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1111 / / / / 34343434

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Ans. [3]

* The similar question can be found in

CP Class notes & CP Exercise sheet

* Topic - Unit & Dimension

Sol. M = d.V ⇒ d = 3L

⇒ d = 3cm

)100/1(4−

Ans. [3]

* The same question can be found in

(One dimension motion/Page no.76)

Sol. Average velocity = 21

Ans. [2]

*Topic-Work, power, energy &

conservation law

Sol. From the law of conservation of linear

momentum

j)v2)(m3(imv + = 4 mv′

v′ = jv2

Ans. [1]

* The similar question can be found in CP Class notes & CP Exercise sheet Also in CP Major test series * Topic - Friction

2222 / / / / 34343434

m 2m/s v=0

F=µmg

retardation of the block on the belt

F = µg

From v2 = u2 + 2as

0 = 22 – 2(µg) s

s = 105.02

×× = 0.4 m

Ans. [4]

* Topic - Rotational motion

Sol. From the law of conservation of angular

momentum

mvr = mv′2

v′ = 2v

so 1KE

Ans. [2]

Gravitation (Ex.-1 Q.No.1)]

Sol. vescape = RGM2

Escape velocity from earth surface.

3333 / / / / 34343434

Ans. [3]

* The same question can be found in CP Class notes & CP Exercise sheet

* Topic - Gravitation Sol.

gravitat ional potential at x point

Vx = 2/a

Ans. [3]

and Rank Shaper (AIPMT-3 Q.No.3)

* Topic - Projectile motion

45º αR/2

ucos45ºα

tanα = 2/R

hmax =

º90sinu

º45sinu

tanα = 4

α = tan–1(1/4)

Ans. [4]

4444 / / / / 34343434

Thermodynamics Ex.3B

Sol. P ∝ Tγ/γ–1

T−γγ

P2 = P1

T−γγ

P2 = 14.1

P2 = 256 atm

Ans. [3]

CP Class notes & CP Exercise sheet SHM Page no.15, Example-3 Sol.

T/12 T/12 T/6

–A/2 x=0 +A/2 AA

Time interval = 6

Phase difference ⇒ 6

T2 ≡ 3

Ans. [2]

Wave theory (Example 29 Page no.188)

Sol. n ∝ T

n ∆=

2TT ∆×=∆ = 2 ×

6006 = 0.02

Ans. [3]

* Topic-Ray optics

Sol. For without deviation

−µ−µ−=

−−

5555 / / / / 34343434

º15−=

A' = –10º

Ans. [4]

* Topic-Ray optics

I10cm 5cm

f = –30 cm

Ans. [4]

* Topic-Electrostatics Sol. WD→E = Q[VE – VD] Q VE = VD ⇒ WD→E = 0

6666 / / / / 34343434

Ans. [1] * The same question can be found in

Question bank (Q.No.39/page no.37)

* Topic-Electrostatics

Sol. Er

∂∂

+∂∂

= )]x8(i[−

)2,0,1(Er

= – i8

So electric field is 8 along negative x-axis.

16. In the circuit shown in the figure, if the potential at po int A is taken to be zero, the potential at point B is-

2Ω 2A

Ans. [1]

CP Class notes & CP Exercise sheet * Topic-Current electricity Sol. By KVL along path ACDB VA + 1 + (1) (2) – 2 = VB 0 + 1 = VB ⇒ VB = 1 volt

Ans. [4]

CP Class notes & CP Exercise sheet * Topic-Electric Instruments

S Current will be unchanged if resistance

remains same so

G = SG

⇒ R = G – SG

7777 / / / / 34343434

Ans. [1] * The similar question can be found in

CP Class notes & CP Exercise sheet * Topic-Thermoelectricity

Sol. For minimum deflection of 1 division required current = 1 µA ⇒ Voltage required = IR = (1µA) (10) = 10

µV ∴ 40 µV ≡ 1ºC

⇒ 10 µV ≡ 4

1ºC = 0.25ºC

Ans. [2]

CP Class notes & CP Exercise sheet Magnetic field Ex.3(A), Q.82

Sol. B = R2I0µ

= R2qf0µ

I = Tq

Ans. [2]

CP Class notes & CP Exercise sheet * Topic-Magnetic field

Sol. U = –MB cos θ U = –MB cos 0 = –0.4 × 0.16 = –0.064

8888 / / / / 34343434

Ans. [1]

CP Class notes & CP Exercise sheet Magnetic field (Ex.1) & discussed in class

2F = →

− 4F

1F = d2

II 210

πµ l

3F = )d(2

II 210

1F > F3 So wire attract loop.

