takes place less readily than chlorination
because weaker C-Br and H-Br bonds are formed. (Refer to Group VII) - Fluorination is dangerously exothermic while iodination is slow and reversible.
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H2 Chemistr
5. React
A ccrea
Bon The
i)
ii) 5.1 Homo
Not
5.2 Hetero
ry 9647
ion mec
chemical rated. nd cleavagere are two
Homol Hetero
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te: How yo
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ou draw y
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A
akes place
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nds to occuativities. eaks, each
ormed in hoal is an atoemely reacwith anothe
our half a
ends to ocve than thaks, the manion. Th
Arroat telec
Alkanes
Page9of18
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NYJC 201
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-
H2 Ch
5.3 F
Initiat
Cl
Propa Cl + CH3C
Termi CH3C Cl + CH3C
emistry 9647
ree-Radical S
Mtion
Clu.v.
agation
CH3CH2H
H2 + ClCl
ination
H2 + Cl
Cl
H2 + CH3CH2
uv
ubstitution (F
Mechanism
Cl Cl
CH3CH2
CH3C
CH3CH2
ClCl
2
Alkanes
RS) Mechanis
2 + HCl
CH2Cl + Cl
2Cl
CH3CH2CH2CH
sm
Homoly
Why is CH3CH C-H bo Note: B The c
chlorid A high
Why i Cl + The f
forma Note: The e
radica The tw
destro
H3
The c
Page10of18
ytic fission of Cl
this step not favH3 CHonds in alkanes aBE(Cl-Cl) = 242
chlorine radical rde molecule. hly reactive ethy
s this step not fa CH3CH2H formation of a ation of a H-Cl bo
BE(H-Cl) = 431
ethyl radical reaal. wo steps are reoyed i.e. termina
chain reaction te
NYJC 2014
D
Cl bond under
vourable? H3CH2 + H are not broken akJmol-1, BE(C-H
removes a hydro
yl radical is produ
avourable? CH3C-Cl bond is leond in the above kJmol-1, BE(C-C
cts with a chlor
epeated till all thation step.
rminates when t
4
Description
UV radiation to f
as the C-H bond H) = 435 kJmol-1
ogen atom from
uced.
CH2Cl + Hess exothermic e mechanism. Cl) = 340 kJmol-
rine molecule to
he reactants hav
two free radicals
form free Cl rad
is much stronge
a ethane molec
and hence les
-1
o produce chloro
ve been used u
s collide with eac
dicals.
er than the Cl-C
cule to form a hy
ss favourable th
oethane and a c
p or when radic
ch other.
l bond.
ydrogen
han the
chlorine
cals are
-
H2 Ch
ExamThe cformsmech
Free
In
Cl
Pr
Te
Note:part o
emistry 9647
mple chlorination of ps 2-chloroprophanism of the re
radical substi
itiation
Clu.v
ropagation
ermination Cl C
For initiation sof a question fo
propane in the pane as a eaction.
itution
v. Cl
Cl
Cl2
Cl
Cl
step uv light ior free radical s
Alkanes
presence of a possible pro
Cl
Cl
Cl2
Cl
is to be written substitution.
limited amounoduct. Sugge
HCl
Cl
in your answe
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nt of Cl2 st the
Exam1-choreact
Free
In
Cl
rs but sometim
NYJC 2014
mple olorocyclohexaion mechanism
radical subst
nitiation
Clu.v
mes conditions
4
ne can be mam of its formatio
itution
v. Cl
like sunlight/he
de from cyclohon.
Cl
eat can be state
hexane. Descr
ed as a conditio
ribe the
on as
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H2 Chemistr
5.4. ProblIn reality, aof the follo 5.4.1 Mult Depen
for rea The re
CH3Cl CCl4 p To avo
(This m
ExamplA possi1,1-dich Mechan Initiatio
Cl CPropag
Termina
(**Write a
ry 9647
ems with a pure sam
owing prob
ti-substitunding on thaction, a meaction of C
predominpredominatoid multisumaximises
le ble produchloroethan
nism: Free
on
Cl Cuv/ heat
ation
ation
at least 3, in
Free-Radmple of thelems:
ution he relative ixture of pCH4 and C
ates whentes when t
ubstitution, s the proba
ct for the cne. Sugges
Radical S
Cl + Cl
ncluding for
P
ical Subst chloroalka
amounts oroducts wi
Cl2 is able to
n there is ehere is excuse an ex
ability that C
chlorinatiost the mec
Substitutio
rmation of t
Alkanes
Page12of1
titution ane (or bro
of halogen ll be obtaino yield a m
xcess CH4cess Cl2. xcess of alCl attacks
n of ethanchanism of
on
he halogen
8
omoalkane
and alkanned. mixture of C
4.
