bingo review game - concordia university...
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Bingo Review Game
This review game allows the students an opportunity to review the material and still have
fun while learning. I used this during Student Teaching 1 in Algebra AB at Seward High School.
The students enjoyed being able to review the material in a more fun way than just going over
problems that would not give them any reward while reviewing.
To begin, each student is given a blank “bingo board,” such as the one on the next page.
They were then able to randomly put the numbers from 1 through 25. This gives them the
opportunity to make their board unique from all the others. I split them in to groups of 2 or 3.
This gave them the opportunity to help each other out if they did not understand how to solve the
problem. The students had to write down their own work and solutions on a separate sheet of
paper in order to get credit if they got a bingo. I had a PowerPoint presentation that had all the
problems and answers on it. To choose the next problem I used a random number generator to
choose the next problem. They were giving 2 minutes to solve the problem given. After the 2
minutes I showed the answer and if they got it right they would mark off the problem on their
sheet.
Contained in this document is a pdf of a blank bingo sheet and a pdf of the PowerPoint
that I used while at Seward High School.
Chapter 4 Review
BINGO
1 2 3 4 56 7 8 9 10
11 12 13 14 1516 17 18 19 2021 22 23 24 25
Question 1Plot these points and describe the location.
A(-2, 0) B(0 ,0) C(-1 ,-1) D(2 ,-3)
A Negative x-axis B Origin C Quadrant 3 D Quadrant 4
Question 2Graph the equation using an
x-y chart
-2x + y = 3
x -2 -1 0 1 2
2x - 3 2(-2) - 3 2(-1) - 3 2(0) - 3 2(1) - 3 2(2) - 3
y -7 -5 -3 -1 1
Question 3Write in slope-intercept form, name the slope and y-
intercept
y - x = 0
y = x Slope: 1
y-intercept: 0
Question 4Graph using slope-intercept form
y = 5x - 3
Question 5Evaluate the Function when x = -2, 0, 3
p(x) = -8x - 2
p(-2) = 14 p(0) = -2
p(3) = -26
Question 6Evaluate the Function when x = -2, 0, 3
h(x) = 3/4x - 6
h(-2) = -7.5 h(0) = -6
h(3) = -3.75
Question 7Find the value of x so that the function has the given
value.
m(x) = 9x - 5; -2
x = 1/3
Question 8Graph with the given intercepts
x: 3
y: 5
Question 9Find the slope between the two given points
(6, -1) (-2, 2)
-3/8
Question 10Plot these points and describe the location.
A(3, 2) B(2, 5) C(0, 4) D(-2 , 2)
A Quadrant 1 B Quadrant 1 C Positive y-axis D Quadrant 2
Question 11Find the x and y intercepts using the zeros method
3x + 2y = 6
2(0) + 7y = 28 2x + 7(0) = 28 y = 4 x = 14
Question 12Which of these points would be on the line
y = 4/3x + 2
(-1, -2) (-3, -2) (3, 6) (1, 1)
(-3,-2) (3, 6)
Question 13Graph using slope-intercept form
3x - 3y = 12
Question 14Write in slope-intercept form, name the slope and y-
intercept
-12x -4y = 2
y = -3x -1/2 Slope: -3
y-intercept: -1/2
Question 15Find the value of x so that the function has the given
value.
g(x) = -x + 5; 2
x = 3
Question 16Evaluate the Function when x = -2, 0, 3
d(x) = -3/2x + 5
d(-2) = 8 d(0) = 5
d(3) = .5 or 1/2
Question 17Find the value of x so that the function has the given
value.
p(x) = -12x -36; -3
x = -2.75 or -11/4
Question 18Graph with the given intercepts
x: 9 y: -1
Question 19Find the x and y intercepts using the zeros method
-3x + 5y = -15
-3(0) + 5y = -15 -3x + 5(0) = -15 y = -3 x = 5
Question 20Find the slope between the two given points
(-1, 1) (4, 1)
0/5 = 0
Question 21Find the slope between the two given points
(5, 3) (2, -1)
4/3
Question 22Write in slope-intercept form, name the slope and y-
intercept
2x + 5y = -10
y = -2/5x - 2 Slope: -2/5
y-intercept: -2
Question 23Plot these points and describe the location.
A(-3, -2) B(4, -2) C(3, 0) D(1, -2)
A Quadrant 3 B Quadrant 4 C Positive x-axis D Quadrant 4
Question 24Find the slope between the two given points
(1, 5) (1, -2)
7/0 undefined
Question 25Graph with the given intercepts
x: -2 y: -6