the traveling salesman problem in theory & practice

Post on 25-Feb-2016

55 Views

Category:

Documents

1 Downloads

Preview:

Click to see full reader

DESCRIPTION

The Traveling Salesman Problem in Theory & Practice. Lecture 1 21 January 2014 David S. Johnson dstiflerj@gmail.com http:// davidsjohnson.net Seeley Mudd 523, Tuesdays and Fridays. Today’s Outline. Requirements, References, & Introductions Problem Definition Applications - PowerPoint PPT Presentation

TRANSCRIPT

The Traveling Salesman Problem in Theory & Practice

Lecture 121 January 2014

David S. Johnsondstiflerj@gmail.com

http://davidsjohnson.net

Seeley Mudd 523, Tuesdays and Fridays

Today’s Outline1. Requirements, References, & Introductions2. Problem Definition3. Applications4. Paths and Cycles5. Complexity6. Introduction to Optimization7. Introduction to Approximation8. Preview of the Rest of the course

Requirements and Grading• Class presentation of results from the

literature.

• Written paper:– Survey paper on an approved topic

– Report on your own new experimental work

– Theoretical paper on new results of your own

• Regular class participation.

About Me• Ph.D. in Mathematics from MIT (1973). Thesis: Near-

Optimal Bin Packing Algorithms.

• 40 years at AT&T (Bell Labs, AT&T Labs – Research), with one year off for good behavior (U. Wisconsin, 1980-81).

• Most famous publication: Computers and Intractiability: A Guide to the Theory of NP-Completeness, (1979, with Mike Garey).

• Many theoretical and experimental papers on the TSP with many co-authors, starting with the proof that the Euclidean version is NP-Hard.

Optional Reference BooksThe Traveling Salesman Problem, Lawler, Lenstra, Rinnooy Kan, and Shmoys (Editors), Wiley (1985). $377.47 (current amazon.com price, new)

The Traveling Salesman Problem and Its Variations, Gutin and Punnen (Editors), Kluwer (2002). $152.10

The Traveling Salesman Problem: A Computational Study, Applegate, Bixby, Chvatal, and Cook, Princeton University Press (2006). $57.99/$44.99 (Kindle)

In Pursuit of the Traveling Salesman, Cook, Princeton University Press (2012). $20.64/$15.37 (Kindle)

Web Resources• http://www.math.uwaterloo.ca/tsp/

“The Traveling Salesman Problem” (Bill Cook)

• http://dimacs.rutgers.edu/Challenges/TSP/ “The 8th DIMACS Implementation Challenge: The Traveling Salesman Problem” (DSJ)

• http://comopt.ifi.uni-heidelberg.de/software/TSPLIB95/ “TSPLIB” (Testbed of Instances, Gerd Reinelt)

• http://davidsjohnson.net/papers.html (DSJ’s downloadable papers on the TSP and other topics)

• http://en.wikipedia.org/wiki/Travelling_salesman_problem (Wikipedia Entry -- Much Improved)

The Traveling Salesman Problem

Given:Set of cities {c1,c2,…,cN }. For each pair of cities {ci,cj}, a distance d(ci,cj).

Find: Permutation that

minimizes)c,d(c)c,d(c π(1)π(N)

1N

1i1)π(iπ(i)

N}{1,2,...,N}{1,2,...,:π

Alternative DefinitionGiven:

Graph G = (V,E)Length d(e) for each edge e in E.

Find: Minimum length Hamiltonian Circuit in the

complete graph G’ on V, where if {u,v} is not in E, we assume d(e) = ∞.

N = 10

N = 10

N = 100

N = 1000

N = 10000

Jan Karel Lenstra

Planar Euclidean Application #1

• Cities:

– Holes to be drilled in printed circuit boards

N = 10000

N = 2392

Planar Euclidean Application #2

• Cities:

– Wires to be cut in a “Laser Logic” programmable circuit

N = 7397

N = 33,810

N = 85,900

Other Types of Instances• X-ray crystallography

– Cities: orientations of a crystal– Distances: time for motors to rotate the crystal

from one orientation to the other

• High-definition video compression– Cities: binary vectors of length 64 identifying the

summands for a particular function– Distances: Hamming distance (the number of

terms that need to be added/subtracted to get the next sum)

