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Assignment IP Address

Problem 1

IP Address - 172.30.1.33

Network Mask - 255.255.0.0

Network Address - ?

Change IP Address and Network Mask into Binary Number

IP Address, 172 = 10101100, 30 = 00011110, 1 = 00000001, 33 = 00100001

By using Short Division by 2 with remainder you can convert a decimal number into binary number,

take the binary number from bottom to up.

172 / 2 = 86 (0) 30 / 2 = 15 (0) 1 / 2 = 0.5 (1) 33 / 2 = 16.5 (1)

86 / 2 = 43 (0) 15 / 2 = 7.5 (1) 16 / 2 = 8 (0)

43 / 2 = 21.5 (1) 7 / 2 = 3.5 (1) 8 / 2 = 4 (0)

21 / 2 = 10.5 (1) 3 / 2 = 1.5 (1) 4 / 2 = 2 (0)

10 / 2 = 5 (0) 1 / 2 = 0.5 (1) 2 / 2 = 0 (0)

5 / 2 = 2.5 (1)

2 / 2 = 1 (0)

1 / 2 = 0.5 (1)

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Network Mask, 255 = 11111111, 255 = 11111111, 0 = 00000000, 0 = 00000000

255 / 2 = 127.5 (1)

127 / 2 = 63.5 (1)

63 / 2 = 31.5 (1)

31 / 2 = 15.5 (1)

15 / 2 = 7.5 (1)

7 / 2 = 3.5 (1)

3 / 2 = 1.5 (1)

1 / 2 = 0.5 (1)

Inverse Number of Network Mask -> 00000000.00000000.11111111.11111111

Inverse Number is when you change 0 to 1 and 1 to 0.

Network Mask 11111111 11111111 00000000 00000000

Inverse

Network Mask

00000000 00000000 11111111 11111111

And then do Logical AND Gate between 2 binary number, whereas;

1 AND 1 = 1

1 AND 0 = 0

0 AND 0 = 0

IP Address

X

10101100 00011110 00000001 00100001

Network Mask 11111111 11111111 00000000 00000000

Network

Address

10101100 00011110 00000000 00000000

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Convert the binary number into decimal to get the Network Address

10101100 = 172, 00011110 = 30, 00000000 = 0, 0000000 = 0

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 0 1 0 1 1 0 0

128+ 0+ 32+ 0+ 8+ 4+ 0+ 0

172

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

0 0 0 1 1 1 1 0

0+ 0+ 0+ 16+ 8+ 4+ 2+ 0

30

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Network Broadcast Address - ?

Use the IP Address binary number and the Inverse Number of Network Mask

And then do Logical OR Gate between 2 binary number whereas;

1 OR 1 = 1

0 OR 1 = 1

0 OR 0 = 0

IP Address

+

10101100 00011110 00000001 00100001

Inverse

Network

Mask

00000000 00000000 11111111 11111111

Network

Broadcast

Address

10101100 00011110 11111111 11111111

Convert the binary number into decimal to get the Network Broadcast Address

10101100 = 172 , 00011110 = 30, 11111111 = 255, 11111111 = 255

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 0 1 0 1 1 0 0

128+ 0+ 32+ 0+ 8+ 4+ 0+ 0

172

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

0 0 0 1 1 1 1 0

0+ 0+ 0+ 16+ 8+ 4+ 2+ 030

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 1 1 1 1 1 1

128+ 64+ 32+ 16+ 8+ 4+ 2+ 1

255

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Total Number of Host Bits - ?

You can get the Total Bits by counting the 1 in the Inverse Number of Network Mask

00000000.00000000.11111111.11111111 (Inverse Number of Network Mask)

We have 16 1

Number of Host - ?

FORMULA : 2n- 2 = number of host (n = total number of host bits)

2162 = 65534

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Problem 2

IP Address - 172.30.1.33

Network Mask - 255.255.255.0

Network Address - ?

