bridge course 13 - kar
TRANSCRIPT
Bridge Course 2012‐13
IntroductionChemistry involves three main divisionsdivisionsInorganic chemistryInorganic chemistryPhysical chemistryy yOrganic chemistry
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IntroductionOrganic chemistry is B h f h i tBranch of chemistryDeals with Deals with 1. Formation of organic compounds2.Properties of organic compounds
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f dFormation of organic compoundsVital force theoryy
Synthesis of urea by Wohler
NH4CNO NH2CONH2Heat
Ammonium Cyanate Urea
Carbon, an essential ingredient, g
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CarbonSpecial properties1. Tetravalent 1. Tetravalent 2. Unique catenation propertyI iti f t b h i h i t Imposition of separate branch in chemistry called organic chemistry
f f hDefinition of Organic Chemistry“Organic chemistry is chemistry of
compounds of carbon”Vikasana Bridge Course 2012
ApplicationsFood – carbohydrates, proteins, oils & fats etc
Clothes – cotton, nylon, silk etc
D i di l hit li i tDyes – indigo, malachite, alizarin etc
Fuel – petrol, diesel, kerosene etcFuel petrol, diesel, kerosene etc
Petrochemicals – Polymers, pesticides,
detergents, cosmetics etcVikasana Bridge Course 2012
Applications continued..Chemotherapy – use of drugs (chemical
substances) against the diseases without
causing harmful side effects to the host g
tissues.
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Applications continued..Drugs:
Antiseptic – dettol, salolAntiseptic dettol, salolAnalgesic – apririn, disprinA ti ti t l iAntipyretic ‐ paracetamol , crocinAntibiotic – penicillin, ampicillinAntimalarial – choloroquin, quinineTranquilizer – morphine, barbituric acida qu e o p e, ba b tu c ac d
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Functional GroupsAn atom or group of atoms that determines properties of organic compounds. E lExamples:
Structure Compound Functional group
H Methyl alcohol ‐OH : alcohol H – C – O – H
H
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Functional Groups contd..Structure Compound Functional grpStructure Compound Functional grp
H OH – C – C – O –H
Acetic acid ‐ COOH: Carboxylic acid H – C – C – O –H Carboxylic acid
H H Acetaldehyde ‐ CHO; HH H
H – C – C = O H
Acetaldehyde CHO; aldehyde
HH
H – C – ClMethylchloride ‐ Cl : chloro
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Homologous SeriesSeries of closely related organic compounds with Series of closely related organic compounds with similar chemical propertiesCharacteristicsC a acte st cs1. These series are represented by General
formula2. Two successive member of series differ by ‐
CH2. 2
3. They are prepared by common methods4 Show a regular gradation in physical 4. Show a regular gradation in physical
properties. Vikasana Bridge Course 2012
Homologous Series continued..Alkane seriesName Molecular
F l
Alkane series
Name Molecular
FormulaMethane CH4Eth C H
Alkene series
FormulaEthene C2H4
Ethane C2H6Propane C3H8B t C H 2 4
Propene C3H6Butene C4H8
Butane C4H10
4 8Pentene C5H10
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Homologous Series continued..
Name MolecularAlcohol seriesName Molecular
FormulaMethanol CH OHMethanol CH3OHEthano C2H5OHPropanol C H OHPropanol C3H7OHButanol C4H9OH
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Composition of organic compoundsp g pDeals with constituent of organic compounds in qualitative and quantitative formsin qualitative and quantitative formsQualitative analysis:D t ti f l t t i i Detection of elements present in organic compound
lQuantitative analysis:Estimation of elements present in organic compound and expressing it in percentage form Vikasana Bridge Course 2012
Chemical FormulaR i f l l f b Representation of a molecule of a substance in terms of symbols of various elementsExample:
Chemical formula of water – H2OChemical formula of carbon dioxide – CO2
Chemical formula of glucose – C6H12O6g 6 12 6
Two types Empirical formulaEmpirical formulaMolecular formula
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Empirical FormulaSimplest formula
Gives the ratio of number of atoms of
various elements present in one molecule of various elements present in one molecule of
the compound
Obtained from percentage of various
l t t i th delements present in the compoundVikasana Bridge Course 2012
Empirical Formula Examples
Compound Emperical formula
Hydrogen peroxide HOy g p
Glucose CH2O
Benzene CH
Napthalene C5H4Napthalene C5H4
Ethene CH2
Ethane CH3
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Molecular FormulaTrue (Actual) formula
Gives actual number of atoms of various
elements present in one molecule of the elements present in one molecule of the
compoundp
Obtained knowing empirical formula and
molecular massVikasana Bridge Course 2012
Molecular Formula Examples
d l l f lCompound Molecular formula
Hydrogen peroxide H2O2y g p 2 2
Glucose C6 H12 O6
Benzene C6 H6
Napthalene C10 H8Napt a e e C10 8
Ethene C2H4
Ethane C2H6
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Relation between Empirical & Molecular Formula
Molecular formula = (Empirical formula) nWhere ‘n’ is simple whole number and is given by,
Molecular massE i i l f l n = Empirical formula mass
Thi l i h l i d i i f l l
n
This relation helps in determination of molecular formula Vikasana Bridge Course 2012
Determination of Molecular Formula knowing molecular mass & empirical formulaExample (1): Example (1): Molecular mass of acetylene is 26, Empirical formula of acetylene is CH Empirical formula of acetylene is CH, ∴Empirical formula mass is 13.
26∴n = = 22613
∴molecular formula of acetylene = (CH)2 = C2H2Vikasana Bridge Course 2012
Determination of Molecular Formula
Example (2):
Determination of Molecular Formula knowing molecular mass & empirical formulaExample (2): Molecular mass of Glucose is 180Empirical formula is CH OEmpirical formula is CH2O∴ Empirical formula mass is 30∴n 6180∴n = = 6
l l f l f Gl (CH O)
30
∴molecular formula of Glucose = (CH2O)6 = C6H12O6 Vikasana Bridge Course 2012