basic engineering drawing - the eye archive/rhodescook... · orthographicprojection:firstangle ......
TRANSCRIPT
BASIC
RS Rhodes& LBCook
ENGINEERINGDRAWING
R S RHODESM Weld J, Diploma in Advanced Studies in Education.Lecturer responsible for Engineering DrawingStafford College of Further Education.
L B COOKB A (Hons), MIED, Cert Ed.Lecturer in Engineering DrawingStafford College of Further Education.
Pitman Publishing
PITMAN PUBLISHING LIMITED39 Parker Street London WC2B 5PB
Associated CompaniesCopp Clark Ltd, TorontoFearon-Pitman Publishers Inc, Belmont, CaliforniaPitman Publishing New Zealand Ltd, WellingtonPitman Publishing Pty Ltd, Melbourne
© R S Rhodes & L B Cook 1975, 1978
First published in Great Britain 1975reprinted (with corrections and amendments) 1978
All rights reserved. No part of this publication may bereproduced, stored in a retrieval system, or transmitted,in any form or by any means, electronic, mechanical,photocopying, recording and/or otherwise without theprior written permission of the publishers. This bookmay not be lent, resold, hired out or otherwise disposedof by way of trade in any form of binding or cover otherthan that in which it is published, without the priorconsent of the publishers.
Camera copy prepared by Morgan-Westley /WPrinted in Great Britain by Unwin Brothers LtdThe Gresham Press, Old Woking, SurreyA member of the Staples Printing Group
ISBN: 273 318£7 X
) ACCESSION No.
r^LiuLmSS no. <ajr /~f
IttaOKY
&Jb%
This book contains what we consider to be the "basics" ofEngineering Drawing. Orthographic Projection, Conventions,Sectioning, Pictorial Representation and Dimensioning havebeen covered in detail as we feel that a thorough under-standing of these topics forms a sound foundation upon whichto build. All technical information, examples, exercisesand solutions have been compiled in accordance with thelatest "metric" drawing office standards - B.S. 308:1972.
The book has not been written for any specific coursebut can be profitably used both by students being introducedto Engineering Drawing and also by those who have acquired alittle knowledge of the subject and wish to consolidate andincrease their understanding by working through carefullygraded exercises. It should prove useful for Craft, Tech-nician (T.E.C.), O.N.D., C.S.E. and G.C.E. students andalso for those H.N.D. and Degree students with littledrawing experience. The book is seen primarily as a studentself-educator though no doubt many teachers will find ituseful as a reference source and/or exercise "bank"
.
Topics have been presented in a similar manner whereverpossible. Generally the opening page introduces the topic,the next imparts the basic facts - visually rather thanverbally wherever possible. An illustrative example isprovided to aid understanding and this is followed by aseries of carefully graded exercises.
We are well aware of the dangers of presenting exer-cises which are known to contain errors. They have beenincluded because in our experience they are the commonmisconceptions among students of engineering drawing. Inall cases the correct method and answers are given, some-times immediately following the example, or in the solutionsat the end of the book.
It must be emphasized that this book not only trans-mits information it is also a work-book. Do not be afraidof drawing and writing on the pages! If maximum benefit isto be derived from the book then the old maxim, "I do and I
understand" must be the students' guide.We thank those people whose observations and suggestions
have helped us improve upon the first edition of the book.We also wish to thank the British Standards Institution forallowing, usf to use extracts from B.S. 308:1972.
Contents
ORTHOGRAPHIC PROJECTION 1
ORTHOGRAPHIC PROJECTION: FIRST ANGLE 2
Lines • 5
Missing detail • 11Missing views • 12Sketching orthographic views • 13
ORTHOGRAPHIC PROJECTION: THIRD ANGLE 14
Comparison of first and third angle projection • 15
SECTIONING 21
The rules of sectioning • 22Sectioning : exceptions • 23Staggered section planes • 24Exercises • 25
TERMINOLOGY 33
ABBREVIATIONS 36
CONVENTIONAL REPRESENTATION 38
Screw threads • 38Springs • 39Shaft details • 40Knurling • 41Bearings • 41Long components • 42Gears • 43
TESTS 45
Test for terminology • 45Test for abbreviations • 46Test for conventional representations • 47Test for abbreviations > terminology j andconventional representations • 48
PICTORIAL DRAWING 49
PICTORIAL DRAWING: ISOMETRIC 50
Inclined edges • 51Exercises • 52Construction of ellipses • 55Examples • 5 7
Exercises • 58Isometric freehand drawing • 59
PICTORIAL DRAWING: OBLIQUE 61
Methods of construction • 62Inclined edges • 63Methods of constructing oblique circles • 64Methods of constructing oblique ellipses • 65Examples • 66
DIMENSIONING 68
Arrangement of dimensions * 72
Dimensioning circles • 73Dimensioning radii • 74Dimensioning angles • 75Designation of plain holes • 76Location dimensions • 77Exercises • 78
LIMITS AND FITS FOR HOLES AND SHAFTS 84
Limit systems • 86Fit • 87Conventional method of illustrating terms • 89
ISO METRIC SCREW THREADS 91
Designation • 92Screw threads 3 nuts and bolts • 93Nuts and bolts exercises • 94
ASSEMBLY DRAWINGS 95
General assembly • 96Sectioned assembly • 98Exercises • 99
DEVELOPMENTS 105
PARALLEL LINE DEVELOPMENT 106
RADIAL LINE DEVELOPMENT 120
Pyramids • 120Right cones • 124
TRIANGULATION 130
SOLUTIONS 136
First angle orthographic projection • 137Third angle orthographic projection - 140Sectioning • 144Terminology 3 abbreviations 3 conventional representation • 148Isometric drawing • 149Oblique drawing • 153Dimensioning • 155Limits and fits • 161Sectioned assemblies • 162Developments: parallel line • 165Developments : radial line • 172Developments : triangulation • 180
Orthographic Projection
CommunicationThere are many different ways of communicating ideas, informa-tion, instructions, requests, etc. They can be transmitted bysigns or gestures, by word of mouth, in writing, or graphically.In an industrial context the graphical method is commonly used,communication being achieved by means of engineering drawings.
If oral and written communication only were used whendealing with technical matters, misunderstandings could arise,particularly in relation to shape and size. The lack of a univ-ersal spoken language makes communication and understanding evenmore difficult because of the necessity to translate both wordsand meaning from one language to another.
However, the universally accepted methods used in graphicalcommunication through engineering drawings eliminate many ofthese difficulties and make it possible for drawings prepared bya British designer to be correctly interpreted or "read" by, forexample, his German, French or Dutch counterpart.
Equally important, the components shown on the drawingscould be made by suitably skilled craftsmen of any nationalityprovided they can "read" an engineering drawing.
Conventionally prepared engineering drawings provide themain means of communication between the "ideas" men (the design-ers and draughtsmen) and the craftsmen (machinists, fitters,assemblers, etc.). For the communication to be effective, every-one concerned must interpret the drawings in the same way. Onlythen will the finished product be exactly as the designer envis-aged it.
To ensure uniformity of interpretation the British StandardsInstitution have prepared a booklet entitled BS 308:1972, Engin-eering Drawing Practice . Now in three parts, this publicationrecommends the methods which should be adopted for the prepara-tion of drawings used in the engineering industry.
The standards and conventions in most common use and hencethose required for a basic understanding of Engineering Drawingare illustrated and explained in this book.
Orthographic ProjectionIn the engineering industry communication between the drawingoffice and the workshop is achieved mainly by means of engineer-ing drawings. The principal method used to prepare these drawingsis known as Orthographic Projection.
Basically, Orthographic Projection is the representation of
a three-dimensional component on a flat surface (the drawingsheet) in two-dimensional form. At least two orthographic views,therefore, are required to indicate fully the shape and size of a
component. If the component is a complicated one then usuallymore than two views are shown to aid understanding.
In this country two methods of Orthographic Projection areused. One is known as First Angle Orthographic Projection (often
referred to as English Projection) , the other as Third AngleOrthographic Projection (American Projection) . Both methods ofrepresentation are illustrated and explained in this section.
Orthographic Projection: First AngleThe pictorial drawing opposite indicatesthe shape of the component with a singleview.
An orthographic drawing indicatesthe shape of a component by using a
number of views each looking at adifferent face of the component.
At least two views are necessaryto fully represent the component.Usually, however, three views areshown in order to clarify internaland external detail:
(1) A Front View
(2) A Plan View
(3) A Side View
Fig.l
Fig. 2 (1) The front view, or front elevation,represents what is seen when lookingat the front of the component in thedirection of arrow F.
Front View (F)
(2) The plan view represents what isseen when looking at the top of thecomponent in the direction of arrowP at 90° to arrow F.
TTT1
i
'
i 1 I
Fig. 3
Plan View (P)
(3) A side view, or side elevation, represents what is seen whenlooking at the side of the component in the direction of eitherarrow R or arrow L. These arrows are at 90 to both arrow F
and arrow P.
View looking indirection of
arrow R.
Ri ght-HandSide View
(R)Fig. 4 Fig.
5
View looking indirection of
arrow L.
Left-HandSide View
(L)
The separate views of the component are combined to form acomplete orthographic drawing as shown below.
The front and side views are drawn in line with each otherso that the side view may be "projected" from the front viewand vice versa.
The plan view is drawn in line with and below tne front view.In other words, the plan is projected from the front view.
R
1
-0-
I I
>:
<
I 1
e
L
Note!
This symbol means
f'irst Angle Ortho-
.graphic Projection,
F i g . 6
Points to note when making a drawing using First Angle Ortho-graphic Projection:
(1) Corresponding heights in the front view and side view arethe same
.
For example, the height of the hole from tne base, H, isthe same in both front and side views.The thickness of the base, T, is the same in both frontand side views.
(2) Widths in the side view correspond to depths in the plan.For example, the total width, D, in the side view is thesame as the total depth, D, in the plan.The width, d, is the same in both plan and side views.
Projection of widths from side view to plan is made easierby using the 4 5° swing line as shown.
(3) The plan view is usually projected BELOW the front view.It can be above but this would be called an "inverted" plan.
(4) The R.H. side view is shown on the L.H. side of the front view.The L.H. side view is shown" on the R.H. side of the front view.
Note: Drawings should be read (or interpreted) by viewingfrom the R.H. side or bottom R.H. corner of the drawing.
The orthographic drawing of the bracket, Fig. 6, was constructed
step by step as follows:
STEP 1. The face to be used as the front view of the component was
chosen, in this case, looking in tne direction of arrow F (Fig-1) .
The selection of the front view is purely arbitrary.
STEP 2. The outline of tne
front view was drawn FAINTLY
in the position shown opp-
osite leaving room on the
drawing sheet for a plan
view and also both end views
to be added.
STEP 3. The outlines of the
plan view and side views
were projected FAINTLY from
the front view and
positioned as shown opposite
STEP 4. All remaining
external details were added
and centre lines inserted
as shown opposite.
STEP 5. All hidden detail, i.e. for hole and recess, was added and
the outline "heavied-in" to complete the drawing as shown in Fig. 6.
Lines
1 —2 —3 --
For general engineering drawings, the following typesof lines should be used.
Visible outlines
Dimension linesProjection linesConstruction linesHatching or section linesLeader lines for notes
Hidden detail
4
5
6
Centre lines;Pitch circles
(Cutting or viewing(planes
(Short break linesj Irregular boundary( lines
Typical applications of some of the recommended types of lineshave been shown in previous figures and are further illustratedbelow.
Hidden detail:shortthindashes
©Centrelines:longthinchain
©Outlinesthickcontinuous
Construc-tion lines:thincontinuous
I (theseare
erased oncompletionof drawing.)
£3-HIDDEN DETAIL
The line numbered 3 above is used to represent hidden detail, i.e.edges, holes, surfaces, etc., which are known to exist but cannotbe seen when viewed from outside the component
.
Note: A hidden detail line is a broken linenot a dotted line
The following drawings are further examples of components drawn
correctly in First Angle Orthographic Projection. Study each drawing
carefully until you understand how each view is obtained.
F
P
F
P
P
CO
Q_
ro
a. —
(N
CL
4->
CO
U-rH
GiH
g
oXiCO
O-P
01
CnCHrd
Q
aO•HPUCD
•r-i
O
ft
u
x:
rd
utnoxi-puoCD
iHCPg
orHCD
Q-p
cCD
GO&eou
CD
x:-p
-p
GCD
CO
CD
HPu<D
M
>i
3<4-l
CD
rd
O
tr>
G•H
rd
T3
CI
-H
CD
x:-p•HCD
CD
-Prd
urd
I
wCD
Oi CD
CD UW
x:u
CD
Ord
CD
CD
G-H
rH
CD
•HMX!
ci
-Hrd
MQjXCD
TtGrd
rd
GO
UO
>OHCD
X!
CD
rHX!rd
-P
CD
x:-p
a
wGrHOCO
>1x;
CD
Oard
mO
-PCD
CD
X!en
uWPS«OU2
•H
GO•H-Prd
-PGCD
Q_
CO
Q_
Q_
en
LO
Q_
Q_
QO
Q_
OCD
Uu
U GG O•H H
-PU rd
P4-1 G
CD
G CO
CD
m Mrd CuCD CD
PS ^
t7>
uQ
CN CO LO CO CO cn
UD
II |^7 '
1
i>
i i
(N IT) OO
osim oH
sh au
CD tnP o•H X!03 -PO M&oO CD
en tn £Cn fi • O
in
3=
cu
•H>
cd
0)
!h
x:p
5O
0}
U)
S-l
a)
xi-P
3s
O
a)
m atn 3=
•H M
to
XO•PCD
M
O T3
cu
a <c a xo w-rH
-p
u
rH
3= -Prtf in +J 0)
H ^ u gT) -rH
0)
xEH
a) O
O
•H 04
l-\
>
a)
m xo +jom
c o
(0 a)
u cnd o
-p
oCD
Sh
UOO
X!id
-P
CD
X-p
a•H
0)
p(0
-pen
-p
CD U
CD
>1-H>
cu r~-
> -H
Dj
XI-p
CD
MUm o
o ua
MCD CD
X! U6 «J
-PO OM CD •
pj M Cfl
M CCD O rHO O Oid c/i
0, CD
W XP •
CD CD
£!T3 oi
-PCJ
CD
UuOO
mo
xu-P 3:
CD CD
W
id
c si a sio
CD
XI X!-P 5
CD XiCD U
>1
S -p
o oX CD
Sh
• O
23 T3 -H
Select, from the views A to L below, the missing view from each ofthe drawings 1 to 12. Insert the letter in the space provided.Example: the missing view from drawing number 1 is C. Solns. p. 137
Q
D10
B
8
11
A
S
I
h
h
12
K B fi
n CO en
^3CN IT) GO
CN m CO
o-p
n id
a;
•H>
0)
X!PPO<uH0)
CO
d)4->
•HCO
O&&o
CD
uf0
rHft
5orHCD
X)
X!CO
p
T3CD
-PH CO
d)
en 3tn D1
G•H
tO
M
6O5-1
fa
0)5-1
W•H
xiu-Hx:
pto
•H5-1
CUO5-1
(0
<d
x;pc-H
a)
-H
>
tn
HsiPmo
5-1
CD
Xis
G
CD
xp
rHX!f0
PCD
X!PG-rH
go•rH
P-HU>
O
pGO5H
<+H
d)
x:p
pGCD
GOOjeoo
5h
Om
Sto
Xd)
5h
ofa
OW
Or-\
a
CO
GrHo
g
ox;01
5H en
d) (0
uo
tn X!H5H
d)
CO
GtO
fa
co
tn (D
G x!•H POo
5CO
•H>
GH
0)
ut0
iH
LU
Q
O
0Q
tnG•rH
fO
uQ
G-rH
CD
H>
PGO!-)
fa
4Ho
GOHpOCD5-1
•Hfa T3
G•H
ft
4Ho
sCD
-H
>
Gt0
GO-rH
pUCD
5h
rH -H
G tH•rH O5d)
•H>
CD
TS•H
GO•HPUCD
5H
•HU3 n3
10
CO toV
en
£-
E-
fN ID 00
i ! I
4\
CO+-»
0)C
(0
oXitfl
-H>
PWM•H
H
0)
O fd -HP >
to
tnCH
S 0)
CD TS-H -H> W
I
OMCm
O•H,c
rS
S-i
tnOxiPMO
Po
rtf (L)
Q 4-1
13G(0
O•HP
tn o
I
C•H
CO
•H
tnC-h
rd
t3
XiO(0
W0)n
•HrC
PQ)
CU
W
rC
OCD
X)
CD
P<urHa.
eo
n3CD
PP-H
a)
<D
X!
CO
(0
.a
tn
•H3=
omcu
a)
p0)
tn
•rH
mw•H
a)
xip
O T! -HU (0 (0
P>i 0)
X! T3
!h
<U
rQ
OPcoHprHo0}
CD
5OrH0)
Xi
C
o
-H
oororH
•
04
•
w dC orH •HO PCO 3
oin
11
r -
i rj
t~-
i
L _i
1
\
ID
1
J
l_ _J 1
1
1
|
1
1 Ln
^mmi
# % a>
--1
1
_J/^^*v F
Tlv y /
1
r
i
X<>y~&}— _
> i
k
Kj^J^^ L
ir ~i
i_ j
i
1
1
I
,/I
r—i
1
CN
1
i'
1
r I
I
1
L|
1
_|
ooIT)
r n
L j
/1
1
1
<1 1
lu^\X^1 '
r
L
-t
j
L ^—
1
'«d-
1
1'
i
! !^i i
, c^
(-+-)
—
1
i
__r:::i
-\! 1
!
r i
iV---4-i> '
i_ jiii1 1
1
CO
CD
>0)CCOCO awings
opposite
show
two
2ws
of
a
component
in
rst
Angle
Orthographic
Djection.
In
the
space
provided
2tch
a
third
view
in
Djection
with
the
two
sws
shown
.
On
the
line
provided
ite
the
name
of
the
view
ich
has
been
added.
a
F
for
front
view
P
for
plan
view
R
for
R.H.
side
view
L
for
L.H.
side
view.
Ins.
p.
139
,
HS
Added
View
__R__
>»> u
Q-rH -H> Cm ( en
5-
C
i H> 5
oen
>i
12
Sketch i
x/Irwsng orthographic
The components shown below aredrawn pictorially.
For each component sketch in good ^Xf\<^vided, a front view, a planview and a l.n. side view.Sketch the front view look-ing from F.Show all hidden detail.Use first angle projectionas shown on the right.
<f<^ s <]
<]
<]/|
A
>A^
\
i
Exampl
e
Solns. p. 139
/T
"" ^^T> ^[^^i \i^
A-
—
^^r^sr
/< < 2
A^
\ u1
. />
1 i
.5jA> ^^^r1 *
\r
|
JA1
AAA
kj^>'1 • i
1i
—;.
J
9>-
1a'Al^fC
A <<A^
;
-.4
\i/
A<. ~Aj
— NA
-1<
V 1
^\^^
iSaau
<!A<
\
<
^>\ AA>ai;
<A<
if
^5
v
^K
A?*
• <ri^A
<- ^a>-
<<
p- \ 3<i\^— D \U^\i —
13
Orthographic Projection: Third AngleYou may remember from information presentedearlier in the text that there are twomethods of orthographic projection used inthe preparation of engineering drawings.
You should, by now, be quite conversantwith one of them - First Angle OrthographicProjection. The other is known as ThirdAngle Orthographic Projection.
j
When representing a three-dimensionalcomponent in Third Angle OrthographicProjection, the basic views are exactlythe same as those shown when using FirstAngle Orthographic Projection. Thedifference between First Angle and ThirdAngle is in the positioning of the viewsrelative to each other.
In Third Angle Orthographic Projection the individual views areplaced on the drawing sheet in projection with each other as shown;
1'
i I I
PLAN VIEWlooking from P
Note!
This symbol means
Third Angle Ortho-
graphic Projection.
LEFT-HAND SIDE VIEWlooking from L
FRONT VIEWlooking from F
RIGHT-HAND SIDE VIEWlooking from R
Special pointsto note:
(1) The plan is always projected ABOVE the frontview
.
(2) The right-hand side view is shown on theRIGHT-hand side of the front view.
(3) The left-hand side view is shown on theLEFT-hand side of the front view.
14
c
oo
a
cCD
D
T3CCD
C
6
ao
cCD
CO
c
IEoo
—r-ri
1 1 1
1 1
a:
1
T
4-
Qgc
Il-
$_j
_j
*i
T
ftTI i
cr
0)
LL
-Pco
m(D
x!-p
w>om
CO
H
CD
-H>
CID
r-H
a,
o
en
&CD
•H
>
+J
O5-1
M-l
CD
X!-P
O
0) 0)
H -Hcn cn
x xi
c oo u
to
•H
?0)
>
a)
X!-P
o
a) <u
-rH -Hcn en
C! a
I
-PI
-H
cd
X!I
-P
f0
xi
Eh
a4h fnCD • W
WEh
Os
OdJOCD.a -h x! x;En > En 4J
CN
CU (U
H>
XEH
CD CD
x-p
wEh
O25
CD
H>
-PCOShmCD
x:p12o^wmin
-H
c
rH
CD
x:Eh
pcouIW
CD
X!-P
mO
CD
T)•Hcn
aC(0
XiI
Eh
•h pq
co
cn
-H
CD
•H>
CD
xi
-p.a
CD
xEH
CN
CD
XIP
5CD
•H>
o
w-H
s'CD
H>
CD
T3•Hcn
C(U
XII
4->
UHCD
CD
XEn
-Paou4H
CD
X-p
o
CD
•Hcn
"•d
c(D
XI
En
o
CD
X-p
CD
•H>
H>
15
0)
a•Hnj
-P£>
Q) O
tn cq
C -H
>
T3U-H
En ^!O
0)
>.5rH O-P -dOCD rtf
oo
as
U)
-P
a)
ao
-ptn
uCD
Ti
O
•H-P
a. c
O >ir
"4-1 r
o 34-4
03 <D
CD M
040e
x aCD O
U XiCD O
f3
CD
Xi-P>-l
CD -Pu CO(TJ
en •
tn GC O•H -H& +>:tO oU CD
T3 -nO
CD H0) CM5-1
Xi O-P -H
Xi-P Q4U) (0
U U•h tn4H O
XiCD -P^ uM o
Q_ LL
CO
LQ_ LJL
CN
CU
o.£CO
0)
-H>
X!U(0
<u
e
t!ato
m
CD
R3
IT)
D
16
n
Q_
UL
CO
I,
Dd uID
Q_
uDC
a: D
li. Q. Q_ LL
(3
S uO -HX! 43 CD
aj -p- u
0) tn-PP O S3
CO -P W 0>
o u CU 43u
o a> a> sHMOGl S3
S3 <cHen
S3
O PUM+JJlT3 43 a) o
o sa)
43EH
a n orlPl O
>1-H Um oa)
-h 5M o
CH43 Ha a)
•H £3 45
n3 (0 <D
Sn -H .HT3 (^43
43 CD +J
UrC T3 CD
a> c 43(0 -P
0)
fl >i S3H iH -Hg -Hiti 3 Mx ih a)
w cu 435H Pcd -HO 0)
Oj CO
S3
O•rH
p-PS3
a)
o
p<u
0>
43en en
a)
o
a
en
53<-{
OCO
a,<c a)
m m •
rS Eh
Qj43 UCD O Hw is a
a) «(0 o<3 43 SO > M
POa>
sh
O •
O £3
£3 O•H -HP
i-l rd
O Pm S3
d)
S3 wO 0)
en M
cu a)
as m
MQ
CN O in ID ao cn
17
ID
IZZT
IT)
CD
PHU)
o
-p
cCD
CO
O, OOj OO
CD
en ,ctn Pc-H
(0
MTi
CD
.gEh
3=
oP r-l
G CD
CD X!CO
CD g
a o
•H
rd
u
CD
,C-P
PtO
oo
CD ,Gen
o-H
CD
a•HuCD
(0
3mCD
S-l
tO
U
to
C
aO T3
CD
to
3
•rH
poCDn >iO rHU PCLi O
!-l
S-l
OO
gCD
CD
X!
mo
o
PCD
6
go-HptO
pCD
tn
CD
u
CD
M
XiUtO
CD
XO,-Q
CD
,GPg-H
pCD
wa
ps-l
•HPm
S-l
o
•aCD
•H>oS-l
I
OCD
•r->
OS-l
a.
o-HXCUtO
S-l
tnoXpS-l
oCD
rHOiG
04 <
tnG<
S-l
-H45En
UO4-1
ro
GOHP
GO•HPUCD
•nOS-l
o•HXa.tO
S-l
tno
pS-l
o
S-l
CD
Xp•HCD
G
S-l
O4H
o
a
wGrHo
18
1
1
w>
/Z-w1 1
r i
L J
^ r ~i
j
ii
i
\ \\i I
i i
q w
i
nt r
i_
ft > o>
11
1
1
*
sft
1
J
1
1
1
1
• -- -)i-\Q wft >
1
{
1 1 1
I 1
1 '
\ 1
^ &o won h
r 1 / 1 1
11
'
r i
L 1
(fu A
!