Ans. [3]

CP Class notes & CP Exercise sheet & given in paper also *Topic-Alternating current

Sol. Vrms =

2/12/T

20 dtV

20 ]t[

= 2/12

0 )2/T(T

or Vrms =

Ans. [2]

CP Class notes & CP Exercise sheet * Topic-Alternating current

Sol. XL = 2πfL

XL ∝ f

2LX = 40 Ω

9999 / / / / 34343434

R = 30 Ω

Z = 22 )40()30( + = 50 Ω

200 = 4A

(1) 1 V (2) 2 V (3) 3 V (4) 5 V Ans. [2]

CP Class notes & CP Exercise sheet * Topic-Photoelectric effect

Sol. e

)–(h

W–EV 0Ph

= 19–

141434–

)103.3–102.8(1062.6

××××

= 191434–

109.46.1

1062.6 +×××

= 1–106.1

9.462.6×

= 2 volt

(1) 2 (2) 3 (3) 4 (4) 5 Ans [2]

* Topic-Photoelectric effect

Sol. EPh = K.Emax + W

= eV0 + W = 10 + 2.75 = 12.75 eV

12.75 eV 12.1 eV 10.2 eV

Differenced of 4 and 1 energy level is 12.75 eV

So higher energy level is 4 to ground and

Excited state is n = 3.

(1) 2N0 (2) 3 N0

N9 0 (4) 2

Ans. [3]

CP Class notes & CP Exercise sheet * Topic-Radioactivity

Sol. P Q 4N0 N0

T1/2 1 min 2 min NP = NQ

4 = 2t/2 22 = 2t/2

= 2 ⇒ t = 4 min

Disactive nucleus or Nuclei of R

N4N4 +

= 4 N0 – 4

N0 + N0 – 4

= 5 N0 – 2

10101010 / / / / 34343434

Ans. [3]

CP Class notes & CP Exercise sheet * Topic-Atomic structure Sol. 11.1 eV is not possible

Ans. [1]

* The same question can be found in CP Class notes & CP Exercise sheet Electronics Q.No.43, Page no.50

Sol. I I1

1kΩ 15V

I2 250Ω

Ι1 = Ωk1

15 = 15 mA

I = 250

1520− = 20 mA

I2 = I – I1 = 20 mA – 15 mA = 5mA

Ans. [3]

CP Class notes & CP Exercise sheet Electronics Q.No.31, Page no.29

Sol. (a), (c) are forward bias.

11111111 / / / / 34343434

CP Class notes & CP Exercise sheet * Topic-Electronics

Ans. [1]

Sol. ne nh = 2in

ne NA = 2in

ne = A

)105.1(

= 5 × 109/m3

Ans. [2]

*The same question can be found in CP class

notes and CP Ex. sheet Chemical Kinetic -

Ex.3B →→→→ Q.1

Sol. Unit of k = mol1 – n ln – 1 s–1

For zero order reaction

unit of k = mol l–1 s–1

Ans. [4]

*The similar question can be found in CP

class notes and CP Ex. sheet Chemical

Kinetic - Ex. 1 →→→→ Q.80

Sol. 1.28 → 0.64 → 0.32 → 0.16

→ 0.08 → 0.04

No. of half lifes (n) = 5

5 = 138

timeTotal

time required = 5 × 138

= 690 s

Ans. [3] *The similar question can be found in CP

class notes and CP Ex. sheet Chemical

Energetics.

12121212 / / / / 34343434

Sol. 2(i) – (iii) + (ii)

∆H = 2(150) – 350 – 125

= – 175 kJ/mol

Ans. [4] *The Similar question can be found in CP

class notes and CP Ex. sheet Chemical Bonding - Ex.3B →→→→ Q.113

Sol. O2+ = KKσ2s2 σ*2s2 σ2pz

2 (π2px2 = π2py

(π*2px1)

O2 = KKσ2s2 σ*2s2 σ2pz2 (π2px

2 = π2py2)

(π*2px1 = π*2py

O2 and O2+ contain unpaired electron in π*

ABMO so paramagnetic.

class notes and CP Ex. sheet Atomic Structure - Ex. 3A →→→→ Q.13

Sol. E =

Ans. [4] *The Similar question can be found in

CP class notes and CP Ex. sheet Ionic Equilibrium - Ex. 2A →→→→ 26

Sol. [Ag+] [Cl–] = 1.8 × 10–10

[Ag+] = 910

108.11.0

108.1 −−

[Pb+2] [Cl–]2 = 1.7 × 10–5

[Pb+2] = 35

107.11.01.0

107.1 −−

13131313 / / / / 34343434

class notes and CP Ex. sheet Gaseous State - Example.20 Page No.13

Sol. P1 = 1.5 bar P2 = 1 T1 = 288 K T2 = 298 K V1 = V V2 = ?

