bengkel teknik menjawab soalan upsr 2008 zon sibuti
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Musuh utama kecemerlangan
bukanlah kekurangan fizikal, sosial
atau ekonomi tetapi mental.
Saya tidak kalah apabila saya
berada di bawah. Saya hanya kalah
sekiranya saya tidak bangun semula
dari bawah.
RAJIN itu adalah punca segala
kejayaan dan MALAS pula punca
segala kegagalan.
(Dr. Shukri Abdullah)
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Strategi belajar secara
sistematik dan berkesan Dari segi mental
Mahir: fakta asas (4 operasi), guna rumus(formula), guna dan tukar unit serta
perkaitannya. Dari segi fizikal
Cergas: bersedia lebih awal sebelumpeperiksaan bermula (latihan bersistem dan
berjadual) Dari segi emosi
Sentiasa tenang: doa dan tawakal
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UPSR Mathematics
Paper 1 (Kertas 1)015/1Paper 2 (Kertas 2)015/2
Mulai 2003 soalan Matematik UPSRdikemukakan dalam dwibahasa (BahasaMalaysia dan Bahasa Inggeris). Bagaimanapun,calon hanya perlu memberi tumpuan penuhuntuk menjawab dalam satu bahasa yangdipilih.
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Topic Type of
question
Duration Number of
questions
Marks
Whole numbers
Mixed numbers
Fractions
Decimals
Percentage
Money
Shape & space
Measurement: mass,
length & volume of
liquid
Data handling
Multiple
choice
Answer all
questions
1 hour 40 40
Paper 1 015/1
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1. UTAMAKAN SOALAN YANG MUDAH
Examples:
(1) 40.129.047 =
A 4.06 B 4.14 C 10.36 D 10.99
(2) RM350RM192.05 + 15 sen =
A RM157.80 B RM158.10
C RM162.20 D RM162.80
(3) 0.5 million + 400 000 =
A 0.9 million B 0.09 million
C 0.45 million D 0.405 million
PENTING
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2 356 709647 935
768 1711 452 355
+ 84 953
Contoh :
3
Jawapan :2
2
2
1
3
0
3
1
3
3
2
5
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5. WASPADA TERHADAP PENGG
PENTING
Example:
A shop sells 630 red and yellow rosesaltogether. The shop sells 124 more red
roses than yellow roses.
How many yellow roses does the shopsell?
A. 568 B. 516 C. 382 D. 253
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6. MEMPASTIKAN SEMUA SOALAN
TELAH DIJAWAB.
Semua 40 soalan telah dijawab
Jangan conteng kertas jawapan. Hitamkan jawapan dengan penuh. Gunakan pensel 2B
Contohnya: (A) (B) (C) (D) Padamkan dengan bersihjika hendak menukar jawapan.
PENTING
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LEARNING
AREA
TYPE OF
QUESTIONS
DURATION NUMBER OF
QUESTIONS
MARKS REMARKS
Basic skill
exclude
data
handling
Not involve
difficult
problem
solving
Subjective
Calculation
process
Answer all
the
questions
40 minutes 20 40
Answer in
space
provided
Marking
scheme
-
Calculation
process
- Finalanswer
Paper 2 015/2
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Langkah-langkah menjawab soalan:
1) Soalan 1 markah = 1 minit (max) atau kurang
1 minit.2) Soalan 2 markah dan 3 markah = gunakan
masa seminimum mungkin iaitu kurangdaripada 2 minit.
3) Masa yang lebih digunakan untuk menyemakjawapan (sekiranya ada)
4) Pastikan tulisan anda KEMAS dan JELAS.
5) Setiap soalan perlu ditunjukkan langkahpengiraan yang TERATUR dan LENGKAP.Pastikan jawapan akhir mengikut kehendaksoalan.Langkah pengiraan mempunyai
taburan markah yang tertentu. Walaupun
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LULUS?????
Pass at least C : 18 questionsPaper 118 marksPaper 2
Lu lus sekurang-kurangnya Gred C
: 18 soalan - kertas 1
: 18 markah - kertas 2
Gred A :
perform both papers BUT Paper 2 determines
candidate to get Gred A. Gred A : Lulu s kedua-dua kertas dengan
cemerlang TETAPI Kertas 2 menentukan calon
un tuk mendapatkan Gred A.