! :
1
1
1
1
•
o«ft
1 |«N ^^j _.
ft > in 1
1
1
1
wH
1
1
1
1
1
1
oo
1 1
1 1
1 1
1-3 |2 cf,-—
--
9 wOh Hft >
:
>
X
PROJ. VIEW
r
L 1_
3
ROJ. 7IEW
1a; h
.ft >«-»-
W-- r ~i
UTUC<\
0\ A 1
=1—1
V • J \ "\ \ *V.L-' \ 1
^T^\S7T
ill J 11
1'
e
drawings
opposite
show
o
views
of
a
component
either
First
Angle
thographic
Projection
OR
ird
Angle
Orthographic
ojection
.
Decide
which
method
of
ojection
has
been
used
d
then
add
the
missing
ew
in
the
space
provided.
Name
the
view
which
has
en
added
and
also
the
thod
of
projection
used
each
drawing.
xiw
wH<DrH
e
Xa)
c< low.
Solns.
p.
141
1 '
Addedview
1
1
1
_, 1
1
1
TJ1
1
3| 1
•
wft
<
O HOh Hft >
1
1
1
1
Xi •? GEh 4-1 -H
S-l
oxiEh
Uft a,
:•
) :
h a) a)
> xi e * HCD
X!Xw
19
The components below are drawn pictorially. For each componentsketch an orthographic drawing, in good proportion, using ThirdAngle Orthographic Projection. Sketch a front view in thedirection of F, a plan view and a right-hand side view showingall hidden detail. Use the 5 mm squared grid on page 6 7 withtracing paper to aid sketching if you wish. Solution on p. 142.
1 2S N/
I**- s\
f <%s 1<Z\
_^*—
-
K\ ,;—
f
/(\\ *
/ // */ / 1f
—r / /r
1/
f
L
—\\^
j/ L , t
/— f" J' / \ J i/'
. ,/ //
^m / \>»-. *.*/ /
—1~F- ^
"
r „,l
3. \ \ 4
s>l
v5""^ \5p— \ \
/\nJ5— S—\ \ \ Jr*\
::
sIti k
i \r I
s_. \ \\
J ]
- I \ \s^ ^/ / r *\pH \Sw >/ ^ KJ
-_M-<f
S— s
s
-
\\ \ \\ r— \F \
F
5. A partly sectioned assembly drawing in shown on page 48.Sketch, in good proportion, using 5 mm squared paper or thegrid on page 67, an EXTERNAL front view, side view and planview of the complete assembly using Third Angle OrthographicProjection. Solns. p. 141 and p. 142
20
SectioningDrawings of the outside of simple components are oftensufficient to convey all the information necessary to makethe component. More complicated components, however, mayrequire sectional views to clarify internal details.
A sectional view is obtainedwhen one imagines thecomponent to be cut througha chosen section plane - oftenon a centre line.
If the vee-block is cuton section plane C-C asshown above, the result-ing sectional viewprojected from the planreplaces the usual frontview of the outside ofthe block.
-E3End view Sectional Front View
looking on cutting plane C-C
Sectional views are drawn only when it is necessary to explainthe construction of a complex object or assembly. Some of tneexamples used in the next few pages have been chosen to illus-trate the rules of sectioning although in practice, as in thecase of the vee-block drawn above, a sectional view may nothave been necessary
The draughtsman has to decide how a component or assemblyshould be sectioned in order to provide the fullest possibleinformation. The recommendations of BS 308 enable him to dothis in a way tnat is understood by all engineers.
21
The rules of sectioning
1. A sectioned object is shownby lines drawn preferablyat 45'
the outline.Thin lines touch
Size of sectionedpart determines linespacing - preferablynot less than 4 mm.
2. If two adjacent parts
are sectioned, the
section lines are
drawn in opposite
directions
.
'/tiWky///,>§^
Lines are staggered
where the parts are
in contact.
3 . Where more than two
parts of an assembly
are to be sectioned,
the lines cannot all
be opposite.
Section lines are
closer together on
the third area —usually the smallest
The sectional view ofa symmetrical objectis obtained when thesection plane cutsthrough the obviouscentre line.Hatching may be omittedif the meaning is clearwithout it.
5. If an object is NOT
symmetrical the section
plane chosen should be
clearly stated, ^-j
7
V///X
cz
A
Secti onal Vi ew
Section A-A
22
Sectioning: exceptionsThere are a number of features and parts which are NOT normally-sectioned even though they may lie in the section plane. Agood way to accept these exceptions to the general rule is toimagine how complicated the drawing would look if they weresectioned. They are sectioned, however, when they lie ACROSSthe section plane. See section D-D. *
Sectioned shaftis more difficultto visualize thanit is whennot sectioned.
Shaft lyingi n thesecti on plane
Secti onalEnd View
BS 308 states that the following are NOT sectioned even if theylie in a given section plane:
ShaftsCotters
Keys Rivets RibsBolts Gear Wheels Nuts
PinsWebs
DowelsWashers
Some of these are illustrated in BS 308 by this diagram:
DShaft( Spindle) \
Section D-DCas ting only
Washer
23
Staggered section planes
ExamplesSection X-X
Section A-ARe-al igned
Each part of the sectionplane is swung to thevertical before projectingto the sectional End View.
By using this conventionthe draughtsman avoids usingtoo many auxiliary views.
A staggered section planeshould only be used whenthere is a resulting gainin clarity.
T
-*-r
IM1.
<t3>n,
!
+
B
Section B-BStaggered or offset
TB
Applications of thisconvention tospecific cases aregiven below.
Spoke
Solid
Section C-CRe vol ved
Section D-DRevol ved
Section E-ERevol ved
24
Errors in sectioning occur in each of the drawings below.Trace or re-draw a correct sectional view in each case.State the method of projection used where applicable.
Solns. p. 144
25
~.
A IExample
H
qj
-4.
ei • i
7
i
8
V
i
V
H
7
'A h
PT
-d
A
N
v,
~d
7"
A
WYZA
IMEZ
7
K G
From the lettered drawings choose the correctsectional view for each numbered drawing.Sketch the view in the space provided. Solns. p. 144s26
(XX)
\y
td
}r\
7
cffi
1 ..1
-LLL
rv
a 8
10
BK
M
f\
N
Q
From the lettered drawings choose the correctsectional view for each numbered drawing.Sketch the view in the space provided. Solns. p. 144
-e*
27
Sectioningexercises
j 'j
Tc
B-ii
6
Solns. p. 145
1. Complete the sectional front view looking on plane C-C,2. Complete the sectional end view looking on plane B-B.
F— End View
F^-
Section E-E
(Both holes
right through)
1. Draw an end view looking in the direction of arrows F-F.2. Complete the sectional front view looking on plane D-D.3. Complete the sectional end view looking on plane E-E.
28
r
n
c
-pP <
U
uQ)
XI-P-HH
0)
s(0
u
-P
0)
>•H
0)H>-P
op.
ft tn en fe
h-
—
1
1
—
'
1
m
C
onu(DDi(0
ft
G •
O mC <-\
Z •
O ftx\w
oX\-p
ow
en
in
Gr-\
o
0)
w
o
.£o
Hfte(d t3X 0)
0)
>o
(0
0)
-P
C•H
03
O•H-PO0)
•nOUft
IHO
-rH
-ppU
P.
0)
-p-Hw
0)
-H>-Pcou
atjiutu
h-
!
I-
-h o
-p0)
e(U
XIp
-pd)
ftpg (0
O -Pa w
xi-p
0)
0)
CC
U(D
C/)(D
29
Sectioning exercises
IT_1Lr
i .—\
n rn—
n
r-1 ^
-0-^—-i-
Solns. p. 146
30
Sectioning exercises
—i1—
r
— J L J_1
L
._..i
i
Solns . p. 146
1
1
1 IT
i II
i ii^1
i
'
O:
i
\
nn3
31
f\.
TJ(1)
c tn
3rH tP rn
fO c -HC -H
r* C-H O nP o •HO rH P<u C)03 +J
(l)
G •r-i
<H 0) nC u
«• o 0.(U 04
aw o Q
o g m C) Q 4-1
fO o nu o CU cu cu (1)p c c c C TI
CD rO (0 m <fl oM -G -I rH rH rH nO -P Pu 0. Pu &. +j
cu^m tn en tn d RXJ o C c c Co H H •H •H ,r;
p & -P p p -P C)
0) 0) P p p P •Hr* -H 3 ^ 3 3 XJCO > U U U U 3:
\uo
i~
b.^-^.
.if
a,
CO
crHOCO
s*-\3CU
CD
T3
CD0)
"oi-
X
0)c"c
+-»
OCD
(/)
h o
Its
T"CD
r<
t-^.-_"
f=------^^
i
—i_
._r
T
J"T\
*>- TCD
0)
o
T<
h oL
32
Information on Engineering DrawingsCommunication between the drawing office and the workshop is mainlyachieved via the engineering drawing - orthographic and/or pictorial.In order to reduce drafting time a number of standard parts ' aredrawn in a simplified form and many items of written information areabbreviated. In BS 308 Part 1:1972 recommendations have been made for
Conventional representation of commonly used parts & materials andAbbreviations of terms frequently used on drawings.
Before this engineers' "shorthand" can be used correctly it isnecessary to understand the terms used to describe features ofengineering components. This terminology is common to both drawingoffice and workshop and is often used when discussing the variousmanufacturing and machining processes used in engineering.
Terminology
Bush(bearing)
VeeBlock
HOUSING A component into which
a "male" mating part fits, sits
or is "housed".
BUSH A removable sleeve or liner.
Known alternatively as a simple
bearing. Fig. shows a flanged bush.
RecessedSurface
Base or Foot
CurvedSlot
Boss
BASE (or FOOT) That part upon
which the component rests
.
RECESSED SURFACE Ensures better
seating of the base. Minimises
machining of the base.
BOSS A cylindrical projection on
the surface of a component -
usually a casting or a forging.
CURVED SLOT An elongated hole
whose centre line lies on an arc.
Usually used on components whose
position has to be adjusted.
33
Terminology
Rib
Fillet:
FILLET A rounded portion, or
radius, suppressing a sharp
internal corner.
RIB A reinforcement positioned
to stiffen surfaces usually at
right angles to each other
KEY A small block or wedge
inserted between a shaft and
mating part (a hub) to prevent
circumferential movement.
KEYWAY A parallel sided groove
or slot cut in a bore or on a
shaft to 'house' a mating key.
TeeGroove(slot)
Flat
TEE SLOT Machined to "house"mating fixing bolts and preventthem turning
FLAT A surface
machined
parallel to
the shaft axis.
Usually used to
locate and/or lock a mating
component.
HEXAGONHEADBOLT
4=4=^1
HEXAGONHEADSCREW
TAPER DOWELPIN PIN
Notethreadlengths
yj
STUD
f4=* n
COTTERor SPLIT
PIN
®
A cylindricalA pin pin used toused locate matingfor parts,fastening
(3D
Used forfastening
34
TerminologyMany different types of holes may be seen on engineering drawings.
The more common ones, associated with drilling, reaming and/or
tapping, are shown below in Fig.l. The name and where appropriate
the application of each is indicated.
Figures 2 and 3 indicate the different terms which may be seen on
drawings that are associated particularly with lathe work.
1
1
2 3 4 5
//
1
17/
1
y//i
1
/// i
1
//7 7///
s\
V W i
/
w>Fig.l
1. A drilled hole or, if greater accuracy is required, a reamed hole,2. A 'blind' tapped hole i.e., a threaded hole which passes only part
way through the plate.3. A countersunk hole. Provides a mating seat for a countersunk
headed screw or rivet.4. A oounterbore . Provides a 'housing' for the heads of capscrews
,
bolts, etc.5. A spotfaae . A much shallower circular recess. Provides a
machined seat for nuts, bolt heads, washers, etc.
StraightKnurling Shoulder Undercut
(or groove)
Chamfer KeywayF i g . 2
Taper Domed or SphericalEnd
StandardCentre
This is a machining symbol. (It indicatesthat a surface is to be machined, without
defining either the surface texturegrade or process to be used)
.
Radius Collar orFlange
Splines Fig. 3
35
AbbreviationsMany terms and expressions in engineering need to be written ondrawings so frequently as to justify the use of abbreviations whichhelp to reduce drafting time and costs. Many of these abbreviationshave been standardized as can be seen in BS 308: 1972: section 11.
A selection of the more commonly used ones are stated and clarifiedin the following tables.
ABBREVIATION MEANING SKETCH/NOTES
A/C
A/F
HEX HD
Across corners
Across flats
Hexagon headHEX HO
ASSY Assembly See page 96
"W~ 25 CRS *4sCRS Centres—
H
£ or CL Centre line +CHAM Chamfered CHAM ^CH HD Cheese head I U I CH HD
^ ^ SCREW]SCSK Countersunk CSK
SCREW ^5 -CSK
C'BORE Counterbore C'BORE
CYL Cylinder or cylindrical
DIA
t
R
Diameter (in a note)
Diameter(preceding a dimension)
Radius (preceding adimension, capital only)
DRG Drawing
FIG. Figure
LH Left hand
LG Long
MATL Material
NO. Number
36
ABBREVIATION
L
PATT NO.
PCD
,/D
0/ D
RH
RD HD
SCR
SPEC
S'FACE
SO
STD
U CUT
M/CD
mm
NTS
RPM
SWG
TPI
MEANING
Pattern number
Pitch circle diameter
Inside diameter
SKETCH/NOTES
Outside diameter
Right hand
Round head
Screwed
Specification
Spotface
Square (in a note)
4 HOLES& 3 e<?u/-
s PACED ON16 PCD
/^r*\ RD HDL * SCREW
S ' FACE
Square(preceding a dimension)
Standard
Undercut
Machined
Millimetre
Not to scale
Revolutions per minute
Standard wire gauge
Threads per inch
See page 4 forconventionalrepresentation
SI symbol: rev/min
* Abbreviations commonly used in practice but not listed in
BS 308: Part 1: 1972
Notes(1) Abbreviations are the same in the singular and plural.(2) Capital letters are shown above, lower case letters may
be used where appropriate. For other abbreviations upperor lower case letters should be used as specified byother relevant British Standards.
(3) Full stops are not used except when the abbreviation makesa word which may be confusing, e.g. NO. for 'number'.
37
Conventional Representationof Common Features: Screw threadsThere are many components commonly used in engineering which are com-plicated to draw in full. In order to save drawing time, these partsare shown in a simplified, conventional form. Some of the morefrequently drawn features are shown in this section.
Subject - STUD
i;t
Convention
The screw thread is represented bytwo parallel lines. The distance be-tween these lines is approximatelyequal to the depth of thread.
Note The inside line is THIN andthe circle is broken \
4 b».
External Screw Thread(Stud, bolt, set-screw, etc.) Front view Side view
TAPPED
"BLIND HOLE"
The shape of the hole formed bythe tapping size drill is drawnin heavy lines.
Note Section linescross thethread
The outsideline is THINand the circleis broken
V^«
/H
Internal Screw Thread Front view Side view
STUD INSIDETAPPED HOLE
The external thread is super-imposed over the internal thread.
Note Section lines are not drawnacross the external thread.
Screw Threads(Assembly) Front view Side view
38
Conventional representation: SpringsA spring is designated by stating the diameter of the wire, thecoil diameter (inside or outside), the form of the spring ends,the total number of coils and its free length - See BS 1726.
In the case of the compression spring, the pitch of the coilsmay be deduced from its free length and number of coils.
Subject Convention
t_I 9 ?I *I I i * i I I
COMPRESSION SPRING
Note
The construction onthe right shows howthe convention maybe drawn from thespring details.Extreme accuracy isnot essential; forexample, a radiusgauge may be usedfor the small radii.
Diameterof wire
This method is onlyused for quick dia-grammatic sketches
TENSION SPRING
Note
The construction onthe right shows onceagain how the pitchof the coils may beused to set out theconvention. Diagrammatic
representation
39
Conventional representation: Shaft DetailsIt is frequently necessary to fix a component to one end of a shaftor spindle so that a torque may be transmitted. Examples below are:
(1) Square on shaft(2) Serrated shaft(3) Splined shaft
Machine handles, valve wheel spindle.Typical example - steering wheel to column on car,Drive shaft on machine or vehicle when slidingalso has to take place, e.g. in a gear box.
Subject Convention
See page 96 forsquare on valvespindle.
SQUARE ON theend of a longSHAFT
^Side view
The enlarged sketchshows how the serrationsmay be constructed
SERRATED SHAFT
NoteThirty-six serrations areshown for convenience only
Vi ew onserrated end
NoteOnly a few teethneed be shown
Splines are usuallydrawn with parallelsides as emphasizedin the enlarged sketch
SPLINED SHAFT
NoteTwelve splines are shownfor convenience only
View onsplined end
Refer to section onterminology - page 35
40
Conventional representation: KnurlingKnurling is a common method of providing a roughened surface to aidtightening or slackening of a screw by hand. This is formed bypressing special rollers against the surface of the component whilstit revolves in a lathe. The commonly used diamond and straight knurlsare shown below.
Subject Convention
I
s*m*wm**&j
I'-'.:':"
i>>
DIAMOND KNURL ona machine screw head
JT'
*'',
i
t *\
ft
v /
STRAIGHT KNURL ona circuit terminal
Bearings
Notice how it ichless drawing isnecessary in orderto represent anyball or rollerbearing in aconventionalmanner
.
Cross-section of adouble rowself-aligningball bearing.
E332
fl
mSee assemblydrawing on page 103
BALL
41
Conventions I representat ion :
Long ComponentsThere are occasions when bars, shafts, spindles or tubes may betoo long to be drawn to a reasonable scale. In such cases theelevation may be interrupted as shown below.
Subject Convention
RECTANGULAR BAR
CIRCULAR SHAFT OR SPINDLE
«HOLLOW SHAFT OR TUBE
MULTIPLE HOLES
When a large number ofholes of equal diameterare equi-spaced arounda diameter or in line,only one hole need bedrawn in full with theremainder marked witha short centre-lineas shown in thedrawings on the right.
Remember that this circleis called the pitch circlediameter or PCD
Holes on a circular pitch
0- -0-
-p p—0~"~^ 0"
Holes on a linear pitch
42
Conventional representation: Gears (1)Before gears can be drawn a great deal of background knowledgeabout their nomenclature and construction must be acquired.The following drawings of gears are presented as conventions only.
Subject - GEARS Convent-ion
*'!.»»»!
Note
Side viewof gearwheel isinsection.
SPUR GEAR Single spur gear
Note
A pinion is so calledwhen it has a relativelysmall number of teethcompared with itsmating gear wheel.
Si devi ew
jL
XS
Pinion
In mesh with a. pinion
WORM AND WHEEL
Wheel
Wormandwheelinmesh.
Worm
43
Conventional representation: Gears (2)A good example of how a complex component may be drawn relativelysimply is the bevel gear. The assembly shown below is of a pair ofgears of equal size, the direction of motion being changed throughan angle of 90°. In this arrangement, the gears are often referredto as mitre wheels
.
The gears may be of differing sizes, of course, and the anglebetween the shafts may be other than 90°. In this latter case, theside view of the gear assembly would have to show one gear as anellipse
.
Sub j eat Convention
BEVEL WHEEL
Assemblyof a pairof bevelgears setat 90° toeach other.
Note BS 308: Part I: 1972 deals with a number of features whichrequire to be shown less frequently than those illustratedin this section. They are:
Thread inserts; repeated parts; semi-elliptic springs;conical springs; torsion springs and a rack and pinion.
Summary In all cases, conventional representation should only beused when it saves drawing time. Where it is not con-sidered adequate, a more detailed view should be shown.
44
cu•
ooSh
Oi" U X)rH 0) 13 ShQ -p CU CU cuCU (0 4-> 3 CT> 4-1
tT> M 4-1 Cn c x: G curd M (0 G X! fO CO p X!0j <U X! O CU -H 3 O 3g
CO CO Eh £ fe PQ u Eh
o
g
>HC7> 13
CU O = 13CU
uM 13 Sh >i 4-> CU cu(0 G (0 (0 O G 4-1 <+H
•H CU iH S fr H 4-1 gto rH rH rH >i •H H aj toG 03 O O CD & ax; x:
•H >H= a u « CO CO CO u
P3 grH «o <co
CD
0)
4-> >3 oO O cu 13 13
G CU
cu
u
0) o G CO r-t a, Q) 4->
13 m CO •H QjrH o X!G Sh rH o ffl id Cu HD O fn PQ = ^K CO «
XG3to u 13Sh CU CU< CU
4->
13rH SH
13tO
G 0) -p 3 cu CD cu cu3 <H O O a. H M rHO O rH X! (0 O X! OU ffi CO CO Eh PQ Eh M
G
— OsJ OO ^f LT) C£)
O
>0)
hie
conventic
item
shown,
mn
the
letter.
CO
i
i |%^•"N
-~s
\
^
&L V2
# i1
1
V N-
c UH-O yj i^Jr
1-r1
1X^j^
E•> rtf G>i CU O tO
to CO ^ *co °- e'-
en o <"•
i^^ u u u
k J——
•
CD+-»
the
az
term
fc
e
answe
g
numbe
v „./
v 1 1 . [ „ ,
\S
S
Y////,4-
,
from
ering in
th
pondin
\\
Y/'s ^'/. 1
CD
V A1 1-
1 Tv
IT 1
(/)+j oi +j co
O G M <U
rH0,
|2CU -H CU Sh 6H tJidl M0) G G Owiiho
(0 __ o-- O"(N ro ^ ^ in
r
45
CO to
"tf -—
.
CU curH tn c
c o •Htn3
CU M -H -H to i-q tO
tn Q CU T3 01
p a) aCn ffi S-l
CU 0)o
Cu CU o <u •H P M-l S-l pg ai g 5 -C p x:
C fO S-l -H (0 tn to c tnO •H OjT3 rH •H si cu HQ ~ Q PS u u r-3
co
CO-H CU
P rH3 uH S-l
oto O
CO
rH•H S-l
U CU
pT3CU
5 CO g £ CU 50) tn O CU 0) o g CUS-l a S-l u CO P fO S-lu o O (0 CO •H -H CJ
3
CO J < En < a. q CO
« c<
CDrH(0 *0
r-l
o-Hpmu•H
01 •H •a (0 m3 s-l CU T5 •H c•H cy p c u 5"a si fO m CU tO(0 a. p p a S-l
Ph CO CO CO CO a
"cu
CU -a p T3o CU S-l o CUc rH a) a S-l
<£ CO (0 X! p 13 0)01 01 r-l g cu to CU M-lP (0 01 g u gS-i (0 CU CO tO c (0 fOU rH rH CO •H -H rH si<; fe u < Q — Cm u
— Csl CO ^J LO OD
CO Pc o
a)
U CU CU S-i
•^— O ,£ ,£ CU
+-» O -P • -P +J
CDC P
>CD
VU 4-1 U Ih UJ
£ O -H g H-P P 3
X3 (0 rH T3 CDua)
CO- U -rH O C
i_ >ifl > u si LO-Q
(0 CU CU
M S-i }-i uu si xt Q) a)
<
_Q OS O jQ S X!
CD•H (0 01 g
0) £ C 3X! 5 C (0 cP to
u oHl_ S-i 0) tn CM p
g O 01 Si cO IH -rl +J -rl
CO 10
•H >H ^a 24- H T3 > CO p4 « Q o < Q <dm a) en c c 0> CO \ u E^ i-q a PS M u Kg C -H O S-l < < CO CO u « r-q Q Q a, u
4-i » tO -H Oi ai si
0)P C S P co rH SiO O M 0) a. <
£<U rH r-l Q) U g
0) 3 O Cco m m h u
to
w o— (NJ CO <=* LO CO r^ GO cn o — CNJ
2 ~"~™"
46
Test for conventional representations
Select, from the array, the names of the items for which thefollowing diagrams are conventional representations.Insert in the answer column the corresponding number and letter,
Conventional reps
Example
7
8
10
eaE EL
ET;K^-l;
£
Answer
4C
^ri1^
Solutions on page 148
ARRAY
WormWheel
Tensionspring
B
ShoulderKnurling
ExternalScrewThread
A Resistor
Square onShaft
7
8
MachineAll Over
RoundShaft
SplinedShaft
BevelGear
SpurGear
Worm
Form ofMachiningSymbol
SerratedShaft
Weld-symbol
InternalScrewThread
Break inRectangularShaft
Break inTubularShaft
Compressionspring
DiamondKnurling
Collar
Counterbore
Bearing
StraightKnurling
47
48
Pictorial Drawing
A component may be represented graphically in various ways.