V2 = 1.55 V

Ans. [1] *The same question can be found in CP class

notes and CP Ex. sheet Solution and Colligative property - Ex.3A →→→→ Q.39

Sol. i = 1 – α + nα

i = 1 – 0.3 + 2(0.3)

i = 1.3

∆T f = iK f m

= 1.3 × 1.86 × 0.1

∆T f = + 0.24ºC

Freezing point of solution = – 0.24ºC

Ans. [4]

notes and CP Ex. sheet Electrochemistry in

heading standard electrode potential

Sol. 2Fe+3 + 2I– → I2 + 2Fe+2

Ans. [3]

notes and CP Ex. sheet Chemical Kinetics -

Ex.2 →→→→ Q.1

Sol. Rate = dt

1 2252 =+=−

]ON['K41

]ON[K21

5252 =

K' = 2K and K" = 2

14141414 / / / / 34343434

Ans. [1]

class notes and CP Ex. sheet Example.16 Page No. 79

Sol. πv = RTm

2.57 × 10–3 × m

200= × 0.083 × 300

m = 61038 gm mol–1

Ans. [3]

Sol. Plaster of paris = CaSO4.1/2 H2O

Epsomite = MgSO4.7H2O

Kieserite = MgSO4.H2O

Gypsum = CaSO4.2H2O

Ans. [2]

notes and CP Ex. sheet Periodic table Ex.3B

→→→→ Q.97

Sol. SnO2 react with acid as well base

So amphoteric

SnO2 + 4HCl → SnCl4 + 2H2O

SnO2 + 2NaOH → Na2 SnO3 + H2O

15151515 / / / / 34343434

Ans. [4]

class notes and CP Ex. sheet Metallurgy -

Ex.1 →→→→ Q.36

Sol. SiO2 + CaO → CaSiO3

Acidic Basic Slag

impunity flux

Ans. [4]

Sol. Aluminium dissolve in excess NaOH to

liberat ing hydrogen and forming

metaaluminate

2 Al + 2NaOH + 6H2O → 2Na Al(OH)4

or (2NaAlO2.2H2O) + 3H2

notes and CP Ex. sheet Periodic Table

Sol. M →+M M+ + e– IE1 = 5.1 eV

M+ + e– → M ∆Heg = – 5.1 eV

Ans. [4]

*The same question can be found in CP class notes and CP Ex. sheet Atom, Molecules Chemical Arithmetic - Ex.1 →→→→ Q.45

Sol. Maximum number of molecules = 2

16161616 / / / / 34343434

notes and CP Ex. sheet Solid State - Ex.1

Sol. 414.0rr

c = ⇒ ra = 414.0

100 = 241.5 pm

Ans. [1]

notes and CP Ex. sheet Chemical Bonding

Sol. Most preferred structure of SO3 with lowest

energy is as it contain maximum number of

covalent bond.

Sσ π

πσO Oσ

π(pπ–pπ bonding)

(pπ–dπ bonding)

Ans. [2]

notes and CP Ex. sheet

Sol. Due to posit ive oxidation state of Mn back

donation in π* ABMO of CO is minimum

therefore C–O bond is strongest.

Ans. [3]

class notes and CP Ex. sheet Co-ordination

chemistry Ex.11A →→→→ Q.66

Sol. [Cr(NH3)6]+3 [Ar] 3d3 4s0

three unpaired electron are present in t2g

orbited

3d t2g

17171717 / / / / 34343434

Ans. [3]

Sol. Localized l.p. is more basic than delocalized l.p.

Ans. [2]

notes and CP Ex. sheet – Biolmolecules

(Theory).

Sol. It is a fact

Ans. [2]

Sol. Intermediate carbanion is involve which is

most stable with –M group.

