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41
1 P02 - Class 02: Outline Answer questions Hour 1: Review: Electric Fields Charge Dipoles Hour 2: Continuous Charge Distributions

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Page 1: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

1P02 -

Class 02: Outline

Answer questionsHour 1:

Review: Electric FieldsChargeDipoles

Hour 2:Continuous Charge Distributions

Page 2: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

2P02 -

Last Time: FieldsGravitational & Electric

Page 3: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

3P02 -

Gravitational & Electric Fields

Mass M Charge q (±)

2ˆMG

r= −g r 2

ˆeqkr

=E rCREATE:

g m=F g E q=F E

This is easiest way to picture field

FEEL:

Page 4: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

4P02 -

PRS Questions:Electric Field

Page 5: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

5P02 -

Electric Field Lines1. Direction of field line at any point is tangent to

field at that point2. Field lines point away from positive charges

and terminate on negative charges3. Field lines never cross each other

Page 6: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

6P02 -

In-Class Problem

d

s

q− q+

P

ij

Consider two point charges of equal magnitude but opposite signs, separated by a distance d. Point Plies along the perpendicular bisector of the line joining the charges, a distance s above that line. What is the E field at P?

Page 7: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

7P02 -

Two PRS Questions:E Field of Finite Number of Point

Charges

Page 8: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

8P02 -

Charging

Page 9: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

9P02 -

How Do You Charge Objects?

• Friction• Transfer (touching)• Induction

Neutral----

++++

+q

Page 10: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

10P02 -

Demonstrations:Instruments for

Charging

Page 11: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

11P02 -

Electric Dipoles

A Special Charge Distribution

Page 12: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

12P02 -

Electric DipoleTwo equal but opposite charges +q and –q,

separated by a distance 2a

q

-q

2a charge×displacementˆ ˆ×2 2q a qa

= =

p

j j

Dipole Moment

p

p points from negative to positive charge

Page 13: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

13P02 -

Why Dipoles?

Nature Likes To Make Dipoles!

http://ocw.mit.edu/ans7870/8/8.02T/f04/visualizations/electrostatics/20-Molecules2d/20-mole2d320.html

Page 14: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

14P02 -

Dipoles make Fields

Page 15: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

15P02 -

Electric Field Created by DipoleThou shalt use components!

3 3x ex xE k q

r r+ −

⎛ ⎞∆ ∆= −⎜ ⎟

⎝ ⎠

3 3y ey yE k q

r r+ −

+ −

⎛ ⎞∆ ∆= −⎜ ⎟

⎝ ⎠

3/2 3/22 2 2 2( ) ( )e

x xk qx y a x y a

⎛ ⎞⎜ ⎟= −⎜ ⎟⎡ ⎤ ⎡ ⎤+ − + +⎣ ⎦ ⎣ ⎦⎝ ⎠

3/2 3/22 2 2 2( ) ( )e

y a y ak qx y a x y a

⎛ ⎞− +⎜ ⎟= −⎜ ⎟⎡ ⎤ ⎡ ⎤+ − + +⎣ ⎦ ⎣ ⎦⎝ ⎠

2 3 3 3

ˆ ˆ ˆx yr r r r

∆ ∆= = +

r r i j

Page 16: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

16P02 -

PRS Question:Dipole Fall-Off

Page 17: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

17P02 -

Point Dipole Approximation

Take the limit r a>>

You can show…Finite Dipole

30

3 sin cos4x

pEr

θ θπε

( )23

0

3cos 14y

pEr

θπε

→ −Point Dipole

Page 18: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

18P02 -

Shockwave for Dipole

http://ocw.mit.edu/ans7870/8/8.02T/f04/visualizations/electrostatics/06-DipoleField3d/06-dipField320.html

Page 19: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

19P02 -

Dipoles feel Fields

Page 20: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

20P02 -

Demonstration:Dipole in Field

Page 21: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

21P02 -

Dipole in Uniform FieldˆE=E i

ˆ ˆ2 (cos sin )qa= +p i jθ θ

( ) 0net q q+ −= + = + − =F F F E E

tends to align with the electric field p

Total Net Force:

