an introduction to trigonometry slideshow 44, mathematics mr. richard sasaki, room 307
DESCRIPTION
The Right-Angled Triangle Trigonometry is like Pythagoras but includes angles. When we have a specified angle, the vocabulary is different. Angle (Theta) Hypotenuse Opposite Adjacent Simple trigonometry involves 2 edges and an angle. If one thing is missing, how do we find it?TRANSCRIPT
An Introduction to Trigonometry
Slideshow 44, MathematicsMr. Richard Sasaki, Room 307
Objectivesβ’ Learn and recall some components of the
right-angled triangleβ’ Understand the meaning of sine, cosine and
tangent in terms of trianglesβ’ Understand the graphs
The Right-Angled TriangleTrigonometry is like Pythagoras but includes angles. When we have a specified angle, the vocabulary is different.
πAngle
(Theta)
HypotenuseOpposite
Adjacent
Simple trigonometry involves 2 edges and an angle. If one thing is missing, how do we find it?
Special Case TrianglesWe saw two basic cases, the 30-60-90 triangle and the 45-45-90 triangle.
30π1 2
β345π
1 β2
1We need to think about the relationship between the edge lengths and the angles. Any ideas?The relationship lies with the three main trigonometric functions, , and .sine cosine tangent
Sine, Cosine and TangentSine, cosine and tangent are the relationships between edge lengths and angles.In calculation, sine, cosine and tangent are shown as , and respectively. We still usually refer to them by their full names though.Each refer to two of the edges.
π
Hypotenuse
Opp
osite
Adjacent
SineCosineTangentS
O HC
A HT
O AYou will need to remember these links.
π
Sine, Cosine and TangentIn fact, sine, cosine and tangent are functions on angles which equates to the ratio of the corresponding two edges.
Hypotenuse
Opp
osite
Adjacent
π ππ (π )=ΒΏπππππ ππ‘π
π»π¦πππ‘πππ’π π
πππ (π )=ΒΏπ΄πππππππ‘
π»π¦πππ‘πππ’π π
π‘ππ (π )=ΒΏπππππ ππ‘ππ΄πππππππ‘
hypotenuse
adjacent
opposite
0 90 0101 0β
As , neither are the hypotenuse so there is no restriction between their sizes.
12 β3
2
β33β2
2β221
Trigonometric FunctionsUsing the same methods, we can calculate trigonometric values for .
30π60π1 2
β3
π ππ (60 )=ΒΏπππππ ππ‘π
π»π¦πππ‘πππ’π π=ΒΏβ32
πππ (60 )=ΒΏπ΄πππππππ‘
π»π¦πππ‘πππ’π π=ΒΏ12
π‘ππ (60 )=ΒΏπππππ ππ‘ππ΄πππππππ‘=ΒΏβ3With a little more imagination, we can do the
same for and .
BoundariesWe do not have time to explore further but after looking at many values inserted in the trigonometric functions, we would have the following boundaries:
β€ π ππ (π )β€β1 1β€πππ (π )β€β1 1ΒΏ π‘ππ (π )<ΒΏββ β
This means the β axes corresponding to these graphs must obey these rules. What do these graphs look like?
We know the graph must satisfy .We saw that , and . This isnβt enough data to draw it, but it looks like this:
12
β22
β32
1
β1
π (π₯)
180 360 540 720 90090
Note: We are using degrees, not radians.
Again, the graph satisfies .We saw that , and . Itβs the opposite, right? Basically itβs like but shifted back :
β32
β22
12
1
β1
π (π₯)
180 360 540 720 90090
This graph has no boundaries about .What is happening? , and .
β33 1
β3
4
β4
π (π₯)
180 360 540 720 90090
The sizes are increasing.There is a cycle howeverβ¦like this:
Note: tends to infinity.