Change IP Address and Network Mask into Binary Number

IP Address, 172 = 10101100, 30 = 00011110, 1 = 00000001, 33 = 00100001

By using Short Division by 2 with remainder you can convert a decimal number into binary number

172 / 2 = 86 (0) 30 / 2 = 15 (0) 1 / 2 = 0.5 (1) 33 / 2 = 16.5 (1)

86 / 2 = 43 (0) 15 / 2 = 7.5 (1) 16 / 2 = 8 (0)

43 / 2 = 21.5 (1) 7 / 2 = 3.5 (1) 8 / 2 = 4 (0)

21 / 2 = 10.5 (1) 3 / 2 = 1.5 (1) 4 / 2 = 2 (0)

10 / 2 = 5 (0) 1 / 2 = 0.5 (1) 2 / 2 = 1 (0)

5 / 2 = 2.5 (1) 1 / 2 = 0.5 (1)

2 / 2 = 1 (0)

1 / 2 = 0.5 (1)

Network Mask, 255 = 11111111, 255 = 11111111, 255 = 11111111, 0 = 00000000

255 / 2 = 127.5 (1)

127 / 2 = 63.5 (1)

63 / 2 = 31.5 (1)

31 / 2 = 15.5 (1)

15 / 2 = 7.5 (1)

7 / 2 = 3.5 (1)

3 / 2 = 1.5 (1)

1 / 2 = 0.5 (1)

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Inverse Number of Network Mask -> 00000000.00000000.00000000.11111111

Network Mask 11111111 11111111 11111111 00000000

InverseNetwork Mask 00000000 00000000 00000000 11111111

And then do Logical AND Gate between 2 binary number, whereas;

1 AND 1 = 1

1 AND 0 = 0

0 AND 0 = 0

IP Address

X

10101100 00011110 00000001 00100001

Network Mask 11111111 11111111 11111111 00000000

Network

Address

10101100 00011110 00000001 00000000

Convert the binary number into decimal to get the Network Address

10101100 = 172, 00011110 = 30, 00000001 = 1, 0000000 = 0

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 0 1 0 1 1 0 0

128 + 0+ 32 + 0+ 8 + 4+ 0+ 0

172

2

7

= 128 2

6

= 64 2

5

= 32 2

4

= 16 2

3

= 8 2

2

= 4 2

1

= 2 2

0

= 10 0 0 1 1 1 1 0

0 + 0 + 0 + 16 + 8 + 4 + 2 + 0

30

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

0 0 0 0 0 0 0 1

0+ 0+ 0+ 0+ 0+ 0+ 0+ 1

1

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Network Broadcast Address - ?

Use the IP Address binary number and the Inverse Number of Network Mask

And then do Logical OR Gate between 2 binary number whereas;

1 OR 1 = 1

0 OR 1 = 1

0 OR 0 = 0

IP Address

+

10101100 00011110 00000001 00100001

Inverse

NetworkMask

00000000 00000000 00000000 11111111

Network

Broadcast

Address

10101100 00011110 00000001 11111111

Convert the binary number into decimal to get the Network Broadcast Address

10101100 = 172, 00011110 = 30, 00000001 = 1, 11111111 = 255

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 0 1 0 1 1 0 0

128 + 64+ 32 + 0+ 8 + 4+ 0+ 0+

172

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

0 0 0 1 1 1 1 0

0+ 0+ 0+ 16 + 8 + 4 + 2+ 0

30

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27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

0 0 0 0 0 0 0 1

0 + 0 + 0 + 0 + 0 + 0 + 0 + 1

1

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 1 1 1 1 1 1

128 + 64 + 32 + 16 + 8 + 4 + 2 + 1

255

Total Number of Host Bits - ?

You can get the Total Bits by counting the 1 in theInverse Number of Network Mask

00000000.00000000.00000000.11111111

We have 8 1

Number of Host - ?

By using the formula 2n

- 2 = number of host (n = total number of host bits)

282 = 254

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Problem 3

IP Address = 192.168.10.234

Network Mask = 255.255.255.0

Network Address = ?

