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    ASSIGMENT 1 ( IP ADDRESS)

    NAMA : AHMAD IKHTIARUDDIN BIN ABDULLAHKOS / KOD : KFC 2144 / COMPUTER FUNDAMENTALSEM / KELAS : 2A

    Create a Subnetting Worksheet to show and record all work foreach problem :

    PROBLEM 1

    Host IP Address 172.30.1.33Network Mask 2 .2 .0.0/1!Network Address "Network roadcast Address "

    !otal Number "f Host its "Number "f Host "

    #angkah $: Con%ert Host IP Address dan Network Mask men&adi bilanganbiner '

    $()'*+'$'** , $+$+$$++ +++$$$$+ +++++++$ ++$++++$)--')--'+'+ , $$$$$$$$ $$$$$$$$ ++++++++ ++++++++

    #angkah ) : Menentukan Network Address'

    • .unakan operator AN/ pada IP address dan subnet mask'C#$#$#%: $ AN/ $ hasiln0a adalah $1 + AN/ apapun 2+3$4 hasiln0a

    tetap + '

    $()'*+'$'** , $+$+$$++ +++$$$$+ +++++++$ ++$++++$)--')--'+'+ , $$$$$$$$ $$$$$$$$ ++++++++ ++++++++

    N5!W"67 A//65SS , $+$+$$++ +++$$$$+ ++++++++ ++++++++ $() *+ + +

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    #angkah * : Menentukan roadcast Address'roadcast address dapat ditemukan dengan cara mengubah semua host

    bits + pada network address men&adi $'

    $()'*+'+'+ , $+$+$$++ +++$$$$+ ++++++++ ++++++++)--')--'+'+ , $$$$$$$$ $$$$$$$$ ++++++++ ++++++++ 899999999 network 99999998 8999999999 host 99999999998

    , $+$+$$++ +++$$$$+ $$$$$$$$ $$$$$$$$

    $() *+ )-- )--

    #angkah : Menentukan &umlah Host bits dan total Host'

    /engan menghitung host bits diatas3 kita dapat menentukan &umlah darihost 0ang dapat digunakan di dalam &aringan tersebut' Host bits , $ !otal host , ) $; , ;-'-*;;-'-*; < ) , ;-'-* 2) alamat terpakai untuk network address2$()')-'+'+4 dan $ untuk broadcast address 2$()')-')--')--4

    CA6A MAN=A# !=7A6 75PA/A INA6>

    $()'*+'$'**

    $()) $() $) ?; +) * $) )$ +

    ) $+ $) - $

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    ) ) +) $ +

    *+) *+ +) $- $) ( $) * $) $ $

    +++

    $) $ +

    ++++++

    **) ** +) $; +) ? +) +) ) +) $ +

    +

    !he @inal 6esult :9

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    Host IP Address 172.30.1.33

    Network Mask 2 .2 .0.0/1!

    Network Address 172.30.0.0Network roadcast Address 172.30.2 .2

    !otal Number "f Host its 1!

    Number "f Host ! 3! &'# * +,'$

    PROBLEM 2

    Host IP Address 172.30.1.33Network Mask 2 .2 .2 .0/24Network Address "Network roadcast Address "

    !otal Number "f Host its "Number "f Host "

    #angkah $: Con%ert Host IP Address dan Network Mask men&adi bilanganbiner'

    $()'*+'$'** , $+$+$$++ +++$$$$+ +++++++$ ++$++++$

    )--')--')--'+ , $$$$$$$$ $$$$$$$$ $$$$$$$$ ++++++++

    #angkah ) : Menentukan Network Address'

    .unakan operator AN/ pada IP address dan subnet mask'C#$#$#%: $ AN/ $ hasiln0a adalah $1 + AN/ apapun 2+3$4 hasiln0a tetap+'

    $()'*+'$'** , $+$+$$++ +++$$$$+ +++++++$ ++$++++$)--')--')--'+ , $$$$$$$$ $$$$$$$$ $$$$$$$$ ++++++++Network address , $+$+$$++ +++$$$$+ +++++++$ ++++++++ $() *+ $ +