An Orthographic Drawing, for example, requiring a minimum of
two views to fully communicate the size and shape of a com-
ponent, is used in engineering mainly to convey manufacturinginstructions from the designer to the craftsman. On the
other hand a well executed Pictorial Drawing, adequately
representing all but the most complicated components usingone view only, is used mainly as an aid to visualization of
the shape of a component rather than for communicating
detailed instructions for manufacture.
A pictorial drawing, generally, is a quickly produced,
approximately scaled representation of a component - a
"picture" rather than an accurately scaled line drawing.
There are many different types of pictorial representa-
tion. Two of the most commonly used ones are known as
Isometric Drawing and Oblique Drawing both of which are dis-
cussed in detail in this section.
Note! There is a method of isometric representation, more
precise than the one discussed here, known as Isometric
Projection. This method is much more time-consuming, and
therefore less commonly used, because all sizes for the
drawings have to be transferred from a specially constructed
isometric scale. It is the approximate method of represent-
ation, Isometric Drawing, which is used in this section.
49
Pictorial Drawing: Isometric
\^ —
»
|3 SC1 —P
in
— -
1
7 t—
s P
Note:All recedinglines aredrawnat 300.All linesare drawnfull-size,
Plan
SV/^Arrow L - Looking from LEFTArrow D - Looking DOWN. Isometric drawing
When making an isometric drawing from orthographic views of acomponent use an isometric grid at first, as shown above.Follow this simple procedure:
1. Choose the direction from which the component is to be viewedso that the resulting isometric drawing will show the mostdetail of the component. Compare the isometric drawings below.
Example A is drawn lookingfrom the left and down, andis a good representation ofthe component
.
Example C shows the samedetail but is drawn froma different direction.
All of the other drawingsfail to; show some of thedetails of the component.
Draw the outlineof a box into whichthe component willjust fit.
3. Use distances fromthe orthographic viewsto set out pointswithin this box, e.g. P.
Heavy-in thelines whenthe outlineis completed.
50
Isometric drawing: inclined edges-hdU square
I sometri c
When components have sloping surfaces, the edge distances inthe orthographic views are transferred to the isometric boxas shown by the dimension D in the above example.
-• —
i
^m- 2iiOlJARtS
1oin < /(Nl \ /
1E
1
11
A|
i
E E
I \ k/ \
>S,
IIy
v N T
4t \-kr
( 1 > .
The component shown above has surfaces sloping in two directionsresulting in inclined edges, for example, IE. In this case,pairs of distances from the orthographic views are used to plotpoints within the isometric box. Distances used in this, way forlocation purposes are called ORDINATES
.
Note:- The angles of inclination in the orthographic views arenever transferred to the isometric box. When I and Ehave been located, they are joined to produce thecorrect slope in the isometric drawing.
51
Isometr ic drawing exerc1
:ises, |
j
,
s
!
ll
'!
i
ji
j i
j d
F
1
P>5
i
i 1 1
1 2
I, I
i
_^J
| i
\V
J
\
-- tr
!
- "T
1
! k1
11 — i 1 _——
—i
—
__li^!^
rr,/ ipm 1,
i
1
3 ^ ' i
i ! 1 1
I
i 4
i
T<\ 11_
\M /r">k^
|
%/U_i
j
j
1
—
V \ !
—:
V —\
j
1 — v5
1
'
!
1 ' 6
Make an isometric drawing of each component on tracing paperplaced over the isometric grid on page 60. Sizes for the ^__-,^ x^isometric drawing are obtained by counting the relevant -£~~-\- 4rt/^number of squares in the orthographic views . * J v^xSolutions are given on p. 149.
52
1 2,
| U : i
l
1
J
1
i —V>V|
1"
' J
1|
'i
l 1i i 1
3 j_ |
4I 1
i
I
\-U^1^-» / —— iI
/—
qi
r—
—
iy / \ /—A / ^/ \\ / \U .J, / \n I
[ 1
~11 1 ! i n
— i
!
-i
—
j—|
5 6L_ . 1 I
/f\
\//
i
—
1 _,
""
'
' 1'
'
i
i nMake an isometric drawing of each component shown aboveusing isometric paper. If the isometric grid sizediffers from that of the squared grid, transfer EQUALnumbers of divisions from the orthoqraphic views to the _*iff^ -TO.1 sometric drawing Solut ic ns are give>n <an P ag e 14 9. ^ ^T
53
Make an isometric drawing of each component shown aboveusing tracing paper with the isometric grid or usingisometric paper. Solutions are given on page 150.Always start with a faintly drawn "isometric box" whichprovides three faces from which to set out ordinates.
54
Isometric drawing: construction of ellipses (1)
B-4s*r
I ^\H
J\V
s
y
A shape which is circular onan orthographic view is shownas an ellipse on an isometricdrawing.The following constructionsillustrate 3 different methodsof producing the ellipticalshape
.
Lines, called ordinates, aredrawn on the circle in theorthographic view as shown.Corresponding ordinates aredrawn on the isometric draw-ing with the same spacing S.The height H of each ordinateon the true circle is trans-ferred to the correspondingordinate on the isometricdrawing to form the outlineof the ellipse. These pointsare joined with a neatfreehand curve
.
The more ordinates, the moreaccurate the ellipse.As the circle and ellipse aresymmetrical, the ordinatesneed only be constructed ina quarter-circle.
2. Diagonals are drawn on theorthographic side view asshown on the left.
Horizontal and verticalordinates are drawn to touchthe points where the circlecrosses the diagonals.
The ordinates are transferredto the isometric box as shownand the resulting points ofintersection P are joinedwith a neat freehand curve.
As in method 1, only aquarter-circle need be drawnto obtain the four pointsrequired
.
This method is useful for quickfreehand sketching but is notas accurate as method 1.
55
Isometric drawing: construction of ellipses (2)
In this method, the ellipse isconstructed on the isometricbox with compasses and severalconstruction lines are neededto find the centres of arcs.
Centre lines and a diagonalare drawn across the face ofthe isometric box as shown.
FRUSTUM(a "beheaded"cone orpyramid)
Lines are drawn from thebottom corner of the box Bto the mid-points of theopposite sides.
The intersections C providethe centres for both minorarcs of the ellipse.
The corners of the box Bare the centres for themajor arcs of the ellipse.
If the centres have beenconstructed accurately,the arcs drawn withcompasses will blendperfectly.
The ellipses of the conicfrustum opposite havebeen drawn using method 3,i.e. with compasses.
Make further isometricdrawings of the frustumusing methods 1 and 2 toplot the ellipses
.
Compare the shapes andsizes of the ellipses ob-tained by the 3 methods
.
In general :
Method 1 gives the bestshaped ellipse and is veryuseful when there is onlypart of a circle to drawon the face of theisometric box.However, methods 2 and 3are more rapid than 1.
56
Isometric drawing examplesEXAMPLE 1
An isometric drawingof the Vee-block shownon page 21
The ellipseshave beenconstructedusing method 3,i.e. with compasses.
The Vee and thesloping facehave been con-structed byusing pairs ofordinates asshown onpage 51
The smallradius at theintersectionof surfaces Imay be drawn:
(a) using ordinatesor
(b) with a radiusgauge if thecurve is small.
EXAMPLE 2 The incompleteisometric drawing ofthe component belowis viewed from theright and
>v looking down
.
Use the procedure suggested on page 52 to complete theisometric drawing in the space provided or make a completeisometric drawing on isometric grid paper. For furtherexamples use the drawings provided for sectioning exerciseson pages 28-31 (solutions are not given)
.
57
1
Isometric drawing exercises
i
i
+)
-1-1
IN
1-
—^i
i
m*e-
Make an isometric drawing of each component shown above.Construct the ellipses by using one of the methods —
•
illustrated on pages 55 and 56. L^_~TIn each case view the components in the direction ^~~-J
indicated by the arrow and looking down.Solns. p. 151.
58
I
]! | v v v v v V 7\/ ./
A7A7A/A7/7/A ./
aa/a?aaaaa~//aaaaaaaaaaaaa77a7aaaaaaaaaaaa//
—r-
• v v v V V v V V k^
7AAA7AA777/A/A7A7A7A77A7/77AA7AA777/777/"AAA77A7/A7777A/VAA7A7/7/77
1 l
' [/—
!/! L
j 1i
1 / 1^^
i
1
j
/j j
r
j
rnvvwxaaaaa/7AA7/7rAA/\AA77777AAAA\7^7A777/AA7/AAAAAA/ZAAAAA/7
AAAAAA'AZAZaz/A/A/AAAAAyy7\7 7 7 z 7 /y
AAAAAAAAAAA77/7/A777/A7/7AAA777/\/A7/777777/7/7/7/7/777/AAAAAAAAAAA7/AA7/A77A/VVA7V777777777AA7A/A777/V77
J
]
Nj
A A i
) I'
! Ji"1
\ A ( /i \ i /
i
i
i A i
: !,
:'
1| \AAAAAAAAAAAAAAAAAAz\AAAAAAAAAAAAAAAAAAz\AAAAAAAAA777777A7AA77A7AZ7/7/77777/7/7A/7A
A-Ai
i
! i AAAAAAAAA! 1 !
1
1 1 1
AA7AZ7A7A7/VA/AAAAAAAAAAZA/ZAAZZZZZ/ZZAAAAAAAAAvV\AAAAAA/AAAAAAAAAnAAAAAAZVVAAAAAAAAA
. ;
;
! j 1!
^-t-^-. -A' -L
! 1
l
\
1
i ! ;! i i
I
i
i
i ZAZZZAAZZAAAzVWXAAAAAAAAAAAAAAA/VNAAAAAAAAAAAAAAAAA/777AA7777AA7AA/VVVVVVVVV
Ii
^^
i/\^^V • £ zZZZZAZAAZZZZZZZZ
77AAAA77AAAzAZZZZZZAAZZAZAAAAAAAAAAA7AAAA/7/7/AAAAA/WV\
.t i i
i
L ) i
;
ii
\^ W*Y ^1
, ^^s. 7AA/V7A/7AAAAAAAAAAA/V1 .1 ...i_
-j_ 1
!!
\/7/7/777/V77777:7
j | \ VVV\ 777 777 \i AAAA/Z/ZAAA
zZZAAZZZZZZAZZZAAAAAAAAA"zAAzAAAZZZZAZAAAAZZZZAZZAzAzAZZAZZZZzZAZAAAAzZZAZAzZ
1
A/VYA 7AA 7 VAAAAAZ7AAA\AAA7/AAAAA7VVAAA7VAA \
7A-AAAA~AAAVVVVVVVVV^A ;AAAAA7~A7"
ii
i
i
! y 1
_
r-"1ti-
i \
~2\, llaL 1. i
!
1:
^ 1' zAAZZAAZAZZzAAAAAAAAAAzAAAzZzZzZAAZAAAAAAAAAzAAAZZZZAZZZAAAAAAAAAAVVVVVVVVV
i VWAAA 7. A7^\i J— __
~l
rni
—
A AAAAAA/7 7 V7A 7AAAAAAA//AAAAZAZA7~A77AVAAAAA7AZWWVVAAA/
"p! /H
_Jrh^i \> )
•^^^
1i J L .. VWV'WVW^ i
t AAAAAAAAAA i 1 77AAA7A77A'A7/ i
i \AAAAAAAA/
sometric
reehand
drawing
ach
drawing
on
this
age
consists
of
two
iews
of
a
component
n
First
Angle
ortho-
raphic
projection.
rom
these
views,
sketch
n
isometric
view
of
ach
component
in
the
pace
provided.
idden
detail
need
not
e
shown
.
n
example
is
given
elow
Solns.
p.
152.
1i\
<\I
\/ 7
-M w Q4 > rH tn U-i <fl 0) 03 K £) <d X!
59
ISOMETRIC GRID - to be used for isometric sketches.
The above grid is composed of lines drawn at an angle of 30° whichintersect with vertical lines . The equilateral triangles thusformed have lengths of side equal to 5 mm.Use the grid with tracing paper or detail paper.
60
Pictorial Drawing: Oblique
L y^
vL) N
_
1
'
Arrow LArrow D
Looking from LEFTLooking DOWN.
An oblique pictorial drawingpresents the component withone of its faces as a true shape.This true shape is drawn on tnefront face of the oblique boxas shown below.
The longest face is usually-drawn on the front of the obliquebox with receding lines betweenh and \ full size.
Compare tnese oblique drawings.Drawings 7, 8 and 9 representthe shape of the componentbetter than the others.
Note:- TL= TRUE LENGTH
45'\!_TL
S=£K3
H5
TL'/2TU f (D«fNL_TL
HK
30°
TL
r^ TL
©
61
Oblique drawing: methods of constructionThere are many variations in angle, length of receding lines,and directions from which a component may be viewed in orderto produce an oblique drawing, as can be seen by the exampleson the previous page. Different oblique drawings of the samecomponent may each provide the detail required.
In general: 1. The receding lines may be drawn at any angleto the horizontal but an angle of 30°, 45°or 60° is preferred as lines can be drawnwith set-squares.
2
.
Receding lines may be any proportion of theirtrue length. A good pictorial representationis obtained if lengths from \ to \ x actuallength is used.
\^ Note: All vertical and horizontal lines are drawn true length.
V
r__
11-
i
^i
ri ,
4 SCI
' I
/oTL
This oblique drawing is ofthe component viewed fromthe left (arrow L) andlooking down (arrow D)
.
Receding lines are drawnat 45° and \ true lengthusing tee and set-squares
.
When making freehand oblique sketches it is convenient to use5 mm squared paper and to draw the receding lines at 45° and
7 x true length. As the diagonal of a square is 1*4 x sideof the square, then each diagonal can be used to representtwo squares on the orthographic views as shown below.
N XLConstruct the shape with faintlines. Complete by lining inthe outline heavily.
An alternative view
62
Oblique drawing: inclined edges
D 6 SQ £>Q
j
l
D
j' 'I
/ \'
/ \/ \
1
1
L
^<
1
representedby
3 diagonals
When components have sloping surfaces, the edge distances inthe orthographic views are transferred to the oblique box asshown by the dimension D in the above example.
1
-»]2S5QI*-
i
, \
2 \ >1—
:;
SQ \ s?
t 1
H ii
1
i
!
>^i
R^'
i
nPi
\i^*, E
\ \\ \>
f\
y/ \£f-
\r- J—
1 diag
The component shown above has surfaces sloping in two directionsresulting in inclined edges, for example IE. Pairs of ordinatesfrom the orthographic views are used to plot points within theoblique box, for example point E.
Note: The angles of inclination in the orthographic views arenever transferred to the oblique box. When I and Ehave been located they are joined to produce the correctslope in the oblique drawing.
63
Nlethods of
1III!
1 1 1 :
constructing "oblique circles"
! 1
i
l l
j^T1 1
1
|f 1
I
A shape which is circular in an
z \\
i
\
orrnograpnic view may be snownas a circle on the obliquedrawing if the component isviewed as shown in example 1.L_
^ //
v ^ The end of the cylinder is a1 true circle which may be drawn
with compasses.
The linfis nf t.hp "nhl irmp lir>v"
have been drawn to show thesize of a box into which thecylinder will just fit.
If the circular face is receding,e.g. at 45°, it will appearelliptical and will have to beplotted. Examples 2, 3 and 4
show ways of constructingTL ,-, -r, ellipses.
T yf When making an oblique drawing_ «« v 45 view the component, if possible,
in a direction which will allowcircular and part-circular facesto be drawn with compasses.
"X\*
1
Tl
1
,
A S 1—
1
The oblique ellipses on the leftare plotted by using a methodsimilar to that used forplotting an isometric ellipse.
The ordinates, however, haveto be proportionately spacedalong the receding lines.
'* =-—=qs,
/ Ci \l. ^
L .
V / l
^ - ^.^y
\lxSk
i
In the case of the freehand\ "
oblique drawing shown in—jr-i example 2, the spacing S is
J" *
1
"^.
^0*7 x s i.e. trie length of
1 N l\1 diagonal represents 2
squares on the orthographicview
.
V ^^ J
\ s^ \v 1
i
s
— sJ \ As in the construction for
>u an isometric ellipse, the
/..t. T L \ X>ordinates need only be
45 >L,ri_
constructed in aquarter-circle
.
2
64
Methods of constructing "oblique ellipses'
The method for constructing anoblique ellipse shown oppositeis only used when the recedinglines are drawn at0*7 x true length,mainly for quickly drawnfreehand sketches.
The larger scale drawing belowshows how the length CD isobtained. The length ^CD canbe judged by eye.
Note: Theactual lengthof CD istransferredto the obliquebox.
Represents8SQ/
TL
\/rJL
The ellipses of the conicfrustum in example 4 havebeen drawn freehand usingthe ordinate method.
The ordinates used for plottingthe points on the ellipse havebeen measured along horizontallines spaced proportionately.
Ordinates are true lengths.
Spacings are true length,
The ordinate method is alsouseful when there is onlypart of a circle to be drawnin the oblique box.
Exercises: Make obliquedrawings of the componentsshown on page 58. Solutionsare not given.
65
Oblique drawing examplesEXAMPLE 1 Two oblique drawings of the Vee-block shown ortho-graphically on page 21. Compare these with the isometricdrawing of the same component on page 57.
TL
Fig lb TL - TrueLength
Ordinates are spaced to suit the size of ellipse oeing plotted andthe accuracy required. More ordinates will make the drawing moreaccurate but it will take longer to draw. Note that ordinates setoff from receding lines are spaced at proportionate distances alongthese lines.
The length, width and height dimensionsof Fig. lb have been rounded off tomultiples of 5 mm so that the squaresof the 5 mm grid may be used to fulladvantage, particularly for lines
EXAMPLE 2 receding at 45° and 0-7 true length.
This viewshows themaximumuse ofcompasses
.
Fig. la has been drawnusing the actual dimensionsof the vee-block. Recedinglines at 45° and \ TL.
zz ~
N-._ i _L.- i^z^E"
l"\ . r
~t -^Sv> — -p-
^t X'V^^f4! — _ ,
—
-T
Complete theoblique viewon the right. -»-
This view in-volves the mostconstruction
.
For further exercises: Make oblique drawings of thecomponents shown on pages 52, 53 and 54, using tracing paper and the5 mm squared grid on page 67. Draw receding lines at 45° and 0*7 x TL,
Solutions are given on pages 153 and 154.
66
—
—
"
~
—
SQUARED GRID - to be used for oblique pictorial drawing and ortho-graphic drawing and sketches.
The above grid is composed of lines drawn to form squares which havelengths of side equal to 5 mm.Use the grid with tracing paper or detail paper.
67
Dimensioning
Any drawing from which a component is to be made must conveyinformation from the designer to the craftsmen in three ways.It must
Describe the shape of the component by using orthographicand, sometimes > pictorial views
Give sizes by dimensioning
Provide information about the workshop processes involved
Draughtsmen and designers should understand not only methodsof projection, but also dimensioning methods and processes requiredfor the manufacture of an engineering component, so that correctinstructions may be issued to the craftsman. Most of the problemsof dimensioning may be solved by the application of a few simplerules. Some may be simply stated, e.g. 1, 2 and 3 below whilst otherscan be more easily explained by reference to diagrams (next page)
.
(1) Dimensions should be placed on drawings so that they may beeasily "read". They must be clearly printed and placed outsidethe outline of the most appropriate view wherever possible.
(2) The drawing must include the minimum number of dimensions necessaryto manufacture the component and a dimension should not be statedmore than once unless it aids communication.
(3) It should not be necessary for dimensions to be deduced by thecraftsman.
The way a draughtsman dimensions a component or assembly is influencedalso by the need to consider the "type" of dimension he will use.
These may be classed broadly as
(i) SIZE DIMENSIONS - used to describe heights, widths, thicknesses,diameters, radii, etc., and, where appropriate, the shapes of
the component.
(ii) LOCATION DIMENSIONS - necessary to locate the various featuresof a component relative to each other, to a reference surface or
to a centre line, etc.
(iii) MATING DIMENSIONS - applied to parts that fit together. This
implies a certain degree of accuracy, and in the case of shaftswhich fit into holes, the application of limits and fits willmost likely be necessary. For details of limits and fits referto pages 84-90.
All the examples in this section are intended to explain the rules ofdimensioning which are set out as recommendations in BS 308: Part 2:1972,
It must be stressed, however, that the dimensioning of any componentdepends on the draughtsman's interpretation of the recommendations.A component may be dimensioned in a number of different ways yet stillbe dimensioned correctly.
68
Dimensioning
A number of the basic rules of dimensioning can be explained byreference to _ the above drawing of a thin plate.The sides marked A and B are known as DATUM faces. They are usedas reference edges from which dimensions are drawn. Datums mayor may not be machined. Even if they are not machined it is goodpractice to choose reference edges in order to simplify thelayout of dimensions.
Points to note:
(1) DIMENSION LINES - thin full lines placed outside the componentwherever possible and spaced well away from the outlines. Thelonger dimension lines are placed outside shorter ones.PROJECTION LINES - thin full lines which extend from the viewto provide a boundary for the dimension line. Drawn at 90° tothe outline.
(3) ARROWHEADS - drawn with sharp strokes which must touch theextension lines.A LEADER LINE is a thin full line which is drawn from a notea dimension or, in this case, a "balloon" and terminates in anarrowhead or a dot.Relatively small gap.Relatively short tail.Crossing extension lines - usually a break to ensure clarity.Dimension placed above the dimension line. This is preferredto the alternative method of placing the dimension in a gap inthe line. Avoid using both methods on the same drawing ifpossible.Dimension placed so that it may be read from the bottom or
(10) Dimension placed so that it may be read from the right handside of the drawing sheet.
Study this information before turning to the next page.
(2)
(4)
(5)
(6)
(7)
(8)
(9)
69
CU
0) .-1
45 X)+J -H
• a; w g>1i-H
u (u to ?rd TS O P
•P H-ri amO 43 to tid) p sh
—>H rH 3 <U
M HO>«O 3 0) <u
Od) d) 13
S G O 45 CD
O •H rd £H 45 rH d)
(1) P ft CD O43
0) 0) 3 0)
(U >H 43 tJi U5-1 cd -HO)3 n3 m mtn 01H CD
•H O0IDMl« fi O 45
•H 45 -P gCD i-H CO O45 4-1 Sh
P C T3 O MHO G
C -H rd <D ^ •
o U CO G U•H d) C CO -H O CO
CO n CD d) rH £ d)
c g g $5 P OCI) <D •H -H 3 O rd
a g id >-h o -P m•H <u
Q & 1 1
0Q.
to
co•HCO
d)
g-H
mo
ud)
43g3
d)
Prd
rHft
CD
45P
ft
d)
d)
W
m
f5 co CO
P -H d)
CO CO tnrd <5 TJd)
i-H
CD
gd)
-H C)
(1) T3 P45P o cu
p O0) s5
-rH TJ d>
d) UP T3 d)
m d) M-l
i(U
15
d)
-p45
p. C7i
T) Hc S-l
•H• MH d)
Ti 45Q) 3 PC oO >. CH C)
cn a(5 (0 CD
cu o S-l
g t0
•rH CO 3n3 u tj1
o CO
>1 Sh
rH u <D
T3 cu 45rd P43 tr<
c CCO
•H
orHcu d)
42 g
•H -rH
co•HCO
£5
CU T) Sh
3>i O
CJ> G >i•Hmcu
45
CU
P•HSH
5
LO
in
01
CDO
38
ZZ
CO.
