answer spss
TRANSCRIPT
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1. A. The diference between mean, mode and median
Mean – nilai purata yang digunakan untuk mewakili satuset nilai./ the "a erage" you!re used to, where you add up
all the numbers and then di ide by the number onumbers
Median – nilai tengah sesuatu taburan skor yang disusunmengikut urutan menaik atau menurun / the "middle"
alue in the list o numbers
Mode # the alue that occurs most o ten. $ no number is
repeated, then there is no mode or the list / digunakanuntuk menyatakan kategori yang mempunyai kkekerapanyang paling tinggi.
b. %hat happen to null hypothesis when p&'.''()*e+act
c. %hat can conclude i the outcome o an analysis is asigni cant negati e correlation between - aribles
That one o the ariable increase and the other tendsto decreace.
o relationship between - ariables.
d. ika signi cant di atas '.'( maka tidak0engan erti kata lain tidak terdapat perbe aan yangsigni kan antara data yang diu+i
e. %hat happen to the altenat e hypothesis whn type 1error occur)
ika berlakunya ralat +enis $ berlaku kita menolak 2oapabila dlm kedaan sebenar , ia benar.
-. A. 3 male indi idual a 42 # 5'.63
b. 3 emale 42 # -6. 7
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h. $s there any signi cant relationshio between i and do this study
B. 8rocedur correlationAnaly – correlate – bi ariate4aribles – Cs1-1, Cds1-7 – optionMean and std de iation – ok
b. copy the correlation
c. what is correlation coeDcient '.15B
d. based on the correlation rule o thumb, what is thestrength o this relationship
positi e relationship
e. conclusioncorrelation is signi cant at the '.'1 le el =1#tailed>
(. A. Analy e – regration – linear – input depent /independent – okb.
c. * s9uare '.B1@
d. Ad+usted * s9uare alue '.55@
e. 67(5.'1;
. #7-.'(5
i. *egression coeDcient 1;B.(B1
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+. *elationship no
k. *eg coeD E or CF 76 1.7(7l. $s the relationship is sig o
m. ebyk B1.@3 drp ketiga tiga actor mempengaruhicrime rate =1'' – B1.@ G (6.5> lagi (6.53 dipengaruhioleh actor lain
n.