Data Storage Layout

Goal: For each row, have as many consecutive entries as possible (minimizes the number of random accesses)

Asymmetric Applications• Payphone Money Collection with One-Way Streets• Stacker-Crane• No-Wait Flowshop• Disk Scheduling• Compiling to Minimize Branching Cost• Minimum Length Common Superstring

The Stacker Crane Problem

No-Wait FlowshopJob: Task on Processor

1Task on Processor 2

Schedule:

Processor 2

Processor 1

No-Wait Flowshop2

1 3

1

2

13

1

6

5

Disk Scheduling

Disk Scheduling

Locations of the fragments of a file one want to retrieveDistance between two fragments = time it takes to move the read head from the end of one to the beginning of the next, taking into account the spinning of the disk

Compiling to Minimize Branching Cost

Code Segment ending in a BranchIn execution, the delay at the end of the segment is much less if the next instruction to be executed is the next one in the code, say 1 versus k.

Based on profiling, one can determine the empirical probability that each branch is taken.

Following A directly by B causes an expected delay of PB + kPC. Following A directly by C causes an expected delay of PC + kPB. Following A directly by anything else causes an expected delay of k.

PB

PC

AC

B

Shortest Superstring• Given: Finite set of S strings over some

alphabet.• Find: Shortest string that contains all

strings in S as substrings.• Cities: Strings in S.• Distances: d(x,y) = |y| - maximum

overlap between a suffix of x and a prefix of y.

X = “alphabet”, y =“ betrayal” d(x,y) = 5 alphabet betrayal

d(y,x) = 6 betrayal alphabet

Hamiltonian Path versus Cycle

• Four variants (both for symmetric and asymmetric TSP).– Cycle– Path between between fixed endpoints– Path with fixed starting vertex– Path with unconstrained endpoints.

• A code for any one can be adapted to handle any of the others.

Path with Fixed Endpoints:Cycle via Path

st

Call Path algorithm once for s and each vertex t in V-{s}. Return result with best value of Path Length + dist(t,s)

Path with Fixed Endpoints:Path via Cycle

st

Add one new vertex and two new edges. Compute shortest cycle, then delete the added vertex and edges

Path with One Fixed Endpoint viaPath with Two Fixed Endpoints

s

For each t in V – {s}, find shortest Hamiltonian path from s to t. Return the best.

Path with Two Fixed Endpoints viaPath with One Fixed Endpoint

st

Add one new vertex t’ with an edge to t. The shortest Hamiltonian path starting with s must end at t’.

t’

Path with No Fixed Endpoints viaPath with One Fixed Endpoint

For each s in V, find shortest Hamiltonian path starting from s. Return the best.

Path with One Fixed Endpoint viaPath with No Fixed Endpoint

s

Add new vertex s’ and an edge from s’ to s.

s’

Directed via Undirected

v1in v1

out

v1

v2in v2

out

v2

v3in v3

out

v3

vNin vN

out

vN

Replace each vertex vi by a triplet of vertices viin,

vi, viout, and edges {vi

in,vi} and {vi,viout}

Replace each directed edge (vi,vj) by the undirected edge {vi

out,vjin}.

v3out

v1in

v1out

v1

v2in v2

out

v2

v3in

v3

v4in v4

out

v4

TSP: The Canonical NP-Hard Problem?

• Commonly used in the popular press to explain NP-completeness and exponential time to the layman: The number of tours grows as N! (actually (N-1)!/2 for symmetric case):

N # Tours N # Tours3 1 12 39,916,800

4 3 13 518,918,400

5 12 14 7,264,857,600

6 60 15 108,972,864,000

7 420 16 1,743,565,824,000

8 3,360 17 29,640,619,008,000

9 30,240 18 533,531,142,144,000

10 302,400 19 10,137,091,700,736,000

11 3,326,400 20 202,741,834,014,720,000

N! = Ω(2NlogN) time is not requiredO(N22N) suffices! [Bellman, 1963][Held & Karp, 1962]

Algorithmic technique: Dynamic ProgrammingStates: Pairs [U,j] with 2 ≤ j ≤ N and {v1,vj} ⊆ U ⊆ V.

