bar bending schedule(by akhil)

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Bar Bending Schedule By Akhil Lamdade

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DESCRIPTION

Bar Bending Schedule (BBS) is a chart which gives a clear picture of bar length, diameter of bar ,bar mark ,location of bar. It allow workers to place steel properly.

TRANSCRIPT

Page 1: Bar bending schedule(by akhil)

Bar Bending Schedule

By Akhil Lamdade

Page 2: Bar bending schedule(by akhil)

CONTENT Introduction B B S for different reinforced concrete structures Measurement of bending dimensions Do’s and Don'ts Typical bar bending schedule Codes , specifications and standards

Page 3: Bar bending schedule(by akhil)

Bar Bending Schedule Member identification Bar mark Type of steel Diameter of bar Length of each bar Number of members Number of bars in each member Total number of bars Total length Shape code Bending dimensions

Page 4: Bar bending schedule(by akhil)

BBS for RC Beams

Page 5: Bar bending schedule(by akhil)

BBS for RC Slabs

Page 6: Bar bending schedule(by akhil)

BBS for Columns and walls

Page 7: Bar bending schedule(by akhil)

Measurement of bending dimensions

Bent-up Bar

h45o

h

h2

Additional Length = 0.414 hTotal Length = L + 0.414 h

L

Page 8: Bar bending schedule(by akhil)

Do’s and Don’tsProper accuracyProvide cover to reinLocation of holes

Bars >36mm shall not bundled

Welding is not permitted at bends

Page 9: Bar bending schedule(by akhil)

Typical BBS CalculationExample: Prepare bar bending schedule for the given beam. Clear cover = 40 mm

2-#20 +1-#15

4000

570 2-#20

2-#10

228

#10 @ 180 c/c

Longitudinal Section

1-# 15

Page 10: Bar bending schedule(by akhil)

Bar Bending Schedule (contd…)Example: Prepare bar bending schedule for the given beam. Clear cover = 40 mm

#10 @ 180 c/c

228

375

2-#10

1-# 15

2-#20

(M-2)

(M-1)

(S-1)

(H-1)

Cross Section

Page 11: Bar bending schedule(by akhil)

Bar Bending Schedule (contd…)Example:

M-1M-1 = 4000 + 2 x 228 – 2 x 40 + 2 x (18 x 20) = 5096

M-2h = 375 – 2 x 40 – 2 x 10 – 2 (15/2) = 260 h

M-2 = 4000 + 2 x 228 – 2 x 40 + (0.414 x 260) x 2 = 5091

H-1H-1 = 4000 + 2 x 228 – 2 x 40 = 4376

Page 12: Bar bending schedule(by akhil)

Bar Bending Schedule (contd…)Example: Prepare bar bending schedule for the given beam. Clear cover = 40 mm

Number of Bars = 4000 / 180 +1 = 24 Round-up

Shear stirrups

a

a = 375 – 2 x 40 – 10 = 285 mm

bb = 228– 2 x 40 – 10 =138 mm

Total length of S-1 = 2 (138 + 285 + 18 x 10) = 1206 mm

Page 13: Bar bending schedule(by akhil)

Bar Bending Schedule

Serial #

Bar Designatio

nNumber of Bars

Length of one

Bar(m)

Dia of

bar

Weight of Steel Bars Shape of Bar

#10 #15 #20

1 M-1 2 5.096 20 24

2 M-2 1 4.591 15 7.2

3 H-1 2 4.376 10 6.9

4 S-1 24 1.206 10 22.7

1.05 Σ

31.1 7.6 25.

2Total Weight = 64 kg

4376

4376

4376

285138

Page 14: Bar bending schedule(by akhil)

CODES , SPECIFICATIONS & STANDARDS IS:2502-1963 IS:1893-2000 SP:34 IS:456 International standard

ISO:4066-1977

some websites which are proving Bar Bending Schedule Software. 

1. www.eigen-tech.com/cs.html 2. www.rgsrebar.com/rebar.aspx 3. www.ensoftindia.com/

prod_barbeque.htm 4. www.steelpac.co.uk/design/

steelpac_rdm... 5. www.cadsglobal.com 6. www.supercivilcd.com 7. www.technocad.co.za 8. www.BendingSchedule.com 9. www.structural-engineering.fsnet.

co.uk...

10.  www.continuousbeamanalysis.com

Page 15: Bar bending schedule(by akhil)

Queries ?

Page 16: Bar bending schedule(by akhil)

Thank you

Good day