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~Kejayaan dan
kemenangan hanya lahmilik orang yang
berusaha~
Percaya kepada diri sendiri ialah rahsia pertama
untuk mencapai kejayaan
- Ralph Waldo marson
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Topic analysis
PAPER 2: KOD 015/2
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PENTING!!!!!
Salin soalan denganJELAS dan TEPAT.
Jawapan yang dibawa kebawah mesti JELAS dan
TEPAT.Pastikan unit/jawapan
ditulis berdasarkan
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PENTING!!!!!
Penukaran unit mestiditulis dengan JELAS.
Sekiranya soalanmenggunakan
rumus/formula, gantikandengan nilai yangsepatutnya.
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PENTING!!!!!
Gunakan Sistem 1, 2, 3 dalampenyelesaian masalah.
1: Ayat matematik
2: Langkah pengiraan
3: Jawapan akhirJangan tinggalkan tempat
kosong.
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QUESTION 1 TO 5
1 MARK)
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TOPIC ANALYSIS
WHOLE NUMBERS
FRACTIONS, DECIMALS &
PERCENTAGEMEASUREMENT : MASS,
LENGTH & VOLUME OF LIQUID
TIME
SHAPE & SPACE
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WHOLE NUMBERS
Write number in
numeralor inwordsDetermine place value
and digit valueRound off
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State the digit value of 4 in the
number 45 090. (UPSR 2007)
45 090
40 0 00
Underlined digit 4
Replace other digits with 0
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5 7 3 4 9
State the place value of the numeral
7 in 57 349. (UPSR 2004)
Determine place value for each digit
OTHThTTh
Underlined digit 5
ThousandsAnswer
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Write fifty thousand and three in
numerals. (UPSR 2006)
TTh Th H T O
Draw place value chart
Insert digit in the place value column
5 0 30 0
Empty column: insert 0
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Round off 38 572 to the nearest ten
thousand. (UPSR 2003)
3 8 5 7 2
Underlined digit in ten thousands
Circle the digit on the right
Less than 5 +0, if 5 or more +1, on circled digit
+1
4 0 0 0 0
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FRACTIONS, DECIMALS &
PERCENTAGE
Write fractions inwords,numeral, simplest formandequivalent fraction
Decimals: place valueanddigit valueConversion
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Convert 0.13 to a fraction.
(UPSR 2004)
Answer:
0 . 1 3 =13
0. 1 3 100
tenths
hundredths
001
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Convert 3.09 to a mixed number.
(UPSR 2005)
Answer:
3 . 0 9 =9
3. 0 9 100
ones
3
tenths
hundredths
001
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Convert 93% to decimals. (UPSR 2006)
93% =93
100
93 100 = 9 31 0 00
= 0.93
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Diagram 1 shows the weight of a apple.
(UPSR 2004)
What is the weight, in g, of the apple?
0
250
750
1
kg
500
Diagram 1
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1 kg
250
500
750
01 kg
250
500
750
01 kg
250
500
750
0
250 5 = 50g
50
50
5050
50
250 + 100 = 350gAnswer:
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TIME
Read a clock face
12-hour system
24-hour system
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Diagram 2 shows Azwans dinner time.
(UPSR 2007)
Diagram 2
Write the time in the 24-hour system
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1
2
3
4
56
7
8
9
10
1112
8.00 p.m.
5 mins
10 mins
15 mins
20 mins
Answer 2020 hours0800 + 1200 = 2000
24-hour system
After 12.00 p.m.
+ 1200
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SHAPE AND SPACE
Namethe shape
2 D shapes : square, rectangle,
triangle, circle etc.
3 D shapes: cube, cuboid, cone,
pyramid, cylinder etc.
Characteristicsof the shapeEdge, vertex, side, flat surface, curve
surface etc
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Diagram 3 shows a cuboid. (UPSR 2007)
State the number of vertices.
vertex
8 vertices
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Table 1 shows the characteristics of a
three dimensional shape. (UPSR 2006)
Number of vertices 8
Number of equal edges 12
Name three dimensional shape.
edgevertex
cube
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Always do your best........