IP Address, 192 = 11000000, 168 = 10101000, 10 = 00001010, 234 = 11101010

192 / 2 = 96 (0) 168 / 2 = 84 (0) 10 / 2 = 5 (0) 234 / 2 = 117 (0)

96 / 2 = 48 (0) 84 / 2 = 42 (0) 5 / 2 = 2.5 (1) 117 / 2 = 58.5 (1)

48 / 2 = 24 (0) 42 / 2 = 21 (0) 2 / 2 = 1 (0) 58 / 2 = 29 (0)

24 / 2 = 12 (0) 21 / 2 = 10.5 (1) 1 / 2 = 0.5 (1) 29 / 2 = 14.5 (1)

12 / 2 = 6 (0) 10 / 2 = 5 (0) 14 / 2 = 7 (0)

6 / 2 = 3 (0) 5 / 2 = 2.5 (1) 7 / 2 = 3.5 (1)

3 / 2 = 1.5 (1) 2 / 2 = 1 (0) 3 / 2 = 1.5 (1)

1 / 2 = 0.5 (1) 1 / 2 = 0.5 (1) 1 / 2 = 0.5 (1)

Network Mask, 255 = 11111111, 255 = 11111111, 255 = 11111111, 0 = 00000000

255 / 2 = 127.5 (1)

127 / 2 = 63.5 (1)

63 / 2 = 31.5 (1)

31 / 2 = 15.5 (1)

15 / 2 = 7.5 (1)

7 / 2 = 3.5 (1)

3 / 2 = 1.5 (1)

1 / 2 = 0.5 (1)

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Inverse Number of Network Mask -> 00000000.00000000.00000000.11111111

Network Mask 11111111 11111111 11111111 00000000

InverseNetwork Mask 00000000 00000000 00000000 11111111

And then do Logical AND Gate between 2 binary number, whereas;

1 AND 1 = 1

1 AND 0 = 0

0 AND 0 = 0

IP Address

X

11000000 10101000 00001010 11101010

Network Mask 11111111 11111111 11111111 00000000

Network

Address

11000000 10101000 00001010 00000000

11000000 = 192, 10101000 = 168, 00001010 = 10, 00000000 = 0

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 0 0 0 0 0 0

128+ 64+ 0 0 0 0 0 0

192

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 0 1 0 1 0 0 0

128+ 0+ 32+ 0+ 8+ 0+ 0+ 0+168

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

0 0 0 0 1 0 1 0

0+ 0+ 0+ 0+ 8+ 0+ 2+ 0

10

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Network Broadcast Address - ?

Use the IP Address binary number and the Inverse Number of Network Mask

And then do Logical OR Gate between 2 binary number whereas;

1 OR 1 = 1

0 OR 1 = 1

0 OR 0 = 0

IP Address

+

11000000 10101000 00001010 11101010

Inverse Network

Address

00000000 00000000 00000000 11111111

Network Broadcast

Address

11000000 10101000 00001010 11111111

11000000 = 192, 10101000 = 168, 00001010 = 10, 11111111 = 255

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 0 0 0 0 0 0

128+ 64+ 0+ 0+ 0+ 0+ 0+ 0

192

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 0 1 0 1 0 0 0

128+ 0+ 32+ 0+ 8+ 0+ 0+ 0

168

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 10 0 0 0 1 0 1 0

0+ 0+ 0+ 0+ 8+ 0+ 2+ 0

10

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27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 1 1 1 1 1 1

128+ 64+ 32+ 16+ 8+ 4+ 2+ 1

255

Total Number of Host Bits - ?

You can get the Total Bits by counting the 1 in the Inverse Number of Network Mask

00000000.00000000.00000000.11111111

We have 8 1

Number of Host - ?

By using the formula 2n- 2 = number of host (n = total number of host bits)

282 = 254

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Problem 4

IP Address = 172.17.99.71

Network Mask = 255.255.0.0

Network Address - ?

