PART 1: MACHINE DESIGN SHORT PROBLEMSSTRENGTH OF MATERIALS

1. A horizontal cantilever beam, 16 ft long is subjected to a load of 500 lb located to its center. The dimension of the beam is 2 x 4 inches respectively. w = 100 lb/ft, find its flexular stress. Answer: AA. 3150 psiB. 2912 psiC. 4510 psi D. 5663 psi2. A 12 m simply supported beam with 30 KN load at the center has a maximum deflection of: (EI = 6000 KN.m2). Answer: DA. 150 mmB. 160 mmC. 170 mm

D. 180 mm3. A 10 m simply supported beam with 25 KN load 3m from the left end has a maximum slope at the left end: (EI = 8000 Kn.m2). Answer: CA. 0.0056 rad

B. 0.0765 rad

C. 0.0186 rad

D. 0.1823 rad

4. A 10 m simply supported beam has a uniform load of 2 KN/m extended from left end to 4 m and has a concentrated load of 10 KN, 2 m from the right end. Find the maximum moment at the 10 KN concentrated load. (EI = 10,000 KN.m2). Answer: AA. 19.20 KN.mB. 26.34 KN.mC. 23.45 KN.mD. 12.34 KN.m5. A 10 m simply supported beam with uniform load of 3 KN/m from right end to left end has a maximum deflection of: (EI = 12,000 Kn.m2). Answer: BA. 43.23 mmB. 32.55 mmC. 54.23 mmD. 36.45 mm6. A 8 m simply supported beam has a uniform load of 2 KN/m from left end to right end and concentrated load of 10 KN at the center has a maximum deflection of: (EI = 5,000 Kn.m2). Answer: BA. 12.34 mm

B. 42.66 mm

C. 21.33 mm

D. 34.34 mm

7. A 10 m cantilever beam has a concentrated load of 10 KN/m at the free end. Find the maximum deflection of the beam. (EI = 7,000 Kn.m2). Answer: AA. 476.20 mm

B. 342.34 mm

C. 544.34 mm

D. 764.44 mm

8. A 14 m cantilever beam has a concentrated load of 25 KN/m at the mid-span. Find the maximum slope of the beam. (EI = 9,000 Kn.m2). Answer: BA. 0.00234 radB. 0.068 radC. 1.23 radD. 0.123 rad9. A 10 m cantilever beam has a uniform load of 2.5 KN/m from left to right end. Find the maximum deflection of the beam. (EI = 11,000 Kn.m2). Answer: DA. 423.45 mm

B. 198.23 mm

C. 323.45 mm

D. 284.10 mm

10. A 10 m cantilever beam has a uniform load of 2 KN/m from left to right end and with concentrated load of 8 KN at the center. Find the maximum slope of the beam. (EI = 13,000 Kn.m2). Answer: CA. 0.011 radB. 0.022 radC. 0.033 radD. 0.044 rad11. A 14 m cantilever beam has a load of 16 KN, 6 m from the fixed end. Find the maximum slope of the beam. (EI = 6,000 Kn.m2). Answer: BA. 0.183 rad

B. 0.048 rad

C. 0.863 rad

D. 0.064 rad

12. A 12 m cantilever beam has a uniform load of 1.5 KN/m extended from fixed end up to 4 m and a concentrated load of 8 KN at the free end. Find the maximum slope of the beam. (EI = 8,000 Kn.m2). Answer: AA. 0.126 rad

B. 0.234 rad

C. 0.654 rad

D. 0.345 rad

13. A 10 m simply supported beam has a triangular load from zero at the left end to a maximum of 10 KN/m at the right end. Find the maximum deflection of the beam. (EI = 10,000 Kn.m2). Answer: BA. 54.24 mmB. 65.10 mmC. 84.67 mmD. 76.56 mm14. An 8 m cantilever beam has a triangular load from left end to a maximum of 12 KN/m at the fixed end. What is the maximum deflection of the beam? (EI = 12,000 Kn.m2). Answer: AA. 136.53 mm

B. 145.34 mm

C. 165.34 mm

D. 154.34 mm

15. A 12 m restrained beams with two end fixed has a concentrated load of 15 KN at the center. Find the maximum deflection of the beam. (EI = 7,000 Kn.m2). Answer: CA. 8.45 mm

B. 34.23 mm

C. 19.28 mm

D. 24.67 mm

16. A 15 m restrained beams with two end fixed has a uniform load of 3 KN/m, find the maximum deflection of the beam. (EI = 9,000 Kn.m2). Answer: DA. 56.34 mm

B. 23.56 mm

C. 34.56 mm

D. 43.94 mm

17. A vertical load of 400 N acts at the end of a horizontal rectangular cantilever beam 2 m long and 25 mm wide. If the allowable bending stress is 130 Mpa, find the depth of the beam. Answer: BA. 23.45 mm

B. 38.43 mm

C. 56.43 mm

D. 45.34 mm

18. A simply supported beam is 50 mm by 200 mm in cross-section and 4 m long. If the flexular stress is not to exceed 8.3 Mpa, find the maximum mid-span concentrated load. Answer: AA. 2.77 KNB. 6.34 KNC. 3.45 KND. 4.34 KN19. A simple wooden beam, 50 mm wide by 250 mm deep and 7.5 m long has a maximum deflection of 102 mm under a uniform load w. E = 12,411 Mpa.A. What is the uniform load, w. Answer: 2KN/mB. What is the slope? Answer: 0.0435 radC. What is the maximum moment? Answer: 14 KN.mD. What is the maximum shear? Answer: 7.5 KNE. What is the flexular stress? Answer: 26.880 MpaF. What is the shearing stress? Answer: 900 Kpa20. A simply supported beam having a span of 6 m carries two concentrated loads of 80 KN at its middle thirds. Compute the deflection at the mid-span due to this load. Let EI = 30,670 x 109 N.mm2. Answer: BA. 18 mmB. 20 mmC. 24 mmD. 30 mm21. A cantilever beam having a span of 6 m, carries a triangular load of 20 KN/m at its fixed end to zero at the free end of the beam. Determine the deflection at the free end of the beam if EI = 50 x 1012 N.mm2. Answer: AA. 17.28 mm

B. 16.48 mm

C. 15.62 mm

D. 12.63 mm

22. A simply supported rectangular beam 50 mm wide by 100 mm deep carries a uniform load 1200 N/m over its entire length. What is the maximum length of the beam if the flexular stress is limited to 20 Mpa. Answer: AA. 3.33 mB. 4.25 mC. 5.2 mD. 6.0 m23. A simply supported beam having a span of 20 m carries a concentrated load of 10 KN at a distance of 5 m from the left support and a counter clockwise couple of 6KN.m acting 3 m from the right support. The maximum moment due to this load is: Answer: AA. 39 KN. m

B. 43 KN. m

C. 36 KN. m

D. 48 KN. m

24. A cantilever beam having a span of 4 m carries a concentrated load of 50 KN at the free end. What is the flexular rigidity if the beam deflects 29.63 mm at is free end. Answer: AA. 36,000 KN. m2B. 42,000 KN. m2C. 24,800 KN. m2D. 54,200 KN. m225. A restrained beam carries a triangular load which increases from zero to 30 KN/m from A to B having a span of 4 m. Determine the moment A. Answer: DA. 12 KN. m

B. 24 KN. m

C. 18 KN. m

D. 16 KN. m

26. A cantilever beam 3 m long carries a concentrated load of 35 KN at its free end. The material is structural steel and the maximum bending stress is not to exceed 125 Mpa. Determine the required diameter of the bar if it is circular. Answer: AA. 204.5 mmB. 188.6 mmC. 164.6 mmD. 179.2 mm27. A steel beam 2 m in length is simply supported at each end and carries a concentrated load of 100 KN acting 0.5 m from one of the supports. Determine the maximum bending stress set-up in the beam if the cross-section is rectangular, 100 mm wide by 150 mm deep. Answer: AA. 100 MpaB. 120 MpaC. 97 MpaD. 150 Mpa

28. A beam made of titanium has a yield point of 850 Mpa. The beam has 25 mm x 50 mm rectangular cross-section and bends about an axis paralles to the 25 mm face. If the maximum bending stress is 650 Mpa, find the corresponding bending moment. Answer: AA. 6.8 KN.mB. 8.4 KN.mC. 4.5 KN.mD. 8.4 KN.m29. A restrained beam having a span of 6 m carries a uniform load of 50 N/m throughout its span. If E = 200,000 Mpa, I = 6080 x 106 mm4, determine the deflection at the mid-span. Answer: AA. 0.14 mm

B. 0.25 mm

C. 0.36 mm

D. 0.48 mm

MECHANICS1. A car travels with an initial velocity of 10 m/s or 36 km/hr. If it is decelerating at the rate of 3 m/s2, how far, in meters, does it travel before stopping? Answer: AA. 17B. 21C. 19D. 152. A block weighing 56 lbs rest on horizontal surface. The force needed to move along the surface is 20 lbs. determine the coefficient of friction. Answer: CA. 0.0B. 0.112C. 0.36D. 0.283. A baseball is thrown straight upward with a velocity of 20 m/s. Compute for the time elapse for the baseball to return. Assume for a zero drag. Answer: DA. 1.84

B. 2.21

C. 2.50

D. 2.04

4. A 114 km/s speed is projected vertically how long will it take to go back to its initial position. Answer: AA. 6.45 hrsB. 1.23 hrsC. 7.23 hrsD. 8.45 hrs5. An occupant moves toward the center of a merry go around at 6 m/s. If the merry go around rotates at 6 rpm, compute the acceleration component of the occupant normal to the radius. Answer: DA. 6.79 m/s2B. 8.29 m/s2C. 7.54 m/s2D. 3.77 m/s26. A wheel accelerates from rest with a = 5 rad/sec.sec. Compute how many revolutions are made in 4 seconds. Answer: BA. 5.71 rev

B. 6.36 rev

C. 7 rev

D. 20 rev

7. What minimum distance can a truck slide on a horizontal asphalt road if it is travelling at 25 m/s. The coefficient of sliding friction between asphalt and rubber is at 0.6. The weight of the truck is 8500 kg. Answer: CA. 44.9B. 58.5C. 53.2D. 63.88. A liquid full is to be rotated in the vertical plane. What minimum angular velocity in radians/sec is needed to keep the liquid not spilling if the rotating arm is 1.2 meters? Answer: DA. 2.26B. 25.6C. 3.16D. 2.869. Compute the speed a satellite to orbit the earth at an elevation of 100 km. Earths radius is at 6400 km. Assume no change in gravity with the elevation. Answer: DA. 6320 m/sB. 7120 m/sC. 8740 m/sD. 7985 m/s10. An elevator weighing 2000 lbs is moving vertically upward with an acceleration of 3 ft/s2. A man standing in said elevator weighs 180 lbs.Compute the tension in the supporting cable under this condition. Answer: DA. 2180 lbs

B. 2191 lbs

C. 1820 lbs

D. 2383 lbs

11. The capsule orbits the earth 180 km above the surface. In what velocity in m/s necessary for a circular orbit to consider the earth radius at 6400 km and 9.2 m/s2? Answer: CA. 8864B. 7016C. 7780D. 805812. A truck skids to a stop 60 m after the application of the brakes while travelling at 90 km/hr. What is its acceleration in m/sec2? Answer: A A. -5.21 m/s2 B. -7.06

C. 6.36

D. 5.7613. A drop hammer of 1 ton dead weight capacity is propelled downward by a 12 in diameter cylinder. At 100 psi air pressure, what is the impact velocity if the stroke is 28 inches? Answer: BA. 63.2 fpsB. 31.6C. 15.8D. 47.414. A flywheel rotates at 120 rpm or 12.57 rad/sec slowed down to 102 rpm or 10.68 rad/sec during the punching operation that requires second of the punching portion of the cycle. Compute the angular acceleration of the flywheel in rad/sec2. Answer: A A. -2.52 rad/s2 B. -2.75 rad/s2 C. 3.15 rad/s2 D. 2.22 rad/s215. A 2-ton weight is lowered at a constant acceleration of 2 ft/s2. What is the cable stress? Answer: CA. 4344.34 lbB. 5344.56 lbC. 3751.55 lbD. 6356.24 lb16. The speedometer of a vehicle changes from 20 km/hr to 80 km/hr in 10 seconds. Find the acceleration for this period in m/s2. Answer: A A.1.67 B. 6.34 C. 2.34 D. 8.4517. A car changes accelerates its speed from 20 m/s to 50 m/s in 10 sec. Find the distance travelled during the period of acceleration. Answer: AA. 350 mB. 500 mC. 400 mD. 600 m18. A box sliding on a floor has a frictional resistance of 100 N. If the coefficient of friction is 0.3, find the weight of the box. Answer: DA. 222.22 N

