answer scheme for biol pat 2011 form 4
TRANSCRIPT
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7/31/2019 Answer Scheme for Biol Pat 2011 Form 4
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UNIT PEPERIKSAAN DALAMANSMKA AL-IRSHADPOKOK SENA , KEPALA BATAS
PEPERIKSAAN AKHIR TAHUNTINGKATAN 4BIOLOGY 4551/2KERTAS 2OKTOBER 2011
2 hours thirty minutes Dua jam tiga puluh minit
JANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHUINFORMATION FOR CANDIDATES
1. This question paper consists of three sections :Section A and Section B
2. Answer all questions in Section A. Write your answers forSection A clearly in the spaces provided in the question paper
3. Answer TWO question from Section B. Write your answer forSection B on the lines paper in detail. You may use equations,diagrams, tables, graphs and other suitable methods to explainyour answer.
4. Show your working, it may help you to get marks..
5. If you wish to cancel any answer, neatly cross out the answer.
6. The diagrams in the questions are not drawn to scale unlessstated.
7. Marks allocated for each questions or part question are shown inbrackets
8. The time suggested to complete Section A is 90 minutes, SectionB is 60 minutes.
9. You may use a non-programmable scientific calculator
10 Hand in this question paper at the end of the examination
For Examiners Use
Section QuestionFull
MarksMarks
Obtained
A
1 12
2 12
3 12
4 12
5 12
B
6 20
7 20
8 20
9 20
Total 100
Kertas soalan ini mengandungi 15 halaman bercetak
1
Nama :
Tingkatan ..
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SECTION A60 MARKS
Answer all questions
1. Figure 1 shows a typical cell observed under the electron microscope.
FIGURE 1
(a) ( i ) Identify whether it is plant cell or an animal cell
Plant cell
[1 mark]( ii ) Give two reasons for your answer in (a)( i ) .
- has cell wall
- has a single / large vacuole
- has chloroplasts
Any two correct answers
[2 marks]Name the organelles P, Q and R .
P : Vacuole
Q : Mitochondrion
R : Nucleus
[3 marks]
What is the significance of P for the cell ?.
To control the osmotic balance // regulate turgor pressure in the cell.[1 mark]
(d) Explain the function of Q.
- Site for generating energy ( needed )
- for cells activities / cell division / cellular respiration
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P
Q
R
S
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[2 marks]
(e) What would happen to the cell if organelle S is absent?
- Cannot maintain the shape of plant cells
- Cannot protect the plant cell from rupturing ( due to the movement of excess waterinto cells )//
- Cannot provide mechanical support for the plant
cells
[3 marks]
TOTAL: 12 MARKS
2.
a)
Figure 2.1 shows a fluid mosaic model of plasma membrane.
Diagram 2.1
Label structures P, Q, R and S in diagram 1.1 using the following:
P: carrier protein
Q: pore
R: cholestrol
S: phospolipid
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Pore
Cholesterol
Carrier protein
PhospholipidPP
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[4 marks]
FIGURE 2.2
An experiment has been carried out on plant cell, S which is soaked in solution T. The resultis shown in Figure 2.2.
(b) State the type of solution T.
hypertonic[1 mark]
(c) (i) Name the phenomenon that occurs on plant cell S. .
plasmolysis
[1 mark](ii) Explain how does the phenomenon in (c) (i) occurs.
P1: there is a different concentration between inside and outside cellP2: water molecules in the cell diffuse out by osmosis
P3: the cytoplasm contract and the plasma membrane moves away from the cell wall
Any 2
[2 marks]
(i) Draw the shape of the plant cell after it is soaked in distilled water in the space providedbelow.
[3 marks]
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(d) (ii) State the process that takes place in the cell.
deplasmolysis
[1 mark]
TOTAL: 12 MARKS
3. Diagram 3 shows structures of protein. The protein structures can be classified into four levels J
K, L and M based on organization of their structures.
Diagram 3
(a) ( i) Label amino acid and peptide bond in J
X : Amino acid
Y : Peptide bond[2 marks
(ii) Name the protein structures of L and M L: Secondary structure
M: Quaternary structure
[2 marks
(b) (i) Name the organelle in the cell where the protein is synthesized?