CO
CO
cu
of0
MH
g
prd
T3
CO
CU
cr>
13d)
d)
occu
Sh
cu
cu
Sh
cu
urd
m
ccO
70
CD
N•H COen
cn
3l+H
«WE-i
«
aG
rd
Sh
P
cu
N•Hen
3
fa
C
mua
wCS3
HCO
Dfa
G
<d
tt
GO•rl
-P3HOW
POcu
Sh
oa
p
G Sh
-H
<d
u
CD
XJ+J
Sh
CO cu
CD X! PM (0
(0 P3 34JCTXl O
c
T3CD
CD en
g g
CD
XJ
c
td CD
n x:T) Pen u•rl O
P Tl O rH 0) G
< L
op
CU
co
en
oX!en T3 rd
0) '
n o• 3
•H CD
fa Sh
<U O
•Hen en
GO-H
G en
H Gtn CD
h e>H -HO T3
en tJQ) r-l
en o•h xien
<d >
X! UPu rd
g cu
Q) rHO
w-H HX! OH HH
P CD
OCD rd
-r-> OXI en
OJ-i
cu <u
XJ rH-P rH
rd
u gcu en
X!-P rd
CU
X! O5 P
GH>i tn
XJ rd
TS tn
O rd
tn
en
cu
oouCu
CnG•H
g
O -Hrl HH
en X! I
•HftOrd S-l
tru oC tJl-rt
H O g£ Prd O CU
H Xi XJTl DuP
cm
,i
h
—
08 o
x:p
zt 0)
prd
G4
<
\
CD—"
,1
Lf~>
i
I
CU
>oX)rd
GO-<H
PrHOen
cu
XJEh
CU
N•Hen
cu
3 rHCn 3-rl 4HUH
CU
XJPen
oX!
mrHrd
XJ
G
rd
Sh
tn t3
poG
P O3 T)
CU XIx! tn
P tn Gsh o
IH CU -Ho P tn
G<UN
(U
rd a)
g
sh -a
cu cn <u
X! -H X!B'M-P
cu
Grl
rd rH
en CU
tn
rd
XI
cu
XJpGO
-PG•r|
Oa.
-rl
UCU
a;rl
rd
g
rd
grlocu
a
CM
O+1
o
CM
d+«
Q
cj+iOM
7ocu
poJ3
OCU
X)
rH
oCQ
0844
tn •HMH G jGo o _ ^- P
•H^ en OZ -
P a) G «3 gen Xj cu
rd g g COcu 3 -h
ze CD
Prd
P<
LO GQ-*-^ LOro
<IT) \
'
\ '
P T3O GCD rd
i—
i
XI <
MHO
GO•rl
Prd
CD
XJP
o
tn
cu
Cn
CD
goum
cu
uCU Ga. cd
rd UXi CD
en mCD
CU 5h
xiP cu
r4
o goSH
CU IHp
p3 CU
O Go
rd CnT3G
G -H <Drd X X!
Sh
MH rd 'OO g rH
3>i tn
P 3O
G•rl
PGO
<N ,,
O CM
4-1o
CI +1
K O CM
vo+1
oca
7"
CU
oGCD
MCDm cu
CD OH G
rd
MCDrHOP(H
O
•rl
O CD
XIP rd
O O
rl
OSh
MCD
CD
i-H
XI-rl
en
tn
O
rd
to
Sh
OSh
Sh
(D
CD
<N
oX!rlen
en +>
Oa*
rd
CD
>HP<dr-\
g3O
CD
XIen
G 'ti
CD r-i
g 3•H Ot> U
tn'
P3O
rd
Sh
3O
rd CD
MU UO rd
fa g
•rl
X}•rl
en
tn
O o -H
O Sh
CD P rd rd
XJ' gP CD
3
XJord
CD
OP
G rd
>iG
T3 Sh
CU CD
>CD
O
ac
tntJ •>* rd
GH en tnuU Sh -HH O fa CD
O U tn'
H fl-Ord CD H CD
MHGO XJU
CD inX) •
tnTJ -H-H fa3O G5 H
71
Arrangement of dimensionsDimensions should be placed so that they may be read from eitherthe bottom or right-hand side of a drawing, for example:
25
o
The arrangements at 1 and 2 are themost usual but there are occasionswhen it may be necessary to use thearrangement at 3
.
Avoid placing dimensionlines in the shaded area- zones of about 30°
.
Various methods of dimensioning narrow spaces or widths are shownbelow. Note the placing of the arrows outside the extension lines.
3
T? J ? )
/
%A m
//n ^nThe figures shown below aredimensioned incorrectly.
2-8 — V^O)^v
1
-.20
,
\
2
\
)
\..
25 \
/ / / \A\ >
4'V / H
7
Exercise : Dimension the figurescorrectly. (Solns. p. 155)
c
Kto
-M
\t^
%o-J 5:
D
y
v s s s n
7
-if
TTT-n J
72
Dimensioning circles
On an engineering drawing a circle may be one of the following;
A thindi sc
A hole in a
thin plateThe side viewof a cyl inder
~e-The side view of a
cylindrical hole
The way a circle is dimensioned is influenced by the factors shownabove and also by the size of the circle and the space availablewithin the circle.
Points to note: (i) The dimension always refers to the diameter andNOT the radius
(ii) A circle is never dimensioned on a centre line,(iii) The conventional symbol for diameter is <j>
Methods used for dimensioning relatively small circles
and larger circles
For diameters of cylinders
7
o<r>
oCM
is7 Z3
*-4 IS
<±^
10In 3 and 4
the leaderline mustbe drawn inin linewith thecentre ofthe circle
When the dimension linehas to be drawn as inexample 6 it is prefer-able to place thedimension as shown sothat it may be easilyread from the bottomof the sheet.
Side view Front view
In this example itis preferable todimension the sideview even thoughthe cylindricalshape is not apparent.Dimensions in thisview, however, mustalways be precededby the symbol
<J>
73
Dimensioning radii
On an engineering drawing a radius usually describes the shape orcontour of a component in a particular view and may beeither
An external radius An internal radius or A spherical radius
A radius should be dimensioned by a dimension line which passesthrough, or is in line with, the centre of the arc.The dimension line should have one arrowhead which should beplaced at the point of contact with the arc.The abbreviation R should always precede the dimension.
The above statements may be interpreted as follows:
For small radii —\
For spherical radii
reR 5
yR 5
ZJFor larger radii
R 5spH£B&
R20
-R 10
The circles shown below are incorrectly dimensioned,
Exercise
:
Dimension thecircles on theright correctlyusing theinformation givenon the previouspage (Solns. p. 155)
74
Dimensioning anglesAngles should be expressed in: (1) degrees e.g. 90°
or (2) degrees and minutes e.g. 27° 30'0° 15'
The placing of the angular dimension depends on:
the position of the angle in relation to the bottom and/or theright-hand side of the drawing sheet and the size of the angle.
Angles may be dimensioned using one of the methods shown in theseexamples
qoo
Alter-native /
Alter-native
Arc struckfrom apexof angle
L /
DIMENSIONING CHAMFERS
45° chamfers should be specified by one of the methods shown below:
251e2x45
2x45
Chamfers at angles other than 45° shouldbe shown as a dimension and not as a note, e.gChamfers should not be specified bya note and a leader line.
The radii below are dimensioned incorrectly.
lORad cfpsExercise:- Dimension the radii below correctly using the information
given on the previous page. (Solutions on page 155)
-26
22V
75
Designation of plain holesIt is often necessary to specify not only the diameter of a holebut also, the way the hole is produced. Processes for forming holesinclude drilling, boring, reaming and coring (holes made whencasting). The drawing below shows how these may be designated.
-cA HOLES EQUI- SPACED
<f>5 DRILL THROUGH
**• s
Section CC Front view
Note:- The 40 mmdiameter circle isreferred to as thePitch Circle DiameterPCD
Designation of "special" holes
COUNTERSINKS
^4 CSK AT 90°
TO 8
25 Ytifa-J I— 04
SCREW THREADS
M 12- 6H
mm«COUNTERBORES
J*6 C'BORE0IOx 5 DEEP
06 C'BORE 10x 5 DEEP
OR
SPOTFACES
OR
S'FACE(f> /2
Note:A coarse ISOthread isdesignated bydiameter andtolerance gradeonly.
MI2-6HTHROUGH
M I2-6H
I— 12 MIN
OR
MI2- feH
12 MIN LENGTHFULL THREAD
ORw>M 12 - GH
12 MIN LENGTHFULL THREAD
76
Location dimensionsExamples on previous pages have shown how components and featuresmay be dimensioned when size is the main consideration.Figures 1, 2 and 3 show how to dimension a component whenlocation is necessary. The features can be located from a machinedsurface or centre line. Such a surface or line is known as a DATUM.
-+oc
e
.m
25
r>B00 (^o
cc RJh
10^ «-15
1.Spigot located fromtwo referenceedges (R)
.
Both holes locatedfrom two referenceedges (R)
.
3.
Hole A located fromtwo reference edges(R) then hole Brelated to hole A.
Size anuse of
d location dimensions andthe machining symbol
20 REAMS
30 S
CD
o
L-r-t-r-1
34 S
44 L
0\2 DRILL
S
20 S'FACE
S SCALE
CD CO
4.The simple bearingbracket casting on theleft shows both sizeand location dimensions.
Reference surfaces aremarked wj.th a machiningsymbol:- s/
This is placed so thatit may be read from thebottom or from the rightof the sheet.
It is preferable toplace the symbol on theappropriate projectionline rather than asshown on the left.
No symbol is requiredwhere the machining isspecified i.e. in thecase of the drilledholes, the reamed holesand the spot-face.
The location dimensions are those shown with a letter L and sizedimensions by a letter S. Some of the size dimensions are less acc-urate than others e.g. the thickness of the rib is fixed during thecasting process whilst the 20 mm diameter hole is accurately reamed.The 20 mm diameter reamed hole is located by the dimension from themachined base to the centre line of the hole.
77
Dimensioning exercisesEach drawing below shows a component made from mild steel plate15 mm thick. Dimension both drawings so that accurate marking outand subsequent manufacture of the plates may be carried out.Use the machined surfaces as reference edges. The holes are tobe reamed. Sizes may be obtained by measuring the drawing.All dimensions in millimetres.
>
sL
Note: Each machining symbol in the following dimensioningexercises has been placed so that it appears "upright"when viewed from either the bottom right hand corner orright hand side of the drawing sheet."The symbol is placed on the machined surface itselfprovided that when it is so positioned it "falls" outsidethe outline of the component. Alternatively, it isplaced on a suitable projection line.
Solutions to the above exercises are given on page 156
78
ao•H4J
DrHOCO
0)
^n d)rH rH3 rH 0) • tn
(0 o •H X! o C(f)
o U P O Hi+-r •d nJ <Tl M
• ^^ O -P 4-1 3 .
o •H d> O M d) CO to
t tn XI 0) X! (0 a)
<DC -P tl cu > d) u•H Ifl (1) O O O O £ p
X £ X! u -P P P d)nJ P -H • T3 >l g
CD M 3 10 WOO) to X) •hO O ffd) •h x: o •H I-l
to d> P -p CO TJ rHto MO 0) 4-1 d) d) H
0)•HX C to t3 1 d) c£ OlH (d a -p • > •H
c -P O -H >h X) 3 O g tO Ci-l M o & £ d) •p H
'cc xi 'a nJ <D U W X! X!O 1 d> to xi to O -P O to-h 0) }-i en P d) CN c03 0) 3 0) trj XJ 4-1 d) . oC > -P o C d) 4-1 O X! tn •H
CO
cd> O 0) -H S-l O o C toBCUC ctj -P d) >itH CH O 4-1 d) U r-i fO S d)
-O ^ 3H rH 0) to d) tP & ca 6-H G rH O x! -H p fi M •H
E>t (d n) X! -P a> 0} CO 13 TJH4Jg QJ a d)rH 10 T3 (1) 13 rH (0 d) N d) rH
• ^— 3 (0 d) T3 Xi G O •h x: •H Xi rH
Q fo O X! < ^ (« x; tj ^ CO P <
I
79
Di mensioni ng exercisesFully dimension this drawing assuming that the component is to be /
machined all over. Take the datum as the face of the flange marked VSizes may be obtained by measuring the drawing.All dimensions in millimetres.Note: Holes - 4 mm drill equi-spaced
Chamfer - 2 mm at 45°
BUSH
#--E3-
Section CC Front view
Solutiononpage 158
Fully dimension this drawing assuming that the component is to be /
machined all over. Take the datum as the face of the flange marked vNote: (1) Use the horizontal centre line for locating the countersunk
holes in the front viewThe countersink is 90° and enlarges the drilled holes from5 mm diameter to 10 mm diameter.The internal chamfer - 3 mm x 60°
(2)
(3)
GLAND
Section CC
Solutiononpage 158
80
Dimensioning exercisesThe component below is to be made of brass. Fully dimension thedrawing to enable the bracket to be manufactured.Note:- (1) The only parts to be machined are the back face (which
should be used as the datum) and the tapped holes.(2) Locate the holes from the centre line in the front view.(3) Locate the holes and slot from point X in the side view,
"^"
*1
LOCATINGBRACKET
Side view Front viewSolutiononpage 159
Fully dimension the drawing so that the adjusting screw may be manu-factured. Take the shoulder marked v' as the datum face.Note:- The thread is M 6. The head is knurled (fine diamond).
The chamfers - 2 mm at 45°The radius at the end of the screw is 8 mm.
-£3#
Side view
ADJUSTINGSCREW
Machinedallover
Front view
Solutiononpage 159
81
Dimensioning exercise
Fully dimension the orthographic views shown above to enable thebracket to be manufactured. Details of sizes, locations, screwthreads, etc., may be taken from the pictorial view of the samecomponent shown on the opposite page. (All dimensions millimetres)Both the 8 mm base holes and the 35 mm bore must be located from themachined face R. The tapped hole must be located from the 3 5 mm bore,
Note: This drawing can be fully and clearly dimensioned using twoviews only. The drawing of a more complicated component wouldpossibly include a side view also to clarify both shape anddimensioning. The solution to this exercise is on page 160.
82
MI2-6H. 16 MiN LENGTH -
FULL THREAD. S'FACE 20
2 HOLES DRILL,
THROUGH 0'p
BOSS 16
HEIGHT 2
In this isometric view of the cast-ironbracket all the corner fillets(or radii) have been omittedin order to simplify thedrawing.
Cast ironBracketforVerticalSpindle.
83
Limits and Fits
In the early days of engineering, "mating" parts, e.g. a
shaft and the bearing in which it is housed, were manufac-tured individually and assembled only after laborious handfitting by craftsmen. This method of production demandedgreat skill, was slow, and thus an expensive operation.
To overcome this the first system of limits and fits
was introduced around the turn of the century. When thesystem was used correctly production costs were greatlyreduced because identical mass-produced components, even
those made in different places, could be readily inter-
changed without resorting to the time-consuming fitting
operation.
The use of a suitable system of limits and fits, the
latest of which (B.S. 4500) is outlined in the following
text, ensures that all identical components are made to a
specific size within narrow limits.
It must be stressed that when assigning limits to
the dimensions of a component it is necessary to consider
not only its function but also the skill of the operator
and the type and condition of the machines which are used
to manufacture the component.
Limits should be applied to the dimensions of a com-
ponent only if the resulting degree of accuracy is essential
for the efficient functioning of the component. It is un-
economical to limit the accuracy of a dimension to ± 0.005 mm
when ± 1 mm would prove satisfactory.
84
Limits and Fits for Holes and Shafts
7
A
Hole
Shaft(normalrepreseri't a t i o n
)
V7,
A
Hole
Tolerance zones(exaggerated
)
Shaftwithtolerancezones
A TOLERANCE on a holeor a shaft is apermissible degreeor error.It depends on:
(1) Machining or cuttingoperation used.
(2) Quality of work.
(3) Type of fit betweenhole and shaft.
Effect of manufacturing process on degree of accuracy obtainable
Process(typical)
Numerical value of tolerance forsample sizes
BS 1916 inch BS 4500 metric0.001 in 0.001 mm
S- (U
-— £o z»
1 Slip blocks, reference gauges
2 High quality gauges
3 Good qual i ty gauges
4 Gauges and precision fits
5 Ball bearings, fine grinding
6 Grinding, fine honing
7 High quality turning, broaching
8 Centre lathe turning and reaming
9 Horiz. and vert, boring
10 Milling, planing, extrusion
11 Drilling, rough turn-ing, boring
12 Light press work, tube drawing
13 Press work, tube rolling
14 Die casting or moulding
15 Stamping (approx)
16 Sand casting, flame cutting
0.119to
0.237
1 .969to
3.150
4.725to
7.087
0.06 0„08 0.16
0.08 0.12 0.2
0.12 0.2 0.32
0.15 0.3 0.5
0.2 0.5 0.7
0.3 0.7 1 .0
0.5 1 .2 1.6
0.7 1 .8 2.5
1 .2 3.0 4.0
1 .8 4.5 6.0
3.0 7.0 10.0
5.0 12.0 16.0
7.0 18.0 25.0
12.0 30.0 40.0
18.0 45.0 60.0
30.0 70.0 100.0
3 mmto
6 mm
50 mmto
80 mm
120 mmto
180 mm
1 .0 2 3.5
1 .5 3 5
2.5 5 8
4 8 12
5 13 18
8 19 25
12 30 40
18 46 63
30 74 100
48 120 160
75 190 250
120 300 400
180 460 630
300 750 1000
480 1200 1600
750 1900 2500
For more detailed lists referto BS 1916 and BS 4500
Tolerance i ncreases wi th size of component
The tolerance number is directly related to the manufacturingprocess and hence to the quality of work in terms of the degreeof dimensional accuracy required. The permissible degree of errorincreases (a) as the process becomes less precise and
{b) as the size of component increases.Tolerance number should not be confused with the numbers whichrelate to surface roughness.
Refer to British Standards for further information.Use BS 1916 for inch sizesand BS 4 500 for metric sizes.
85
Limit systems
vHole sizeconstant
Shaft sizevaries toprovide therequired fit
Shaft sizeconstant
Hole sizevaries toprovide therequired fit
Clearance Interference
HOLE BASIS
Clearance Interference
SHAFT BASIS
BS 1916 and BS 4500 use the hole basis but there are occasionswhen it is necessary to design a fit on a shaft basis.
Basic size and disposition of tolerance
Whenever possible, holes are designed and machined to sizesobtained with standard tools and/or to preferred sizes inmillimetres (see BS 4318)
.
The basic size of a hole is the dimension used if no toleranceswere applied. Another name used is "nominal size".
Tolerances can be applied to holes and shafts in various ways.o
'///, ofooo
CM
V///
Uni 1 ateraldisposition
Basic size = 24.000Tolerance = 0.030
+ 0-0 30
Write 24.000 °
or 24.0302 4 . 000
Toleranceplaced toONE side ofbasic size
Bi
1
ateraldisposition
Basic size = 24.000Tolerance = 0.030
+ 0-0 1 5
Write 2 4.000-0 - 015
or 24.01523.985
Tol erancesplit aboveand belowbasi c size
BS 1916 and BS 4500 generally use the unilateral method ofapplying limits to a size.
The tolerances can be represented as shapes on a graph. TheOX axis is the top side of the basic size, in this case, the hole,
+
0.
InchesSHAFT
HOLE 1
15HAFToo
r*
CI earance
IHOLE
<2 NCD U>
Interference
Mi 1
1
imetresISHAFT
HOLE
5HAFT
CI earance
©*ooM
1 HOLE1
U
< —CO u>
Interference
86
piT-the relationship between hole (or internal feature) and shaft(or external feature)
ALLOWANCE - the prescribed (algebraic) difference between the lowlimit of size for the hole (or internal feature) andthe high limit of size for the "mating" shaft (orexternal feature), i.e.
allowance*^_y (positive)T
maximum metal condition
lllllllftfllglllltf v vv * %
SHAFT
e.g.a simplebearing
(exaggerated)
The shaft is"loose" running or"easy" running or"slide".
CLEARANCE FITShaft is ALWAYSsmaller than hole.
e.g. for <j>2 inch (BS1916:53)
Hole sizes 2.00182.0000
"Mating" shaft sizes 1.99881.99702.00001.9988
BEARING
Verbal descriptionsof the fit may varywidely. Numericaldifferences are moreimportant.
Smallest holeLargest shaftALLOWANCE + 0.0012
for $24 mm (BS4500:69)
Hole sizes
"Mating" shaft sizes
Smallest holeLargest shaftALLOWANCE
24.03324.00023.98023.9592 4 . 00023.9800.020
Note I Allowance is ALWAYS positive ( + ) for a clearance fit.
/allowance*/ (negative)
e.g. a gearwheel on ashaft(exaggerated)
INTERFERENCE FITShaft is ALWAYSlarger than hole.
/
5252
2
GEAR
The shaft is forcedinto the hole.
The fit can bedescribed in suchterms as
:
"light press" or"press" or"heavy press" or"shrink"
Numerical differencesare more important.
e.g. for $2 inch (BS1916:53)
Hole sizes"Mating" shaft
Smallest holeLargest shaftALLOWANCE
(as above)sizes 2.0032
2.00202 . 00002.0032
- 0.0032
for $24 mm (BS4500:69)
Hole sizes"Mating" shaft sizes
Smallest holeLargest shaftALLOWANCE
(as above)24.04824.0352 4.00024.0480.048
As shaft sizes are subtracted from hole sizes, the allowance willalways be negative (-) for an interference fit.* The use of the word "allowance" has been omitted from BS4500. Ithas been used here solely to explain the difference between clearancefit and interference fit. It is still used, of course, in BS1916:53.
87
Both BS 1916 and BS 4500 recommend limits and fits for a wide rangeof engineering processes and activities - even horology J For mostgeneral purposes a carefully selected range of hole and shaft sizesare given in each standard.
-Holes are lettered by capitals, A, B,C, etc., the limits allocatedto the H-hole being recommended. The H-hole always has the basicsize of the hole as one size. The letter is followed by thetolerance grade number e.g. H8 . Shafts are lettered by lower caseletters, a,b,c, etc., and a range of fits is provided by those given
the charts below.inBS 1916 01.182-1 .575 in
Tolerance grade number
BS 4500 <j)30-40 mm
+ 160+ 10
+ 75.
+ 50
+ 25.
- 25-
- 50
- 75-
-100
-125-
-150
-1 75-
-20-280
"•%£**•
Hll
$ 30 40 mm
H9
DH8 H7 o-
D U
I- 0.02S mm
n
d
10
If the tolerances on hole and shaft overlap it is possible in therandom selection of components to obtain either clearance orinterference. These are called TRANSITION fits e.g. H7 with k6,and are described as "push", "easy keying", "tight keying" or"drive". A fit between an H8 hole and an f7 shaft is writtenH8-f7 and reference to the chart above will show that this mustalways be a CLEARANCE fit. Further reference to BS 1916, parts2 and 3 will show the types of fit recommended for particulartypes of work.Extract from BS 1916-Limit values. Extract from BS 4500-Limit values
HoleH7
3.001 in
Shafts
componentbetween
e8 f7 h6 J6 s6+
+ 0.5i n
0.12i n
0.24- 0.8- 1.5
- 0.4- 0.9 - 0.3
+ 0.2- 0.1
+ 1 .0+ 0.7
+ 0.6 0.24 0.40- 1.0- 1 .9
- 0.5-1.1 - 0.4
+ 0.3- 0.1
+ 1 .4+ 1 .0
+ 0.70.40 0.71
- 1 .2- 2.2
- 0.6- 1 .3 - 0.4
+ 0.3- 0.1
+ 1 .6+ 1 .2
+ 0.8 0.71 1 .19- 1.6- 2.8
- 0.8- 1 .6 - 0.5
+ 0.3- 0.2
+ 1.9+ 1.4
+ 1 .01.19 1 .97
- 2.0- 3.6
- 1 .0- 2.0 - 0.2
+ 0.4- 0.2
+ 2.4+ 1 .8
+ 1 .2 1 .97 2.56 - 2.5
- 4.3
- 1 .2
- 2.4 - 0.7
+ 0.4
- 0.3
+ 2.7+ 2.0
2.56 3.15+ 2.9+ 2.2
HoleH7
3.001 mm
ShaftsSize o t
componentbetween
96 k6+
n6+
s6+
ESEI
+ 15mm6
mm10
- 5
- 14
+ 10+ 1
+ 19+ 10
+ 32+ 23
esei
ESEI
+ 1810 18
- 6- 17
+ 12+ 1
+ 23+ 12
+ 39+ 28
esei
ESEI
+ 2118 30
- 7
- 20+ 15+ 2
+ 28+ 15
+ 48+ 35
esei
ESEI
+ 2530 40
- 9
- 25+ 18+ 2
+ 33+ 17
+ 59+ 43
esei
40 50
ES
EI
+ 3050 65
- 10
- 29
+ 21
+ 2
+ 39
+ 20
+ 72+ 53
+ 78+ 59
esei
esei
65 80
88
Conventional method of illustrating terms
BS 1916 - H hole
Q
X<S
1LE J SHAFT
<a
x<2i
BS 4500
BASIC SIZE
DEVIATION
For H hole.Zero line coincides with basic sizeline, hence lower deviation = 0,as shown above.
The size to which hole and shaft are referred.
The algebraic difference between a size and thecorresponding basic size.
UPPER DEVIATION The difference between the maximum limit of sizeand the basic size._ . , , ES for hole The letters standDesignated: c , c . ~ .. _ , .^ es for shaft for the French term
ecart superieur.
