BO CO TH NGHIM BIN I NNG LNG IN C

BI 1:O LNG TI 3 PHA

I.MC TIU:- Tm hiu,lm quan vi cc thit b o v phng php o lng cng sut tc dng (W), cng sut biu kin (VA), cng sut phn khng (VAR) v h s cng sut PF trong mch 3 pha.

II.TH NGHIM:A.Lp t:

- Ngun 3 pha c ni vi 1 ng c KP 1Hp 380V ni Y

S nguyn l ng c AC KB gn vi ti c hc

B.o cng sut trng hp ti cn bng-khng b:

- 3 pha ca ng c c ni vi 3 pha ca ngun in.Dy trung tnh ca ng c ni vi dy trung tnh ca ngun.

- Khi ng ng c khng ng b bng cch cp ngun t b ngun 3 pha v gi tr in p khng i (U< 200V).

- Kt qu:

Varms = 161,1 VVbrms = 172,2 VVcrms = 163,2 V

Iarms = 0,81 AIbrms = 0,8 AIcrms = 0,79 A

Cosa = 0,166 Cosb = 0,066Cosc = 0,09

Ia =0,81.cos(t+800)Ib =0,8.cos(t+860)Ic = 0,79.cos(t+850)

- V biu pha:

Gin pha- Nhn xt: Theo l thuyt, trng hp ti cn bng khng b nn gi tr in p, dng in h s cng sut ca tng pha xp x nh nhau.Gin pha cho thy cc gc pha lch nhau 1 gc gn bng 1200.

- Cng sut biu kin,tc dng v h s cng sut ca tng pha:

Sa = 261 VASb = 262 VASc = 274 VA= 797 VA

Pa = 33 WPb = 11 WPc = 38 W= 82 W

Qa = 257 VARQb = 260 VARQc = 268 VAR= 785 VAR

PFa = 0,115PFb = 0,038PFc = 0,111

- Mi quan h gia S,P,Q,PF trn pha a theo cng thc l thuyt:

PFa = ==0,126

- Nhn xt: Gia l thuyt v thc nghim c sai s khng ng k do sai s trong qu trnh o. Nhn chung kt qu thc nghim gn ng vi l thuyt.

C.o cng sut trng hp ti cn bng, c b:- Ly t b ni gn song song vi ng c khng ng b.

- o P,Q,S,PF tng pha ca b ngun.

Sa = 280 VASb = 279 VASc = 260 VA

Pa = 44,8 WPb = 22,32 WPc = 33,8 W

Qa = 279 VARQb = 276VARQc = 259 VAR

PFa = 0,16PFb = 0,08PFc = 0,13

- Xc nh gi tr t b theo kt qu PF nhn c theo cng thc:

Pha a:

D.o cng sut trng hp khng ti mt cn bng:- Bng s liu: Sa = 281 VASb = 299 VASc = 241 VA

Pa = 64 WPb = 20 WPc = 9 W

Qa = 273 VARQb = 299 VARQc = 800 VAR

PFa = -0,214PFb = -0,066PFc = -0,041

- Nhn xt: Cng sut tc dng chnh lch nhau nhiu, h s cng sut cao nht pha a v thp nht pha c.o d trng hp ti mt cn bng s nh hng n ng c.BI 2: MY BIN P 1 PHAI.MC TIU:

- Hiu v kim tra li cc c tnh ca my bin p, c tnh khng ti,c tnh ngn mch, c tnh c ti ca my bin p.- T cc th nghim, xc nh v v s mch tng ng ca my bin p.

II.TH NGHIM:

A.Th nghim khng ti:

S nguyn l

S u dy

- Bng s liu:

U10(V)406080100120140160180200220

U20(V)2030415360718291102111

I10(mA)4353637484107123158215285

P10(W)0,591,532,834,466,799,513,420,7632,0443,96

cos0,0880,2680,4050,5030,5530,5970,6030,6070,5940,61

- c tnh khng ti: U10=f(I10).

- Nhn xt:

Nguyn l lm vic ca my bin p:

Khi c U1 vo dy qun s cp s c dng s cp I1 to sc t ng I1.1, to t thng mc vng qua cun s cp v th cp. Khi my bin p khng ti th do dng khng ti I10 chy trong dy qun s cp sinh ra.

Gi tr P10 l cng sut tn hao khng ti ca my bin p, tc l cng sut ngun in cung cp cho my bin p ch khng ti.

Trong dy cng sut o c th gi tr P10 ti p nh mc c ngha nht. V gi tr quy i tn hao khng ti thng ln nn sai s ln.- Cc thng s cho s tng ng:

S tng ng

- Tng tr khng ti:

B.Th nghim ti ngn mch:S nguyn l

S u dy

- Bng s liu:

I2n(A)12345678910

U1n(V)1,84,15,97,91011,713,715,817,319,3

I1n(A)0,4941,081,5622,52,993,533,874,414,92

P1n(W)0,854,2915,524,534,648607594

cos10,9950,9930,9920,9920,9910,9920,9910,9910,9910,991

- c tnh ngn mch: U1n= f(I1n)

-Nhn xt:

th nghim ngn mch,c th b qua tn hao st t.