Ribosome
[1 mark](iii) By using the letters J,K L and M, which protein structure is represented
Enzyme : K
Haemoglobin : M
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J K L M
X
YYY
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[ 2 marks
(c) Explain why food is kept in refrigerator?
F : Temperature in refrigerator is low
P1 : Enzyme (in bacteria) is inactive P2 : food cannot be decomposed
[3 marks
d) A branded washing machine is provided with temperature regulator. A housewife uses
the detergent containing enzyme at 40oC to wash the clothes. Using the information
given, explain why?
F: 40o
C is an optimum temperatureP1: enzyme activity is maximum
P2: the cleaning is more effective.
[ 2 marks
TOTAL: 12 MARKS
4. Figure 4.1 shows phases U and V of the cell cycle of a cheek cell.
Phase U and phase V are two main phases in the cell cycle.
Phase U consists of three sub-phases, X, Y and Z.
Phase V involves two processes, P and Q
Figure 4.1
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U
V
X
P
Q
Y
Z
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(a) Name the phase labelled U and V.
U : Interphase
V : Mitotic phase // M phase
[ 2 marks ]
(b) (i) Draw and label the cell during U phase.
[ 3 marks
(ii) What happen in the cell during U phase.
Protein synthesis// Number of organelles increases // energy storage
Replication of DNA //
Final preparation of cell for cell division to take place //synthesis of cellular materials//mitotic spindle begins to form// Energy storage increases
Any ONE above
[ 1 mark
(i) Name the processes P and Q in phase V :
P : Mitosis Q : Cytokinesis[ 2 marks
(ii) Figure 4.2 shows a cell which is found in human cheek.
Figure 4.2
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chromatin
Nuclearmembrane
plasmamembrane
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State two characteristics of daughter cells when the cell in Figure 4.2 undergoes P process ?
Number of chromosomes:
The daughter cell has similar number of chromosomes to the parent cell
Genetic content:
The daughter cell has similar genetic content to the parent cell .[ 2 marks
Figure 4.3 shows the formation of cancer cell in the mouth.
Normal cheek cell Cancer cells
Figure 4.3
Based on Figure 4.3 , explain how cancer cell develops ?
F nature of carsinogenic chemicals
Carsinogenic Chemical causes uncontrolled mitosis
E1 formation of cancer cells
Carsinogenic chemical can induce the cheek cell to divide and form cancer cells
E2 its effect to the surrounding cells
Cancer cells interrupt / interfere the function of normal cells
[ 2 marks
TOTAL: 12 MARKS
5. (a) Diagram 5 shows the use and production of energy in human body.
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Carsinogenicchemical
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Diagram 5
(i) Name the processes labeled X and Y.
X : Cellular respiration
Y : Cell activity // muscles contraction[2 marks
(ii) Name the organelle in the cell that is able to synthesis ATP.
.
Mitochondria
[1 mark
(b) State two differences between aerobic respiration and anaerobic respiration when one molecule
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X
A D P ~ P
Y
ATP + P
Glucose + oxygen Carbon dioxide + heat
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of glucose is used.
Aerobic respiration Anaerobic respiration
- oxygen is present
- carbon dioxide, water and
energy are produced
- 38 molecules of ATP are
generate
- large amount of energy is
released (2898 kJ)
- in mitochondria
- oxygen is absence
- lactic acid and energy (in muscle cells) or
ethanol, carbon dioxide, and energy (inyeast)
- 2 molecules of ATP are generate
- small amount of energy is released (210
kJ during fermentation) and (150kJ in
muscle cells)
- in cytoplasm
[4 marks
(c) (i) After a vigorous exercise, the oxygen content in human body decrease while the carbon
dioxide content increase.
State the receptor that detect the change of oxygen and carbon dioxide content.
Central chemoreceptors // Peripheral Chemoreceptor // Aortic bodies and Carotid bodies
[1 mark
(ii) Describe how the change of oxygen and carbon dioxide content are regulated by the body.
