detailed analysis of jee main 2015
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JEE Main 2015 question paper detailed analysisOVERALL PAPER:
1.Overview (general theme setting and touching upon briefly on all points). We can have aJEE 2014 vs 2015 approach
2.Class XI and XII break-up of syllabus3.Difficulty level analysis - by section and overall
o Question-wise difficulty level break-upo Section-wise difficulty level break-upo Questions that should've been attempted firsto Questions that should've been avoided in first go
4.Time management analysis - by section and overallo Question-wise time spent break-upo Section-wise time spent break-upo Questions that should've been attempted firsto Questions that should've been avoided in first go
5.Special Insights and Tricks that could've been usedo 2 questions that were wrong, why?o Speed tips that could've saved timeo Trick questions?
Seemingly difficult but easy questions Seemingly easy but difficult questions
Analysis
The question papers were available in four sets- A, B, C and D.
Version Order of Subjects
A Physics, Chemistry, Mathematics
B Chemistry, Mathematics, Physics
C Mathematics, Physics, Chemistry
D Physics, Mathematics, Chemistry
Physics: : It was the toughest amongst the three; the questions that were included in this sectionwere a little tricky. Out of the 30 questions from Physics, only five questions were theory based,the rest 25 were numerical based questions. It was a time consuming section. Some experts alsobelieve that the questions in this section were ambiguous, which increased the difficultylevel. The topic of Thermodynamics in Physics was very tough, especially the Entropy questionswere quite unexpected. About 25% of the questions are pertaining to graphs. a few areas likewave optics, properties of liquids etc. were totally absent in the paper.
Ideal Time for Physics – (Student should invest 75 min. for this section)
Chemistry Majority of the questions in the Chemistry part of the JEE Main 2015 are in the rangeof easy to moderate. The overall difficulty level of this part in this year exam is less as comparedto last year. Usually, application level questions are expected from Physical and Organicchemistry areas, but this year questions from these two areas were quite straight in nature.However, one question from Inorganic Chemistry was based on practical part and it can be rateddifficult to answer. Moreover, this year's contribution from Inorganic Chemistry was morecompared to previous years. The questions were all fact based. This section was not very timeconsuming. Most of the questions are asked directly from the NCERT texts for Chemistry.
Ideal Time for Chemistry – (Student should invest 40 min. for this section)
Mathematics: This section, however, not difficult, was found a little lengthy by the examinees. Ithad a good mix of questions. Also, two questions were not properly framed in Mathsection. One was from Probability (All options were incorrect) and other was from DifferentialEquation. (Initial condition was not given). There was one question each from Statistics, SetRelation and Mathematical Reasoning and one easy questions from height and distancetrigonometry. All these chapters are not in JEE Advanced Syllabus. Questions from InverseTrigonometry ,3-D and Vectors were easy. Few questions, which posed difficulty, weregenuinely concept wise difficult and tricky in nature.
Ideal Time for Math – (Student should invest 65 min. for this section)
Analysis of JEE (Main) 2015 Paper -1
Marks Distribution from Class XII CBSE Syllabus
Subject No. of questions Total Marks
Mathematics 14 56
Chemistry 20 80
Physics 17 68
Marks Distribution from Class XI CBSE Syllabus
Subject No. of questions Total Marks
Mathematics 16 64
Chemistry 10 40
Physics 13 52
Q.No.Topic(based on SET-A) JEE mainPaper-1 Easy Moderate Difficult
1 Kinematics
embibepredicted highweightage
2 Unit & Dimensions
embibepredicted easyto score
3 Laws of Motion
embibepredicted LowWeightage
4 Conservation of Momentum
embibepredicted easyto score (MustDo)
5 Centre of Mass
embibepredictedLowWeightage
6 Rotational Mechanics embibe
predicted LowWeightage
7 Gravitation
embibepredicted highweightage
8 Simple Harmonic Motion
embibepredicted highweightage
9 Heat &Thermodynamics
embibepredicted highweightage
10 Heat &Thermodynamics
embibepredicted highweightage
11 Heat &Thermodynamics
embibepredicted highweightage
12 Simple Harmonic Motion
embibepredicted highweightage
13 Wave & Sound
embibepredicted highweightage
14 Electrostatics
embibepredicted highweightage
15 Electrostatics
embibepredicted highweightage
16 Electrostatics