B. 111.11 N

C. 444.44 N

D. 333.33 N

19. An object dropped on a gravity travels 300 m after how many seconds? Answer: CA. 5.34 secB. 6.34 secC. 7.82 secD. 10.23 sec20. An object is projected upward at the rate of 40 m/s. How high will the object rise? Answer: DA. 54.34 mB. 76.45 mC. 65.34 mD. 81.55 m21. A stone is projected upward from the ground travels a maximum height of 50 m. Find the velocity of stone when it returns to the ground. Answer: AA. 31.32 m/secB. 54.34 m/secC. 43.23 m/secD. 23.45 m/sec22. An object is projected upward at the rate of 45 m/s at 300 from the horizontal. Find the maximum range of projectile. Answer: AA. 178.77 m

B. 165.34 m

C. 189.34 m

D. 109.34 m

23. A capsule orbits the earth at the rate of 6000 m/s. If the radius of earth is 3000 km, find the height of capsule from the surface of the earth. Answer: BA. 435.66 m

B. 669.72 m

C. 543.23 m

D. 785.45 m

24. A car that travels 100 mph reduces its speed 50 mph in 30 seconds. Find the distance travelled by the car until it stops. Answer: AA. 4402.10 mB. 3452.34 mC. 5434.56 mD. 6456.35 m25. A car travelling at 40 m/s in a radius of 1000 m will have a banking angle of:. Answer: CA. 7.340B. 183.40C. 9.360D. 12.30MACHINE SHOP

1. Determine the time in seconds, to saw a rectangular magnesium bar 5 in wide and 2 in thick if the length of cut is 5 in. The power hacksaw does 120 strokes/min and the feed/stroke is 0.127 mm. Answer: BA. 189B. 500C. 99D. 202. In an Oxy-Acetylene manual welding method, to weld a 3 ft long seam in a 0.375 thick steel plate at a consumption rate of 9 ft3/ft for oxygen and 7 ft3/ft for acetylene. Compute for the total combined gas consumption in ft3. Answer: CA. 189

B. 500

C. 99

D. 20

3. Compute for the drill penetration in in/min when a drill turns at 1200 rpm and the feed of 0.005 in/rev. Material is steel. Answer: DA. 1.8B. 3.6C. 12D. 64. What is the value in degrees of 1 radian? Answer: CA. 57.490B. 57.940C. 57.290D. 57.9205. Compute the manual cutting time in minutes, of steel plate 4 ft by 8 ft by 2.5 cm thick with a hand cutting speed of 3.8 to 4 mm/sec, cutting lengthwise Answer: AA. 10B. 1.81C. 0.38D. 8.166. Compute the cutting speed in fpm of a workpiece with 2 inches diameter and running at 100 rpm. Answer: AA. 52B. 62C. 25D. 267. Compute the cutting speed in fpm of a workpiece with 2 inches diameter and turning at 100 rpm. Answer: DA. 72B. 102C. 62D. 528. Determine the average time to cut by automatic oxyacetylene (machine) crosswise a 4 ft x 8 ft x 4 in thick steel plate. Answer: BA. 6.85B. 318C. 10D. 3609. Calculate the rpm for machining a cast iron workpiece 6 inches in diameter. The lowest cutting speed for cast iron is 50 fpm. Answer: CA. 35.3B. 43.3C. 33.3D. 53.3210. With the arc welding rate of 18 in/min, how long will it take to weld in thick plate by 3 feet long seam? Answer: CA. 3 minB. 1.5 minC. 2 minD. 4 min11. How long will it take to mill a by 2 long keyway in a 3 diameter shafting with a 24 tooth cutter turning at 100 rpm and a 0.005 feed/tooth? Answer: BA. 0.136 minB. 0.166 min

C. 0.196 min

D. 0.106 min

12. How long will it take to saw a rectangular piece of aluminum plate 8 in wide and 1 in thick if the length of the cut is 8 in, the power hacksaw makes 120 rev/min and average feed per stroke is 0.0060 in? Answer: CA. 13.11B. 14.01C. 11.11D. 12.0313. Using oxy-acetylene welding method to weld a 3 ft long seam in a 3/8 in thick plate at a consumption rate of 9 ft3/ft of weld for oxygen and 7 ft3/ft for acetylene. What is the total combined gas consumption in ft3? Answer: CA. 51B. 45C. 48D. 5514. A grinding wheel rotates 1750 rpm and has a surface speed of 2290 ft/min. Find the diameter of the wheel in inches. Answer: BA. 3 inB. 5 inC. 4 inD. 6 in15. To facilitate the milling (roughing) work of a cast steel material using a 1 inch diameter cutter choose between the two available stock. Find the speed of the cutter in rpm. high speed steel cutter with a cutting speed of 50 fpm- carbide tipped cutter with cutting speed of 200 fpm.. Answer: BA. 389B. 509C. 572D. 41216. A piston reciprocates 100 times per minute (single stroke). The length of the stroke is 6 in. What is the average wristpin velocity in ft/min? Answer: AA. 50 ft/minB. 100 ft/minC. 75 ft/minD. 125 ft/min17. A workpiece turning at 300 rpm has a tangential speed of 15 ft/s. Find the diameter of the workpiece. Answer: AA. 11.46 inB. 15.23 inC. 13.23 inD. 17.34 in18. A workpiece turning at 20 rad/sec has diameter of 4 in. Find the peripheral speed of workpiece. Answer: BA. 1.23 fpsB. 3.33 fpsC. 5.23 fpsD. 7.34 fps19. Two plates 4 ft x 8 ft plate in thick is to be joined lengthwise. A welding machine to be used has a welding rate of 20 in/min. How long will it take to join the plates? Answer: CA. 7.34 minB. 1.23 minC. 4.80 minD. 6.45 min20. A 10 ft long seam can be weld in 10 min. the welding rate is: Answer: BA. 8 in/minB. 12 in/minC. 10 in/minD. 14 in/min21. A seam can be weld in 3 min. If the welding rate is 15 in/min, find the length of the seam. Answer: DA. 20 inB. 30 inC. 25 inD. 45 in22. How long will it take to mill by 1.5long keyway by means of 25 teeth cutter turning at 120 rpm and 0.008 feed/tooth. Answer: DA. 1.23 sec B. 6.34 secC. 4.23 secD. 3.75 sec23. A 5 in long keyway is to be mill at the rate of 0.2 in/min. How long will it take to mill the keyway? Answer: CA. 20 sec

B. 15 sec

C. 25 sec

D. 30 sec24. It takes 1 min to mill a x 4 keyway of a hub by means of a cutter having 30 teeth at 120 rpm. Find the equivalent feed per tooth, in/tooth. Answer: DA. 0.00222B. 0.00444C. 0.00333D. 0.0011125. How long will it take to cut a rectangular plate 4 ft wide by means of a saw that has a speed of 160 rev/min and an average feed per stroke of 0.009 in? Answer: BA. 22.22 minB. 33.33 minC. 55.55 minD. 44.44 min26. A 4 ft wide x 8 ft long and in thick steel plate is be cut into 4 equal parts crosswise. If cutting rate is 0.02 in/stroke and saw speed is 110 rpm, how long will it take to do the job? Answer: CA. 53.45 minB. 34.23 min

C. 65.45 min

D. 67.45 min

27. It takes 5 min to cut a plate 20 ft long by means of a saw having a speed of 250 rpm. What is the average feed per stroke of the saw, in/stroke? Answer: BA. 0.534B. 0.192C. 0.745D. 0.34228. An oxyacetylene cutter is use to cut a 4 ft x 8 ft steel plate crosswise and divided the whole plate into five equal parts. If the cutting rate is 10 in per minute, how long will it take to cut plates? Answer: AA. 19.20 minB. 13.45 minC. 21.23 minD. 17.34 min29. Using oxyacetylene welding method to weld a 10 ft long seam in a in thick plate at a consumption rate of 10 ft3/ft oxygen and 8 ft3/ft for acetylene. What is the total gas consumption? Answer: DA. 150 ft3B. 170 ft3C. 160 ft3D. 180 ft330. A 24 ft2 lateral surface for a cylindrical tank is to be made by joining 2 ft by 2 ft steel plate to form 6 ft x 4 ft. The consumption rate for both oxygen and nitrogen is 20 ft3/ft using oxyacetylene welding method. Find total gas consumption needed, ft3? Answer: DA. 250 ft3B. 470 ft3C. 440 ft3D. 280 ft331. A 10 ft x 20 ft plate is to be divided into 8 pieces 5 ft x 5 ft steel plate by means of an oxyacetylene cutter that has a cutting rate of 10 in per minute. How long will it takes to do the job? Answer: CA. 50 minB. 70 minC. 60 minD. 80 minMACHINE ELEMENTS1. Two parallel shafts connected by pure rolling turn in the same direction having a speed of 2.75. What is the distance of the shafts if the smaller cylinder is 32 cm in diameter? Answer: DA. 16.67 cmB. 25.25 cmC. 30.25 cmD. 19.25 cm2. A lineshaft runs at 360 rpm. An 18 pulley on the shaft is belt connected to a 12 pulley on the countershaft. From a 15 pulley on the countershaft, motion is transmitted to the machine. Compute/ check the required diameter of the pulley on the machine to give a spindle speed of 660 rpm. Answer: BA. 16B. 12 C. 10 D. 8 3. A 5 ft diameter pulley is turning at 200 rpm. Find the speed of the pulley mid-way of the center and outer surface of the pulley. Answer: DA. 20.45 ft/sB. 30.45 ft/sC. 24.34 ft/sD. 26.18 ft/s4. A wheel is turning at 360 rpm. If tangential speed of the wheel is 150.80 ft/s, what is the radius of the flywheel? Answer: CA. 8 ftB. 2 ftC. 4 ftD. 10 ft5. Two cylinders rolling in opposite direction has a speed ratio of 3. If the center distance is 40 in, find the diameter of smaller cylinder. Answer: AA. 20 inB. 60 inC. 40 inD. 80 in6. Three cylinders A:B:C rolling in external contact has a speed ratio of 4:2:1. If the diameter of cylinder A is 10 cm, find the center distance between cylinder A and C. Answer: CA. 40 cmB. 35 cmC. 45 cmD. 50 cm7. Four cylinders A:B:C:D has a speed ratio of 6:4:2:1. If the center distance between cylinder A and C is 30 inches, find the center distance A and D. Answer: AA. 68.57 mB. 83.45 mC. 56.34 mD. 76.34 mSTRESSES

1. A steel rod 30 mm & 800 mm long has an allowance elongation not to exceed 1.5 mm, find the allowable load in KN. Answer: AA. 274B. 248C. 316D. 2362. Compute the induced/compressive stress, in kpa, of a steel solid shafting of 50 mm diameter and 800 mm in length that is subjected to an increase of temperature by 800 C. Answer: DA. 181,816B. 242,816C. 218,182D. 196,5603. Compute for the load in KN on a 3 cm diameter, 100 cm long steel rod if its maximum elongation exceed 0.12 cm. Answer: AA. 178B. 196C. 148D. 287

4. Compute for the polar section modulus of a SAE 1060 shafting having a diameter of 3 inches. Use a factor of safety of 2 and design stress at 800 psi. Answer: DA. 4.7B. 6.1C. 4.2D. 5.35. Compute the allowable load in KN on a 20 mm x 120 cm long steel rod with a maximum elongation must not exceed 1 mm. Answer: BA. 35B. 55C. 66D. 766. Determine the load in KW on a 25 mm diameter x 1200 mm long steel shaft if its maximum elongation exceeds 1 mm. Answer: AA. 83B. 125C. 103D. 2347. The total weight of steel plates x 3 x 20 is: Answer: AA. 1838 lbs

B. 1698 lbs

C. 3676 lbs

D. 1848 lbs8. What pressure is required for punching a hole 2 inches in diameter thru a in steel plate? Answer: DA. 10 tonsB. 30 tonsC. 20 tonsD. 40 tons9. A link has a load factor of 0.8, the surface is 0.92 and the endurance strength is 28,000 psi. Compute the alternating stress of the link if it is subjected to a reversing load. Assume a factor of safety of 3. Answer: CA. 8150B. 10920C. 9333D. 726010. Determine the minimum mean diameter of a taper pin for use to fix a lever to shaft, if it is transmit a maximum torque of 700 in-lbs. The shaft diameter is 2 inches and the material allowable stresses is 15,000 psi. Use factor of safety of 2. Answer: DA. 7 mmB. 7.2 mmC. 5.2 mmD. 6.2 mm11. How many 5/16 inch holes can be punched in one motion in a steel plate made of SAE 1010 steel, 7/16 inch thick using a force of 55 tons. The ultimate strength for shear is 50 ksi and use 2 factor of safety. Answer: CA. 5.8