- The higher level of carbon dioxide in the blood cause the drop of pH value- The drop in pH is detected by Central Chemoreceptor in Medulla Oblongata- Then the Central Chemoreceptor send the nerve impulses to the diaphragm and
intercostal muscle, causing (respiratory muscles) to contract and relax
- Finally, increases the breathing and ventilation rate- Concentration of carbon dioxide and pH value of the blood return to normal levels
[3 marks
(d) (i) Based on your knowledge in Biology, state another situation where our body will give thesame response as in (c)(ii)
Climbing a mountain
[1 mark
TOTAL: 12 MARKS
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SECTION BANSWER ANY TWO QUESTIONS
40 marks
6 (a)
Based on the above statement, explain the necessity for food processing.
[10 marks]
(b)
Type of food Food preservation method
Milk Pasteurisation
Fruits Canning
Meat and fish Refrigeration
TABLE 1
Table 1 shows several methods of food preservation that being used in food processing.Describe how the method can preserve food for along period of time.
[10 marks]
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Food preservation involves methods ofpreparing food to extend the lifespan
and to avoid wastage of food.
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ITEM
NO
SCORING CRITERIA MARKS REMARK
6 (a)
(b)
Able to explain the necessity of food processing
Sample answer
F1 prevent food spoilageE1 (food spoilage) causes by the action of microorganism
E2 decomposing bacteria/fungi on carbohydrate/protein
E3 produced carbon dioxide, water, ammonia hydrogenE4 make food become toxic
F2 Oxidation of food when cut/expose to airE1 oxygen react with enzymes/chemicals released by cell
F3 Increase it commercial valueE1 food additives is added in preserving the freshness of
foodE2 Improve the taste/appearance/texture
F4 Intention of diversifying the uses of food
E1 increased the variety of products
Able to describe how each method can preserve food for along period of
time
Sample answerPasteurisation:
- milk is treated to 63oC for 30 minutes//72oC for 15 seconds
- followed by rapid cooling to below 10o
C- destroy bacterias but not the spores- retains the natural flavour of milk//nutrients//vitamin B
- must refrigerated to avoid the growth of sperms
Canning:- use heat sterilisation
- kill microorganisms and spores
- steamed at high temperature and pressure to drive out air- sealed while the food is being cooled
- vacuum in the can prevent growth of microorganism
Refrigeration:- stored at temperature below 0oC
- prevent the growth of microorganisms/the germination of spores
TOTAL
11
1
11
11
1
11
1
1
1
111
1
1
1
1
1
1
1
1
12
10
Max4
Max4
2
10
13
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7 (a) Briefly describe the respiratory system found in organism Q and R in diagram 7.1 and how theyobtain oxygen for respiration.
[10 marks]
(b) Diagram 8.2 shows gaseous exchange across the surface of the alveolus and blood capillaries in
the lungs. Based on diagram 7.2, explain how respiratory gaseous are transported in humanbody.
[10 marks]
Hjk
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ITEM
NO
SCORING CRITERIA MARKS REMARK
7 (a) Able to explain the respiratory system found in grasshopper and fish.
Sample answer
GrasshopperP1- the respiratory system of insects is known as tracheal system
P2- air enters the trachea through spiracles
P3- opening & closing of spiracle is control by valvesP4- the trachea is reinforced with rings of chitin to prevent collapsing
P5- trachea branch into tracheoles which provide a large surface area for
diffusion of gasP6- oxygen then dissolves into the fluid at the end of tracheoles
P7- oxygen diffuse directly from tracheloes into th cells, while carbon
dioxide diffuse out from cells into the tracheloesP8- contain air sacs which speed up the movement of gases to and from
insectss tssue
Any fve
Fish
P9- Respiratory structure in fish is gillsP10- a fish has four pairs of gills covered by an operculum on each side
P11- each gill has two rows of gill filament to increase the surface area
for gaseous exchangeP12- the filament have thin membranes with a rich supply of blood
capillaries to facilitate exchange of respiratory gases
P13- the efficiency gaseous exchange is aided by countercurrentexchange mechanismP14- during inspiration, the mouth opens, buccal cavity expands both of
the operculums are closed. Water enter the mouth
P15- the mouth then closes. The floor of the buccal cavity is raised.Water
Any five
1
1
1
1
1
1
1
1
1
1
1
1
1
1
1
8
5
7
5
15
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ITEM
NO
SCORING CRITERIA MARKS REMARK
7 (b) P1- gaseous exchange occurs at alveoli
P2- movement of gases occur through simple diffusion
P3- oxygen from alveoli diffuse to the blood capillaries// carbondioxide diffuse from blood capillaries to the alveoli
P4- diffusion of oxygen from alveoli to blood capillaries andcarbon dioxide from blood capillaries to alveoli caused bydifference in partial pressure of both gases
P5- partial pressure of oxygen in alveoli is higher than partialpressure of oxygen in blood capillaries// while partial pressure ofcarbon dioxide in blood capillaries is higher than partial pressureof carbon dioxide in alveolus
P6- oxygen diffuse into red blood cell
P7- oxygen combined with haemoglobin to form oxyhaemoglobin
P8- oxygen in the form of oxyhaemoglobin is pumped by heart toall body cells
P9-oxygen diffused from blood capillaries to the cell// carbondioxide diffuse from cells to the blood capillaries
P10- carbon doxide is sent to the lungs as bicarbonate ions/carbonic acid/ carbaminohaemoglobin
P11- deoxygenated blood is sent back to the heart by the venacava
P12- Deoxygenated blood is sent to the lung by pulmonary arteryto excrete out the carbon dioxide
Any 10.