Change IP Address and Network Mask into Binary Number

IP Address, 172 = 10101100, 17 = 00010001, 99 = 01100011, 71 = 01000111

By using Short Division by 2 with remainder you can convert a decimal number into binary number

172 / 2 = 86 (0) 17 / 2 = 8.5 (1) 99 / 2 = 49.5 (1) 71 / 2 = 35.5 (1)

86 / 2 = 43 (0) 8 / 2 = 4 (0) 49 / 2 = 24.5 (1) 35 / 2 = 17.5 (1)

43 / 2 = 21.5 (1) 4 / 2 = 2 (0) 24 / 2 = 12 (0) 17 / 2 = 8.5 (1)

21 / 2 = 10.5 (1) 2 / 2 = 1 (0) 12 / 2 = 6 (0) 8 / 2 = 4 (0)

10 / 2 = 5 (0) 1 / 2 = 0.5 (1) 6 / 2 = 3 (0) 4 / 2 = 2 (0)

5 / 2 = 2.5 (1) 3 / 2 = 1.5 (1) 2 / 2 = 1 (0)

2 / 2 = 1 (0) 1 / 2 = 0.5 (1) 1 / 2 = 0.5 (1)

1 / 2 = 0.5 (1)

Network Mask, 255 = 11111111, 255 = 11111111, 0 = 00000000, 0 = 00000000

255 / 2 = 127.5 (1)

127 / 2 = 63.5 (1)

63 / 2 = 31.5 (1)

31 / 2 = 15.5 (1)

15 / 2 = 7.5 (1)

7 / 2 = 3.5 (1)

3 / 2 = 1.5 (1)

1 / 2 = 0.5 (1)

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Inverse Number of Network Mask -> 00000000.00000000.11111111.11111111

Inverse Number is when you change 0 to 1 and 1 to 0.

Network Mask 11111111 11111111 00000000 00000000

Inverse

Network Mask

00000000 00000000 11111111 11111111

And then do Logical AND Gate between 2 binary number, whereas;

1 AND 1 = 1

1 AND 0 = 0

0 AND 0 = 0

IP Address

X

10101100 00010001 01100011 01000111

Network Mask 11111111 11111111 00000000 00000000

Network

Address

10101100 00010001 00000000 00000000

10101100 = 172, 00010001 = 17, 00000000 = 0, 00000000 = 0

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 0 1 0 1 1 0 0

128+ 0+ 32+ 0+ 8+ 4+ 0+ 0+

172

27

= 128 26

= 64 25

= 32 24

= 16 23

= 8 22

= 4 21

= 2 20

= 10 0 0 1 0 0 0 1

0+ 0+ 0+ 16+ 0 0 0 1

17

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Network Broadcast Address - ?

Use the IP Address binary number and the Inverse Number of Network Mask

And then do Logical OR Gate between 2 binary number whereas;

1 OR 1 = 1

0 OR 1 = 1

0 OR 0 = 0

IP Address

+

10101100 00010001 01100011 01000111

Inverse

NetworkMask

00000000 00000000 11111111 11111111

Network

Broadcast

Address

10101100 00010001 11111111 11111111

10101100 = 172, 00010001 = 17, 11111111 = 255, 11111111 = 255

27

= 128 26

= 64 25

= 32 24

= 16 23

= 8 22

= 4 21

= 2 20

= 11 0 1 0 1 1 0 0

128+ 0+ 32+ 0+ 8+ 4+ 0+ 0+

172

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

0 0 0 1 0 0 0 1

0+ 0+ 0+ 16+ 0+ 0+ 0+ 1

17

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 1 1 1 1 1 1

128+ 64+ 32+ 16+ 8+ 4+ 2+ 1+

255

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Total Number of Host Bits - ?

You can get the Total Bits by counting the 1 in the Inverse Number of Network Mask

00000000.00000000.11111111.11111111 (Inverse Number of Network Mask)

We have 16 1

Number of Host - ?

FORMULA : 2n- 2 = number of host (n = total number of host bits)

2162 = 65534

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Problem 5

IP Address192.168.3.219

Network Mask255.255.0.0

Network Address = ?