B. 3.7

C. 5

D.6.2

12. The shaft whose torque varies from 2000 to 6000 in-lbs has 1 inches in diameter and 60,000 psi yield strength. Compute for the shaft mean average stress. Answer: AA. 6036 psiB. 6810 psiC. 5162 psiD. 5550 psi13. A journal bearing with diameter of 76.2 mm is subjected to a load of 4900 N while rotating at 200 rpm. If its coefficient of friction is 0.02 and L/D = 2.5, find its projected area in mm2. Answer: DA. 12090B. 13050C. 14165D. 1451614. A steel tie rod on bridge must be made withstand a pull of 5000 lbs. Find the diameter of the rod assuming a factor of safety of 5 and ultimate stress of 64,000 psi. Answer: CA. 0.75B. 0.84C. 0.71D. 0.7915. If the weight of 6 diameter by 48 long SAE 1030 shafting is 174.5 kg, then what will be the weight of chromium SAE 51416 of same size? Answer: BA. 305.5 lbsB. 384.6 lbsC. 426.4 lbsD. 465.1 lbs16. If the ultimate shear strength of a steel plates is 42,000 psi, what force is necessary to punch a 0.75 inch diameter hole in a 0.625 inch thick plate? Answer: BA. 63,008 lbs

B. 61,800 lbs

C. 68,080 lbs

D. 66,800 lbs 17. What is the modulus of elasticity if the stress is 4,000 psi and unit a strain of 0.00105? Answer: AA. 41.905 x 106B. 42.300 x 106C. 41.202 x 106D. 43.101 x 10618. A 2.5 in diameter by 2 in long journal bearing is to carry a 5500-lb load at 3600 rpm using SAE 40 lube oil at 2000F through a single hole at 25 psi. Compute the bearing pressure. Answer: AA. 1100 psiB. 1000 psiC. 900 psiD. 950 psi19. It is a problem of expansion and shrinkage of steel material so that the slightly bigger shafting of 2 diameter can be inserted/fitted to the slightly smaller holes of a steel bushing of 1.999 diameter with the following process/material/data to apply: Coefficient of expansion of carbon steel = 0.0000068 /0F temperature raised by gas heating = 24.5 0F. Cooling media to use dry ice with boiling point of -109.30F (-78.50C). Shrinkage rate below boiling point is 0.00073 in/in. Determine the final clearance between the expanded steel bushing hole against the shrinkage of steel shaft. Answer: AA. 0.000793B. 0.000693C. 0.000750D. 0.00080020. What modulus of elasticity in tension is required to obtain a unit deformation of 0.00105 m/m from a load producing a unit tensile stress of 44,000 psi? Answer: DA. 42.300 x 106 psiB. 43.101 x 106 psi

C. 41.202 x 106 psi

D. 41.905 x 106 psi21. What force P is required to punch a in hole on a 3/8 in thick plate if the ultimate shear strength of the plate is 42,000 psi? Answer: DA. 24,940 lbsB. 24,960 lbsC. 24,620 lbsD. 24,740 lbs22. What pressure is required to punch a hole 2 diameter through a steel plate? Answer: DA. 10 tonsB. 30 tonsC. 20 tonsD. 40 tons23. Compute the working strength of 1 bolt which is screwed up tightly in packed joint when the allowable working stress is 13,000 psi. Answer: BA. 3600 lbsB. 3900 lbsC. 3950 lbsD. 3800 lbs24. What is the working strength of a 2 bolt which is screwed up tightly in a packed jointly when the allowable working stress 12,000 psi? Answer: BA. 20,120 lbsB. 20,400 lbsC. 20,100 lbsD. 20,200 lbs25. Determine the estimated weight of an A-36 steel plate size x 4 x 8. Answer: DA. 280 kgsB. 301 kgsC. 332 kgsD. 297 kgs26. Determine the estimated weight of an A-36 steel plate size 3/16 x 6 x 20. Answer: AA. 919 lbsB. 829 lbsC. 1012 lbsD. 735 lbs27. A 19 mm stud bolts is used to fastened on a 250 mm diameter cylinder head of diesel engine. If there are 10 stud bolts, determine the pressure inside the cylinder if bolt stress is limited to 50 Mpa. Answer: AA. 288.8 KpaB. 2888 KpaC. 3426 KpaD. 4828 Kpa28. A 19 mm stud bolts is used to fastened on a 250 mm diameter cylinder head of diesel engine. If there are 10 stud bolts, determine the pressure inside the cylinder if bolt stress is limited to 50 Mpa. Answer: AA. 288.8 KpaB. 2888 Kpa

C. 3426 Kpa

D. 4828 Kpa

29. A column supports a compressive load of 250 KN. Determine the outside diameter of column if inside diameter is 185 mm and compressive stress of 50 Mpa. Answer: BA. 200.62 mmB. 201.47 mmC. 216.42 mmD. 208.41 mm30. A steel hollow tube is use to carry a tensile load of 500 KN at a stress of 140 Mpa. If outside diameter is 10 times the tube thickness, find the thickness of the tube. Answer: AA. 11.24 mmB. 107 mm

C. 20.64 mm

D. 22.61 mm

31. A 20 mm diameter rivet is used to fastened two 25 mm thick plate. If the shearing stress is 80 Mpa. What tensile force applied each plate to shear the bolt?. Answer: DA. 26.35 KNB. 28.42 KNC. 30.41 KND.25.13 KN32. What force is necessary to punch a 30 mm hole in 12.5 mm thick plate if ultimate shear stress is 410 Mpa? Answer: CA. 564 KNB. 342 KN

C. 483 KN

D. 983 KN

33. Two 30 mm thick plate is fastened by two bolts, 25 mm in diameter. If the plates is subjected to 50 KN tension, find the bearing stress in bolts. Answer: AA. 33,333.33 KpaB. 4444.44 KpaC. 5555.55 KpaD. 555,555 Kpa34. A 2.5 inches shaft is subjected to 3 KN-m torque. Find the stress developed. Answer: CA. 48.62 MpaB. 52.75 MpaC. 59.68 MpaD. 38.64 Mpa35. A shaft when subjected to pure tension developed a stress of 50 Mpa. If the polar moment of inertia is 6.1359 x 10-7 m4, determine the maximum torque the shaft could handle. Answer: AA. 1.23 KNB. 1.68 KN

C. 1.84 KN

D. 2.48 KN

36. What is the modulus of elasticity if the stress is 300 Mpa and strain of 0.00138? Answer: AA. 217.39 x 103 MpaB. 200.61 x 103 MpaC. 220.61 MpaD. 215.21 Mpa37. In a 2.0 m cantilevered I-beam, a 2 Mton weight is applied at the free end. If the allowable stress in beam is 110 Mpa, determine the section modulus. Answer: BA. 18.54 in3B. 21.77 in3C. 26.83 in3D. 24.28 in338. A 5 KN force acting at the end of a 3 m cantilever beam. If section modulus of the beam is 10 in3, what is the stress induced? Answer: DA. 86,285 KpaB. 78,318 KpaC. 29,684 KpaD. 91,535 Kpa

39. A 6 mm steel wire is 5 m long and stretches 8 mm under a given load. If the modulus of elasticity is 200 Gpa, find the load applied. Answer: CA. 7 KNB. 8 KNC. 9 KND. 10 KN40. A steel wire 10 m long, hanging vertically supports a tensile load of 2 KN. Neglecting the weight of wire, determine the required diameter if the stress is not to exceed 140 Mpa and the total elongation is not to exceed 5 mm. Assume E = 200 Gpa.. Answer: DA. 2 mmB. 3 mmC. 4 mmD. 5 mm41. An iron rod 4 m long and 0.5 cm2 in cross section stretches 1 mm when a mass of 225 kg is hang on it. Compute the modulus of elasticity of the iron. Answer: AA. 176. 58 GpaB. 169.81 GpaC. 160.41 GpaD. 180.26 Gpa42. A 20 m rod is stretches to a strain of 0.001. Determine the deflection of the rod. Answer: AA. 20 mmB. 25 mm C. 30 mmD. 35 mm43. A rail having a coefficient of linear expansion of 11.6 x 10-6 m/m-0C increases its length when heated from 700F to 1130F. Determine the strain. Answer: DA. 2.04 x 10-4B. 6.05 x 10-4C. 4.21 x 10-4D. 2.77 x 10-444. What temperature will the rails just touch if steel railroad is 10 m long are laid with clearance of 3 mm at initial temperature of 150C? Use k = 11.7 x 10-6 m/m-0C Answer: BA. 35.64 0CB. 40.64 0CC. 45.64 0CD. 50.64 0C

45. For a given material, the modulus of elasticity is 100 GN/m2 in tension and 40 GN/m2 in shear. Find the Poissons ratio. Answer: CA. 0.10B. 0.50C. 0.25D. 0.3546. A 25 mm shaft is keyed to a 300 mm diameter pulley and transmits 3 KW of power. The keyed assembly rotates at 1725 rpm. What is the tangential force at the key? Answer: AA. 1.33 KNB. 5.23 KN C. 2.33 KND. 8.34 KN47. What force is necessary to punch a 1 in hole in a 1/8 in steel plate if the ultimate shearing stress is 60,000 psi and the ultimate compressive stress is 80,000 psi? Answer: DA. 34,520.34 lbsB. 8,345.56 lbsC. 12,344.56 lbsD. 23,561.90 lbs48. A U-bolt supports a load of 6000 lb. The cross section of the bolt has a diameter of inch. How much stress is induced in the sides of the bolt? Answer: DA. 12,734.45 psiB. 14,567.23 psiC. 13,345.56 psiD. 15,278.12 psi49. A 1 inch diameter shaft has a 2 in diameter collar resting on a support. The axial load on the shaft is 10,000 lb and the thickness of the collar is in. How much shearing stress is induced? Answer: AA. 6366.20 psiB. 4234.56 psiC. 5244.56 psiD. 8456.34 psi

50. A hollow rivet has an outside diameter of 5 mm and an inside diameter of 3mm. If the allowable shearing stress is 400 x 106 N/m2, what maximum shearing force can the rivet sustain if subjected to double shear? Answer: AA. 10 KNB. 20 KN C. 15 KND. 25 KN

51. A vertical load of 400 Newtons acts at the end of a horizontal rectangular cantilever beam 2 m long and 25 mm wide. If the allowable bending stress is 130 MN/m2, find the depth of the beam in mm. Answer: BA. 23.44 mmB. 38.43 mmC. 30.23 mmD. 43.23 mm

52. A simply supported timber beam is 50 mm by 200 mm in cross section and 4 m long. If the fiber stress is not to exceed 8.3 Mpa and the beam weight is neglected, find the maximum mid-span concentrated load that the beam can support if the 200 mm dimension is vertically oriented. Answer: AA. 2,766.67 NB. 3,233.45 NC. 2,345.56 ND. 1,234.45 N53. A lap joint consists of steel plate 250 mm by 18 mm in thickness is connected by 4-20 mm diameter rivets. Compute the bearing capacity of the rivet connection if the allowable bearing stress is 210 Mpa. Answer: AA. 302,400 NB. 360,200 NC. 420,340 ND. 460,240 N

54. A steel hanger of 2 m length is to carry an axial load of 18 KN. If the tensile stress is restricted to 104 Mpa and the elongation caused by this load is restricted to 1mm, what is the minimum cross-sectional area the member can have? E = 200,000 Mpa . Answer: AA. 180 mm2B. 173 mm2C. 164 mm2D. 190 mm255. A short hollow steel cylinder with a wall thickness of 38 mm is to carry a compression load, applied uniformly on the end, of 7,800 KN. If the allowable working stress in steel in compression is 138 Mpa, then the minimum outside diameter of the cylinder required to safely support the load is: Answer: AA. 512 mmB. 482 mmC. 396 mmD. 460 mm

56. A 25 mm diameter steel bar is loaded in double shear until failure, the ultimate load is found to be 446 KN. If the allowable stress is based on a factor of safety of 3 what must be the diameter of a pin designed for an allowable load of 26 KN in single shear be? Answer: AA. 14.79 mmB. 15.64 mmC. 13.24 mmD. 12.63 mm

57. A steel bar, initially free of stress, is held between rigid supports. Determine the stress in the bar if temperature drops 1300F. K = 6.5 x 10-6 in/0F, E = 30 x 10 6 psi Answer: AA. 25,350 psiB. 26,234 psiC. 24,896 psiD. 23,654 psi

58. A steel rod with a cross sectional area of 16o mm2 is to be attached between two fixed points 1.25 m apart. If the rod is too short by 0.25 mm, find the stress applied to put the rod back to fitness. E = 200,000 Mpa Answer: AA. 40 MpaB. 30 MpaC. 50 MpaD. 60 MpaSHAFT