What you plant now ,
you will harvest later
Og Mandino
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QUESTION 6 TO 15
(2 MARKS)
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TOPIC ANALYSIS:
WHOLE NUMBERS, FRACTIONS, DECIMALS,PERCENTAGE, TIME, MONEY, MASS, LENGTH,
VOLUME OF LIQUID, SHAPE SPACE.
BASIC OPERATIONS (+, -, X, )MIXED OPERATIONS
CONVERSION OF UNIT
PERIMETER AREAVOLUME OF 3D SHAPES
AVERAGE
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UPSR 2002
5
21
5
4+ =
16
5
655
1
11 + 1
1
5 21
5
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UPSR 2002
45.37.09 =
45.3
- 7.09
10 102
1283 .
03
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0.72 9 = ____ (UPSR 2002)
0 . 7 29
0
0707 2
0 8
7 2
-
-
. 98
7
65
4
32
1
0
0
1
2
34
5
67
8
9
0
UPSR 2002
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100 5= 2020 5= 4
96 4 =
100
25 X 96
Answer:
UPSR 2002
Calculate 25% of 96
5
20
25 5= 55 5= 1
24
1
4
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(UPSR 2003)
Find the value of of RM270.5
2
RM270x52 = RM108
2 X RM270 = RM 540
RM540 4 = RM108
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UPSR 2007
6 days x 9 = __ weeks __ days
Notes: 1 week = 7 days
6 x 9 = 54
54 7 = 7 remainder 5
Answer: 7 weeks 5 days
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(UPSR 2006)
Diagram 6 shows the time Sue Lan
reaches her school in the morning.
Diagram 6
She leaves her
house at 6.45 a.m.
How longdoes it
take her to reach
her school?
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Hour Minute
7 15
45-
Anwer: 30 minutes
6
6 +60
30
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Hour Minute
3 3530+
3 65601+ -
4 5
Answer: 4 hours 5 minutes
T th t
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(UPSR 2006)
3 years 7 months + 5 years 8 months =
____years __________months
(UPSR 2005)4 hours 15 minutes + 1 hour 50
minutes
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.00
(UPSR 2004)
RM9RM0.75 + RM2.35 =___
RM9
RM0.75
81
9 10
-
RM8.25
RM2.35+RM10.60
1
T bl 1 h th titi f t
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Table 1 shows the quantities of notes
and coins. ( UPSR 2005)
Money Quantity
RM5 4
50 sen 3
Calculate the total value of the money.
TABLE 1
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Answer:
RM 5 x 4 = RM 20
RM 5 + RM 5 + RM 5 + RM 5 = RM 20
@
50 sen + 50 sen + 50 sen = 150 sen
50 sen x 3 = 150 sen @
150 sen 100 = RM1.50
C ti d
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Continued
RM 20 + RM 1.50 =
RM 20.00+ RM 1.50
RM 21.50
(UPSR 2007)
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(UPSR 2007)
Calculate 4.03 km750 m.
Give your answer, in m.
CONVERSION OF UNIT
4.03 km = ______ m km m
x 1000
10004. 0 3 x 1000= 4030 m
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1 km = 1000 m
4
4.03 km - 750 m
0 3
7 5 0
0
-
2 8 03
Answer:
3 280 m3 19 10
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(UPSR 2006)
Calculate 2.05 kg x 12.
Give your answer, in g.(UPSR 2007)
Calculate 1.27 l 10.Give your answer, in ml.
Try these out:
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Diagram 4 consists of three triangles,
PQR, RSU and STU of the samesize.
(UPSR 2005)
8 cm
6 cm
10 cm
P
Q
RS
U T
Calculate the
perimeter,in cm, of the
whole
diagram
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Jangan takut menghadapi kegagalan kerana
dengan kegagalan kita beroleh pengetahuan
tentang kekurangan dan kelemahan diri kita ,
yang ditakuti ialah gagal untuk kali kedua
dalam perkara yang sama
-Hamka
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QUESTION 16 TO 20 3 MARKS)
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TOPIC ANALYSIS: PROBLEM SOLVING
INCLUDE WHOLE NUMBERS,PERCENTAGE , MONEY,
MEASUREMENT (MASS, LENGTH
& VOLUME OF LIQUID ),TIME,
SHAPE & SPACE AND AVERAGE.