embibepredicted highweightage
17 Electrostatics
embibepredicted highweightage
18 Electrostaticsembibe
predicted high
weightage
19 Magnetism
embibepredicted highweightage
20 Magnetism
embibepredicted highweightage
21 Magnetism
embibepredicted highweightage
22 Magnetism
embibepredicted highweightage
23 Optics
embibepredicted highweightage
24 Optics
embibepredicted highweightage
25 Optics
embibepredicted highweightage
26 Optics
embibepredicted highweightage
27 Modern Physics
embibepredicted highweightage
28 Modern Physics
embibepredicted highweightage
29 Communication Systems
embibepredicted highweightage
30 Magnetism
embibepredicted highweightage
31 s-Block elements and Hydrogen
embibepredicted LowWeightage
32 Solid State
embibepredictedLowWeightage
33 Atomic Structure
embibepredicted highweightage
34 Chemical Bonding
embibepredicted highweightage
35 Thermochemistry and thermodynamics
embibepredicted highweightage
36 Liquid solution
embibepredicted highweightage
37 Chemical Equilibrium
embibepredicted easyto score (MustDo)
38 Electrochemistry
embibepredicted highweightage
39 Chemical kinetics
embibepredicted highweightage
40 Surface chemistry
embibepredicted highweightage
41 Periodicity
embibepredictedLowWeightage
42 Metallurgy embibe
predicted highweightage
43 s-Block elements and hydrogen
embibepredictedLowWeightage
44 s-Block elements and hydrogen
embibepredictedLowWeightage
45 group 15 - 18
embibepredicted highweightage
46 Transition metals
embibepredicted highweightage
47 group 15 - 18
embibepredicted highweightage
48 Coordination compounds
embibepredicted highweightage
49 Coodination compounds
embibepredicted highweightage
50 group 15 - 18
embibepredicted highweightage
51 Stoichiometry
embibepredicted highweightage
52General Organic Chemistry andIsomerism
embibepredicted highweightage
53 Hydrocarbons
embibepredicted easyto score
(Must Do)
54 Alkyl and Aryl halides
embibepredicted highweightage
55 Aldehyde and Ketone
embibepredicted highweightage
56 Amines
embibepredictedLowWeightage
57 Polymers
embibepredicted easyto score(Must Do)
58 Biomolecules
embibepredicted easyto score(Must Do)
59 Chemistry in everyday life
embibepredicted easyto score(Must Do)
60 Salt Analysis
embibepredicted easyto score(Must Do)
61 Matrices
embibepredicted highweightage
62 Complex Number
embibepredicted highweightage
63 Quadratic Equation & Expression
embibepredicted highweightage
64 Matrices embibe
predicted highweightage
65 Determinants
embibepredicted highweightage
66 Permutation & Combination
embibepredictedLowWeightage
67 Binomial Theorem
embibepredicted highweightage
68 Progression & Series
embibepredicted highweightage
69 Progression & Series
embibepredicted highweightage
70 Limit,Continuity & Differentiability
embibepredicted highweightage
71 Limit,Continuity & Differentiability
embibepredicted highweightage
72 Straight Lines
embibepredicted highweightage
73 Application of Derivatives
embibepredicted highweightage
74 Indefinite Integral
embibepredicted LowWeightage
75 Definite Integral
embibepredicted highweightage
76 Area under Curves embibe
predicted highweightage
77 Differential Equation
embibepredicted easyto score(Must Do)
78 Straight lines
embibepredicted highweightage
79 Straight lines
embibepredicted highweightage
80 Circle
embibepredicted highweightage
81 Ellipse
embibepredicted highweightage
82 Parabola
embibepredicted highweightage
83 3 - D Geometry
embibepredicted highweightage
84 3 - D Geometry
embibepredicted highweightage
85 Vector Algebra
embibepredicted highweightage
86 Probability
embibepredicted highweightage
87 Statistics
embibepredicted easyto score (MustDo)
88 Height & Distance
embibepredicted easyto score (MustDo)
89 Inverse Trigonometric Function
embibepredicted easyto score (MustDo)
90 Mathematical Reasoning
embibepredicted easyto score (MustDo)
Physics – 25 Questions From High weightage and 2 from Easy to Score – (90% from the topicsmentioned important by embibe.
Chemistry – 18 Questions From High weightage and 6 from Easy to Score – (80% from thetopics mentioned important by embibe.
Math– 23 Questions From High weightage and 5 from Easy to Score – (93.3% from the topicsmentioned important by embibe.
Category Expected Cutoff Score 2015
Common Merit List (CML) 112-117
Other Backward Class (OBC - NCL) 74-80
Scheduled Caste (SC) 53-59
Scheduled Tribe (ST) 46-50
Tricks for lengthy questions –
1. A complex number z is said to be unimodular if |z| = 1. suppose z and z are complex
numbers such that is unimodular and z is not unimodular. Then the point z lies on a:
(A) Circle of radius √2(B) Straight line parallel to x-axis.
(C) Straight line parallel to y-axis.