LOWER DEVIATION The- difference between the lower limit of sizeand the basic size._ . , EI for holeDesignated
r
ei for shaft ecart inferieur,
ZERO LINE
FUNDAMENTALDEVIATION
The line to which the deviations are referred.The line of zero deviation.The line which represents the basic size.
For each pair of deviations, the fundamentaldeviation is the one nearer to the zero line.This defines the position of the tolerance zonein relation to the zero line.
Graphical representation of fits - H holes
Clearance Interference Transi tion
HOLE HK ZERO o
SHAFT^SECT '
HOLE± HOLE I t
ES ES
SHAFTKSSSSSa'
es LINE TiT es TTes
nes es
EI XERO
BSSCT3.
vm t
ET EI
^im^i.
eL LINE EI » et SHAFT TeL et
t
el
89
Ho le
CL>
>oUp
to
and
including
ShaftExerci ses
Fit
^ H7-g6
H 7
0.001mm96
0.001mm v///,-r^SxV/////>/>/?/
ZERO/ 1
ES+
EI es ei V///A holeH 7 YLirife
oJ
15 6 10 5 14V///A shaft n h 1
—
'
i ,_ . ///////////.\_r
i^^^
18 10 18 6 17 CI earan-ce
r^^21 18 30 7 20
Hoi e Shaft
Basicsize
ES EIMax.si ze
Mi n
.
sizeBasicsize es ei
Max .
si zeMi n .
si ze25 30 50 9 25
10 0-015 10-015 10-000 10 0-0051)0»4 9-995 9-986
30 50 80 >0 29
HoleH 7
0.001mm
Complete the table for any other two hole and shaft sizes.
H7-s6
ES+
15
18
21
25
30
EI
CD
>o
10
18
30
50
-a co
ca -i-
-ao 3+-> r—
OQ- CZD -i-
Shafts 6
0.001mm
10
18
30
es+
32
39
48
50 59
80 78 50
ei+
23
28
35
43
Fit
S6&ZZ2 SHAFT
H7^houE
Interference
Hole
Basi c
sizeES EI
Max .
sizeMi n
.
size
Shaft
Basicsize es ei
Max .
sizeMi n .
size
HoleH 7
0.001mm
Complete the table for any three hole and shaft sizes,
H7-k6
ES+
15
18
21
25
30
EI
~0 CDc c(O -r-
J- -ocu O =3
> +J 1—o o
10
18
30
Q- £=
10
18
30
50
50
80
Shaftk 6
0.001mm
es+
10
12
15
18
21
ei+ H7^
Fit
k6 SHAFT
I HOLE
,^5^
f5
Z. Y7>?>f///1
V////S
Transition
f/SM/S/^
s:
Hole
Basicsize ES EI
Max.size
Mi n .
size
Shaft
Basicsize es ei
Max .
sizeMi n .
size
Complete the table for any three hole and shaft sizes. Solns . p. 161.
90
ISO Metric Screw Threads (BS3643)One of the most common items which needs to be clearly described onan engineering drawing is the screw thread which may be used for:
(1) Transmitting power, e.g. square thread in a vice or a lathe.(2) Adjusting parts relative to each other (usually a Vee-thread)
.
(3) Fastening parts together, e.g. a nut and bolt (a Vee-thread).
The following section deals mainly with the ISO metric thread whichis recognized internationally and, over the next few years, will beused in preference to the many varied types of threads which exist inindustry today. In order to specify an ISO metric thread on a drawingit is necessary to understand the basic terminology of screw threadsand how the fit between internal and external threads is derived.
The fit is basedon the "effective"diameter, i.e. thediameter at whichthe pitch ismeasured.
NUT(INTERNAL)
BOLT (EXTERNAL)
Threadangl eW Pitch
Note: Thehelix andthread formare drawnsimplified.
BOLTSecti onshowi ngthread formor "profile"
Class of fit
,
s_
<D+->
s_ CD
o Ec fO•1— •1—
2: -a'
CD
>+->
CJ
CD
crest
Right-hand thread
CD
Although the thread profile is a Vee in section, the nuts are classedas "holes" and the bolts as "shafts" and tolerances are appliedaccording to BS 4500 (Limits and Fits) . They may be representedgraphically like any hole and shaft combination.
NUTS Close fitInternal thread
+zero line 5H
4h* 0)
> U0)
-uCD
Fi
External threadBOLTS
-p
fd «wffl 0)1
Medium fit Free fit
6H 7H
K 8g
1— minimumclearance
Fit designated as -*- 5H/4h 6H/6g 7H/8g
Coarse and fine pitches are available but it is expected that thecoarse pitch screw threads will suffice for most applications andthat the medium fit will be the most commonly used. This may besummarized as follows:
Class of fit
medium
Bolts & screws
6g
Nuts
6H
91
ISO Metric screw thread designation
In production engineering it is necessary to provide informationabout the size of thread and the tolerance allocated to it. On a
drawing, the thread would be "dimensioned" or designated by-
stating the information as shown in the following examples:
M 10 x 1.5 - 6H [NUT - capital H for hole or internal thread.]
M 10 x 1.5 - 6g [BOLT - small g for shaft or external thread.]
Thread tolerance grade number y—MI0~6H
-Pitch in millimetres
•Nominal size in millimetres
Symbol for ISO metric.
The ISO metric coarse is the thread most commonly used and adesignation for this would omit the pitch, e.g. M 10-6H as shown.
Isometric threadsPreferred sizes
Nominaldi ameter
mm
Pitchcoarse
mm
1 .6 0.35
2 0.4
2.5 0.45
3 0.5
4 0.7
5 0.8
6 1
8 1 .25
10 1 .5
12 1.75
16 2
20 2.5
24 3
Note
In thetable onthe right,the inchand numbersizesrelateonlyapprox-imatelyto theISO metricsizes inthe centrecolumn,e.g.5 .
S ln
actuallyequals
15. 875 mm
13 ISO metric threads comp (jred with74 Imperial inch and number sizes
UNC UNF ISO metric BA BSW BSF
No. No. DIA mm No.
D] A D [A
1-6 10
1 1
2 9
2 2
8
3 32-5
4 4 7 1
5 5 3"5
6 6 6 5
8
10
8
10
45
4
3
T2"
3c 2 T6
12 12 1
11
75
I
5
T*3"8"
e\
T53"5
7i
7
TE 1
92
TE 1
92
i 2T6 c T5 K
5"5
i 65"8
3
"ZF
7"5
3
J1"5
2
1 2 4 1
92
Screw threads, nuts and bolts (ISO metric series)
A rapid, easy-to-remember method of drawing screw threads, nutsand bolts is essential if templates are not available. The drawingshould look right and slight discrepancies in size are not impor-tant. The most used ISO metric bolts (up to <}>24 mm) are:
Major diameter mm
Minor diameter
Minor diameter(approx.
)
Example ofapplication
M6 M8 M10 M12 M14 M16 M20 M22 M24
6-00 8-00 10-00 12 «00 14-00 16-00 20-00 22-00 24-00
4-77 6-47 8-16 9-85 11-55 13-55 16-93 18-93 20-32
4-8 6-5 8-2 9-8 11-6 13-6 17-0 19-0 20-4
M 16 StudCD CD
CO
Nut and bolt head sizes across the flats (spanner sizes) in mm.
Major diam. D.
Distance acrossthe flats
D x 1-5
(Dxl-5) + 1 mm""
Thickness of nut
Height of head
10
10
5-0
4-0
13
13
6-5
5-5
10
17
16
8-0
7-0
12
19
19
10-0
8-0
14
22
22
11-0
9-0
16
24
24
13-0
10-0
20
30
30
16-0
13-0
22
32
33
18-0
14-0
24
36
36
19-0
15-0
Approximate method: Thickness of nut = D x 0-8 e.g. M10Height of head = D x 0-7 e.g. M10
Example of application
M 16 Nut
Nuts are usually madefrom hexagonal stock barand a 30° chamfer ismachined on at least onesurface.In the plan view thisappears as a circle, thediameter of which isequal to the distanceacross the flats.The chamfer is drawnin the front view butnot in the side view.
,-No chamferhere
D* 0.8= 16x0.8
= 12.8
D = I6
93
Nuts and bolts exercisesThe drawing below is of an M 24 nut showing how the radii in thefront view and side view may be constructed. The major diameter ofthe bolt is the size D for calculating the distance across theflats and the thickness of the nut.
Major diameter D = 24 mmMinor diameter = 20-4 mm approx. (See p. 93).
D x 1.5 = 24 x 1-5 = 36 mm A/F
and R = 18 mm - this value of R is usedto .find the centres forradii (1), (2) and (3)
D x o-8 = 24 x o-8 = 19-2 mm
T = 19 '2 mm
Plan
Procedure
(1)
Side view
(2)
(3)
(4)
(5)
(6)
FrontviewDraw major and minor diameter circles in plan,
according to BS convention (See page 38)
.
Set out circle in plan with radius = 18 mm, i.e. distance A/F.Construct hexagon around this circle using 60° set-square.Set out thickness of nut = 19*2 mm and project the hexagon to thefront and side views.In the front view the centres for the radii marked (1) and (2) areobtained by setting out the radius R = 18 mm from and 0] as shown.In the side view the centres for the radii marked (3) are obtainedby setting out the radius R from 2 and 3 as shown.
Note:
Length of bolt = 60 mm
Front view
The length ofa bolt ismeasured fromunder thehead as shown
.
Exercise
M 20 Bolt with nut.
1. Verify that
(a) minor diameter =
(fc) distance across flats =
(c) thickness of nut =
(d) height of bolt head =
2. Complete the drawing.
17 -0 mm30*0 mm16*0 mm14 '0 mm
(approx.
)
94
Assembly DrawingsThe purpose of an assembly drawing is to. provide visual inform-ation about the way in which parts of a machine or structure fittogether. There are several types of assembly drawings and thedifferences in presentation depend on the uses for which they areintended. They are:
(1) LAYOUT ASSEMBLIES - in which the designer places together allthe various parts in order to establish overall sizes, dis-tances, etc., and, as a result, the feasibility of his design.
(2) OUTLINE ASSEMBLIES - these give general information about amachine or a group of components, for example, main sizes andcentre distances which would show how the unit would beinstalled. This type of assembly is often used in cataloguesgiving details of the range of units offered for sale.
(3) GENERAL ASSEMBLIES or ARRANGEMENT DRAWINGS - show clearly howcomponents fit together and, more important, how the assembledunit functions. Outside views, sectional and part-sectionalviews may be used but dimensions are rarely needed. The variousparts may be labelled by ballooning and a parts list would com-plete the drawing.
(4) SUB-ASSEMBLIES - are drawings which show only one unit of amulti-unit component. On more complicated or multiple partcomponents it may first be necessary to arrange parts intosub-assemblies which are then built up into the main assembly.
(5) SECTIONED ASSEMBLIES - a simple assembly may be drawn withoutthe need for sectional views and be clearly understood. Onmore complex assembly drawings, however, too many hidden detaillines tend to confuse and a sectional view of the assembledparts conveys the information more clearly.
Note An assembly drawing should not be overloaded with detail.The correct place to fully dimension and describe a" singlepart is on a detail drawing.
The drawings shown on the next page are typical of the use of ageneral assembly to give a general picture of a valve and a sub-assembly to show how the spindle unit is built up. A detaildrawing of one of the parts is added to emphasise that the physicalassembly of the valve depends on the manufacture of a large numberof individual items.
The exercises which follow are of relatively simple assemblieswhich could be drawn with reasonable clarity without the use ofsections but the resulting increase in clarity will show theadvantage to be gained by their use.
The solution to the example on page 98 indicates the way in whichthe exercises should be carried out.
95
General assembly (or General arrangement)
The above drawing is a general assembly of a screwdown valve
used to control the flow of water.
The purpose of this sectional view is to label the various parts
of the valve and to show how they fit together. A parts list
which matches the ballooned letters is necessary and this may be
either on the assembly drawing or on a separate document.
The general assembly is not dimensioned in detail although the
sizes of the inlet and outlet and a few overall sizes may be
shown as the drawing may be typical of a range of valves of
differing sizes.
96
_i
3+ _J
ni
*at
!
! i *i —i— t t^M24-6
3
SUB-ASSEMBLY DETAIL DRAWING
The above sub-assembly
drawing shows how several parts
are assembled together before
being fitted into the main body
of the valve. This type of
drawing is particularly useful
if information more detailed
than that shown on the general
assembly is required, for
example, by the person
assembling the valve or the
maintenance worker.
The detail drawing shown above
is of one of the numerous com-
ponents which make up the com-
plete valve and in this case is
a single-part drawing.
All the dimensions and processes
required to manufacture the part
must be shown on the drawing.
It is probable that the machin-
ist who makes this item will
take no part in assembling the
valve and will therefore use
only this detail drawing.
97
Sectioned assembly - Typical exercise
>
H*J
-
-
i :
i | | ("1
1 1
H Front view
End viewon bol
t
£3-
Exercise Build up a sectioned assembly drawing of the componentparts looking on cutting plane CC to obtain a sectionalfront view and cutting plane SS to obtain a sectionalend view, by tracing over and correctly positioningeach part
.
Solution Note that most of the outlines are unaltered.
Sectional Front View lookingon cutting plane CC
Sectional End Viewlooking on
cutting plane SS.
Note The bolt and rib are notsectioned in the front view, but are sectioned in the end view.
98
m
H<:wmo
w
WQH
B>
S
to
m
—- ' - •*
a,
X!CO
>1CU
3Oj
P2:
03
H
O-H-P
rHOCO
CM
CU
CP(0
to cj>1p >1
V-l (U >H(0 C POj to o
.H <1J
-P ftH
43Sd)
to
to
to cu cr> oceocoH-p
oCUP -aS P cO 3o o
tO
-p
to
&X!O
o oj in a) m
01 P -P(0
to mo
cu3
-d
c•w
tn On OC C to
•H -H US M -Pt0 O
>o
CT> CH
oHPHCO
3 M O >i OCQ T3 rH ,Q a
.Q
ECD0)(/)
CD
"DCD
0)
Q)
0)0--
coo
<I
ISwuCO
0)
r»
oCO
CO
is
H
tO
-aa cu >i3 "
CU
X!PMHo
to
P cu
U £ Q)
tO P CCu 10
G rH•P OC
t3rH•H
G r-\ &> tu cr> tn oCQCCfiflUO -H -H Mcu.* p pSOPo to to
cu to uPQ to t0 13
o oO rH
ucu
> >1op
o> oCU G CU -H P
H SH G >H
M o tO
O-HftO -P
•H £!TJ to o
3 >i G O f0
o Xi to cu tu
5CD
co
co•Hp
oCO
CM
CU
tntO
99
Sectioned assembly exercisesHINGE FOR VICE
eI
1
!; I HI
Upper hinge
For both exercises
niT\
1
1
1
1
^Nri<k
ILower Hinge
2L
I ! !i
i
I
i
ca
i i
1 h :i i i
^ •»
-m
Hinge Pin -&Build up a sectioned assembly drawing of the componentparts looking on the cutting plane CC by tracing over
and positioning each part.
Ji
Solutiononpage 162
Pivot Arm
ANT I-VIBRATION MOUNTING
Steel Liner
Rubber Bush Rubber BushSide View Front View
^
^HingePin V-
)
--&--
mWeldedBaseforPivot Arm
-i—L.
Side View Front View
-E3-
Solutiononpage 163
100
ftxt SC (d-P
SOS
o
EH
o
Eh
wsHDa
wmgog
oEh
OPQ
G•Ha<
fteto
rHU
,
//
/// s
CD
>CD
s C/1
/7/
ZJ
CO
fei
CD
CO
O\-
<D c 1 i
XCD >>
i
-Q I£ L 5
CD•r-
0)
0)
CD > os_
u_
"DCD -p
C oft >t kCUT) "
+-» w moCD
0)
w>1-p
.Q fO Gg ft to
tfl -P ftw g
g g gH o -Hto ftp
o so o
to
goH-pO 0) Q)
0) -C x! tnto -P P G
-Hto m g o
o O (0
ft M3 tn tn+j
G GH -H >,
(0 O^ ou
T3rH-H3ffl^HU
COG•HGO•H-PHCO
Oft
>1-P*•H HP fO
O ftCD
rH SiM OO (0
O <U
P 0)
3 P G
tn<Hft-H£ H CD
(0 Uh m+io ,c cP CD
oGO (U
siX! -P
cd a>
G4-4o o•H-P T3U G0) (0
(0 .G
T3Gt0
Si
sip
oX!
Go•HprHoen
CU
to
ft
O
CD
-PfO
rH0<
I*fO
rHU
K
11
11
r '
i
1
I
!I
11
-1 j—1 1
\-\ \-
1 f ^V 1
c:
h;
101
Sectioned assembly exerciseJOURNAL BEARING
Washer2 required
ED
Bearing Cap
1 f.1 1
1
1
1 1
1 1
1 1
i <H
1 1
! MI i
i i
i i
i \-
ii
i
• v. jl
t:
BearingHousing
Front view with R.H. half in section
Exercise Build up a sectioned assembly drawingof the component parts looking on thecutting plane CC by tracing over andcorrectly positioning each part.
Splitbearing
-e
Solutiononpage 163
102
co•H-P
rHoco
CD
tP
tf
CD
•H
o c4H o
rH -rH
H U+J* c mo -P
tn-P tu
m c tn
d, CD CD
> ^oi a ft<d o <u
CO O M
U_ Hqp
-HCO
o
o
<d
>•H
Q
CO
CD
O
PC
(0
(U
o
ft ftCO -H
COOU•Hu
rHOift
<D
in
tO
a)
,11111< CD o Q tu li.
(d Sh
01
GO•H-M-H01
O&>i
01
01
<
tn
(0
>irH
£
01
01
(0
CD
OH-poCD
01
H3
<d
CT> >c oH
CD -Pu
ft
•H OO (0
(0 Q)
-P tn
>i-H
H
ft
rH•H
01
-p
M(0
ft£! fl
o-P O -Hc u -p0) -HC CD 01
o c oft f0 ft
ft >1oo
<d
-P
MHO
tn-pc CJ
o o
103
0)
T-{
CHaCO
10
oHP.HOCO
ft
\
MCU
3 P CO
P 3 <d
co S !s
gM
cuopCO
J
fl-
t =M a
rt--=d--^ .y
!f
To
3CU
00
a.
h
"n—
j*f
. ^
CU
4->
eo
-_r
u
oPuDCO
WQISHCUCO
u
g
>
enc•H
to an otj
tp>i crH -HX! .*g OCU oCO f-i
CO
(0 tn
PT3 S-i
CU ffl
o
-p
Cu
-p
co CU
CU
CO
rti
Oa,eo
a, o
CU
-H P•H3 <4-l
m o
to
•t»
oSs
0)
H
T3C(«
H •
CU P> nO rt
tnC xl-H OU rd
(0 CU
U-P Cn
>i-HX! C
OU -HU P
-HCU CO
C Octf CUHCu >i
.HCnpC O
O O
104
DevelopmentsMany objects in everyday use are made from thin materials such as
cardboard, plastic, aluminium, copper, brass and steel. Metals notmore than about 3 mm thick are referred to as SHEET METALS.
The objects made from these materials are developed from the flatsheet. A pattern is drawn on the sheet which is then cut to theoutline of the pattern. The material is bent, folded or rolled intothe required shape, these processes giving the object stiffness andstrength for a comparatively small weight of material.
A pattern which is used to mark out further patterns is called aTEMPLATE
.
There are four basic shapes in sheet metal development from whicha wide variety of work is fashioned, including hoppers, bins, chutes,vessels and ducts for ventilation and dust-extraction.
1. PRISM
CYLINDER
H E
2 . PYRAMIDL= Slant Height
on edge
4 . CONE
TTD
L=Slant Height
Simple shapes based on prisms, cylinders, pyramids and cones may bedeveloped by three commonly used methods of construction. They are
1. PARALLEL LINE DEVELOPMENT: for prisms and cylinders mainly.
2. RADIAL LINE DEVELOPMENT: for pyramids and cones.
3. TRIANGULATION: for transition pieces which are used to joindifferent shapes.
A pattern is usually folded so that the lines indicating its shapeappear on the inside of the component. In practice, allowances mayhave to be made for extra material required for joints, stiffenededges, bends and seams.
No such allowances have been made in the exercises in thefollowing pages so that basic principles can be emphasized.
105
"* -1_ ^
^r^
n
^V
(N Ll_
bull pueg
CO
,
cCD
Eao
>CD
"D
C
Id
\
CO
CM <
x 1
cd
>oSi(0
c
oSico
rd
CO
0)
•H>
Sift
S-l
ft tr>
o o
-p
a)
>cd
01
-rH
o
cu
sip
<: go
= usi moc crd cu
u xSi (d= -p
U CD
o na)
-pn en
to -PCusi
>h -ho cu
M-l si
C 13sh ccd rd
-P-P to
rd xlftp
0) CX! CD
Eh J
CU
<d
Ucd
ft
CD
S-l
(d
X!o•H
£
CO
CU
cu
oSh
si
>ixi
T3cu
-prd
o•H
c•H
-acu
pocu
•r->
o
ft
CU
u(d
>1cu
Sip£!CJ
•H.e
goS-l
CU IMSh
cd co
CD
CO 01CD T3
•H
T3
CD
m
CD
CD
POP
CD7"
4H-H M-l
O
CU >itr> gT3 •
CD a 0)
rH-P o cd
01 CD -Hcu S-l
p S-l cu
l-l o pO 4-1 cd
Si g01 *•
cd 'cs
P .H G(d X! rd
•Hg 01 CD
cd 01 gcu o HCO ftp
a>+->
s_
ai
>
CD
S-l
•H
CU
S-l
CU
X!
>ifd
g
PCHO
S-l
o
o
o•Hpr-\
o01
acrd
ft
XCD
td
UHft>iEh
2OHEnUwc/i
l-H
O
EH
oo
EH13Wsa<ow>wQWHhH
ijwl-H
01
CD
SH
PCD
g-rH
Hg
aH01
GO
f=C 01
CD
g•HT3
106
G ^ 1\. Jk
' •H
r^^CU
c G rH •
j EH•H -H O
X10
0) / 53W
!<cu
N / / / 04
< (
/ pu
P X! CO ^r"-SJ oc\ (d (0 G ^•si- v w
\ 04 O.M-4 -H >'\ • o rd w\ M CU M -P 53 Q
4-> > O CU X) O(_>
m o lW 0< o X H w3
'
'
X) rd Eh 53-Q \N G rd G £1 ^ U H
- M ^ to P CD W vA
if./ i
d) T3 CU CO CU M W WQ P 0) P <D co G .G rd g u iA
/ : -P T3 P .G £ 4J3'0 -H W Q W^ / rd -H rd P CU -H D1 CU H 53 J
/ O. > O. h -p <u co g CO CM O -3
/O 3 > O ^ -H g r=£
CU H CD g <D id id h o • W ^ Phx; a •C -H cu co o -H CO W H <
j
/' •p P M4 .G i pq . C CO 0) h a CmA.
'
ft) P CO <L) -«H G Sh
QJ0) o CU O CO T3 • CU P oP rd P -P CD O G -H G e g) O0) Pu CD M M rd O o •h e Oi<-\ co H M 3 o * -h in T5 -H
_i
Comp the Comporde Meas
The of
Asame sect
at
4All
mill
<1
rH CM CD•
—
*
—
pr- CO ~1 o
53
CQ
fl,*7
| 1
1i
1 1
1 1
1 1
"
/ 1
cu 1
y/ <
v 1
•r- 1 ,/V. s_X a I ai ""\x / 1
C| -*->
"\x a> '
+-> \.vx 1
CQ| ra
ex
v"\X ^r
1 |
1 |
1 1
1 1
/> /\. U' w//\ _i/\ f^3
^V \ </' \ QJ+->
^\ x x /x x >
>v X i-
» X x \ X > i in
g \/ Xx 3 >£>
H rH
H > NX +
r-
c
1 a.^
) GX u3 OCq
107
EXERCISES
Joint
True shape ofduct A
Start the shape ofthe hole at this point,
Solutionson p. 166
(1) Develop thepattern forbranch A.
(2) Develop thepattern forone half ofbranch B(SSS) tofind thetrue shapeof half ofthe hole.
Measure the orthographicviews to obtain dimensions.
All dimensions in millimetres
30° TEE-PIECE DIAMOND SECTION
PARALLEL LINE DEVELOPMENT
108
EXERCISE
True shape
of cross-section
of chute
looking in
direction X
Complete the pattern for
the | | -section chute in
the space provided.
Measure the orthographic
views to obtain dimensions.