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    #angkah * : Menentukan roadcast Address'roadcast address dapat ditemukan dengan cara mengubah semua host

    bits + pada network address men&adi $

    $()'*+'$'+ , $+$+$$++ +++$$$$+ +++++++$ ++++++++)--')--')--'+ , $$$$$$$$ $$$$$$$$ $$$$$$$$ ++++++++

    , $+$+$$++ +++$$$$+ +++++++$ $$$$$$$$ 89999999999999 network 9999999999999998 99 host 9998

    $() *+ $ )--

    #angkah : Menentukan &umlah Host bits dan total Host'/engan menghitung host bits diatas3 kita dapat menentukan &umlah darihost 0ang dapat digunakan di dalam &aringan tersebut' Host bits , ? !otal host , ) ? , )-;)-; < ) , )- 2) alamat terpakai untuk network address 2$()'*+'$'+4 dan$ untuk broadcast address 2$()'*+'$')--4

    CA6A MAN=A# !=7A6 75PA/A INA6>

    $()'*+'$'**

    $()) $() $) ?; +) * $

    ) )$ +) $+ $

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    ) - $) ) +) $ +

    *+) *+ +) $- $) ( $) * $) $ $

    +++

    $

    ) $ +

    ++

    +

    +

    +

    +

    **) ** +) $; +) ? +) +) ) +

    ) $ +

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    +

    !he @inal 6esult :9

    Host IP Address 172.30.1.33

    Network Mask 2 .2 .2 .0/24

    Network Address 172.30.1.0Network roadcast Address 172.30.1.2

    !otal Number "f Host its -

    Number "f Host 2 ! &'# * +,'$

    PROBLEM 3

    Host IP Address 1 2.1!-.10.234Network Mask 2 .2 .2 .0/24Network Address "Network roadcast Address "

    !otal Number "f Host its "Number "f Host "

    #angkah $: Con%ert Host IP Address dan Network Mask men&adi bilangan

    biner'

    $ )'$;?'$+')* , $$++++++ $+$+$+++ ++++$+$+ $$$+$+$+

    )--')--')--'+ , $$$$$$$$ $$$$$$$$ $$$$$$$$ ++++++++

    #angkah ) : Menentukan Network Address'

    .unakan operator AN/ pada IP address dan subnet mask'

    C#$#$#%: $ AN/ $ hasiln0a adalah $1 + AN/ apapun 2+3$4 hasiln0a tetap +

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    $ )'$;?'$+')* , $$++++++ $+$+$+++ ++++$+$+ $$$+$+$+)--')--')--'+ , $$$$$$$$ $$$$$$$$ $$$$$$$$ ++++++++Network address , $$++++++ $+$+$+++ ++++$+$+ ++++++++ $ ) $;? $+ +

    #angkah * : Menentukan roadcast Address'roadcast address dapat ditemukan dengan cara mengubah semua host

    bits + pada network address men&adi $'

    $ )'$;?'$+'+ , $$++++++ $+$+$+++ ++++$+$+ ++++++++)--')--')--'+ , $$$$$$$$ $$$$$$$$ $$$$$$$$ ++++++++ 899999999999999 network 9999999999999998 899 host9998

    , $$++++++ $+$+$+++ ++++$+$+ $$$$$$$$ $ ) $;? $+ )--

    #angkah : Menentukan &umlah Host bits dan total Host'/engan menghitung host bits diatas3 kita dapat menentukan &umlah darihost 0ang dapat digunakan di dalam &aringan tersebut'Host bits , ?

    !otal host , ) ? , )-;

    )-; < ) , )- 2) alamat terpakai untuk network address 2$ )'$;?'$+'+4dan $ untuk broadcast address 2$ )'$;?'$+')--4CA6A MAN=A# !=7A6 75PA/A INA6>$ )'$;?'$+')*

    $ )) $ ) +) ; +) ? +

    ) ) +) $) +) ; +) * $) $ $

    $;?) $;? +) ? +

    ) ) +) )$ $

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    ) $+ +) - $) ) +) $ $

    $+) $+ +) - $) ) +) $ $) +) +) +) +

    )*) )* +) $$( $) -? +) ) $) $ +) ( $) * $) $ $

    !he @inal 6esult :9

    Host IP Address 1 2.1!-.10.234

    Network Mask 2 .2 .2 .0/24

    Network Address 1 2.1!-.10.0

    Network roadcast Address 1 2.1!-.10.2

    !otal Number "f Host its -

    Number "f Host 2 ! &'# * +,'$

    PROBLEM 4

    Host IP Address 172.17. .71Network Mask 2 .2 .2 .0/24

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    Network Address "Network roadcast Address "