(D) Circle of radius 2
Answer: (D)
Sol. – Put z = 0, as it is not unimodular, we can assume z = 0, so we will get as unimodular
which will give us |z | = 2. Hence Option (D) is correct.
2. The normal to the curve, x + 2xy − 3y = 0, at (1, 1):
(A) Meets the curve again in the fourth quadrant.
(B) Does not meet the curve again.
(C) Meets the curve again in the second quadrant.
(D) Meets the curve
again in the third quadrant.
Answer: (A)Its Pair of straight lines passing through origin.x + 3y = 0 or x − y = 0 so normal at (1,1) will meets the curve again in thefourth quadrant. (Draw Diagram).
3. The negation of ~s ∨ (~r ∧ s) is equivalent to:
(A) s ∧ r(B) s ∧∼ r(C) s ∧ (r ∧ ∼ s)(D) s ∨ (r ∨ ∼ s)Answer: (A)Consider it as Sets.
S = (1, 2) …..(i)r = (2, 3)U = (1, 2, 3, 4)Draw the Venn Diagram.S = (3, 4) (negesion of s)r̅ = (1, 4) (negesion of r)(r̅ ∩ S) = 1
And S U (r̅ ∩ S) -(3, 4) U (1) = (1, 3, 4)And Compliment of (1, 3, 4) is (2) which is (s ∩ r). Hence Option (A) is correct.
4. If A = 1 2 22 1 −2a 2 b is a matrix satisfying the equation AA = 9I, where I is 3 × 3 identity
matrix, then the ordered pairs (a, b) is equal to:
(A) (−2,−1)(B) (2, −1)
(C) (−2, 1)(D) (2, 1)Answer: (A)1 2 22 1 −22 1 22 1 22 −2 =
9 0 00 9 00 0 9Multiply first row of A [1 ,2,2] by last column of . We will get + 4 + 2 = 0Only option (A) satisfies it.
5. If m is the A.M. of two distinct real numbers ( , > 1) , are threegeometric means between , ℎ + 2 + equals.
(A) 4(B) 4(C) 4(D) 4Answer: (C)From Dimension Analysis (A) is incorrect as giving dimension of (length) the power 6. FromSymmetry (C) is the answer. Links.
6. Let O be the vertex and Q be any point on the parabola, = 8 . If the point P divides theline segment OQ internally in the ratio 1 : 3, then the locus of P is:
(A) = 2(B) =(C) =(D) = 2Answer: (A)
Sol. Find any one point on the locus and substitute in answers. Like (4,2) is a point on the curveand (1,1/2) divides OQ in the ratio 1:3. Hence (1,1/2) will satisfy the options.
7. The equation of the plane containing the line 2 − 5 + = 3 ; + + 4 = 5, and parallelto the plane, + 3 + 6 = 1, is:
(A) 2 + 6 + 12 = −13(B) 2 + 6 + 12 = 13(C) + 3 + 6 = −7(D) + 3 + 6 = 7Solution (D) Let the plane be + 3 + 6 = ,
As it contains the common line of line 2 − 5 + = 3 ; + + 4 = 5, we can find any pointon the line and substitute it in the our plane and find the value of K.
Put z = 0, 2 − 5 = 3 ; + = 5We will get x =4 and y=1. Put (4, 1, 0) in + 3 + 6 = , you will get K=7.
Hence (D) is the Correct option.
8. The sum of coefficients of integral powers of x in the binomial expansion of 1 − 2√ is:
(A) (2 + 1)(B) (3 + 1)(C) (3 )(D) (3 − 1)Solution: (B)It’s an easy question but if it is not striking to you then you can do it by Simulation Technique.
Put 50 as 2 in the question and options. The question will become
The sum of coefficients of integral powers of x in the binomial expansion of 1 − 2√x is:
(A) (2 + 1)(B) (3 + 1)(C) (3 )(D) (3 − 1)1 − 2√x = 1 - 4 √x + 4x.
Sum of integral powers of x would be 5. (1 + 4 )
Only Option B is correct.
9. Locus of the image of the point (2, 3) in the line (2x − 3y + 4) + k (x − 2y + 3) = 0, k ∈R, is a :
(A) Circle of radius √3(B) Straight line parallel to x-axis.
(C) Straight line parallel to y-axis.
(D) Circle of radius √2Solution: (D)The infinite lines (2x − 3y + 4) + k (x − 2y + 3) = 0, k ∈ R, are passing through (1,2) and willhave infinite images of (2,3), Obviously the locus would not be a straight line (Draw .theDiagram ). As one of the line passes through (2,3) and image of (2,3) in that line would be (2,3)
itself, therefore (2,3) would lie on the locus. And distance of (2,3) from (1,2) is √2 hence option(D) is correct.
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