All dimensions in millimetres
Typi calchuteappl i cati on
Solutionon p. 166
-SECTION CHUTE
PARALLEL LINE DEVELOPMENT
109
•
en
rH
3 oO1
G vorH rHO G •
O G W ° ft
CD CD CD G * mCM .G U ^ CD CO (D «{
-P PCD
CN OrH JC
O CD -P +{G 6 P £ Eh
\
i-l e en fd -H (0 3 Oh 12O -H o 4J4J& ^ W a^— m rH P T3
G Otn K Q S•H CN CD X 2 CU1 rH
J g -H h si TJH£ m H q-—V 1 S-l
• g p P -. iJ 1-5
CDi
CD U G CD CD £ ? >* PP J -p CD c H B ^ 5>H ^ O >cd - -- -/ - <i p XJ •H CD +3 -H O S ' We / ^ rd G P rH > s ^: e-i q•H / cu •H en P (0 SQ) rn 3 KX / rH g to u MH g in ™ O wosh
// __
<3-
CD >1 oH Oi -H <4H f0 (0 "H ,- H S
OrHja •« « H/CU / P to CD P »4 c 2 ^a, T5 c 45 •• CD Cn <D Ji-f, Qr0 / CD CD CD p >i e G CD x: t, w "^*
/ P P e X3 O -H Si -P -2 EH H
pj cn 2 ^ u «-3u"*- / ...,,..... .rr_,
v^ CD t0 •rH CD CD
TS en tji~~/
/Pq & G •H P cd g g -Fi S s "SX CO a 3 rH > M CD •POO -ti 5 D «
CM /HCoft:
OU
>h
PrH<
•H (0 .GQft P in MrH QJ 5 « <:
= MH fd s ^ Eh &<c~
1 fei *-* • • ^-^ ,^^H ! X rH W A XIO
.. .._..._„, ^S
fel EH —O CO
*-» zcd 7 ^p
\_
_
- / **~
(0 / =
uu(0
IT
01 / w7 o> <;x " \
"**/
"~~/ «> G— / • O\__ _v-4'\
Q 1 ^ H- 7n mm
II \ CO
:::;1 J |
/ i in
7 to o cn G
+ -/- \--y-—1\ /<u T ( v. s \^ o —V^j. cn o tn
ogCD CN
\II
a/ r-\ P -H
~7co >__/ G -H -H7cn -H CD 'd/ rH O rH/— IS bHH' 3 (0 to
\
0)NV Vr,
MH\ r
x V a^ 1- VKJ v„y -^/ ,<. £_ rn u 3^ P CD • ro D1
CD fji W CU CDO
\
, ,
.,_)' - Hfl(N<
'° ', o W tn CD "H . in CN'
<C G rH G CD rH'
CO P O G4J >, -H CDCN
V~°"
3>lCO01rl>O G iB CD -H
rd X O £ &>p "d (h to ro
CD P G cd a Sh
to co co S tn Q P
\Vto
urA^-" "^>^£ ,
O tn1 / +J.G
rH \ **/ \ oo G -HCD P T3 V a 00 •h in •
rH G CD \ ^ ^ jj CD
h O 4-> tn \ CD i-4-> CU
G Hto u u c: \ rd en <d
Sh m CD -H \ (O ~oo>
1 OI
-J- QrH P 3ft H O1
(0 r-cd \ COPu CD O G CD \ C *r-
3 i—s- >>I— o
id in
.G u o si \ (D & I
in +) OjOi-M \O cn \ o
^x y1— O.G PP rH CD
rd cnG CD CD G • Jrw -h sh fn o G \ 1 \ CD 3P CO )H Sh \ H OOa* in o vQ qj \ _ '
tn CD £ O CD P >rl C (!) C! -P CN *"-r*^ : > ro
•H CN<U -H -H O -H tJ
OJ Q rH t0
KM > p M a
no
1
i
' ]i i
; ./ .
G r-vo Ph
'
!
: / -H rH W;— ._._ ...... /.. . 4J •
TJ Cu
1 II If f^\
Eh EhW !S
:
i
Mi / r-K
o c2 W
Eh i/
! : /to Q O
U i [III/ ! \
CD
t3!
i /I
1 Is '
i
/ ro <; >C
1•*---t
i—l
1 /- cr
/ \ y »~i
«* a qn w
Ph S
/ \y \'
~ y \^ \ />- <£>
' \s O HT3 — '
'
/ - 0^ JQ) i /!
|W
£ i
: / ! u « ^(0 /
(U 3 CO 05 <4-J W WO
- — r~ X! 10 ft! -H nj o-p cu x: (u w
- Q ^S IS J/3 1/
^ !/ :
-PI :
iHXJG-PtQ «CUX!-H O H fd
G-HE-i£ td^C+J ffl J On
•H 0) C Q) O C ij >h <;• i|
<o x; c h i-( -h x; ^to-p • X (G>tnOro
H U fU
•P rH ;\;
CD . \
u a \ \ i
f0 4-> <U C -H M o'O 01 •O.-P-Hxl'a o
. \s- cu-pco OrdO-P co
C! -H M >H -H M o x: -H
cr>
o : \ : !
CD;
1\ !
G T3 • \CD > i ! \+J O i \-P U
j: \ :
3 H C0 (D>< +)H(HH tPO OO-P UH (13 C
-= En
•n a C 0) OJ -h 11) ooOi-H C! CO & ^ M S-l -H
0) • CX! ^ OO 0)O -HSh 4JOX5-P
W M OH (U (D m +i Oto (CXI-P -P>C 0).. P CD -H
tJ CU j
CU J r - V0)
;: \
X! ro ;! \
-P Cu :
m -4- j
- -Oh
• rt wO +JflM-H'd^C0^
Ul-WO CH 3 (Bin ^ O
)
the
top
of
the
front
vi
:ersect
this
of
intersect
it
view.
Eh +J0) -H-H O0)C0PQQ)rH
\ - - - -
ISH. p!.
r
M^tOOm C 3 —' +J CUfdtOCO-r-iOCU-H Cx)CU X! rH fQ CO -HH 0) tJHI+J O-P T3
Develop
in
the
O Or0MC> nJxiCH^a)\
m ^ -h rd -h s-i a) x: -p -h o e:•pjh -PrJrHcncuo -h
- X -~g OCOrHOCu-HgCUCUfOC-M (D 3 SfO >rH
\i - D5JOOra(l)r3h(D(DMft ]j .Bidflinx!-Hroa)x:x-Px:x!3X ^ m S 'i J1 PS: Cum )H4->a)t0EH-POQ) C U U-t
+J M O 3C O +J O CD
< 03 c > c i
,
TJ -H rcS x!(T» a) o c a) -p
"*s^ '+j a. c 5 x:
^ O £ (0 -P C1/I /^ ^"
/\ «= IPX Id H -H.
"* -m CO >H T( C.. ._..... -.- -- v<**-
-*
+>/' C S 2/ \ / \ <^ r~ o -h -o o c
_. _>-/ s~ o cu Y / * .
a MH to OS- »r- \ Oixf C -H in -H
rd 0) PQ +J_
n u_ > r
7" ^ '\
Q //\
to -P X! C O""-•\ r^^ _ -H to -P rd -P a)
^r <o ^'<U rH C C0
•4 ,--" / C CO Cu-H !h-=»
:\ /" / / rd O -H O 0)o V'" / / H+J C Q.-Pin y *it
:*v / \ y' CU CQ -H Ccay \
"* ^ 0) -H
\ C 0) E in >•H -HO -H m
> ^ g rjiOinCO k
^**' — -*^^mID m hh o<\
' to 4) M O CD
| ~^^^—^\. i '
j -p >o a) m -p >C -H c uH CO -H 0) CD 3
,
1
- - -H^ j
\ 1 O HflCO' / \ O) S.
11 CU CD -H-H
XI rH rH rH 0)T3 <U
T\ \ / ^
-'
'
•r- «i— X 6 -P td x:\
y'
t/) > O -P rH rH 4JM C G rd rd
MH -H O O +J CDN -H C +J
CO <\ ^/^y CD CD -H +J O CDy^ /[\ \y G rH >H M N rH
/ i\ *^\ •rH O O CD -H CU
"* \>^*^ / i \ ;
^--. % rH M X! > H g•H O O
< o <; <; x: u/ ' \yrv-i
^^^I —
^"^1' rH CN ro
63 Q ^ ^_
111
&
f
fc
4
©
®
4fe-
^^
cu
p
xx:
pto
co-HPO(U
03
CU
-PC•H
CD
XPMO<4H
0)
0) M-l
P oCU
rH 0)
a >g MO 3u o
^CU
P •
P EH(0
ft^oCU
(1) XX ^P ffl
EftO £r-\ uCU c> (C
CU uQ A
en
ID
upCD
g
-Hg
CO
cO•HCO
c
g•HT3
<
fM
Hft;
X
CN
on
CO«WQ2H>H
o
Eh
Q
O
WUwHI
wwEh
oO
"O cu
oo >
CO
WEhW
HQi-3
<CDCtwsDEnO
Eh
S3WsCmO
>wQWH
w
<
en
ao•HP3
r-
C •
tn o ft
IW CU
O MCU 3
h- CU X t3> P CU
C >-l o •
O c O en
o •H H Pft C
cu c •rH
r 43 s CU
<n P X ftr— X! EH
Q. C en uo cu
en • XICN rd rH -p
u rH OP rH
p 3 T(c o CU C-rH tr> f0
o -a to
ft 0) ftrorl a
u >H c>H o *
MH f0 rHU CU CQ
a en
o en H !h
-H •H UP u mo C cu
3 X 13>H •H cu cu
p p pen u en to
C cu 3 cu
O en O ftu M •H CU
cu > SH
cu p cu
JC c 5-i en
EH H ft-rH
112
EXERCISES
B
Frontvi ew
-e#
Plan on T
S D
c
B
A
D3
C2
T
A 12
Cylinder Tis shown intwo planviews, bothof which aredivided into12 equalparts
.
Note how theprojectionlines inter-sect to pro-vide pointson the curveof intersection.These corres-pond to pointsobtained bythe constructionused on page 112
2 Plan on T
Solutions on p. 168
All dimensions in millimetres
(1) Complete the curve ofintersection at XX.
(2) Complete the patternfor one half of thecylinder B (SSS)showing the shapeof the hole in B.
90° TEE-PIECE FORMED WITH
CYLINDERS OF
UNEQUAL DIAMETERS.
PARALLEL LINE DEVELOPMENT
113
«a
T3 Q<D C 0) 3C rC SI H•H -p 1-H HH 1)1 S X !3O rG 0) J-l U U4
C -H Mh O 0) f£h
-H T3 > O l*H .C s a,(1) -p E-i W o
CD -P CD <U • c M K h-i
.C O TS > X H G s W wP Q) -H H X 0) -H H >n to p -P Q d4 wiw O O -P -P < W
SQ
O U <D (0 (0 2a>si 0) cu'd P5 H W—
• -P x: c 0) • O P S>H CO -P o 0) M CD fa H>H -H C •H A u > J i-J
*— -H -p -p •P nj o W <M o o E X! o L> i-l
tJ Q) CD 3 CD O. (0 w m wC TJ co M to O ^ H w HJ
1
CD C 04 -P M •H O 0) 04 a l-l
•H -H CO 0) 0) c o 1 D <i0) rH rH C -P > fd rO w w4^ >i>H o c <u s-» cu w Cm <cEh O CD U -H q ,q CO Eh U a.
• • ^_^ ,_, oCD H CN O-p — *
—
^o
oS3
oo
O
03tqtoH<o
114
k en
w >i u <u a;u rd cu x! a> X0) 1% p -P u pTJ a) ITS •
c w e U Qi m a) a)•H •H rd o CO O X PrH x •rH m m p -h>i a) p T( • CD en
o X! •P d xl C DiO-p £ -H 3 M -p U C CUp H rd O CU o) o aX e X P c P rH O
tn o O* Cn P -H . -P OS
-H M • (U 3 05 CD 03 >H}-i m T3 PMrt] > &PQ >h
C 4-1 Sh
a; T3 CD o x CU X) XI CD tj a;*h a) xt -P X CD 05 x: cu ao5 -p tn P ^ P X -H
u Sh m ts M T3 rH rHPQ 3 03 a) a) &, 03 CU Qj 03 1
=t HH^IIl o stj o g a)
TJ -p 3 d 3 rH -H rH rHc C CO u •H d) P > a) p pS- td G ^H > n o > M c<u o -H ^•M (0 u CU 05 CD
<: o U o oj Qftft Q CU U<o .. ^^ ^^o. w
Eho
r-l CM
EHKH
>H
PQ
QWpa
<:En
wsowC/3
oO
CO^s
• wCO s:H P4S oW H1
s wo >w wCO uco W
aH• KH
cocm ^w Wu hHs r^lHrj ^X <U A
COfc]
coHCoCqfel
fel
CO
s-
cu+->
+JCO
$#-
>-
rH
a.
co
CO
o•HPrHOCO
0}
cu
M•PCU
g•H
•H6
CO
O•HCO
ccu
g-H
<
115
EXERCISES
Front view &
(1) Complete the end view looking on theinclined circle YY.
(2) Show that the curve of intersection isa straight line in the front view.
(3) Develop the pattern for the cylinder A.
Solutions on p. 16
9
30 TEE-PIECE FORMED WITH CYLINDERS
OF EQUAL DIAMETERS
All dimensions in millimetres. PARALLEL LINE DEVELOPMENT
116
EXERCISES
-GJ
Pattern B
(2) Complete the pattern for thecylinder marked B showingthe shape of the hole in B.
All dimensions in millimetres.
(1) Construct theellipse in theend view whichrepresentsthe inclinedcircle YY.
30 u TEE-PIECE
FORMED WITH
CYLINDERS
OF EQUAL
DIAMETERS
.
Solutionson p. 170
PARALLEL LINE DEVELOPMENT
117
EXERCISE
True shape "
of cross-sectionof chute lookingin direction A.
Complete the pattern for
the \^J -section chute in the
space provided.
Solution on p. 170
All dimensions in millimetres. PARALLEL LINE DEVELOPMENT
118
03 CD CD
• O « cn x!£ pq rd +J
-P Q CD
Xi rH CD CD 3 5-lM-l
O CD X! W H O OC Si -P cn i-l C Ehrd 3 >h x! -h rd C S5-1 Tf in cn O -P CD O WX! 0) 10 •H o u -H a
V3 O CD S ^ +J fO 4J OiCD -H u si • O O oxs > O -P - PS 'CH 0) M-p o m o fe W -H fd to w
u Sh - tf a u >U ft CD O O O Q W -P O CD Mo ftO in- W E-l CD -H +J QU-l CD ns CD 2 W rH +J C
o X! CD C C Pn 2 O *H WC f0 0) £ 5h -H • O << CD CD sS-l ft H CD rH rH _ fa h +^ cn cd IHCD CO CD rH -PI r- Q cd i x! M•p 3 -P CD rH c W h cn +»-P CD M CD rd S-l • i_ u J ft cn
o, w ^ o -P1^
cd x: P X! ft-P ft wft-p -P S +j H |D +J 5-1 cd ^
CD CD CD c +j ftOID O J<D C X! 4-> X! O rt I W cn CD
^x: -h +J (d -P o. w cn cd ft•p CD en w fn 3 ,c; -h <:
Eh CD U CD Si C Eh O Cn-P ft Ojft -P -P -PO T3 CD -P CD H orH CD rH CD <H tn -P OCD ,* ft CO ft C 3 (T>
> 5h e to e o rH oCD rd O 3 OH OQ E CJ Cn U rd Ul
^-. —^ --^
iH cm n
X\X\
% <? vX ^ x^
X X\ X CD\ X. / \ / X / n
"\\ X\ \ x\ ^ / \x yy to CD
x\ X *X / X VA^v to o oX \ \ x\/ X X \y CD 5-1 XI/ X X / S\ ' /, \ o m (dX \ / / X X c\ \ \ />. / // s\s' / ^ (dm*
[y / / / / S7 \ / -H H-4 0»E \ \ X / //// X, tn o fto \ \ / X //>^/ /t -H 1 rd•r- \ \ X /\Jr / / <5> T( 13 X!
O) +-> X A. / XX / / CD u>Q-4J O
/XX' X x — cn ft cd(0 <U CD
.£ </> co \ /'XxxX X h—^ -H CD CD 310 10 1 X /C3 X XoX r<] X! -P 5H3 CO
<u en to \A~ / \/ NP' *- Eh cn +J
,—3 o N. r x • ^^r- ~ '"' 7\ •
s- <<- s- \. /\/ y^^" / x en
1— o o \ / \ CN CD
5h
-Py '/\s a / ^y
N. /^s \ CD^ ^ ei
•H
/<\./
rHrHo X h~ x -
^/ CD T3 -P •
•H
v ^^ C C O >i•H fd C 5h
•H
H td CO
c! CD cn fi
cn c cd s-4 cn OCD OH (0 (U •HrH -H ft O CO
o +j to cdCO 5-1 5-1 O CD & C CDfej -H O 3 -P CD gCO O M-i 5-i CD -H W -HH 1 -P rH > >, 13o •H Tj 10 ft (0te; gocg-os rHfe) CD CO O O d rH iH>< U 3 UO (1) «! «;fel
119
• 4-1 •»
0) 0) CD O CD CD . CDX £ -x -p 3 C"X . O X-P -P 0) -P •H X! to M -P C -P •>* • -P -PCn rH cn •P CD •P C CD 1 5 X CD CDG 4-i <D cn m o Cn S-i C •H C X O CD -P X 4-1
CD O X! -H O ft C 3 • •H CD U rd O -P •H Cn -p Er< OrH ft CU O O rH Si 4-1 T3 > C a
0) 01 C J o o nm m -P -P m tT> C Cn cs W Cn H S 0) u fd rH CD 3 I C rd -P rH C - S-lo D T3 O -rH rd C 0) - m • g X o o O G O • Eh CDH 03 cd T3 x > ? 3 BQ CD H a O -P rH CN CD rH rH 03 -PH Eh •H CO c o M X! T3 S U -P CD rd 1 U 3 rd | -PCJ Cn g -P rd X! -P ^-P rd o 4-1 C •H C O 4h rH O cn rdD CD C m co c cn 0) u si rH H Eh -P Eh -P ft« X -H ^ m o • >i CD Cn-3 to CM -P rH O cn CD 03 W aH •P ft >i us: >H CO ^o C CD 1 CD CD 1 CD X rd 1 CD •H CDCO o ft^ 4-1 -p -P rd -P CD 3 XI cn O C CO rH o c P O C O Xs CD rH cd tr> C O -P rd -rH rd •H -p •H ft-Po C 0) • CD G CD C •H kq 4-1 CD U IHHIJ-H • 4-1 rH C O 4-1 rHu •H T3 x o x 0) rd 4-1 10 rd a >1 4h C 'CS C 4h H C 4-4 ft g gg 0) •H •P-H-PrH 4-1 CO O rrj -H rH O X rd rd rH O rH O rH 5^i3fcl M x g -p Xl cn •p -p U CD rd • • to rd O -Po CD -P (0 C -rH C CI) S -H ft CD S C ft Cn £ -P ft-H CD •H ft-H CH CO
•p u cd co"-h 3 rd 13 CD CD g rd •H CD C CD CD -P CD T3 -P CD T3 -H 3Q CD 4-1 >iX O U M m -P X -H ,rH rd -P CD •H X rd -P rd O a •P rd O O rHO Q O ft!2 ft>-J -P Q U C/3 -P -P Q 4H W rH > -P ft CO U 3 o CO U h3 -P 4-t
EH ,-^ ^^ ^^ fg-^ , ^ ^_^ *—> ^^
W rH CM n -*? m CO r^ 00g ~ ^"^ N*_- N—
'
Eh
Mga.orH
W>MQW2
r-H
HQOh
120
4fo0) TS 0)
vv,J) x o) >i • 43^ •y ^v +J (3 4J 43 G 1 -P 'O
\ S3 4-i-hmco cd n 5 gX <u+j O 4J -P £ 43 TJ O urcj
, L_ jS\_\n r——1—
1
—j
-O 43 CO -H CD J3<UTj *Ur-M- CO f3 H £ -PtJ CD
ooo o to m cd <i)-Pi: to
cduth -h >(d^ nJ
\ i /
\_ju w 1*— J v. \^^^•^ X^^ >
^J>>l
^_ -p cd in <u s xjOT
ia -i XI 3 -H +J CU CU CD
Cn+JQ)>C-H f!^ • 5hG-H 0> SH4-ICD «0 4-»o.^^. "
•H'Q>CSh CD CO 3 CN-H (OMHC 4->CD(tJ tj1 CD
•HgflrH (0 4->-P,Q CO giHrtJlOftCDiH (0CD ft
o* (C MH ,d ft ftrH CD -P O3 >1 fttl -P 04X! 45 rHCOftC CD CDg+J tncD•h « « e ^ £ O -H>>CDC O-P -PU-P U CD
Q_ —^..^^^ X! RJ £ >H -h "dO-P CDMHCD iW'-^g (04->CD-H4->OCNO CD
ar^""''***— ^, m-a>incD "— mhc:TJO-HCiHIO o-h•H CO CD -H ft +J • rH
y rdg Tl-Pg ^-E g^ 3CU-HOO Jitl 3 • D J\ C+JJ3 01 (DU ftCD-PCN Eh <\ nSt04J -r-i ftcor- Ui H\ 3 CUO^- 003.-I D Q\ = 01 ^IHX! MH £>H^« K <
s- <C "4H O Eh ft*-' EH CU *w ft fo Kai
\
\X. 00
\ +->
\\ / W rH.\ / \\ cp nj
/x \\ A- C -P
o \/ \\ /\ E tCO)
/ \\ / \ = 2* ° •&\t\ \\ / \ +j C! N +)
-2\ / \\ / \ «« -rj -H•<* \ v- ' \\ / \ 3 ^ H ID
-o \ S^~~^ W / W i. » O -HVi „, / ^^1\. u. A
03 \H \Co \
^~^^cr> ^--'
\
a. ^r af\- _ -^ oT3 4->
ft; \ O- 3 O •
O 4-1 Cfcl \/
1
CD
X^'^s^folx
\4H ;$
•> Oco -^r xi •
1 \ / ° """
i^ -H 1 CO CO\J-— \ O CD
CD V^^ > cu w tnX! >^_^— — tT> ^ fO
4-> CO/ ™ T3 CO (D
to cd / I
^ CD CD £rtf 4->|tr>
O T3 .n
'
in CD t7>
Cnna -h cJ
T3 did) 4-> C QJ > -HCD ct> a> •H ftC to tn c c ft a) -p o
-rH c <U T- O^CHH -HPH ft•H 1
f— r- »-, H+) o ra
<U a.
^^"^ ~~~~>^ m iw nra O h 3 \. _ CD O 3
to
ft.£S_ *t CO
1- qT^\^. V 4J CD Xi 4-1
P 0) X C 4-»
to CP.C x / m O rH•H C +J N. O O rH
UH 4J (CCD \^—"^-X °TOH1H t / Xi o•H O -H / C 4-> t?MHg - g olfc / o <a tJiJ CO(0 £43 rd * / r- C! CD -HM O 4-> Sh / D. CD -H 4-> XI>irH tr> >1 H > O+lft cd a ft 1 CD tn
43 a> rJ CD C -r-i Cas rH cd
C 43G 5 CD 4-1
0) O 3
°t1 \ 3 m o cd
U rH M rH— 4-> ft ft
CD
/O 0) X — CMi
XI £! S-l 4-1 S--r- L. «- CD CD TH. 3S CO 4-> O a H -P (d +J
121
+->
CS-
QJ+->
Gto CD
£ -H X! £O (U ft P oH O rH> (0 <u M CD
o.x; O X!0) CO P mTS g•H (U CD C 3 •
CO X! P S-l P COP CD (D ra en
T3 rH P 3cca P M CD
(0 -H g (0 m cXI O ft m
i g o CD <-< •
p 3 CD Xl ft CD
U-l P TJ XI P CO
CD CO C p a <cH 3 n! 'HO^M P "H
CD *W t3 U P CD
X! <D 3(UU£P (D T3 M O CD P
x: -h P (ti to
5 p > to m P(0 o C M (U-Hu m ^ o 3 x: ga o a U to P o
H£
W Wa CO £M <: eu
<!PQ o
en ^ wX < >a. s w
o CJ
< CD< w
h X su w H
K i-5
:>:
tD «C i-l
Er> <CO H! HD Eh Q«Pn 2
(N
PCD
gftO
P HU CD <D
rd > HP CD CD
co-ox:
03HCoft;
fei
XW
ai
-a
ft
CJ
O
CO
CO-HPrHoCO
122
•\^ ^^^ gE (0 a)
1 _^^_ \ 3 S rH XI srri r >^_j +-> oj a) a P o\ / l. n
—
10 •H o rH
\ / \—-U 3 > m oj M OJ
M-* X n i. &xi O XI1 ^--^j^ U_ <D W -P 14-1 Eh
-h <u ai G 3 w Wto x: p U -P Q CO S
-P OJ OJ to H < CU<0 rH •P 3 5* a Og g a. P M • <r ^qtJ-H E to m co K
3W
x: o cu co >H >i e o OJ C4 2 Wp 9 oj x: oj oj o QIH+J>0 x: -p g to < o0) to g -P (0 (0 <: WH3«! M-l M X! fc X S
S-i -p o a, O w HOJ 4-t T* u OJ K t-3
X! OJ 3 oj c x: S+J OJ T3 M o O P D rtj
3X! -H P (0 -H Eh& P > to IW P -p CO S3 Hto O G M O -H D &H QU M-l M 3 11) e « H
gq o cm O to to O En &_^ ,_^
H CN*
—
-p
c cS- OJ
<X) e*-> aJ-i o
OJ r-03 -P rH
M OJ
<0 >P flj OJ
CO T3 X! a.
