beats: the interference of waves with different frequencies
TRANSCRIPT
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What is a beat?Have you ever been stopped at a red light in a car, waiting to turn, and noticed that your indicator light is blinking at a slightly different tempo than the car in front of you?
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At first they seem to be blinking at the exact same time, like two waves in phase
…but slowly the small time difference between the two signal lights increases, and eventually the indicators are blinking directly opposite to one another, like two waves perfectly out of phase
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Why do beats occur?
This oscillation between blinking together, opposite, and eventually together again, parallels how two waves with different frequencies create “beats” when superimposed
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Here are two waves, with frequencies of 10 and 11 Hz:
Begin in At t=0.5s, By t=1s, they
phase they are perfectly are back in
out of phase phase again
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When added together, the regions that are in phase undergo constructive interference, while opposing crests and troughs will cancel each other out in destructive interference
Because the regions between those in-phase and perfectly out-of-phase are offset due to the difference in frequencies, superimposing the waves results in something like this:
Constructive Destructive Constructive
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Tracing the outside limits of the superimposed wave creates a new wave, with a new frequency
Beat Frequency
This beat has a frequency of 1 Hz
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Beat Frequency*The frequency of the beat is directly linked to the frequencies of the two waves used to create it
Our two waves had frequencies of 10 and 11 Hz, and when added together, the beat they created has a frequency of 1 Hz
So, the beat frequency (fb) = fwave 2- fwave 1
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Because frequency cannot be negative, the formula for beat frequency becomes:
fb = |f2 – f1|
This formula can be used to find the frequency for any beat, given the frequencies of the two original waves
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Let’s Practice
Two sound waves travelling in the same direction with frequencies of 35 and 39 Hz are superimposed.
What is the frequency of the beat created?
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We know that both waves are sound waves, so they both have a wave speed of ~343 m/s
The question states that the frequencies of the waves differ from one another, so knowing that their wave speeds are the same, and remembering the formula
V = fλ
we know that their wavelengths must also be the same
** Frequency is the only thing that is different between the two original waves
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The only thing left to do is to apply the formula:
fb = |f2-f1|
= |39-35|
= 4
The beat has a frequency of 4 Hz
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Image Sources http://ineke.co.uk/category/my-big-ideas/
http://www.shutterstock.com/pic-162551174/stock-vector-driver-education-car-rear-indicators-with-headlights-off-day-time.html?src=-t6tes-ri--sjJ4_6BW8CQ-1-6
http://www.phys.uconn.edu/~gibson/Notes/Section5_5/Sec5_5.htm