THE PROBLEM SOLVING WILLCOMBINE 2 OR MORE SKILLSIN
A QUESTION.
TIPS
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TIPSProblem solving:Penyelesaian masalah (cara-caranya)
a) Read the questionBaca soalan yang diberi
b) Extract the informationKumpul maklumat:
What is given? Apa yang diberi?What is asked for? Apa kehendak soalan?What opeartion is needed?Apa operasi yang diperlukan?
c) Calculate step by step.
Kira (langkah pengiraan yang TERATUR danLENGKAP)d) Check the answer
Semak semula
Ahmad Bala and Chong collected used tins The
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Ahmad, Bala and Chong collected used tins. The
averagenumber of tins collected by the 3 boys was
16. Ahmad and Chong collected 9 and 17 tins,
respectively.
Calculate the number of tins collected by Bala.
(UPSR 2003)
Follow the flow of the question
Total value of unit : average x number of unit
Average : Total value of unitNumber of unit
Manipulate the formula
Average : Total value of unit
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Total value of unit : average x number of unit
Average : Total value of unitNumber of unit
Manipulate the formula
22 tins48179 =
16 x 3 = 48 tins
Answer:
Diagram 6 shows a collection of three
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Diagram 6 shows a collection of three
types of shapes. (UPSR 2007)
Calculate the percentage of of the whole collection.
Calculate the percentage of of the whole collection.
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=100%x20
5
= 5 pieces
Total shapes = 20
x 100%
1
4
=
20%
ANSWER:
20
55 x 100 20
Musa has RM100. He buys a pair of
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y p
shoes for RM72.90 and 3 pens for
RM4.50 each.
How much money does he have left?
(UPSR 2004)
RM4.50 X 3 = RM13.50RM72.90 + RM13.50 =
RM100.00RM86.40 =
penTotal
RM13.60
Left
Answer
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Linas mother used of 2 kgof
sugar to bake a cake.How much sugar did she use?
Give your answer, in g. (UPSR 2003)
1
4
1
4
x 2000 g =
500 g2 kg = 2000 g
1 x 2000 4
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Notes to remember!
Topic/
Fraction
Mass
(kg=g)
Length
(km=m)
Volume of liquid
(l=ml)
1
2
0.5 kg
500 g
0.5 km
500 m
0.5l
500 ml
1
4
0.25 kg
250 g
0.25 km
250 m
0.25l
250 ml
3
4
0.75 kg
750 g
0.75 km
750 m
0.75l
750 ml
A bottle contains 1 5 l of water
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A bottle contains 1.5lof water.
of the water is split.
How much is the volume, in ml, of water is left
in the bottle? (UPSR 2004)
5
2
TOPIC/
FRACTION
MASS LENGTH VOLUME
OF LIQUID
0.2kg = 200g 0.2km = 200m 0.2l= 200ml
0.4kg = 400g 0.4km = 400m 0.4l= 400ml
0.6kg = 600g 0.6km = 600m 0.6l= 600ml
0.8kg =800g 0.8km =800m 0.8l=800ml
1
5
25
3
5
4
5
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Answer:
1 500 m200 m =
1.5 x 1000= 1 500 m
1 300 m 1 500
2001 300
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Table 1 shows the time taken by Mohan
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Table 1 shows the time taken by Mohan
to revise his lesson. (UPSR 2007)
4
3
Subject Time taken
Mathematics 1 hour 30 minutes
Science hour
Mohan starts his revision at 2.15 p.m.At what timedoes Mohan finishhis revision?
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Answer:
2 151 30
3 4545903
1 60-+
+
+
304
at 4 30p m
MinuteHour
Diagram 5 shows a rectangle PQRS
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Diagram 5 shows a rectangle PQRS
and a square PKLM. (UPSR 2005)
P
3 cm
M
K
L
S12 cm
7 cm
Q
R
Calculate the area, in cm2,
of the shaded region.