1
1
1
1
1
1
1
1
1
1
1
1 12
10
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8 (a) Diagram 8 shows the process of colonization and succession in a barren land.
Based on diagram 8, explain what is meant by colonization and succession and how the processleads to a complex community
[8 marks]
(b) State the problems faced by the mangrove plants grown near the estuaries of rivers.Explain how these plants adapt to survive.
[8 marks](c) Give reasons why the mangrove swamps is ecologically valuable.
[4 marks]
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ITEM
NO
SCORING CRITERIA MARKS REMARK
Able to explain what is meant by colonisation and
succession and how the process lead to a complexcommunity
ColonizationIs a process whereby a species colonise a newly formed
area.
Succession
A process when a species of organisms/ changes the
environment/ habitat which results in the species/ organism
being replaced/ succeeded by other species/ community
P1- pioneer species have special adaptation that enable
them to survive on dry and nutrient poor soil
P2- usually hardy plants which have dense root system to
bind the sand particles and hold water as well as humus.
P3- Activities of the pioneer species cause a change in the
habitat making it more suitable for other species
P4- they have short life cycles thus when they die, theyremain add to the humus content of the soil
P5- pioneer species modifies the environment creating a
less favorable condition to themselves
P6- instead, they establish condition that are more
conducive to other species which are called successor
speciesP7- successor species i.e. herbaceous plant grow bigger
than pioneer species i.e. grass, reducing the amount of
sunlight that reaches them and gradually replacing them
P8- most of the successor species have small wind-
dispersable seeds which are able to spread and grow rapidy
P9- they (successor species/ herbaceous plants) also
change the structure and quality of the soil, making it more
conducive for a larger plants like shrubs to grow
1
1
1
1
1
1
1
1
1
1
1
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P10- new plants/ shrubs then become the new dominant
species. They can grow faster and they out-compete the
pioneer/ herbaceous plants which grow at a slower rate
P11- the dominant species in turn modify the environment,allowing larger trees to grow
P12- the larger trees out-compete the shrubs which are
replaced by forest-floor species which require lower lightintensity
P13- Finally, a climax/ complex community is formed
Any 8
1
1
1
1 138
(b) Problems
P1- swamp is muddy, too soft to support the plants
P2- waterlogged soil with little oxygen for plant roots toRespire
P3-water in the soil has high concentration of salt
P4- seeds of plant fall on the soft mud and sink easilyinto the mud/ will not germinate/ die due to the lack ofoxygen in waterlogged mud
Adaptation
P5- mangrove plants are able to support themselves insoft ground by having a highly branched and widespreadroot system. e.g prop roots
P6- have breathing roots called pneumatophores
P7- roots of mangrove trees have higher salt contentthan seawater
P8- excess salt which enters the roots are eliminated via
hydathodes at lower epidermis of leaves
P9- seeds of mangrove trees are viviparous
P10- the germinated seeds having long radical that stillattached at the parent trees
P11- long radical help to support the shoot above muddyground and do not drown or get washed to sea by waves.