Torque on Dipole: = ×τ r F( )( )2 sin( )a qE θ=

= ×p Esin( )rFτ θ+= sin( )pE θ=

Page 23: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

23P02 -

PRS Question:Dipole in Non-Uniform Field

Page 24: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

24P02 -

Continuous Charge Distributions

Page 25: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

25P02 -

Continuous Charge Distributions

( ) ?P =E

Vi

iQ q

Break distribution into parts:

= ∆∑

2ˆe

qkr∆

∆ =E r

E field at P due to ∆q

Superposition:

= ∆∑E E

V

dq→ ∫

d→ ∫ E

2ˆe

dqd kr

→ =E r

Page 26: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

26P02 -

Continuous Sources: Charge DensitydVdQ ρ=

R

L

2Volume V R Lπ= = QV

ρ =

LQ

QA

σ =

dAdQ σ=w

L

Area A wL= =

dLdQ λ=Length L=

L

Page 31: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

31P02 -

Example: Ring of Charge

P on axis of ring of charge, x from centerRadius a, charge density λ.

Find E at P

Page 33: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

33P02 -

Ring of Charge3) Write Equation dq a dλ ϕ=

2

ˆe

rd k dqr

=E

a) My way

3x exdE k dqr

=

b) Another way

22 xar +=

3erk dqr

=

cos( )xdE d θ= E 2 3

1e e

x xk dq k dqr r r

= ⋅ =

Page 34: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

34P02 -

Ring of Charge4) Integrate

3x x exE dE k dqr

= =∫ ∫22 xar +=

dq a dλ ϕ=

3exk dqr

= ∫

Very special case: everything except dq is constant

2aλ π=dq∫2 2

0 0a d a d

π πλ ϕ λ ϕ= =∫ ∫

Q=

Page 35: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

35P02 -

Ring of Charge5) Clean Up

3x exE k Qr

=

( )3/ 22 2x exE k Q

a x=

+

0a →

( )3/ 22 2ˆ

exk Q

a x=

+E i

6) Check Limit

( )3/ 2 22

ex e

k QxE k Qxx

→ =

Page 36: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

36P02 -

r

2L

−2L

+

s

P

j

i

In-Class: Line of Charge

Point P lies on perpendicular bisector of uniformly charged line of length L, a distance s away. The charge on the line is Q. What is E at P?

Page 37: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

37P02 -

r

θ

θ

2L

−2L

+

xd ′

x′

xddq ′= λs

22 xsr ′+=

P

j

i

Hint: http://ocw.mit.edu/ans7870/8/8.02T/f04/visualizations/electrostatics/07-LineIntegration/07-LineInt320.html

Typically give the integration variable (x’) a “primed” variable name.

Page 38: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

38P02 -

E Field from Line of Charge

2 2 1/ 2ˆ

( / 4)eQk

s s L=

+E j

Limits:

2ˆlim e

s L

Qks>>

→E j Point charge

ˆ ˆ2 2lim e es L

Qk kLs s

λ<<

→ =E j j Infinite charged line

Page 39: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

39P02 -

In-Class: Uniformly Charged Disk

P on axis of disk of charge, x from centerRadius R, charge density σ.

Find E at P

( 0 )x >

Page 40: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

40P02 -

Disk: Two Important Limits

( )1/ 22 2ˆ1

2disko

x

x R

⎡ ⎤⎢ ⎥= −⎢ ⎥+⎣ ⎦

E iσε

Limits:

2

1 ˆlim 4diskx R o

Qx>>

→E iπε

*** Point charge

ˆlim 2diskx R o<<

→E iσε

Infinite charged plane

Page 41: Answer questions Hour 1: Review: Electric Fields Charge ... · P02 - 3 Gravitational & Electric Fields Mass M Charge q (±) 2 ˆ M G r gr=− G 2 ˆ e q k r Er= G CREATE: Fgg =m G

41P02 -

E for Plane is Constant????

1) Dipole: E falls off like 1/r3

2) Point charge: E falls off like 1/r2

3) Line of charge:E falls off like 1/r4) Plane of charge: E constant