1. Compute for the twisting moment in in-lb developed when the shaft delivers 20 hp at 1200 rpm. Answer: CA. 1166B. 915C. 1050D. 9452. Find the torsional deflection, in degrees, of a solid steel shaft, 110 mm OD x 1.4 m long subject to 3.1 x 106 N-mm torque. The torsional modulus of elasticity is 80,000 N/mm-mm. Answer: DA. 0.221B. 0.195C. 0.28D. 0.213. Compute for the torsional deflection, in degrees, of a 110 mm diameter, 1.4 m long shaft subjected to a twist moment of 3 x 106 N.mm. The torsional modulus of elasticity is 83000 N/mm2. Answer: CA. 0.27B. 0.31C. 0.20D. 0.244. Find the torsional moment (in Newton-mm), developed when the shaft delivers 20 KW at 200 rpm. Answer: BA. 0.75 x 106B. 1.0 x 106C. 1.20 x 106D. 2.10 x 1065. A 102 mm diameter shaft is driven at 3000 rpm by a 300 hp prime mover. The shaft drives a 121.9 cm diameter chain sprocket having 85% output efficiency. Compute the torque in in-lb developed in the shaft. Answer: DA. 5,600B. 7,100C. 8,150D. 6,3006. A 3 in diameter short shaft carrying pulleys close to the bearings transmit how much horsepower if the shaft makes 280 rpm? Answer: CA. 991 hpB. 919 hpC. 199 hpD. 260 hp7. What power would the spindle 55 mm in diameter transmit at 480 rpm stress allowed for short shaft is 59 N/mm2? Answer: BA. 98.68 KWB. 96.88 KWC. 68.98 KWD. 68.89 KW8. A hollow shaft has an inner diameter of 0.035 m and an outer diameter of 0.06 m. Compute the torque if the shear stress is not to exceed 120 Mpa in N-m. Answer: CA. 4,400 N-mB. 4,300 N-mC. 4,500 N-mD. 4,200 N-m9. What power would a spindle 55 mm in diameter transmit at 480 rpm. Stress allowed for short shaft is 59 N/mm2. Answer: No correct answer in the given choices.A. 45.12 kwB. 50.61 kwC. 45 hpD. 39.21 hp10. A small countershaft is 1 inch in diameter and has an allowable stress of 8500 psi. Find the horsepower delivered by the shaft at a speed of 15.7 rad/s. Answer: CA. 7.20B. 1.4C. 13.31D. 14.7211. Determine the torque received by the motor shaft running at 4250 rpm, transmitting 11 HP, through a 10 in diameter, 200 involute gear. The shaft is supported by the ball bearings at both ends and the gear is fixed at the middle of 8 in shaft length. Answer: AA. 163 in-lbB. 167 in-lbC. 132 in-lbD. 138 in-lb12. A 16 ft lineshaft has no bending action except its own weight. What power in HP can the shaft deliver at a speed of 200 rpm. Consider that the torsional deflection will not exceed 0.08/ft length.. Answer: DA. 13.2B. 15.8C. 24.4D. 14.613. The torsional deflection of a SAE 1040 steel shaft is 0.80 in a length of m. The shear stress is 69 Mpa. Compute the diameter of the shaft in millimeter. Steel modulus of elasticity is 79,300 Mpa or N/mm2. Answer: DA. 51B. 50C. 75D. 6214. Compute the diameter of a solid shaft transmitting 75 Hp at 1800 rpm. The nature of the load and the type of service is such that the allowable SS based on pure torsion is 6000 psi.. Answer: CA. 1 7/7B. 2 1/16C. 1 5/16D. 3 1/815. The shaft is subjected to a steady load of 36,000 lbs at a shear stress of 10,000 psi. Compute the diameter of the said shaft in inches. Answer: CA. 1 7/8B. 2 1/4C. 3D. 2 3/416. Determine the torque received by the motor shaft running at 4250 rpm, transmitting 11 HP, through a 10 in diameter, 200 involute gear. The shaft is supported by the ball bearings at both ends and the gear is fixed at the shaft length. Answer: AA. 163 in-lbB. 132 in-lbC. 167 in-lb

D. 138 in-lb17. Compute the maximum unit shear in a 3 inches diameter steel shafting that transmits 24,000 in-lb of torque at 99 rpm. Answer: AA. 4530 psiB. 3860 psiC. 4250 psiD. 4930 psi18. Compute the linear shaft diameter to transmits 12 Hp at 180 rpm with torsional deflection of 0.08 degrees per foot length. Answer: BA. 3 inB. 2.35 inC. 5 cmD. 62 mm19. Compute the nominal shear stress at the surface in Mpa for a 40 mm diameter shaft that transmit 750 Kw at 1500 rpm. Axial and bending loads are assumed negligible. Torsional shearing stress is 28 N/mm2. Answer: DA. 218B. 232C. 312D. 38020. A hollow shaft has inner diameter of 0.035 m and outer diameter of 0.06 m. Compute for the torque if the shear stress is not to exceed 120 Mpa in N-m. Answer: AA. 4500B. 4300C. 4100D. 415021. Design the size of solid steel shaft to be used for a 500 Hp, 250 rpm application if the allowable torsional deflection is 10 and the allowable stress is 10,000 psi and modulus of rigidity is 13 x 106 psi. Answer: BA. 5 dia.B. 4-7/8 dia.C. 4-5/8 dia.D. 4-3/4 dia.22. A 2-in solid shaft is driven by a 36-in, gear and transmit power at 120 rpm. If the allowable shearing stress is 12 ksi, what horsepower can be transmitted? Answer: CA. 29.89B. 38.89C. 35.89D. 34.8923. A short 61 mm diameter shaft transmits 120 Hp. Compute the linear speed of a pulley 55 cm diameter mounted on the shaft. Answer: BA. 1796 fpmB. 1870 fpmC. 1766 fpmD. 2106 fpm24. A hollow shaft has inner diameter of 0.035 m and outer diameter of 0.06 m. Determine the polar moment of inertia of the hollow shaft. Answer: DA. 1.512 x 10-6 m4B. 1.152 x 10-6 m4C. 1.215 x 10-6 m4D. 1.125 x 10-6 m425. Compute the speed of the gear mounted on a 52.5 mm diameter shaft receiving power from a driving motor with 250 Hp. Answer: BA. 2182 rpmB. 2282 rpmC. 2071 rpmD. 2341 rpm26. A solid cylindrical shaft 48.2 cm long is used for a transmission of mechanical power at a rate of 37 KW running at 1760 rpm. The SS is 8.13 Mpa. Calculate the diameter. Answer: DA. 30 mmB. 40 mmC. 35 mmD. 50 mm27. A hollow shaft with outside diameter of 14 cm and wall thickness of 0.8 cm transmits 200 Kw at 400 rpm. What must be the angular deflection of the shaft if the length is 5 meters? The material of the shaft is C4140 steel. Answer: BA. 0.84 degB. 1.14 degC. 1.83 degD. 1.50 deg28. A 3 diameter short shaft carrying 2 inches pulleys close to the bearings transmit how much power if the shaft makes 280 rpm. Answer: AA. 199 HpB. 200 HpC. 198 HpD. 210 Hp29. A step shaft made of SAE 1117 steel with an ultimate strength of 69.7 ksi. The notch sensitivity factor is 0.00435 is the constant dependent upon the ultimate strength, check the radius stress raiser. Answer: CA. 0.192B. 0.386C. 0.250D. 0.77530. A shaft is used to transmit 200 Kw at 300 rpm by means of a 200 mm diameter sprocket. Determine the force tangent to the sprocket. Answer: DA. 60.44 KNB. 60.33 KNC. 60.88 KND. 63.66 KN31. Find the diameter of a steel shaft which will be used to operate a 110 Kw motor rotating at 5 rps if torsional stress is 90 Mpa. Answer: BA. 60.2 mmB. 58.3 mmC. 38.3 mmD. 46.2 mm32. What is the speed of 63.42 mm shaft that transmit 75 Kw if stress is not to exceed 26 Mpa. Answer: AA. 550 rpmB. 660 rpmC. 650 rpm

D. 650 rpm

33. A steel shaft transmits 50 Hp at 1400 rpm. If allowable stress is 500 psi, find the shaft diameter. Answer: BA. 3.58 inB. 2.84 inC. 1.65 inD. 2.54 in34. A hollow shaft that has a 100 mm outside diameter and 80 mm inside diameter is used to transmit 100 Kw at 600 rpm. Determine the shaft stress. Answer: AA. 13.73 MpaB. 16.82 MpaC. 19.86 MpaD. 17.21 Mpa35. Determine the length of the shortest 2 mm diameter bronze wire which can be twisted through two complete turns without exceeding a shearing stress of 70 Mpa. G = 35,000 Mpa. Answer: AA. 6,283 mmB. 5,484 mmC. 4,836 mmD. 7,263 mm36. A hollow shaft developed a torque of 5 KN-m and shaft stress is 40 Mpa. If outside diameter of shaft is 100 mm, determine the shaft inner diameter. Answer: DA. 68.43 mmB. 63.28 mmC. 58.38 mmD. 77.64 mm37. What is the polar moment of inertia of a solid shaft that has a torque of 1.5 KN-m and a stress of 25 Mpa? Answer: BA. 2.46 x 10-6 m4B. 2.02 x 10-6 m4C. 3.46 x 10-6 m4D. 1.24 x 10-6 m438. A force tangent to a foot diameter pulley is 5 KN and is mounted on a 2 inches shaft. Determine the torsional deflection if G = 83 x 106 Kpa. Answer: AA. 0.805 0/mB. 0.654 0/mC. 0.768 0/mD. 0.938 0/m39. What is the minimum diameter of a steel shaft which will be used to operate a 14 KN-m torque and will not twist more than 30 in a length of 6 m? ( G = 83 x 106 Kpa) Answer: CA. 100.64 mmB. 96.80 mmC. 118.45 mm

D. 120.72 mm

40. A solid shaft 5 m long is stressed to 60 Mpa when twisted through 40. Find the shaft diameter if G = 83 Gpa. Answer: DA. 95.64 mmB. 90.42 mmC. 101.32 mm

D. 103.54 mm

41. What is the diameter of a line shaft that transmit 150 Kw at 15 rps? Answer: AA. 2.28 inB. 3.54 inC. 1.62 inD. 2.04 in42. A main shaft has 50 mm diameter is running at 300 rpm. What power that could be delivered by the shaft? Answer: BA. 3.40 HpB. 28.60 HpC. 32.50 HpD. 16.42 Hp43. A 1.5 in diameter short shaft is used to transmit 44.4 Hp. Determine the shaft speed. Answer: BA. 500 rpsB. 8.33 rpsC. 400 rpsD. 450 rps44. A 3 in solid shaft is desired to replaced a hollow shaft having 4 in outside diameter. Consider the strength to be the same, determine the inside diameter of hollow shaft. Answer: CA. 2.5 inB. 3.0 inC. 3.48 in

D. 4.0 in

45. A motor is used to drive a centrifugal pump that discharges 3000 li/min at a head of 10 m. The pump efficiency is 68% and running at 550 rpm. Find the torsional stress of shaft if shaft diameter is 35 mm. Answer: DA. 13.85 MpaB. 11.85 MpaC. 12.85 MpaD.14.87 Mpa46. A circular saw blade has a circular speed of 25 m/sec and 500 mm diameter is driven by means of belt that has an efficiency of 95%. Find the required diameter of the driven shaft. If power transmitted is 50 Hp. Answer: BA. 1 inB. 2 inC. 3 in

D. 4 in

47. An 800 mm diameter circular saw blade is driven by a 1800 rpm motor with belt speed ratio of 1.8. Find the peripheral speed of the blade. Answer: AA. 137.43 ft/secB. 140.65 ft/secC. 132.43 ft/secD. 135.21 ft/sec48. A machine shaft is supported on bearings 1 m apart is to transmit 190 Kw at 300 rpm while subjected to bending load of 500 kg at the center. If maximum shearing stress is 40 Mpa, determine the shaft diameter. Answer: CA. 100 mmB. 90 mmC. 92 mmD. 98 mm49. A 100 mm diameter shaft is subjected to a torque of 6 KN-m and a bending moment of 2.5 KN-m. Find the maximum bending stress developed. Answer: AA. 45.84 MpaB. 60.25 MpaC. 50.28 MpaD. 55.46 Mpa50. A round steel shaft transmits Hp at 1800 rpm. The shear modulus of elasticity is 12,000,000 psi. The torsional deflection is not to exceed 1 deg in a length equal to 20 times the diameter. Find the shaft diameter. Answer: BA. 1.04 inB. 0.257 inC. 0.864 in

D. 2.045 in

51. A line shaft is to transmit 200 Hp at 900 rpm. Find the diameter of the shaft. Answer: BA. 2 3/16 inB. 2 7/16 inC. 3 15/16 in

D. 1 3/16 in

52. A centrifugal pump is directly coupled to a motor. The pump rating is 3,600 liters per a minute against a total head of 8 meters of water. Pump efficiency is 65% at a speed of 550 rpm. Calculate the torsional stress induced on the 40 mm diameter motor shaft. Answer: CA. 11,193.45 KpaB. 13,467.34 KpaC. 10,010.85 KpaD. 16,345.67 Kpa53. A round steel shaft transmits 0.375 Kw at 1800 rpm. The shear modulus of elasticity is 80 Gpa. The torsional deflection is not to exceed 1 degree in a length equal to 20 diameters. Find the shaft diameter. Answer: AA. 6.621 mmB. 8.342 mmC. 12.344 mmD. 16.345 mm54. A round steel shaft rotates at 200 rpm and is subjected to a torque of 225 N.m and a bending moment of 340 N.m. The allowable shearing stress is 40 MN/m2, the allowable tensile is 53.3 MN/m2. Find the dimater. Answer: AA. 6.621 mmB. 8.342 mmC. 12.344 mm