Note: There are θ(N2N) states [U,j].Values: X[U,j] is the length of the shortest Hamiltonian path, starting with v1 and ending with vj, in the subgraph of G induced by U.Note: The optimal tour length equals

min {X[V,j] + d(vj,v1): 2 ≤ j ≤ N}.

Computing the Values X[U,j]X[{v1,vj},j] = d(v1,vj) , 2 ≤ j ≤ N.

Now assume we already have computed X[U,j], 2 ≤ j ≤ N, for all U, {v1,vj} ⊆ U ⊆ V, with |U| = k.

Let W be such that v1 ∈ W ⊆ V and |W| = k+1. Suppose vi, i > 1, is in W. Then

X[W,i] = min {X[W - {vi},j] + d(vj,vi): vj ∈ W - {vi}}

Computation takes O(N) time for each state [W,i]. Since there are θ(N2N) states overall, this yields an overall running time of O(N22N).

N = 85,900

Current World Record (2006)

Using a parallelized version of the Concorde code, Helsgaun’s sophisticated variant on Iterated Lin-Kernighan, and 2719.5 cpu-days

Concorde • “Branch-and-Cut” approach exploiting linear

programming to determine lower bounds on optimal tour length.

• Based on 30+ years of theoretical developments in the “Mathematical Programming” community, plus some very good data structures and heuristics work from computer science.

• For surprisingly large instances, it finds an optimal tour and proves its optimality (unless it runs out of time/space).

• Executables and source code can be downloaded from http://www.tsp.gatech.edu/

Running times (in seconds) for 10,000 Concorde runs on random 1000-city planar Euclidean instances (2.66 Ghz Intel Xeon processor in dual-processor PC, purchased late 2002).

Range: 7.1 seconds to 38.3 hours

Concorde Asymptotics[Hoos and Stϋtzle, 2009 draft]

• Estimated median running time for random Euclidean instances.

• Based on– 1000 samples each for N = 500,600,…,2000– 100 samples each for N = 2500, 3000,3500,4000,4500– 2.4 Ghz AMD Opteron 2216 processors with 1MB L2

cache and 4 GB main memory, running Cluster Rocks Linux v4.2.1.

0.21 · 1.24194 √N

Actual median for N = 2000: ~57 minutes, for N = 4,500: ~96 hours

For Larger Instances: Fast Heuristics• Tour construction heuristics like Nearest Neighbor,

Greedy, Christofides.

• Local search heuristics like 2-Opt, 3-Opt, Lin-Kernighan, Iterated Lin-Kernighan, or Helsgaun’s Algorithm.

• A range of heurstics may be useful, based on tradeoffs between tour quality and running time.

Necessary Digression: Metrics

• As the TSP is defined, the city-city distances (edge lengths) are only constrained to satisfy

1. d(c,c’) ≥ 0, for all pairs of cities c,c’ (non-negativity)

2. d(c,c’) = 0 if and only if c = c’

• To be a quasimetric, the distances also must satisfy the “triangle inequality”

3. d(c,c’) ≤ d(c,c’’) + d(c’’,c’) for all triples of cities

• To be a metric, the distances must also be symmetric:

4. d(c,c’) = c(c’,c), for all pairs of cities c,c’

Shortest Path “Metric”• Let d be a TSP distance function. For any pair c,c’ of

cities, let dS(c,c’) be the length of shortest path from c to c’ under d.

• Note that dS will be a quasimetric (and a metric if d is symmetric)

• For most real-world applications, dS is actually the distance function of interest, and so the triangle inequality holds.

• As we shall see shortly, if we have the triangle inequality, we can obtain good performance guarantees for certain heuristics.

Additional Restriction in Practice• Distances are integers.

– Simplifies codes.– Yields a definitive optimal solution value.– Not a real restriction if distances are rational.– Allows us to cope with the problemmatic

Euclidean metric.

Euclidean Difficulties• The length of a TSP tour for points in the plane under

the Euclidean metric is a sum of square roots:Length = ∑i(xi)1/2

• Given such an expression and a constant B our current best algorithm for determining whether the length is less than B takes exponential time.

• Hence, we do not even know whether the decision problem version of the Euclidean TSP is in NP.

• And if we round the distances to some fixed precision, then we may get different optimal tours for different precisions (up to an exponential number of bits).