IP Address, 192 = 11000000, 168 = 10101000, 3 = 00000011, 219 = 11011011

192 / 2 = 96 (0) 168 / 2 = 84 (0) 3 / 2 = 1.5 (1) 219 / 2 = 109.5 (1)

96 / 2 = 48 (0) 84 / 2 = 42 (0) 1 / 2 = 0.5 (1) 109 / 2 = 54.5 (1)

48 / 2 = 24 (0) 42 / 2 = 21 (0) 54 / 2 = 27 (0)

24 / 2 = 12 (0) 21 / 2 = 10.5 (1) 27 / 2 = 13.5 (1)

12 / 2 = 6 (0) 10 / 2 = 5 (0) 13 / 2 = 6.5 (1)

6 / 2 = 3 (0) 5 / 2 = 2.5 (1) 6 / 2 = 3 (0)

3 / 2 = 1.5 (1) 2 / 2 = 1 (0) 3 / 2 = 1.5 (1)

1 / 2 = 0.5 (1) 1 / 2 = 0.5 (1) 1 / 2 = 0.5 (1)

Network Mask, 255 = 11111111, 255 = 11111111, 0 = 00000000, 0 = 00000000

255 / 2 = 127.5 (1)

127 / 2 = 63.5 (1)

63 / 2 = 31.5 (1)

31 / 2 = 15.5 (1)

15 / 2 = 7.5 (1)

7 / 2 = 3.5 (1)

3 / 2 = 1.5 (1)

1 / 2 = 0.5 (1)

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Inverse Number of Network Mask -> 00000000.00000000.11111111.11111111

Inverse Number is when you change 0 to 1 and 1 to 0.

Network Mask 11111111 11111111 00000000 00000000

Inverse

Network Mask

00000000 00000000 11111111 11111111

And then do Logical AND Gate between 2 binary number, whereas;

1 AND 1 = 1

1 AND 0 = 0

0 AND 0 = 0

IP Address

X

11000000 10101000 00000011 11011011

Network Mask 11111111 11111111 00000000 00000000

Network

Address

11000000 10101000 00000000 00000000

11000000 = 192, 10101000 = 168, 00000000 = 0, 00000000 = 0

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 0 0 0 0 0 0

128+ 64+ 0 0 0 0 0 0

192

27

= 128 26

= 64 25

= 32 24

= 16 23

= 8 22

= 4 21

= 2 20

= 11 0 1 0 1 0 0 0

128+ 0+ 32+ 0+ 8+ 0+ 0+ 0+

168

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Network Broadcast Address - ?

Use the IP Address binary number and the Inverse Number of Network Mask

And then do Logical OR Gate between 2 binary number whereas;

1 OR 1 = 1

0 OR 1 = 1

0 OR 0 = 0

IP Address

+

11000000 10101000 00000011 11011011

Inverse

Network

Mask

00000000 00000000 11111111 11111111

Network

Broadcast

Address

11000000 10101000 11111111 11111111

11000000 = 192, 10101000 = 168, 11111111 = 255, 11111111 = 255

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 0 0 0 0 0 0

128+ 64+ 0 0 0 0 0 0

192

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 0 1 0 1 0 0 0

128+ 0+ 32+ 0+ 8+ 0+ 0+ 0+

168

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 1 1 1 1 1 1

128+ 64+ 32+ 16+ 8+ 4+ 2+ 1+

255

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Total Number of Host Bits - ?

You can get the Total Bits by counting the 1 in the Inverse Number of Network Mask

00000000.00000000.11111111.11111111 (Inverse Number of Network Mask)

We have 16 1

Number of Host - ?

FORMULA : 2n- 2 = number of host (n = total number of host bits)

2162 = 65534

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Problem 6

IP Address192.168.3.219

Network Mask255.255.255.224

Network Address = ?