D. 16.345 mm

55. A 1 in diameter shaft is to be replaced with a hollow shaft of the same material, weighing half as much, but equally strong in torsion. The outside diameter of the hollow shaft is to be 1 in. Find the inside diameter. Answer: AA. 1.322 inB. 2.132 inC. 1.653 inD. 3.123 in56. A in diameter shaft is designed with a working stress of 7000 psi in shear. If it rotates at 1725 rpm and shear modulus of elasticity is 12,000,000 psi, what is the torsional deflection in degrees per foot of length? Answer: CA. 3.820B. 2.560C. 3.210D. 4.23057. A hollow shaft has an outside diameter of 4 in and an inside diameter of 3 in. Find the diameter of a solid shaft with equal strength in torsion. Answer: DA. 2.12 inB. 3.23 inC. 4.23 in

D. 3.52 in

58. A in steel shaft transmits 30 in-lb of torque. The effective length of the shaft is 12 in; the modulus of elasticity in shear is 12,000,000 psi. Find the angular deflection in degrees. Answer: CA. 2.240B. 1.230C. 4.480D. 6.34059. A 1 in Monel shaft is used in a torsional application. Based on operating speed of 100 rpm and safety factor of 12. How much horsepower can it transmit? Assume the shearing stress is of the ultimate tensile stress which is 100,000 psi. Answer: AA. 6.57 hpB. 3.45 hpC. 2.34 hpD. 5.23 hpKEYS

1. A 76.2 mm in diameter shafting of SAE 1040 grade, cold rolled, having a yield point of 50 ksi and with a x 5 inches key. Compute the minimum yield point in the key in order to transmit the torque of the shaft. The factor of safety to use is 2 and Sys = 0.50 Sy. Answer: DA. 39.120 ksiB. 42.130 ksiC. 279.20 ksiD. 47.120 ksi2. A keyed sprocket delivers a torque of 778.8 N.m thru the shaft of 54 mm OD. The key thickness is 1.5875 cm and the width is 1.11 cm. Compute the length of the same key. The permissible stress value of 60 Mpa for shear and 90 Mpa for tension. Answer: DA. 39.12 cmB. 4.82 cmC. 52.22 cmD. 4.32 cm3. A 76.2 mm in diameter shafting of SAE 1040 grade, cold rolled, having a yield point of 50 ksi and with a x x 5 inches key. Compute the minimum yield point in the key in order to transmit the torque of the shaft. The factor of safety to use is 2 and Sys = 0.50 Sy. Answer: DA. 47.52 ksiB. 47.25 ksiC. 47.12 ksi

D. 47.21 ksi

4. A keyed gears delivers a torque of 912.4 N-m thru its shaft of 63.5 mm outside diameter. If the key has a thickness of 15.875 mm and width of 11.1125, find the length of the key. Assume the permissible stress values of 61.2 Mpa for shear and tension at 99.8 Mpa. Answer: CA. 47.42 mmB. 39.72 mmC. 42.22 mmD. 46.92 mm5. A metric M4 x 15 square key is used with a 16 mm shaft. If the allowable shearing stress is 50 Mpa. How much torque can the assembly handle? The rotational speed of the shaft is 600 rpm. Answer: CA. 20 N-mB. 12 N-mC. 24 N-mD. 34 N-m6. A flat key is to be designed for 75 mm diameter shaft which will transmit 150 KW at 400 rpm. If allowable shearing stress is 200 Mpa and key width is 55 mm, determine the length of key. Answer: BA. 30.65 mmB. 31.83 mmC. 33.75 mmD. 32.85 mm7. A rectangular key is used in pulley to transmit 100 Kw at 1000 rpm on 50 mm shaft diameter. Determine the force required to remove the shaft from the hub if friction is 0.4. Answer: DA. 33.24 KNB. 36.85 KNC. 28.35 KND. 30.55 KN8. A 7/16 in height x 3 in length flat key is keyed to a 2 inches diameter shaft. Determine the torque in the key if bearing stress allowable is 25 Ksi. Answer: AA. 16,406.25 in-lbB. 15,248.56 in-lbC. 17.42 in-lbD. 246.75 in-lb9. A rectangular key is used in pulley connected to a line shaft at 15 Kw and 600 rpm. If shearing of key is 230 Mpa, determine the force acting on key length if key width one-fourth of shaft diameter and key length is 1 inch. Answer: CA. 43 KNB. 48 KNC. 45 KN

D. 46 KN

10. A square key is to be used in 40 mm diameter shaft and that will developed a 2 KN-m torque. If bearing stress of the key is 400 Mpa, determine the cross sectional dimension of square key to be used if key length is 30 mm. Answer: DA. 324.80 mm2B. 246.80 mm2C. 446.80 mm2D. 277.77 mm211. A 100 KN force is acting on a key that has a length of 4 times its height. If bearing stress of key is 400 Mpa, determine the height of key. Answer: BA. 10.54 mmB. 11.18 mmC. 12.65 mm

D. 15.25 mm12. A one meter pulley is fastened to a 100 mm shaft by means of 25 mm square key and 150 mm long. What force tangent to pulley rim will shear the key if shear stress is 200 Mpa? Answer: CA. 65 KNB. 70 KNC. 75 KND. 80 KN13. A 1.2 m pulley is fastened to a 120 mm shaft by means of a square key with 140 mm long. What force tangent to pulley rim will crush the key if bearing stress is 410 Mpa. Assume key and shaft are of the same material. Answer: CA. 160.42 KNB. 165.25 KNC. 180.42 KN

D. 172.20 KN

COUPLING

1. A flanged bolt coupling has ten (10) steel 25.4 mm diameter bolts evenly tighten around a 415 mm bolt circle. Determine the torque capacity of the connection if the allowable shearing stress in the bolt is 50 MN/m2. Answer: BA. 59.95 KN.mB. 52.6 KN.mC. 46.15 KN.mD. 43.8 KN.m2. A flanged bolt coupling consists of eight 20 mm diameter steel bolts space evenly around a bolt circle 300 mm in diameter. If the coupling is subjected to a torque of 15.1 KN-m, determine the maximum shearing stress in the bolts? Answer: AA. 40 MpaB. 38 MpaC. 70 MpaD. 29 Mpa3. A flanged coupling having 180 mm bolt circle and 19 mm thick uses 8 bolts, 16 mm diameter to connect two shaft. It is used to transmit 60 Kw at 180 rpm. Determine the factor of safety in bearing if yield point in compression is 448 Mpa. Answer: CA. 15.6B. 18.5C. 30.8D. 25.44. A turbine connected to generator by means of flanged coupling that has a bolt circle diameter of 500 mm. The generator output is 40 MW, 3600 rpm and 90% efficiency. If there are 16 bolts, determine the force acting on each bolt. Answer: BA. 26.41 KNB. 29.47 KNC. 35.62 KN

D. 32.61 KN5. A 75 mm diameter shaft is transmitting 300 Kw at 600 rpm. A solid coupling has a 6 bolts each 18 mm in diameter. Find the required bolt circle diameter if shearing stress in bolts is 27.5 Mpa.. Answer: AA. 227.40 mmB. 233.60 mmC. 254.50 mmD. 272.60 mm6. The total force of 125 KN is required of flange coupling that has 5 bolts has also shearing stress of 30 Mpa for bolt. Determine the required diameter of bolt. Answer: DA. 62.54 KNB. 54.21 KNC. 45.62 KND. 32.57 KN7. A flanged coupling with bolt circle diameter of 250 mm uses 8 bolts, 25 mm diameter. The torque transmitted is 15 KN-m and compressive stress of bolt is 15 Mpa. Determine the required flange thickness. Answer: DA. 25 mmB. 30 mmC. 35 mmD. 40 mmPRESSURE VESSEL

1. Find the thickness of a metal needed in the semi-spherical end of cylindrical vessel 0.70 meter in diameter subjected to an internal pressure of 2.7 N/mm2. The material is mild carbon steel and tensile stress is 69 N/mm. Answer: DA. 5.2 mmB. 6.02 mmC. 7.53 mmD. 6.84 mm2. A cylindrical tank with 10 inches inside diameter contains oxygen gas at 2500 psi. Calculate the required wall thickness in millimeter under stress of 28,000 psi. Answer: BA. 10.54B. 11.34C. 10.24D. 12.443. Determine the bursting pressure of steel with diameter of 10 inches and make of in thick plate. The joint efficiency is at 70% and the tensile strength is 60 ksi. Answer: DA. 4,020 psiB. 4,002 psiC. 2,400 psiD. 4,200 psi4. Determine the safe wall thickness of a 30 inches steel with internal pressure of 7.82 Mpa. The yield stress of material is at 275.48 Mpa. The factor of safety to use is 2.0. Answer: CA. in B. 23.4 cmC. 21.6 mmD. 5/8 in5. Determine the bursting steam pressure of a steel shell with a diameter of 10 inches and made of inch thick steel plate. The joint efficiency is at 70% and the tensile strength is 60 ksi. Answer: AA. 4,200 psiB. 10.5 psiC. 42.8 psi

D. 8,500 psi

6. Compute the safe wall thickness of a 76.2 cm diameter steel tank. The tank is subjected to 7.33 Mpa pressure and the steel material has yield stress of 215.4 Mpa. The factor of safety to use is 3.Answer: BA. 1 inB. 3.89 cmC. 4.09 cmD. 3.69 cm7. A steel cylinder air receiver with 5 feet diameter and pressure load of 180 psi, design stress of 9500 psi maximum. The pressure vessel is to be provided with 1 diameter drain valve installed at the bottom of the vessel and safety pressure relief valve installed either at the top most or at the side with prop-out rating of 200 psi. Assume a 100% weld joint efficiency. The lap welding tensile strength is 65,000 psi. Determine the bursting pressure of this air receiver. Answer: BA. 1154 psiB. 1354 psiC. 1454 psi

D. 1254 psi

8. Determine the thickness of a steel air receiver with 30 inches diameter and pressure load of 120 psi, design stress of 8000 psi. Answer: AA. 1/4 inB. 3/8 inC. 5/8 inD. 1/2 in9. A cylindrical tank with 10 inside diameter contains oxygen gas at 2500 psi. Calculate the required wall thickness in (mm) under stress of 28,000 psi. Answer: CA. 11.44 mmB. 10.6 mmC. 11.34 mmD. 10.3 mm10. Determine the internal pressure of a cylindrical tank 500 mm internal diameter, 20 mm thick and 3 m long if stress is limited to 140 Mpa. Answer: CA. 10.06 MpaB. 10.52 MpaC. 11.20 MpaD. 12.88 Mpa11. A water tank 10 m x 12 m is completely filled with water. Determine the minimum thickness of the plate if stress is limited to 50 Mpa. Answer: AA. 11.77 mmB. 12.66 mmC. 13.55 mm

D. 12.44 mm

12. A spherical shell of 1.8 m outside and 1.725 m inside diameter contains helium at a pressure of 10.4 Mpa. Compute the stress in the shell.. Answer: BA. 124.08 MpaB. 119.06 MpaC. 96.48 MpaD. 88.46 Mpa13. A 600 mm diameter spherical steel pressure vessel has a uniform 8 mm wall thickness and an internal gage pressure of 10 Mpa. If the ultimate stress of steel is 420 Mpa, determine the factor of safety with respect to tensile of failure. Answer: AA. 2.30B. 1.89C. 2.69D. 1.4814. Determine the largest internal pressure which maybe applied to a cylindrical tank 2 m in diameter and 15 mm wall thickness, if the ultimate stress of steel is 420 Mpa and a factor of safety of 4.5. Answer: AA. 1.4 MpaB. 2.6 MpaC. 1.8 MpaD. 2.2 Mpa15. The cylinder of a hydraulic press is made up of thick walled cylinder having an inside diameter of 300 mm. It is subjected to an internal pressure of 40 Mpa. Determine the thickness of a cylinder without exceeding a shearing stress of 80 Mpa. Answer: CA. 62.13 mmB. 58.61 mmC. 109.80 mmD. 72.40 mm16. The internal pressure of a 400 mm internal diameter cylindrical tank is 10 Mpa and tank thickness is 25 mm. Determine the stress developed if joint efficiency is 95%. Answer: BA. 80.10 MpaB. 84.21 MpaC. 86.75 Mpa

D. 78.42 Mpa

17. A spherical tank 15 mm thick has an internal pressure of 5 Mpa. The joint efficiency is 96% and stress is limited to 46,875 Kpa. Find the tank internal radius. Answer: CA. 540 mmB. 200 mmC. 270 mmD. 300 mm18. A cylindrical tank has an inside diameter of 5 in and is subjected to an internal pressure of 500 psi. If maximum stress is 1200 pasi, determine the required thickness. Answer: CA. 1 inB. 1.2 inC. 1.4 inD. 1.6 in19. A thick wall cylinder has 50 mm thick and internal diameter of 300 mm. If stress is limited to 30 Mpa, determine the maximum internal pressure. Answer: DA. 8.1 MpaB. 8.2 MpaC. 8.3 Mpa