18181818 / / / / 34343434

Ans. [2]

notes and CP Ex. sheet GOC-I (Ex.3(A) Q.4)

H3CC = C

CH2 – CH3

Configurat ion is (trans) OR (E)

Name ⇒ 2- chloro-3-iodo- 2-pentene

Ans. [1]

CH3 – CH2 – COOH

NH3 CH3 – CH2 – COONH4

–H2O∆

CH3 – CH2 – C–NH2

Br2 + KOH

Hoffmann degradation

CH3 – CH2 – NH2

Ans. [1]

class notes

19191919 / / / / 34343434

*Ph – C – H alc. KCN Ph – CH – C – Ph

Ph – C – H

(Benzaldehyde)OH O

(Benzoin)

Conc. H2SO4

(– H2O)

*Phthalic anhydride

OH OH(Phenolphthalein)

* Methyl benzoate is involve in fries rearrangement.

C – OH + H – OCH3

(– H2O)H⊕

C – OCH3

OMethyl salicylate OR Oil of wintergreen

Ans. [4]

notes and CP Ex. sheet Bimolecules

(Theory).

Sol. Primary structure is unaffected by

denaturation.

Ans. [1] *The similar question can be found in CP

class notes and CP Ex. sheet

Sol. N.A. R ∝ ⊕ Charge on Sp2

carbon ∝ M

+− ∝

20202020 / / / / 34343434

Ans. [4]

Sol. 1° halide generally shows SN2 reaction.

(No rearrangement)

Ans. [2]

* The same question can be found in CP class notes & CP Rank Shaper dt. 24/4/11

Q. 77 & Rank Shaper dt. 3/5/11 Q. 64

Ans. [1]

* The same question can be found in CP

class notes & CP Sheet – Plant Diversity-I

Page No. 138

21212121 / / / / 34343434

Ans. [3]

class notes & CP Sheet – Plant Diversity-I

Ans. [4]

class notes & CP Sheet – Cell Biology &

Cell division, Page No. 55

Ans. [3]

class notes & AIPMT Pre Major Test -2

(Full syllabus) dt. 22/3/11 Q. 158

Ans. [4] * The same question can be found in CP

class notes & CP Sheet – Genetics - Page No. 55

Ans. [1]

* The same question can be found in CP class notes & CP Sheet – Virus & Mycoplasma - Page No. 4

22222222 / / / / 34343434

Ans. [1]

* The same question can be found in CP class notes & CP Sheet – Plant Physiology-II Chapter-Absorption of water by plants, Page No. 54

Ans. [2]

* The same question can be found in CP class notes & CP Sheet – Plant Physiology-II Chapter-Food translocation in plants, Page No. 63 and also refer pg 191 (NCERT) Mass Flow Hypothesis.

class notes & CP Sheet – Plant Anatomy – Page No. 24

Ans. [3]

* The same question can be found in CP class notes & CP Rank Shaper # 2 dt. 16/4/11 Q. 83 and CP Sheet Plant Morphology & Families of Angiosperm- Page No. 28-29

Ans. [2]

* The same question can be found in CP class notes & CP Sheet – Plant Physiology-I Chapter-Photosynthesis, Page No. 13; Ex. 1, Q. 139,144,280

23232323 / / / / 34343434

Ans. [3]

class notes & CP Sheet – Plant Physiology-

I Chapter-Photosynthesis, Page No. 19; CP

Minor test # 5

Ans. [1]

class notes & Plant Morphology &

Families of Angiosperm.

Ans. [4]

II Chapter-Mineral Nutrition, Page No. 76

Ans. [1]

* The same question can be found in CP class notes & AIIMS # 1 dt. 18/3/11, Q. 90

& CP Sheet Plant Morphology & Families

of Angiosperm- Page No. 16

Ans. [1]

class notes & CP Sheet – Life Cycle of

Angiosperm, Page No. 37

24242424 / / / / 34343434

Ans. [4]

I Chapter-Cell Respiration, Page No. 73

Ans. [3]

class notes & CP Sheet Plant Morphology

& Families of Angiosperm- Page No. 8-9

Ans. [2]

class notes & CP Sheet – Life Cycle of

Angiosperm, Page No. 19

Ans. [2]

* The same question can be found in CP class notes & CP Sheet – Ecology-I, Chapter – Organism and environment Page No. 58

Ans. [2]

* The same question can be found in CP class notes & CP Sheet – Ecology-I, Chapter- Ecosystem Page No. 86

Ans. [3]

class notes & CP Sheet – Ecology-I,

Chapter- Ecosystem Page No. 88

25252525 / / / / 34343434

Ans. [4]

class notes & CP Sheet – Ecology-II,

Chapter- Environmental Pollution &

Issues Page No. 47

Ans. [3]

class notes & CP Sheet-Demography - Page

No. 10; CP Sheet – Ecology-I, Chapter-

Population, Community Page No. 49;