IP Address, 192 = 11000000, 168 = 10101000, 3 = 00000011, 219 = 11011011

192 / 2 = 96 (0) 168 / 2 = 84 (0) 3 / 2 = 1.5 (1) 219 / 2 = 109.5 (1)

96 / 2 = 48 (0) 84 / 2 = 42 (0) 1 / 2 = 0.5 (1) 109 / 2 = 54.5 (1)

48 / 2 = 24 (0) 42 / 2 = 21 (0) 54 / 2 = 27 (0)

24 / 2 = 12 (0) 21 / 2 = 10.5 (1) 27 / 2 = 13.5 (1)

12 / 2 = 6 (0) 10 / 2 = 5 (0) 13 / 2 = 6.5 (1)

6 / 2 = 3 (0) 5 / 2 = 2.5 (1) 6 / 2 = 3 (0)

3 / 2 = 1.5 (1) 2 / 2 = 1 (0) 3 / 2 = 1.5 (1)

1 / 2 = 0.5 (1) 1 / 2 = 0.5 (1) 1 / 2 = 0.5 (1)

Network Mask, 255 = 11111111, 255 = 11111111, 255 = 11111111, 224 = 11100000

255 / 2 = 127.5 (1) 224 / 2 = 112 (0)

127 / 2 = 63.5 (1) 112 / 2 = 56 (0)

63 / 2 = 31.5 (1) 56 / 2 = 28 (0)

31 / 2 = 15.5 (1) 28 / 2 = 14 (0)

15 / 2 = 7.5 (1) 14 / 2 = 7 (0)

7 / 2 = 3.5 (1) 7 / 2 = 3.5 (1)

3 / 2 = 1.5 (1) 3 / 2 = 1.5 (1)

1 / 2 = 0.5 (1) 1 / 2 = 0.5 (1)

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Inverse Number of Network Mask -> 00000000.00000000.00000000.00011111

Inverse Number is when you change 0 to 1 and 1 to 0.

Network Mask 11111111 11111111 11111111 11100000

Inverse

Network Mask

00000000 00000000 00000000 00000000

And then do Logical AND Gate between 2 binary number, whereas;

1 AND 1 = 1

1 AND 0 = 0

0 AND 0 = 0

IP Address

X

11000000 10101000 00000011 11011011

Network Mask 11111111 11111111 11111111 11100000

Network

Address

11000000 10101000 00000011 11000000

11000000 = 192, 10101000 = 168, 00000011 = 3, 11000000 = 192

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 0 0 0 0 0 0

128+ 64+ 0 0 0 0 0 0

192

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 11 0 1 0 1 0 0 0

128+ 0+ 32+ 0+ 8+ 0+ 0+ 0

168

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

0 0 0 0 0 0 1 1

0+ 0+ 0+ 0+ 0+ 0+ 2+ 1

3

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Network Broadcast Address - ?

Use the IP Address binary number and the Inverse Number of Network Mask

And then do Logical OR Gate between 2 binary number whereas;

1 OR 1 = 1

0 OR 1 = 1

0 OR 0 = 0

IP Address

+

11000000 10101000 00000011 11011011

Inverse

NetworkMask

00000000 00000000 00000000 00011111

Network

Broadcast

Address

11000000 10101000 00000011 11011111

11000000 = 192, 10101000 = 168, 00000011 = 3, 11011111 = 223

27

= 128 26

= 64 25

= 32 24

= 16 23

= 8 22

= 4 21

= 2 20

= 11 1 0 0 0 0 0 0

128+ 64+ 0 0 0 0 0 0

192

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 0 1 0 1 0 0 0

128+ 0+ 32+ 0+ 8+ 0+ 0+ 0

168

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

0 0 0 0 0 0 1 1

0+ 0+ 0+ 0+ 0+ 0+ 2+ 1

27= 128 26= 64 25= 32 24= 16 23= 8 22= 4 21= 2 20= 1

1 1 0 1 1 1 1 1

128+ 64+ 0+ 16+ 8+ 4+ 2+ 1

223

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Total Number of Host Bits - ?

You can get the Total Bits by counting the 1 in the Inverse Number of Network Mask

00000000.00000000.00000000.00011111 (Inverse Number of Network Mask)

We have 5 1

Number of Host - ?

FORMULA : 2n- 2 = number of host (n = total number of host bits)

252 = 30