warm–up #1. warm–up #1 solutions isolate abs val check in original!! not a soln!
Post on 18-Jan-2016
219 Views
Preview:
TRANSCRIPT
Warm–up #11. Solve
2.
3 32 2
7 9 22 2 2
3 34 4
911 44 4 4
5114 4
2 3( ) 1
2 3( ) 1
3
2
2 3 13 3
3 3 or (3 3)2 3 or 3 3
3 or 4 3
23
or 4
t tt t
t t t tt t t
t t
t
Warm–up #1 Solutions
Isolate Abs Val
Check in original!!
NOT a soln!
Abs Val either (+) or zero
But, NEVER (–)
NO SOLUTION
Warm–up #1 Solutions
3 7 4x
Homework LogThurs
10/1
Lesson 2 – 1
Learning Objective: To solve absolute values & solve for variables
Hw: #202 Pg.102 #33 – 59 odd, 67, 69
10/1/15 Lesson 2 – 1 Absolute Values & Formulas Day 2
Advanced Math/Trig
Learning Objective
To solve absolute value equations
To solve for variables
Solving for a Variable1. Solve for r: P = A(1 – rx)
P = A – Arx –A –A
P – A = –Arx –Ax –Ax
or
Solving for a Variable2. Solve for i:
(1+𝑛𝑖)(1+𝑛𝑖)
Absolute Value Equations
3.
x – 2 = 3x + 1 or x – 2 = –(3x + 1)
–2x = 3 or x – 2 = –3x –14x = 1
Check for extraneous solutions!
Absolute Value Equations
3. Check!
Amount of Loan
(1 )A P rt
A: amt owed on
loan
P: principal
r: interest rate
t: time
% decimal
Amount of Loan
interest = 11% r
= .11
t = 3
A = 4522
P = ?
4. A sum of $ is borrowed at 11% per year & amt required to pay off loan after 3 years is $4522. How much $ is borrowed?
principal
A = P(1 + rt)
4522 = P(1+ (.11)(3))
4522 = P(1.33)
P = $ 3400
Discount Rate
(1 )P A rn A: maturity value
P: proceeds
r: discount rate
n: years discounted
% decimal
Discount Rate
n = 2
P = 889.20
rate = 11% r = .11
A = ?
5. Find the maturity value of a note discounted for 2 years if the proceeds are $889.20 and discount rate is 11%.
P = A(1 – rn)
889.20 = A(1 – (.11)
(2))
889.20 = A(.78)
A = $ 1140
Discount Rate
n = 5
P = 225
A = 1500
r = ?
6. The maturity value of a note discounted for 5 years is $1500 with the proceeds of $225. Find the discount rateP = A(1 – rn)
225 = 1500(1 – (r)(5))
225 = 1500 – 7500r
–1275 = –7500r
0.17 = r r =
17%
7.
8x – 12 = 8x – 8 Or 8x – 12 = – (8x – 8)
– 12 = – 8 8x – 12 = – 8x+8
No solution 16x = 20x =
Absolute Value Equations
7. x =
Check for Extraneous Solutions
8.
2x – 1 = 5 or 2x – 1 = – 5 +1 +1 +1 + 12x = 6 2x = – 4 2 2 2 2
x = 3 or x = – 2 {–2, 3}
Solving an Absolute Value Equation
Ticket Out the Door
Solve for a
Explain your process.
Homework
#202 Pg. 102 #33 – 59 odd, 67, 69
top related