D. 8.4 Mpa

20. A round vertical steel tank has inside diameter of 3 m and 6 m height. It contains gasoline with a density of 750 Kg/m3. If the allowable tensile stress is 25 Mpa, find the minimum thickness required. Answer: AA. 2.65 mmB. 2.85 mmC. 3.65 mmD. 1.82 mm21. A cylinder having an internal diameter of 16 in and external diameter of 26 inches is subjected to 1500 psi external pressure and internal pressure of 9,000 psi. Determine the hoop stress on outer surface of cylinder. Answer: BA. 8,742.65 psiB. 7,642.85 psiC. 9,400.62 psiD. 9,471.43 psi22. A cylindrical tank has a mean diameter of 40 cm and thickness of 10 cm. It is subjected to an external pressure of 140 kg/cm2. Determine the maximum internal tangential stress is 900 kg/cm2. Determine the maximum internal pressure of the tank. Answer: AA. 2947.5 kg/cm2B. 3426.5 kg/cm2C. 1246.5 kg/cm2D. 1942.6 kg/cm2BOLTS & POWER SCREW1. Compute the working strength of 1 in bolt is screwed up tightly in packaged joint when the allowable stress is 13,000 psi. Answer: DA. 3,600 lbsB. 3,700 lbsC. 3,800 lbsD. 3,900 lbs2. What is the working strength of a 2inches bolt which is screwed up tightly in a packed joint when the allowable working stress is 12,000 psi. Answer: AA. 20.4 klbB. 22.4 klbC. 23.4 klbD. 18 klb3. An eyebolt is lifting a block weighing 350 lbs. The eyebolt is of SAE C 1040 material with SU = 67 ksi and SY = 55 ksi, what is the stress area ( in inches square ) of the bolt if it is under the unified coarse series thread? Answer: BA. 0.1341B. 0.1134C. 0.0991D. 0.10434. If the pitch of a screw is 2/9 find the thread per inch. Answer: BA. 0.34B. 4.5C. 5.4D. 175. Find the horsepower lost when a collar is loaded with 1000 lb rotates at 25 rpm, and has a coefficient of friction 0.15. The outside diameter of the collar is 4 in and the inside diameter is 2 in. Answer: CA. 0.045 hpB. 0.89 hpC. 0.089 hpD. 0.56 hp6. Compute how many 3/8 inch diameter set screws required to transmit 3 HP at a shaft speed of 1000 rpm. The shaft diameter is 1 inch. Answer: BA. 1 1/2B. 2C. 3D. 17. What is the frictional Hp acting on a collar loaded with 100 kg weight? The collar has an outside diameter of 100 mm amd an internal diameter of 40 mm. The collar rotates at 1000 rpm and the coefficient of friction between the collar and the pivot surface is 0.15. Answer: AA. 0.8 HpB. 0.3 HpC. 0.5 HpD. 1.2 Hp8. Determine the permissible working stress of a UNC bolts that has a stress area of 0.606 in2 if material used is carbon steel. Answer: AA. 4055.5 psiB. 5244.5 psiC. 4675.5 psiD. 4185.5 psi9. The stress area of NC bolt is 0.763 in2, if material used is carbon steel, determine the applied load on the bolt. Answer: AA. 3407.14 psiB. 5244.5 psiC. 4675.5 psiD. 4186.5 psi10. A 12 cm x 16 cm air compressor has 5 bolts on cylinder head with yield stress of 440 Mpa. If the bolt stress area is 0.13 in2, determine the maximum pressure inside the cylinder. Answer: BA. 546.71 psiB. 671.96 psiC. 742.78 psiD. 840.60 psi11. The cylinder head of ammonia compressor has core gasket area of 80 cm2 and flanged pressure of 90 kg/cm2. Determine the torque applied on the bolt if nominal diameter of bolt used is inch and there 5 bolts. Answer: AA. 476.28 in-lbsB. 586.28 in-lbsC. 696.28 in-lbsD. 666.26 in-lbs12. The total torque required to turn the power screw is 50 N-m. If linear speed of screw is 8 ft/min and lead of 8 mm, determine the Hp input of the power screw. Answer: CA. 2.82 HpB. 2.54 HpC. 2.14 HpD. 2.38 Hp13. A single square thread power screw has a lead of 6 mm and mean diameter of 34 mm. It is used to lift a load of 26 KN and coefficient of friction of thread is 0.15, determine the torque required to turn the screw. Answer: AA. 91.9 N-mB. 65.8 N-mC. 72.6 N-mD. 86.5 N-m14. An ACME thread power screw that has a mean diameter of 25 mm and a pitch of 5 mm is used to lift a load of 500 kg. If friction on threads is 0.1, determine the torque needed to turn the screw. Answer: AA. 10.30 N-mB. 12.63 N-mC. 13.10 N-m

D. 14.10 N-m

15. The torque required to overcome collar friction of a 100 mm mean diameter collar power screw is 50 N-m and collar friction of 0.15. Determine the weight lifted by the screw. Answer: DA. 458.57 kgB. 478.57 kgC. 487.57 kgD. 679.57 kg16. A double square thread power screw has a mean radius of 80 mm and a pitch of 10 mm is used to lift a load of 80 KN. If friction of screw is 0.13 and collar torque is 20% of input torque, determine the input torque required. Answer: DA. 830.76 N-mB. 835.76 N-mC. 1246.30 N-m

D. 1365.30 N-m

17. The root diameter of a double square thread power screw is 0.55 in. The screw has a pitch of 0.2. Determine the major diameter. Answer: BA. 0.524 inB. 0.750 inC. 0.842 inD. 0.961 in18. A power screw consumes 6 Hp in raising a 2800 lb weight at the rate of 30 ft/min. Determine the efficiency of the screw. Answer: CA. 12.5%B. 16.8%C. 42.42%D. 66.62%19. A square thread power screw has a pitch diameter of 1.5 and a lead of 1. Neglecting collar friction, determine the coefficient of friction for threads if screw efficiency is 63.62%. Answer: AA. 0.113B. 0.121C. 0.146D. 0.15120. A square thread screw has an efficiency of 70% when friction of threads is 0.10 and collar friction is negligible. Answer: AA. 14.300B. 10.370C. 12.430D. 16.450FLYWHEEL1. A cast iron flywheel is rotated at a speed of 1200 rpm and having a mean radius of 1 foot. If the weight of the rim is 30 lbs, what is the centrifugal force? Use factor C = 41. Answer: DA. 14,800 lbsB. 14,860 lbsC. 7 mtD. 14,724 lbs2. A flywheel for a punching press must be capable of furnishing 3400 N-m of energy during the 25% revolution while the hole is being punched. The flywheel maximum speed is 200 rpm and the speed decreases 8.7% during the load stroke. The mean radius of the rim is 1016 mm diameter and contributes 90% of the energy requirements. Approximate total weight of the flywheel to be 1.20 times that of the rim. Find the weight of the flywheel. Answer: AA. 97.5 kgB. 65.2 kgC. 103.34 kgD. 234.5 kg3. A press is used to punch 10 holes per minute of 30 mm diameter hole from 25 mm thick plate. Determine the power needed to punch a hole if ultimate shear stress is 400 Mpa. Answer: BA. 2.68 KwB. 1.96 KwC. 3.58 KwD. 0.96 Kw4. The kinetic energy needed to punch a hole is 5 KJ. What is the maximum thickness of a hole that can be punch if hole diameter is 25 mm and ultimate shearing stress of plate is 420 Mpa. Answer: CA. 12.61 mmB. 14.68 mmC. 17.41 mmD. 19.62 mm5. During a punching process of 350 kg flywheel the speed varies from 200 rpm to 180 rpm with 1 m mean diameter. Determine the kinetic energy released by the flywheel. Answer: AA. 3.64 KJB. 6.28 KJC. 4.51 KJD. 5.62 KJ6. A plate 200 mm wide and 25 mm thick with strength of 410 Mpa is to be shear along its width. During shearing process an 800 mm mean diameter flywheel changes its speed from 200 rpm to 180 rpm. Determine the weight of flywheel to be use. Answer: DA. 3265.84 kgB. 3452.71 kgC. 3821.72 kgD. 3845.97 kg7. The energy required to punch a square hole from 20 mm thick plate is 10 KJ. If the ultimate strength of plate is 420 Mpa, determine the maximum sides of square that can be punched. Answer: BA. 45 mmB. 30 mmC. 60 mmD. 55 mm8. A 1 mm mean diameter flywheel, 500 kg weight changes its speed from 220 rpm to 200 rpm during shearing process. What average force is needed to shear a 30 mm thick plate. Answer: AA. 384 KNB. 653 KNC. 234 KND. 1082 KN9. The energy required to punch a hole is 3 KJ from a flywheel mean diameter of 800 mm that slows down from 3.3 rps to 3 rps during punching. If weight of arm and hub account 10% of rim weight, determine the rim weight. Answer: BA. 421.08 kgB. 457.40 kgC. 482.68 kgD. 416.68 kg10. A flywheel has a total weight of 500 kg and the weight of arm and hub is 8% of total weight. It has a mean diameter of 1 m and width of 300 mm. Determine the thickness of the flywheel if density of material is 7000 kg/m3. Answer: CA. 60.65 mmB. 65.48 mmC. 69.72 mmD. 75.42 mm11. A flywheel has a rim weight of 450 kg and mean radius of 450 mm. If the rim width is 5 times the rim thickness and material density is 7200 kg/m3, determine the width of flywheel. Answer: AA. 332.45 mmB. 242.61 mmC. 286.76 mmD. 298.78 mm12. The power required to shear a plate 50 mm thick for 10 seconds is 5 Kw. If ultimate strength of plate is 420 Mpa. How wide should the plate be? Answer: DA. 80.42 mmB. 85.65 mmC. 90.28 mmD. 95.23 mm13. A 900 mm mean diameter flywheel has a width of 350 mm, 75 mm thick and density of 7100 kg/m3. Neglecting the weight of arm and hub, find the energy released if its speed changes from 280 rpm to 250 rpm. Answer: BA. 7.89 KJB. 9.30 KJC. 5.48 KJD. 6.71 KJ14. A flywheel weighing 1000 kg has a radius of gyration of 1.5 m. The normal operating speed is 160 rpm and coefficient of fluctuation is 0.08, determine the energy released by the flywheel. Answer: DA. 31.70 KJB. 36.70 KJC. 41.70 KJD. 46.70 KJ15. A 5 ft mean diameter flywheel has to absorb 3500 ft-lb of energy and maintain a coefficient of fluctuation of 0.09. If mean speed is 80 ft/sec, find the weight of flywheel. Answer: BA. 190.66 lbsB. 195.66 lbsC. 198.66 lbsD. 200.77 lbsSPRING1. A body weighing 1000 lbs falls from a height of 6 in and strikes a 2000 lb/in spring. The deformation of the spring is_______. Answer: CA. 2B. 4C. 3D. 52. Compute the deflection of an 18 coils helical spring having a load of 100 kg. The modulus of elasticity in shear of spring is 96.62 Gpa, OD of 9.256 cm and with wire diameter of 9.525 mm. The spring is squared and ground ends. Answer: AA. 9 cmB. 101 cmC. 11 cmD. 14 cm3. Compute the maximum deflection of a 20 coils helical spring having a load of 75 kgs. The spring is a square/ground ends with modulus of elasticity in shear of 79.84 Gpa, outside diameter of 101.6 mm, wire diameter of 9.525 mm. Answer: DA. 140.7 mmB. 112.7 mmC. 15.17 mmD. 126.7 mm4. A three extension coil springs are hooked in series that support a single weight of 100 kg. The first spring is rated at 0.400 kg/mm and the other 2 lower springs is rated at 0.64 kg/mm. Compute the total deflection. Answer: AA. 563 mmB. 268 mmC. 156 mmD. 250 mm5. A high alloy spring having squared and ground ends and has a total of 16 coils and modulus of elasticity in shear of 85 Gpa. Compute the Wahl factor. The spring outside diameter is 9.66 cm wire diameter is 0.65 cm. Answer: CA. 1.058B. 1.185C. 1.10D. 1.26. A coil spring with 5 cm outside diameter is required to work under the load of 190 N. The wire diameter is 5 mm, the spring is to have 6 active coils and the ends are to be closed and ground. Determine the total number of coils. The modulus of rigidity is 80 Gpa, and the mean radius is to be 23 mm, with 7 mm pitch of the spring. Answer: BA. 6.5 coilsB. 8.5 coilsC. 7.5 coilsD. 9.5 coils7. A helical spring having square and ground ends a total of 18 coils and its material has modulus of elasticity in shear of 78.910 Gpa. If spring has an outside diameter of 10.42 cm and wire diameter of 0.625 cm, compute the maximum deflection that can be produced in the spring due to a load of 50 kgs. Answer: BA. 302 mmB. 490 mmC. 342 mmD. 322 mm8. An extension coil spring is to be elongated 5 in under a load of 50 lb. What is the spring rate? Answer: BA. 5 lb/minB. 10 lb/minC. 15 lb/minD. 20 lb/min9. A spring has a rate of 50 lb with a spring index of 8. If stress induced is 90,000 psi, determine the wire diameter. Answer: DA. 0.058 inB. 0.828 inC. 0.452 inD. 0.1157 in10. Determine the maximum shearing stress of a helical spring composed of 20 turns of 20 mm diameter wire on a mean radius of 80 mm when the spring is supporting a load of 2 KN. G = 83,000 Gpa. Answer: CA. 108.20 MpaB. 98.62 MpaC. 120.60 MpaD. 88.68 Mpa11. A helical spring is made by wrapping steel wire 20 mm diameter around a forming cylinder 150 mm in diameter. Compute the elongation of the spring without exceeding a shearing stress of 140 Mpa if it is composed of 18 turns. Answer: CA. 96.42 mmB. 100.6 mmC. 117.57 mmD. 89.62 mm12. It is found that a load of 50 lbs on extension coil spring deflects 8.5 in. What load will the spring deflects 2.5 in? Answer: DA. 10.64 lbB. 12.48 lbC. 13.48 lbD. 14.70 lb13. A spring sustain 200 ft-lb of energy with deflection of 3 in. Assume that the coil diameter is 7 times the wire diameter and allowable stress of 100,000 psi, determine the wire diameter. Answer: AA. 0.416 inB. 0.321 inC. 0.568 inD. 0.672 in14. A weight of 100 lbs strikes a coil from a height of 18 inches and deflects the spring of 6 inches. Find the average force acting on the spring. Answer: CA. 600 lbB. 700 lbC. 800 lbD. 900 lb