Area: Length x Breadth
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84
Area: Length x Breadth
12 cm x 7 cm = 84cm2PQRS
PKLM 3 cm x 3 cm = 9cm2
Shaded
region84cm29cm2= 75cm2
Answer: 75cm2
(UPSR 2007)
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85
(UPSR 2007)
Diagram 4 shows a rectangle JKLM
and a right angled triangle LKN.J
M L
K N6 cm
8 cm
JKN is straight line.The length of KN is equal tothe length of KL.
Calculate the area, in cm2, of the coloured region.
JK N6
cmJKN is straight line.
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86
Formula for AREA of Triangle:
1
2x Base x Heigth
1
2
x (6 cm + 8 cm) x 6 cm
14 x 6 =
2 1
3
=
42 cm2
M L8
cm
JKN is straight line.
The length of KN is equal tothe length of KL.
Calculate the area, in cm2, of the coloured region.
(UPSR 2006)
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87
(UPSR 2006)
Table 2 shows the number of classes
and the averagenumber of pupils inYear One and Year Two.
YearNumber of
classes
Average number of
pupils
One 4 31
Two 3 35
Find the differencebetween thenumber of pupils in Year One and Year
Two.
Average : Total value of unit
Average : Total value of unit
Average : Total value of unit
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88
g u f unNumber of unit
Manipulate the formula
Total value of unit : average x number of unit
Year 1: 31 x 4 = 124
Year 2: 35 x 3 = 105Difference: 124 - 105 15 pupils
g u f unNumber of unit
Manipulate the formula
Total value of unit : average x number of unit
g u f unNumber of unit
Manipulate the formula
Table 2 shows the length of 4 ribbons
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89
g
bought by Karina. (UPSR 2005)
Ribbon Length
Blue 4.2 m
Green 1.25 m
Yellow 0.5 m
Red 2.25 m
Calculate the averagelength,in m, of the ribbons.
TABLE 2
Average : Total value of unitAverage : Total value of unit
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90
g fNumber of unit
Average:
4.2 m + 1.25 m + 0.5 m + 2.25 m4
= 8.20 m = 2.05 m
4
g fNumber of unit
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91
~Tiada kejayaansemanis madu tanpa
usaha sepahithempedu ~
RENUNGKAN!!!!
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92
RENUNGKAN!!!!
Some people watch it happened. Somepeople wonder what has happened. Somepeople makes it happened!
Perjalanan seribu langkah dimulai denganperjalanan satu langkahKegemilangan masa depan, dicorakkan
oleh tangan Anda.
Fikir kejayaan, usaha ke arah kejayaan.Ambil keputusan untuk menjadi orangberjaya hari ini juga!
STANDING IN THE EYES OF THE WORLD
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Pahit getir hidup, dan pengorbanan
Terpaksa dihadapi, demi kejayaan
Terdidik sejak mula,tabah berusaha
Tanpa cuba melangkah,
tak kemana, Di mana kau berada
Pencapaian tak tiba dengan mudah
( korus )
Kini
"Standing In The Eyes Of The World"
Hanyalah selangkah dari nyata
Keazaman membara dijiwa
Menanti saat bebas merdekaTiba masa kau melangkah gagah
Bersemangat ke arah matlamat sedaya
upaya, Engkau terunggul
Wajar
"Standing In The Eyes Of The World"
Harapan yang pernahterkulai layu
Kembali segar mekar bawah
bayanganmu
Setiap manusia ingin berjaya
Namun tak semua miliki tuahEngkau menghampirinya
Kesempatan telah pun tiba...
Salin soalan :JELAS & TEPAT
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94
Salin soalan :JELAS & TEPAT
5900 + 7891405 =
5900789+
6689
66891405-
UPSR 2006
798
6698
6698
52935284
Jawapan :JELAS & TEPAT
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Jawapan :JELAS & TEPAT
5900 + 7891405 =
5900789+
6689
66981405-
5293
UPSR 2006
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