1
1
1
1
1
1
1
1
1
1
1
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Any 8118
(c) Able to state the reasons why the mangrove swmps isecologically valuable
P1- provide sheltered nurseries for young fishes, crabsand other sealife
P2- spawning grounds for ishes and crabs
P3- Habitat for variety of animals (eg monkey, bird) livingin the mangrove swamp
P4- help to prevent coastal erosions by sea waves
1
1
1
1 4
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9 (a) (a) Diagram 9 shows the Nitrogen Cycle..
Diagram 9.1
Based on Diagram 9.1, discuss the role of microorganisms in the Nitrogen Cycle. Berdasarkan Rajah 9.1 , bincangkan peranan mikroorganisma di dalam Kitar Nitrogen
[10 marks]
(b) Diagram 9.2 shows the ozone layer in atmosphere that protects earth from ultraviolet
4551/2 21Root nodules
of legumes
Nodul akarkekacang
Urine
Organic materials
Root nodulesof legumes
Ammonium compound
Nitrite
Nitrate
Faeces
Nitrogen in theatmosphere
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rays from the sun.
DIAGRAM 9.2
Describe how the ozone layer becomes thinner. Discuss its effects on humans and the
environment and suggest the ways to solve these problems.
[10 marks]
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Solar radiationSinaran suria
StratosphereStratosfera
Ozone layerLapisan ozon
Harmfulultraviolet radiationSinaran ultra ungu
berbahaya
TroposphereTrofosfera
EarthBumi
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Itemnumber
Criteria Marks Notes
9 (a) F1 - Rhizobium bacteria inside the root nodulesof legumes and Nostoc sp. found freely inthe soil fixed the nitrogen in air
F2 - decaying bacteria / fungi decompose
plant /animal / dead organism / wasteproduct
P1 - to form ammonium compound
F3 - Nitrosomonas sp./ nitrifying bacteriaconverted ammonium compound to nitrite
F4 - Nitrobacter sp /nitrifying bacteria convertnitrite to nitrate
P2 - nitrate is absorbed by plant to form plant
protein
P3 - (plant protein) eaten by an animal to formanimal protein
F4 - Denitrifying bacteria reduce the nitratecontent in the soil
P4 - by converting the nitrate into nitric oxideand nitrogen gas
P5 - nitrogen gas goes back into the
atmospheric to complete the nitrogen cycle
1
1
1
1
1
1
1
1
1
1 10
marks
9 (b)Able to explain how the ozone layer becomes
thinner / ozone depletion occur
Thinning of the ozone layer is due to the
widespread use of CFC
It is used in aerosol, industrial solvents,
electronics and Freon in air conditioners
Ultraviolet radiation strikes a CFC molecule cause
the chlorine atom to break away
Then the chlorine atom collides with an ozone
molecule and combines with an oxygen atom to
form chlorine monoxide and oxygen
Then the free atom of oxygen collides with the
chlorine monoxide, the two oxygen atoms form a
molecule of oxygen
1
1
1
1
1
1Max 5
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Itemnumber
Criteria Marks Notes
The chlorine atom is released and free to destroy
more ozone molecules
The chlorine produced re-enters the cycle
When the ozone layer becomes thinner, moreultraviolet radiation reaches the Earth
The effect of excessive ultraviolet radiation on
human
reduction of the bodys immune system
skin cancer
cataract of the eye
Effect on plants
reduction of the rate of growth therefore reducing
crop yields
Effect on aquatic organism
death of plankton, reduce food supply to aquatic
organism, fishermans catch is reduced.
Steps to overcome this problem
Reduce or stop using CFC or chlorine-based
products
Replace CFC with HCFC
Use wrapping papers instead of polystyrene
boxes
Patch up the holes in the ozone layer by firing
frozen ozone balls into the atmosphere
1
1
1
1
1
1
1
1
1
1
1
Max 3
Max 2
TOTAL10marks
Disediakan oleh, Disemak dan Disahkan oleh,
.. .(NUR HAFEZA BT ABU HASSAN) (Salahiah Bt Daman)Guru Biologi Tingkatan 4. Guru Kanan Bidang
Sains & Matematik.