8.77 medicare hz
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Difference
1725
14-1020
4035302822155
A What sample size should she select?
Population Standard Deviation 30
Sampling Error 5Confidence Level 95%
Z Value -1.95996398Calculated Sample Size 138.292518
Sample Size Needed 139
3.8416 900
25
138.2976
B Construct a 90% confidence interval estimate for the population proportion of reimbursetments th
Sample Size 139Number of Successes 12Confidence Level 90%
Sample Proportion 0.08633094Z Value -1.64485363
INTERMEDIATE CALCULATION
DATA
INTERMEDIATE CALCULATION
RESULT
DATA
139
2976.138
5
3096.12
22
2
22
2/
n
n
n
e
Z n a
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Standard Error of the Proportion 0.02382156Interval Half Width 0.03918299
Interval Lower Limit 0.04714795Interval Upper Limit 0.12551392
0.0863
0.0863139
0.0006
0.0238
0.0392
0.04710.1255
C Construct a 95% confidence interval estimate for the population mean reimbursetments per office
Sample Standard Deviation 13.527Sample Mean 20.083Sample Size 139Confidence Level 95%
Standard Error of the Mean 1.147Degrees of Freedom 138
t α/2 Value 1.977
Interval Half Width 2.269
Interval Lower Limit 17.815Interval Upper Limit 22.352
from table above shows that:sample mean = 20.083sample standard deviation = 13.527for 95% confidence, cumulative probability = 0.975
since we have 139 sample size so that we get 138 degrees of freedom, from table E.3 we interpol
Degrees of Freedom
110
CONFIDENCE INTERVAL
DATA
INTERMEDIATE CALCULATIONS
CONFIDENCE INTERVAL
Cumulative Probabilities = 0.975
1.9818
1255.00471.0
0392.00863.0
0238.0645.10863.0139
0863.010863.0645.10863.0
12/
n
p p Z p
0863.0139
12
n
X p
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120138 ← results of
-0.0019
-0.0053
1.9765
2.268 17.81622.351
D Construct a 95% confidence interval estimate for the population total amount of reimbursetments f
Population Size 25,056Sample Mean 93.70$
Sample Size 139Sample Standard Deviation 34.55$Confidence Level 95%
Population Total 2,347,747FPC Factor 0.99724226Standard Error of the Total 73,224
Degrees of Freedom 138t Value 1.9773Interval Half Width 144785.946
Interval Lower Limit 2,202,961$Interval Upper Limit 2,492,533$
1.97651.9799
DATA
INTERMEDIATE CALCULATIONS
CONFIDENCE INTERVAL
351.22816.17
268.2083.20
139
527.13)9765.1(083.20
)2.8(2/
equationn
S t X
9765.1
9818.10053.0
10
0019.0289818.1
0019.0289818.110
9818.10019.0
2810
9818.1
9818.19799.1
110138
110120
X
X
X
X
X
X
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E Construct a 95% confidence interval estimate for the total difference between the amount reimbur
Population Size 25,056
Sample Size 139
Confidence Level 95%
Sum of Differences 241 Average Difference in Sample 1.73381295
Total Difference 43,442Standard Deviation of Differences 1.66327691FPC Factor 0.9972Standard Error of the Total Differen 3525.08483Degrees of Freedom 138t Value 1.9773Interval Half Width 6970.16272
Interval Lower Limit 36,472Interval Upper Limit 50,413
Number of Differences Not = 0 12Number of Differences = 0 127SS for Differences Not = 0 0SS for Differences = 0 381.775633Sum of Squares 381.775633Variance of Differences 2.76649009
1.7338
17 233.056525 541.315514 150.4593
For standard deviation of differences:
DATA
INTERMEDIATE CALCULATIONS
CONFIDENCE INTERVAL
ADDITIONAL CALCULATIONS
3078.474,492,2$0922.020,203,2$
1078.727,1442.747,347,2
9972.09305.2184.523,492.747,347,2
1056,25
139056,25
139
55.349765.1056,2570.93056,25
12/
total population
N nt N X N
7338.1139
2411 n
D D
n
i
i
2
D Dn
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-10 137.682420 333.653640 1464.3011
35 1106.639230 798.977328 689.9126
22 410.718315 175.9917
5 10.6680
1
1
nS i D
6231.6 DS
7139.185,714717.698,15
6211.743,270928.442,43
9972.05618.0184.523,490928.442,43
,25
0,25
139
6231.69765.1056,257338.1056,25
12/
differencetotal
N
n N
n
S t N D N D
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t contain errors.
CARA
CARA
ARA
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0.9137
visit.
te tα/2:
CARA
ARA
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interpolating
or this geographic are in June.
CARA
"MANUA
CARA
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2,347,747.2
49,523.1840
2.9305
0.9972
144,727.1078
2,203,020.09222,492,474.3078
edand the amount that the auditor determined should have been reimbursed.
6,053.375443.86506.6231
CARA
"MANUAL"
CARA
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43,442.0928
49,523.1840
0.5618
0.9972
27,743.6211
15,698.471771,185.7139
1056
13956
CARA
"MANUA
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