Go
to
GO•H-P33 rH
a* O•r— CO
1 _
>
ai-a•r—
oo
</>\^- A \\ C
/ _±/ \ 03
\^
/\ / Q.co ^~~~~"---_ \ A/ki ^~~~-—^ \ /to ^""-~-.
.
>V /H +-> \ . x /^ c 5 \/ \/ce; o <uPq S-T- \H v \/
>< U. > COfcl
123
(b) Development ofright cones
Funcircumference = 2ttL
(360°)
There are two methodscommonly used for dev-eloping patterns ofconic shapes . Both areexplained below.
(1) The accurate method (Fig.l)
The true length of the slopingedge of the cone is L
.
Using as centre, an arc isdrawn of radius L
.
Before the circumference of thebase of the cone can be drawnalong this arc, angle 6 mustbe calculated as follows.
9 _ 360°ft
27Tr 2ttL
2-rrr 360°2-rrL
6 = j- x 360°
Fig.l
ise: Measure r and L (in milli-metres) from fig.l, calculateangle 6 , and check that thepattern is correctly drawn.
(2) The approximate method (Fig. 2)
An arc is drawn with ascentre and radius L as inmethod 1
.
The plan view is divided intoequal parts as shown. 12 partsare convenient, being easilyobtained using a 30° set-square.Distance d, which is the approx.length of the distance betweenpairs of points on the basecircle, is stepped off aroundthe arc 12 times to completethe development.The sketch below shows clearlythat a distance stepped off inthis way is the true length ofthe chord between the points andnot the true length of the arc.
Fig. 2
Exerc%se. Compare the pattern constructedby this method with the oneobtained using the accuratemethod by measuring theangles at 0.
124
DEVELOPMENT OF THE FRUSTUM OF A RIGHT CONE
Radial1 ines
Truelengthline 0-
(1) Develop the full surface areaby using either the approximatemethod or the accurate method.
(2)
(3)
(4)
Add radial lines as shown. Thesecorrespond to the radial linesdrawn on the surface of the cone.
From the points where the radiallines on the surface of the coneintersect the cutting plane SS
,
project horizontally to the truelength line e.g. 2 to 2
T , 3 to 3„ etc.
Swing these true lengths from Oto the corresponding radial lineson3T
the pattern, e.
to line 3 etc.to line 2
Frontview
Exercise: (5)
Note:
Plan
Complete the pattern by addingthe remaining points and joiningwith a heavy line.
All lengths on the pattern mustbe true lengths
.
The shortest edge is usuallyused as the joint line. In thiscase it is along line 0-1.
'As an aid to visualizing the shape of conicfrusta the construction of the front andplan views is illustrated and explained below.
Construction of plan view andside view of a conic frustum
Plan viewProject the points of inter-section of the radial linesand the cutting plane S-S fromthe front view to the corres-ponding radial lines in theplan as shown.
e.g. pointsg
to lines 6 and 8.
Side viewProject the points of inter-
* section of the radial linesand the cutting plane S-S fromthe front view to the corres-ponding radial lines in theside view as shown.
4e.g. points ,. to lines 4 and 10.
Exercises : Complete the planand side view.
Solns
.
RADIAL LINE DEVELOPMENT p. 175
125
EXERCISES
Completecone
\\ Sidevi ew
Solutionson p. 176.
(1) Complete the development of the pattern of the surfacearea of the frustum in the space provided.
(2) Complete the plan view.(3) Complete the side view. RADIAL LINE
DEVELOPMENT
126
to •
-fc
anX.
the
ution
p.
177
T " s>*i-
o <us- -r-
,
—
-
r- X rHo. m o C^^^^x Li_ > ^>sro p o WO
oo
/ ^\ rd •
C rd 3 -dk ^ O rH -P <D tf
_. H ClOtJ WV™ +j rJ -h q
L *^ '^
OJ/ \ / \ o m u > !s
\ (U rH IW O H\ 01 fd M i-3
I1
I
—
\ 0) £ • ut \ 4J <U -P (U 0)
1 ci x: o c <c1
'*:—i i) it (it I
'
'
I O Q.rH CJ/ m c mh w z/ O -H 4J H H*"—
\
\.—^"/ CHIC H 2
\ ^ ^^\ / (D (D ^ Jd -H U W/ >>Q)-UO W g
\ "V. / S-i M -P -r-i W CU^ 3 3 4-> G Pn O
O O ftJ -H 0) W i-3
*\ a x: eh w
0) (U M -P IS >,c £ a) <u h w+J -P Xi CU w Qp Pu to a;/ x -^ (1) 0) O WW4J -p ft^ x & a0) 0) O 1 Pn Hs HHH Of O 1-3
cu & a) -h a-
a g > c <u jO O <D O CO O <UOQUO H H
1 ><^^ ^^ 2 Q(U
ll "\ ^^.^ o <^v rH CN CO UKc:
•i—^\ —— —
r—
-C+->
OlC<u / /"'—""*
'— / _^—;—^. y^
*y^''° '^"'- y \ COCD y£ sfy- . • < \ <u-3 / ^S- / ' 1 \ '
"" ~
\ "H1— /\ ""^
\ Cn •X\. \_ \ C O
\ -H +J
\ t3 0),/
\ G^sss^' ,/
\ O -CO / / N^ D)(Nfcl CO
CO s,^ o
Cj ^\ ^y. Q) C '"" r4
ft: "\\ \ /\ > •H T3 O <Nfci \ / \ U C oX \ / \^ 3 C <d
i f^ -fc) V. \ / ^s. O
drawiew
e
to
to
1
XI ^^^/' > / •-•
<U / OHrl 0) / U
,1 ^~^*r \ «
x
fO T3 • / -rl •-—"V^^ I H X •H G\. / O tji^^ / +• CO CO ^ ^\ /^^ / -^ c <U O ^\ / 0)0)£ ' / O O CO£ rH W •£
rH -H •h c co m V -p ^ro Pj-P rH rrj +> X ^ rH CD
1 / X CJ CO C CO <U «J = -HN ^ / / V^«J. r4 <D
O 01
rH^fd O -p-H.H-P>Id QJ N<U rCJC> rCJ3^S^^S'^*^ ^/ ( v\^^^ ^^ >H 1 \ *H M H -H rc( .H j^ fjj .H (d O +J^^ "^ ^ 1 <D rO><D r4td-POQ)M= C
CM ^ ^^ 11 (1)C y -O -P rd U O U pLirQ O^^^ m-i c (0-^ \ yv o c tt-Pd) K01Q) H (Dili rl1^ 10 -H rH . ... _ V>^ ^ x: -h C^ (D-ngWrHCDMHS* ^ -S -p
a) m— o g -^coo cuerHS-13 N'HMrlfl^Tlfl
£S«S 5> ^" *° ^ MH C ^- rH 04^ -H ^ rH -H
127
0} •
C ooO r-•H r-(
CD P •
X! 3 ft-P
U o cC CD • co o•H -P T3
P CD
EH
C fd 'd DO ft-H aH >+J CD O
§U .d mCD -P ft <U) D^1 M-l CD aCD U CO-P rfl
c 4J ft <-H • C W
CD CD C3IW > 6 CD 2O O ft.£ H B
X! O -P H 20) rO iH U W> CD C W S3U fi > -H CO CM3 & <D Pi oo O TJ H w tJ
.c CD tX wc CD CO CO ft 2 >co A X ft H wr— -P £ -P O QD. <D .C a
0) H CD w W-p > -P <D CM 2CD <!)£ CM H>-) -P -H -P o ^a. c ft ECe O g H l-q
o U U <O M-l u m H H2 a
^—n ^-N O <rH CN u tf
tofel
toHtoft;
ccs*!
Ed
ci.
ai
IS> >
128
CO
G tn0) d) O r-m t3 A <u •H rH
o -h uC CO o d>
pp
p •
3 »45 ^ ? m > "O tn rH
s nj P 0) +) Q) 4J G C M O G<u j-i o co co g x! -h •H O • w o•r— T3 X! ffl 3 -H+J CO rH CO M-4 ^> •HO (0 >i
dj-pcuo) <d ft g o3 d)
c -a
r l—
H
CL) X! (tf rH X) • -H -H CO >1 V< -Ho X! O = p G M d) XI d) >•r— c-p ^ >iC c o c to x: • -P oGO nS -h n) O o> iH S d) -P C >i-P M
o ooog-wcn-po a oh ni ftco p c o x: & m-i •H CO ft/^^k 1 \ ^^ — <d c o ro d> to as o -P 3 d)
d) CO X! O d) +) (0 O O d) oSstz
MPP-HCQ V401 H tt) (U -H X! rtJ
tt) G +* ^ ^ D m i g CO > +J ftX! d) O O d> tt) -P U -HQ,CP3PCC^ | rH
U d) CO
d) M U-4
COO H G G -H O H 1 P ft O tt)
ftr-l .p -H -H ^ d) c x:
O>i e fO CO d) G M -H G -P +J
\^^T I *r^— MO-Hcmcuxico o p 5 c(cjo-poox:-p<u -h g m o tt) cG CO +) G -P d) o x! e -hH Old) d) O "H O O CO ft &Hen G tn«n > ih+jh a) = O d) a
1—
1
i
—
(0-HCnJMO co tt) (PBrlC•r—
-t->
g -P (0 -H 3 <tj rH H ,G-Ho-Pooio<o<ti tt) -P
d) d) = +J C -H -P
> O tt) OM X! > O3 -p tt) o
, C C 01 0) 04 C-H+J c ^ O d) tf d) 1-1
fO <- L (U in (0S-)J-lCQd)-HOC -H O = e x w•r— <D CD 0> ^d)td ^Jo-ntt) «rH d) -p >+-> —*~
+-> C C P Id-P ft 0> M-ICOd)cucco a>c oa)^3
co 0) x:•H G -P M-l
wac 3 lO-r
S- d) CO o +-> <— tH-Hd)^Q)c!JqHj c X! -H Ocu cr> cu o tncusonj-p •=-HC0 P rH d) wGEE r^--** > i-t O 13 > -H -H d) d) rH -H p g 2C (O •- 1 -HSd)06-P-^H>> >*•-* tt) 3 Hr-4 +-> r— r-» OP X!MOH(UOJH-PO
d) (0 d) <lJ^'P tQ 3i|m rd rH -P•H -H ft CO
r^
fl CO Pco 3 nj o t? m -a e 3 (-}
1 1 ^s^->•H -H C d) ^ CO O = -H •• tt) nJ o U <<C^CO^'OCUd) ^ IS d) > j-i U m Hd)-PPO Pfid)d)d)MP Q
^ -h 3 £ o c-hxj-h^ipo ^^ —
»
<S5OC0PHrHP>EHC0|S rH CN «t—ll
..
U3^- 03
« ^^^\ to
xri^s^ \ •^o
wCO •*»/ \ \
< aJ n/ \ \ \ Q< 2H HU i-3
w CM / \^ \ \ \ X04 uco
<:
<: / .X/^\ a ;C \ \ \_ l"xv >C / \ \ \ \ oi /cm/ - / \/ \ \ \ \
7--- ro/ /\ \ \ \ \
2H
w L *"/ ^^ \ \ \ \ /^ / \ 1 / \ BPi
i i
Zi^S' \ N^ \ \ \ uw ! ^^*" i^^S^^ \ \ \ \ \ w
CO04
CO w\ c: Eh
<L- fQ S3H1 r—
&, / °-M Oi
2 wwu (M
1 \—^vso^""*^to\ / / ^ P4
o2 ^^^^^ 3 Eo co ^-'^ d)
o>
LO .^ CO
*
u -t-> (H
w o oK S- uEn U-
129
rHCD
rH^""^/ \
^rH
X^ td
Sh
id . CD
/ \. ' \. ft G X GO •P CD
1 XP tn •
O td •-i CC+JC CD •H O
U CD O CD
en P G G SH
•H CD -G -H £ en id
PI• g tn rH O -H
tn • P • id rl XCD CD •H ^ en Sh m tn < •
V \/""""T"""
~-A-k< / rr>rHtn td
CD
(D -H CD
OCD •
Otn tJ -P
G rH en > si X! CD — • id (D CD\ j\ IP id ft p P G Eh CN .*
"\NJ
-H id C •rl rH tn Sh -
Sh
-PrHtd
u id
CD rH oOH-P
CD
GCD id prH g^^ xi \
p X! ftm CD ,G •H tn-- "^N^^"*' HH • c 5 tn P rH G CD u
O S o G CD G CD td tn id rH
OtO f-i
N•H
to si id
rH P rH•H X! G> CD
HHo
•H tn «. Sh g m
CD CD u ft a CD rH "SJ1 -P id
•H XJ o Sh P .G .—
.
•h tn
tn CD Sh £! U O Sh G P CD CD EH CD Sh CD
G > CD CD O O G G CN ft-P rHtfl -H td >1 tn on CD Z Sh tn Sh •rl id tnp tn x CD rH id JC 5 CD 5 UH G P rH X CD GG G OHH G id ft P CD -rH CD O X tn X id
<D X CD CD rd CD •H > •H rH CD IM p -P -Hc ft o HHO CD O CD o > > Si id jG o tn <D Sh
o o • -h tn w ftrH -H en tn -P si p -P P P G 3 ^EhftrH en x c cd rd x id C P P C P , V CD Sh ^g (1) 13 ^ H rH G Sh ft en •H rH C O G g M en Eh rH P rHo > o oi a id rd id rH C CD O SH O O — -rH ^r •
u o£ in a g •H ft M 'O o f-{ Sh m Sh Sh—
CD U CD CD
13 P P tfl -P tJi rH CD CD rH m m IHC-O G CD G tnM-i CD O TS X •H G O G T> f4 td CD id CD X Sh X -H T3O O g 3 CD CD CO CD X! CD •H •h id Sh cu x: CD — rH g P P P rH CD
-P 13 ft G CD -P g rH > rH id£-M£ > ft Vh tn CD•—
en CD O en id & M -H •H ft ftp p — G CD tn X •
CdlC^Hfi Sh P O i-H HH • •a Sh CD HH CD X O g O GV-l .H -H CD CD -H P CD O o CD en Sh CD y> rH X!' rH P -P id id £CD X3 r-\ X > £ XI G HH o w si •H CD Si <D P en CD CD OP -H P CD id S O x <Xi •H +) Si P si CD G CD >i tn tn XP CO rH CD 13 iH cn id p P P -H p • G g x! G HH G Sh en
id 0) Id tn >H en G Sh • P tr> CD P C •H H CD •rl rH •HOP Sh •H •H (DOftO-HO 0) O & O 13 £ X G XI C -H CD CD rH SH P Sh G X MH W
ftTJ P X! 4-1 O -H O fji CD CD CD C CD 4H CD CD •H +J id
a g to Si -P W rH •H rH p C i< tn G -H G G m r-\ CD > O XO -H Sh G >i CD W O -H CD CD en o •H •rl •rl O -H tnx: •n g +J CD
H -H (d£ CD X) X CD • 3 ft'O td CD rH G P «. O tn OCD Sh M O g P cd cn -P si £ g g CD o si G si P CD id G >tHCC> O •(-> -P G CD CD -p O O X CD P td p m Si C-rl O O Xi m cd cd
CD - G •H CD CD tn X! rH M O Sh X! tn rH tn o tn-H sh tn •H rH GT) P CD x! cn -H en U G id -P • CO CD id G ft G •HH+J <-i P T3 tn tJ
1
rH G O G o id o & s •h xi xi CD g si CD CD CD to O CD G CD CD
O 3 -h -H O C a 3 a< cn O c X! p rH t-\ •-^ p Si 4H CD G ft-H G tn
P U rH X -H 5 ft O1 g CD •H rH K & id -P CD tn td tn O X en Sh O -P Sh
•H £ P o tn o x! CD CD iH C CD U CD G rH P H P rH Sh h-> -P13 HH -H o si O -P > XI CD •H > i*h tn CD 3 -H G- CD to X en CD Id OCD HH CD - CD cn S G > o c <-\ M P SH rH O P MH P G > -P CD <D
w -h rH tn en CD £ CD G CD £ •H c id P S-l P •H tn O •H O CD W X SH
S T) rH (D | CO •H P g O g CD rH c CD id -h CD CD CD P G O 13 -P 5Hid o to id > id •H •H id CD CD Sh 3 td > td G Sh CD CD O
tn cd n cd cn tn en cd rH > rH rH S Sh -P Sh sh CD >H en rH CD en • tn O•H X! id -H G H+J r-i id ft-p id P PlCD p P > G ft s rl £ G
ftftkO id O CD ft rH p P CD CD olsi o CD CD g rd O -H CD
13 13 O -H -H CD X g id G G CD XI CD si td GIP G CD CD si G t0 in G rH tn XrH CD Z P Sh G Eh rd o o o x U P Si XI P CD X Sh CD G P
. X 3iO+J id O G X •H Sh N P CD id en tn o en p P P CD CD CD XtP O P H G rH P O CD •P HH •H rH m u -H •H P •rl m o X •P 13 GCD & Eh CD G CJ O • SH Sh G tn U CD T3 P m ft tn p -p CD CD -H
cg U M SH CJl •h en <D CD CD O -H Pi
rj T3 CO <-\ CN G O O >i-H rd rH -p^ men <u c ftX CD Si > X! si id en -h •rl CD XX tn ft ft O 13
to o x! S m td V G P •P G en CD CD CD MH -n ft p G g G <D•rl -H +J fi >H -rl
Si Si -H « -H Sh
CD -H (d CD <D CD CD CD C C G G O CD CD H CD rd Sh TJ^J5HC Si G X! CD Si £ O •H H •rl O U P X G tn X X -P 13"£ En £ CD £h 13 P Eh £ ft-H Eh •H EH cn Eh Eh U r-H hH rH Eh &4 CO Eh H D En CD en rd
CD^mmim
3 +i
0)s
c s
CD "X5
O'i_ ^ 0)
H CD
130
a ooo
u •H rH
o -p •
c cu
tow
3 CUrHo c
M O <cto
0) CU J-P -H ft-p a.ns W J&. c ft wo < »4
CU -H tD J S3.£ -P o2 o-P -H CO ft H
CO <CU c O ft-P (0 End) M £H -P w wa ft wg 0) < so x\ D EhU -P aw
co pq
Eh
D
HftEh
WUWHft
OHEhHCO
3
H-00
cu
MtO
cu
c in-HiH -a
cCU (0 •
4^ £-P ro <u
•HC >i >O rH
G GW (0
CU rHG -a a•H • curH d) >H cu
c cu x;CD -H •9 +1
£ rH g-P 3 c
CU C "HH £!a) -p CO CO
XI CU X\
r- 6 ° a -p
« 3 4J •h tn•° C -H CIT >h CU°- CO (0 CU rH
>i CU X!(C c -P cu
s 3r-i s-i m ^< o O 4->
a)-p
S3
131
COfel
COH +jCj s= 3ft; o a>
fei i- -r-
X Ll_ >k)
o c -P3 -p •H enc .H c
n 0)
w to Q) iH>> cu x;trt c -P <u
£ 3m M m M< o o -P
132
. rHc 00rH rHo c •
M-lto o a,
OU
10 o w£} IH wP
C CD §C U O ^CD CD 0) o<t-\ • P -H
CM P & JCD rd
T3 &£H C o < ^ 2P f0 CD -H O
.£ P HCU -H P -H CO < EH£1 W a. <P - CD C o r-3
O P (0 eh s D>i JH w Om en .H P Q W *pr.
H (U a s s <in c e <u !=> EH MCD -H O Xi O W tf> -H O P tf oa EH
CN
a)
ai
P-H
P•h x\o P& o
o
•Ho
CO
(0
+>C7>
cCU,—
cu
3£= S-
S- •4->
a>+j cu
-t-> J/J
<o ZOD_
CO
toHft;
fei
xfa
cu
+->
oS-
CD
C «* •
-H SrH TJ CD
c •HCD fO >.GP n
(0
C >1>HO rH O.
(0 o CD
CD X!C TS P•H • CDrH CD Jh C
C CD •HCD -HX! rH i cn
P 3 XiCD c P
,- ^-^ tnC (U P CO C- -i
CD CD
O C rH^ p P •Hc rH CD
M 3w (0 CD 5H
>i CD .C PCO a PS CDrH S-I MH (H
< o o CO
• •
CD
-POS3
J
133
oo
E
00
OCO 04
CD
si-P
Mw co
m u wC
w 53
Sh Ph i-q
cu O O4-p • 53 53-P cu O D ^(0 o HOWOh CD Eh Oh hh
•H M J 3Q) Dj W O <J o-d H-P c 3 <K W Oh
Ho rt!
<D -rH EH r3 J-p -p O Z D0) -H Eh 53 W OrH CO W 5] W 5304 C CO Eh & <e nj hUEn HO H fa w w «O -P O CU PQ Eh
COCdJ
QJ
S-
//
y^ V-y
y
coH
><!
VK^_
/
-©-
E
I/O
cu
Os_
3 10sz s- .cs_ +-> +->
CD CD-P QJ C+-> (/> <ufa rs i—q. —
tdc CL)
(0 • •PrH CO (0
04 .G SH
P CD -P •
<U CP.Q CO cu
£ c >-P cu P rH o
rH CO rH 42C 3 •H tO
•H a) fc
3 >i^13 !h (0 rHQ) •P (U en >dM C 3 c0) CD •H o (0
irt rH •H(0 > rH
3 H cu
C r- a) SH «h
si PhOco na -P »
cu C o a) •
c (0 si CJ1
C -H m -p •
(O rH n o>i
cu
Q- CU *. co xi cx: cm si o-p -P 'O •H
>i tJ. 0) +J
m rH C c CJ
o c cu •H 3O rH b Sh
•• >h -p<D £ a) a) CO
-P 0) 3 -p aO •H M cu o53 > Eh 'O CJ
134
X-±N. CU
//t\\ >^? \'\ X!
VSR/>^ / \ \ Pv^ / LS^r-\ U
1
fa CO— I o
i
/ *" u ww sf~\ r \
VTl/ V Y^ i L / G h <;
\ ' 1 / n di j\ i / 1 i ^L^f5
' / / / <N cu
M^ 1 -p •
O rfi Jl / —/
j~ ,Q-7if/ iii / P CU
/ (0 O H > faI --, 1 > L / / ft CU EHO J
' -H H J IS<D ft CO o < o
2 eh a h.fl
r^^A i^ / P c < < Eha w en </ ^^^y / N / o
c: P PEH l-H JOS D
(11
oo
CU -H En S W • OiH W w < w-. . ISft fl CO En !2 <Cg to fa O Eh HO M fa fa W «OKM EhU P^^i-H
CNC corH rHO C •
CO o ft
<u^3 t/>
in X c s- .C4J+> fl)
S_ +-> 4->
G -H > cu enh ;? }h
~ +-> cu cO 3 +-> CO cu
ft c o lODr-u Q.
(h<ax:O P P 1-
p p o t>-"^ K^ 1/0
m o ^^^ ^^^c ft g•H CO /^\ ^^
V) O HH H}-bOU CN o
CD r-
CUcu H- Jj
f
o rrj
d) /^y^ ^_^_—-~C3
1
0) P •;3 £ ,Q W <Us_
re CU 3 >r- \ M P rH O
ftJ CO <-\ Xi\ CU
OO1
C -H tO
!
1uo •H IT) g
T3 X! CQ rHt~r\ .^ "/// (DC <U CO t)o ,
--', U (0 CSC^^ / cu -h o fd
in fN^f .