- Tng tr ngn mch:

C.Th nghim c ti:S u dy

- Bng s liu:

I1(A)0,6741,0711,5111,952,352,83,273,724,53

U1(V)220220220220220220220220220

I2(A)1234567810

U2(V)110110108106,8106,1105,3104,2103,1101,1

cos10,990,990,990,990,990,990,990,990,99

cos20,8860,9340,9600,9710,9810,9860,9900,9920,994

P1(W)146,5233330424,7512610712810987

P2(W)97205,5311414,55206237228181004,9

- c tnh ti: U2=f(I2)

- st p khi dng s cp gi tr nh mc:

- Tnh v v c tnh hiu sut theo h s ti:

Sm=U2m.I2m=110.10=1100 VA

0,6620,8820,9420,9761,0161,0211,0141,011,018

0,10,20,2950,3880,4820,5740,6630,7490,919

- c tnh hiu sut theo h s ti:

BI 3: MY BIN P MT PHA C NHNH PHN TI.MC TIU:

- Hiu s nh hng ca cu to mch t n c tnh lm vic ca my bin p. S nh hng ca t thng r ln gi tr in khng ca my bin p.II.TH NGHIM:

A.Th nghim khng ti:

S nguyn l

S u dy

- Bng gi tr:

U10(V)406080100120140160180200220

U20(V)19,1429,340,150,660,971,181,693,4102,9112,2

I10(A)0,1440,190,2330,2740,3140,3570,4020,4490,4970,555

cos10,2030,290,330,340,330,320,30,280,270,26

P10(W)1,173,36,159,312,41619,322,6326,8431,75

- c tnh khng ti:

- Tnh ton thng s ca mch tng ng my bin p:

S tng ngB.Th nghim ngn mch:

S nguyn l

S ni dy

- Bng gi tr:U1n(V)406080100120140160180200220

I2n(V)0,250,511,522,533,644,4

I1n(V)0,4760,6950,9161,1351,351,5751,7951,962,192,41

cos10,070,080,090,090,090,090,090,090,090,09

P1n(W)1,333,346,610,2214,5819,825,8531,7539,4247,72

- Cc thng s cho s tng ng ca my bin p:

- c tnh ngn mch: U1n= f(I1n)

- Nhn xt: ng c tnh khng t v ngn mch c dng ging nhau, gn nh l tuyn tnh theo I.C.Th nghim c ti:S u dy- Bng s liu:U1(V)220220220220220220220220220

I1(A)0,9571,391,6911,98722,112,192,252,32

U2(V)106,394,984,174,665,457,95247,239,8

I2(A)1,0021,832,312,672,963,163,33,413,55

cos10,680,680,640,570,530,480,440,400,35

cos20,9980,9980,9990,9990,9890,9980,9970,9990,998

P1(W)143,2208238,1249,2233,2222,8212198178,6

P2(W)106,3173,3194,1199191,5182,6171,1160,8141

- c tnh ti: U2= f(I2)

BI 4: KHUCH I TI.MC TIU:

- Hiu v s bo ha ca mch t, tc dng ca t thng mt chiu v t thng xoay chiu ln sc in ng cm ng v t cm ca cun dy.

II.TH NGHIM:

A.S mch

B.Th nghim:

- iu chnh thay i dng DC, o v v dng sng ca tn hiu p hai u cun dy, tn hiu p v dng trn ti (n ).

- iu chnh thay i IDC t 0250mA

- Bng kt qu o:

IDC(mA)050100150200250

UC1HHHHHH

Volt/div222111

UdHHHHHH

Volt/div0,212555

In(A)0,0610,1660,230,2630,2810,29

- Nguyn l hot ng:

Mch khuch i t thc cht l mt cun dy hot ng vng bo ha. Mch khuch i t ng dng tnh cht bo ha ca li t.

Mt dng in DC nh, vi tr khng ngun thp c a vo hai u cun dy iu khin

in p xoay chiu t vo mt u cun dy xoay chiu. Gi tr ca dng in mt chiu c a vo cun dy lm thay i c im lm vic trn ng cong t ha, c hai cun dy u tin dn n vng bo ha. Khi cun dy s chuyn t trng thi tr khng cao sang trng thi tr khng thp hn. Vy dng in mt chiu thay i tr khng ca cun xoay chiu.

V cun mt chiu c ni trit tiu in p cm ng nn mch mt chiu khng b nh hng bi mch xoay chiu. Vy n ch p ng theo in tr thun ca cun dy. Suy ra nng lng a vo cun iu khin rt ln so vi cun xoay chiu.

S thay i ca dng in mt chiu iu khin dn n s thay i tr khng ca cun dy, do dng in ti s b thay i. T suy ra mch c t tnh khuch i dng in. _1383196972.xlsChart1

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