lkane or a s CH4.)
ne in the pthe reactio
, product an
e) is seldom
e present
CH3Cl, CH2
limited am
presence oon.
nd one poss
m obtained
and the tim
2Cl2, CHC
mount of C
of excess
sible side p
NYJC 201
d because
me allowed
l3 and CCl4
Cl2.
chlorine is
roduct)
4
d
4:
s
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H2 Chemistry 9647 Alkanes NYJC 2014
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5.4.2 Isomeric Products In the case of alkanes with 3C, isomeric products are formed depending upon which
H atom is replaced.
Expected Ratio: 10% 90% A simplified way to obtain the expected ratios is to count the number of hydrogens that
have the same chemical environment which will lead to the formation of a specific product. (probability)
Example: Draw all the possible monosubstituted products when a mixture of 2-methylbutane and bromine is allowed to react in the presence of sunlight. State the ratio in which they are formed.
Br
Br
Br
Br
= 1 : 2 : 3 : 6
C C
Hd
Hd
Hd
Ha
C
Hb
C
Hb
Hc
Hc
Hc
C HdHd
Hd
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H2 Chemistry 9647 Alkanes NYJC 2014
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Example: Draw all the possible monosubstituted products when a mixture of pentane and bromine is allowed to react in the presence of sunlight. State the ratio in which they are formed.
Br
C C
H
H
H
C
H
H
C
H
H
C
H
H
H
H :
H
C C
H
H
Br
C
H
H
C
H
H
C
H
H
H
H :
H
C C
H
H
H
C
H
Br
C
H
H
C
H
H
H
H = 6 : 4 : 2 = 3 : 2 : 1
a) Draw the displayed formula of another isomer of C5H12 which reacts with bromine to form only one monobrominated product.
Ans:
C
CH
H
H
C C
CH
H
HH
H
H
H
H
H
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H2 Chemistry 9647 Alkanes NYJC 2014
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6. Environmental Concern (Refer to Heterogenous catalysis in Kinetics, Page 30) There are several environmental concerns regarding the use of hydrocarbons as fuels.
(i) Pollutants such as carbon monoxide, oxides of nitrogen and unburnt hydrocarbons (soot) found in car exhaust can be removed from the car engines using catalytic converter.
Pollutants Formation in car engine Environmental/ Health Impact
Reaction for removal in catalytic converter
Carbon monoxide
Incomplete combustion of fuel
Combines irreversibly with haemoglobin and makes it ineffective as oxygen carrier in the human body suffocation or blood poisoning
Conversion of CO to CO2 2CO(g) + O2(g) Pt 2CO2(g)
Oxides of nitrogen (NO2, NO)
Reaction of N2 with O2 at high temperatures
Catalyzes formation of acid rain Forms smog
Conversion of NO to N2 2NO(g) Pt N2(g) + O2(g) 2NO(g) + 2CO(g) N2(g) + 2CO2(g)
Unburnt hydrocarbon
Incomplete combustion of fuel
Forms smog Oxidation of unburnt hydrocarbon to CO2 and H2O e.g. 2C8H18(l) + 25O2(g) Pt 16CO2(g) + 18H2O(l)
Note:
- The catalyst in the converters would be poisoned by the lead present in petrol. Therefore, cars fitted with catalytic converters must use unleaded petrol.
- A honeycomb structure is used to maximise the surface area on which catalysed reactions can take place.
(ii) Carbon dioxide and methane are greenhouse gases responsible for global warming
and climate changes. One of the major sources of carbon dioxide comes from burning of fossil fuels for energy production; hence there is a need to find alternative fuels for mankind.
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H2 Chemistry 9647 Alkanes NYJC 2014
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Summary of important concepts in Alkanes
Physical Properties of Alkanes: Non-polar Consisting of molecules held together by weak intermolecular van der Waals forces. Soluble in non-polar (organic) solvents Insoluble in polar solvents Boiling point increases with number of carbons
o Number of electrons in the molecule increases. o Polarisability increases, o Strength of intermolecular van der Waals forces increases. o More energy is required.