•=*/
///oo LO
^ CN rH -H
3 «• rl CU
x i/^X / fl rH Q) M ^
~ / | / ix / x: fto3 W >i P*_ °
cu// /_ o (D rH O d) •
r" c c s: cr>>i •HO l»H P •—
+->C rH o a>
C o >— CU 0) CO CO ,Q CoI
o Cl. £i -H £1 XI OS-
\ p > +J +J rrj -H
g Li_ \ '
tn tn CU Pfel <a \ y MH C fl C C Ooa
CU \^ ^y O n3 CU CU -r) 3H oo ^—i
—
^ rH rH rH g Mct;
••ft in PCU CU CU CU CO
fci +J 0) 3 3 P c>< O .fl !h (h CU Ofc) •S +J 4J Eh T3 O
135
Solutions
In this section a solution is given for each of the exercises
presented in the text. Each solution is identified by the
page number on which the exercise appears. The solutions
are arranged in the order in which the exercises are set.
Where an exercise has specifically requested a sketch
or tracing the solution is sketched or traced freehand.
Where it is felt, however, that an accurate representation
makes it easier to understand the solutions they have been
drawn to scale using instruments. On some of the more com-
plicated solutions notes have been added in order to emphas-
ize important points.
The Isometric and Oblique solutions shown are those
thought to provide most detail. As explained in the text
there is not necessarily a unique solution for each of these
exercises.
Similarly the solution given for each of the dimension-
ing exercises may not be the only correct solution. The
alternatives must, however, not only meet the requirements
of the exercise but also obey the "rules" of dimensioning.
If cardboard or paper models are made of each of the
development solutions and folded into the three-dimensional
shape indicated in the corresponding exercise then these
solutions can be easily and convincingly verified. Notice
that all lines on the patterns are, as emphasized in the
text, "true length" lines.
136
Solutions: First AngleOrthographic Projection
Onpage7
Drg. Reason for incorrect interpretation
1Plan incorrectly positioned. It should be below F.
2 Plan incorrectly positioned. It should be projected below F.
3 Plan and side view incorrectly positioned. They shouldbe interchanged.
4 Side view out of position. It should be projected from F.
5 Plan incorrectly positioned. It should be projected below F.
6 Plan incorrectly drawn. The cut away should be at thefront of P.
7 Side view incorrectly drawn. The cut away should behidden detail.
8 Side view positioned incorrectly. It should be drawn onthe right hand side of F.
9 Plan drawn incorrectly. The cut away should be atthe rear of P.
On page 9 On page 8 Note These are sketched freehand.
2
3
C
D
K
1
6
i
MB » _ «
4
5
L
F
8 1
i- -
6
7
H
A
5
On page 10
8
9
10
II
B
G
J
I
Drawing A B C D E F
Front view indirection of F 10 1 1 1 4 7 6
Plan view indirection of P 14 17 8 3 1 8 9
12 F
Side view indirection of R 5 16 2 12 13 15
137
;
I
; ; i
J—U-J—
.
CO CD
WO)
•H
-p
tr-
CHen
•H
g
O
do-H
•H
TS
£
B
—
i
CN LO OO
QJ
CD«Q.
o
to
QJ
10
oi_
OJ
XQJ
O+->
</>
o+->
oOO
I
izzr
| i
1
i
i
i I i
r^
138
Solutions to exercises on pages 12 and 13 (sketched freehand)
L L
!!
4F
i_T7frr
1 1\\ i
z- Pj—"D
—
r
— i-—
i
L
7 8
1
— •}
S$s nnin
ID[¥
run Eb
Ttr-M-l
139
z — CO —-z. z Z — z:
Q. U_
— (NJ 00 -=3" LO <X> r» CX) CD
IV
ic enco
I | O (O i—
1 1
Q.
i i
fa
iw
c •
O
CD
•H
CD
•HIM4*
l
1
to to
1 _l• • •
0) 1 o • rt i-q1I^M .£ C
CO
oco
a*
Q.
to x: CD
(0
PO
to
en
rd
cu
XT3
T3CD
OHrHn
i c rH rH rHL •
1
P 3o
CL rH
i\
a(0
~4> _ — _—u_
M-l
O
ft
4-1
I
Xto
P
CD
XIH
(d
*sP
o
a;
Cn
CD
-H
1
HO
CD
X
8)
tn-H
> XirHCn
O H 0) X 3rH rd «w >icd c a O (C .CX O c T3 5 0)
(0 Q) CD•
rt
4-1 TS ^ O d fi< C>4
O CD
C Ord
rH to
PU
p4-1
CD
> H"^ _
_l1 -H
fa
<d
rHOX >1
td<U T3 cd P rd 5-1 e, &D1
CD C> (0
£1p g
& >1iH rd
rd
^^ a. M c P 5-i PCDC
4-1 5-1 o OCD
a 3O
o O T3 >i•d m 0) P T3 <D •H rH tn
< m CD 4-1
pX!
a;a)
p (0
a -PO •H
0) CD <-<o(0 0)
rHCD
CD
S-i
PC
"0 1-1 -po oJ-i 0) xi
X! •nOU H
o
rH
UOO
CD
to
CD1
Oa> s-i
to
5-1
a,
a) CD
O4
CD
•Hua.CD1
en XI a cd TJ X H X tn i-i
T3 0) > 10 t)>
-O-H
CDH XI •H H CD rH s c3 <D 3 T3 3 CD •H
(0 O T3 TS C o -H •H Hx: H •H rd ,G 0) 4^ >
c 10 3 0) r-1 03 CO co &! P P CD
(0 en
PCD (0
Si1
k H 0) £ rH •H rH S-l •rH
+* \ (U Pi ^ EH ft, OJ ftl Cu a
31\
(0
| \D_ Li.
rH CN n •«tf ID >X> r» 00 o^
' CD
O <TJ r—Q.«=»
140
Solutions to exercises on page 19 Addition of missing views,
ThirdR . H . 5
Third [~Front L.
Fi rstL.H.S.
—i
—
i
l
—
J—•
ThirdPlan
FirstFront
ThirdFront
8
FirstFront
ThirdFront i
*
FirstFront
i h
Solution toexercise 1
on page 20
+-r TTTi '
-M
Note
These viev/saresketchedfreehand
I—
r-
141
I
142
o•H •
jC XiLO a c
m CU rd
CD tp S-l M ,£t/1 C tP rd CU
•r- •H CU
O CO X! CO Ms- d -P S m01 U CU
X CO O •H xi<u
CU
>xi
o •rH 0) • CU o+-> o > rH C CO p
CM tP O CU cu
c rH C! -H xi Mo CU (0 < P EH CO
•1™ o> C O4-> <0 u Xi 0)
3 Q. CU M •n CU
r— -p •H O po c X Xi U u1/1 o w Eh ih Xi
<*
^
T1
1
1
1
H-JJ.
ii ^ n
!L
T
"\
v-
143
Solutions: Sectioning Exercises on page 25
I
y///.
v/fr%First angle Third angle
r7T//A
Third angle
if
m^m
Third angle
Third angle
8
First angle
SSSQ3
*&Z2
r
-4j id
<D-
Solutions to sectioning
exercises on page 26
Solutions to sectioning
exercises on page 27
H
A
7
D
M
K
N
L
8
10
K
H
N
M 7
J
R
B
L
4
8
144
Solutions to sectioning exercises on page 28
i7-7-
iV/V/. i
// '///A X/////S
'/, tSection CC Section BB
/////
////
/////
//',
///
--h
E
J 4-
///
zz
Section DD End View FF Section EE
Solutions to sectioning exercises on page 29
'//Third angle
%^Third angle
Third angle
^ %\'////////
i
-11
L^ |
Third angle
145
Solutions to sectioning exercises on page 30
Third angle
Third angle
Va y/'/\ t
//
AU
'a
/ri
Third angle
'-VAAAAW//
iV/
1.
Third angle
Note: In exercise 1 there is no bolt in the threaded hole,so the section lines cross the thread.
Solutions to sectioning exercises on page 31
Thi rd angle
lj/A I 1
Vz
zz]A//
Third angle
Third angle
xaI
x///y
_d
Third angle
V
146
Solutions to sectioning exercises on page 32
V
-d
A sectional Front View looking on cutting plane CC
/}
/"
/
/
// '/,.
A sectional Side View lookingon cutting plane AA
//A
A sectional Side View lookingon cutting plane BB
Ld J
A sectional Side View lookingon cutting plane DD
Third Angle Orthographic projection £}
147
53 inO 3HEn a) T3
•H
«; CO cd rdto En rd a) UQJ s PQ M10 w U < < U <: U cq << CQ o A P J2*r- 00 r- r~ ro CO in ro in rH ro in -P OJ COO w -P rH 3S- PS O EH r-i PQ<L) ft O X •HXQJ
Ph w Ph <• • • •
OH->
rs,
o
in OrH
inrH
OCN
(/) «* r-H CM ro ^ in vo r^ 00 CTl o r-iE H rH Oo OJ Eh §'r- C7> 534-> res pa
> CO3 Q.*
—
53 uO £ o CP CD COCO o u
to
CO
OCQ
f4•rH
o
a
•pcu
srd
•HQ
CU
U
ccu
u• • • .
«* CTv 3" CT>
0)
r-H rH
rH(/> -H•r-
CO rdo53O u < Q CJ PQ Q ca U Q < U <
pcu
OJ "tf rH rH vo ^ in rH CN cn *r m VO -P TJXQJ
HC
M 0) "OO > CD 1313
rt
•H4-> ,QUD •H c •rl X3
to ** Pi 1=1 w Ehco QJ rH CN ro •<* in vo r- CO cm O rH CN 9 • . •
•r— en rH rH rH ro oo ro CO+-> IO rH r-t
oco o
CO
QJCJ>
cu
•HrH
a)
CU
Ord
cu
rH•pCU
er)u
<a -P cu -P rHCL
0) rrj
O t-i
•rH
CD Ocj B W a
to - • • • •
•r- CD CN r- CN r-o to rH r-HS-
oQ Q CQ C_> CQ < < CQ U o •r—
0J IT) •* V£> rH t-\ ro <-\ in vo in UX s- cu rHOJ 1-3
o53
aj a) C rH
oX d rd 3
G0J •H rH4->
LOH
orH Ph ^
OJto «=f W
Eh
+-> C tP tf rHc O c c: Oo OJ i-H CM ro >* m vo r- oo CTv O to •H •H o x;•r- CD rH c •P P e+-> re o o P rd i<13 Q. r-
-t->
cu
COPi •H
QCOuo £= 13
CO OoCO
rH VOrH rH
148
Solutions: Pictorial Drawing isometric ex. P a ge 52
Solutions to exercises on page 53
149
Solutions to exercises on page 54
Note In these, and the preceding exercises dealing with isometricprojection, each component has been viewed in the directionwhich shows the most detail.
150
Solutions to exercises on page 58
Note Each view has been drawn looking the directions indicatedin the exercise. These were chosen so as to show the mostdetail in the pictorial view. All solutions have been drawnusing either an isometric grid or a framework of lines as in 2.
151
Solutions to exercises on page 59
Note Each solution has been sketched freehand on an isometric grid.The resulting pictorial views are those which show the mostdetail of each component.
\l-"'l\U"' \i-" |\1.-"'|\U-
152
OBLIQUE Solutions to exercises on page 66 (drawings on page 52)
F^^_^ b-i
Solutions to exercises on page 66 (drawings on page 53)
XK ££\
^e
153
Solutions to exercises on page 66 (drawings on page 54)
Note In these, and the preceding exercises dealing with obliqueprojection, each component has been viewed in the directionwhich shows the most detail.
154
Solutions:Dimensioning
Solutions toexercises on page 72
74
and 75
28
Note
The solutions given areideally spaced becausethere is adequate spacefor dimension linesand numbers
.
On an engineering drawing,other lines may reducethe amount of spaceavailable for dimensionsand care must be taken toensure that lines andnumbers are clear and donot clash with any otherdetail.This is particularly thecase with circles andradii when the dimensionis often taken outsidethe circle or the radius.
20
\25
-^ ta>
20/ / / / /ov / s / s
\
r
15 6 7
see page 72
06
^<f>20
see page 74
R5RIO R20
see page 75
155
Solutions to
exercises on
e 7880
d 20 REAM
/
40
R20 >
1
^Ltn
MATL-I5mm MILD STEEL.
<f>30 REAM
R25
MATL - 15 mm MILD STEEL.
156
o
^8.
OJ
</>
•i—
O5-
<U
X<u
o+-> o>
r~co QJ
*T— O)•M <o=3 Q.
i—
-
o EOO o
o
h-IP<tu
I
-J
s
$#
157
Solutions to
exercises on
page 80
-E3-
40
—\— 2x4-5°
30
3 HOLES EQUI-SPACCD
4 DRILL THROUCH
MACHINE ALL OVER
•e
MACHINE ALL OVER
R7
RI5
2 MOLES 5 CSKAT 90° TO ft 10
h-c
158
Solutions to exercises
on page 81
#-£3-
2 HOLESM6-6H
10 10
MATL- BRASS.
€3#
SPHERER8
30
25
*"^
20
/T
^ ALL RADot-oou
7II 2^
2*4-51,
(50)
•
/
5
40
RIO
Note
In this view, the heavyline of the root dia-meter is in front ofthe fine line circleof the thread.
FINEDIAMONDKNURL
MI0-6g
.2x4-5°
Note: The brackets indicate that this isan AUXILIARY dimensiongiven for information only
159
50
st>so
NOTE - ALL FILLET RADII 3 RI8-
e2 HOLES 4> 8DRILL THROUGH
•i a
"TV9
tf/6
040MI2-6H 16 MIN LENGTHFULL THREAD S'FACE $ 20
ALL DIMENSIONSMILLIMETRES.
Solution to exercise on page 82
In this exercise, an end view of the casting could have been used forindicating several of the above dimensions, but it is possible tofully dimension the component using two views only. There might wellbe other arrangements of the dimensions which would be quite satisfac-tory providing that the "rules" of dimensioning are observed and thata clear distinction is made between size and location dimensions.
160
Solutions: Limits and FitsSpecimen solutions to exercises on page 90
Note: All sizes are in millimetres.The decimal point is on the base line.
H7-g6
Hole Shaft
Basi c
Si zeES+
EI Max.Si ze
Min.Si ze
BasicSize
es ei Max
.
Si zeMin.Si ze
10 0.015 10.015 10.000 10 0.005 0.014 9.995 9.986
15 0.018 15.018 15.000 15 0.006 0.017 14.994 14.983
25 0.021 25.021 25.000 25 0.007 0.020 24.993 24.980
40 0.025 40.025 40.000 40 0.009 0.025 39.991 39.975
65 0.030 65.030 65.000 65 0.010 0.029 64.990 64.971
H7-s6
H7-k6
Hole Shaft
BasicSi ze
ES+
EI Max
.
Si zeMin.Si ze
BasicSi ze
es+
ei+
Max.Si ze
Min. .
Si ze
8 0.015 8.015 8.000 8 0.032 0.023 8.032 8.023
18 0.018 18.018 18.000 18 0.039 0.028 18.039 18.028
28 0.021 28.021 28.000 28 0.048 0.035 28.048 28.035
38 0.025 38.025 38.000 38 0.059 0.043 38.059 38.043
78 0.030 78.030 78.000 78 0.078 0.050 78.078 78.050
Hole Shaft
Basi c
Si zeES+
EI Max
.
Si zeMin.Si ze
BasicSi ze
es+
ei+
Max.Si ze
Mi n .
Si ze
7 0.015 7.015 7.000 7 0.010 0.001 7.010 7.001
11 0.018 11 .018 11 .000 11 0.012 0.001 11.012 11 .001
20 0.021 20.021 20.000 20 0.015 0.002 20.015 20.002
50 0.025 50.025 50.000 50 0.018 0.002 50.018 50.002
70 0.030 70.030 70.000 70 0.021 0.002 70.021 70.002
161
Solutions: Sectioned Assemblies
s^ffSS
Exercises on pages 99 and 100
On page 99
(1) Sectioned assembly looking on
cutting plane CC,
Note :
Although the screw lies in the
cutting plane it is not sectioned
when cut longitudinally
(i.e. along its length).
On page 99
(2) Sectioned assembly looking on
cutting plane CC.
Note :
The pin, nut and washer are
not sectioned.
The spacer is not considered
to be the same as a washer
and is sectioned in this case.
On page 100
(3) Sectioned assembly looking on
cutting plane CC.
Note :
The hinge pin lies across the
cutting plane and is sectioned
when cut transversely.
162
Solutions to Sectioned Assembly Exercises on pages 100, 101 and 102
On page 100
(4) Sectioned assembly
looking on cutting
plane CC.
Note ;
The thin steel liners
are sectioned by
single thick lines
On page 101
(5) Sectioned assembly
looking on cutting
plane CC.
Note :
As the Vee grooves are
at 4 5°, the section
lines may be drawn at
an angle other than
the normal 45°.
On page 102
(6) Sectioned
assembly
looking on
cutting
plane CC.
163
Solutions to Sectioned Assembly Exercises on pages 103 and 104
On page 103
(7) Sectioned Assembly looking on
cutting plane CC.
Note :
The grease nipple is similar to a nut
and need not be sectioned.
The ball race is shown in the
conventional manner. See page 41.
^
On page 104
(8) Sectioned Assembly
looking on cutting
pi ane CC
.
164
Solutions: Developments: Parallel Line
In the solutions of development exercises, the followingnotes will be useful:
(1) Types of line. Outlines
Bend lines
Construction lines
(2) All the prisms, cylinders, pyramids, cones and transitionpieces are hollow, thus no section lines are requiredon cut surfaces.
(3) The development of a sheet metal component can be shownto be correct by forming the required shape from thepattern. A tracing can be made of each solution andtransferred to thin card from which the pattern canbe cut. An allowance must be made for extra materialalong fixing edges. See the example on page 105.The card folds more easily if the bend lines are scoredon the inside surface of the pattern with a fine ballpoint pen. A quick drying latex type adhesive is idealfor joints.
PARALLEL LINE DEVELOPMENT
Solutions to exercises on page 107
Bend line
Pattern forbranch B
S-
s-
o
c
165
O
Ol«3
a.
coCD
CO•r-
Os-
ai
xcu
co
oc/>
I/)
-4-
s- coo
<j
c c:s- re
+•> JQ+->
fO<4-Q- O
166
-to
- c»
Solution
to
exercise
on
page
11
1
•
CD-p
oS3
u
If
the
pattern
the
truncated
linder
T
is
own.
The
othe
If
is
a
mirror
tage
of
this.
\ s-
\ o
fof
ternnch
1
TV' i— +-> toX to to i~
N^ IE CLJ2WOO IDXI'H
,_cM
0)
en
cu
.00
en
00
s_
o«f-
I—ci. J=.
OJ o+J c
. to s-
U>
-in
-M O
O CO i
—
QJ
<J>
in
o c-»-> oCO COc a» cmo CO i—•r— •r— i—M O3 X- COr— cu a>o x to
CO a> o.
-ro
-CN
-f-CM
«
CM
CM
CM
CM
CO
767
Solutions to
exercises onpage 113
3 2 1 12
Pattern forone half ofcylinder B
showing theshape of thehole in B
.
Solutions toexercises on page 114
Pattern for branch A
1€8
Solutions toexercises onpage 1 1
5
Pattern A
Pattern BY Y
"Curve" ofi ntersecti on
Solutions toexercises onpage 116
r1^Ellipse YY
169
Solutions toexercises onpage 117
Ellipse YY
Pattern for B
showing shapeof hole
Pattern for the\J -section
chute
Note ;
Line isstraighthere *
Solution toexercise onpage 118
170
I CM
<+- co o
•r—
<D •t->
Q_ o<0 O 0)
.c </)
to +J1
o> </)
a> to to3 to oS- 3 i-
I— en o
to
cu
l/>
•t—
os-
<uXai
o+j en
1
—
to 1
—
co <u
• r— CO4-> (O3 a.
i
—
O cCO o
171
CO"0
£(U
>0.
c
Eao
lQ
c
(0
o £+-> o10 COc <1) I
—
o CO CM•r- *r— r—4-1 O3 S- cu
i
—
a> CT>
o X fOCO 0) Q.
3
CO
O
S-
+->
+->
rO
Q.
172
EZ3+->
I/)
S-
<+-
i-
o
cs-
+->
CO
Q.
<u to
tn Q) a; tr>
a) c 3 cJ2 -HEh -H
QJ
-a
o £=+-> o
v> </>
c QJ CMo V) CM•r- •r- i
—
-t-> O3 S- aj
i
—
d) a>o X A3
</} a> Q.
cTO
173
I/)
S-4-
S-
o<+-
cs-
<u4->
4->
<UQ.
w <D 0) tr>
<u C 3 C
EH
-POIS
H 0)
-P M
-o
to
o c+-> o10 1/1
c dl COo </> <M*p— •^ r—+> o3 s- 0J
i
—
<u eno X fO
l/> <D Q.
174
Radial Line Development - Cones
Complete pattern forsurface area of frustumof a right cone
Completion of exercisesstarted on page 125
Note ;
A RIGHT CONE is one in whicha line drawn from the apex ofthe cone to the centre of thecircular base is always atright angles to the base.
Apex
Centre of base
An OBLIQUE CONE is one in whichthe line from apex to the centreof the circular base is inclinedat any angle other than" 90°to the base.
Note ;
Section lines are not drawn
on cut surfaces because
the cone is hollow
Plan
I/O
Patternfrustum
PlanSolutions toon page 126
exerci ses
176
XX
t/1
CD</)
•r—
us-
a>
XCD
O+-> r-.
CNI
i/> «—co CD•1— en-•-> (03 Q.
o SZ
oo o
+-> S_
S- CU
o <- Q.4- O Q.
Oc E xzS- Z3
cu +-> o4-> </) •r—+-> 3 c<o S- oD. 4- o
177
"*^~—
^—
1
Nj 1
XX
OJ
COS-
OOJ>S-
o
0)10•1—
os-
<u
X<u
o+J 00
CVJ
t/> r—£Z
o OJ•1— en4-> cO
3 Q.r—o CCO o
cs- s-
0) CD+-> o.+J S- Q.<o o oQ. f- IE
178
o
o e+-> o10 toc 0) <Xl
o in cvir— •r* i—+-> o3 s- <u
CD C7>
o X <0v) oa
-c aj s-+-> .c cu
-t-> Q.S- Q.o 4- o<4- o -G
c E ,—s- 3 <o
cu 4-> o4-> (/> •r-M 3 C<a S- oa. <- o
179
\ 7
\ /
\ /
\ /
\ /
1 \ '/ 7
/ /L— \ 7
/ // /
/ // /
\ Q /\ / °
s- \/ -^^O E<4- O
<D •!-
+-> C +->
OJ £- -r- CG ./i— <L) (/) OJQ-+-> JZ UE4-> IO (UO reJ S-t-C_> CX+-> Q. <
c
4*ft1M3 o c
+-> o
0) C CJr-
c O to CO
ft-t-> o3 S- CDm •— <U Ol
> o x (o<S) CD Q.
h
180
oCD COCO CO'r- I—ui- CD
r— Q) CTI
O X (O00 CD Q-
O
o+->
3
<LI CMCO CO
o
o5- CD
CD CT>
X (O
CD Q.
181
CU S- m-i— CU c/> CUQ--t-> £= OE +-> <0 CUO <0 S- •!-
C_) CL+J Q-
3O1/9
cu «a-</> n•r— f—OS- CU
CU Ol
i-
o c«4- O
cu •-+-> E +>CU J- t-
1— cu </> cuQ.4-> C OE +-> <o cuo <a s- •-C_} Q-4-> CL
:, **
182
Basic Engineering Drawing is for any student about to begin the study of
engineering or technical drawing. It is actually used throughout the wholeeducational spectrum -from CSE to degree students. The pace of workingthrough the book is dictated by the ability of the student.
It is particularly suitable for craft and technician students and has found great
favour with first-year engineering degree students who have done little or noengineering drawing. For CSE and O-level students it provides a firm foundation
in the practicalities of engineering,
It is not oriented towards a particular syllabus but deals with the basic
requirements for the preparation and the interpretation of engineering
drawings, Information and exercises are presented on a one-sheet system,and attention is concentrated on particular topics by using a minimum of wordsand a maximum of pictorial explanation.
The approach to the subject is based largely on the interpretation of drawingsas a means of communication, The student is encouraged to interpret andproperly use the conventions of BS308:1972. Subjects covered are 1st and 3rd
angle projection, technology, abbreviations, conventional representation,
sectioning, isometric and oblique drawing, dimensioning, limits and fits, ISOmetric screw threads, assemblies, and parallel line, radial line, and triangulation
developments.
Each section deals with basic ideas and applications with the maximuminvolvement of the student. Many of the exercises are for completion in the
book itself, and solutions to exercises are given at the end. For these reasons,
the book is ideal for self-study.
iSBN 273 31887 X