    !otal Number "f Host its "Number "f Host "

    #angkah $: Con%ert Host IP Address dan Network Mask men&adi bilanganbiner'

    $()'$(' '($ , $+$+$$++ +++$+++$ +$$+++$$ +$+++$$$

    )--')--'+'+ , $$$$$$$$ $$$$$$$$ ++++++++ ++++++++

    #angkah ) : Menentukan Network Address'

    .unakan operator AN/ pada IP address dan subnet mask'C#$#$#%: $ AN/ $ hasiln0a adalah $1 + AN/ apapun 2+3$4 hasiln0a tetap + .

    $()'$(' '($ , $+$+$$++ +++$+++$ +$$+++$$ +$+++$$$ )--')--'+'+ , $$$$$$$$ $$$$$$$$ ++++++++ ++++++++Network address , $+$+$$++ +++$+++$ ++++++++ ++++++++ $() $( + +

    #angkah * : Menentukan roadcast Address'roadcast address dapat ditemukan dengan cara mengubah semua host

    bits + pada network address men&adi $'

    172.17.0.0 = 10101100 00010001 00000000 00000000

    255.255.0.0 = 11111111 11111111 00000000 00000000 |------- network --------| |----------- host --------|

    = 10101100 00010001 11111111 11111111

    172 17 255 255

    #angkah : Menentukan &umlah Host bits dan total Host'

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    /engan menghitung host bits diatas3 kita dapat menentukan &umlah darihost 0ang dapat digunakan di dalam &aringan tersebut' Host bits = 16

    Total host = 2 16 = 65.536

    65.536 – 2 = 65.534 (2 alamat ter akai !nt!k network a""ress (172.17.0.0# "an 1 !nt!k

    broadcast address 2$()'$(')--')--4CA6A MAN=A# M5NCA6I INA6>$()'$(' '($

    $()) $() +) ?; +

    ) * $) )$ $) $+ +) - $) ) +) $ $

    $(

    ) $( $) ? +) +) ) +) $ $) +) +) +

    ) $) $) ) +) $) +) ; +) * $

    ) $ $

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    ) +

    ($) ($ $) *- $) $( $) ? +) +) ) +) $ $) +

    !he @inal 6esult :9

    Host IP Address 172.17. .71

    Network Mask 2 .2 .0.0

    Network Address 172.17.0.0Network roadcastAddress

    172.17.2 .2

    Number of Host its 1!

    !otal Number of Hosts ! 3! $,$# +,'$' #$#& ! 34 &'# *+,'$'

    PROBLEM

    #angkah $: Con%ert Host IP Address dan Network Mask men&adi bilangan

    biner'

    Host IP Address 192.168.3.219

    Network Mask 255.255.0.0

    $etwork %""ress & $etwork 'roa" ast %""ress & $!mber o) Host 'its &Total $!mber o) Host &

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    $ )'$;?'*')$ , $$++++++ $+$+$+++ ++++++$$ $$+$$+$$

    )--')--'+'+ , $$$$$$$$ $$$$$$$$ ++++++++ ++++++++

    #angkah ) : Menentukan Network Address'

    .unakan operator AN/ pada IP address dan subnet mask'C#$#$#%: $ AN/ $ hasiln0a adalah $1 + AN/ apapun 2+3$4 hasiln0a tetap+ .