Rank shaper # 4 dt. 21/4/11 Q.90

Ans. [4]

class notes & CP Sheet – Biotechnology

Page No. 9 (Organic acid)

Ans. [3]

class notes of Immunosuppressive drug-

Cyclosporin drug (Trichoderma) &

CP Sheet – Biotechnology Page No. 7 (IInd

line) and Rank shaper test-2, 16-4-2011 as

26262626 / / / / 34343434

Ans. [2]

class notes & Chapter-Virus &

Mycoplasma.

Ans. [1]

class notes & CP Sheet – Biotechnology

Page No. 14 (Biological Products)

Ans. [3]

* The same question can be found in CP class notes & CP Rank Shaper.

27272727 / / / / 34343434

Ans. [4]

* This question is similar to the question

asked in CP Rank Shaper test (growth can

not be taken as defining property of living )

(NCERT XI Class, Page 4, Line 12)

Ans. [4]

class notes & CP Sheet – Muscle - Page No.

70 (exercise)

Ans. [1]* The same question can be found in CP

class notes & CP Sheet – Animal Diversity-I

28282828 / / / / 34343434

Ans. [2]

class notes & CP Sheet – Genetics –

Page No. 28

Ans. [4]

class notes & CP Sheet – Genetics –

Page No. 10

Ans. [4]

class notes & CP Sheet–Genetics-Page no. 10

and CP Sheet – Digestive system – Ex. # 1,

Q.No. 193,218 Ex. # 2, Page no. 54, 56]

29292929 / / / / 34343434

Ans. [3]

Cell division, Page No. 19

Ans. [2]

Cell division, Page No. 19 and CP Sheet –

Respiratory System – Page No. 15

(Transport of CO2)]

30303030 / / / / 34343434

Ans. [2]

class notes & CP Sheet – Circulatory

System – Page No. 16 (ECG)]

Ans. [4]

class notes & CP Sheet – Frog - Page No.

Ans.[3]

class notes & CP Sheet – Animal Tissue

(Simple squamous Epith.) – Ex. # 1

Q.N. 3,5,29,43,88

Ans. [1]

class notes & CP Sheet – Endocrine system

- Page No. 31

Ans. [3]

class notes & CP Sheet – Skeletal System –

Page No. 30 (Girdle bones)

31313131 / / / / 34343434

Ans. [2]

class notes & CP Sheet – Lower Animal (Earthworm) – Ex. Q. 44

Ans. [1]

class notes & CP Sheet – Frog - Page No.

148 and Also in CP Sheet – Reproduction

System – State PMT Ex. Q.10

class notes & CP Sheet – Digestive system -

Page No. 25

Ans. [4]

class notes & CP Sheet – Respiratory

System – Page No. 10 (Mechanism of

breathing)

Ans. [2]

class notes & CP Sheet – Embryology –

Page No. 23 (Fertilization)

32323232 / / / / 34343434

Ans. [2]

* This question is asked in CP Rank

Shaper (Can also be seen in family

planning –

CP Sheet)

Ans. [2]

* The same question can be found in CP class notes & CP Sheet – Frog - Page No.

145 & 147

Ans. [2]

* The same question can be found in CP class notes & CP Sheet – Reproductive System – Page No. 18 (Menstrual Cycle)

Ans. [1]

* The same question can be found in CP class notes & CP Sheet – Ecology-I, Chapter- Organism & Environment Page No. 21 & Ecology-II Chapter-Biodiversity Page No. 17

33333333 / / / / 34343434

Ans. [4]

class notes & CP Sheet – Biotechnology –

Page No. 18 (Organic farming)

Ans. [3]

class notes & CP Sheet – Ecology-II,

Chapter- Biodiversity Page No. 2

Ans. [3]

* The same question can be found in CP class notes & CP Sheet – Immunity &

Disease - Page No. 34

Ans. [4]

class notes & CP Sheet- Animal diversity

& disease

34343434 / / / / 34343434

Ans. [2]

class notes & CP Sheet – Immunity & Disease - Page No. 14

Ans. [2]

Page No. 17 (Biopesticides)

Ans. [2]

Page No. 11 (R-DNA Technology)

Ans. [4]

class notes & CP Sheet – Embryology –

Page No. 28 (Importance of Notochord)

aipmt 2011 mains examination career point

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