Branching decreases the boiling point. o More spherical in shape o Smaller surface areas of contact between molecules o Strength of intermolecular van der Waals forces decreases o Less energy is required
Chemical Properties of Alkanes: Alkanes are unreactive because the C-H bond is non polar and relatively strong. Carbon atoms in alkanes form four sp3 hybrid orbitals from hybridization of one 2s and three 2p
orbitals. They form 4 sigma bonds () via head-on overlap of orbitals. Complete combustion of alkanes produces carbon dioxide(CO2) and water(H2O). Alkanes undergo reactions by a mechanism called free-radical substitution in the presence of
ultraviolet light or heat.
o In reaction of ethane with bromine, the 3 stages in the mechanism are (1) Initiation
Equation: Cl Clu.v. Cl Cl
(2) Propagation Equations:1st step - Cl 2CH3 CH2H H HClCH3CH2
2nd step - Cl Cl ClCH3CH2 CH3CH2 Cl
(3) Termination Equations:
2 Types of Bond Fission
Occurs between atoms of _______ electronegativities
Electrons in bond broken goes to Arrows Products
(1) Homolytic fission Similar One to each atom
Radicals
(2) Heterolytic fission Different
Both electrons go to more EN atom
Cation + Anion
CH3CH2 Cl CH3CH2 Cl
Cl Cl Cl ClCH3CH2 CH3CH2 CH2CH3CH3CH2
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H2 Chemistry 9647 Alkanes NYJC 2014
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Annex (For additional reading) A1. Cracking Cracking is a process of breaking down large alkane molecules into smaller alkanes and alkenes. There are two processes we can split alkane chains: By high temperature (about 800oC) and pressure, known as thermal cracking. By catalyst (Al2O3 and SiO2, 450 oC), known as catalytic cracking. For example, C10H22 C4H8 + C6H14 C14H30 C2H4 + C12H26
[Note TYS Pg 118, Qn 5a (N2005/III/8 Either) is no longer in syllabus]
A2. Hydrocarbons as Crude Oil Fractional Distillation Petroleum is a mixture of a very large number of different hydrocarbons; the most commonly found molecules are alkanes (linear or branched), cycloalkanes and aromatic hydrocarbons. Raw oil or unprocessed ("crude") oil is not useful in the form it comes in out of the ground. To make it useful, it must be separated into its components by fractional distillation as shown in Figure 1.
Figure 1. Fractional distillation of crude oil. The fractionating column is cooler at the top than at the bottom because the fractions at the top have lower boiling points than the fractions at the bottom.
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H2 Chemistry 9647 Alkanes NYJC 2014
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Crude oil is fractionally distilled to give the following fractions. Fraction Length of Carbon
chain Uses
Refinery
gases
C1-C4 Fuel; domestic heating, gas cookers
Gasoline C5-C12 Fuel in internal combustion engines
Kerosene C12-C18 Fuel for jet engines
Diesel Oil C18-C25 Fuel for transport and industrial
heating
Residue > C25 paraffin wax, lubricating oil, petroleum
jelly, bitumen
A3. Octane number (octane rating)
In a cylinder of a motor car engine, a mixture of petrol vapour (mostly C5 to C10 alkanes) and the air is ignited by an electric spark, producing an explosive reaction which drives the piston down.
Petrol rich in straight-chain alkanes (e.g. heptane) ignites very readily and explodes rapidly, causing knocking of the engine and inefficient combustion.
Combustion of branch-chain alkanes (e.g. 2,2,4-trimethylpentane) is much smoother and more controlled. It is a more efficient fuel and less likely to cause knocking.
A numerical representation of the antiknock properties of motor fuel, compared with a standard reference fuel.
Heptane is assigned an octane number of 0. 2,2,4-trimethylpentane (iso-octane) is assigned an octane number of 100. The octane number of a petrol is found by comparing its performance with a mixture of
heptane and 2,2,4-trimethylpentane. The octane number of a sample of fuel is determined by burning the gasoline in an
engine under controlled conditions, e.g., of spark timing, compression, engine speed, and load, until a standard level of knock occurs.
Gasoline that have high octane numbers denotes that they have good anti-knock properties
Reference texts 1. Understanding Chemistry for Advanced level, Ted Lester, Janet Renshaw, Chapter 19 [540LIS] 2. Chemistry for Advanced Level. Peter Cann, Peter Hughes, Chapter 23 [540CAN]