announcements hw set 10 due this week; covers ch 24.5-9 (skip 24.8) and 25.1-3 office hours: prof....

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Announcements • HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 • Office hours: • Prof. Kumar’s Tea and Cookies 5-6 pm today • My office hours Th 2 -3 pm • or make an appointment • Final exam Saturday 4/23, 3 – 5 pm, CUMULATIVE EXAM • Make-up exam, Wednesday 4/20, 5:10 – 7:00 pm, NPB 1220, CUMULATIVE EXAM • Always check out http://www.phys.ufl.edu/courses/phy2054/spring11/ for more announcements QUESTIONS? PLEASE ASK!

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Page 1: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Announcements

• HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3

• Office hours:• Prof. Kumar’s Tea and Cookies 5-6 pm today • My office hours Th 2 -3 pm

• or make an appointment

• Final exam Saturday 4/23, 3 – 5 pm, CUMULATIVE EXAM

• Make-up exam, Wednesday 4/20, 5:10 – 7:00 pm, NPB 1220, CUMULATIVE EXAM

• Always check out http://www.phys.ufl.edu/courses/phy2054/spring11/ for more announcements

QUESTIONS? PLEASE ASK!

Page 2: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

From last time…

Constructive and Destructive Interference

Young’s double slit experiment Bright fringe: d sin θbright = m λ

Dark fringe: d sin θbright = (m+1/2) λ

Thin film interference Three different media Constructive and destructive

interference equations depend on indices of refraction for each media

Page 3: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Interference in Thin Films Interference is due to the

interaction of the waves reflected from both surfaces of the film

Ray 1 - phase change of 180° with respect to the incident ray

Ray 2 - no phase change with respect to the incident wave

Ray 2 travels an additional physical distance of 2t in the film

The wavelength λ is reduced by n in the film the optical path length is 2 n t

Constructive interference 2 n t = (m + ½ ) λ m = 0, 1, 2 …

takes into account both the difference in optical path length for the two rays and the 180° phase change

Destructive interference 2 n t = m λ m = 0, 1, 2 …

Page 4: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Anti-reflection coatings

Two phase shifts

Constructive interference 2 n t = m λ

m = 0, 1, 2 … takes into account both the

difference in optical path length for the two rays and both 180° phase changes

Destructive interference 2 n t = (m + ½ ) λ

m = 0, 1, 2 …

Page 5: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Handling thin films problems

Identify the thin film causing the interference

Determine the indices of refraction in the film and the media on either side of it

Determine the number of phase reversals: zero, one or two

Interference is constructive if the path difference is an integral multiple of λ and destructive if the path difference is an odd half multiple of λ

NOTE: The conditions are reversed if one of the waves undergoes a phase change on reflection

Equation 1 phase reversal0 or 2 phase reversals

2nt = (m + ½) constructive destructive

2nt = m destructive constructive

Page 6: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Diffraction Huygen’s principle – light waves

spread out after they pass through slits

diffraction

Diffraction occurs when waves pass through small openings, around obstacles or by sharp edges

A good example was Young’s double slit experiment

A single slit placed between a distant light source and a screen produces a diffraction pattern

broad, intense central band a series of narrower, less intense

secondary bands secondary maxima In between the secondary maxima are

a series of dark bands minima

Cannot be explained by geometric optics!!

Page 7: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Single Slit Diffraction

Huygen’s principle - each portion of the slit acts as a source

Light from one side of the slit interferes with light from the other side

The resultant intensity on the screen depends on the direction θ

Wave 1 travels farther than wave 3 by a path length difference d = (a/2) sin θ

If d = /2, the two waves cancel each other and destructive interference results

2sin2

a

DEMO

Page 8: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Single Slit Diffraction, 2 Divide slit into 1/4, 1/6, … In general, destructive

interference occurs for a single slit of width for:

m = 1, 2, 3, … Note: doesn’t give any

information about the variations in intensity along the screen

2sin2

ma

Page 9: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Single Slit Diffraction, 3

Broad central bright fringe flanked by much weaker bright fringes alternating with dark fringes

Points of constructive interference lie approximately halfway between the dark fringes

Page 10: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Problem 24.36, p 819

A screen is placed 50 cm from a single slit that is illuminated with light of wavelength 680 nm wavelength. If the distance between the first and third minima is 3.0 mm, what is the width of the slit?

Page 11: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Polarization of Light Waves Each electron in an atom produces a

wave with its own orientation of E Electrons in oscillating sinusoidal

motion

Unpolarized light - all directions of the electric field vector are equally possible and lie in a plane perpendicular to the direction of propagation of the light

A wave is said to be linearly polarized if the resultant electric field vibrates in the same direction at all times at a particular point

Polarization can be obtained from an unpolarized beam by

Selective absorption Reflection Scattering In Lasers

E

unpolarized

polarized

Page 12: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours
Page 13: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

The most common technique for polarizing light Your sunglasses!!

Uses a material that i) transmits waves whose electric field vectors in the plane

are parallel to a certain direction and ii) absorbs waves whose electric field vectors are

perpendicular to that direction

Polarization by Selective Absorption

Page 14: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Selective Absorption

ET = Eo cos

I E2

IT = Io cos2 θ

Io is the intensity of the polarized wave incident on the analyzer

This is known as Malus’ Law and applies to any two polarizing materials whose transmission axes are at an angle of θ to each other

Page 15: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Problem 24.58, p 821

Plane-polarized light is incident on a single polarizing disk, with the direction of E0 parallel to the direction of the transmission axis. Through what angle should the disk be rotated so the intensity of the light is reduced by a factor of (a) 2, (b) 4, and (c) 6?

Page 16: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Polarization by Reflection

Page 17: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Polarization by Reflection II The angle of incidence

for which the reflected beam is completely polarized is called the polarizing angle, θp

Brewster’s Law relates the polarizing angle to the index of refraction for the material

θp may also be called Brewster’s Angle

Brewster’s Angle

Page 18: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Polarization by Scattering When light is incident on a system of

particles, the electrons in the medium can absorb and reradiate part of the light

This process is called scattering

An example of scattering is the sunlight reaching an observer on the earth becoming polarized

The horizontal part of the electric field vector in the incident wave causes the charges to vibrate horizontally

The vertical part of the vector simultaneously causes them to vibrate vertically

Horizontally and vertically polarized waves are emitted

Why is the sky blue?

Page 19: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Optical Activity

Certain materials display the property of optical activity A substance is optically active if it

rotates the plane of polarization of transmitted light

Also called birefringence Optical activity occurs in a material

because of an asymmetry in the shape of its constituent materials

Page 20: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Answer to 23.36

Page 21: Announcements HW set 10 due this week; covers Ch 24.5-9 (skip 24.8) and 25.1-3 Office hours: Prof. Kumar’s Tea and Cookies 5-6 pm today My office hours

Answer to 23.58