    $ )'$;?'*')$, $$++++++ $+$+$+++ ++++++$$ $$+$$+$$

    )--')--'+'+ , $$$$$$$$ $$$$$$$$ ++++++++ +++++++Network roadcast , $ ) $;? + +

    #angkah * : Menentukan roadcast Address'roadcast address dapat ditemukan dengan cara mengubah semua host

    bits + pada network address men&adi $'

    $ )'$;?'+'+ , $$++++++ $+$+$+++ ++++++++ ++++++++)--')--'+'+ , $$$$$$$$ $$$$$$$$ ++++++++ ++++++++

    899999999 network 9999998 89999999999 host 9999999998

    , $$++++++ $+$+$+++ $$$$$$$$ $$$$$$$$ $ ) $;? )-- )--

    #angkah : Menentukan &umlah Host bits dan total Host'

    /engan menghitung host bits diatas3 kita dapat menentukan &umlah darihost 0ang dapat digunakan di dalam &aringan tersebut'

    Host bits = 16

    Total host = 2 16 = 65.536

    65.536 – 2 = 65.534 (2 alamat ter akai !nt!k network a""ress (1*2.16+.0.0# "an 1 !nt!k

    broa" ast a""ress (1*2.16+.255.255#

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    CA6A MAN=A# M5NCA6I INA6>$ )'$;?'*')$

    $ )) $ ) +) ; +) ? +) ) +) $) +) ; +) * $

    ) $ $

    $;?) $;? +) ? +) ) +) )$ $) $+ +

    ) - $) ) +) $ $

    *) * $) $ $) +

    ) +) +

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    ) +) +) +

    )$) )$ $) $+ $) - +) )( $) $* $) ; +) * $) $ $

    !he @inal 6esult :9

    Host IP Address 1 2.1!-.3.21Network Mask 2 .2 .0.0

    Network Address 1 2.1!-.0.0

    Network roadcastAddress

    1 2.1!-.2 .2

    Number of Host its 1!

    !otal Number of Hosts ! 3! $,$# +,'$' #$#& ! 34 &'# *+,'$'

    PROBLEM !

    Host , %""ress 192.168.3.219

    $etwork ask 255.255.255.224

    $etwork %""ress & $etwork 'roa" ast %""ress & $!mber o) Host 'its &Total $!mber o) Host &

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    #angkah $: Con%ert Host IP Address dan Network Mask men&adi bilanganbiner'

    $ )'$;?'*')$ , $$++++++ $+$+$+++ ++++++$$ $$+$$+$$

    )--')--')--')) , $$$$$$$$ $$$$$$$$ $$$$$$$$ $$$+++++

    #angkah ) : Menentukan Network Address'.unakan operator AN/ pada IP address dan subnet mask .C#$#$#%: $ AN/ $ hasiln0a adalah $1 + AN/ apapun 2+3$4 hasiln0a tetap+'

    $ )'$;?'*')$ , $$++++++ $+$+$+++ ++++++$$ $$+$$+$$)--')--')--')) , $$$$$$$$ $$$$$$$$ $$$$$$$$ $$$+++++Network address , $$++++++ $+$+$+++ ++++++$$ $$++++++

    1*2 16+ 3 1*2

    #angkah * : Menentukan roadcast Address'roadcast address dapat ditemukan dengan cara mengubah semua host

    bits + pada network address men&adi $

    $ )'$;?'*'$ ) , $$++++++ $+$+$+++ ++++++$$ $$+ +++++)--')--')--')) , $$$$$$$$ $$$$$$$$ $$$$$$$$ $$$ +++++

    899999999999999 network 999999999999999999999889host98 , $$++++++ $+$+$+++ ++++++$$ $$+ $$$$$

    $ ) $;? * ))*

    /an kah 4 enent!kan !mlah Host bits "an total Host.

    en an men hit!n host bits "iatas kita "a at menent!kan !mlah "ari host an "a at

    "i !nakan "i "alam arin an terseb!t.

    Host bits = 5

    Total host = 2 5 = 32

    32 – 2 = 30 (2 alamat ter akai !nt!k network a""ress (1*2.16+.3.1*2# "an 1 !nt!k broa" asta""ress (1*2.16+.3.223#

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    ) +) +) +) +) +) +

    )$) )$ $) $+ $) - +) )( $) $* $) ; +) * $) $ $

    !he @inal 6esult :9

    Host IP Address 1 2.1!-.3.21

    Network Mask 2 .2 .2 .224

    Network Address 1 2.1!-.3.1 2

    Network roadcast Address 1 2.1!-.3.223

    Number of Host its !otal Number of Hosts 32 $,$# +,'$' #$#& 30 &'# *

    +,'$

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