15. Three coil spring are hooked in series and support a weight of 70 kg. One spring has a spring rate of 0.209 kg/min and the other two have spring rates of 0.643 kg.mm. Find the deflection. Answer: CA. 346.71 mmB. 389.30 mmC. 552.65 mmD. 416.58 mm16. Four compression coil spring in parallel support a load of 360 kg. Each spring has a gradient of 0.717 kg/mm. Find the deflection. Answer: AA. 125.52 mmB. 132.52 mmC. 138.52 mmD. 145.52 mm17. A force of 1.1 KN is acting on a 7.5 active coils with wire diameter of 13 mm. The outside diameter of coil is 117 mm and G = 80 GN/m2. Find the coil deflection. Answer: CA. 27.60 mmB. 29.80 mmC. 32.50 mmD. 34.60 mm18. A concentric helical spring is use to support a load of 90 KN. The inner spring has a rate of 495.8 KN/m and outside spring is 126.5 KN/m. If initially the inner spring is 25 mm shorter than the outer spring, find the percent load carried by inner spring. Answer: DA. 34.56%B. 55.86%C. 68.25%D. 76.81%19. How long a wire is needed to make helical spring having a mean diameter of 1 inch if there are 8 active coils? Answer: AA. 25.13 inB. 26.65 inC. 30.21 inD. 32.34 in20. A 0.08 diameter spring has a length of 20 in. If density of spring is 0.282 lb/in3, determine the mass of spring. Answer: BA. 0.0395 lbB. 0.0283 lbC. 0.0485 lbD. 0.0686 lb21. A square and ground ends spring has a free length of 250 mm. There are 10 active coils with wire diameter of 12.5 mm. If the spring rate is 150 KN/m and mean diameter is 100 mm, determine the solid stress. Answer: AA. 2,315.54 MpaB. 7,654.8 MpaC. 7,842.7 MpaD. 8,432.9 Mpa

22. A square and ground ends spring has a pitch of 20 mm, wire diameter of 12.5 mm. If there are 12 actual number of coils, find the deflection when the spring is compressed to its solid strength. Answer: BA. 78 mmB. 75 mmC. 77 mmD. 79 mm23. A spring with plain ends has 15 active coils, diameter of 6 mm and pitch of 10 mm. If spring rate is 100 KN/m, determine the solid force. Answer: CA. 4 KNB. 5 KNC. 6 KND. 7 KN24. A spring has a spring rate of 30 KN/m. If wire diameter is 10 mm with mean diameter of 70 mm, determine the number of active coils. G = 80 GN/m2. Answer: DA. 6.54 B. 7.82C. 8.42D. 9.7225. A spring has a diameter of 25 mm and 12 active coils. If a load of 10 KN is applied it deflects 75 mm. Determine the mean diameter of the spring if G = 80 GN/m2. Answer: CA. 124.65 mmB. 129.65 mmC. 134.65 mmD. 140.65 mmGEAR1. Compute the tooth thickness of 14 deg. spur gear with diameter pitch of 5. Answer: AA. 0.34116 inB. 0.31146 inC. 0.41416 inD. 0.31461 in2. A 36 tooth pinion with a turning speed of 300 rpm drives 120 tooth gear of 14 degrees involute full depth pressure angle. What would be the speed of the driven gear. Answer: CA. 1000 rpmB. 100 rpmC. 90 rpmD. 140 rpm3. A triple thread worm has a pitch diameter of 3 inches. The wheel has a 25 teeth and a pitch diameter of 5 inches. Material for both the worm and the wheel is of phosphor bronze. Compute the helix angle (tan ). Answer: AA. 0.20B. 0.30C. 0.40D. 144. Find the tooth thickness on tooth circle of a 20 degree full depth involute tooth having a diametrical pitch of 3, circular pitch of 1.0472 and whole depth of tooth at 0.60. Answer: BA. 10.7 mmB. 13.2 mmC. 10.1 mmD. 7.9 mm5. A pair of gear/pinion of 42 tooth and 18 tooth with a diametrical pitch of 0.7874 teeth/cm and the addendum is 0.80/p and the addendum 1/p. The gear pressure angle is 200. Compute the center distance of the pair of gears in meters. Answer: CA. 0.5026 mB. 0.3426 mC. 0.381 mD. 0.4013 m6. A helical gear having a 14 1/20 normal pressure angle and transverse diametrical pitch of 2.3622 per cm. The helix angle is at 450 and has 8 teeth. Compute the transverse pressure angle in degrees. Answer: DA. 22.20B. 18.90C. 19.30D. 20.107. Two idlers of 28T and 26T are introduced between the 24T pinion with a turning speed of 400 rpm driving a final 96T gear. What would be the final speed of the driven gear and its direction relative to the driving gear rotation? Answer: CA. 120 rpm and opposite directionB. 80 rpm and same directionC. 100 rpm and opposite directionD. 100 rpm and same direction8. A spur pinion rotates at 1800 rpm and transmits to a mating gear 30 HP. The pitch diameter is 4 and the pressure angle is 14 1/2. Determine the tangential load in lbs. Answer: CA. 495B. 535C. 525D. 4759. Compute the pitch angle of a bevel gear given the pinions number of teeth of 14 and 42 teeth on the gear. Answer: AA. 18.40B. 33.40C. 28.40D. 38.4010. Compute the circular pitch of a pair of gears having a ratio of 4 and a center distance of 10.23. Each gear has 72 teeth and pinion has 18 teeth. Answer: CA. 0.8095B. 0.8035C. 0.7854D. 0.808511. The tooth thickness of a gear is 0.5 inch and its circular pitch is 1.0 inch. Calculate the dedendum of the gear. Answer: BA. 0.3183B. 0.3979C. 1.250D. 0.111412. An internal gear is set up with a 5 in diameter pinion and center distance of 18 inches. Find the diameter of the internal gear. Answer: DA. 36B. 21.5C. 26D. 4113. The minimum whole depth of spur gear of 14-1/2 deg. involute type with diameter pitch of 24 and circular pitch of 0.1309. Answer: CA. 0.09000B. 0.08900C. 0.08987D. 0.0897514. The minimum clearance allowed for meshing spur gears with a circular pitch of 0.1571 and diametrical pitch of 20. The spur gear have 25 teeth. Answer: AA. 0.007855B. 0.007558C. 0.008578D. 0.00758515. Find the distance between centers of a pair of gears, one of which has 12 teeth and the other 37 teeth. The diametrical pitch is 7. Answer: BA. 3 inB. 3.5 inC. 4 inD. 4.5 in16. Determine the pitch diameter of a gear with 28 teeth, 4 diametrical pitch. Answer: AA. 7 inB. 8 inC. 9 inD. 10 in17. Two parallel shafts have an angular velocity ratio of 3 to 1 are connected by gears, the largest of which has 36 teeth. Find the number of teeth of smaller gear. Answer: CA. 10B. 11C. 12D. 1318. The parallel shafts have a center distance of 15 in. One of the shaft carries a 40-tooth, 2 diametrical pitch gear which drives a gear on the other shaft at a speed of 150 rpm. How fast is the 40-tooth turning? Answer: DA. 600 rpmB. 300 rpmC. 150 rpmD. 75 rpm19. A pair of meshing gears has a diametrical pitch of 10, a center distance of 2.6 inches, and velocity ratio of 1.6. Determine the number of teeth of smaller gear. Answer: BA. 10B. 20C. 30D. 4020. A spur gear 20 degrees full-depth involute teeth has an outside diameter of 195 mm and a module of 6.5. Determine the number of teeth. Answer: CA. 20B. 25C. 28D. 4121. What is the pitch diameter of a 40-tooth gear having a circular pitch of 1.5708 in? Answer: AA. 20 inB. 25 inC. 30 inD. 35 in22. How many revolutions per minute is a spur gear turning if it has 28 teeth, a circular pitch of 0.7854 in and a pitch line velocity of 12 ft/sec? Answer: DA. 378.44 rpmB. 643.82 rpmC. 954.66 rpmD. 392.88 rpm23. How many revolutions per minute is a spur gear turning if it has a module of 2, 40 teeth, and a pitch line velocity of 2500 mm/sec? Answer: AA. 596.83 rpmB. 386.83 rpmC. 476.85 rpmD. 312.83 rpm

24. The module of a gear having a diametrical pitch of 8 is: Answer: BA. 5.234B. 3.175C. 4.23D. 2.3425. The diametrical pitch of a gear having a module of 2.3 is: Answer: BA. 9B. 11C. 10D. 1226. A gear turning 300 rpm has diametrical pitch of 8. If there are 40 teeth on the gear, find the pitch line velocity of gear. Answer: AA. 6.54 fpsB. 8.34 fpsC. 7.45 fpsD. 9.45 fps27. Two gears meshing each other have 18 teeth and 30 teeth. If circular pitch is 0.23 in. Find the center distance between gears. Answer: DA. 5.23 inB. 2.34 inC. 3.23 inD. 1.76 in28. A gear with pitch line velocity of 6.126 m/s when turning at 600 rpm. If module is 3, find the number of teeth on the gear. Answer: CA. 60B. 50C. 65D. 7029. Two gears meshing each other has a center distance of 200 mm. The pinion has 20 teeth and gear has 60 teeth. Find the module of meshing gears. Answer: DA. 2B. 4C. 3D. 530. A gear has a tooth thickness of 0.1308 in. Find the addendum of the gear at 14.50 involute. Answer: AA. 2.12 mmB. 4.12 mmC. 3.12 mmD. 5.12 mm31. A gear has an addendum of 0.10 in. What is the dedendum of the gear at 200 pressure involute. Answer: BA. 0.037 inB. 0.125 inC. 0.345 inD. 0.235 in32. A gear is use to transmit 12 Kw at 450 rpm with 26 teeth. If the diameter pitch of the gear is 10, find the force tangent to the gear. Answer: CA. 12.34 KNB. 14.24 KNC. 15.42 KND. 16.45 KN33. A gear is use to transmit 20 Kw at 600 rpm to a driven gear. The pinion has a pitch diameter of 200 mm. If pressure angle is 14.5 degrees, find the load that tends to separate the two gears. Answer: DA. 0.234 KNB. 0.534 KNC. 0.763 KND. 0.823 KN34. The pressure angle of the 12 in diameter gear is 20 degrees. The total load of the gear is 5 KN and is turning at 750 rpm. Find the power delivered by the gear. Answer: CA. 43.23 KNB. 64.23 KNC. 56.23 KND. 34.23 KN35. Three gears meshing each other has a driving power of 30 Kw with 900 rpm. The speed ratio is 1:3:5 and each meshing gear has an efficiency of 96%. Find the torque developed of the driven gear, KN.m. Answer: AA. 4.40B. 7.60C. 5.60D. 8.20BEARING1. A 1 inch horizontal shaft rotates at 500 rpm in a sleeve-type bearing. The coefficient of friction is 0.15. Calculate the horsepower lost in the bearing if the reaction between the shaft and the bearing is 800 lb. Answer: DA. 0.2634 hpB. 1.2344 hpC. 0.0925 hpD. 0.4759 hp2. A 2 in horizontal shaft rotates in a sleeve type bearing. The coefficient of friction is 0.10 and the shaft applies a load of 500 lb. Find the frictional resistance. Answer: DA. 20 lbsB. 40 lbsC. 30 lbsD. 50 lbs3. A bearing sustains a load of 4450 N. The shaft diameter is 100 mm, the coefficient of sliding friction is 0.01, and the shaft speed is 400 rpm. Find the horsepower lost in the bearing. Answer: AA. 93.20 wattsB. 76.34 wattsC. 83.45 wattsD. 45.23 watts4. A 50 mm diameter shaft supported by two sleeve bearings carries a load of 13.3 MN. The shaft rotates at 150 rpm. If the coefficient of sliding friction between the shaft and bearings is 0.1, how much power is lost in friction? Answer: AA. 261 kwB. 643 kwC. 345 kwD. 108 kw5. A 36 mm shaft uses a sleeve bearing that sustain a load of 4000 N. If the allowable bearing pressure is 1.3 MN/m2. Find the length of the bearing. Answer: DA. 75.47 mmB. 23.44 mmC. 89.23 mmD. 85.47 mm6. A 20 mm shaft uses sleeve bearings. The total load per bearing is 2000 N. An L/D ratio of 2.5 is desired. What is the bearing pressure? Answer: CA. 1 MpaB. 3 MpaC. 2 MpaD. 4 Mpa7. A 22 mm diameter shaft is supported by sleeve bearing at a distance of 0.50 m. A load of 2.2 KN is applied at 0.2 m from the left end. The sleeve bearings have an L/D ratio of 1.5. Find the maximum bearing pressure. Answer: AA. 1.82 MpaB. 3.45 MpaC. 2.12 MpaD. 5.23 Mpa8. A sleeve bearing is to have an LD ratio of 1.0 and an allowable bearing pressure of 0.5 MN/m2. Find the inside diameter and the length of the bearing if it is to sustain a load of 2550 N. Answer: BA. 23.45 mmB. 71.41 mmC. 45.34 mmD. 98.34 mm9. A sleeve bearing has an outside diameter of 1.50 in and a length of 2 in. The wall thickness is 3/16 in. The bearing is subjected to a radial load of 450 lb. Find the bearing pressure. Answer: CA. 100 psiB. 150 psiC. 200 psiD. 250 psi10. A thrust washer has an inside diameter of 12 mm and an outside diameter of 75 mm. If the allowable bearing pressure is 0.6 Mpa, how much load can it sustain? Answer: AA. 2582.9 NB. 1235.5 NC. 3293.44 ND. 8634.45 NBELTS

