how can you solve a problem using a linear relationship if you are not given an initial value?

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How can you solve a problem using a linear relationship if you are not given an initial value?. In this lesson you will learn how to solve a problem involving a linear relationship by making a table and graph. - PowerPoint PPT Presentation

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How can you solve a problem using a linear relationship if you are not given an initial

value?

In this lesson you will learn how to solve a problem

involving a linear relationship by making a table and graph.

Let’s Review

Linear relationships are commonly expressed in three ways: tables,

graphs, and equations.

x y

-3 -4

0 -2

3 0

6 2

y = mx + b

+3

+2

+2

+2

+3

+3

A Common Mistake

Interpreting the wrong point as the y-intercept

Core Lesson

You are going to a carnival with your friend. You know that there is a fee to get into the carnival, and then you also

pay to go on rides.Your friend paid $5.50 and rode 2 rides.

Each ride costs $0.75.

How much will it cost to pay the entry fee and ride 8 rides?

Constant rate of change

Core Lesson

Number of Rides Cost

0 ??

1 ??

2 $5.50

3 $6.25

4 $7.00

5 $7.75

+0.75

+0.75

+0.75

Rate of change = slope = $0.75

Core Lesson

How to solve this problem?

1) Use the table2) Find an equation to model this

function3) Put the points from the table on a

graph, and use the graph

Core Lesson

Number of Rides Cost

0

1

2 $5.50

3 $6.25

4 $7.00

5 $7.75

6 $8.50

7 $9.25

8 $10.00

+0.75

+0.75

+0.75

Core Lesson

How to solve this problem?

1) Use the table2) Find an equation to model this

function3) Put the points from the table on a

graph, and use the graph

Core Lesson

Number of Rides Cost

0

1

2 $5.50

3 $6.25

4 $7.00

5 $7.75

c = $0.75r + $4.00

$4.75

$4.00

c = $0.75(8) + $4.00 = $10.00

-0.75

-0.75

Work backwards

Core Lesson

How to solve this problem?

1) Use the table2) Find an equation to model this

function3) Put the points from the table on a

graph, and use the graph

Core Lesson

Number of Rides Cost

0

1

2 $5.50

3 $6.25

4 $7.00

5 $7.75

+0.75

+0.75

+0.75

Rate of change = slope = $0.75 = ¾

Core Lesson

Number of rides

Cost (in dollars)

(4, $7.00)(5, $7.75)

(3, $6.25)(2, $5.50)

(8, $10.00)

In this lesson you have learned how to solve a problem

involving a linear relationship by making a table and

graphing.

Guided Practice

A 2-mile cab ride costs $5.25. A 5-mile cab ride costs $10.50. How much does a 4.2-mile cab ride cost, if the cost of the cab is calculated by the mile?

Extension Activities

Extension Activities

Quick Quiz

A water jug with 3 cups of water in it weighs 2.25 pounds. With 5 cups of water it weighs 3.25 pounds. How much does the water jug weigh when empty?

Quick Quiz

Sean likes to eat cookies. He eats 3 cookies per day. Five days after opening a box of cookies, there are 24 cookies left in the box. How many cookies were in the box at the time it was opened?

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