Rounding Conventions1. Round Nearest dn(x) = floor(x+.5)

– Likely to be yield tour lengths closest to the true Euclidean– Although optimal tours may opportunistically favor the

rounded-down edge lengths– And triangle inequality may no longer be obeyed

dn(x,z) = 3 > dn(x,y) + dn (y,z) = 1 + 1 = 2.

1.3 1.3x z

y

Rounding Conventions2. Round Down df(x) = floor(x)

– Possibly most efficiently computable.– But underestimates true tour length. – Also fails to obey triangle inequality. floor(3.8) > floor(1.9) + floor(1.9)

3. Round Up dc(x) = ceiling(x) – Does obey the triangle inequality.– But overestimates true tour length.

Exploiting Triangle Inequality

• Observation 1: Any connected graph in which every vertex has even degree contains an “Euler Tour” – a cycle that traverses each edge exactly once, which can be found in linear time.

• Observation 2: If the Δ-inequality holds, then traversing an Euler tour but skipping past previously-visited vertices yields a Traveling Salesman tour of no greater length.

Obtaining the Initial Graph• Double MST algorithm (DMST):

– Combine two copies of a Minimum Spanning Tree.– Theorem [Folklore]: DMST(I) ≤ 2Opt(I).

• Christofides algorithm (CH):– Combine one copy of an MST with a minimum-length

matching on its odd-degree vertices (there must be an even number of them since the total sum of degrees for any graph is even).

– Theorem [Christofides, 1976]: CH(I) ≤ 1.5Opt(I).

Optimal Tour on Odd-Degree Vertices(No longer than overall Optimal Tour by the

triangle inequality)

Matching M1 Matching M2+ = Optimal Tour

Hence Optimal Matching ≤ min(M1,M2) ≤ OPT(I)/2

2-Opt

3-Opt

Smart-Shortcut Christofides

1 million cities on my 3.06 Ghz iMac: Lin-Kernighan gets within 2% of optimal in 61 seconds.

The “strip” heuristic gets within 30% in 2 seconds.

Compared to 40% for the much slower “double MST” heuristic.

The Held-Karp Bound and the Optimal Solution Value

Integer Programming Formulation for Symmetric TSP

• Minimize ∑dixi

where di is the length of edge ei

• Subject to xi ∈ {0,1}, for all edges ei ∈ C X C

∑c∈eixi = 2, for all cities c ∈ C,

∑|ei∈U|=1 xi ≥ 2, for all proper subsets U ⊂ C

Linear Programming Relaxation: “Held-Karp” or “Subtour” Bound

• Minimize ∑dixi

where di is the length of edge ei

• Subject to xi ∈ [0,1], for all edges ei ∈ C X C

∑c∈eixi = 2, for all cities c ∈ C,

∑|ei∈U|=1 xi ≥ 2, for all proper subsets U ⊂ C

Percent by which Optimal Tour exceeds Held-Karp Bound

For “Uniform Points” in the Unit Square (+), the gap appears to decline to a value of about 0.44% asymptotically.

Computing the HK Bound• Major obstacle: exponential number of cut constraints.

∑|ei∈U|=1 xi ≥ 2, for all proper subsets U ⊂ C.

• However, one can find violated constraints in polynomial time by maximum flow techniques (and other heuristics).

• Concorde has options for computing the bound in roughly this way (5 hours on my iMac for a million cities).

• One can also construct an alternative LP formulation that is of polynomial size, so the HK bound can in principle be computed in polynomial time.

Topics to Be Covered• NP-completeness proofs, hardness of approximation results.• Polynomial-time (and 2o(n)-time) solvable special cases.• Branch-and-cut optimization algorithms (Concorde, etc.): theory and

engineering.• Properties of optimal solutions.• Polynomial-time approximation tour construction heuristics with good worst-

case guarantees and/or average case performance.• Data structures, exploiting geometry, and other speed-up tricks for heuristics.• Local Optimization heuristics (2-Opt, 3-Opt, Lin-Kernighan).• Metaheuristics (neural nets, simulated annealing, genetic algorithms, etc.).• Variants (max TSP, min-latency TSP, prize-collecting TSP, Vehicle routing, …)

top related