1. Find the angle of contact on the small pulley for an open belt drive with a 72 in center distance. The pulley diameters are 6 in and 12 in. Answer: AA. 175.22B. 170.34C. 185. 34D. 165.342. Find the belt length at a 72 in distance connected in open belt. The pulley diameters are 6 and 12 in. Answer: DA. 162.34 inB. 173.45 inC. 123.55 inD. 172.39 in

3. A 6 in diameter pulley turning at 600 rpm is belt connected to ma 12 in diameter pulley. If there is 4% slip, find the speed of the 12 in pulley. Answer: DA. 187 rpmB. 223 rpmC. 203 rpmD. 288 rpm4. For a given belt a manufacturer gives a horsepower rating of 2.5 hp per inch of width based on a belt speed of 2600 ft/min. The drive is to handle 10 hp and the arc of contact correction factor is 0.90. Find the width of belt needed. Assume that the belt widths are available in 1 inch increments. Answer: BA. 3 inB. 5 inC. 4 inD. 6 in5. A in round endless belt connects a 1 in diameter pulley with a 2 in pulley; spacing between pulleys is 4 in on centers. The allowable stress is 400 psi. If the 1 in pulley is the driver and rotates 100 rpm. How much horsepower can be transmitted? Assume the coefficient of friction to be 0.30 for each pulley. Answer: DA. 0.123 hpB. 1.234 hpC. 0.0115 hpD. 0.0090 hp6. A 3/8 in flat leather belt is 12 in wide and is used on a 24 in diameter pulley rotating 600 rpm. The specific weight of the belt is 0.035 lb/in3. The angle of contact is 150. If the coefficient of friction is 0.3 and the allowable stress is 300 psi how much hp can it transmit? Answer: BA. 34.5 hpB. 69.5 hpC. 78.5 hpD. 54.5 hp7. A 5 mm round belt connects a 20 mm pulley with a 40 mm pulley. The center distance is 150 mm. The 20 mm pulley rotates at 100 rpm and the coefficient of friction of the belt is 0.25. Find the horsepower capacity for this arrangement if the allowable belt stress is 2.6 N/mm2. Answer: CA. 0.12 kwB. 0.23 kwC. 0.00282 kwD. 0.054 kwBRAKE

1. The band brake of a band brake has 210 degrees of contact with its drum. By laboratory tests, it is found that the pull on the tight side is 800 lbs and the pull on the slack side is 285 lb. What is the coefficient of friction? Answer: AA. 0.281B. 0.753C. 0.186D. 0.4532. The inertia load on an electric brake is 32 lb-ft2 and the drive shaft is rotating at 2000 rpm. What average torque is required to bring this load to a complete stop in 1.2 sec? Answer: AA. 173.61 ft-lbsB. 153.45 ft-lbsC. 123.45 ft-lbsD. 237.23 ft-lbs3. The band of a band brake has a contact angle of 180. It is found experimentally that the pulls on the bands are 275 kg and 100 kg respectively under certain operating conditions. Find the coefficient of friction. Answer: DA. 0.973B. 0.567C. 0.197D. 0.3224. A brake requires 900 in-lb of torque to stop a shaft operating at 840 rpm in a period of 3.5 seconds. What is the inertial load expressed in lb-ft2? Answer: DA. 90.23B. 74.34C. 34.45D. 96.25CLUTCH

1. A cone clutch has an angle of 10 and coefficient of friction of 0.42. Find the axial force required if the capacity of the clutch is 7 kw at 500 rpm. The mean diameter of the active conical sections is 300 mm. Answer: CA. 234.45 NB. 186.45 NC. 368.49 ND. 492.45 N2. How much torque can a cone clutch transmit if the angle of the conical elements is 10 degrees the mean diameter of the conical clutch sections 200 mm and an axial force of 550 N is applied? Assume the coefficient of friction is 0.45. Answer: CA. 123.23 N-mB. 34.56 N-mC. 142.53 N-mD. 234. 56 N-m3. If the inertia is 90 lb-ft2 and the speed of the driven shaft is to be increased from 0 to 2500 rpm in 5 seconds, shaft material is of SAE 4140 with yield strength of 110,000 lb/in2, find the clutch starting torque in ft-lb. Answer: CA. 159B. 128C. 146D. 1914. Find the frictional radius for a disc clutch. The disc clutch has an outside diameter of 10 in and an inside diameter of 6 in. Answer: BA. 4.54 inB. 4.08 inC. 5.34 inD. 8.44 in5. In a clutch the outside diameter is 8 in and the inside diameter is 4 in. An axial force of 400 lb is used to hold the two parts together. If the coefficient of friction of the mating materials is 0.4, how much torque can the clutch handle? Answer: BA. 123.45 in-lbB. 497.80 in-lbC. 213.34 in-lbD. 563.23 in-lb6. A disc clutch has 6 pairs of contracting friction surfaces. The frictional radius is 2 in and the coefficient of friction is 0.3. An axial force of 100 lbs acts on the clutch. The shaft speed is 400 rpm. How much horsepower can the clutch transmit? Answer: AA. 2.28 hpB. 1.23 hpC. 3.23 hpD. 4.23 hp7. A cone clutch has cone elements at an angle of 10. The clutch transmits 20 hp at a speed of 100 rpm. The mean diameter of the conical friction sections is 16 in and the coefficient of friction is 0.3. Find the axial force needed to engage the clutch. Answer: AA. 246.37 lbsB. 212.56 lbsC. 234.56 lbsD. 346.78 lbs8. In a band clutch, the ratio of the pull on the tight side of the band to that of the slack side is 4:1. The band contacts the drum for 250 degrees. What is the coefficient of friction? Answer: BA. 0.123B. 0.318C. 0.234D. 0.4629. A band clutch has an angle of contact of 270 on a 15 in diameter drum. The rotational speed of the drum is 250 rpm and the clutch transmits 8 hp. The band is 1/16 in thick and has a design stress of 5000 psi. How wide should the band be? Assume a coefficient of friction of 0.40. Answer: CA. 2.123 inB. 3.234 inC. 1.014 inD. 4.354 in10. The angle of contact of a band clutch is 250 degrees. The cross section of the band is 1/16 in x 1.5 in. The design stress for the band material is 8,000 psi. If the drum is 16 inches in diameter and rotates at 350 rpm, what is the horsepower capacity of the clutch? The coefficient of friction is 0.4. Answer: DA. 20.34 hpB. 15.23 hpC. 22.34 hpD. 27.50 hp11. Find the power capacity under uniform wear of a cone clutch with mean diameter of 250 mm if the conical elements are inclined 8 degrees and the axial force is 450 N. The rotational speed of the driver is 200 rpm and the coefficient of friction is 0.20. Answer: AA. 1.683 kwB. 2.340 kwC. 1.287 kwD. 3.234 kw12. Determine the power capacity of a cone clutch under uniform pressure and assuming the following conditions: major diameter = 250 mm; minor diameter = 200 mm; length of conical elements in contact = 125 mm; rotational speed = 870 rpm; coefficient of friction = 0.30; and allowable pressure = 70,000 N/m2? Answer: BA. 12.34 kwB. 19.09 kwC. 14.56 kwD. 23.45 kw13. Find the power capacity under uniform wear of a cone clutch with the following specification speed = 870 rpm; length of conical elements in contact = 125 mm; major diameter = 250 mm; minor diameter = 200 mm; coefficient of friction = 0.30; and axial operating force = 500 N. Answer: AA. 7.69 kwB. 5.23 kwC. 9.34 kwD. 3.23 kw14. Assuming uniform wear, find the power capacity of a single disc clutch with an outside and inside diameter of 200 mm and 100 mm respectively, rotational speed of 1160 rpm, a coefficient of friction of 0.35 and an axial operating force of 800 Newtons. Answer: BA. 4.23 kwB. 2.55 kwC. 6.32 kwD. 8.23 kwMACHINERIES

1. A flywheel on a press rotating at 120 rpm is slowed to 102 rpm during a punching process that requires sec for the punching portion of the cycle. What angular deceleration the flywheel experience? Answer: AA. -2.52 rad/s2B. -5.45 rad/s2C. -1.23 rad/s2D. -8.45 rad/s22. A 100 lb body is being hoisted by a winch, the tension in the hoisting cable being kept constant at 110 lb. At what rate the body is accelerated? Answer: BA. 1.22 ft/s2B. 3.22 ft/s2C. 2.22 ft/s2D. 4.44 ft/s23. A body of mass 50 kg is being hoisted by a winch, and the tension in the cable is 600 N. What is the acceleration? Answer: DA. 4.23 m/s2B. 5.23 m/s2C. 3.23 m/s2D. 2.19 m/s24. A flywheel has a diameter of 3 ft and weighs 1000 pounds. What torque must be applied, neglecting bearing friction, to accelerate the flywheel at the rate of 100 revolutions per minute, per second? Answer: CA. 265.8 ft-lbsB. 565.80 ft-lbsC. 365.80 ft-lbsD. 665.80 ft-lbs5. A flywheel has a diameter of 1.5m, and a mass of 800 kg. What torque is needed to produce an angular acceleration of 100 revolutions per minute, per second? Answer: DA. 5356 N.mB. 4356 N.mC. 3356 N.mD. 2356 N.m6. A 12 inch cube of steel weighing 490 lbs is being moved on a horizontal conveyor belt at a speed of 6 miles per hour (8.8 ft/s). What is the kinetic energy of the cube? Answer: BA. 323.45 ft-lbsB. 489.22 ft-lbsC. 534.34 ft-lbsD. 633.34 ft-lbs7. If a cube of mass 200 kg is being moved on a conveyor belt at a speed of 3 m/s, what is the kinetic energy of the cube? Answer: DA. 800 JB. 900 JC. 850 JD. 950 J8. A pile driver weighing 200 pounds strikes the top of the pile after being fallen from a height of 20 ft. If forces a pile into the ground a distance of foot. What is the average force of the blow? Answer: AA. 8,200 lbsB. 8,600 lbsC. 8,400 lbsD. 8,800 lbs9. A pile driver of mass 100 kilograms falls 10 meters and moves the pile a distance of 0.3 m. What is the average force of the blow? Answer: BA. 23.45 KNB. 33.68 KNC. 54.23 KND. 43.23 KN10. A 1000 lb block is pulled up a 2-degree incline by a cable exerting a constant force F of 600 lbs. If the coefficient of friction between the block and the plane is 0.5, how fast will the block be moving up the plane 10 seconds after the pull is applied? Answer: DA. 12.4 mphB. 10.2 mphC. 17.3 mphD. 14.3 mph11. A 500 kg block is pulled up a 2 degree incline by a constant force F of 4 KN. The coefficient of friction between the block and the plane is 0.5. How fast will the block be moving 10 seconds after the pull is applied? Answer: AA. 27.6 m/sB. 34.2 m/sC. 30.4 m/sD. 38.3 m/s12. A flywheel havin